7. what is the maximum angle of climb (steady velocity climb) for a turbojet powered aircraft with an (l/d)max equal to 10.5 and a gross weight of 8000 lb. if it is producing a thrust of 2000 lb.?

Answer:

See the answers below. And the free body diagrams attached.

Explanation:

To solve this problem, we must build a free body diagram, where we show the forces acting on a body, first for the m2 body, where the force of 3.5 [N] acts to the right. In such a way that a reaction force is presented in the opposite direction due to the string tied between both bodies, we will call this force T1.

Now using Newton's second law, which is defined as the sum of forces equal to the product of mass by acceleration, we can determine an equation as a function of T1.

∑F = m*a

\(3.5 -T_{1}=0.6*a_{2}\)

We have an equation with two unknowns, in such a way we must perform a second free body diagram for the body with mass m1, to acquire the additional equation.

∑F =m₁*a₁

\(T_{1}=0.4*a_{1}\)

By kinematics we know that if the string tied to Body 2 moves a distance, the part of the string at the end tied to body 1 will move the same distance. This same analysis is valid for velocities and accelerations.

This is the accelerations a1 and a2 are equal. Now equalizing both equations.

\(3.5-0.4*a_{1}=0.6*a_{2}\\but\\a_{1}=a_{2}\\3.5-0.4*a_{1}=0.6*a_{1}\\a_{1}=3.5[m/s^{2} ]\)

The acceleration of each block connected by the given string is 3.5 m/s².

The given parameters;

The net force on the blocks is calculated as follows;

\(\Sigma F = ma\\\\F - T = m_2a\\\\F - m_1(a -g)= m_2a\\\\g = 0 \ , \ in \ horizontal \ direction\\\\F - m_1a = m_2 a\\\\F = m_2 a + m_1 a\\\\F = a(m_1 + m_2)\\\\a = \frac{F}{m_1 + m_2} \\\\a = \frac{3.5 }{0.4 + 0.6} \\\\a = 3.5 \ m/s^2\)

Thus, the acceleration of each block connected by the given string is 3.5 m/s².

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Twelve seconds after starting from rest a freely falling of  cantaloupe has a speed of 114 m/s

When a body moves exclusively under the influence of the Earth's gravity, it is said to be in freefall. The motion of the ball will be accelerated as a result of an external force acting on it. This free-fall acceleration is also known as acceleration due to gravity.

The branch of physics that defines motion with respect to space and time, ignoring the cause of that motion, is known as kinematics.

from kinematic equation of motion`

v = u+ at

  =u + gt               (The acceleration for a free-falling object is g)

since, starting from rest

initial velocity = u = 0

time = 12 seconds

g= 9.81 m/ \(s^{2}\)

v = u + gt

  = 0 + 9.8 * 12

  = 117.6 m/s

  ≈ 118 m/s

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Chewing is an example of mechanical digestion.Mechanical digestion refers to the process by which food is physically broken down into smaller pieces to improve digestion and absorption.

The process begins in the mouth and is carried out by a number of organs such as the tongue, teeth, and stomach. Chemical digestion occurs next, in which enzymes break down food molecules to their essential components, allowing them to be absorbed into the bloodstream and delivered to the cells that need them.

What is an example of mechanical digestion?As stated earlier, mechanical digestion involves the physical breakdown of food into smaller particles. Here are some examples of mechanical digestion:Chewing - Your teeth grind food into smaller pieces, making it easier to digest and absorb.

Your saliva, which contains enzymes that start the chemical digestion process, also softens the food and helps to break down starch into simpler sugars.Grinding - After you swallow, your food moves to the stomach, where it is further broken down by contractions of the stomach muscles.

Mixing - The stomach's muscular walls contract to create churning movements that mix food with gastric juices, resulting in a semi-solid substance known as chyme that can be transported to the small intestine for further digestion and absorption.In conclusion, chewing is an example of mechanical digestion.

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As per the given data the the expression representing the motion of a mass-spring oscillator is :\(x(t) = (\frac{-2}{5} ) * e^(^-^t^) + (2/5) * e^(^-^3^t^) - (\frac{2}{5} ) * sin(t) + (4/5) * cos(t)\)

To find the position function x(t) for the given mass-spring oscillator, we can solve the second-order linear differential equation that governs its motion. The equation is obtained by applying Newton's second law and taking into account the forces involved:

\(m * x''(t) + b * x'(t) + k * x(t) = F(t)\)

where m is the mass, x(t) is the position function, x'(t) is the velocity function, x''(t) is the acceleration function, b is the frictional constant, k is the spring constant, and F(t) is the external force.

