A 0.25 kg length of aluminum wire is warmed 10.0°C by an electric current. How much heat was generated by the current?

Answers

Answer 1

2,302.74 J is the heat generated.

Current electricity is the electricity produced by the movement of electrons. Static electricity is the electricity that accumulates on a substance's surface. Power plants and batteries are used to produce the current electricity.

Electric current in a wire, where electrons serve as the charge carriers, is a measurement of the amount of charge that moves through any point of the wire in a given amount of time.

The mass of the aluminum is m = 0.25 kg.

The difference in temperature is T=10 C.

The following is a list of aluminum's specific heat capacities:

c=921.096 J/kg∘C

Therefore, we apply the following formula in this instance:

Q=mcΔT

We replace with:

Q=(0.25kg)(921.096J/kg∘C)(10∘C)

Thus, we will receive the heat produced:

Q=2,302.74 J

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Related Questions

A parallel-plate air capacitor is connected to a constant-voltage battery. If the separation between the capacitor plates is doubled while the capacitor remains connected to the battery, the energy stored in the capacitor
1) drops to one-fourth its previous value.
2) quadruples.
3) becomes six times its previous value.
4) doubles.
5) drops to one-third its previous value.
6) Not enough information is provided.
7) triples.
8) drops to half its previous value.
9) drops to one-sixth its previous value.
10) remains unchanged.

Answers

Answer:

Drop to half of the previous value

Explanation:

Energy stored in capacitor is inversly propotional to the distance between the plates.

If the separation between the capacitor plates is doubled while the capacitor remains connected to the battery, the energy stored in the capacitor drops to half its previous value.

What is parallel plate capacitor?

The two parallel plates placed at a distance apart used to store charge when electric supply is on.

The capacitance of a capacitor is  given by

C = ε₀ A/d

where, ε₀ is the permittivity of free space, A = area of cross section of plates and d is the distance between them.

Capacitance is inversely proportional to the distance between them. So, if distance is doubled, the capacitance decreases to half its original value.

Thus, the correct option is 8.

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3. What is the weight of a 462-kg bar?


Answers

Answer:

F = M g = 462 kg * 9.80 m/s^2 = 4528 Newtons

It somewhat unfortunate that weight in the English System is measured in pounds (mass in slugs) and in the metric system weight is measured in Newtons (mass in kilograms)

A diver shines a light up to the surface of a flat glass-bottomed boat at an angle of 37◦ relative to the normal. If the indices of refraction of air, water, and glass are 1.0, 1.33, and 1.4 respectively, at what angle does the light leave the glass (relative to its normal)? Answer in units of ◦ .

Answers

Answer:

Approximately \(53^{\circ}\), assuming that the upper and lower surfaces of the glass on this boat are parallel.

Explanation:

Assume that the upper and lower surfaces of the glass at the bottom of this ship are parallel. Refer to the diagram attached. The two normals would also be parallel to each other.

The following angles would be alternate interior angles between the two normals:

The angle at which the light enters the glass, andThe angle at which the light leaves the glass.

Since the two normals are parallel to each other, these two angles would have the same value. Let \(\theta_{\text{glass}}\) denote the value of both of these angles.

Let \(\theta_{\text{src}}\) denotes the angle at which a beam of light leaves the original medium (angle of incidence.) Let \(\theta_{\text{dst}}\) denote the angle at which this beam of light enters the new medium.

Let \(n_\text{src}\) and \(n_\text{dst}\) denote the refractive indices of the original and the new medium, respectively. By Snell's Law:

\(\begin{aligned}\frac{\sin(\theta_{\text{dst}})}{\sin(\theta_{\text{src}})} = \frac{n_{\text{src}}}{n_{\text{dst}}}\end{aligned}\).

Let \(\theta_{\text{water}}\) denote the angle at which the beam of light in this question leaves the water. Let \(\theta_{\text{air}}\) denote the angle at which this beam of light enters the air. It is given that \(\theta_{\text{water}} = 37^{\circ}\), while \(\theta_{\text{air}}\) is the value that needs to be found.

