80t²u(t) For a unity feedback system with feedforward transfer function as 60(s+34) (s+4) (s+8) G(s): s² (s+6) (s+17) The type of system is: Find the steady-state error if the input is 80u(t): Find the steady-state error if the input is 80tu(t): Find the steady-state error if the input is 80t²u(t): =

More x-rays are likely to be absorbed by or prevented from reaching the film by the enamel structure.

X-rays are a type of radiation that belong to the electromagnetic wave group. Your body's internal structures can be seen with the help of X-ray imagery. In a variety of black and white tones, the photos show the different body parts. Because distinct tissues absorb radiation in varying ways, this is the case. Calcium in bones most effectively absorbs X-rays, which is why bones look white. Soft tissues that don't absorb as much blood, like fat, can look gray. The least oxygen absorption causes the lungs to appear black. To image bodily tissues and aid in the diagnosis of illness, X-rays have long been used in the field of diagnostic radiology.

Know  more about X-rays here:

https://brainly.com/question/23281551

#SPJ4

Answer:

Explanation:

The missing diagram attached to the question is shown in the attached file below:

The very first thing we need to do in other to solve this question is to determine the mass of both the tractor and the mass of the gravel

For tractor, the mass is:

\(m_1 = \dfrac{2400 \ lb }{32.2 \ ft/s^2}\)

\(m_1 = 74.53 \ lb.s^2/ft\)

For gravel, the mass is:

\(m_2 = \dfrac{900 \ lb}{32.2 \ft/s^2}\)

\(m_2 = 27.95 \ lb.s^2/ft\)

From the diagram, let's consider the force along the horizontal components and vertical components;

So,

\(\sum F_x = ma_x \\ \\ 2F = (m_1+m_2) a \\ \\ F = \dfrac{1}{2}(74.53 4 + 27.950)lb.s^2/ft(2 \ ft/s^2) \\ \\ F = 102.484 \ lb\)

\(\sum F_y = 0 \\ \\ 2N_A+2N_B - 2400 -900 = 0 \\ \\ N_A +N_B = 1650 \ lb\)

Consider the algebraic sum of moments in the plane of A, with counter-clockwise moments being positive.

\(\sum M_A = I_o \alpha + \sum ma (d) \\ \\ = -2400 (20) + 2N_B (60) -900(110) = 0 - (74.534)(2)(20) - (27.950)(2)(40)\)

\(=-48000 + 2N_B (60) -99000 = -2981.36-2236 \\ \\ = + 2N_B (60) = -2981.36-2236+48000+99000 \\ \\ = + 2N_B (60) = 141782.64 \\ \\ N_B = \dfrac{141782.64}{120} \\ \\ N_B = 1181.522 \ lb\)

Replacing the value of 1181.522 lb for \(N_B\) in equation (1)

\(N_A\) + 1181.522 lb = 1650 lb

\(N_A\) = (1650 - 1181.522)lb

\(N_A\) = 468.478 lb

The net reaction on each of the rear wheels now is:)

\(F_R = \sqrt{N_A^2 +F^2}\)

\(F_R = \sqrt{(468.478)^2 + (102.484)^2}\)

\(\mathbf{F_R =479.6 \ lb}\)

Now, we can determine the angle at the end of the rear wheels at which the resultant reaction force is being made in line with the horizontal

\(\theta = tan ^{-1}( \dfrac{468.478 }{102.484})\)

\(\theta = 77.7^0\)

Finally, the net reaction on each of the front wheels is:

\(F_B = N_B\)

\(F_B =\) 1182 lb  

To determine the reactions at points A, B, and C, we will first need to analyze the forces and moments acting on the beam. Given that F1 = 450 N and F2 = 720 N, we can use the following steps:

1. Calculate the sum of the vertical forces, which should be equal to zero for static equilibrium:

ΣFy = Ay + By + Cy - F1 - F2 = 0

2. Calculate the sum of the moments about point A, which should also be equal to zero for static equilibrium:

ΣMA = (F1 * d1) + (F2 * d2) - (Cy * d3) = 0

Here, d1, d2, and d3 are the distances from point A to the points where the forces F1, F2, and Cy are applied.

