Initially before the engine is ignited, the weather rocket sits at rest on the top of the spring, and the spring is compressed 0.214m
After the engine is ignited, the rocket speed (that generates a thrust of 200N) when the spring has stretched 40cm is 1.78m/s
Answer to question a.
Given from the question
mass of weather rocket = 12kg
Thrust by rocket Ft = 200N
Spring constant K = 550N/m
Let spring compressed = x meters
Now, let us using the force formula
F rocket = F spring
mass rocket (m) * g (earth gravity) = spring constant (K) * x
12 * 9.8 = 550 * x
117.6 = 550x
x = 0.214m (X₁)
Answer to question b
where y = x₁ + x₂ ; x₁ = 0.214m ; x₂ = 0.4m (stretched 40cm)
y = 0.614
200 * 0.614 + 1/2 * 550 * 0.214² = 1/2 * 550 * 0.4² + 12 * 9.8 * 0.614 + 1/2 * 12 * v²122.8 + 12.59 = 44 + 72.21 + 6 * v²6v² = 19.18v = 1.788m/s
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b. How many square meters does an 80. ft2 rug occupy? (1 ft = 12 in.)
b.
First squared the following conversion factor: 1 ft = 12 in, as follow:
\(\begin{gathered} 1ft=12in \\ (1ft)^2=(12in)^2 \\ 1ft=144in^2 \end{gathered}\)Then, use the previous result as a conversion factor to convert 80.0ft^2, as follow:
\(80.0ft^2\cdot\frac{144in^2}{1ft^2}=11520in^2\)Now, consider that 1 m = 39.3701 in, then, if you squared you obtain:
\(\begin{gathered} 1m=39.3701in \\ (1m)^2=(39.37in)^2 \\ 1m^2=1550.004774in^2 \end{gathered}\)use the previous result as a conversion factor:
\(11520in^2\cdot\frac{1m^2}{1550.004774in^2}\approx7.43m^2\)Hence, 80.0ft^2 is approximately 7.43 m^2
A steam engine takes in superheated steam at 270 °C and discharges condensed steam from its cylinder at 50 °C. The engine has an efficiency of 30%, and taken in 50 kJ from the hot steam per cycle. If a Carnot engine takes in the same amount of heat per cycle and operates at these temperatures, the work it can turn into is most likely to be:a) 15 kJ. b) 20 kJ. c) 10 kJ. d) 50 kJ.
Answer:
b) 20 kJ
Explanation:
Efficiency of carnot engine = (T₁ - T₂ ) / T₁ Where T₁ is temperature of hot source and T₂ is temperature of sink .
T₁ = 270 + 273 = 543K
T₂ = 50 + 273 = 323 K
Putting the given values of temperatures
efficiency = (543 - 323) / 543
= .405
heat input = 50 KJ
efficiency = output work / input heat energy
.405 = output work / 50
output work = 20.25 KJ.
= 20 KJ .
How does the comet's energy change as it moves from point B to point C?
A. KE increases, GPE increases
B. KE increases, GPE decreases
C. KE decreases, GPE increases
D. KE decreases, GPE decreases
Need it asap please help me thanks in advance just trying to pass my senior year :)
Option C. KE decreases, GPE increases
What is the GPE of the comet?The GPE of the comet is given by, U(r) = -GMm/r, where M is the mass of the sun, and m is the mass of the comet.
The total energy E of the comet remains constant.
We know, E = K + U ⇒ K = E - U. So, if U increases K decreases.
As the comet moves from B to C, the distance r between the comet and the sun increases.
When r increases U(r) increases according to the above equation, it becomes more positive. So, the GPE of the comet increases as it moves from B to C. KE, according to the energy relation, thus, decreasing during the same course of motion.
Therefore, as the comet moves from B to C, its KE decreases, and its GPE increases.
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Two forces, one four times as large as the other, pull in the same direction on a 10kg mass and impart to it an acceleration of 2.5 m/s2. If the smaller force is removed, what is the acceleration of the mass?
Answer:
The acceleration of the mass is 2 meters per square second.