Let \(n_{\text{air}}\), \(n_{\text{water}}\), and \(n_{\text{glass}}\) denote the refractive index of air, water, and glass, respectively. By Snell's Law:

\(\begin{aligned}\frac{\sin(\theta_{\text{glass}})}{\sin(\theta_{\text{water}})} = \frac{n_{\text{water}}}{n_{\text{glass}}}\end{aligned}\).

\(\begin{aligned}\frac{\sin(\theta_{\text{air}})}{\sin(\theta_{\text{glass}})} = \frac{n_{\text{glass}}}{n_{\text{air}}}\end{aligned}\).

Thus:

\(\begin{aligned} & \frac{\sin(\theta_{\text{air}})}{\sin(\theta_{\text{water}})} \\ =\; & \frac{\sin(\theta_{\text{glass}})}{\sin(\theta_{\text{water}})}\times \frac{\sin(\theta_{\text{air}})}{\sin(\theta_{\text{glass}})} \\ =\; & \frac{n_{\text{water}}}{n_{\text{glass}}}\times \frac{n_{\text{glass}}}{n_{\text{air}}} \\ =\; & \frac{n_{\text{water}}}{n_{\text{air}}}\end{aligned}\).

Since \(\theta_{\text{water}} = 37^{\circ}\):

\(\begin{aligned} & \sin(\theta_{\text{air}})\\ =\; & \sin(\theta_{\text{water}}) \times \frac{\sin(\theta_{\text{air}})}{\sin(\theta_{\text{water}})} \\ =\; & \sin(\theta_{\text{water}})\times \frac{n_{\text{water}}}{n_{\text{air}}} \\ =\; & \sin(37^{\circ}) \times \frac{1.33}{1.0} \\ \approx \; & 0.800 \end{aligned}\).

Therefore:

\(\begin{aligned}\theta_{\text{air}} &= \arcsin(\sin(\theta_{\text{air}})) \\ & \approx \arcsin(0.800) \\ &\approx 53^{\circ} \end{aligned}\).

In other words, this beam of light would leave the glass at approximately \(53^{\cic}\) from the normal.

A diver shines a light up to the surface of a flat glass-bottomed boat at an angle of 37 relative to

Three parallel sheets of charge, large enough to be treated as infinite sheets, are perpendicular to the x-axis. Sheet A has surface charge density σA = +8.00 nC/m^2. Sheet B is 4.00 cm to the right of sheet A and has surface charge density σB = -4.00 nC/m^2. Sheet C is 4.00 cm to the right of sheet B, so is 8.00 cm to the right of sheet A, and has surface charge density σC = +6.00 nC/. What are the magnitude and direction of the resultant electric field at a point that is midway between sheets B and C, or 2.00 cm from each of these two sheets?

Answers

Answer:

E_{total} = -1.13 10² N / C

the sign indicates that the electric field points to the left

Explanation:

Let's start this exercise by looking for the electric field created by an infinite leaf, for this let's use Gauss's law

       \(\Phi_E\) = ∫ E. dA = \(q_{int}\) /ε₀

Let's define a Gaussian surface that is a cylinder, the normal to the faces of the cylinder is parallel to the field created by the face inside the surface, the normal of the cylinder walls is perpendicular to the electric field so its scalar product is zero

            \Phi_E = E (2A) = q_{int} /ε₀

the number 2 is due to having two faces

            E =    \(\frac{q_{int} }{A} \ \frac{1}{2 \epsilon_0 }\)

the surface charge density is

            σ= Q / A

we substitute

             E = \(\frac{\sigma }{2 \epsilon_o}\)

we can see that the field is independent of the distance.