3. Solve for the unknown reactions Ay, By, and Cy using the above equations.

Note that without the distances (d1, d2, and d3) or a diagram (Figure 1), it is not possible to provide specific numerical values for the reactions at A, B, and C.

learn more about analyze the forces here:

https://brainly.com/question/30815592

#SPJ11

Answer:

Trash rack

Open channel

Fore bay

Pen stock

Inlet valve

Turbine

Tailrace

Generator

Power house

Answer:

Area of square = 2,450 mm²

Explanation:

Given:

Length of diagonal = 70 mm

Find:

Area of square

Computation:

Area of square = diagonal² / 2

Area of square = 70² / 2

Area of square = 4900 / 2

Area of square = 2,450 mm²

❎❎❎❎❎❎❎ sorry but that didn't help me that much

An engineer would indicate the unit of measurement used in a design in millimeters.

The primary unit of measurement is the stocking unit of measure for a given item in a specific organization. You must define an item attribute that serves as the primary unit of measurement when creating each item.

Because the technical drawings are scaled, engineers, architects, and builders may create the items according to exact specifications.

When understanding scales, the number on the left relates to the measurement of the drawing, while the number on the right represents the actual size of the object.

Therefore, a millimeter is used in a design.

To learn more about measurements, refer to the link:

https://brainly.com/question/28390923

#SPJ1

The defining feature of the Metaverse is that it is Virtual. This is its a most distinctive feature. See further details below.

The Metaverse does not compete with the internet; rather, it expands upon it.

Users navigate a virtual environment that duplicates features of the actual world utilizing technologies such as virtual reality (VR), augmented reality, artificial intelligence (AI), social media, and digital money in the metaverse.

Metaverse features include digital avatars, remote working, developing decentralization, hardware, encryption, and many more.

Similarly, virtual places like Zoom only allow for a single conversation. Participants at physical events can transition seamlessly from one talk to the next. Some colleges are utilizing metaverse technology to bypass internet and video meeting tool constraints.

Learn more about the Metaverse:
https://brainly.com/question/5513926
#SPJ1

Answer:

Utilizing flush valves for toilets and urinals and/or low-flow versions of each, as well as installing low-flow faucets, or aerators can significantly reduce water use.

Explanation:

In this problem, we are given the terminal velocity \(V_f\) of a projectile, and we need to determine the distance traveled by the projectile when its speed has been reduced to 0.59\(V_0\). We are also given the equation for the terminal velocity of the projectile, which relates the dynamic viscosity η and the characteristic dimension σ to the terminal velocity \(V_f\).

The terminal velocity of the projectile is \(V_f\) = 3.90 m/s.

The equation for the terminal velocity of the projectile is:

σ = η\(V_f2\)

where:

\(V_f\) is the terminal velocity of the projectile

σ is the characteristic dimension of the projectile

η is the dynamic viscosity of the fluid through which the projectile is traveling

By solving for \(V_f\) in this equation, we can determine the terminal velocity of the projectile.

The distance traveled by the projectile when its speed has been reduced to 0.59\(V_0\) is given by:

y = \(V_0\) / 2σ ∫ 0 0.59\(V_0\) (σ - η\(V_2\)) dv

where:

y is the distance traveled by the projectile

\(V_0\) is the initial velocity of the projectile

σ is the characteristic dimension of the projectile

η is the dynamic viscosity of the fluid through which the projectile is traveling

y = \(V_0\) / 2σ ∫ 0 0.59\(V_0\) (σ - η\(V_2\)) dv

y = \(V_0\) / 2σ [(σv - η/3\(V_3\)) | 0 to 0.59\(V_0\)]

y = \(V_0\) / 2σ [1.86(0.59\(V_0\)) - 0.19(1/3)(0.59\(V_0\))3]

y = \(V_0\) / 2σ [1.1\(V_0\) - 0.0073\(V_03\)]

y = 0.527\(V_0\)

Therefore, for \(V_0\) = 5.6 m/s, the distance traveled by the projectile when its speed has been reduced to 0.59\(V_0\) is y = 2.937 m.

The terminal velocity \(V_f\) of the projectile is given by the equation:

σ = ηvf2

\(V_f\) = √(σ / η)

\(V_f\) = √(1.86 / 0.19)

\(V_f\) = 3.90 m/s

Therefore, the terminal velocity of the projectile is \(V_f\) = 3.90 m/s.

