A 0.59−kg particle has a speed of 5.0 m/s at point A and kinetic energy of 7.6 J at point B. (a) What is its kinetic energy at A ? J (b) What is its speed at point B ? m/s (c) What is the total work done on the particle as it moves from A to B ? J 0.18−kg stone is held 1.2 m above the top edge of a water well and then dropped into it. The well has a depth of 5.4 m. (a) Taking y=0 at the top edge of the well, what is the gravitational potential energy of the stone-Earth system before the stone is released? ] (b) Taking y=0 at the top edge of the well, what is the gravitational potential energy of the stone-Earth system when it reaches the bottom of the well? J (c) What is the change in gravitational potential energy of the system from release to reaching the bottom of the well?

The strength of the magnetic field at the center of the solenoid is 0.006 T

The strength of the magnetic field at the center of a solenoid is given by:

B = μ₀ * n * I

where B is the magnetic field strength, μ₀ is the permeability of free space, n is the number of turns per unit length of the solenoid, and I is the current flowing through the solenoid.

In this case, the length of the solenoid is not given, but we can assume that it is much greater than the diameter of the solenoid, so we can treat it as a long solenoid. The number of turns per unit length is given as 200 loops divided by the length of 6.5 cm, or:

n = 200 / 0.065 m = 3076.92 turns/m

The current flowing through the solenoid is 5 A.

The permeability of free space, μ₀, is a constant with a value of 4π x 10^-7 T m/A.

Therefore, the magnetic field strength at the center of the solenoid is:

B = μ₀ * n * I

= 4π x 10^-7 T m/A * 3076.92 turns/m * 5 A

= 0.006 T

So the strength of the magnetic field at the center of the solenoid is 0.006 T. The north pole of the solenoid is the end from which the magnetic field emerges, and the south pole is the end where it enters.

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Answer:

8.6 to west

Explanation:

The initial momentum of the system is given by the sum of the momentum of the launcher and the momentum of the balloon. The correct answer is option C. 7.6 m/s west.

To solve this problem, we can apply the principle of conservation of momentum. According to this principle, the total momentum before an event is equal to the total momentum after the event, assuming no external forces act on the system.

The momentum of an object is calculated by multiplying its mass by its velocity.

Initial momentum = (mass of launcher × velocity of launcher) + (mass of balloon × velocity of balloon)

Let's substitute the given values into the equation:

Initial momentum:

\((1.75 kg * 0 m/s) + (1.25 kg * 12.0 m/s)\)

Initial momentum = 15 kg·m/s

Since the net force on the launcher is equal to the reaction force, we can assume no external forces act on the system. Therefore, the total momentum before firing the balloon is equal to the total momentum after firing the balloon.

Final momentum = (mass of launcher + mass of balloon) × final velocity of the launcher

Let's solve for the final velocity of the launcher:

Final momentum:

\((1.75 kg + 1.25 kg)\) × Final velocity of the launcher

15 kg·m/s = 3 kg × final velocity of the launcher

Dividing both sides of the equation by 3 kg gives us:

The final velocity of the launcher = 15 kg·m/s / 3 kg

The final velocity of the launcher = 5 m/s

Since the initial velocity of the balloon is to the east, the final velocity of the launcher will be to the west. Therefore, the correct answer is option C. 7.6 m/s west.

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Answer:

‍♂️

Explanation:

‍♂️‍♂️‍♂️

Answer:

first answer is C,second answer is A, third answer is B

Answer:

c, a, b

Explanation:

Diagram (c) represents the force between the two charges. Like charges repel, each other, and unlike charges repel each other.

The electric force between the two charges is directly propotional to the product of the charge and inversly propotional to the square of the distance between them.

The electric force is found as;

\(\rm F = \frac{K q_1q_2}{r^2}\)

Like charges repel, each other, and unlike charges repel each other. Both the charge is of the opposite sign they attract each other.

Hence diagram (c) represents the force between the two charges.

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The electric field at a point on the x-axis, located at x = 36.0 cm, due to two particles with charges of 52.0 nC each, positioned on the y-axis at y = ±25.0 cm, can result in both magnitude and direction.

To find the electric field at the specified point, we can treat each particle individually and then sum up their contributions. The electric field produced by a point charge can be calculated using the equation E = k * (Q / r^2), where E is the electric field, k is the electrostatic constant (8.99 x 10^9 Nm^2/C^2), Q is the charge, and r is the distance from the charge to the point of interest.

