Given:
The resistance of the bulb is,
\(R=15.0\text{ }\Omega\)The voltage of the battery is
\(V=12\text{ V}\)To find:
The current through the bulb
Explanation:
The current through the bulb is,
\(\begin{gathered} i=\frac{V}{R} \\ =\frac{12}{15.0} \\ =0.80\text{ A} \end{gathered}\)Hence, the current through the bulb is 0.80 A.
The electric potential inside a living cell is lower than the potential outside. Suppose the electric potential difference between the inner and the outer cell wall is 0.095 V, a typical value. To maintain the internal electrical balance, the cell pumps out sodium ions. How much work must be done to remove a single sodium ion (charge e)
Answer:
1.52 × 10⁻²⁰ J
Explanation:
The electrical potential difference is defined as the amount of work done in carrying a unit charge from one point to another point in an electric field. Electric potential difference is measured in volts. It is given by the formula:
ΔV = ΔU / q
ΔV is electric potential difference between the two points, ΔU is the work done and q is the unit charge.
Given that ΔV = 0.095 V, q = 1.6 × 10⁻¹⁹ C. Hence:
ΔU = ΔV.q
ΔU = 0.095 V * 1.6 × 10⁻¹⁹ C
ΔU = 1.52 × 10⁻²⁰ J
The electric potential difference is the amount of effort done in an electrical field to shift a unit charge from one spot to another.The electric potential difference will be 1.52×10⁻²⁰J.
What is the electric potential difference ?
The electrical potential difference is the amount of effort done in an electrical field to shift a unit charge from one spot to another.
Traditional current flows from positive to negative terminals, signifying positive charge transfer in that direction.
The given data in the problem is
\(\triangle V\) is the electric potential difference between the inner and the outer cell wall = 0.095 V
\(\triangle U\) is the amount of work done
q is the charge on the electron =1.6×10⁻¹⁹C
Electric potential difference is given by the formula
\(\triangle V=\frac{\triangle U}{q} \\\\ \triangle U=\triangle Vq\\\\\triangle U=0.095 V\times1.6\times10^{-19}\\\\ \triangle U=1.52\times10^{-20}J\)
Hence the electric potential difference will be 1.52×10⁻²⁰J.
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Questions:
1. Clara drives 250 km West to play a gig in Colombia City. After the gig he drives 450 km
east to jam with some musicians in Columbia. What distance did he cover? What was his
displacement?
Answer:
700km
Explanation:
going was 250km and leaving was 450
250+450=700
Calculating Displacement under Constant Acceleration
Use the information from the graph to answer the
question.
Velocity (m/s)
40
30
20
10
0
Velocity vs. Time
0 5
10
15
Time (s)
20
25
What is the total displacement of the object?
I
m
Answer:
1 km
Explanation:
displacement =velocity ×time
displacement =40m/s ×25s
displacement =1000m equivalent to 1km
A hungry rabbit sprints... what is the average velocity of the rabbit between the times t = 2 s and t = 12 s
Answer: -0.10m/s
Explanation:
khan academy
Holding force constant, what will be the effect of increasing the Moment arm?
(a) Depends on the direction of the force.
(b) Torque will increase.
(c) Torque is constant.
(d) Torque will decrease.
(e) The direction of rotation will change.
Answer:
(b) Torque will increase.
Explanation:
Torque is given as the product of force and moment arm (radius).
τ = F x r
F = τ / r
where;
F is force
τ is torque
r is radius (moment arm)
Keeping force constant, we will have the following;
τ ∝ r
This shows that torque is directly proportional moment arm (radius), thus increase in moment arm, will cause increase in torque.
For instance;
let the constant force = 5 N
let the initial moment arm, r = 2m
Torque, τ = 5 N x 2m = 10 Nm
When the moment arm is increased to 4 m
Torque, τ = 5 N x 4m = 20 Nm
Therefore, at a constant force, increasing in the Moment arm, will cause increase in torque.
Coorect option is "(b) Torque will increase."
A pipe of constant radius carried water at 3.25 m/s. Please answer in PA.
Pipe of constant radius, we can use Bernoulli's equation, which relates the pressure, velocity, and height of a fluid at two points in a flow system.the pressure of water in the pipe is approximately 105,142 Pa.
