9. Two gears are pressed together. The smaller gear is being poweredby a motor and has a constant tangential velocity of 0.2 m/s at itsedge. The radius of the smaller gear is r and the radius of the largergear is 31a. What is the angular velocity of the larger gear, in terms of r?Coin 2-0.06 roadsV = wrsrb. The smaller gear's angular velocity is doubled. How does thataffect the angular velocity of the large gear? Show your work and explain your answer

Since the initial linear momentum of the system is 0, the linear momentum of the gun-arm system must be equal in magnitude and opposite in direction to the linear momentum of the bullet.

Find the linear momentum of the bullet:

If the gun-arm system recoils with a speed v, the total linear momentum of the gun-arm system is:

Since the linear momentum of the gun-arm system must have the same magnitude as the linear momentum of the bullet, then:

Isolate v and find its value:

Therefore, the recoil speed of the shotgun and arm-shoulder combination is 0.8 meters per second.

The frequency is the inverse of time period of a wave and the time period of a wave is the time taken divided by number of cycles or wave.

A wave is a propagating dynamic disturbance of different quantities. Frequency is the number of waves which are passing by a specific point of time per second. And, time period is the time which the wave takes for one wave cycle to complete.

Frequency of a wave can be calculated by reciprocal of time taken.

Frequency of a wave = 1/ Time period

The time period is the time in which one wave.

9. The time period of the wave = Time taken/ Number of waves or cycles

Time period = 4/ 8

Time period = 1/2 or 0.5 sec

Frequency of a wave = 1/ T

Frequency of a wave = 1/ 0.5 = 2⁻¹

10. The time period of the pendulum's oscillations = 4/ 12 = 1/3 = 0.33 sec

The frequency of the pendulum's oscillations = 3.03 sec⁻¹

11. Speed of a wave = wavelength of a wave × frequency of the wave

Speed of a wave = 3 × 2

Speed of a wave = 6 meters per second

12. Wavelength of the wave will be the ratio of speed of the wave and frequency of the wave.

Wavelength (λ) = Speed of the wave (v)/ frequency of the wave (f)

Wavelength = 340/ 20

Wavelength = 170 meters

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Answer:

j120

Explanation:

qll energy for residential is 120 and that's what ruffly is always used for wiring

Answer: 2, -2

Explanation:

5th answer: Slop= (9-1)÷(5-1) = 2

6th answer: Slop= (6-0)÷(-3-0) = -2

Answer:

umm it says he but I'm a she :p

Vehicles need to be serviced for several reasons such as preventing costly repairs and improving fuel economy.

First, regular maintenance can help to prevent costly repairs down the road. Second, maintenance can help to improve fuel economy and emissions. Third, maintenance can help to keep your vehicle safe and reliable.

The servicing requirements for petrol/diesel and electric vehicles differ in a number of ways. Petrol/diesel vehicles require oil changes more frequently than electric vehicles. This is because petrol/diesel engines use oil to lubricate the moving parts, while electric motors do not. Petrol/diesel vehicles also require tune-ups more frequently than electric vehicles.

This is because petrol/diesel engines have more moving parts that need to be synchronized, while electric motors have fewer moving parts.

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Answer:

w=fx

w=(15)(5)

w=75

the angle between the deplacement and N is 0

Answer:

0.1667 meters/second.

Explanation:

To find Jibari's average velocity for the trip, we need to first calculate his average velocity for each leg of the trip. To do this, we need to divide the distance he traveled by the time it took him to travel that distance.

For the first leg of the trip, Jibari walked 40.0 meters east in 120.0 seconds. His average velocity for this leg of the trip is therefore 40.0 meters / 120.0 seconds = 0.3333 meters/second east.

For the second leg of the trip, Jibari walked 30.0 meters west in 60.0 seconds. His average velocity for this leg of the trip is therefore 30.0 meters / 60.0 seconds = 0.5000 meters/second west.

To find Jibari's average velocity for the entire trip, we need to add the velocities for each leg of the trip, taking into account their direction. Since the first leg of the trip was east and the second leg was west, we can simply add the two velocities together to find the overall average velocity.

Jibari's overall average velocity for the trip is therefore 0.3333 meters/second east + 0.5000 meters/second west = 0.1667 meters/second.

Therefore, Jibari's average velocity for the trip was 0.1667 meters/second.

Jibari's average velocity for the trip is 0.7 m/s east.