Learn more about projectile:

https://brainly.com/question/24097127

#SPJ4

Answer:

What’s the most important reason we should need a mask?

we were because it protects us from germs and viruses.

Is the ban on removal of the mask requirement being implemented too fast in an area without general consensus (moral, political, cultural, technological)?

Face coverings limit the volume and travel distance of expiratory droplets dispersed when talking, breathing, and coughing.

This is going to be a long one, here is all of the definitions:

Habitat - The natural home or environment of an animal, plant, or other organism.

Traits - A distinguishing quality or characteristic, typically one belonging to a person.

Pollination - The transfer of pollen to a stigma, ovule, flower, or plant to allow fertilization.

Ecosystem - A biological community of interacting organisms and their physical environment.

Biosphere Ecology - The regions of the surface, atmosphere, and hydrosphere of the earth (or analogous parts of other planets) occupied by living organisms.

Community Ecology - A group of interdependent organisms of different species growing or living together in a specified habitat.

Pollinators - The organisms that pollinate plants, like a bee.

Plant Reproduction - The process by which plants generate new individuals, or offspring.

Environment - The surroundings or conditions in which a person, animal, or plant lives or operates.

Pollen - A fine powdery substance, typically yellow, consisting of microscopic grains discharged from the male part of a flower or from a male cone.

Chromosomes - A threadlike structure of nucleic acids and protein found in the nucleus of most living cells, carrying genetic information in the form of genes.

Heredity - The passing on of physical or mental characteristics genetically from one generation to another.  In other words, these traits cannot be changed.

Ecology - The branch of biology that deals with the relations of organisms to one another and to their physical surroundings.

DNA - Deoxyribonucleic acid, a self-replicating material which is present in nearly all living organisms as the main constituent of chromosomes. It is the carrier of genetic information.

Population Ecology - A community of animals, plants, or humans among whose members interbreeding occurs.

Answer: the cancer risk for an adult male drinking the water for 10 years is 2.88 × 10⁻⁶

Explanation:

firstly, we find the time t required to travel for the contaminant to the well;

Given that, contamination flowing rate = 0.5 ft/day

Distance of well from the site = 1 mile =  5280 ft

so t = 5280 / 0.5 = 10560 days

k is given as 1.94 x 10⁻⁴ 1/day

next we find the Pollutant concentration Ct in the well

Ct = C₀ × e^-( 1.94 x 10⁻⁴ × 10560)

Ct = 0.3 x e^-(kt)  

Ct= 0.0386 mg/L

next we determine the chronic daily intake, CDI

CDI =  (C x CR x EF x ED) / (BW x AT)

where C is average concentration of the contaminant(0.0368mg/L), CR is contact rate (2L/day), EF is exposure frequency (350days/Year), ED is exposure duration (10 years), BW is average body weight (70kg).

now we substitute  

CDI = (0.0368 x 2 x 350 x 10) / ((70x 365) x 70)

= 257.7 / 1788500

= 0.000144 mg/Kg.day

CDI = 1.44 x 10⁻⁴ mg/kg.day  

Finally we calculate the cancer risk, R

Slope factor SF is given as 0.02 Kg.day/mg

Risk, R = I x SF

= 1.44 x 10⁻⁴ mg/kg.day  x 0.02Kg.day/mg    

R = 2.88 × 10⁻⁶

therefore the cancer risk for an adult male drinking the water for 10 years is 2.88 × 10⁻⁶

The calculated thrust that we are required to find in this question are solved as:

Rate = excess power / weight

= dn / dt

= V∞sin θ

V∞sin θ = Tn - Tr / w * V∞

sin θ  = Tn - D / w

Tr = D

sin θ = T / w - D / w

T / w = sin θ + D / w

We would have the formula here as

ma x √vRTw

= 0.85 x √1.4 x 287 x 226.73

= 256.5 m/s

Next we have to solve for the angle of climb

∅ = sin⁻¹ (1.524 / 256.5)

= 5.94 x 10⁻³

T = w (θ + 1/10)

= 2446521.9 * 5.94 x 10⁻³ * 1/18

= 150.45

The static thrust at the sea level = 2446521.9 / 18

= 135.917 N

Therefore the required thrust at the cruising altitude is equal to  150.45

while the corresponding thrust at the sea level is equal to 135.917 N

Read more on  static thrust  here

https://brainly.com/question/426110

#SPJ1

The center of gravity, also known as the balance point or point of rotation when an object is permitted to freely rotate, is the average location of an object's weight.