What is a system?System refers to a collection of related components or parts that work together to achieve a specific goal or purpose. The concept of a system can be applied to a wide range of fields and disciplines, including science, engineering, economics, and social sciences.
In science, a system is often defined as a portion of the universe that is being studied or analyzed. This can include anything from a single atom or molecule to an entire ecosystem or planet. By defining the boundaries of a system, scientists can focus their attention on understanding the interactions and relationships between the various components within that system.
In engineering, a system refers to a collection of components that are designed to work together to perform a specific function or task. This can include everything from simple mechanical systems like gears and pulleys to complex electrical or computer systems.
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Mention two ways in which the effects of friction can be minimised
Answer:
Polishing the rough surface.
Oiling or lubricating with graphite or grease the moving parts of a machine.
Providing all bearings or wheels between the moving parts of a machine or vehicles reduce friction and allow smooth movement as rolling friction is less than sliding friction.
Explanation:
Please help
A 90 kg football player is running at 0.9 m/s. Assuming a head on collision, at what speed would a 110 kg football player have to run into the 90 kg
player in order to stop him
Answer:
The two moments must be the same:
p1=p2
m1v1=m2v2
v2=(m1v1)/m2
v2=(90 kg x 0.9 m/s)/110kg=0.7 m/s
What happens to the salt crystals in the bottom of the tank
B. More of the salt dissolves because the additional water can hold more salt ions
On a roller coaster, your energy is conserved, so when you start at the top of a curve and head downward on the slope,what increases?
Since the energy is conserved, we can write the following equations:
\(\begin{gathered} E_m=E_k+E_p \\ E_k=\frac{mv^2}{2} \\ E_p=mgh \end{gathered}\)Where Em is the mechanical energy, Ek is the kinetic energy and Ep is the potential energy.
The kinetic energy is related to the velocity, and the potential energy is related to the height.
When the roller coaster goes down, the potential energy is converted into kinetic energy.
That means the height decreases (and so do the potential energy), but the velocity increases (and so do the kinetic energy).
Therefore the correct option is the sixth one (Both B and D).
Determine the maximum static friction when the normal force is 890 N and the coefficient of static friction is 0.55.
Answer:
489.5 N
Explanation:
The maximum static friction can be calculated as
\(F_f=\mu_sF_N\)Where μ is the static friction and Fn is the normal force.
So, replacing the values, we get:
\(F_f=0.55(890N)=489.5N\)Therefore, the maximum static friction is 489.5 N
No no no no. no no no no
Please solve this.. I can't find R_th and V_oc at 6kohm....
The current I through the 4 kΩ resistor in the original circuit is 0.199 mA.
Thévenin's theorem states that any linear network of voltage and current sources and resistors can be replaced by an equivalent circuit consisting of a single voltage source and a single resistor. The equivalent circuit provides the same output voltage and current as the original circuit for any external load connected to it.
To find the current I in the circuit using Thévenin's theorem, we need to follow these steps:
Step 1: Find the Thévenin equivalent voltage (Vth) across the 4 kΩ resistor.
To find Vth, we need to first find the open circuit voltage (Voc) across the 4 kΩ resistor. We can do this by removing the 4 kΩ resistor and finding the voltage between its two terminals using a voltage divider:
Voc = 6 kΩ/(2 kΩ + 6 kΩ) x 2 mA = 1.2 V
Next, we need to find the Thévenin equivalent resistance (Rth) across the 4 kΩ resistor. To do this, we need to short-circuit all the independent voltage sources (in this case, there is only one) and find the equivalent resistance seen from the terminals of the 4 kΩ resistor. With the 2 mA current source shorted out, the 2 kΩ and 4 kΩ resistors are in parallel:
Rth = 2 kΩ || 4 kΩ = 1.33 kΩ
Step 2: Replace the original circuit with the Thévenin equivalent circuit.
We can now replace the original circuit with the Thévenin equivalent circuit, which consists of a voltage source Vth = 1.2 V in series with a resistor Rth = 1.33 kΩ.
Step 3: Find the current I through the 4 kΩ resistor in the Thévenin equivalent circuit.
To find the current I, we can use Ohm's law:
I = Vth/(Rth + 4 kΩ) = 1.2 V/(1.33 kΩ + 4 kΩ) = 0.199 mA
Therefore, the current I through the 4 kΩ resistor in the original circuit is 0.199 mA.
