A 10cm long, 2cm wide wooden wedge is pushed into a soft wood block calculate the load on the soft wood if the effort applied id 30 N
Answers
The velocity ratio of the wedge is 0.1
The load on the soft wood is 300 N.
Related Questions
Under water, Zachary can hear waves that travel with frequencies up to 15,000 Hz. What is the velocity of sound in water if a wave with this frequency has a wavelength of 1.2 m?
Answers
Answer:
18 000 m/ s
Explanation:
speed = wavelength * frequency
speed = 1.2 * 15 000 = 18 000 m/s
HELP PLEASE!! GIVING BRAINLIEST!! If you answer this correctly ill answer some of your questions you have posted! (20pts)
Answers
Explanation:
potential energy =360800J
mass(m)=?
height (h)=25m
g=9.8m/s²
we have
potential energy =360800J
mgh=360800J
m×9.8×25=360800
m=360800/(9.8×25)=1472.653061kg
Answer:
HELP PLEASE!! GIVING BRAINLIEST!! If you answer this correctly ill answer some of your questions you have posted!
Which is an example of potential energy being transformed into kinetic energy?
A. A rock sitting at the top of a hill rolling down the hill.
B. A rock sitting at the top of a hill without moving.
C. A rock at the bottom of a hill being pushed up the hill.
D. A rock sitting at the bottom of the hill without moving.
Answers
Answer:
B is the right answer
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when an object is placed 12 inches from the face, how will the lens change to help focus on the object?
Answers
When an object is placed 12 inches from the face, then the lens : will thicken and therefore refract light more strongly.
How does the lens change to focus on objects that are close?The process of changing the shape of the lens to focus on near or distant objects is called accommodation. To focus on a near object , lens becomes thicker which allows the light rays to refract more strongly.
Cornea provides most of the eye's optical power or light-bending ability. When the light passes through the cornea, it is bent again for more finely adjusted focus by the crystalline lens inside the eye. Lens helps in focusing the light on the retina.
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How many grams are in 0. 02mol of Mg (25. 3g/mol)
Answers
There are 0.506 grams in 0.02 moles of Mg
To find the grams of Mg in 0.02 mol, you can use the formula:
grams = moles × molar mass
In this case, moles = 0.02 mol, and the molar mass of Mg = 25.3 g/mol. Plug in the values:
grams = 0.02 mol × 25.3 g/mol
grams = 0.506 g
So, there are 0.506 grams of Mg in 0.02 mol.
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when there is zero voltage across an ideal photocell, the amount of current that flows from the photocell is:
Answers
When there is zero voltage across an ideal photocell, the amount of current that flows from the photocell is zero.
What is a photocell? A photocell is a transducer that converts light energy into electrical energy. It is also known as a photoresistor or light-dependent resistor (LDR). It is a sensor that detects light and converts it into electricity.
A photocell is a component that senses light levels and reacts to them. It is a semiconductor device that has an electrical resistance that changes depending on the amount of light it receives.
The amount of light received by a photocell is proportional to the current generated. As the light intensity decreases, the resistance of the cell increases.
The current through the circuit and the voltage across the circuit decrease when the resistance of the cell increases.The current that flows from an ideal photocell when there is zero voltage across it is zero.
The photocell produces a current proportional to the amount of light it receives. As a result, the ideal photocell has zero current when there is zero voltage across it. The photoelectric effect is responsible for the current generated by a photocell.
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An engineer is troubleshooting trying to figure out the value of a capacitor. She knows that the charge value is 480 coulombs and the power supply feeds 110 V. What's the capacitor value?Question 19 options:A) 128B) 4.36C) 0.88D) 5,400
Answers
We can use the formula of the capacitance
\(C=\frac{Q}{V}\)where C is the capacitance, Q is the charge and V is the voltage.
In our case
Q=480 C
V= 110 V
\(C=\frac{480}{110}=4.36\text{ F}\)The value of the capacitor is 4.36 F
ANSWER B) 4.36F
when an object is placed 20 cm from a diverging lens, areduced image is formed. which one of the following statements isnecessarily true?
a. the image is inverted
b. the image could be real
c. the image distance must be greater than 20 cm
d. the focal length of the lens may be less than 20 cm
e. the refractive power of the lens must be greater than 0.05diopters
Answers
When an object is placed 20 cm from a diverging lens and a reduced image is formed, the following statement is necessarily true: d. the focal length of the lens may be less than 20 cm.