Explanation:
By Newton's second law, we know that force (\(F\)), measured in newtons, is the product of mass (\(m\)), measured in kilograms, and net acceleration (\(a\)), measured in meters per square second. That is:
\(F = m\cdot a\) (1)
The initial force applied in the mass is:
\(F = (10\,kg)\cdot \left(2.5\,\frac{m}{s^{2}} \right)\)
\(F = 25\,N\)
In addition, we know that force is directly proportional to acceleration. If the smaller force is removed, then the initial force is reduced to \(\frac{4}{5}\) of the initial force. The acceleration of the mass is:
\(\frac{25\,N}{20\,N} = \frac{2.5\,\frac{m}{s^{2}} }{a}\)
\(a = 2\,\frac{m}{s^{2}}\)
The acceleration of the mass is 2 meters per square second.
Water flows at a speed of 13 m/s through a pipe that has a diameter of 1.2 m. What is the
diameter of the smaller end of the pipe that the water comes out with a speed of 30 m/s?
The diameter of the smaller end of the pipe is approximately 0.78 meters.
To determine the diameter of the smaller end of the pipe, we can use the principle of conservation of mass. According to this principle, the mass flow rate of water should remain constant throughout the pipe.
The mass flow rate is given by the equation:
Mass flow rate = density of water * cross-sectional area * velocity
Since the density of the water remains constant, we can write:
Cross-sectional area1 * velocity1 = Cross-sectional area2 * velocity2
Given that the velocity1 is 13 m/s, the diameter1 is 1.2 m, and the velocity2 is 30 m/s, we can solve for the diameter2 using the equation:
(pi * (diameter1/2)^2) * velocity1 = (pi * (diameter2/2)^2) * velocity2
Simplifying the equation:
(1.2/2)^2 * 13 = (diameter2/2)^2 * 30
Calculating the equation:
(0.6)^2 * 13 = (diameter2/2)^2 * 30
0.36 * 13 = (diameter2/2)^2 * 30
4.68 = (diameter2/2)^2 * 30
Dividing both sides by 30:
0.156 = (diameter2/2)^2
Taking the square root of both sides:
0.39 = diameter2/2
Multiplying both sides by 2:
0.78 = diameter2
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The diagram shows an electromagnet made with copper wire, a steel nail,
and a 1.5 V battery. Which action could cause this electromagnet to be
stronger?
A. Replace the steel nail with a plastic straw.
B. Replace the battery with a 6 V battery.
C. Reduce the number of coils of wire wrapped around the nail.
D. Reverse the direction of the battery in the circuit.
Correct answer is B!
Answer:B
Explanation: i took the test and i got it right
A teacher is examining laboratory supplies with a diverging lens. The lens has a focal length of magnitude 19.4 cm. The lens is always held between the teacher's eye and the object under study. However, the distance between the lens and the object is different for each object that the teacher observes.
Determine the image location and magnification for each of the following three objects. In addition, determine whether the image is real or virtual, whether it is upright or inverted, and whether it makes the object appear larger or smaller than actual size.
A) The object lies 38.8 cm behind the lens. Determine the image location. (Enter the magnitude in cm.)
|q| =
Determine the magnification.
M =
Select all of the following that apply to the image formed in part (a).
- real
- virtual
- upright
- inverted
- enlarged
- shrunken
B) A) The object lies 19.4 cm behind the lens. Determine the image location. (Enter the magnitude in cm.)
|q| =
Determine the magnification.
M =
Select all of the following that apply to the image formed in part (b).
- real
- virtual
- upright
- inverted
- enlarged
- shrunken
C) A) The object lies 9.70 cm behind the lens. Determine the image location. (Enter the magnitude in cm.)
|q| =
Determine the magnification.
M =
Select all of the following that apply to the image formed in part (c).
- real
- virtual
- upright
- inverted
- enlarged
- shrunken
The answers are (a) |q| = 58.2 cm, M = -1.50, virtual, upright, shrunk; (b) |q| =, M = -, actual, substantially magnified; and (c) |q| = 6.5 cm, M = -1.68, virtual, upright, enlarged.