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As positively charged sodium ions enter the axon, _______ flow(s) out to repolarize part of the axon
a. potassium ions
b. a neural impulse
c. the action potential
d. glial cells
As positively charged sodium ions enter the axon, potassium ions flow out to repolarize part of the axon.
At the beginning of an action potential of cell membrane, the sodium ion gates open and sodium ions flows into the cell. This process is called depolarization. Due to rapid influx of sodium ion, the channel is eventually closed.
The potassium channels are then activated in a process called repolarization. This process occurs when the potassium channels open and allow potassium ions to flow out of the cell.
To maintain the cell membrane potential, cells are kept at low concentration of sodium ions and high concentration of potassium ions.
Thus, as positively charged sodium ions enter the axon, potassium ions flow out to repolarize part of the axon.
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Two identical metallic spheres A and
B, each carrying a charge of q C, are fixed.
They repel each other with a force of
2x10-5 N. Another identical uncharged
sphere C is made to touch A, moved to
touch B, and placed halfway between A
and B. What is then the electric charge
and the electric force (in N) on each
sphere in terms of q?
The electric charge and the electric force on each sphere in terms of q is 2
The Electric Charge and Electric ForceThe ability of particles or objects to attract or repel one another without coming into contact is known as electric charge. Incompatiblely charged particles are drawn to one another. Like-charged particles repel one another. Electric force is the name given to the force of attraction or repulsion.
Two metallic spheres, a and b, with a charge of half and a force of two tens of five
F1=k(1/2)(1/2)/r2
Equation F1=k/4r
A and C are two metallic spheres, respectively, so
Equation F2=k/2rsquare
equ1/equ2
2×10^-5/F2=k/4r^2×2r^2/k
F2=4×10^-5
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Two test charges are located in the x–y plane. If q1=−2.600 nC and is located at x1=0.00 m, y1=1.0400 m, and the second test charge has magnitude of q2=3.600 nC and is located at x2=1.400 m, y2=0.400 m, calculate the Ex and Ey components, of the electric field ⃗ in component form at the origin, (0,0). The Coulomb force constant is 1/(40)=8.99×109 N·m2/ C2.
Answer:
Eₓ = -4,187 N / C, E_y = 6,937 N / C
Explanation:
To solve this exercise we will calculate the electric field at the desired point (0, 0) and then add it vectorially
E = \(k \frac{q}{r^2}\)
charge 1
the value of q₁ = - 2,600 nC = -2,600 10⁻⁹ C
r₁ = \(\sqrt{ (x_1-x_o)^2 + (y_1-y_o)^2}\)
r₁ = \(\sqrt{0 +(1.04-0)^2}\)RA 0 + (1.04 - 0) 2
r₁ = 1.04 m
we substitute
E₁ = k q1 / r12
E₁ = 9 10⁹ 2.6 10⁻⁹ / 1.04²
E₁ = 21.635 N / C
This electric field is directed towards the negative charge and is in the direction of the y axis.
E₁ = 21.635 j ^ N / C
charge 2
the value of q₂ = 3,600 nC = 3,600 10-9 C
r₂ = Ra (1.4 -0) 2 + (0.4 -0) 2
r₂ = 1.4560 m
we substitute
E₂ = k q₂ / r₂²
E₂ = 9 10⁹ 3,600 10⁻⁹ / 1.4560²
E₂ = 15.283 N / C
This field leaves the charge since the charge is positive, let's find the angle
tan θ = y / x
θ = tan⁻¹ y / x
θ = tan⁻¹ 0.400 / 1.400
θ = 15.9º
let's decompose the electric field
sin 15.9 = E_{2y} / E2
cos 15.9 = E₂ₓ / E2
E_{2y} = E2 sin 15.9
E₂ₓ = E2 cos 15.9
E_{2y} = 15.283 sin 15.9 = 4.187 N / C
E₂ₓ = 15.283 cos 15.9 = 14.698 N / C
the field lines leave the positive charge and are directed to the left, therefore
E_{2y} = - 4.187 N / C
E₂ₙ = -14.698N / C
the total field on each axis is
Eₓ = E_{1x} + E_{2x}
Eₓ = 0 -4,187
Eₓ = -4,187 N / C
E_y = 21.635 - 14.698
E_y = 6,937 N / C
The temperature of a body is from 200 to 300C.The change of temp at absolute scale is
Answer:
mark me brainliest
Explanation:
The change of temperature at absolute scale is. A. 3.73 K
Answer:
373K
Explanation:
300°c - 200°c =100°c
Absolute scale means Kelvin scale so
0°c= 273°c
100°c = 100 + 273
=373K
A car is moving at 20 meters per second for 1 minute, how far did the car travel?