When an object is placed 20 cm from a diverging lens and a reduced image is formed, we can infer certain properties based on the nature of the lens and the resulting image.
a. The image is inverted: Since a diverging lens always produces virtual and upright images, the image formed in this case will also be upright. So, statement a is not necessarily true.
b. The image could be real: A diverging lens always produces virtual images that cannot be projected onto a screen. Therefore, statement b is not true.
c. The image distance must be greater than 20 cm: When a diverging lens forms a reduced virtual image, the image distance is negative. It means that the image is formed on the same side as the object. So, statement c is not true.
d. The focal length of the lens may be less than 20 cm: This statement is necessarily true. A diverging lens has a negative focal length, and the image formed by the lens will be virtual and reduced when the object is placed within the focal length of the lens.
e. The refractive power of the lens must be greater than 0.05 diopters: The refractive power of a lens is given by the reciprocal of the focal length. Since the focal length can be negative for a diverging lens, the refractive power can be negative as well. Therefore, statement e is not necessarily true.
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30 J of work are done in 15 seconds to push a bowl of fruit horizontally. What was the power delivered completing this task?
Answers
Answer:
Explanation:
The power delivered completing this task can be calculated using the formula Power = Work/Time. In this case, the power is equal to 30 J/15 s, which simplifies to 2 J/s. This can also be expressed as 2 Watts (W).
Important Formulas:
\(p=\dfrac{w}{t}\)
power(measured in watts) = work(measured in joules) / time(measured in seconds)
__________________________________________________________
Given:
\(w=30J\)
\(t=15s\)
\(p=?\)
__________________________________________________________
Finding power:
\(p=\dfrac{w}{t}\)
\(p=\dfrac{30}{15}\)
__________________________________________________________
\(\fbox{p = 2 watts}\)
A 560 Hz tuning fork and a piano key are struck together, and four beats are heard. When a 572 Hz tuning fork and the same piano key are struck, eight beats are heard. What is the frequency of the piano key?
564 Hz
556 Hz
572 Hz
560 Hz
Answers
Answer:
556
Explanation:
THERMAL ENERGY
Thermal energy is heat energy. In equation form, heat energy is represented as a (Q). The
unit for thermal energy is Joules (J). You can determine how much heat energy is lost or
gained when the temperature of a substance changes.
The equation to solve for change in thermal energy is ΔQ=CmΔT
Q=Thermal energy (J)
C= the specific heat of the object (g x°C)
m= mass (g)
T=temperature (°C)
Solve for change in thermal energy (Q) .
1. A 10.0 g piece of copper wire, sitting in the sun reaches a temperature of 80.0ºC. How
many Joules are released when the copper cools to 40.0ºC? The specific heat capacity of
copper is 0.377J/(gºC).
Q=?
C=
m=
Δt=
2. The specific heat capacity of water is 4.184 J/(gºC). How much thermal energy is
required to change the temperature of 700.0 g of water from 25.6ºC to 75.4ºC?
3. How much thermal energy is released when a 201 g piece of blown glass at an initial
temperature of 150ºC is cooled to 25ºC? The specific heat capacity of glass is 0.837
J/(gºC).
4. How much heat must be absorbed by a 500 g pot of water in order to raise the
temperature of the water from 20 °C to 30 °C? (specific heat capacity of water is 4.184
J/(g°C)
5. An element has a specific heat of 0.18 J/(gºC). If 10 g of this element are heated and release 345 J of energy, what would be the resulting change in temperature?
Answers
Q=150.8J
2. T= 75.4-25.6 = 49.8
Q = (700)(4.184)(49.8)
Q = 145854.24J
3. Q = (201)(0.837)(125)
Q= 21029.625J
4. Q = (500)(4.184)(10)
Q = 20920J
The speed, v, of an object moving along a straight line can be given in terms of time, t by v = at +b/(t-c)where a, b, c are constants. Assume, the expression is physically correct. If the dimensions of v are L/T, determine the dimensions of the terms a, b and c. Carefully layout your procedure.
