A 0.050 kg metal bolt is heated to an unknown initial temperature. It is then dropped into calorimeter containing 0.15 kg of water with an initial temperature of 21.0°C. The bolt and the water then reach a final temperature of 25.0°C. If the metal has a specific heat capacity of 899 J/kg•°C, find the initial temperature of the metal.

Answers

Answer 1

The initial temperature of the metal bolt is 80.8 °C

We'll begin by calculating the heat absorbed by the water.

Mass of water (M) = 0.15 Kg Initial temperature (T₁) = 21 °CFinal temperature (T₂) = 25 °CChange in temperature (ΔT)  = T₂ – T₁ = 25 – 21 = 4 °CSpecific heat capacity of water (C) = 4184 J/KgºCHeat absorbed (Q) =?

Q = MCΔT

Q = 0.15 × 4184 × 4

Q = 2510.4 J

Finally, we shall determine the initial temperature of the metal bolt.

Heat absorbed by water = 2510.4 JHeat released by metal (Q) = –2510.4 JMass of metal (M) = 0.050 Kg Final temperature (T₂) = 25 °CSpecific heat capacity of metal (C) = 899 J/Kg°CInitial temperature (T₁) =?

Q = MC(T₂ – T₁)

–2510.4 = 0.050 × 899 (25 – T₁)

–2510.4 = 44.95 (25 – T₁)

Clear bracket

–2510.4 = 1123.75 – 44.95T₁

Collect like terms

–2510.4 – 1123.75 = –44.95T₁

–3634.15 = –44.95T₁

Divide both side by –44.95

T₁ = –3634.15 / –44.95

T₁ = 80.8 °C

Thus, the initial temperature of the metal is 80.8 °C.

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Related Questions

A 0.842g sample of Hydrogen 3 decays until 0.0526g remains. How many half lives have occurred?

Answers

A 0.842g sample of Hydrogen-3 decays to 0.0526g. Approximately 4.206 half-lives have occurred.

To determine the number of half-lives that have occurred, we can use the decay equation and the concept of exponential decay. The decay equation for radioactive decay is given by:

N(t) = N₀ * (1/2)^(t/T),\((1/2)^(^t^/^T^),\)

where N(t) is the remaining amount of the substance at time t, N₀ is the initial amount, t is the time elapsed, and T is the half-life of the substance.

In this case, we have an initial mass of 0.842g (N₀) and a remaining mass of 0.0526g (N(t)). We can set up the equation as follows:

0.0526g = 0.842g \(* (1/2)^(^t^/^1^2^.^3^2)\),

where t represents the number of half-lives that have occurred.

To solve for t, we can take the logarithm of both sides of the equation:

log(0.0526g/0.842g) = log\([(1/2)^(^t^/^1^2^.^3^2^)\)].

Using the logarithmic property log(\(a^b\)) = b*log(a), we can rewrite the equation as:

log(0.0526g/0.842g) = (t/12.32) * log(1/2).

Simplifying further:

log(0.0526g/0.842g) = (t/12.32) * (-log2),

where log2 is the logarithm base 2.

Now, we can solve for t:

t = (12.32 * log(0.0526g/0.842g)) / (-log2).

Using the given values and performing the calculation, we find:

t ≈ 4.206.

Therefore, approximately 4.206 half-lives have occurred.

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PLEASE HELP ANYONE?!!!!!

PLEASE HELP ANYONE?!!!!!

Answers

Answer:

for question 3 the answer is A.

Explanation:

Pulse is not a part of the body but rather a measurement, same as with strength.

Answer: A
Brainliest?

The Earth surface temperature is around 270 K and emissivity of 0.8, while space has temperature of around 2K. What is the net power radiated by the Earth in free space?​

Answers

The net power radiated by the Earth in free space is approximately

1.2 x 10^ 17 W watts.