We can use the magnification formula and the thin lens equation to solve:
Where f is the lens's focal length, d_i is the image distance, and d_o is the object distance, the equation is: 1/f = 1/d_i + 1/d_o.
The formula for magnification is M = -d_i/d_o, where M stands for magnification.
For part (a), the object distance is d_o = -38.8 cm and the focal length is f = -19.4 cm.
1/-19.4 = 1/d_i + 1/-38.8
|d_i| = 58.2 cm
The image is virtual and smaller than the object (since the magnification is less than 1)
For part (b), the object distance is d_o = -19.4 cm, and the focal length is f = -19.4 cm.
1/-19.4 = 1/d_i + 1/-19.4
|d_i| = ∞
The image is at infinity, which means it is a real image and highly magnified (since the object distance is close to the focal length).
For part (c), the object distance is d_o = -9.70 cm, and the focal length is f = -19.4 cm.
1/-19.4 = 1/d_i + 1/-9.70
|d_i| = 6.5 cm
The image is virtual and larger than the object (since the magnification is greater than 1).
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A 1050 W carbon-dioxide laser emits light with a wavelength of 10μm into a 3.0-mm-diameter laser beam. What force does the laser beam exert on a completely absorbing target?
The force exerted by the laser beam on a completely absorbing target is \(3.5 \times 10^{-6} \ N\).
The given parameters;
power of the laser light, P = 1050 Wwavelength of the emitted light, λ = 10 μmThe speed of the emitted laser light is given as;
v = 3 x 10⁸ m/s
The force exerted by the laser beam on a completely absorbing target is calculated as follows;
P = Fv
\(F = \frac{P}{v} \\\\F = \frac{1050}{3\times 10^8} \\\\F = 3.5 \times 10^{-6} \ N\)
Thus, the force exerted by the laser beam on a completely absorbing target is \(3.5 \times 10^{-6} \ N\).
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The point that represents maximum potential energy is W.
The point that represents potential energy at 0 joules is Z.
The point that represents potential energy at 50 percent is Y.
The point that represents maximum kinetic energy is X.
Potential energy is the energy held through an object because of its function relative to other items, stresses inside itself, its electric-powered fee, or different elements. potential energy is energy this is saved – or conserved - in an object or substance. This saved energy is based totally on the position, arrangement, or state of the object or substance.
Potential energy refers to the stored energy within an object that exists because of the item's role, country, or arrangement. Potential energy is the strength this is stored in an item because of its function relative to some 0 roles. An item possesses gravitational capability strength if it is located at a top above (or beneath) the zero top.
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and it is corrupted by additive white gaussian noise, n(t) that has power spectral density (psd) of n0/2 w/hz. the frequency response of the ideal low pass filter (lpf) is given as
The performance of a digital communication system is quantified by the probability of bit detection problems in the presence of thermal noise.
In the context of wireless communications, the major source of thermal noise is the addition of random signals arising from the vibration of atoms in the receiver electronics.
Gaussian: The probability distribution of the noise samples is Gaussian with a zero mean, i.e., in the time domain, the samples can acquire both negative and positive values in addition.
the values near zero have a higher chance of occurrence while the values far away from zero are less likely to appear.
As a result, the time domain average of a greater number of noise samples is equal to zero.
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you have been asked to design an experiment to show whether spaghetti cooks faster with or without salt in the cooking water. which of the following is the variable being tested?
The quantity of water used, the type of spaghetti used, and the intervals at which the spaghetti is checked to see if it is finished.
Water becomes harder due to the presence of calcium, magnesium, and iron(II) ions, which prevents soap solution from creating a lather. Students examine the impact of several dissolved salts, which comprise a variety of cations and anions, on the production of lather in this experiment. After that, they try to determine which ions are impeding lathering.
The students can work in pairs or bigger groups to complete this as a class project.
The first step for the students is to label eight test tubes. Alternatively, they can individually conduct an investigation using three or four more test tubes and distilled water, as long as they include at least one sodium or potassium salt and one calcium or magnesium salt.