For the particle located at y = 25.0 cm, the distance from the point on the x-axis (x = 36.0 cm) can be calculated as the hypotenuse of a right-angled triangle with sides 36.0 cm and 25.0 cm. Similarly, for the particle located at y = -25.0 cm, the distance is calculated as the hypotenuse of a triangle with sides 36.0 cm and 25.0 cm. Once the distances are determined, we can plug the values into the equation for the electric field and find the magnitude and direction of the field at x = 36.0 cm.

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Answer:   b or c

Explanation:  on khan academy

Answer:

A dicot is a flowering plant that has one seed leaves. The monocot plants have a single cotyledon. Maize only has one cotyledon in their seed, so it's a monocot. Seeds having two Cotyles are mainly called a Dicot. A pea is a dicotyledonous plant, the seed (the pea itself) has two halves, cotyledons, hence dicot being 2.

Explanation:

One or more of the cotyledons are the first to appear from a germinating seed. Based on the number of cotyledons, botanists classify flowering plants (angiosperms) into :

a) plants with one embryonic leaf, termed monocotyledonous (monocots).

b) plants with two embryonic leaves, termed dicotyledonous (dicots).

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Given that the charges are divided in half, 1:2,

According to Newton's third law, every action has a corresponding and opposing response. This means that the force applied by Q1 to Q2 is equal to the force applied by Q2 to Q1. However, these forces will be acting in the opposite manner.

The ratio of the force's magnitude on q1 to its magnitude on q2 is therefore 1:1.

If charges q1 and q2 have the same sign (both positive or both negative), then the forces acting on each charge are mutually repulsive and point away from one another. One charge is positive and the other is negative, according to the equation.

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Starting from rest on a circular track with a radius of 300 m and a constant tangential acceleration of 0.75 m/s², the car will travel a distance of approximately 0.2119 meters or 21.19 centimeters in 0.75 seconds.

To determine the distance traveled and the time elapsed by the car starting from rest on a circular track with a radius of 300 m and a constant tangential acceleration of 0.75 m/s², we can use the equations of circular motion.

The tangential acceleration is the rate of change of tangential velocity. Since the car starts from rest, its initial tangential velocity is zero (v₀ = 0).

Using the equation:

v = v₀ + at

where v is the final tangential velocity, v₀ is the initial tangential velocity, a is the tangential acceleration, and t is the time, we can solve for v:

v = 0 + (0.75 m/s²) * t

v = 0.75t m/s

The tangential velocity is related to the angular velocity (ω) and the radius (r) of the circular track:

v = ωr

Substituting the values:

0.75t = ω * 300

Since the car starts from rest, the initial angular velocity (ω₀) is zero. So, we have:

ω = ω₀ + αt

ω = 0 + (0.75 m/s²) * t

ω = 0.75t rad/s

We can now substitute the value of ω into the equation:

0.75t = (0.75t) * 300

Simplifying the equation gives:

0.75t = 225t

t = 0.75 seconds

The time elapsed is 0.75 seconds.

To calculate the distance traveled (s), we can use the equation:

s = v₀t + (1/2)at²

Since the initial velocity (v₀) is zero, the equation becomes:

s = (1/2)at²

s = (1/2)(0.75 m/s²)(0.75 s)²

s = (1/2)(0.75 m/s²)(0.5625 s²)

s = 0.2119 meters or approximately 21.19 centimeters

Therefore, the car travels a distance of approximately 0.2119 meters or 21.19 centimeters.

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Answer:

deuteron

Explanation:

Answer:

C. The Third Picture

Explanation:

EDGE 2021

The linear speed of the electron is 7.03 x 10¹³ m/s and the angular speed of the electron is 5.6 x 10¹³ rev/s.

The speed of the electron is calculated as follows;

F = ma = mv²/r  ---(1)

F = qvB  ----- (2)

mv²/r = qvB

mv/r = qB

mv = qBr

v = qBr/m

where;

v = (1.6 x 10⁻¹⁹ x 2 x 10³ x 0.2) / (9.1 x 10⁻³¹)

v = 7.03 x 10¹³ m/s

ω = v/r

ω = (7.03 x 10¹³ m/s) / (0.2 m) = 3.51 x 10¹⁴ rad/s

ω = 3.51 x 10¹⁴ rad/s  x 1 rev/2π rad

ω = 5.6 x 10¹³ rev/s

Thus, the linear speed of the electron is 7.03 x 10¹³ m/s and the angular speed of the electron is 5.6 x 10¹³ rev/s.

