When one mole of ideal gas is compressed isothermally from 1 atm to 100 atm, the change in entropy is 19.14 J/mol K. This is because the entropy of a system increases when it is compressed isothermally.
Maxwell relations relate the partial derivatives of thermodynamic quantities. They can be used to calculate the change in entropy during the isothermal compression of one mole of an ideal gas from 1 atm to 100 atm.
In this case, we can use the following Maxwell relation:
\(\begin{equation}\Delta S = 1 \times 8.314 \frac{\text{J}}{\text{mol K}} \times \ln \left( \frac{100 \text{ atm}}{1 \text{ atm}} \right)\)
where:
S is the entropy
P is the pressure
T is the temperature
V is the volume
The partial derivative of pressure with respect to temperature at constant volume can be calculated using the ideal gas law:
\(\begin{equation}\frac{dP}{dT}_V = \frac{nR}{V}\)
where:
n is the number of moles of gas
R is the ideal gas constant
The change in volume can be calculated from the initial and final pressures and temperatures:
\(\begin{equation}dV = \frac{P_2 - P_1}{T}\)
where:
\(P_1\) is the initial pressure
\(P_2\) is the final pressure
Substituting these equations into the Maxwell relation, we get:
\(\begin{equation}dS = \frac{nR}{V} \cdot \frac{P_2 - P_1}{T}\)
We can then simplify this equation to get:
\(\begin{equation}\Delta S = nR \cdot \ln \left( \frac{P_2}{P_1} \right)\)
Plugging in the values for n, R, \(P_1\), and \(P_2\), we get:
ΔS = 1 * 8.314 J/mol K * ln(100 atm / 1 atm)
ΔS = 19.14 J/mol K
Therefore, the change in entropy when one mole of ideal gas is compressed isothermally from 1 atm to 100 atm is 19.14 J/mol K.
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What does (2.3 x 10^5 times 3.8 x 10^-8) divided by (2.56 x 10^9) equal?
1.5 x 10^-22
3.4 x 10^6
3.4 x 10^-12
3.4 x 10^4
\(3.4 \times {10}^{ - 12} \)
Multiply first and then divide
when i mixed 5 drops of 0.10 m hcl with 5 drops of naoh i expected a ph of 7 but got a ph of 12, why?
The reason you observed a pH of 12 instead of 7 after mixing 5 drops of 0.10 M HCl with 5 drops of NaOH is likely because you added an excess of NaOH, leading to a basic solution rather than a neutral solution.
A neutral solution is a type of solution that has a pH value of 7, which is considered to be neither acidic nor alkaline (basic). The pH scale ranges from 0 to 14, with 7 being neutral. This means that the concentration of hydrogen ions (H+) is equal to the concentration of hydroxide ions (OH-) in the solution. In a neutral solution, the number of H+ ions is exactly balanced by the number of OH- ions, resulting in a balanced and stable solution.
A neutral solution is essential for many chemical reactions and industrial processes, such as the production of pharmaceuticals and food products. It is also important for maintaining the natural balance of the environment, as many organisms require a neutral pH for survival.
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The "barking dog" reaction is an exciting combustion reaction that generates a bright blue flame because sulfur is produced during the reaction (sulfur burns blue!). At the end of the reaction, a "woosh" sound is made which sounds like a dogs bark (hence the name of the reaction). Assume the reaction is carried out in a closed container. CS₂ + 4N₂0 CO₂ + SO₂ + S + 4N₂ Note: the equation is balanced How many moles of CO₂ can you generate if you were to carry out the reaction with 8.28 g CS₂?
From the mole ratio CO₂ and CS₂ in the reaction, the moles of CO₂ produced is 0.109 moles.
What is the mole ratio of the reaction?
The mole ratio of the reaction is the ratio in which the reactants combine to form products.
The mole ratio of the reaction is obtained from the equation of the reaction.