Let's write the field for each leaf, remember that the field is salient for positive charges

       

sheet 1

           E₁ = \(+ \frac{\sigma_1}{2 \epsilon_o}\)

sheet 2

           E₂ = \(- \frac{\sigma_2}{2 \epsilon_o}\)

sheet 3

           E₃ = \(+ \frac{\sigma_3}{2 \epsilon_o}\)

at the point the Field of sheet 1 points to the right,

the field on sheet 2 points to the left and the field on sheet 3 points to the left.  Tthe electric field at the midpoint is

           E_ {total} = E₁ - E₂ - E₃

            E_ {total} = \(\frac{1}{2 \epsilon_o}\)  (σ₁ - σ₂ -σ₃)

calculate

             E_total = \(\frac{1}{2 \ 8.85 \ 10^{-12}}\)   (8.00 -4.00 -6.00) 10⁻⁹

             E_total = -1.13 10² N / C

the sign indicates that the electric field points to the left

Deimos's Orbit. Deimos orbits Mars at a distance of 23,460 km from the center of the planet and has a period of 1.263 days. Assume that Deimos's orbit is circular. Calculate the mass of Mars. Express your answer in units of kg. (Hint: Use the circular orbit velocity formula ; remember to use units of meters, kilograms, and seconds.) Please round the answer to four significant digits.

Answers

Answer:

M = 5.882 10²³ kg

Explanation:

Let's use Newton's second law to analyze the satellite orbit around Mars.

         F = m a

force is universal attraction and acceleration is centripetal

          a = v²/ R

the modulus of velocity in a circular orbit is constant

         v= d/T

the distance of the cicule is

        d =2pi R

       a = 2pi R/T  

we substitute

          - G m M / R² = m ( \(- \frac{4\pi^2 R^2 }{T^2 R}\))

         G M = \(\frac{ 4\pi ^2 R^3 }{T^2 }\)

         M = \(\frac{4 \pi ^2 R^3 }{ G T^2 }\)

the distance R is the distance from the center of the planet Mars to the center of the satellite Deimos

         R = 23460 km = 2.3460 10⁷ m

the period of the orbit is

         T = 1,263 days = 1,263 day (24 h / 1 day) (3600s / h)

          T = 1.0912 10⁵ s

let's calculate

          M = \(\frac{4 \pi ^2 ( 2.3460 \ 10^7)^3 }{5.67 10^{-11} \ (1.0912 \ 10^5)^2 }\)

          M = 509.73418 10²¹  /8.66640 10⁻¹

          M = 58.817 10²² kg

          M = 5.882 10²³ kg

An object at rest will stay at rest and an object in motion will stay in straight line uniform motion unless acted on by a force. Which one of Newton's Laws of Motion is this statement? Un objeto en reposo permanecerá en reposo y un objeto en movimiento permanecerá en movimiento uniforme en línea recta a menos que sea actuado por una fuerza. ¿Cuál de las leyes del movimiento de Newton es esta afirmación?

1. 3rd Law of motion
2. 1st law of motion
3. 2nd law of motion

Answers

The Answer Is: Newton’s 1st Law Of Motion

Newton's First Law of Motion..........................

The half-life of Silver-105 is 3.57 x 106 seconds. A sample contains 5.78 x 1017 nuclei. What is the decay constant for this decay?

Answers

Answer:

The decay constant, or "lambda" (λ), is the rate at which a radioactive isotope decays. It is usually measured in units of inverse time, such as seconds. In this case, the decay constant can be calculated as follows:

16:42

λ = (ln(2)/3.57 x 106) x (5.78 x 1017) = 0.

Explanation:

HELPPPPP!!! Please

A cone with an apex radius of 2 theta = 60 degrees rolls without slipping on a horizontal boundary with the apex of the cone held at rest as shown in the figure. What is the apex of the cone at the same height as the center of the base of the cone which is moving with speed. Determine the angular speed of the cone and the angular acceleration of the cone

HELPPPPP!!! PleaseA cone with an apex radius of 2 theta = 60 degrees rolls without slipping on a horizontal

Answers

I done it can’t remember

what differentiates between static and dynamic charge

Answers

Static charge and dynamic charge are two different types of electrical charges.

Static charge refers to an electric charge that is stationary or at rest on an object. This type of charge is typically caused by the transfer of electrons between two objects, resulting in an imbalance of electric charge. When two objects are in contact, electrons can move from one object to another, creating a static charge on one or both objects. The charge remains in place until it is discharged, either through a spark, a sudden movement of electrons, or through contact with a grounded object.