How to find the power radiated

To calculate the net power radiated by the Earth in free space, we can use the Stefan-Boltzmann Law:

Power = σ * A * ε * (T^4 - T0^4)

where:

σ is the Stefan-Boltzmann constant (5.67 x 10^-8 W/m^2K^4)

A is the surface area of the Earth (4πR^2, where R is the radius of the Earth)

ε is the emissivity of the Earth (0.8)

T is the temperature of the Earth surface (270 K)

T0 is the temperature of space (2 K)

Plugging in the values, we get:

Power = 5.67 x 10^-8 * 4πR^2 * 0.8 * (270^4 - 2^4)

The radius of the Earth is approximately 6.37 x 10^6 m, so:

Power = 5.67 x 10^-8 * 4π(6.37 x 10^6)^2 * 0.8 * (270^4 - 2^4)

Power ≈ 1.193 x 10^ 17 W

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(8.6) A space station in deep space is spun like a giant wheel to produce centrifugal force so the occupants experience artificial gravity of one g. How does a clock at the rim of the space station compare with one residing at the hub? What does this say about the behavior of a clock sitting on the surface of a planet with a surface gravity of one g?

Answers

The way that the clock at the rim of the space station compare with one residing at the hub is that Rim clock will always runs slower.

The behavior of a clock sitting on the surface of a planet with a surface gravity of one g is the same.

Is there a timepiece on the ISS?

For instance, timekeeping on the International Space Station (ISS) is slightly slower than that of reference clocks on Earth. This explains why astronauts on the International Space Station (ISS) mature more slowly, lagging by 0.007 seconds every six months.

Ground-based atomic clocks have served as the industry standard for timekeeping since the 1950s. These clocks use the extremely steady and accurate frequencies of light emitted by particular atoms to keep time.

Therefore, Satellite clocks run slower due to more velocity but faster due to reduced gravity. Clocks move more slowly at the ISS orbital height because velocity dominates. At GPS altitude, clocks move more quickly due to the influence of gravity.

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A motorcyclist is traveling in the positive direction at a
velocity of 7.0 meters per second. She increases her
velocity to 9.0 meters per second. What additional
information is needed to calculate the acceleration of
the motorcycle?

Answers

The additional information needed to calculate the acceleration of the motorcycle is the time taken to complete the distance.

What is acceleration?

Acceleration is the amount by which a speed or velocity increases (and so a scalar quantity or a vector quantity).

The acceleration of a moving body can be calculated by dividing the change in velocity of the motion (∆V) by the time taken to complete the motion as follows:

Acceleration (m/s²) = change in velocity (m/s)/time(s)

According to this question, a motorcyclist is traveling in the positive direction at a velocity of 7.0 meters per second. She then increases her velocity to 9.0 meters per second. This means that the change in velocity {∆V} is 2m/s.

However, the time taken to complete the distance is still required to compute the acceleration of the motorcycle.

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The figure below shows a ball resting on a frictionless track at position A.

The ball has a mass of 20 kg and is released from position A, the acceleration due to gravity is 9.8 m/s. How much kinetic energy will the ball have at position B?

 The figure below shows a ball resting on a frictionless track at position A.The ball has a mass of 20

Answers

The kinetic energy of the ball at position B is determined as 11,760 J.

What is the kinetic energy of the ball at position B?

The kinetic energy of the ball at position B is calculated by applying the law of conservation of energy, which states that the total mechanical energy of a system is always conserved.

That is the initial potential energy of the ball at position A = final kinetic energy of the ball at position B.

P.E (A) = K.E (B)

P.E = mgh

where;

m is the mass of the ballh is the height above the groundg is gravity

The kinetic energy of the ball at position B is calculated as;

P.E = 20 kg x 9.8 m/s² x 60 m

P.E = 11,760 J

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on Truck drivers in your community load their trucks beyond what is required by traffic rules. They are always arrested and changed for over loading by the traffic police department.Present a sensitization message to truck owners and the police in your community using the scene of turning effect of forces and stability.

Answers

The sensitization message to truck owners and the police in my community using the scene of turning effect of forces and stability is Let us work together so that the prioritization of road safety as well as the stability in our community can be secured by the promotion of responsible behavior so that all all road users can be safe.

What is sensitization ?

In the non-associative learning process of sensitization, the delivery of a stimulus repeatedly causes a response's volume to gradually increase. In addition to the recurrent stimulus, sensitization is frequently accompanied by an improvement in responsiveness to a whole class of stimuli.

This is a sort of community-level intervention where we work hand-in-hand with the local population using creative means of contact and communication that enable the target audience to relate to the problems on a personal level.

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The force F shown in Figure 4.30 has a moment of 40 Nm about the pivot. Calculate the magnitude
of the force F.

