The speed of the 9.00-kg ball after the perfectly elastic collision with the 10.0-kg ball, which has a velocity of 3.00 m/s initially, is approximately 3.14 m/s.
To find the speed of the 9.00-kg ball after the collision, we can use the principle of conservation of momentum.
According to the principle of conservation of momentum, the total momentum before the collision is equal to the total momentum after the collision in an isolated system.
p = m * v
Before the collision, the 10.0-kg ball has a velocity of 3.00 m/s and the 9.00-kg ball is stationary (v = 0 m/s).
Before the collision, the total initial momentum, where m1 and v1 are the mass and velocity of the 10.0-kg ball, and m2 and v2 are the mass and velocity of the 9.00-kg ball.
P_initial = (10.0 kg) * (3.00 m/s) + (9.00 kg) * (0 m/s)
= 30.0 kg m/s
After the collision, the 9.00-kg ball is sliding away with a velocity (v_final) and the 10.0-kg ball has a velocity of 0.156 m/s.
Final momentum after the collision is:
P_final = (10.0 kg) * (0.156 m/s) + (9.00 kg) * (v_final)
The system's entire kinetic energy is conserved since the impact is fully elastic. As a result, we can compare the initial and end kinetic energies:
(1/2) * m1 * v1^2 + (1/2) * m2 * v2^2 = (1/2) * m1 * v1'^2 + (1/2) * m2 * v2'^2
(1/2) * (10.0 kg) * (3.00 m/s)^2 + (1/2) * (9.00 kg) * (0 m/s)^2 = (1/2) * (10.0 kg) * (0.156 m/s)^2 + (1/2) * (9.00 kg) * (v_final)^2
Simplifying the equation, we can solve for v_final:
45.0 J = 0.612 J + (1/2) * (9.00 kg) * (v_final)^2
44.4 J = (1/2) * (9.00 kg) * (v_final)^2
v_final^2 = (44.4 J) / (4.5 kg)
v_final^2 = 9.87 m^2/s^2
v_final ≈ √9.87 m^2/s^2
v_final ≈ 3.14 m/s
Therefore, the speed of the 9.00-kg ball after the collision is approximately 3.14 m/s.
The speed of the 9.00-kg ball after the perfectly elastic collision with the 10.0-kg ball, which has a velocity of 3.00 m/s initially, is approximately 3.14 m/s.
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What are the four theories of the origin of the moon?
why it is important to have a regular
supervision of the weight and measurement and in the market
_____ is described as the change in potential energy per unit charge in an electric field.
Question 18 options:
Gravitational field
Electric potential difference
Electric field
Electric field line
A hot-air balloon is ascending at a rate of 7.5m/s when a passenger drops a camera. If the camera is 27m above the ground when its dropped, how much time does it take for the camera to reach the ground? What is its velocity just before it lands?
Answer:
v_{f}=21.75[m/s] (velocity just before it lands)
t = 2.98 [s]
Explanation:
The key to solving this problem is the initial velocity since when the camera falls it is moving up, we will take this velocity as negative and the acceleration gravitation down as positive.
We will use the following equation of kinematics to solve this problem.
\(V_{f}^{2} =V_{o}^{2}+2*g*y\)
where:
Vf = final velocity [m/s²]
Vo = initial velocity = 7.5 [m/s]
g = gravity acceleration = 9.81 [m/s²]
y = elevation = 27 [m]
\(v_{f}^{2} = - (7.5)^{2} +(2*9.81*27)\\ v_{f}^{2} = 473.5\\v_{f}=\sqrt{473.5}\\v_{f}=21.75[m/s]\)
Now using the following equation of kinematics, we can calculate the time that the fall lasts.
\(v_{f}=v_{o}+g*t\)
\(21.75 = -7.5 +9.81*t\\9.81*t = 29.25\\t = 2.98[s]\)
5. An airplane must reach a velocity of 71 m/s for takeoff. If the runway is 1.0 km long, what
must the constant acceleration be?