Answer: he goes 1200 m/s
Explanation: because 1 minute is equal to 60 sconds and you have to multiply 20 times 60 so the answer is the car goes 1200 m
The diagram below depicts a game of tug of war between Person A and Person B. Person A pulls the rope with a force of FA while Person B pulls with force FB.
If FB is greater than FA, what describes the movement of the center flag?
It moves in the direction of FB at a changing rate of speed.
It moves in the direction of FA at a constant rate of speed.
It moves in the direction of FB at a constant rate of speed.
It moves in the direction of FA at a changing rate of speed.
Answer:
It moves in the direction of FB at a constant rate of speed.
Explanation:
In order to answer this question, the Newton's Second Law of motion shall be used. The Newton's Second Law of Motion states that when an unbalanced force is applied to an object, it produces an acceleration in that object. This acceleration is in the direction of the unbalanced force. So, when the person A and person B are applying forces FA and FB, the force FB is greater than FA. Hence, the unbalanced force will be in the direction of FB, the greater force. So, the flag will move in the direction of FB at a acceleration (rate of speed). So, the correct option is:
It moves in the direction of FB at a constant rate of speed.
Your class goes on a field trip to observe drilling machinery. The geologists at the drill site show you displays of drilled rocks to compare different types of drills and methods. The drilled holes in one rock display are significantly larger than the holes drilled in the display next to it. Given this information, which statement is correct?
We can see here that the statement that is correct will be: B. The rock display with larger holes shows petroleum drilling, which is deep underground.
Who is a geologist?A geologist is a scientist who focuses on the solid components of the Earth, such as minerals and rocks, as well as the processes that shape the planet's surface.
Geologists study the make-up, structure, and past of the Earth's crust in order to comprehend geological processes including mountain creation, earthquake and volcanic activity, and the exploitation of natural resources. They frequently perform fieldwork, gathering samples, running surveys, and researching geological formations.
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The complete question is that:
Your class goes on a field trip to observe drilling machinery. The geologists at the drill site show you displays of drilled rocks to compare different types of drills and methods. The drilled holes in one rock display are significantly larger than the holes drilled in the display next to it. Given this information, which statement is correct? (1 point)
A. The rock display with smaller holes shows copper drilling, which is deep underground.
B. The rock display with larger holes shows petroleum drilling, which is deep underground.
C. The rock display with smaller holes shows petroleum drilling, which is closer to the surface.
D. The rock display with larger holes shows copper drilling, which is closer to the surface.
A shaft carries five masses A, B, C, D and E which revolve at the same radius in planes
which are equidistant from one another. The magnitude of the masses in planes A, C and
D are 50 kg, 40 kg and 80 kg respectively. The angle between A and C is 90° and that
between C and D is 135°. Determine the magnitude of the masses in planes B and E and
their positions to put the shaft in complete rotating balance.
The magnitude of the masses in planes B and E is 40 kg, and their positions are 120° and 240°, respectively, from the reference point on the shaft to achieve complete rotating balance.
To achieve complete rotating balance, the sum of the moments of the masses in planes A, C, D, B, and E should be equal to zero. Let's determine the magnitude of the masses in planes B and E and their positions.
Consider the moments of the masses in planes A, C, and D. The moment of a mass is given by the product of its magnitude and the sine of the angle between the mass and a reference line. The moments of masses A, C, and D are:
Moment of A = 50 kg * sin(0°) = 0 kg·m,
Moment of C = 40 kg * sin(90°) = 40 kg·m,
Moment of D = 80 kg * sin(135°) = -80 kg·m.
Since the moments of A, C, and D are known, we can use the principle of complete rotating balance to determine the magnitude and position of the masses in planes B and E.
Let's assume the magnitude of the masses in planes B and E as M. The moments of masses B and E can be represented as:
Moment of B = M * sin(120°) = M * √(3)/2,
Moment of E = M * sin(240°) = -M * √(3)/2.