The force F shown in Figure 4.30 has a moment of 40 Nm about the pivot. Calculate the magnitudeof the

Answers

\(\boxed{\sf \tau=rFsin\theta}\)

Put values

\(\\ \rm\hookrightarrow 40=2Fsin40\)

\(\\ \rm\hookrightarrow Fsin40=20\)

\(\\ \rm\hookrightarrow 0.64F=20\)

\(\\ \rm\hookrightarrow F=31.25N\)

The moment of force is 40 Nm here. The displacement is 2.5 m and the angle of inclination is 45°. The force about the pivot is then 28.2 N.

What is moment of force?

Moment of force is the product of the force and distance from a fixed axis. Moment of force can be calculated for both balanced and unbalanced forces.

The expression for moment of force relating the distance d and force f with an angle of inclination θ is written as below:

moment of force =  f d sin θ

Given that moment of force = 40 Nm

distance from the fixed axis from the figure =  2 m

angle of inclination = 45 °

40 Nm =   2 f sin 45.

20 = f sin 45

  f = 20 N / sin 45

    = 28.2 N

Therefore, the force about the pivot is 28.2 N.

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Two boys searching for buried treasure are standing underneath the same tree. One boy walks 18 m east and then 18 m north. The other boy walks 16 m west and then 11 m north. Find the scalar product of their net displacements from the tree.

Answers

It is 15.75 but u can put 16

Children's behavior is marked by egocentrism during the concrete-operational stage.
O True
False

Answers

Answer:

false because this is not possible that children behaviour is marked over by egocentrism children are also the tender creation of God

A piano of mass 852 kg is lifted to a height of 3.5 m. How much gravitational potential energy is added to the piano? Acceleration due to gravity is g = 9.8 m/s2 O A. 102,282 J O B. 29,224J O C. 2982 J O D. 304.3J SUSM​

Answers

Answer:

29223.6J

Explanation:

Given parameters:

Mass of Piano = 852kg

Height of lifting  = 3.5m

Unknown:

Gravitational potential energy  = ?

Solution:

The gravitational potential energy of a body can be expressed as the energy due to the position of a body;

  G.P.E  = mgh

m is the mass

g is the acceleration due to gravity

h is the height

 Now insert the given parameters and solve;

   G.P.E  = 852 x 9.8 x 3.5 = 29223.6J

A candle is placed in front of a concave mirror as it is shown . State the image characteristics (SALT)

Answers

As a result, the picture behind the mirror is virtual, upright, and enlarged.

What does SALT in concave mirrors stand for?

You will find that the properties of an image (SALT) created in a concave mirror depend on the object's position. A) if the item is larger than C. Size, attitude, and location are all important considerations.

The image will be true, but reversed and much reduced. To obtain a crisp flame image, move the burning candle towards the mirror while moving the screen away from it. The size of the inverted picture grows.

Concave mirrors may create both physical and virtual images. A virtual and enlarged picture is produced when the item gets closer to the mirror. When the item is placed further away from the mirror,.

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At room temperature, sound travels at a speed of about 344 m/s in air. You see a distant flash of lightning and hear the thunder arrive 7.5 seconds later. How many miles away was the lighting strike? (Assume the light takes essentially no time to reach you).

Answers

Answer:

1.6031 miles

Explanation:

Given the following data;

Speed = 344 m/s

Time = 7.5 seconds

To find how many miles away was the lighting strike;

Mathematically, the distance travelled by an object is calculated by using the formula;

Distance = speed * time

Distance = 344 * 7.5

Distance = 2580 meters

Next, we would have to convert the value of the distance travelled in meters to miles;

Conversion:

1609.344 metres = 1 mile

2580 meters = X mile

Cross-multiplying, we have;

X * 1609.344 = 2580

X = 2580/1609.344

X = 1.6031 miles

make figures showing the patellar reflex conduction times and patellar reflex conduction velocites under te various experimental conditions

Answers

The patellar reflex happens when there is a sudden change in muscle length; in this situation, the tendon velocity is stretched as a result of the application of the hammer stroke [3, 4].

How does one measure a normal patellar reflex?

The deep tendon reflexes are ordinarily ranked as follows: The response of zero is always abnormal. 1+ indicates a weak but unmistakably present response; this could or could not be typical. Fast response; 2+; considered usual.

If your knee doesn't respond, what does that mean?

A symptom of hyporeflexia is a diminished or nonexistent reflex reaction in your skeletal muscles. Damage to any area of your reflex arc—which may have occurred as a result of an underlying medical condition—causes it to occur.