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Block X of mass M travels with a speed vo. Block Y of mass 2M travels with a speed 2vo. Both blocks travel toward each other and collide. After the blocks collide, they separate so that the kinetic energy of the system remains conserved. Which of the following equations for the conservation of momentum could a student use to help determine the speed vf of each block after the collision? A movo – 4movo = movxf + 2movyf, because the two blocks initially travel in opposite directions, and the blocks do not stick after the collision. movo + 4movo = movxf + 2movyf, because the two blocks initially travel toward each other, and the blocks do not stick after the collision. с movo – 4movo 3movsystem f, because the two blocks initially travel in opposite directions, and the velocity of the center of mass should first be determined. D movo + 4movo 3movsystem f, because the two blocks initially travel toward each other, and the velocity of the center of mass should first be determined.
m0v0 − 4m0v0 = m0vXf + 2m0vYfm0v0 − 4m0v0 = m0vXf + 2m0vYf, due to the fact that the two blocks initially move in the opposing directions and that they do not keep together after colliding.
What happens to an object's speed after a collision?The change in velocity between the objects following a collision is known as the relative velocity. When particles collide, momentum and energy are transferred, which results in a change in velocity. It abides under the rule of conservation of energy and momentum.
Is velocity unchanged following a collision?The velocity of the center of mass prior to and following the collision can be simply verified to be the same (as it should be obviously since there are no external forces acting on the system).
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\(m_0v_0 − 4m_0v_0 = m_0vXf + 2m_0vYfm_0v_0 - 4m_0v_0 = m_0vXf + 2m_0vYf\), due to the fact that the two blocks initially move in the opposing directions and that they do not keep together after colliding.
What happens to an object's speed after a collision?The change in velocity between the objects following a collision is known as the relative velocity. When particles collide, momentum and energy are transferred, which results in a change in velocity. It abides under the rule of conservation of energy and momentum.
Is velocity unchanged following a collision?The velocity of the center of mass prior to and following the collision can be simply verified to be the same (as it should be obviously since there are no external forces acting on the system).
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Eve's
contractor recommended she not install baseboard heating. In which scenario would it be disadvantageous to install a baseboard heating system?
A. Where there is high room air circulation
B. Where there are low ceiling heights
C. Where electricity is generated from a gas-fired plant
D. Where the TD is zero
Mark for review (Will be highlighted on the review page)
Installing an underfloor heating system in a situation where the electricity is generated by a gas-fired plant would not be advantageous.
What is electricity exactly?Charge or electrical supply flow is what is referred to as electricity. It is an alternative fuel source, which means we obtain it by transforming other natural resources into energy supplies, such as carbon, dirty energy, hydrocarbons, and nuclear energy.
How does electricity get made?To create electricity, a turbine set converts mechanical energy into electrical energy. The heat produced by sources of energy such natural gas, carbon, nuclear reactors, biomass, petroleum, volcanic, and solar heat is employed to transform to steam, which powers the rotors of turbines.
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A motorcycle stoop is at a traffic light, when the light turns green, the motorcycle accelerates to a speed of 78 km/h over a distance of 50 m. What is the average acceleration of the motorcycle over this distance?
The average acceleration of the motorcycle over the given distance is approximately 9.39 m/s².
To calculate the average acceleration of the motorcycle, we can use the formula:
Average acceleration = (final velocity - initial velocity) / time
First, let's convert the final velocity from km/h to m/s since the distance is given in meters. We know that 1 km/h is equal to 0.2778 m/s.
Converting the final velocity:
Final velocity = 78 km/h * 0.2778 m/s = 21.67 m/s
Since the motorcycle starts from rest (initial velocity is zero), the formula becomes:
Average acceleration = (21.67 m/s - 0 m/s) / time
To find the time taken to reach this velocity, we need to use the formula for average speed:
Average speed = total distance/time
Rearranging the formula:
time = total distance / average speed
Plugging in the values:
time = 50 m / 21.67 m/s ≈ 2.31 seconds
Now we can calculate the average acceleration:
Average acceleration = (21.67 m/s - 0 m/s) / 2.31 s ≈ 9.39 m/s²
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Find the vector whose magnitude is 36 and inclination is 60°.