The equation of the reaction is given below:
CS₂ + 4N₂0 → CO₂ + SO₂ + S + 4N₂Mole ratio of CO₂ and CS₂ is 1 : 1
Moles of CS₂ reacting = mass/molar mass
Molar mass of CS₂ is 76 g/mol
Mass of CS₂ reacting is 8.28 g
Moles of CS₂ reacting = 8.28/76
Moles of CS₂ reacting = 0.109 moles
Based on the mole ratio of the reaction, moles of CO₂ produced is 0.109 moles.
In conclusion, the moles of CO₂ produced is determined from the mole ratio CO₂ and CS₂ in the reaction.
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how many ml of water must be added to 300 ml of 0.75 m hcl to dilute the solution to 0.25 m? select one: a. 600 ml b. 100 ml c. 900 ml d. 300 ml
To dilute the solution to 0.25 M, ml of water must be added to 300 ml of 0.75 M HCl is a. 600 mm.
To dilute the solution from 0.75 M to 0.25 M, we need to decrease the concentration of HCl (hydrochloric acid) in the solution. We can use the formula for dilution of a solution to calculate the volume of water that must be added:
C1 * V1 = C2 * V2
Where:
C1 = initial concentration (0.75 M)
V1 = initial volume (300 ml)
C2 = final concentration (0.25 M)
V2 = final volume (V1 + V added)
Rearranging the equation to solve for V added:
C1 * V1 = C2 * V2
V2 = (C1 * V1 ) / C2
= 0.75 * 300 / 0.25
= 900
Since V2 = V1 + V added then
V added = V2 - V1
= 900 - 300
= 600
Hence, total water that must be added is a. 600 ml
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25 points !!!!!!
a 10 ml sample of borax- borate equilibrium solution reacts completely with 23.33 ml of a 0.1006 M HCl solution. calculate the concentration of borate and then the Ksp for borax
Answer:
See answer below
Explanation:
To do this, you need to write down the chemical reaction giving place here.
As this is to explain the thermodynamics of the borax-borate reaction, the general reaction is as follow:
Na₂B₄O₅(OH)₄.8H₂O(s) <---------> 2Na⁺(aq) + B₄O₅(OH)₄²⁻(aq) + 8H₂O(l)
Where:
Na₂B₄O₅(OH)₄.8H₂O(s) = Borax
B₄O₅(OH)₄²⁻(aq) = Borate ion
Now, in order to calculate the concentration of borate, this compound undergoes a titration with HCl. The reaction that takes place here is:
B₄O₅(OH)₄²⁻(aq) + 2HCl + 3H₂O <---------> 4H₃BO₃(aq) + 2Cl⁻(aq)
According to this reaction, it takes 2 moles of HCl to completely react with the borate ion, therefore, the expression to calculate the concentration will be:
2 nHCl = nB₄O₅(OH)₄²⁻
2M₁V₁ = M₂V₂
Replacing the data of concentration and volume of both compounds we have:
2 * 0.1006 * 23.33 = 10M₂
M₂ = 2 * 0.1006 * 23.33 / 10
M₂ = 0.4693 M
This is the concentration of the borate. Now, to calculate the Ksp we need to write the equilibrium reaction taking place with the borax:
Na₂B₄O₅(OH)₄.8H₂O(s) <---------> 2Na⁺(aq) + B₄O₅(OH)₄²⁻(aq) + 8H₂O(l)
Ksp = [B₄O₅(OH)₄²⁻] [Na⁺]²
As we already have the concentration of borax, we can also know the concentration of sodium. If we call concentration as "s" (Stands for solubility), and rewrite the expression of Ksp:
Ksp = s * (2s)²
Finally, replacing the value of the concentration we have:
Ksp = (0.4693) (2*0.4693)²
Ksp = 0.4693 * 0.881
Ksp = 0.4134
Hope this helps
HELP pls with this lab sheet
A balanced equation obey the law of conservation of mass. According to law of conservation of mass, mass can neither be created nor be destroyed.