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the acceleration due to gravity on the moon is about 5.4ft/s2. if your weight is 150lbf on earth

Answers

... then your weight is 25.2 lbf on the moon.

a. When throwing a ball vertically upward, my hand moves through a distance of about 1.0 m before the ball leaves my hand. The 0.80 kg ball reaches a maximum height of about 20 m above my hand. while the ball is in my hand after the ball leaves my hand

Answers

The required, it experiences a downward force due to gravity and a force due to air resistance.

What is the projectile motion?

Projectile motion is the movement of an entity projected into space. After the initial force that launches the object, it only experiences the force of gravity. The object is called a projectile, and its path is called its trajectory.

Here,

When throwing a ball vertically upward, there is a displacement of about 1.0 m from the initial position of the hand to the position where the ball leaves the hand. The mass of the ball is 0.80 kg and it reaches a maximum height of about 20 m above the initial position of the hand. While the ball is in the hand after it leaves, it experiences a downward force due to gravity and a force due to air resistance.

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2. This diagram shows an electric bell ringing in a sealed glass chamber containing air. to vacuum pump 5655 bell A student hears the bell ringing. The air is then removed from the chamber. State and explain any change in the sound heard by the student.​

Answers

When the air is removed from the chamber using a vacuum pump, the sound heard by the student will become quieter.

What is Vacuum?

Vacuum is typically created by removing gases and other matter from a closed container, using methods such as mechanical pumps, diffusion pumps, or cryopumps. In the absence of matter, there is no medium for sound waves to propagate, which is why sound cannot travel through a vacuum.

This is because sound waves require a medium to travel through, such as air. When the air is present in the chamber, the sound waves from the vibrating bell can travel through the air and reach the student's ear. However, when the air is removed, there is no medium for the sound waves to travel through, so they cannot reach the student's ear as effectively.

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The first P-wave of an earthquake travels 5600 kilometers from the epicenter and arrives at a seismic station at 10:05 a.m. At what time did this earthquake occur?

Ahhhhhh I have a Regent's test in 2 hours and I don't know how to solve this type of question! Any help would be appreciated.

Anyone know what the steps to do this are? I dont even need an answer, just how to get to it. Thank you!

Answers

The earthquake would occur 13 minutes before 10:05 a.m. which will be at 9.52 am.

The p-waves travel with a constant velocity of 7 km/s

The time can be calculated by using the formula

t = d / v

where

T1 =  10:05 a.m

d is the distance they take to travel from the epicenter

v is the speed of the p-waves

On average, the speed of p-waves is

v = 7 km/s

d = 5600 km (given)

Substituting the values in the formula;

t = d / v

t = 5600 ÷ 7

t = 800 seconds

Converting into minutes,

t = 800 ÷ 60

t = 13.3

≈ 13 mins

T1 -  13 mins = T2

10:05 - 13 mins = 9.52 am

It means the earthquake occurred prior 13 minutes, that is at 9.52 am.

Therefore, the earthquake occurred at 9.52 am.

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What’s SI units and SigFigs???

Answers

Answer:

Significant figures have a few rules about 0s and you should research but simply, for example say round 27.879 to 3 significant figures you round up until you have 3 numbers that aren't 0s so it would be 27.9.

SI units are the international system of units.

Answer:

SI units refer to the International System of Units. These are the standard units that measurements are typically given in. For example, the SI unit for time is seconds, meters for distance, kg for mass, etc.

Significant figures are the number of notable digits given for a measurement. For example, let's say you measured a piece of metal to be exactly 3.00 meters long. The value 3.00 has three significant figures, where as 3 only has one significant figure. Larger amounts of significant figures indicate a more precise measurement. In this case, by writing 3.00 instead of 3, you're telling me that you measured that piece of metal to be precisely 3.00 meters long.

he generation of a magnetic field by an electric current is

Answers

Answer: electromagnetism.

Explanation:The use of coils of wires produces a relationship between electricity and magnetism that gives us another magetism called electromagnetism.

a roller coaster weighs 2000 kg This ride includes an initial vertical drop of 59.3 m.
Assume that the roller coaster has a speed of nearly zero as it crests the top of the hill.
If the track was frictionless, find the speed of the roller coaster at the bottom of
the hill.

Answers

The speed of the roller coaster at the bottom of the hill if the track was frictionless is 34.04 m/s.