Answers
Given
\(v=at+\frac{b}{t-c}\)
Procedure
Dimensions of v are L/T
The answer would be:
\(LT^{-2},L\text{ and T}\)The letter a is multiplying to one dimension in time, so it must be a value of distance over two of time. LT^(-2)
The letter b is in the numerator so it must be a distance dimension. L
The letter c is being operated as a subtraction in the denominator so it must be time T
the event that settled the shapley-curtis debate about the nature of spiral nebulae was the discovery of
Answers
The event that settled the Shapley-Curtis debate about the nature of spiral nebulae was the discovery of is cepheid variable stars in the Andromeda nebula.
History of Shapley-Curtis debate
In 1920, the so-called "Great Debate" took place between Harlow Shapley and Heber Curtis about the nature of the Milky Way, spiral nebulae and the dimensions of the universe. To support his claim that the Great Andromeda Nebula is an external galaxy, Curtis pointed out evidence of dark bands resembling the dust clouds present in the Milky Way as well as a significant Doppler shift.
The problem was definitively resolved in 1922 when the Estonian astronomer Ernst Öpik provided distance determinations that supported the theory that the Andromeda Nebula was legitimately a distant extragalactic object.
Using the Mount Wilson Observatory's new 100-inch telescope, Edwin Hubble was able to determine that the outer fields of some spiral nebulae were clusters of single stars and identified several Chepeid variable stars, which allowed him to estimate the distances of the nebulae: they were too far away to be able to form part of the Milky Way. In 1936 Hubble created a classification system for galaxies that is still used today, the Hubble sequence.
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In a 'keep-fit' exercise, a student of mass 45 kg steps 40 times on and off a box of height 0.50 m.
a) Calculate the weight of the student.
Answers
Weight of a body is the force with which the earth pulls on it. So W = mg = 45 * 9.8 newtons.
How can you calculate weight?Weight is a gauge of how strongly gravity is dragging something down. It relies on the mass of the item and the acceleration brought on by gravity, which on Earth is 9.8 m/s2. F = m 9.8 m/s2 is the formula for computing weight, where m is the object's mass in kilogrammes and N is the object's weight in Newtons (N).Body Mass Index (BMI) is calculated by dividing a person's weight in kilogrammes (or pounds) by their height in metres squared (or feet). High body fatness may be indicated by a high BMI. BMI does not make a body fat or health diagnosis for a person, but it does screen for weight categories that may cause health issues.Learn more about Weight refer to ;
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If a baseball lands with a speed of 80 miles/hr after traveling with an acceleration of -6 miles/hr/sec for 5seconds, what was the initial speed at which the ball was hit?
Answers
We are given that an object falls with an acceleration of -6 miles/h/s. To determine the initial velocity we will use the following motion:
\(v_f=v_0+at\)Where:
\(\begin{gathered} v_f,v_0=\text{ final and initial velocity} \\ a=\text{ acceleration} \\ t=\text{ time} \end{gathered}\)Now, we solve for the initial velocity by subtracting "at" from both sides:
\(v_f-at=v_0\)Now, we plug in the values:
\(80\frac{mi}{h}-(6\frac{mi}{hs})(5s)=v_0\)Now, we solve the operations:
\(50\frac{mi}{h}=v_0\)Therefore, the initial velocity is 50 mi/h.
Find the acceleration of an object when the force is 850 N and the mass is 85 kg.
A. 0 m/s2
B. 7.3 x 104 m/s2
C. 0.1 m/s2
D.10 m/s2
Answers
A student holds a pipe vertically, with one end submerged in water while the opposite end is out in the air. Just above the pipe, the student holds a tuning fork. The student carefully moves the pipe up and down, varying the level of water inside of it, until they detect a strong resonant sound.
The student detects this sound when the length of air inside of the pipe measures 56.25 cm, and then again when the length is 68.75 cm. Taking the speed of sound in air to be of 340. m s–1, what is the frequency of the tuning fork?
Answers
With the use of formula, the frequency of the tuning fork is 13.6 Hz
RESONANCEA tuning fork can be used to determine the speed of sound in air using a resonance tube. The apparatus needed for this experiment are;
Tuning forkbeakerglass tubewaterThe experiment begins when a student holds a pipe vertically, with one end submerged in water while the opposite end is out in the air. Just above the pipe, the student holds a tuning fork. The student carefully moves the pipe up and down, varying the level of water inside of it, until they detect a strong resonant sound.