Using the principle of complete rotating balance, the sum of the moments should be zero. Thus, we have:
Moment of A + Moment of C + Moment of D + Moment of B + Moment of E = 0.
0 + 40 kg·m + (-80 kg·m) + M * √(3)/2 + (-M * √(3)/2) = 0.
Simplifying the equation:
40 kg·m - 80 kg·m + M * √(3)/2 - M * √(3)/2 = 0,
-40 kg·m = 0.
From the equation, we can deduce that M must be equal to 40 kg to satisfy the condition of complete rotating balance.
Finally, we determine the positions of masses B and E. Since planes A, C, D, B, and E are equidistant from one another, and the angle between A and C is 90°, we divide the circle into 360°/5 = 72° sections. Thus, the positions of masses B and E are:
Position of B = 0° + 2 * 72° = 144°,
Position of E = 0° + 4 * 72° = 288°.
Therefore, the magnitude of the masses in planes B and E is 40 kg, and their positions to put the shaft in complete rotating balance are 144° and 288°, respectively, from the reference point on the shaft.
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The following are four electrical components.
A. A component which obeys ohm's law
B. Another component which obeys ohm's law
but which has higher resistance than A
A filament lamp
C.
D. A component, other than a filament lamp,
which does not obey ohm's law.
a. For each of these components, sketch current-
voltage characteristics, plotting current on the
vertical axis, and showing both positive and
negative values. Use one set of axes for A and
B, and separate sets of axes for C and for D.
label your graphs clearly.
b.
Explain the shape of the characteristic for C
c. Name the component you have chosen for D.
For the following are four electrical components:
a. For components A and B, both of which obey Ohm's law, the current-voltage characteristics would be a straight line passing through the origin. The slope of the line for component B would be steeper than that of component A, indicating higher resistance.
b. The shape of the characteristic for component C, the filament lamp, can be explained by its construction. A filament lamp consists of a filament made of a resistive material, typically tungsten, which heats up and emits light when an electric current passes through it.
c. The component chosen for D, which does not obey Ohm's law, could be a diode. A diode is a two-terminal electronic component that allows the current to flow in only one direction.
For the following are four electrical components:
a. Sketches of current-voltage characteristics:
For components A and B, both of which obey Ohm's law, the current-voltage characteristics would be a straight line passing through the origin. The slope of the line for component B would be steeper than that of component A, indicating higher resistance.
Current (I)
^
| B
| /
| /
| /
| /
| /
| /
| /
| /
| /
|/
+------------------> Voltage (V)
Current (I)
^
| A
| /
| /
| /
| /
| /
| /
| /
| /
| /
|/
+------------------> Voltage (V)
For component C, a filament lamp, the current-voltage characteristic would be a curve that is not linear. It would exhibit a non-linear increase in current with increasing voltage. At lower voltages, the lamp would have low resistance, but as the voltage increases, the resistance of the filament also increases due to the phenomenon of thermal self-regulation. This leads to a slower increase in current at higher voltages.
For component D, a component that does not obey Ohm's law, the current-voltage characteristic could be any non-linear curve depending on the specific component chosen. Examples of components that do not obey Ohm's law include diodes and transistors.
b. The shape of the characteristic for component C, the filament lamp, can be explained by its construction. A filament lamp consists of a filament made of a resistive material, typically tungsten, which heats up and emits light when an electric current passes through it. As the voltage across the filament increases, the temperature of the filament increases as well, causing its resistance to increase. This increase in resistance results in a slower increase in current with increasing voltage, leading to the characteristic non-linear curve observed.
c. The component chosen for D, which does not obey Ohm's law, could be a diode. A diode is a two-terminal electronic component that allows the current to flow in only one direction. It exhibits a non-linear current-voltage characteristic where it conducts current only when the voltage is above a certain threshold, known as the forward voltage. Below this threshold, the diode has a high resistance and blocks current flow in the reverse direction. The characteristic curve of a diode would show negligible current flow until the forward voltage is reached, after which it exhibits a rapid increase in current with a relatively constant voltage.
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22 Humans see different colors of
the visible light spectrum because
A. the wavelength of light is
reflected by what it is hitting and
directed back into the eye.
B. the wavelength of light is
refracted by what it is hitting and
directed back into the eye.
C. the wavelength of light is
diffracted by what it is hitting
and directed back into the eye.