The vector whose magnitude is 36 and inclination is 60° is v = <18, 18√(3)>.
The inclination of a vector is the angle between the vector and a reference line. In this case, the reference line is the horizontal axis. Let the components be x and y. We know that the magnitude of the vector is 36, so,
magnitude = √(x² + y²) = 36
Squaring both sides of this equation, we get,
x² + y² = 1296
We also know that the inclination is 60°. The tangent of 60° is √(3), which is equal to the ratio of the vertical component to the horizontal component of the vector,
tan(60°) = y/x
y/x= √(3)
Multiplying both sides by x, we get,
y = √(3)x
Now we can substitute y in terms of x in the equation x² + y² = 1296,
x² + (√(3)x)² = 1296
Simplifying this equation, we get,
4x² = 1296
x² = 324
Taking the square root of both sides, we get,
x = +/- 18
Since the vector is making an angle of 60° with the horizontal, it must be in the first or fourth quadrant, where x is positive. Therefore, we take x = 18. Using y = √(3)x, we get,
y = sqrt(3)18
y = 18√(3)
So the vector is,
v = <18, 18√(3)>
Therefore, the vector whose magnitude is 36 and inclination is 60° is v = <18, 18√(3)>.
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Given that the luminosity of a star is given as a function of its radius and temperature by the equation. I do not understand this last question in terms of what to put into the given equation.
The luminosity of this star in units of the solar luminosity would be: 483.7L.
How to calculate the luminosityTo calculate the luminosity, we would use the different values given and the formula for luminosity.
Temperature = 9305K
Star's radius = \(5.90 * 10^{9} m\\\)
Luminoisty of the star
Luminosity of the sun
= \(\frac{4π * (5.90 * 10^9)^2 * 5.67 * 10^-8 * 9305^4 W}{3.846 * 10^26 W}\)
= 483.7L
This is the unit for luminosity.
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Explain/Describe how atoms in domains determine whether a material is magnetic or not. (Please help this is due today)
Answer:
In a material, the magnetic behavior depends on the alignment of magnetic moments of the atoms. Magnetic moments are generated by the motion of the electrons in the atoms. When the magnetic moments of atoms in a material are aligned in a specific pattern, it creates a magnetic field which results in the material being magnetic.
In many materials, the magnetic behavior arises due to the alignment of magnetic domains, which are regions of atoms with magnetic moments aligned in the same direction. When many domains with aligned magnetic moments are present in a material, the material becomes magnetic.
The magnetic behavior of a material depends on the number of electrons and the arrangement of those electrons in the atoms. In particular, for an atom to have a magnetic moment, it must have unpaired electrons, meaning electrons that are not paired with another electron with the opposite spin. When these unpaired electrons in the atoms are aligned, they generate a magnetic moment. If all electrons are paired, there will not be a net magnetic moment, so the material will not be magnetic.
So, in summary, the magnetic behavior of a material is determined by the alignment of magnetic moments of atoms. When the magnetic moments of many atoms in a material align in the same direction, it creates a magnetic field, leading to a material being magnetic. This alignment is usually present in magnetic domains consisting of atoms with unpaired electrons.
24. A body A rests on a smooth horizontal table. Two bodies of mass 2 kg and 10 kg hanging freely, are attached to A by strings which pass over smooth pulleys at the edges of the table. The two strings are taut. When the system is released from rest, it accelerates at 2 m/s2 . Find the mass of A.
The two strings are taut. When the system is released from rest, it accelerates at 2 m/s2 then, Mass of A = 8m/5 kg.
Let the mass of the body A be ‘m’.
The two strings are taut so they exert a tension ‘T’ on body A.
Let ‘a’ be the acceleration produced in the system.
The free body diagram of body A is given below: mA + 2T = mA + ma = mA + m(2)mA + 10T = mA + ma = mA + m(2)
As the two strings are taut, we can say that tension in both strings is equal.
Therefore 2T = 10T or T = 5T As the body A is resting on a smooth horizontal table, there is no friction force acting on the body A.