Answer:
final velocity 'v' = 71m/s distance 's' = 1000m intial velocity 'u' =0 therefore,using third equation of motion v^2- u^2=2*a*s 71*71=2*a*1000 a=71*71/(2*1000 a= 2.52m/s^2
Explanation:
Mrs. Byers is swinging a mass on a string above her head with a radius of 7 m. If she decreases the radius by a factor of 7, by what factor does the centripetal acceleration change?
Answer:
Explanation:
Given:
V₁ = V₂ = V
R₁ = 7 m
n = 7
R₂ = R₁ / n = 7 / 7 = 1 m
____________
aₙ₂ / aₙ₁ - ?
aₙ₁ = V₁² / R₁ = V² / 7
aₙ₂ = V₂² / R₂ = V² / 1 = V²
aₙ₂ / aₙ₁- = V² / (V²/7) = 7
Centripetal acceleration increased by 7 times
PLEASE HELP I may just need the Element name and I can figure out the rest!!!!
Answer:
First one after Oxygen is Oxygen. Then Iron(Fe). Then Carbon(C). Then Potassium(K)
during tug of war team adoes 2.20 10^5* J of work in pulling team b 8.00 m. what combined force was team a exerting
Answer:
27,500 N
Explanation:
W = Fd
F = W/d = (2.2x10⁵J)/(8 m ) = 27,500 N
Un ladrillo de 2kg que se encuentra a 200º c, se sumerge en 5 kg de agua a 32º¿a que temperatura se alcanza el equilibrio térmico?
Answer:
El equilibrio térmico se alcanzará a los 152ºC.
Explanation:
Dado que un ladrillo de 2kg que se encuentra a 200º c, se sumerge en 5 kg de agua a 32º, para determinar a qué temperatura se alcanza el equilibrio térmico se debe realizar el siguiente cálculo:
2+5 = 7
(200 x 5 + 32 x 2) / 7 = X
1064 / 7 = X
152 = X
Por lo tanto, el equilibrio térmico se alcanzará a los 152ºC.
Qualitatively compare the following quantities for objects a and b. If a has the greater value write a in the blank. If b has the greater value write b
It is not possible to provide a qualitative comparison between objects a and b without knowing the specific quantities being compared.
To make a qualitative comparison, we need to know the specific attributes or characteristics being compared. Without this information, we cannot determine which object has a greater value. For example, if the quantities being compared are size, weight, or temperature, we would need the specific values for a and b to make a comparison.
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How long would it take you to travel 163 meters at a speed of 33 meters per second?
Speed=
\(33m {s}^{ -1} \)
Distance=
\(163m\)
speed= distance/time
So,
Time= distance/speed
Time= 163/33
=\(\huge\underline\mathtt\colorbox{cyan}{4.9393s}\)
doc based on this lab: https://phet.colorado.edu/sims/html/wave-on-a-string/latest/wave-on-a-string_en.html
Answer:
hope it helps make brainlliest ty
Please help I don't understand how to do any of this!!!!!!!!
The temperature of 3.0 L of nitrogen gas is raised from 200. K to 300. K; what is the new volume of the gas?
Answer:
solve the ratio so 200 to 300 that dicid eby 3.0 then times
Which is an example of potential energy? a swimmer kicking their legs a car driving on the road an arrow flying at a target a yo-yo in someone’s hand
Answer:
The yo-yo :)
Explanation:
The energy E of a photon and its wavelength are related by E λ =X. What is the numerical value of X. (h=6.63*10^-34Js; c=3*10^8m/s) (10 pts)
Answer:
19.89×10^-26Jm
Explanation:
The Energy of a photon is given as;
E = h×c/λ
Where h is Plank's constant.
c is speed of light
λ is the wavelength.
By multiplying both sides of the equation to λ
E × λ = h×c/λ × λ
E × λ = h×c
= 6.63×10^-34× 3×10^8
= 19.89×10^-26Jm
A runner starts at point A, runs around a 1-mile track and finishes the run back at point A. Which of the following statements is true?