All objects with mass are attracted to one another by the gravitational attraction, which has a magnitude that is directly proportional to the masses of the two objects and inversely proportional to the square of their distance from one another.

By means of gravity, a planet or other body pulls items toward its core. All the planets are maintained in their orbits around the sun by the force of gravity.

Any particle of matter in the universe will gravitate toward any other with a force that varies directly as the product of the masses and inversely as the square of the distance between them, according to Newton's law of gravity.

To learn more about Gravity refer to:

https://brainly.com/question/940770

#SPJ9

To determine the velocity of block A after it has moved 4 m, we can use the principles of Newton's laws of motion and energy conservation. Here are the moves toward tackle the issue:

1. First, draw a free-body diagram for each block. Block A experiences weight (mg) downward, tension (T) upward, and friction (f) opposing its motion. Block B experiences weight (2mg) downward and tension (T) upward.

2. Apply Newton's second law of motion to both blocks. For Block A, we have the equation:

  T - f = ma     (Equation 1)

  For Block B, we have:

  2mg - T = 2ma   (Equation 2)

3. The erosion power can be determined as:

  f = μN

  N = mg (normal force)

  Therefore, f = μmg, where μ is the coefficient of friction.

4. Use the constraint equation due to the inextensible cable:

  s = rθ

  where s is the distance traveled by block A, r is the radius of the pulley (unknown), and θ is the angle in radians subtended by the arc on the pulley.

5. Apply conservation of energy:

  The change in potential energy is equal to the change in kinetic energy for block A.

  mgh = (1/2)mv^2

  Solving for v, we get:

  v = √(2gh)

6. Use the given information that block A has moved 4 m to determine the angle θ and the radius r using the constraint equation.

7. Substitute the values of μ, m, g, and h into the equation for v to calculate the velocity of block A after it has moved 4 m.

By following these steps, you can find the velocity of block A after it has moved 4 m. Remember to double-check your calculations and units to ensure accurate results.

For more such questions on velocity, click on:

https://brainly.com/question/80295

#SPJ11

The Web server software accepts HTTP requests from Web browsers connected to the Internet. HTTP (Hypertext Transfer Protocol) is the protocol used for communication between web servers and clients (web browsers).

When a user types a web address or URL into their browser, the browser sends an HTTP request to the web server to retrieve the requested web page. The web server then responds to the request by sending back an HTTP response, which includes the requested web page content. ARP (Address Resolution Protocol) is used for mapping IP addresses to MAC addresses on a local network, while NAT (Network Address Translation) is used to translate private IP addresses to public IP addresses for internet communication. DHCP (Dynamic Host Configuration Protocol) is used to automatically assign IP addresses to devices on a network. In summary, the Web server software only accepts HTTP requests from Web browsers connected to the Internet. It is essential to have a good understanding of HTTP, as it is the foundation of modern web development and a critical aspect of web hosting.

Learn more about Hypertext Transfer Protocol here-

https://brainly.com/question/3308534

#SPJ11

Answer:

A pointer is spun on a fair wheel of chance having its periphery labeled Trom 0 to 100. (a) Whhat is the sample space for this experiment? (b)What is the probability that the pointer will stop between 20 and 35? (c) What is the probability that the wheel will stop on 58?

​

Explanation:

thats all you said

Answer:

hii my name is RAGHAV what is your name

Explanation:

this question is which chapter

The value of RL in ohms cannot be determined without more information about the circuit. However, the maximum average power delivered to RL is infinite according to the maximum power transfer theorem.

In Fig. 10.24, the variable resistor in the circuit is adjusted until maximum average power is delivered to RL. This means that the resistance of the variable resistor is adjusted until the maximum amount of power is transferred from the source to the load resistor. To find the value of RL in ohms, we need more information about the circuit. However, we can calculate the maximum average power delivered to RL.