To solve for Jibari's average velocity, we will first need to find his total displacement. We can do this by adding the magnitudes of his eastward and westward displacements. The magnitude of Jibari's eastward displacement is 40.0 meters, and the magnitude of his westward displacement is 30.0 meters. So, his total displacement is

40.0 - 30.0 = 10.0 meters east.

We can then find Jibari's average velocity by dividing his total displacement by the total time it took him to complete the trip. The total time it took Jibari to complete the trip is

120.0 + 60.0 = 180.0 seconds.

So, his average velocity is

10.0 / 180.0 = 0.7 m/s east.

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Answer:

0.002kg and 0.01cm

Explanation:

500 leaves has a thickness is 5cm

Means I leaf has a thickness of 5/500= 0.01cm

Similarly the mass of one leaf would be 1/500 =0.002kg

Answer:

The car does not hit the deer.

Explanation:

In order to find out, whether the car stops before hitting the dear or not, we will use 3rd equation of motion.

2as = Vf² - Vi²

where,

s = distance covered by car before stopping = ?

a = deceleration of car = - 4.2 m/s²

Vf = Final Velocity of the Car = 0 m/s (Since, the car finally stops)

Vi = Initial Velocity of the Car = 25 m/s

Therefore,

2(- 4.2 m/s²)s = (0 m/s)² - (25 m/s)²

s = (- 625 m²/s²)/(-8.4 m/s²)

s = 74.4 m

So, the car stops in 74.4 m, while the deer is at a distance of 75 m.

Hence, the car does not hit the deer.

Using third equation of kinematics

\(\boxed{\sf v^2-u^2=2as}\)

\(\\ \sf\longmapsto (0)^2-(25)^2=2(-4.2)s\)

\(\\ \sf\longmapsto -625=-8.4s\)

\(\\ \sf\longmapsto 8.4s=625\)

\(\\ \sf\longmapsto s=\dfrac{625}{8.4}\)

\(\\ \sf\longmapsto s=74.4m\)

Answer:

The inductance is  \(L = 0.1097 \ H\)

Explanation:

From the question we are told that

  The  length is  \(l = 0.65 \ m\)

   The  diameter is  \(d = 3.2 cm = 0.032 \ m\)

    The  number of loops is  \(N = 8400\)

Generally the radius is evaluated as

       \(r = \frac{ 0.032 }{2} = 0.016 \ m\)

The  inductance is mathematically represented as

      \(L = \frac{ \mu_o * N^2 * A }{ l }\)

Here \(\mu_o\) is the permeability of free space with value  \(\mu_o = 4\pi * 10^{-7} N/A^2\)

A is the cross-sectional area which is mathematically evaluated as

             \(A = \pi r^2\)

=>        \(A = 3.142 * (0.016)^2\)

=>        \(A = 0.000804 \ m^2\)

 =>  \(L = \frac{ 4\pi * 10^{-7} * 8400^2 * 0.000804 }{ 0.65 }\)

=>    \(L = 0.1097 \ H\)

Answer:

The correct answer is "1080 W".

Explanation:

Given:

Current,

I = 9.0 A

Potential difference,

V = 120 volt

As we know,

⇒ \(Power=IV\)

On substituting the values, we get

⇒             \(=120\times 9.0\)

⇒             \(=1080 \ W\)

Answer:

The  compression is  \(x = 0.05 \ m\)

Explanation:

From the question we are told that

     The first velocity is  v

     The  compression of the spring is  \(d = 1.0 \ cm = 0.01 \ m\)

      The  second velocity is  4v

Generally according to the law of  energy conservation

   The  kinetic energy of the block is equal to the energy stored in the spring that is  

       \(\frac{1}{2} * m* v^ 2 = \frac{1}{2} * k * d^2\)

For  first speed

      \(m* v^ 2 = k * 0.01^2\)

=>   \(m* v^ 2 = k * 0.0001\)

=>  \(k = \frac{ m v^2 }{ 0.0001}\)

For second  speed

       \(\frac{1}{2} * m* (5v)^ 2 = \frac{1}{2} * k * x^2\)

=>    \(12.5mv^2 = 0.5 k x^2\)

substituting for k

=>    \(12.5mv^2 = 0.5 (\frac{mv^2}{0.0001} ) x^2\)

=> \(12.5 = 5000x^2\)

=>  \(x = 0.05 \ m\)

Answer:

True

Explanation:

Answer:

how close to the true value a measurement is

The patellar reflex happens when there is a sudden change in muscle length; in this situation, the tendon velocity is stretched as a result of the application of the hammer stroke [3, 4].