This question is incomplete because the options are missing; here is the complete question:
A runner starts at point A, runs around a 1-mile track, and finishes the run back at point A. Which of the following statements is true?
A. The runner's displacement is 1 mile.
B. The runner's displacement is zero.
C. The distance the runner covered is zero.
D. The runner's speed was zero.
The answer to this question is B. The runner's displacement is zero
Explanation:
Displacement always implies a change of position; this means an object or individual moves from point A to point B, and therefore the original position is different from the final position. Additionally, in displacement, other related factors such as the total distance the body moved and the direction of movement. In the case presented, it can be concluded there was no displacement or the displacement is zero because even when the runner moved and ran two miles, he returned to the initial position, and without a change in the position, there is no displacement.
I am unsure about what I'm suppose to do
Answer:
1st box: increase
supporting evidence: As the girl swings downward she will gain more height due to the increasing force pushing her
2nd box: increase
supporting evidence: the magnetic force of the earth will increase the kinetic energy of the girl when she goes downward slightly as she swings forward
3rd box :increase
supporting evidence:As the girl swings downward she will gain more speed due to the gravitational pull
Explanation:
A cylinder of lead has a diameter of 3 centimeters and a height of 8 centimeters. The density of lead is 11.4 g/cm3. What is the mass of the cylinder
Answer:
m = 644.67
Explanation:
m = v x d
m = pi x r^2 x h x d
m = 56.55 x 11.4
The mass of the cylinder with diameter and height of 3 cm and 8 cm respectively is 644.3 grams.
Which term is equivalent to product of density and volume?The product of density and volume of a body represents its mass. Mathematically -
M = V x ρ
ρ - density
M - mass
V - volume
Given is a cylinder of lead that has a diameter of 3cm and a height of 8 cm. The density of lead is 11.4 g/cm3.
The product of density and volume of a body represents its mass
M = V x ρ
Volume of cylinder = πr²h
Therefore, we can write -
M = πr²h x ρ
M = 3.14 x 3/2 x 3/2 x 8 x 11.4
M = 56.52 x 11.4
M = 644.3 grams
Therefore, the mass of the cylinder with diameter and height of 3 cm and 8 cm respectively is 644.3 grams.
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help ill give brainleist
Mechanical energy is lost:
when parts rub against each other
when heat radiates from the engine
whenever friction is present
all of the above
Transformation of Energy
5. Explain how forming an ionic bond makes metal and nonmetal atoms more stable.
6. Describe how metallic bonds contribute to the physical characteristics of a metal.
7. Describe the type of ions created through metallic bonding.
8. List the three types of atomic bonds and describe the types of atoms-metal
or nonmetal-that form each type of bond.
A 4000 kg truck traveling at 10 m/s collides with a 1000 kg car that is at rest. Answer the following questions concerning the collision. (Circle all that apply. Consider only the magnitude of the values, ignore the fact that some are negative numbers. )
A) Which experiences a larger force? truck or car or neither
B) Which experiences a larger impulse? truck or car or neither
C) Which experiences a larger change in momentum? truck or car or neither
D) Which experiences a larger change in velocity? truck or car or neither
I will mark brainliest if correct! Please!
Ignore the fact that some of the values are negative numbers and instead consider their magnitude.
A) Both are experience large force.
B) Both are experience large impulse.
C) Both are experience large momentum.
D) Car experience large change velocity.
What does the word collides mean?collision; collision To come together and have a strong or direct effect is an intransitive verb. The vehicle struck a tree. Hovercraft collision
According to the solving:Utilizing the rule of conservation of momentum, we can find a solution to this issue. If there are no outside forces, the truck-car system's total momentum must be preserved both before and after the collision.