What is a balanced equation?A balanced chemical equation is an equation in which the number of atoms of reactants and products on both sides of the equation are balanced. The coefficients are the numbers which are used to balance the chemical equation.
The decomposition of potassium chlorate is:
2KClO₃ (s) + heat → 2KCl (s) + 3O₂ (g)
Here the number of 'K', 'Cl' and 'O' atoms are equal on both sides of the equation.
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the average rate of disappearance of ozone gas was 228.28 torr*s-1 2o3(g) -> 3o2(g) what is average rate of appearance of oxygen?
The average rate of appearance of oxygen is 342.42 torr*s^-1.
From the balanced chemical equation: 2O3(g) → 3O2(g), we know that for every two moles of O3 consumed, three moles of O2 are produced. Therefore, the rate of appearance of O2 is related to the rate of disappearance of O3 by the stoichiometric coefficients:
rate of appearance of O2 = (3/2) * rate of disappearance of O3
Substituting the given value for the rate of disappearance of O3:
rate of appearance of O2 = (3/2) * 228.28 torr*s^-1
Simplifying the expression:
rate of appearance of O2 = 342.42 torr*s^-1
Therefore, the average rate of appearance of oxygen is 342.42 torr*s^-1.
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PLEASE HELP ASAP
Barney was a very inventive scientist and tried to perform the same experiments as those by famous scientists from long ago. One of the most challenging experiments was to roll out a very thin film of gold and put X-ray film in a circle around it. The difficult part was to get ahold of some radioactivity that he could shoot at the thin film for gold. One day, he ran into The Great Gazoo and told him his goal. The Great Gazoo said he had the perfect substance for him that was radioactive and should work. The element was named after him and had the symbol Gz. Barney quickly went back to his lab to run the experiment. What Barney noticed is that all the radioactive particles went through the gold film and none of them ricocheted back, but all went straight through the gold. Being puzzled, he quickly went to the lab to analyze this unknown radioactive substance. He found that the atomic number was 119, the mass number was 305. After a few more tests, Barney realized what was wrong with Gz. Your task is to figure out what was wrong with Gz by answering the following questions:
Whose experiment was Barney trying to imitate?
Where would Gz be located on Earth’s periodic table, column and row?
Give as many details on Gz that you could predict based on its location on the periodic table: type of chemical (metal, metalloid, or nonmetal), reactivity, ionization energy, electronegativity, and size of element.
What would the elements electron configuration end in?
Why did all the radioactive particles go straight through the gold film?
What would the daughter product be for Gz? Give all details for the atomic number, mass number, number of protons, neutrons and electrons.
If Gz had worked correctly, like Barney intended, what type of decay should Gz have had?
If Gz had worked correctly, what would the daughter product be? Give all details for the atomic number, mass number, number of protons, neutrons and electrons.
If Gz had worked correctly, what element would it become?
Answer:
a) Barney wants to repeat the rutheford experiment
b) the element will be in row 8 column 1 being an alkali metal
c) it should be a radioactive element, with a lot of mass
Explanation:
n this exercise they indicate that the particle Gz has atomic number 119 and atomic mass 305 amu, when reviewing the element periodicity table with this atomic number it has not yet been discovered, it should be in row 8 column 1 therefore it should be an alkali metal .
Therefore, it has only one electron in its last orbit.
a) Barney wants to repeat the rutheford experiment
b) the element will be in row 8 column 1 being an alkali metal
c) it should be a radioactive element, with a lot of mass
How many grams in 25Kg?
Answer:
it adds up to 25000 grams
How much heat is absorbed by 150. 0 g of ice as it
melts at 0°C?
150.0 g of ice absorbs 49.97 kJ of heat as it melts at 0°C.
To calculate the amount of heat absorbed by 150.0 g of ice as it melts at 0°C, we need to use the heat of fusion of water, which is the amount of heat required to melt one mole of a substance at its melting point. For water, the heat of fusion is 6.01 kJ/mol.