The net force acting on body A is the force due to tension in the strings. ma = 2T – mg …(1)
As per the given problem, the system is released from rest.
Hence the initial velocity is zero.
Also, we are given that the system accelerates at 2 m/s2.
Therefore a = 2 m/s2 …(2)
From the equations (1) and (2), we get, m(2) = 2T – mg …(3)⇒ m(2) = 2×5m – mg⇒ 2m = 10m – g⇒ g = 8m/5
Thus, the mass of A is 8m/5 kg.
Answer: Mass of A = 8m/5 kg.
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[21] Design a questionnaire to conduct interviews with more than six community members in your area about their right to safe and healthy liven name and the signature of the interviewee must also appear on the living. questionnaire. Green (3 the s hmitted with your Project.
The Title of the interviews Questionnaire is : Community Members' Right to Safe and Healthy Living Questionnaire. The Questionnaire is attached.
What is the questionnaireA tool for research known as a questionnaire comprises a series of questions formulated to extract data from individuals or a collective of individuals. A systematic approach in acquiring data, which permits researchers to obtain uniform feedback and perspectives from respondents, is termed as structured data collection.
Questionnaires have multiple applications such as conducting surveys, holding interviews, performing assessments, and carrying out evaluations.
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Which statements explain the special theory of relativity? Check all that apply.
- Time and space are relative.
- The speed of light in a vacuum is constant for all observers.
- Physical laws change based on an observer's motion.
- Physical laws remain constant regardless of an observer's motion.
- The special theory of relativity applies to objects with constant velocity.
- The special theory of relativity applies to accelerating objects.
Answer:
A. Time and space are relative.
B. The speed of light in a vacuum is constant for all observers.
D. Physical laws change based on an observer's motion.
E. Physical laws remain constant regardless of an observer's motion.
Explanation:
The statements that explain the special theory of relativity are a),b) and e) respectively.
The special theory of relativity, developed by Albert Einstein, is based on the idea that the laws of physics are the same for all observers who are moving uniformly relative to each other. This means that there is no "absolute" or "preferred" frame of reference in the universe. Instead, all frames of reference are equally valid, and any observer can use their own frame of reference to describe physical phenomena.
One consequence of this idea is that time and space are relative. This means that the measurements of time and distance depend on the observer's frame of reference. For example, if two observers are moving relative to each other, they will measure different lengths and times for the same event. This effect is known as time dilation and length contraction.
Finally, the special theory of relativity applies only to objects with constant velocity. It does not apply to accelerating objects, which require the more general theory of relativity. The special theory of relativity is a fundamental theory in modern physics, and it has important implications for our understanding of space, time, and the nature of reality.
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The correct question is :
Which statements explain the special theory of relativity? Check all that apply.
a) Time and space are relative.
b) The speed of light in a vacuum is constant for all observers.
c) Physical laws change based on an observer's motion.
d) Physical laws remain constant regardless of an observer's motion.
e) The special theory of relativity applies to objects with constant velocity.
f) The special theory of relativity applies to accelerating objects.
Two blocks, 1 and 2, are connected by a massless string that passes over a massless pulley. 1 has a mass of 2.25 kg and is on an incline of angle 1=42.5∘ that has a coefficient of kinetic friction 1=0.205. 2 has a mass of 5.55 kg and is on an incline of angle 2=33.5∘ that has a coefficient of kinetic friction 2=0.105
. The figure illustrates the configuration.
A system of two blocks connected by a rope passing over a pulley. The system sits atop a scalene triangle whose long edge forms the base. The pulley is attached to the apex of the triangle. Box M subscript 1 rests on the triangle edge to the left of the pulley, which makes an angle of theta subscript 1 with the base of the triangle. The coefficient of friction between box M sub 1 and the surface is mu subscript 1. Box M subscript 2 rests on the triangle edge to the right of the pulley, which makes an angle of theta subscript 2 with the base of the triangle. The coefficient of friction between box M sub 2 and the surface is mu subscript 2.
The force acting on the system of two blocks connected by a rope passing over a pulley is -13.26 N.