Given that the student detects this sound when the length of air inside of the pipe measures 56.25 cm, and then again when the length is 68.75 cm. Taking the speed of sound in air to be of 340. m s–1.
The parameters given are:
\(L_{1}\) = 56.25 cm
\(L_{2}\) = 68.75 cm
V = 340 m/s
The formula to use for this question is
V = 2F( \(L_{2}\) - \(L_{1}\) )
340 = 2F (68.75 - 56.25)
340 = 2 x 12.5 x F
340 = 25F
F = 340/25
F = 13.6 Hz
Therefore, the frequency of the tuning fork is 13.6 Hz
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You find a micrometer (a tool used to
measure objects to the nearest 0.001 mm) that has
been badly bent. How would it compare to a new,
high-quality meterstick in terms of its precision? Its
accuracy?
Answers
Explanation:
A micrometer is a measuring device or an instrument which is used to measure very minute measurements very accurately and precisely. It is mathematical tool used to provide accurate measurement for any mechanical components.
Now, if the micrometer that I have found is badly bent, it would provide faulty or wrong measurements both in terms of precision and accuracy when compared to a high quality meter stick.
he length of a moving spaceship is 30.0 m according to an astronaut on the spaceship. if the spaceship is contracted by 13.8 cm according to an earth observer, what is the speed of the spaceship? c
Answers
The speed of the spaceship is 0.099c.
What is speed?Speed is the fastest movement of something.
Given:
L = 30 m is the proper length of the ship
• Delta*L = 13.8cm = 0.13m is the change in length
Let us first determine our contracted length. We can do this by subtraction:
L = 30m - 0.13m
We get:
L = 29.87
Now to determine the speed of the ship, we use the length contraction equation:
L = L_{0} * √(1 - (v ^ 2)/(c ^ 2))
We isolate the square root term:
√(1 - (v ^ 2)/(c ^ 2)) = L/L_{0} To simplify calculations, let us first substitute our lengths:
√(1 - (v ^ 2)/(c ^ 2)) = (29.87/(30) =
= 0.995
After calculation
V/C = 0.099874
Or V= 0.099c
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The actual speed of the car at the top of the hill is 20.0m/s. What is the reason for this difference in velocity?
Answers
Answer:
Please find the answer in the explanation.
Explanation:
Given that the actual speed of the car at the top of the hill is 20.0m/s. What is the reason for this difference in velocity?
Speed is a scalar quantity that is, it has only magnitude but no direction.
While velocity is a vector quantity, that is, it has both magnitude and direction.
If the actual speed of a car is 20 m/s, that is the magnitude of the speed only without direction.
The velocity will therefore be of the same magnitude but with addition of direction. Either west, east or north south.
Water is heated by hot air in a double-pipe heat exchanger L = 10 m, with water flowing in the inner tube (Di = 3 cm), and air flowing in the tube annulus (Do = 5.5 cm). The flow rate of the water is 1.2 kg/s and that of the air is 0.5 kg/s. The water enters at 40°C while the air enters at 280°C. If the air-side convection coefficient hair = 1000 W/m2·K, determine the following:
(a) The outlet temperatures of both the air and the water if the heat exchanger is operating in a parallel-flow arrangement.
(b) The outlet temperatures of both the air and the water if the heat exchanger is operating in a counter-flow arrangement.
Assume fully-developed flow conditions. Evaluate the fluid properties at the inlet temperatures.
Answers
(a) In a parallel-flow arrangement, the outlet temperature of the water and the air can be determined using the energy balance equation. The heat transfer rate between the water and the air is equal to the product of the water mass flow rate, specific heat capacity of water, and the change in temperature of the water:
Similarly, the heat transfer rate between the air and the water is equal to the product of the air mass flow rate, specific heat capacity of air, and the change in temperature of the air:
Since the heat exchanger is operating under fully-developed flow conditions, the outlet temperature of the water and the air can be found by equating the heat transfer rates:
By substituting the given values, including the specific heat capacities of water and air, and solving the equations, the outlet temperatures of the air and water can be calculated.