The formula for average power is P=V^2/R, where P is power, V is voltage and R is resistance. We know that the power delivered to the load is at its maximum, so we can use the maximum power transfer theorem which states that the maximum power is transferred when the load resistance equals the source resistance. In this case, the load resistance is RL and the source resistance is the internal resistance of the source, which we can assume to be negligible.

Using the formula for maximum power transfer, we can calculate the value of RL that results in maximum power transfer. RL = Rsource = 0 (since we assumed the internal resistance of the source to be negligible).

Substituting this value into the formula for average power, we get Pmax = V^2/RL = V^2/0 = ∞. This means that the maximum average power delivered to RL is infinite. However, in reality, there are practical limitations to the amount of power that can be transferred and this calculation assumes ideal conditions.

In summary, the value of RL in ohms cannot be determined without more information about the circuit. However, the maximum average power delivered to RL is infinite according to the maximum power transfer theorem.

Learn more on variable resistor here:

https://brainly.com/question/15146292

#SPJ11

Answer: Most master’s degree programs will take an average of two years from start to finish – about half of the time it takes to earn your bachelor’s degree. While bachelor’s degree programs involve many introductory and general education courses, a master’s degree curriculum is all about the subject area you selected to study.

Explanation: Hope this was helpful

Answer:

Explanation:

From the given information:

Addition of all the materials = 65+ 36+ 5 +6 = 112  which is higher than 100 percentage; SO we need to find;

The actual percentage of each material which can be determined as follows:

Percentage of the coarse aggregate will be = 65 × 112/100

= 72.80%

Percentage of the Fine aggregate will be = 36 × 112/100

= 40.32%

Percentage of the filler  will be = 5 × 112/100

= 5.6%

Percentage of the   asphalt binder will be = 6 × 112/100

= 6.72 %

So; the theoretical specific gravity (Gt) of the mixture can be calculated as follows:

Gt = 100/( 72.80/2.635 + 40.32/2.710 + 5.6/2.748 + 6.72/1.088)

Gt = 100/( 27.628 + 14.878 + 2.039 + 6.177)

Gt = 100/ (50.722)

Gt =1.972

Also;Given that the bulk density = 143.9 lb/ft³

LIke-wsie ; as we know that unit weight of water is =62.43lb/cu.ft

Hence, the bulk specific gravity of the mix (Gm) = 143.9/62.43

=2.305

The percentage of air  void  = (Gt -Gm )× 100/ Gt

= (1.972 - 2.305) ×  100/ 1.972

= -16.89%

The percentage of the asphalt binder is =(6.72/1.088*100)/(72.80+40.32+5.6+6.72)/2.305)

= 617.647/54.42

= 11.35%

Thus; the percentage voids in mineral aggregate =  -16.89% + 11.35%

the percentage voids in mineral aggregate = -5.45%

The percent voids filled with asphalt. = 100 × 11.35/-5.45

The percent voids filled with asphalt = - 208.26 %

The Airline Tariff Publishing Company (ATPCO) is an airline clearing house that is used by airlines to publish and distribute fares and cargo rates to the travel industry.

What is airline?
The structure and size of airlines differ. Others lease the aircraft for a set amount of time while hiring workers from other businesses, while some purchase the aircraft to provide special services. Typically, it is scheduled from one location to another. Worldwide, airlines play a significant role in the travel business. In order to make the route flexible and accessible, they frequently use jets and helicopters. People frequently mistakenly believe that the airline industry and aviation are interchangeable, which is not the case. It's important to note that the aviation industry includes all businesses related to aviation, including aircraft manufacturers, providers of non-commercial flights, regulatory bodies, aerospace firms, and others. The airline industry, on the other hand, refers to businesses that offer air transport services to paying customers or even for cargo services.

To learn more about airline
https://brainly.com/question/28749965
#SPJ4

The stress at elastic limit is 1.27 N/mm^2, the Young's modulus is 254 N/mm^2, the percentage elongation is 57.5%, the percentage reduction in area is 97.44%, and the ultimate tensile stress is 696.67 N/mm^2.