Given the values:

m = 1 kg

k = 3 kg/sec^2

b = 4 kg/sec

F(t) = 2sin(t)

Using these values, the differential equation becomes:

\(x''(t) + 4 * x'(t) + 3 * x(t) = 2sin(t)\)

To solve this equation, we can first find the homogeneous solution by assuming x(t) = e^(rt), where r is a constant. Plugging this assumption into the equation, we get the characteristic equation:

\(r^2 + 4r + 3 = 0\)

Solving this quadratic equation, we find two distinct roots: r1 = -1 and r2 = -3.

Therefore, the homogeneous solution is given by:

\(x_h(t) = c1 * e^(-t) + c2 * e^(-3t)\)

Next, we need to find a particular solution to account for the external force term. Since the external force is 2sin(t), we assume a particular solution of the form:

\(x_p(t) = A * sin(t) + B * cos(t)\)

Plugging this into the differential equation, we find:

\(-2A * sin(t) - 2B * cos(t) + 4A * cos(t) - 4B * sin(t) + 3(A * sin(t) + B * cos(t)) = 2sin(t)\)

Matching the coefficients of sin(t) and cos(t), we get two equations:

\(-2A + 4B + 3A = 2-2\\B - 4A + 3B = 0\)

Solving these equations, we find A = -2/5 and B = -4/5.

Therefore, the particular solution is:

\(x_p(t) = (-2/5) * sin(t) - (4/5) * cos(t)\)

The general solution is the sum of the homogeneous and particular solutions:

\(x(t) = x_h(t) + x_p(t)\\= c1 * e^(^-^t^) + c2 * e^(^-^3^t^) + (-2/5) * sin(t) - (4/5) * cos(t)\)

To find the constants c1 and c2, we use the initial conditions: x(0) = 0 and x'(0) = 0.

Plugging these values into the equation, we get:

\(c1 + c2 - 4/5 = 0\)     (equation 1)

\(-c1 - 3c2 - 2/5 = 0\)     (equation 2)

Solving these equations simultaneously, we find c1 = -2/5 and c2 = 2/5.

Finally, substituting these values back into the general solution, we obtain the position function:

\(x(t) = (\frac{-2}{5} ) * e^(^-^t^) + (2/5) * e^(^-^3^t^) - (\frac{2}{5} ) * sin(t) + (4/5) * cos(t)\)

This is the solution

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The generalization that can be made about the relative speeds that the sun and the stars move through the sky over the course of a day is that the sun appears to move much slower than the stars. This is because the sun is much closer to Earth than the stars, so its movement is more noticeable.

The stars, on the other hand, are much farther away and their movement is less noticeable.

Another way to think about this is to consider the fact that the Earth is rotating on its axis. As the Earth rotates, the sun appears to move across the sky at a relatively slow speed because it is close to Earth. The stars, however, are much farther away and their movement is not as noticeable. This is why the stars appear to move much faster than the sun over the course of a day.

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Answer:

How do static and sliding friction affect the speed of a paperback book, a flat eraser and a key?

Prediction: Which item (paperback book, flat eraser, or key) will have the most static friction and which item will have the most sliding friction?  Make sure your prediction gives an explanation of your reasoning.

Explanation:

The chemical potential (µ) for 1 mole of helium gas at t = 300 K and p = 1 atm is approximately 6.07 x 10⁻²¹ J/atom.

To calculate µ (the chemical potential) for 1 mole of helium gas at t = 300 K and p = 1 atm, we will use the following equation:
µ = µ₀ + kT * ln(n)

where µ₀ is the standard chemical potential, k is the Boltzmann constant, T is the temperature in Kelvin, and n is the number density (number of atoms or molecules per volume).

First, we need to find n, the number density.

We can use the Ideal Gas Law equation, PV = nRT, where P is pressure, V is volume, n is the number of moles, R is the gas constant, and T is the temperature.

1 atm * V = (1 mole) * (0.08206 L atm/mol K) * (300 K)
V = (1 * 0.08206 * 300) / 1
V = 24.618 L

Now, we have the volume (V) and can calculate the number density (n):
n = N / V
where N is the number of atoms and V is the volume.