Truck of mass m1 = 4000kg
velocity of truck V1 = 10m/s
Car of mass m2 = 1000kg
let
velocity of car V2
principle of conservation of momentum use
m1V1=m2V2
4000×10=1000×V2
V2=40000/1000
V2=40m/s
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FILL THE BLANK. the ________________ cortex receives most of its input from the thalamic relay nuclei of a given sensory system.
The term you're looking for is "primary sensory cortex." The primary sensory cortex receives most of its input from the thalamic relay nuclei of a given sensory system.
The primary sensory cortex, often referred to as the primary somatosensory cortex or primary visual/auditory cortex, is a portion of the brain that collects and interprets sensory data from numerous body regions. For somatosensory processing, it is situated in the parietal lobe, for visual processing in the occipital lobe, and for auditory processing in the temporal lobe. The perception and interpretation of sensory stimuli like touch, pressure, pain, visual input, and aural signals are fundamentally influenced by the primary sensory cortex. It is in charge of encoding and organising sensory data, which enables us to experience and comprehend the outside world.
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A biker travels once around a circular track of radius 20.0m in3s calculate the average tangential speed
Answer:
the average tangential speed of the biker is approximately 41.89 m/s.
Which one is greater 2.62 , 2 2/5 , 26.8 , 2.26 , 271%.
In order to compare the numbers, let's put all of them into the decimal form:
\(\begin{gathered} 2.62 \\ \\ 2\frac{2}{5}=2+\frac{2}{5}=\frac{10}{5}+\frac{2}{5}=\frac{12}{5}=2.4 \\ \\ 26.8 \\ \\ 2.26 \\ \\ 271\text{\%}=\frac{271}{100}=2.71 \end{gathered}\)We can see that the greater one is 26.8 (all other numbers are close to 2, and this one is close to 27).
The numbers in decrescent order are:
26.8, 271%, 2.62, 2 2/5, 2.26.
Answer:
26.8
Explanation:
2.26 < 2.4 < 2.62 < 271/100 = 2.71 < 26.8
32g of water at 60°C is poured into 60g of cold water at 15°C, which is contained in a
calorimeter of mass 40g, and S.H.C of water is 0.1Jg'K'. Neglecting heat loss show that
the resulting temperature is 29°C.
Explanation:
Let thermal capacity of the vessel be C' J K-1
Heat energy given by hot water = 40 x 4.2 x (60 - 30) = 5040 J
Heat energy taken by cold water = 50 x 4.2 x (30 - 20) = 2100 J
Heat energy taken by vessel = C' x (30 - 20) = 10 C' J
If there is no loss of heat energy,
Heat energy given by hot water = Heat energy taken by cold water and vessel
or 5040 = 2100 + 10 C'
or 10 C' = 2940
or C'= 294 J K-1
Thus, thermal capacity of vessel = 294 J K-1.
HOPE IT HELPS mark me in brainliest answers please please pleaseALWAYS use significant figure rules. Remember that these rules apply to all numbers that are measurements.
In working this problem, assume the value of "g" to be 9.8 m/s2 with two (2) significant digits unless otherwise stated.
Given that a lever has a mechanical advantage of 6.0 and is 100% efficient, if the resistance is to be lifted 2.0 inches, then how far must the effort move?
De = _____ in.
12
8.0
4.0
3.0
NEXT
The effort must move 8•0
4.
A steel plate that weighs 200 N and has a u with the asphalt of 0.6. If the steel
plate is sliding along the asphalt (constant velocity), what is the force of friction present?
Given
Want
Equation and solve
Answer:
120N
Explanation:
The question gives us Mg = 200 N and in this equation Mg is equal to the normal force. Kinetic friction is calculated by normal force * coefficient of kinetic friction. Therefore kinetic friction = 200N * 0.6 = 120N
An atmospheric layer of a specific gas provides shielding from harmful ultraviolet light from the sun, allowing life to thrive on earth. What gas makes up this layer?.
The gas that makes up this layer is O3 (Ozone).