The first step is to determine the number of moles of ice present in 150.0 g,
n = m/M
n = 150.0 g / 18.02 g/mol
n = 8.32 mol
Next, we can use the heat of fusion to calculate the amount of heat absorbed by the ice as it melts,
q = n x ΔHfus
q = 8.32 mol x 6.01 kJ/mol
q = 49.97 kJ
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the data is plotted so students can find and report the boiling point elevation by getting the average temperature at the two plateaus and finding the difference. what does the first plateau represent?
The first plateau represents the boiling point of the pure solvent. This is explained in the below section.
Boiling point elevation refers back to the growth withinside the boiling factor of a solvent upon the addition of a solute. When a non-unstable solute is introduced to a solvent, the ensuing solution has a better boiling factor than that of the natural solvent. Boiling-factor elevation describes the phenomenon that the boiling factor of a liquid can be better whilst any other compound is introduced, which means that an answer has a better boiling factor than a natural solvent. This takes place every time a non-unstable solute, including a salt, is introduced to a natural solvent, including water.
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What is the concentration in mass-volume percent for 13.9 g caf2 in 255 ml of solution?
The concentration in mass-volume percent of the solution is: 5.45 %
To solve this problem the formula and the procedure that we have to use is:
% m/v = m(solute)/v(solution) * 100
Where
% m/v = concentration in mass volume percentm = mass of solutev = volume of solutionInformation about the problem:
m(solute)= 13.9 gv(solution)= 255 ml% m/v =?Applying the concentration formula we get:
% m/v = m(solute)/v(solution) * 100
% m/v = (13.9 g/255 ml) * 100
% m/v = 0.0545 *100
% m/v =5.45 %
What is a solution?In chemistry a solution is known as a homogeneous mixture of two or more components called:
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What energy associated with light that allows us
to see colors on the ROYGBIV spectrum?
Answer:
Visible light waves let you see the world around you. The different frequencies of visible light are experienced by people as the colors of the rainbow.
Explanation:
Which action by industry leaders would directly address the causes of global warming? (1 point)
The action by industry leaders that would directly address the causes of global warming is to reduce the production of greenhouse gases.
What is global warming?
Global warming is the phenomenon in which the average overall temperature of the earth increases over time resulting in drastic changes that occurs on the earth.
The effects of global warming include the following:
excessive droughts in some parts of the globemelting of polar ice and glaciers resulting in a rise in seawater levelsexcessive rainfall in some parts of the globe resulting in floodingThe major cause of global warming has been identified as the excessive release of greenhouse gases into the atmosphere.
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when the white part is on the left the moon is.??
Answer:
Last Quarter also called Third Quarter.
Explanation:
In a 3.21g sample of the hydrate, CuSO4 • 10H2O (339.8 g/mol), how many grams of water are expected?
Therefore, 9.49 grams of water is expected in the given 3.21 g sample of CuSO4 • 10H2O.
To determine the number of water molecules in the given hydrate, CuSO4 • 10H2O, we'll need to find out the molar mass of the compound and the molar mass of water to make a comparison.
The molar mass of CuSO4 • 10H2O is calculated as:
CuSO4 → 159.6 g/mol10H2O → 180.16 g/mol (18.016 g/mol × 10)CuSO4 • 10H2O → 159.6 g/mol + 180.16 g/mol
= 339.76 g/mol (rounded to three significant figures)
Thus, we can see that the molar mass of CuSO4 • 10H2O is 339.76 g/mol.
We know that this hydrate consists of ten molecules of water, each having a molar mass of 18.016 g/mol (which is the same as the molar mass of water), and one molecule of CuSO4 with a molar mass of 159.6 g/mol.
Therefore, the number of moles of water in the sample is:
(10 × 18.016 g/mol) ÷ 339.76 g/mol = 0.527 moles
So, the mass of water is equal to its molar mass multiplied by the number of moles.