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Answer:Examples of input devices include keyboards, mouse, scanners, cameras, joysticks, and microphones.

pls mark brainliest

Explanation:

Answer:6000

Explanation:

Kinetic Energy is the energy an object has owing to its motion. In classical mechanics, kinetic energy (KE) is equal to half of an object's mass (1/2*m) multiplied by the velocity squared. For example, if a an object with a mass of 10 kg (m = 10 kg) is moving at a velocity of 5 meters per second (v = 5 m/s), the kinetic energy is equal to 125 Joules, or (1/2 * 10 kg) * 5 m/s2. We use Joules, kilograms, and meters per second as our defaults, although any appropriate units for mass (grams, ounces, etc.) or velocity (miles per hour, millimeters per second, etc.) could certainly be used as well - the calculation is the same regardless.

Answer:

2nd one :)

Explanation:

Answer:  the second one

Explanation:

The magnitude of the charge that is carried by each of the balloons is 7.6 *10^-7 C.

The link between the electric charges of two objects and the force acting between them is described by Coulomb's law, a fundamental principle of electrostatics.

We know that according to the Coulomb's law we can be able to write that;

F = Kq^2/r^2

k is a proportionality constant called Coulomb's constant, which has a value of approximately 9 x 10^9 N·m^2/C^2 in a vacuum.

0.0648 = 9x10⁹ q^2/(0.079524)

q = √0.0648 (0.079524)/9x10⁹

q = 7.6 *10^-7 C

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Answer:(:

Explanation:

discovered alpha and beta rays, and proposed the laws of radioactive decay.

Answer:

products would appear after the raw materials

Explanation:

raw material + raw material = product (anything deriving from combining two materials)

Answer:

electrical conductivity in liquid solutions depends on the availability of free ions.

Show us the experiment then

Answer:

D. The rock cycle takes too long to be able to observe it in entirety.

Explanation: is answer

After watching the Ted Talk, there were still a few questions that I had about supermassive black holes. Firstly, I wanted to know more about the event horizon and what it exactly entails. Although the speaker briefly touched upon this subject, I would have appreciated a more in-depth explanation. Additionally, I would have liked to know more about the role of supermassive black holes in the universe.

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When two rope segments pull up on the load in the single movable pulley, the optimal mechanical advantage is 2. This sort of pulley does not change the direction of the applied force, but it does increase it by a factor of two.

There are two methods for calculating a pulley system's mechanical advantage.

The mechanical advantage may be calculated simply by counting the number of falls (or active lifting ropes) that are really attached to the load. You may also split the effort distance by the load distance.

Assuming an ideal rope and pulley system with a mechanical advantage of  \(2.00\) , the output load that can be lifted with an input force of \(200 N\) can be calculated using the formula:

Output force = Input force x Mechanical advantage

Where the mechanical advantage is given as \(2.00\)  .

Thus, the output force is:

Output force \(= 200 N \times 2.00 = 400 N\)

Therefore, with an input force of \(200 N\)  , the rope and pulley system can lift an output load of up to \(400 N\) .

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Given :

Father drove 176 km in 7 hours.

For the first 92 km he spent for 4 hours.

To Find :

His average speed for the remaining journey .

Solution :

\(v_{avg}=\dfrac{u_1+u_2}{2}\\\\v_{avg}=\dfrac{u_1}{2}+\dfrac{u_2}{2}\\\\\dfrac{176}{7}=\dfrac{92}{4\times 2}+\dfrac{u_2}{2}\\\\\dfrac{u_2}{2}=\dfrac{176}{7}-\dfrac{92}{8}\\\\u_2=13.64\times 2 \ km/h\\\\u_2=27.28\ km/h\)

Therefore , his average speed for the remaining journey is 27.28 km/h .

Hence , this is the required solution .

Answer:

false

Explanation:

E2020

Answer:

false

Explanation:

Answer:

Both balls will reach the ground at the same time

Explanation:

That is because the acceleration due to gravity of both balls are same.

Answer:

Explanation:

4.  Density of water = 1.01g/ml

6:  Mass of silver = 892.5g

8:  Mass of 157.8g  I gave the answer as mass, even though it asked for weight.