The ozone layer protects the earth from most of the sun's UVB rays. Greenhouse gases are a set of gases that accumulate in the lower layer of the atmosphere the troposphere and absorb infrared radiation to increase the average temperature of the Earth's surface. At the top of the stratosphere, 30 miles up, ozone absorbs most of the sun's harmful UV rays.
At the top of the troposphere 12 miles, up ozone acts as a greenhouse gas and traps heat. The troposphere is the lowest layer of the Earth's atmosphere. Most of the atmospheric mass is in the troposphere. Most types of clouds are in the troposphere, and almost all weather phenomena occur in this layer. Greenhouse gases are so named because they absorb infrared radiation from the sun in the form of heat which circulates in the atmosphere and is eventually lost to space.
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During an autumn storm, a 0.012-kg hail stone traveling at 20.0 m/s made a0.20-cm-deep dent in the hood of Darnell's new car. What average force didthe car exert to stop the damaging hail stone?
Answer:
1200 N
Explanation:
First, we need to calculate how much time the force was applied. If the stone traveled at 20.0m/s and made a 0.20 cm deep dent, the time is equal to
\(\text{ Avg }speed=\frac{distance}{time}\Rightarrow time=\frac{distace}{Avg\text{ }speed}\)Where the distance is 0.20 cm = 0.0020 m and the average speed can be calculated as:
\(\text{ avg speed = }\frac{v_i+v_f}{2}=\frac{20\text{ m/s + 0 m/s}}{2}=10\text{ m/s}\)Therefore, the time is equal to
\(time=\frac{0.0020\text{ m}}{10\text{ m/s}}=0.0002\text{ s}\)Then, the force can be calculated using the following equation for impulse
\(\begin{gathered} Ft=mv \\ F=\frac{mv}{t} \end{gathered}\)Where m is the mass, v is the speed and t is the time, so replacing m = 0.012 kg, v = 20 m/s and t = 0.0001 s, we get
\(F=\frac{0.012\text{ kg \lparen20 m/s\rparen}}{0.0002\text{ s}}=1200N\)So, the average force was 1200 N
During autumn, the storm travels at a speed of 20 m/s, then the average force the car has to exert to stop the damaging hail storm is 1200 N.
What is Force?A force in physics is an effect that has the ability to modify an object's motion. A bulk object's velocity can vary, or accelerate, as a result of a force. Intuitively, a push or a pull can be used to describe force. Being a vector quantity, a force also has magnitude and direction. The SI unit of newton is used to measure it (N). The letter F symbolizes for force.
As per Newton's second law's original formulation, an object's net force is equal to the speed at which momentum is changing over time.
According to the given information in the question,
Speed, s= 20 m/s
Average speed, s = Distance/Time
s = [v(i) + v(f)] / 2
s = (20 + 0)/2
s = 10 m/s
Now calculate the time,
Time, t = 0.0020/10
t = 0.0002 seconds.
Use the equation for impulse,
f × t = mv
⇒f = mv/t
f= (0.012 × 20)/0.0002
f = 1200 N
Therefore, the force applied is 1200 N.
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a 5.4kg ball is dropped from a cliff and it accelerates downward due to the force of gravity. what is the ball's downward velocity after 3 seconds of freefall? (assuming we ignore air resistance)
Answer:
velocity = 29.4 m/s
Explanation:
We have been told to calculate the velocity of a ball after 3 seconds of freefall. To do this, we can use the following formula:
\(\boxed{v = u + at}\),
where:
• v = final velocity
• u = initial velocity
• a = acceleration
• t = time of freefall
In this case, u = 0 m/s, because the ball is initially stationary before it is released. Also, a = 9.81 m/s² because the ball is falling while inside the Earth, where the acceleration of freefall is 9.81 m/s².
Using the above information along with the formula, we can calculate the velocity of the ball after 3 seconds of freefall:
v = 0 m/s + (9.81 m/s² × 3 s)
= 29.4 m/s