The mass of water is:
0.527 mol × 18.016 g/mol = 9.49 g
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What is the IUPAC name for Ester with 9 carbon atoms ?
Explanation:
\(CH _{3}CH _{2}COOCH _{2} CH _{2}CH _{2}CH _{2}CH _{2}CH _{3}\)
NAME: Hexylpropenoate
Select the curve that is produced by adding hydrochloric acid to 25 cm3 of sodium hydroxide.A,B,C or D
B
The sodium hydroxide (NaOH) solution is a basic solution, so the pH of that solution should be close to 14
then when adding hydrochloric acid (HCl) we start to neutralice the solution, meaning the pH must sift slowly to lower pH.
Assuming both solutions have similar concentration the pH shall shift form basic (above 7) to acid pH (below 7). Until now both B and D images agreed with the explanation given. To chose between them we need to remember that HCl is a very strong acid, which means that in solution will get to very acid solutions (very low pH values) which leaves only B as possible answer
which of the following amines would be the most soluble in water?
(hint: consider hydrogen bonding)
a. N-ethylaniline
b. 1-propanamine
c. Propanediamine
d. N,N-dimethylpropanamine
e. N,N-diphenylaniline
Answer:
The correct answer is B. 1-propanamine.
Explanation:
Amines can form hydrogen bonds with water molecules, which makes them soluble in water. The more hydrogen bonding sites an amine has, the more soluble it will be in water.
Out of the given options, 1-propanamine has only one carbon chain, which allows it to form more hydrogen bonds with water molecules compared to amine molecules with longer carbon chains. Also, it does not have any other functional groups that could interfere with hydrogen bonding. Therefore, 1-propanamine would be the most soluble in water.
Further Explanation:A. N-ethylaniline - contains a nonpolar aromatic ring that can interfere with hydrogen bonding and reduce solubility in water.B. 1-propanamine - has only one carbon chain, allowing it to form more hydrogen bonds with water molecules.C. Propanediamine - has two amine groups that can form hydrogen bonds with water molecules, but it also has a longer carbon chain that can interfere with hydrogen bonding and reduce solubility in water.D. N,N-dimethylpropanamine - has two methyl groups that can interfere with hydrogen bonding and reduce solubility in water.E. N,N-diphenylaniline - contains two bulky aromatic rings that can interfere with hydrogen bonding and reduce solubility in water.Hope it helps!
pressure has little effect on the solubility of liquids and solids because they are almost incompressible. This state of True Or False
- True
- False
Pressure has little effect on the solubility of liquids and solids because they are almost incompressible. This statement is True. Solid solubility hardly gets affected by changes in pressure.
A substance's physical and chemical characteristics affect how soluble it is. A few other factors and circumstances can also influence it. A few of them are: temperature, pressure, type of binding, and forces between the particles.
Pressure has a significantly greater impact on gases than it does on solids and liquids. The likelihood of a gas's solubility also increases as its partial pressure rises. One instance of how CO2 is stored under high pressure is in a soda bottle.
In like, like dissolves.
Each molecule has a unique set of intermolecular forces and connections. The likelihood of solubility between two dissimilar compounds is less likely than that between like substances. For instance, ethanol is highly soluble in water, a polar solvent, whereas water is not.
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Help me pretty please
Which contribution is a modification to Thomson's plum pudding model?
Atoms are indivisible.
Electrons are scattered in an atom.
A positively charged nucleus sits at the center of an atom.
Atoms of the same element have the same properties.
Answer:
Option C: A positively charged nucleus sits at the center of an atom.
Explanation:
Thompson’s plum pudding model was a model proposed by Thompson to show that an atom consisted of more than one fundamental unit.
In Thompson's model, he suggested that the atom consisted of a cloud of positive charges which were surrounded by electrons which are negative charges distributed throughout.