Dynamic charge, on the other hand, refers to an electric charge that is in motion or flowing. This is the type of charge that is used to power electrical devices, such as batteries or generators. In a dynamic charge system, electrons move through a circuit, generating a flow of electrical current that can be harnessed to power machines or devices.

In summary, the main difference between static and dynamic charge is that static charge is stationary or at rest, while dynamic charge is in motion or flowing through a circuit.

Richard has just completed his science experiment, and collected all of the data. What is the next step that Richard needs to complete?

a.background research
b.analyze results
c.recognize a problem
d.form a hypothesis

Answers

B) all the other answers should have been done before the lab

A car accelerated uniformly from rest and attained a velocity of 8m/s. it then travels with the uniform velocity of for the next 22 seconds and later brought to rest in 5 seconds
(a )draw the velocity time graph
(b.) calculate the total distance covered (c.) calculate the distance covered after 25 seconds.​

Answers

Answer:

See below

Explanation:

See diagram below

8 seconds to 60 m/s     then    60 m/s for 22 seconds then   to 0 m/s in 5 seconds

A car accelerated uniformly from rest and attained a velocity of 8m/s. it then travels with the uniform

A first year student projected a farm business brochure to a farmer at 30 degrees to horizontal. calculate the maximum height attained by the projectile if it was launched at 400m/s​

Answers

Answer:

Maximum height = 2040 m

Explanation:

We can solve the problem using kinematics.

Consider the vertical motion of the object and use the equation:

\(\boxed{v^2 = u^2 + 2as}\)

where:

v = final velocity      (0 m/s, because when the object is at max. height, it has no vertical velocity)

u = initial velocity    (400sin30° m/s ⇒ vertical component of 400 m/s at 30° to horizontal)

a = acceleration      (-9.81 m/s²; considering upward acceleration to be negative)

s = displacement    (? m; this represents the max. height of the object),

Substitute the values into the equation and solve for s :

\(0^2 = (400 sin (30 \textdegree))^2 + 2(-9.81)(s)\)

⇒ \(2(9.81)(s) = (400 sin (30 \textdegree))^2\)

⇒  \(s = 2040 \space\ m\)     (3 s.f.)

According to the principal of superposition,

Answers

Answer:

the resultant wave is the algebraic sum of all the waves reaching that particular point at a given time.

Explanation:

imagine two or three waves reaching a particular particle x at the same time. The particle will vibrate those waves and give out or transmit a resultant wave which is the algebraic sum of the incoming two waves. If both the waves have the same amplitude and phase, the resultant wave will be amplified. However if the waves have the same amplitude and equal but opposite phase then the resultant wave will be a straight line

If there is a potential difference V between the metal and the detector, what is the minimum energy Emin that an electron must have so that it will reach the detector

Answers

Answer:

Emin= eV

Explanation:

This minimum amount of energy is the work function and so for an electron to reach the detector the energy must b more than work function and the stopping potential so

Emin=eV

We can easily tell that a bowling ball rolling down an ally has energy of motion. But why would a scientist say that a white-hot piece of iron also has the energy of motion within it?

Answers

A white-hot iron piece has internal motion energy due to constant particle movement at the atomic and molecular levels, as per scientists. Thermal energy or heat energy is motion. Higher temperature means more kinetic energy and faster motion of atoms and molecules.

What is the  energy of motion?

White-hot iron vibrates atoms and molecules at high temperatures. Kinetic theory states that all matter is made up of moving particles. Motion occurs at the microscopic level, beyond eye view. Higher temperature = greater particle energy.

When a scientist refers to white-hot iron, they recognize its high temperature corresponds to increased kinetic energy and motion. Motion and energy at the atomic level are not visible like a bowling ball, but are fundamental traits of matter.

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if a person does not just do what you told what happens​

Answers

Then that means they are disobeying you.

explaination: simple vocabulary

Answer:

Of course we feel bad or angry.

Explanation:

that it what i know....

Yes hello I’m stuck on this one and it’s very confusing

Yes hello Im stuck on this one and its very confusing

Answers

Answer:

I will guess c for your answer!

Explanation:

I don't know really how to explain my guess.