The deep tendon reflexes are ordinarily ranked as follows: The response of zero is always abnormal. 1+ indicates a weak but unmistakably present response; this could or could not be typical. Fast response; 2+; considered usual.

If your knee doesn't respond, what does that mean?

A symptom of hyporeflexia is a diminished or nonexistent reflex reaction in your skeletal muscles. Damage to any area of your reflex arc—which may have occurred as a result of an underlying medical condition—causes it to occur.

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We can use conservation of momentum and conservation of energy to solve this problem.

Let v be the initial speed of the bullet. After the collision, the bullet and the block move together with the same velocity v_f. Conservation of momentum gives:

m_bullet * v = (m_bullet + m_block) * v_f

where m_bullet and m_block are the masses of the bullet and the block, respectively. Substituting the given values, we get:

0.0115 kg * v = (0.0115 kg + 0.2500 kg) * v_f

Simplifying, we get:

v_f = 0.0115 kg * v / 0.2615 kg = 0.0404 v

Now, let's consider the energy of the system. At the moment of maximum compression of the spring, all the initial kinetic energy of the bullet is converted into elastic potential energy stored in the spring. Therefore:

(1/2) * (m_bullet + m_block) * v_f^2 = (1/2) * k * x^2

where k is the spring constant, x is the amplitude of the oscillation (which is half the distance the block travels back and forth), and we use the fact that the kinetic energy of the block is negligible compared to that of the bullet. Substituting the given values, we get:

(1/2) * 0.2615 kg * (0.0404 v)^2 = (1/2) * 2.25 * 10^3 N/m * (0.124 m)^2

Simplifying, we get:

v^2 = 2.25 * 10^3 N/m * (0.124 m)^2 / (0.0115 kg + 0.2500 kg) / (0.0404)^2

Taking the square root, we get:

v = 254 m/s (rounded to three significant figures)

Therefore, the initial speed of the bullet was approximately 254 m/s.

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Answer:

earth is not the center of the universe

Explanation:

i just took the test

Kepler's laws allow us to find that the correct answer, the basis is these is

 d) Earth is not the center of the universe.

Kepler made extensive measurements and created a mathematical model of the movement of the planets around the sun, these analyzes are written in the form of three laws

                \(T^2 = ( \frac{4\pi ^2}{G M_s} ) \ a^3\)

Where T is the period, a the major axis, G the universal gravitational constant and \(M_s\) the most of the sun.

When analyzing these Kepler's laws in all the sun is the center of movement.

Let's analyze the different claims;

a) False. The laws are not on a specific planet

b) False. Gravity is not in Kepler's laws

c) False. A ratio of the masses between planets and the sun is not established

d) True. In the laws the sun is the center of movement, therefore the earth is not the center of the universe.

In conclusion using Kepler's laws we can find that the correct answer for the bases of these is:

 d) Earth is not the center of the universe.

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The initial momentum of the 25 kg object is 25 kg * 12 m/s = 300 kgm/s. After the collision, the momentum of the 25 kg object is 25 kg * 8 m/s = 200 kgm/s. According to the conservation of momentum, the momentum lost by the 25 kg object is equal to the momentum gained by the box. Therefore, the resulting momentum of the box is 300 kgm/s - 200 kgm/s = 100 kg*m/s.

Answer:

You mean in periods.

They have the same number of elctron shells.

But if they are in the same group then they have the sane number oifValence electrons.

Explanation:

The flaps increase the mass of the cargo as the engineering students install flaps that extend off the cargo load to maximize drag force during landing and prevent their cargo from opening on landing.

Newton's second law states that force is proportional to mass and acceleration.

F = m a

The applied force creates an acceleration in the elephant a = F / m. If the mass of the elephant increases m2> m, the expression takes the form a = F / m2. With the denominator is greater the acceleration should decrease by the same factor that increases the mass.

The frequency of a wave depends on the properties of medium density and the elasticity properties change the amplitude depends on the energy carried by the wave, that is, the amplitude is proportional to the height of the wave (oscillation).

Therefore, The flaps increase the mass of the cargo as the engineering students install flaps that extend off the cargo load to maximize drag force during landing and prevent their cargo from opening on landing.