Given that the weight of the roller coaster is 2000 kg and the initial vertical drop of the ride is 59.3 m. We are to find the speed of the roller coaster at the bottom of the hill if the track was frictionless.We know that the roller coaster will lose potential energy due to the vertical drop. Assuming there is no friction, the potential energy will be converted into kinetic energy at the bottom of the hill.Considering the conservation of energy between the potential and kinetic energy, we can set the initial potential energy equal to the final kinetic energy. We can use the formula to calculate potential energy, which is PE = mgh where m = 2000 kg, g = 9.8 m/s², and h = 59.3 m. Therefore,PE = 2000 kg × 9.8 m/s² × 59.3 m = 1,157,924 JWe can use the formula to calculate kinetic energy, which is KE = 1/2mv² where m = 2000 kg and v is the final velocity. Therefore,KE = 1/2 × 2000 kg × v².The total energy remains constant as we know there is no friction. Therefore the final kinetic energy will be equal to the initial potential energy,1,157,924 J = 1/2 × 2000 kg × v²v² = (2 × 1,157,924 J) / 2000 kgv² = 1157.924v = √1157.924v = 34.04 m/s.

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For an n- channel JFFT, IDSS = 8 mA, and VP = - 6 V. If VGS = - 2 V. What is the value of the drain current ID?

Answers

Answer: the value of the drain current ID is 3.56 mA

Explanation:

Given that;

IDSS = 8 mA

VP(VGS_OFF) = - 6 V.

VGS = - 2 V

value of the drain current ID = ?

Drain current ID is expressed as;

ID = IDSS [ 1 - (VGS/VP(VGS_OFF)) ]²

we substitute our value

ID = 8 [ 1 - (-2 / -6) ]²

ID = 8 [ 1 - 0.3333 ]²

ID = 8 [ 0.6667 ]²

ID = 8 [ 0.4444 ]

ID = 3.5552 ≈ 3.56 mA

Therefore the value of the drain current ID is 3.56 mA

Find the amplitude (in m) of such a sound wave if its frequency is 800.0 Hz, the density of air is 1.29 kg/m3 and the speed of sound is 344 m/s. Again, show the algebraic version of the formula you used in your calculation.

Answers

Answer:

0.9x10^-11m

Explanation:

Pls see attached file

Find the amplitude (in m) of such a sound wave if its frequency is 800.0 Hz, the density of air is 1.29

Please help with these 4 questions

Please help with these 4 questions

Answers

The amount of time which the impetus was implemented is 3.04 seconds.

The momentum of the automobile is 34124.26 kg*m/s.

How to calculate the value

In order to figure out the time, the following formula for impulse can be applied: impulse = force x time. Reformulating and rearranging this equation, we reach the derivative of time = impulse / force. With the provided calculations of 536.49 N*s divided by 176.32 N, these figures conclude that the amount of time which the impetus was implemented is 3.04 seconds.

Additionally, we can use the formula of momentum = mass x velocity to further determine the vehicular testament of import. When applying these specified numbers of 2546.9 kg and 13.4 m/s respectively, the momentum of the automobile is 34124.26 kg*m/s.

momentum = 2546.9 kg x 13.4 m/s

= 34124.26 kg

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Susan is running to the right, in the +x-direction, at 2 m/s. A bird flies past her, traveling to the left at 10 m/s. What is the bird's velocity in Susan's reference frame?

Answers

The concept of relative velocity can be found the speed of the bird respecting susan v = -12 m / s. The negative sign indicates that the bird is approaching susan

given parameter

the speeds of Susam and the bird

to find

the relative speed between Susan and the bird

Velocity is a vector unit, therefore, in addition to magnitude, it has direction and sense, therefore, to make the sum of the same quantities, vector relations must be used

         v₁ = v₂ + v₃

where v₁, v₂ and v₃ are velocity and the bold letters indicate vectors

in this case Susan and the bird go on the x axis therefore the algebra is reduced to the algebraic sum. We will assume that the positive direction is to the right of the x-axis, consequently the velocities are:

Susan       v_{st} = 2 m / s

Bird          v_{bt} = - 10 m / s

The relative velocity is the vector sum of the velocities of the bodies, one way to perform this sum is by using subscripts

           v_{pt} =   v_{ps} + v_{st}

           

Where  v_{ps} is the speed of the bird relative to susan, v_{st} is the speed of susan relative to the ground, and v_{pt} is the speed of the bird relative to the ground.

            v_{ps} = v_{pt} - v_{st}

            v_{ps} = -10 - 2

            v_{ps} = - 12 m / s

Using the concept of relative velocity, the velocity of the bird respecting susan v = -12 m/s can be found. The negative sign indicates that the bird is approaching susab.