Answer:

I believe B

Explanation:

73 - 65 = 8

8 / 5 = 1.6

Read a sample of one type of narrative nonfiction below and determine the type of narrative nonfiction: Monique went through many trials and tribulations and decided to write a book about this particular period in her life. Read a sample of one type of narrative nonfiction below and determine the type of narrative nonfiction: Monique went through many trials and tribulations and decided to write a book about this particular period in her life

Answers

Memoir is a type of narrative nonfiction: Monique went through many trials and tribulations and decided to write a book about this particular period in her life.

Because it combines elements of creative writing with the relation of facts required to produce a work of nonfiction, narrative nonfiction is a type of writing that is occasionally referred to as creative nonfiction. This genre comprises of writing that is factually accurate yet written with a creative flair that contributes to improving the work's flow and appeal. The genre of narrative nonfiction can include journalism and some genres of biography, essay, memoir, and personal essay. When compared to plain nonfiction, this genre is very new, and as the genre has developed, so too has the scrutiny that is applied to this kind of writing.

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The system shown above is released from rest. If the friction is negligible, the
acceleration of the 4 kg block sliding on the table shown above is:
(Take g = 10 m/s2)
A 0 m/s
B. 1.7 m/s2
C. 3.3 m/s
D. 5 m/s
E. 10 ms​

Answers

The answer is c most likely

The system shown above is released from rest. If the friction is negligible, the acceleration of the 4 kg block sliding on the table shown above is: 3.3 m/s². Hence option C is correct.

What is system ?

A system, as it is used in physics or chemistry, is nothing more than a group of identifiable items or smaller systems. The word "system" often refers to a collection that makes it easier to think about an issue. Everything else outside of what the system defines is considered the surrounds. For instance, if the system under study is a home, the surroundings would consist of everything else (including other houses, the neighborhood, the surrounding area, etc.) that is not the house. There are three methods to characterize a system. An isolated system is one in which neither matter nor energy are exchanged with the environment.

Hence option C is correct.

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Sierra lives in a southwestern town in a valley where air pollutants sometimes settle. The mountains that surround the town keep air pollution from blowing away. Sometimes Sierra can actually see the pollution in the air. Which choice is NOT a source of outdoor air pollution?

Answers

Radon gas is a major indoor pollutant, not outdoor. The rest of the choices can cause outdoor air pollution.

The following is not a source of outdoor air pollution : D) Household cleaning products.

What is meant by the outdoor air pollution?

Presence of one or more substances in air at concentration or for a duration above the natural level is called air pollution.

Outdoor air pollution refers to pollutants that are released into the atmosphere by sources outside of buildings or structures. The sources of outdoor air pollution can be natural or human-made. Some examples of sources of outdoor air pollution are:

A) Exhaust from cars and trucks

B) Smoke from factories and power plants

C) Pollen from trees and plants

D) Solid fuel burning

E) Forest fires

Therefore, the correct option is D) Household cleaning products.

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Note: The question given on the portal is incomplete. Here is the complete question.

Question: Sierra lives in a southwestern town in a valley where air pollutants sometimes settle. The mountains that surround the town keep air pollution from blowing away. Sometimes Sierra can actually see the pollution in the air. Which choice is NOT a source of outdoor air pollution?

A) Exhaust from cars and trucks

B) Smoke from factories and power plants

C) Pollen from trees and plants

D) Household cleaning products.

Alcohol of mass 33.2g and density 0.79kg/m³ or 790kg/m³ is mixed with water of 9g. What is the density of the resulting mixture?.​

Answers

Answer:

  0.83 g/cm³

Explanation:

The volume of the alcohol is ...

  (33.2 g)/(0.79 g/cm³) ≈ 42.0253 cm³

The density of water is about 1 g/cm³, so the volume of 9 g of it is ...

  (9 g)/(1 g/cm³) = 9 cm³

The total volume is ...

  42.0253 cm³ +9 cm³ = 51.0253 cm³

The total mass is ...

  33.2 g + 9 g = 42.4 g

So, the resulting density is ...

  (42.4 g)/(51.0253 cm³) ≈ 0.83 g/cm³

The resulting mixture has a density of about 0.83 g/cm³.