(b) In a counter-flow arrangement, the outlet temperatures of the air and water can be determined using a similar energy balance equation. However, in this case, the change in temperature of the air is taken as the difference between the outlet and inlet temperatures of the air:
Again, by equating the heat transfer rates, substituting the given values, and solving the equations, the outlet temperatures of the air and water in a counter-flow arrangement can be calculated.
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The negative terminal on a flashlight cell is ?
Answers
two stars have the same luminosity (energy output per second), but star a is 6 times farther away from us than star b. how much fainter does star a appear compared to star b? x 10^
Answers
If two stars have the same brightness (energy production per second), but star an is six times further away from us than star b, star a will look nine times fainter than star b.
The quantity of light released by an object in a given length of time is known as luminosity in astronomy. The Sun has a brightness of 3.846 1026 watts (or 3.846 1033 ergs per second). An observer's distance from an object has no bearing on the value of luminosity, which is an absolute measurement of radiant power. Astronomers frequently speak about an object's luminosity in terms of solar luminosities, where one solar luminosity is the same as the brightness of the Sun. The brightest stars produce several million solar luminosities of light. With 1017 solar luminosities, supernovae are the most brilliant. A few millionths of the Sun's luminosity characterises the faint brown dwarfs.
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what is practical machine?
Answers
Explanation:
A practical machine is a simple machine that losses energy and have parts that have weights, friction and it causes some loss of work done.
the input value that makes the recursion stop is called the base case or ending case. true or false
Answers
The statement that the input value that makes the recursion stop is indeed called the base case or ending case is True.
In recursive algorithms or functions, the base case serves as the condition that determines when the recursion should terminate. It is the input value or condition for which a direct result can be determined without further recursive calls. Once the base case is reached, the recursion stops, preventing infinite recursion and allowing the algorithm to return the desired result.
The base case is crucial in recursive programming as it defines the boundary condition that signals the end of the recursive process.
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What’s the velocity for 3.5 seconds?
Answers
Answer:
After 3 seconds, the velocity is 4.5+3×1.5=9 m/s.
Explanation:
hope it helps
Answer:
Acceleration = delta velocity/delta time a = 70 m/s/35 seconds = 2 m/s2
Explanation:
see attached, thanks !!
Answers
Explanation:
3. A jet aircraft is moving at a constant speed of 500
kilometers per hour. How long does it take the jet to
travel 2,000kilometers?
Answers
Answer:2 hours
Explanation:
A convex mirror of radius of curvature 1.6 m has an object placed at a distance of 1.0 m from it. Find the position of image and the magnification.
Answers
Answer:
The image is formed at 0.44 m in front of the mirror
magnification (M) = 0.44
Explanation:
Applying, mirror formular
1/f = (1/u)+(1/v).................... Equation 1
Where f = Focal length of the convex mirror, u = object distance, v = image distance.
Using the real is positive convection,
From the question,
Given: f = -1.6/2 = -0.8 m( The focal length of a convex mirror is vitual), u = 1.0 m
Substitute these values into equation 1
-1/0.8 = (1/v)+(1/1)
Solve for v
1/v = 1.25+1
1/v = 2.25
v = 1/2.25
v = 0.44 m
Hence the image is formed at 0.44 m in front of the mirror
Magnification (M) = v/u
m = 0.44/1
m = 0.44
An axially loaded short column has length of 3.5m carries factored load of 1600KN. Concrete fc'=28MPA and Fy=420 MPA. Maximum aggregate size is 19mm. Calculate the suitable dimensions for tied and spiral columns.qr 1. Calculate • Required loads • Stresses • Gross area • Area of steel • Design satisfies risk assessment against use Appropriate reinforcement SELECTION • All relevant checks to make design safe
Answers
The suitable dimensions for tied and spiral columns of Required loads, Stresses, Gross area, Area of steel are 1142.86 kN, 12.6 MPa, 90.89 m².
The required loads can be determined by dividing the factored load by the appropriate load factor. For this example, let's assume a load factor of 1.4. Required loads = Factored load / Load factor
= 1600 kN / 1.4
= 1142.86 kN
Determine the allowable stresses: a concrete compressive strength of fc' = 28 MPa, the allowable compressive stress (fa) can be calculated using the formula:
= 0.45 * 28 MPa
= 12.6 MPa
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