D. the wavelength of light is
absorbed by what it is hitting and
directed back into the eye.
Answer:
A. the wavelength of light is reflected by what it is hitting and directed back into the eye.
Explanation:
what is shear stress
Answer:
T=F/A
Explanation:
T= shear stress
F=applied force
A=cross sectional area
shear stress, force tending to cause deformation of material by slippage along a plane or planes parallel to the imposed stress, the resultant shear is of a great importance in nature, being intimately related to the downslope movement of earth materials and earthquakes.
when does Neuroplasticity occur in the brain????
Answer:
Neuroscientists believed that neuroplasticity only manifested itself in childhood, but late 20th-century research suggests that many aspects of the brain can change (or become "plasticized") even in adulthood.
Explanation:
How long has tension been building in the cascadia fault zone
Answer:
The Cascadia Subduction Zone has not produced an earthquake since 1700 and is building up pressure where the Juan de Fuca Plate is subsiding underneath the North American plate.
Explanation:
At depths shallower than 30 km (19 mi) or so, the Cascadia zone is locked by friction while stress slowly builds up as the subduction forces act, until the fault's frictional strength is exceeded and the rocks slip past each other along the fault in a megathrust earthquake. Below 30 km (19 mi) the plate interface exhibits episodic tremor and slip .
what is percentage....
Answer:
Percent composition is calculated from a molecular formula by dividing the mass of a single element in one mole of a compound by the mass of one mole of the entire compound. This value is presented as a percentage.
Explanation:
Hope this helps..
Answer:
In mathematics, a percentage is a number or ratio expressed as a fraction of 100. It is often denoted using the percent sign, "%", although the abbreviations "pct.", "pct" and sometimes "pc" are also used. A percentage is a dimensionless number; it has no unit of measurement.
And
A percentage is a portion of a whole expressed as a number between 0 and 100 rather than as a fraction. All of something is 100 percent, half of it is fifty percent, none of something is zero percent. ... A percentage can also mean a portion of something but only when it has to do with numbers.
hope this helps
10. IB challenge question: Two masses hang from a pulley as shown. Calculate the acceleration of the smaller mass. Use 10 for acceleration due to gravity instead of 9.81. (Hint: look at each mass separately, and create a system of equations) I 1kg 3kg
The acceleration on the block of mass 1 kg will be equal to the acceleration due to gravity that is 9.81 m/s².
What is Acceleration?
Acceleration of an object is the rate of change of the velocity of the object with respect to time.
As the string and pulley system is ideal so the tension will be constant throughout the string and thus both of the blocks will move with the same acceleration, suppose the tension is T and the common acceleration is a
Then, 3kg being heavier weight will move downward.
The tension always act towards a direction away from the block.
The net downward force on 3kg block will be (3g − T)
So, the equation of Force will be F = ma or (3g − T)= 3a ...(1)
Similarly, the net upward force on 1kg block will be (T − 1g)
So, the equation of Force will be F = ma or (T − 1g) = 1a ...(2)
By adding both these equations 1 and 2.
We get,
2g = 2a
a = g
Therefore, acceleration on the block of 1 kg will be equal to the acceleration due to gravity that is 9.81m/s².
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where were the first psychology laboratory established?
Answer:
it was established in USA, Johns Hopkins University.
Answer:
The 1st psychology lab in the U.S.A. was established in 1883 at Johns Hopkins University by G. Stanley Hall
A toroid with a square cross section 3.0 cm × 3.0
cm has an inner radius of 25.0 cm. It is wound with 500
turns of wire, and it carries a current of 2.0 A. What is the
strength of the magnetic field at the center of the square
cross section?
The magnetic field is 1.353 x 10⁻³ T.
What is the magnetic field at the center of the square cross section?Now we know that the magnetic field is given by the formula;
B = μ₀ NI/2πr
N = number of turns of the wire
μ₀ = permeability of free space
I = current in each turn
r = distance at which the magnetic field
B = magnetic field
Given that;
r = (a + b)/2, where a = inner radius and b= outer radius
b = 25.1 + 3 = 28.1 cm
a = 25.1 cm
r = (25.1 + 28.1)/2 = 26.6 cm = 0.266m
B = 4π x 10⁻⁷ x 600 x 3/2π x 0.266
B = 1.353 x 10⁻³ T
Hence the magnetic field is 1.353 x 10⁻³ T.
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