N = (1 mole) * (6.022 x 10²³ atoms/mol)
n = (6.022 x 10²³ atoms) / (24.618 L)
n = 2.44 x 10²² atoms/L

Now, we can calculate the chemical potential (µ):
µ = µ₀ + kT * ln(n)
Note that for an ideal gas, µ₀ is typically 0.

Thus:
µ = (0) + (1.38 x 10⁻²³ J/K * 300 K) * ln(2.44 x 10²² atoms/L)
µ ≈ 6.07 x 10⁻²¹ J/atom

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Answer:

physical

Explanation:

physical weathering and disaggregation, causes rocks to crumble. Water, in either liquid or solid form, is often a key agent of mechanical weathering. For instance, liquid water can seep into cracks and crevices in rock.

Answer:

It would be considered a close circuit when the circuit is off

When metallic substances lose electrons, they are trying to achieve the electron configuration of D.

This is because the noble gases have completed outer electron shells, making them stable and unreactive. By losing electrons, metals can achieve a similar electron configuration and become more stable. The previous noble gas. When metallic substances lose electrons, they are trying to achieve the electron configuration of the previous noble gas. This is because noble gases have a stable electron configuration with full outer energy levels, making them less reactive. Metals lose electrons to attain this stable state.

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Answer:

The expectation that a larger object will feel heavy is presumably caused by the fact that larger objects generally contain more material and consequently have a larger mass than smaller objects. When, in contrast, the two objects have the same mass, an illusory heaviness difference occurs.

Explanation:

sorry if this is wrong

Answer:

120

Explanation:

lambda = 12

f=10

10×12=120

Answer:

In substances such as iron, cobalt, and nickel, most of the electrons spin in the same direction. This makes the atoms in these substances strongly magnetic—but they are not yet magnets. To become magnetized, another strongly magnetic substance must enter the magnetic field of an existing magnet.

The uterus lining is rebuilt by the end of the menstrual period. The rebuilding of the uterus lining starts after menstruation and the lining is typically completely rebuilt by day 14 of the menstrual cycle, which is when ovulation occurs and the uterus is preparing to potentially receive a fertilized egg.

The endometrium is the inner lining of the uterus, and it thickens every month to prepare for pregnancy. After menstruation, the endometrium grows and thickens to prepare for the implantation of a fertilized egg. The cells in the lining multiply and enlarge, and the glands in the lining begin to secrete mucus and other substances that help support the fertilized egg and promote its growth.

The rebuilding of the endometrium usually takes about two weeks after menstruation. This process is closely regulated by hormones such as estrogen and progesterone, which are produced by the ovaries and other parts of the body. These hormones help control the growth and development of the endometrium and other reproductive tissues.

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The velocity of the cannonball along the x axis after 7.59 s is therefore:vx = (150 m/s)(cos 0°)(7.59 s)vx = 1139.85 m.(d) Dimensionless velocity and dimensionless time are given by:v' = v/vTt' = 2gh/ vT²These expressions simplify the solution to part (c).

(a)  Terminal velocity along y axis is the maximum velocity that the cannonball can reach along y-axis as it falls. When it reaches terminal velocity, the acceleration of the cannonball becomes zero since its weight is balanced by air resistance. According to Stoke’s law, the drag force (Fd) experienced by a sphere moving slowly in a fluid is given by: Fd = 6πηrvwhere:η is the kinematic viscosity of the fluidv is the speed of the sphere, andr is the radius of the sphereHence, the terminal velocity (vT) of the cannonball is given by:  mg = 4/3 πr³ρg   [weight of cannonball = volume of cannonball x density of cannonball x acceleration due to gravity]6πηrvT = mgvT = mg/ (6πηr)The velocity of the cannonball along the y-axis is zero at the start and it reaches terminal velocity after falling through some height h.The velocity of the cannonball at any time t is given by:v = (2gh/ 3πr² ρ)½The velocity of the cannonball along the y axis is 131.3 m/s.(b)At 95% of terminal velocity, the velocity of the cannonball is 124.74 m/sUsing the expression:v = (2gh/ 3πr² ρ)½124.74 = (2gh/ 3πr² ρ)½h = (3/2)(124.74)² πr²ρ/g = 1509.65 mTherefore, it takes 7.59 s to reach 95% of the terminal velocity.(c)At the time determined in part (b), the velocity of the cannonball along the x axis can be calculated using the equation below:vx = vo xcosθtwhere vo is the initial velocity along the x-axis, θ is the angle of projection, and t is the time taken.At launch, the initial velocity along the x axis is 150 m/s and the angle of projection is 0°.