_____

Additional comment

Alcohol dissolves in water, so the total volume will be slightly less than 51.0253 cm³. The attached curve shows the result of mixing ethanol and water.

The weight of a mole of ethanol is about 46 g, of water, about 18.02 g. Then the mole fraction of alcohol is ...

  (33.2/46)/(33.2/46 +9/18.02) ≈ 0.59

The volume of the mix is then estimated to be (-1.05 cc/mol)(1.221 mol), or about 1.28 cm³ less than the volume indicated above. That brings the density up to about 0.85 g/cm³.

We're not completely sure of the relevance of this calculation, since many of the applicable parameters are not specified. The point is that the density of the mix will probably be slightly more than the value calculated above. YMMV

Alcohol of mass 33.2g and density 0.79kg/m or 790kg/m is mixed with water of 9g. What is the density

If a microwave oven emits 1,100 J of energy every second, how much energy will be emitted after 8.9 seconds

Answers

Answer:

it would make 9790 J of energy

it will emit 9,790 J of energy after 8.9 seconds, since every second it emits 1,100 J of energy everysecond, therefore, you multiply it by 8.9.

A 12 V automobile battery is connected to an electric starter motor. The current
through the motor is 250 A.
a) How much power does the motor dissipate?
b) How much energy does the battery deliver to the motor during the 26 s period?

PLEASE HELP QUICK

Answers

Answer: \(3000\ W,\ 78,000\ J\)

Explanation:

Given

The voltage of the battery is \(V=12\ V\)

Current through the battery is \(I=250\ A\)

(a) Power is the product of voltage and current

Power dissipates is given by

\(P=VI\\P=12\times 250\\P=3000\ W\)

(b) Energy delivered

\(E=P\times t\)

\(E=3000\times 26\\E=78,000\ J\)

You travel 250 km south in 6.5 hours, turn west and travel 155km in 3 hours, then turn north and travel 32 km in 30 minutes.


(A) What is the elapsed time?
(B) What is the total distance traveled?
(C) What is the total displacement?
(D) What is the average speed for the trip?
(E) What is the average velocity for the trip

Answers

Answer:

Explanation:

(A) What is the elapsed time?

t = 6.5 + 3.0 + .05 = 10 hr

(B) What is the total distance traveled?

d = 250 + 155 + 32 = 437 km

(C) What is the total displacement?

d = √((250 - 32)² + 155²) = 267.48644... = 267 km

as displacement is a vector, we also need a direction

θ = arctan((250 - 32) / 155) = 54.6° S of W

(D) What is the average speed for the trip?

437/10 = 43.7 km/hr

(E) What is the average velocity for the trip

267/10 = 26.7 km/hr  54.6° S of W

Alicia is naturally rather shy and is graduating from college. She will need to find a job, so she is starting to go on job websites and work on her
resume. She knows she should network, but it sounds a little intimidating. What is the BEST advice for Alicia?
ОА. If she is not comfortable networking, she will never find a job.
ОВ. The majority of jobs are found through networking, so she should really try it.
OC. Networking is overrated, so she can skip that part of the job search process.
OD If she is naturally shy, she probably has really poor social skills and should work on that.

Answers

Answer:

OB and i have no reasoning

which theory says dreaming is an unimportant by-product of neural firing during sleep

Answers

Answer:activation-synthesis

Explanation:

help me plzzz

The punter on a football team tries to kick a football so that it stays in the air for a long "hang
time". If the ball is kicked with an initial velocity of 30 m/s at an angle of 60 degrees above the
ground.

a. Calculate the "hang time".

b. How far does the ball go in the horizontal direction?

c. What is the maximum altitude (height) the ball reaches?

Answers

first resolve the initial velocity of the ball into two components

1)one parallel to ground(u)

2)another perpendicular to ground(v)

call the initial velocity=p=25.4 m/s at 58.0° deg to ground

so the horizontal component of velocity=25.4cos58=13.46 m/s

so the vertical component of velocity=25.4sin58=21.54 m/s

we have nothing to do with the horizontal component of velocity as it plays no part in the hang time

only vertical component of velocity determines the hang time

hang time=2*(vertical component of velocity)/(acceleration due to gravity)

==>hang time=2*21.54/9.8=4.39 s

==>hang time =4.39 s

If I'm wrong please let me know, thank you.