Now, Thompson's experiment was later rejected by Ernest Rutherford when he carried out the gold foil experiment and came to the conclusion where he proposed a model that the atom consisted of mainly empty space and that all its positive charge are concentrated at its center and further surrounded by a cloud of electrons.
From the given options, the correct one is Option C.
Answer: Option C: A positively charged nucleus sits at the center of an atom.
Explanation:
What is the freezing point, in °C, of
a 0.655 m solution of C4H10 in
benzene?
FP (benzene) = 5.5 °C
Kr(benzene) = 5.12°C/m
[?] °C
Give your answer to the thousandths place.
Freezing Point
Enter
The freezing point of the solution is - 2.15.
What is the freezing point?The freezing point is the point at which a liquid is changed to solid. We can use the formula;
ΔT = K m I
ΔT = temperature change
K = freezing constant of benzene
m = molality
i = Van't Hoff factor
Now;
ΔT = 5.12°C/m * 0.655 m * 1
ΔT = 3.35°C
ΔT = Freezing point of pure benzene - Freezing point of solution
Freezing point of solution = ΔT - Freezing point of pure benzene
= 3.35°C - 5.5 °C = - 2.15
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Answer:
2.143 degrees celsius
Explanation:
Summarizing your investigation using the Five-Column Chart. For my investigation I use Solid.
Answer:
The Five-Column Chart is a useful tool for summarizing your investigation. In the case of your investigation involving solids, the chart would include columns for Properties, Examples, Uses, Interactions and Special Characteristics. In the Properties column, you would list the physical and chemical properties of solids, such as shape, texture, melting point, boiling point and solubility. The Examples column would list examples of solids, such as metals, plastics and rocks. The Uses column would list the various uses of solids, such as in construction, engineering and medicine. The Interactions column would list how solids interact with each other, such as through adhesion, cohesion and friction. Finally, the Special Characteristics column would list any special characteristics of solids, such as their electrical conductivity or magnetic properties.
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1MeV = 1.6 x 10-13 J
Energy use per person per year in the United States = 3.5 x 1011Joules
(estimated, varies by source, August 2009)
Approximate population of USA: 310,000,000
Given: Energy released = 17.59 MeV per deuterium/tritium reaction pair (mass = 5 amu)
----------------------------------------------
Determine the energy released per kilogram of fuel used.
Given MeV per reaction, calculate energy in joules per kilogram of reactants.
Consider 1 mole of tritium plus 1 mole of deuterium to be a mole of "reactions" (total molar mass = 5 grams).
...
The energy released = 17.59 MeV per deuterium/tritium reaction pair (mass = 5 amu). The energy released per kilogram of fuel used is approximately 3.382 x \(10^{14}\) Joules.
To determine the energy released per kilogram of fuel used, we need to follow these steps:
Step 1: Convert MeV to Joules
Given that 1 MeV = 1.6 x \(10^{-13}\) J and the energy released per deuterium/tritium reaction pair is 17.59 MeV, we first convert this value to Joules:
17.59 MeV * (1.6 x \(10^{-13}\) J/MeV) = 2.8144 x \(10^{-12}\) J
Step 2: Calculate moles of reactions in 1 kg of fuel
Given that 1 mole of tritium plus 1 mole of deuterium (total molar mass = 5 grams) is considered a mole of reactions, we need to determine how many moles of reactions are in 1 kilogram of fuel:
1 kg = 1000 g
1000 g / 5 g/mole = 200 moles of reactions
Step 3: Calculate the total energy released per kilogram of fuel
Now we can find the total energy released per kilogram of fuel by multiplying the energy per reaction (in Joules) by the number of moles of reactions in 1 kg of fuel:
2.8144 x \(10^{-12}\) J/reaction * 200 moles * (6.022 x \(10^{23}\) reactions/mole) = 3.382 x \(10^{14}\) J/kg
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lime kilns are very large. why is this necessary?
a 7.5 l mixture of gases is produced by mixing 4.0 l of n2 at 450 torr, 3.5 l of 02 at 252 torr, and 0.21 l of c02 at 150 torr. if the temperature is held constant at 65 0 c, what is the total pressure of the mixture?