Stress = Force / Area

Young's modulus = Stress / Strain

Percentage elongation = (extension / gauge length) x 100%

Percentage reduction in area = [(original area - area at neck) / original area] x 100%

Ultimate tensile stress = Maximum load / Area

Diameter of specimen = 100 mm

Gauge length = 100 mm

Extension at 70 KN load = 0.50 mm

Load at elastic limit = 10 KN

Maximum load = 140 KN

Total extension at fracture = 58 mm

Diameter at neck = 16 mm

We can calculate the area of the specimen as follows:

Area = π/4 x d^2

Area = π/4 x (100 mm)^2

Area = 7853.98 mm^2

The stress at elastic limit can be calculated as:

Stress = Load / Area

Stress = 10 KN / 7853.98 mm^2

Stress = 1.27 N/mm^2

The Young's modulus can be calculated as:

Strain = Extension / Gauge length

Strain = 0.50 mm / 100 mm

Strain = 0.005

Stress = Load / Area

Load = Stress x Area

Load = 1.27 N/mm^2 x 7853.98 mm^2

Load = 9982.16 N

Young's modulus = Stress / Strain

Young's modulus = 1.27 N/mm^2 / 0.005

Young's modulus = 254 N/mm^2

The percentage elongation can be calculated as:

Percentage elongation = (extension / gauge length) x 100%

Percentage elongation = (58 mm - 0.50 mm) / 100 mm x 100%

Percentage elongation = 57.5%

The percentage reduction in area can be calculated as:

Original area = π/4 x (100 mm)^2 = 7853.98 mm^2

Area at neck = π/4 x (16 mm)^2 = 201.06 mm^2

Percentage reduction in area = [(original area - area at neck) / original area] x 100%

Percentage reduction in area = [(7853.98 mm^2 - 201.06 mm^2) / 7853.98 mm^2] x 100%

Percentage reduction in area = 97.44%

The ultimate tensile stress can be calculated as:

Area at neck = π/4 x (16 mm)^2 = 201.06 mm^2

Ultimate tensile stress = Maximum load / Area

Ultimate tensile stress = 140 KN / 201.06 mm^2

Ultimate tensile stress = 696.67 N/mm^2

Therefore, the stress at elastic limit is 1.27 N/mm^2, the Young's modulus is 254 N/mm^2, the percentage elongation is 57.5%, the percentage reduction in area is 97.44%, and the ultimate tensile stress is 696.67 N/mm^2.

Learn more about stress on;

https://brainly.com/question/11819849

#SPJ1

Answer:

Question 1 A 1020 Cold-Drawn steel shaft is to transmit 20 hp while rotating at 1750 rpm. Calculate the transmitted torque in lbs. in. Ignore the effect of friction. Answer with three decimal points. 60.024 Question 2 Based on the maximum-shear-stress theory, determine the minimum diameter in inches for the shaft in Q1 to provide a safety factor of 3. Assume Sy = 57 Kpsi. Answer with three decimal points. 0.728 Question 3 If the shaft in Q2 was made of ASTM 30 cast iron, what would be the factor of safety? Assume Sut = 31 Kpsi, Suc = 109 Kpsi 0 2.1 O 2.0 O 2.5 0 2.4 2.3 O 2.2

Explanation:

hope it helps

Answer:

c Many transportation industries were deregulated.

Explanation:

correct on edge 2022

Approximately 6.6% of the incident power is dissipated in the medium after traveling a distance of 96 mm.

The attenuation constant, denoted by α, represents the rate at which a wave's power decays as it propagates through a medium. In this scenario, the given attenuation constant is α = 0.7 Np/m. To determine the percentage of incident power dissipated in the medium after traveling a distance of 96 mm, we need to calculate the power attenuation over that distance.

The power attenuation can be expressed using the formula\(P = P0 * e^(-2αz)\), where P0 is the initial power and z is the distance traveled. Plugging in the values, we have \(P = P0 * e^(-2*0.7*0.096).\)

To find the percentage of incident power dissipated, we compare the attenuated power P with the initial power P0. The dissipated power can be calculated as \(P_dissipated = P0 - P\). The percentage of dissipated power relative to the incident power is then given by\((P_dissipated / P0) * 100.\)

By performing the calculations, we find that approximately 6.6% of the incident power is dissipated in the medium after traveling a distance of 96 mm.

It is important to note that the attenuation constant varies for different materials and frequencies. Additionally, other factors such as reflection, refraction, and scattering can also contribute to power loss in real-world scenarios.

Learn more about Distance

brainly.com/question/31713805

#SPJ11