The system of two blocks connected by a rope passing over a pulley are M1 and M2, where M1 rests on the triangle edge to the left of the pulley, which makes an angle of theta subscript 1 with the base of the triangle. The coefficient of friction between box M1 and the surface is mu subscript 1. M2 rests on the triangle edge to the right of the pulley, which makes an angle of theta subscript 2 with the base of the triangle.
The coefficient of friction between box M2 and the surface is mu subscript 2. The system sits atop a scalene triangle whose long edge forms the base. The pulley is attached to the apex of the triangle.M1 has a mass of 2.25 kg and is on an incline of angle 1=42.5∘ that has a coefficient of kinetic friction 1=0.205. M2 has a mass of 5.55 kg and is on an incline of angle 2=33.5∘ that has a coefficient of kinetic friction 2=0.105.The free-body diagram of M1 shows that the weight of M1 acts straight downwards (vertically) and the normal force acts perpendicular to the slope.
The force of friction opposes the motion and acts opposite to the direction of motion.M1 = 2.25 kgTheta subscript 1 = 42.5 degreesMu subscript 1 = 0.205g = 9.81 m/s²In the free-body diagram of M2, the normal force acts perpendicular to the incline of the slope, the weight of the object acts vertically downwards and parallel to the incline, and the force of friction opposes the motion and acts opposite to the direction of motion.M2 = 5.55 kgTheta subscript 2 = 33.5 degreesMu subscript 2 = 0.105g = 9.81 m/s²The tension in the string is the same throughout the rope. Since the masses are being pulled by the same rope, the acceleration of the objects is the same as the acceleration of the rope.
The tension in the string is directly proportional to the acceleration of the objects and the rope.A system of two blocks connected by a rope passing over a pulley has a total mass of M. The acceleration of the system is given by the formula below:a = [(m1-m2)gsin(θ1) - μ1(m1+m2)gcos(θ1)] / (m1 + m2)Where, μ1 = 0.205 is the coefficient of friction of block M1θ1 = 42.5 degrees is the angle of the incline of block M1M1 = 2.25 kg is the mass of block M1M2 = 5.55 kg is the mass of block M2g = 9.81 m/s² is the acceleration due to gravitysinθ1 = sin 42.5 = 0.67cosθ1 = cos 42.5 = 0.75The acceleration of the system is:a = [(2.25-5.55)(9.81)(0.67) - (0.205)(2.25+5.55)(9.81)(0.75)] / (2.25 + 5.55)a = -1.7 m/s² (the negative sign indicates that the system is accelerating in the opposite direction).
The force acting on the system is given by:F = MaWhere M is the total mass of the system and a is the acceleration of the system. The total mass of the system is:M = m1 + m2M = 2.25 + 5.55M = 7.8 kgThe force acting on the system is:F = 7.8(-1.7)F = -13.26 N (the negative sign indicates that the force is acting in the opposite direction).
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If the car was initially traveling at 96 km/h and came to a stop in 5.0 s along a straight, level road, what was the magnitude of the average force applied to the passenger by the seatbelt? The shoulder strap seatbelt holds a 56kg passenger in place.
The average force exerted by seatbelts on the passenger is 1493.3N.
initial velocity of the car, u = 96km/h
time taken by the car, s = 5.0 sec
final velocity of the after coming to rest, v = 0
mass of the passenger, m = 56 kg
to find out the acceleration of the car we use equation of motion
v = u+ at
0 = 96km/h + ax 5s
a = - 96 x 18/5x5
a = -26.6m/s²
The deceleration of the car is 26.6 m/s²
The force exerted on the passenger by the backward action of the car is calculated as
F = ma
where
m is mass
a is acceleration
F = 56 x 26.6
F = 1493.3 N
Therefore, the average force exerted by seatbelts on the passenger is 1493.3N.
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A 1,364 kg car is driving down the highway at a constant velocity of 23 m/s. What is the net force acting on the car?
A car of mass 1364 kg which is moving at a constant velocity of 23 m/s then the net force acting on the car is 31,372 N.