HELP PLS!!

What are open, closed and isolated systems?

Answers

Open systems allow energy and mass to pass across the system boundary. A closed system allows energy but not mass across its system boundary. An isolated system allows neither mass or energy to pass across the system boundary

what is the full distance when an object is thrown at 35 m/s at an angle of 45 degrees

what is the full distance when an object is thrown at 35 m/s at an angle of 45 degrees

Answers

Okay, here are the steps to calculate the full distance traveled when an object is thrown at a certain speed and angle:

You have the initial velocity (v): 35 m/s

You have the launch angle (θ): 45 degrees

We need to split the initial velocity into its horizontal (vx) and vertical (vy) components.

To calculate vx (horizontal component):

vx = v * cosθ

vx = 35 * cos(45) = 24.7 m/s

To calculate vy (vertical component):

vy = v * sinθ

vy = 35 * sin(45) = 24.7 m/s

We can calculate the horizontal distance (d) traveled using:

d = vx * t (where t is time)

Since there is no air resistance, the vertical velocity (vy) will remain constant. This means the time the object is in the air is:

t = vy / g (where g is acceleration due to gravity, 9.8 m/s^2)

t = 24.7 / 9.8 = 2.52 seconds

Now we can calculate the full horizontal distance traveled:

d = vx * t

d = 24.7 * 2.52

= 62.3 meters

So the full distance the object will travel when thrown at 35 m/s at a 45 degree angle is approximately 62 meters.

Let me know if you have any other questions!

Answer:

To calculate the full distance traveled by an object thrown at a velocity of 35 m/s at an angle of 45 degrees, we need to consider the horizontal and vertical components of the motion separately.

The horizontal component of the motion remains constant throughout the trajectory and is given by:

Horizontal distance = (Initial velocity) * (Time of flight) * cos(angle)

In this case, the initial velocity is 35 m/s, the angle is 45 degrees, and we need to find the time of flight.

The time of flight can be calculated using the vertical component of the motion. The vertical motion can be described using the equation:

Vertical displacement = (Initial velocity * sin(angle))^2 / (2 * acceleration)

Where the initial velocity is 35 m/s, the angle is 45 degrees, and the acceleration is the acceleration due to gravity, approximately 9.8 m/s^2.

The vertical displacement is zero at the highest point of the trajectory since the object comes back down to the same height it was launched from. So we can solve the equation for the time of flight.

Using these calculations, we can find the horizontal distance traveled by the object.

Let's calculate step by step:

Step 1: Calculate the time of flight

Vertical displacement = 0 (at the highest point)

0 = (35 * sin(45))^2 / (2 * 9.8)

0 = (24.75^2) / 19.6

0 = 616.0125 / 19.6

0 = 31.43

Step 2: Calculate the time of flight

Vertical displacement = (Initial velocity * sin(angle)) * time - (1/2) * acceleration * time^2

0 = (35 * sin(45)) * time - (1/2) * 9.8 * time^2

0 = 24.75 * time - 4.9 * time^2

4.9 * time^2 - 24.75 * time = 0

time * (4.9 * time - 24.75) = 0

time = 0 (initial point) or 24.75 / 4.9

time = 5.05 seconds

Step 3: Calculate the horizontal distance

Horizontal distance = (Initial velocity) * (Time of flight) * cos(angle)

Horizontal distance = 35 * 5.05 * cos(45)

Horizontal distance = 35 * 5.05 * (sqrt(2)/2)

Horizontal distance = 88.96 meters

Therefore, when an object is thrown at 35 m/s at an angle of 45 degrees, the full distance traveled is approximately 88.96 meters.

What is the force of gravity (in newtons) acting between the earth and a 5 kg bowling ball that is resting on the surface of the earth

Answers

Answer:

49 N

Explanation:

F = m a

 = 5 * 9.81 =~ 49 N

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