The total pressure of the mixture is 359.5 torr, that is calculated by using ideal gas equation.
Volume of N2, V1=4.0 L
Pressure of N2, P1=450 Torr=450/760 atm
Thus, number of moles of N2, n1= P1V1/RT
=(450/760)*4/0.082*338
=0.085 mol
Similarly,
Volume of O2, V2=3.5 L
Pressure of O2, P2=252 Torr=252/760 atm
Thus, number of moles of O2, n2= P2V2/RT
=(252/760)*3.5/0.082*338
=0.042 mol
Similarly,
Volume of CO2, V3=0.21 L
Pressure of CO2, P3=150 Torr=150/760 atm
Thus, number of moles of CO2, n3= P3V3/RT
=(2150/760)*30.21/0.082*338
=0.001 mol
Total number of moles = n1+n2+n3
=(0.085+0.042+0.21)
=0.128 mol
Total volume, V=7.5 L
Using, ideal gas law
Thus, total pressure, P=nRT/V
=0.128*0.082*338/7.5 atm
=0.473 atm
=0.473*760
=359.5 torr
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Nuclear bombs cause much more damage upon
explosion than non-nuclear bombs because
Select one:
- the fallout from a nuclear bomb explosion has a much shorter half-life than the fallout from non-nuclear bombs.
- nuclear bombs are a million time greater in size than bombs that react chemically.
- nuclear explosions emit alpha particle radiation, and non-nuclear bombs emit only beta particle radiation
- energy released by nuclear reaction is much greater than energy released by chemical reaction.
Answer:
- energy released by nuclear reaction is much greater than energy released by chemical reaction.
Explanation:
This is because nuclear bombs rely on nuclear reactions, which release energy from the splitting of atomic nuclei or the merging of atomic nuclei, whereas non-nuclear bombs rely on chemical reactions, which involve the breaking and forming of chemical bonds. Nuclear reactions release many orders of magnitude more energy than chemical reactions, resulting in much greater destructive power.
Which of the following statement is true: a. The strength and stiffness of a polymer increases with an increase in crystallinity b. As the degree of crystallinity increases, a polymer's melt transition decreases c. Amorphous polymers are opaque d. all of the above e. none of the above
The statement that is true is :a. The strength and stiffness of a polymer increases with an increase in crystallinity.
What is Crystallinity ?The degree of ordering or arrangement of polymer chains in a solid polymer is referred to as crystallinity. A polymer's chains are highly arranged and densely packed when it has a high degree of crystallinity, which improves strength and stiffness.
This is because superior load transfer and deformation resistance are made possible by the regular arrangement of polymer chains.
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A gas is heated from 263.0 K to 298.0 K and the volume is increased from 24.0 liters to 35.0 liters by moving a large piston within a cylinder. If the original pressure was 1.00 atm, what would the final pressure be?
Answer:
The final pressure is approximately 0.78 atm
Explanation:
The original temperature of the gas, T₁ = 263.0 K
The final temperature of the gas, T₂ = 298.0 K
The original volume of the gas, V₁ = 24.0 liters
The final volume of the gas, V₂ = 35.0 liters
The original pressure of the gas, P₁ = 1.00 atm
Let P₂ represent the final pressure, we get;
\(\dfrac{P_1 \cdot V_1}{T_1} = \dfrac{P_2 \cdot V_2}{T_2}\)
\(P_2 = \dfrac{P_1 \cdot V_1 \cdot T_2}{T_1 \cdot V_2}\)
\(P_2 = \dfrac{1 \times 24.0 \times 298}{263.0 \times 35.0} = 0.776969038566\)
∴ The final pressure P₂ ≈ 0.78 atm.