What is Force?In physics, a strain is an effect with the ability to alter the velocity of an object. A force can influence a surplus object's velocity to alter or rise. To describe force, a pushing or a pulling makes intuitive sense. Forces have both size and direction, since they are vector quantities. It is measured in newtons using the SI system (N). F is the symbol that denotes force.
Given data provided by the question,
Mass, m = 1364 kg and,
Velocity, v = 23 m/s
Force, F = 1364 × 23
F = 31,372 N.
Therefore, the force is 31,372 N.
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A uniform magnetic field of 7.35 T points in some direction. Consider the magnetic flux through a large triangular wire loop that has three equal sides of 1.95 m. Determine the maximum of the absolute value of the magnetic flux.
Answer:
The maximum of the absolute value of the magnetic flux is \(\phi_{max} = 12.10 1 \ Weber\)
Explanation:
From the question we are told that
The magnetic field is \(B = 7.35 \ T\)
One side of the triangle is \(d = 1.95 \ m\)
Generally the absolute value of the magnetic flux is mathematically represented as
\(\phi = B * A cos (\theta _1 )\)
At maximum \(\theta_1 = 0\)
So
The maximum of the absolute value of the magnetic flux.
\(\phi_{max} = B * A\)
Now we are told that the triangle is of equal sides so the angle each makes with the other is \(\theta = 60 ^o\) this is because total angle in a triangle is 180
Now the height of the triangular loop is mathematically evaluated using SOHCAHTOA as
\(sin \theta =\frac{h}{d}\)
=> \(sin( 60)=\frac{h}{1.95}\)
=> \(h = sin (60) * 1.95\)
=> \(h = 1.6887 \ m\)
Hence the area is evaluated as
\(A = \frac{1}{2} * d * h\)
substituting values
\(A = 0.5 * 1.95 * 1.6887\)
\(A = 1.6465 \ m^2\)
Thus
\(\phi_{max} = 7.35 * 1.6465\)
\(\phi_{max} = 12.10 1 \ Weber\)
Please help me out! I will pay real money to whoever solves this
Answer:
I KNOW THE ANSWER IT WILL COST 30$
Explanation:
are ice crystals forming on a window a change of state
Answer:
True
Explanation:
Ice crystals forming on a window is a change of state because matter is being changed from one state to another. Since water turns to ice crystals, the water is being changed into a solid state.
The disk that BTK sent to the television station contained just one valid file. What was the name of the file?
Answer:
The name of the file is Floppy.
Explanation:
Given that,
The disk that BTK sent to the television station contained just one valid file.
We need to find the name of the file
According to given data,
The disk that BTK sent to the television station contained just one valid file.
This file is called floppy.
Floppy :
The floppy disk is storage disk. It is made of thin and flexible disk of magnetic storage, It shape of square.
Floppy disk are read and written to by floppy drive.
Hence, The name of the file is Floppy.
Who is your greatest scientist, and what was his or her achievement? « brainliest assured»
Answer:
My greatest scientist is David Baltimore.
Explanation:
David Baltimore is an American biologist, university administrator, and 1975 Nobel laureate in Physiology or Medicine. He is currently President Emeritus and Distinguished Professor of Biology at the California Institute of Technology, where he served as president from 1997 to 2006.
Hope I helped! Ask me anything if you have any questions. Brainiest plz!♥ Hope you make a 100%. Have a nice morning! -Amelia♥
HELP!!! 20 POINTS!! TRUE OR FALSE??
The acceleration of objects in free-fall will remain constant in a vacuum regardless of their mass and size.
Answer:
It might be true
Explanation:
Answer:
its FALSE i think
Explanation:
Samuel placed a plastic container upside down over a paperclip. He held a strong magnet up to the side of the bowl and the paperclip moved toward the magnet. Which best explains the result of Samuel's investigation. A. The magnet caused a balanced force on the paperclip. B. The magnet caused a non-contact force on the paperclip. C. The magnet increased the amount of energy in the paperclip. D. The magnet reduced the net force acting on the paperclip.
Answer:
The magnet caused a non-contact force on the paperclip.