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The value of the resistance r is 20.25 ohms.

The value of the resistance r is calculated by applying Ohm's law as shown below.

Ohm's law states that the current flowing in a circuit is directly proportional to the voltage across the circuit.

V = IR

where;

P = IV

I = P / V

I = ( 32 W ) / ( 24 V + 12 V )

I = 0.889 A

R = V/I

R = ( 24 + 12 ) / ( 0.889 A )

R = 40.5 ohms

The value of each resistance, r is calculated as;

r = 40.5 ohms / 2

r = 20.25 ohms.

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Answer:

\(\mathbf{\dfrac{I(5l)}{I(l) } =10^{-8}}\)

Explanation:

We are being told that the current is proportional to the tunneling coefficient\(I(l) = I_0 e^{-2kl}\) ;

where l = distance between the tip and the surface.

Let      \(I(l) = I_0 e^{-2kl}\)        ------------  equation (1)

and     \(I(5l) = I_0 e^{-2k(5l)}\)   ------------ equation (2)

Dividing equation (2) by (1); we have :

\(\dfrac{I(5l)}{I(l) } = \dfrac{I_0 e^{-2k(5l)}}{ I_0 e^{-2kl}}\)

\(\dfrac{I(5l)}{I(l) } =e^{-2k(5-1)l}\)

\(\dfrac{I(5l)}{I(l) } =(e^{-2kl})^4\)

where ;

\((e^{-2kl})\) represents the transmission coefficient T = 0.01

Thus; replacing the value for 0.01;we have;

\(\dfrac{I(5l)}{I(l) } =0.01^4\)

\(\mathbf{\dfrac{I(5l)}{I(l) } =10^{-8}}\)

The time period remains the same = 1 sec.

We have a mass–spring system.

We have to determine the period of oscillation if mass–spring system is displaced from equilibrium by 10cm and not from 5cm.

The time period is given by -

\($T = 2\pi \sqrt{\frac{M}{K} }\)

According to the question -

For x = 5 cm the time period is 1 seconds.

The time period is directly proportional to \($\sqrt{\frac{M}{K} }\) and it is not dependent on x.

So the time period remains the same = 1 sec only and only is the spring - mass system is the same.

Hence, the time period remains the same = 1 sec.

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Answer:

1. Somewhat 2.Yes

Explanation:

Answer:

C,a

Explanation:

The gymnastic tumbler has a total kinetic energy of 0.9375 J, and 38.46% of that total kinetic energy is due to rotational motion.

What is kinetic energy?

Kinetic energy is the energy possessed by an object due to its motion. It is defined as the work required to accelerate an object of a certain mass from rest to its current velocity.

Given:

Mass of the tumbler (m) = 75 kg

Diameter of the tumbler (d) = 1.0 m

Angular velocity (ω) = 0.50 rev/s

The radius (r) of the tumbler is half of its diameter, so r = d/2 = 0.5 m.

Linear velocity (v) = ω * r

v = (0.50 rev/s) * (0.5 m)

v = 0.25 m/s

a) Total kinetic energy (K_total) of the tumbler consists of both translational and rotational kinetic energy. The translational kinetic energy (K_trans) can be calculated using the formula:

K_trans = (1/2) * m * v^2

K_trans = (1/2) * (75 kg) * (0.25 m/s)^2

K_trans = 0.9375 J

b) The rotational kinetic energy (K_rot) can be calculated using the formula:

K_rot = (1/2) * I * ω^2

I = (1/2) * m * r^2

I = (1/2) * (75 kg) * (0.5 m)^2

I = 4.6875 kg·m²

K_rot = (1/2) * (4.6875 kg·m²) * (0.50 rev/s)^2

K_rot = 0.5859 J

Percentage of rotational kinetic energy = (K_rot / K_total) * 100

Percentage of rotational kinetic energy = (0.5859 J / (0.9375 J + 0.5859 J)) * 100

Percentage of rotational kinetic energy ≈ 38.46%

Therefore, the gymnastic tumbler has a total kinetic energy of approximately 0.9375 J, and approximately 38.46% of that total kinetic energy is due to rotational motion.