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air at 30,000 feet is at a temperature of -35.0 c. a sample of air was collected and the mixture is 75.56% nitrogen, 23.15% oxygen and 1.29% argon (percentages are by mass). if .594 moles of air are captured in a 45.0 l container from a plane flying at 30000 feet:

Answers

0.594 moles of air were collected from the plane flying at an altitude of 30,000 feet and is at a temperature of -35.0 C.

What is temperature?

Temperature is the measure of the average kinetic energy of the particles in a substance. It can be measured in degrees Celsius (°C), Fahrenheit (°F), or Kelvin (K). Temperature is an important physical property of matter, as it can affect the state of a substance.

The total moles of air in the container is 45.0 L * (1.00 mol/22.4 L) = 2.01 mol.
Since the sample is 75.56% nitrogen, 23.15% oxygen, and 1.29% argon, the moles of each are:
Nitrogen = 0.7556 * 2.01 mol = 1.52 mol
Oxygen = 0.2315 * 2.01 mol = 0.46 mol
Argon = 0.0129 * 2.01 mol = 0.03 mol
The 0.594 moles of air collected from the plane is the difference between the total moles and the moles of nitrogen, oxygen, and argon:
Air = 2.01 mol - 1.52 mol - 0.46 mol - 0.03 mol = 0.594 mol
Therefore, 0.594 moles of air were collected from the plane flying at an altitude of 30,000 feet and is at a temperature of -35.0 C.

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Which example represents a class 2 lever? (1 point)
O salad tongs picking up salad
O tweezers plucking hairs
O a car door being opened and shut
a screwdriver opening a paint can

Answers

The  example that represents a class 2 lever is: D. a screwdriver opening a paint can.

Which example represents a class 2 lever?

The load is situated in a class 2 lever halfway between the fulcrum and the effort. The screwdriver's resting place against the paint can's rim serves as the fulcrum in this scenario.

The paint can's lid serves as the load, and the force exerted by the hand on the screwdriver's handle serves as the effort. A class 2 lever can be identified by the load being situated between the fulcrum and the effort.

Tweezers, salad tongs, and opening and closing a car door are not examples of class 2 levers. Class 1 levers include things like tweezers and salad tongs, whereas class 3 levers include things like car doors that open and close.

Therefore the correct option is D.

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An aeroplaneflying above groundnd490m with 100 meterpersecond how far on ground it will strike

Answers

The airplane will strike the ground at a horizontal distance of 490 meters.

To determine how far the airplane will strike on the ground, we need to consider the horizontal distance traveled by the airplane during its flight.

The horizontal distance traveled by an object can be calculated using the formula:

Distance = Speed × Time

In this case, the speed of the airplane is given as 100 meters per second and the time it takes to cover the distance of 490 meters is unknown. Let's denote the time as t.

Distance = 100 m/s × t

Now, to find the value of time, we can rearrange the equation as follows:

t = Distance / Speed

t = 490 m / 100 m/s

t = 4.9 seconds

Therefore, it takes the airplane 4.9 seconds to cover a horizontal distance of 490 meters.

Now, to calculate the distance on the ground where the airplane will strike, we can use the formula:

Distance = Speed × Time

Distance = 100 m/s × 4.9 s

Distance = 490 meters

It's important to note that this calculation assumes a constant speed and a straight flight path. In reality, various factors such as wind conditions, changes in speed, and maneuvering can affect the actual distance traveled by the airplane.

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A 4 newton lamp
is lifted 2 meters.
How much work
was done?

Answers

Answer:

The answer is 8 J

Explanation:

The work done by an object can be found by using the formula

workdone = force × distance

From the question we have

workdone = 4 × 2

We have the final answer as

8 J

Hope this helps you

Calculate the kinetic energy, in joules of a 1160-kg automobile moving at 19.0 m/s.

Answers

Answer:

Explanation:

K.E=1/2 mv²

m=1160 kg

v=19.0 m/s

so k.e=1/2*1160*(19.0)²

K.E=1/2*1160*361

K.E=1/2*418760

K.E=209380=2.0*10^5 j

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