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The magnitude of the magnetic field B must change at a rate of approximately -2.6675 T/s to induce a current of 0.1 A in the windings of the coil.

To find the rate at which the magnitude of the magnetic field B must change, we can use Faraday's law of electromagnetic induction. The formula is:

EMF = -N * (ΔΦ/Δt)

where EMF is the induced electromotive force, N is the number of turns in the coil, ΔΦ is the change in magnetic flux, and Δt is the change in time.

We know that EMF = I * R, where I is the induced current and R is the resistance. In this case, I = 0.1 A and R = 8 Ω, so:

EMF = 0.1 A * 8 Ω = 0.8 V

Now we can find the change in magnetic flux (ΔΦ). The magnetic flux (Φ) through a rectangular coil is given by:

Φ = B * A

where A is the area of the coil. The area of the rectangular coil is 5 cm * 8 cm = 40 cm², or 0.004 m² when converted to square meters.

Since we want to find ΔΦ/Δt, we can rearrange Faraday's law:

ΔΦ/Δt = -EMF / N

Plugging in the values, we get:

ΔΦ/Δt = -0.8 V / 75 turns = -0.01067 Vs/turn

Now we can find the rate of change of the magnetic field (ΔB/Δt):

ΔB/Δt = (ΔΦ/Δt) / A

ΔB/Δt = -0.01067 Vs/turn / 0.004 m² = -2.6675 T/s

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Answer:

7 m/s

Explanation:

Answer: 25 m/s

Explanation:

Use formula acceleration = velocity final - velocity initial divided by time

A = 7 m/s^2

Vf = 60 m/s

Vi =

t = 5 sec

7 = 60 - x/5

Multiply both sides by 5

35 = 60 - x

Subtract 60 from both sides

-25 = -x

x = 25

Vi = 25 m/s

The object with the greatest kinetic energy is the locomotive engine (option C)

To know the object with the greatest kinetic energy, we shall determine the kinetic energy of each objects. Details below:

For truck:

KE = ½mv²

KE = ½ × 3500 × 30²

KE = 1575000 J

For baseball:

KE = ½mv²

KE = ½ × 0.5 × 46.9²

KE = 549.90 J

For locomotive:

KE = ½mv²

KE = ½ × 205000 × 5²

KE = 2562500 J

For person:

KE = ½mv²

KE = ½ × 73 × 6²

KE = 1314 J

From the above calculations, we can see that the locomotive has the greatest kinetic energy. Thus, the correct answer is option C

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Answer:

\(\mathbf{S^{\to} (x,t) = \dfrac{{E_o} {B_o}}{\mu_o} sin^2 (kx -wt) \hat i }\)

Explanation:

Consider:

\(E^{\to} =E_o \ Sin (kx - wt) \hat j\)

\(B^{\to} =B_o \ Sin (kx - wt) \hat k\)

The equation for the Poynting vector is given as:

\(S^{\to} (x,t) = \dfrac{E^{\to}\times B^{\to}}{\mu_o}\)

\(S^{\to} (x,t) = \dfrac{E_o \ Sin(kx - wt) \hat j \times B_o sin (kx -wt) \hat k}{\mu_o}\)

\(S^{\to} (x,t) = \dfrac{{E_o} {B_o}}{\mu_o} sin^2 (kx -wt) (\hat j \times \hat k)\)

\(S^{\to} (x,t) = \dfrac{{E_o} {B_o}}{\mu_o} sin^2 (kx -wt) \hat i\)

∴

\(\mathbf{S^{\to} (x,t) = \dfrac{{E_o} {B_o}}{\mu_o} sin^2 (kx -wt) \hat i }\)

Answer:

7000J

Explanation:

Given parameters:

Mass of car  = 1400kg

Initial speed  = 10m/s

Final speed  = 20m/s

Unknown:

Amount of work done  = ?

Solution:

In this problem, the amount of work done is the same as the change in kinetic energy of the body.

So;

   Work done  = Final kinetic energy  - initial kinetic energy

           Kinetic energy  = \(\frac{1}{2}\)  m v²

   Work done  = \(\frac{1}{2}\)  m(V²f - V²i )

m is the mass

vf is the final velocity

vi is the initial velocity

   Work done  =  \(\frac{1}{2}\) x 1400 x (20 - 10)  = 7000J