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Answer:

Explanation:

7ün go up to the meaning of the name to the class finish it was in the picture of the meaning is F C B you send me your pic of clans go for a walk and 10 even though I am not say that you wake me up

The National Electric Code (NEC) identifies rigid metal conduit (RMC) as a wiring method, even though it is often referred to as galvanized rigid conduit (GRC).

If 11/2 RMC is threaded (screwed wrench-tight) together between boxes or enclosures, the maximum distance allowed between supports is 130 feet. This straight run of the conduit is almost 200 feet, so it would require additional support to ensure proper electrical performance and safety.

When determining the proper support spacing for a straight run of conduit, it is important to consider factors such as the weight of the conduit, the conductors inside, and the number of bends in the conduit. Too few supports can create sagging and tension, which can damage the insulation of the conductors and potentially cause a short circuit.

Too many supports can be costly and difficult to install. Therefore, it is important to understand the proper support spacing requirements and follow the NEC guidelines.

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To drag the box from point A to B on a horizontal surface using a horizontal force of 10 N, a work of 60 joules (J) must be done over a distance of 6 meters (m).

On a horizontal surface, if a box is dragged from point A to B by a horizontal force of 10 N, the work done can be calculated using the formula:

Work = Force x Distance

In this case, the force applied is 10 N and the distance between points A and B is 6 m.

Plugging these values into the formula, we get:

Work = 10 N x 6 m = 60 Nm

The unit for work is joules (J), so the work done in this scenario is 60 J.

When a force is applied to move an object, work is done.

The work done is calculated by multiplying the force applied by the distance over which the force is exerted.

In this case, the force applied is 10 N and the distance is 6 m.

Multiplying these values gives us the work done, which is 60 J.

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Answer: 5g/ml

Explanation:

Answer: B

Explanation: I answered this question already at my school.

Answer:

Explanation:

Statement A: Increasing a moving average window will enhance noise dampening.

Statement B: Decreasing a moving average window will enhance impulse response.

Statement C: Increasing the smoothing constant in exponential smoothing will enhance impulse response.

Statement D: Decreasing the smoothing constant in exponential smoothing will enhance noise dampening.

Let's evaluate each statement:

A. Increasing a moving average window will enhance noise dampening.

This statement is true. Increasing the window size of a moving average smooths out the fluctuations in the data and reduces the effect of noise, thus enhancing noise dampening.

B. Decreasing a moving average window will enhance impulse response.

This statement is false. Decreasing the window size of a moving average reduces the number of data points considered, leading to less smoothing and a faster response to changes in the data. It does not enhance impulse response.

C. Increasing the smoothing constant in exponential smoothing will enhance impulse response.

This statement is false. Increasing the smoothing constant in exponential smoothing increases the weight given to more recent data points, which results in smoother and more stable forecasts. It does not enhance impulse response.

D. Decreasing the smoothing constant in exponential smoothing will enhance noise dampening.

This statement is true. Decreasing the smoothing constant in exponential smoothing gives more weight to past observations, which helps in reducing the impact of noise and enhances noise dampening.

Based on the evaluation, 2 out of the 4 statements are correct.

Explanation:

The electromotive force acts when the magnetic field is applied to a current-carrying wire.

The electromotive force is given by the formula

Here, v is the velocity, q is the charge and theta is the angle between the magnetic field and direction of velocity.

The electromotive force will be maximum when the coil of wire is moving perpendicular to the magnetic field.

Thus, the correct option is a

Therefore, even though Europa has a diameter that is only one-fourth that of Earth, her ocean may hold twice the amount of water as Earth's seas do.The immense and unfathomably depths ocean of Europa is regarded as the best area to look for life outside of Earth.

As a result of the liquid water's close proximity to the silicate mantle, Europe is one of the finest options for habitability.The amount of radiation that strikes the moons from Jupiter is a crucial component in determining whether or not they are habitable.

Europa would need to contain the necessary chemical components for life's chemistry in order to be potentially habitable.These include the frequently occurring elements carbon, hydrogen, nitrogen, oxygen, phosphorus, and sulfur, which are thought to have been present on Europa at the time it originated.

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