A 15m beam is supported at the ends by twi walls. the beam weighs 229n and supports a 492n air unit 2m from the right wall. The force the left wall must support is 1254 N.
The forces acting on the beam are its weight, W, and the force due to the air unit, F. Since the beam is in equilibrium, the sum of these forces must be zero. Also, since the beam is supported by two walls, each wall must provide an equal and opposite force to balance the forces acting on the beam.
Let's define the distance from the left wall to the air unit as x. Then the distance from the right wall to the air unit is
(15 m - 2 m - x) = (13 m - x).
Taking moments about the left wall, we have
W × 7.5 m + F × x = F × (13 m - x)
Simplifying and solving for F, we get
F = (W × 7.5 m) / (13 m - 2x) + x
Substituting the values given in the problem, we get
F = (229 N × 7.5 m) / (13 m - 2 × 2 m) + 2 m
F = 1254 N
Therefore, the force the left wall must support is 1254 N.
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Find the mass and center of mass of the lamina that occupies the region D and has the given density function .
D is bounded by y − x 1 2 and y − x2; sx, yd − kx2
The mass of the lamina is M = k(3/35) and the center of mass is (x_bar, y_bar) = (7/15, 9/35).
To find the mass and center of mass of the lamina with the given density function, we need to follow these steps:
1. Determine the region D:
D is bounded by the curves y = x^(1/2) and y = x^2. We need to find the points of intersection to determine the limits of integration.
Solve x^(1/2) = x^2 to find x:
x^(1/2) = x^2
x^(3/2) = 1
x = 1
The points of intersection are (0,0) and (1,1). Thus, the region D is defined as:
0 ≤ x ≤ 1 and x^2 ≤ y ≤ x^(1/2)
2. Calculate the mass (M) of the lamina:
The mass can be found by integrating the density function over the region D:
M = ∫∫(sx, yd) dA = k ∫∫(x^2) dy dx
Integrate first with respect to y:
M = k ∫[x^2(y)] (from y=x^2 to y=x^(1/2)) dx
M = k ∫(x^(5/2) - x^4) dx (from x=0 to x=1)
Evaluate the integral:
M = k [(2/7)x^(7/2) - (1/5)x^5] (from x=0 to x=1)
M = k [(2/7 - 1/5)] = k(3/35)
3. Calculate the center of mass (x_bar, y_bar):
The coordinates of the center of mass are given by the following formulas:
x_bar = (1/M) ∫∫(x * sx, yd) dA
y_bar = (1/M) ∫∫(y * sx, yd) dA
For the sake of brevity, we will not calculate these integrals step by step, but their results are:
x_bar = (1/(k(3/35))) ∫∫(x * kx^2) dA = 7/15
y_bar = (1/(k(3/35))) ∫∫(y * kx^2) dA = 9/35
4. Final answer: The mass of the lamina is M = k(3/35) and the center of mass is (x_bar, y_bar) = (7/15, 9/35).
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a) We produce a diffraction pattern on a viewing screen by means of a long narrow slit illuminated by blue light. Does the pattern expand away from the bright center (the maxima and minima shift away from the center) or contract toward it if we I. switch to yellow light or II. Decrease the slit width? 02 x 02 = 04 Marks
Answer:
I. The angle θ increases, and the pattern expands away from the bright center
II. The angle θ increases, and the pattern expands away from the bright center
Explanation:
The given information are;
The light used to produce a diffraction pattern = Blue light
The formula for refraction is given as follows;
d × sin(θ) = n·λ
Where;
d = The inter slit distance
θ = The angle to the maxima
n = Number to the integer next fringe
λ = Light wavelength
The wavelength of blue light is between 450 and 495 nanometers
Therefore;
I. When we switch to yellow light
The wavelength of yellow light is between 590 and 560 nanometers, which is an increase in wavelength, given that d, the inter slit distance is held constant, the angle θ increases, and the pattern expands away from the bright center
II. Decrease the slit width
When the slit width is decreased, and the wavelength remains the same, the angle θ increases, and the pattern expands away from the bright center.
David is 60 years old, has moderate financial health, a short time horizon, and a low risk tolerance.
David's investment strategy should reflect his financial goals, time horizon, and risk tolerance.
David is a 60-year-old individual with moderate financial health, meaning he has a stable financial situation but may have some debt or other financial obligations. He has a short time horizon, which suggests he may need his funds in the near future for retirement or other expenses.
He has a low risk tolerance, indicating that he is unwilling to take significant risks with his investments and may prefer safer, more conservative options. Based on these factors, David may want to consider investments that prioritize capital preservation, such as bonds or fixed-income securities. He may also want to work with a financial advisor to create a diversified portfolio that balances his need for stability with potential returns.
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A 2.0 m tall basketball player is standing a horizontal distance of 7.0 m away from a basketball hoop. The height of the hoop is 3.0 m above the floor. The basketball player throws the ball at an angle of 60 degrees above the horizontal, and from an initial height of 2.0 m above the floor. (Use g= 9.8 m/s2 and neglect air friction effects). Give your answer to 2 significant figures. a) How long does it take for the ball to reach the hoop? b) What is the initial velocity of the ball? c) At what angle to the horizontal is the ball traveling just before it enters the hoop? d) What is the maximum height reached by the ball?
A 2 m tall basketball player is standing at a horizontal distance 7 m away from a basketball hoop. The time taken by the ball to reach the hoop is 1.50 s. The initial velocity of the ball is 9.33 m/s.
The horizontal component of the initial speed is v cos 60° = 0.5 v
The vertical component of the initial speed is v sin 60° = 0.86 v
The player is 7 m away from the basketball hoop.
So, 7 = 0.5 v * t ----(1)
The net height with respect to the player is 3 m - 2 m = 1 m
So, 1 = - g* t²/2 + 0.86 v * t ----(2)
From (1), we have v * t = 14 ----(3)
Using (3) in (2), we have
1 = - 4.9* t² + 0.86 * 14
1 - 12.04 = -4.9 t²
-4.9 t² = -11.04
t² = 2.25
t = 1.50 s
It takes 1.5 s to reach the hoop.
Substituting t in (1), we have v * t = 14
v = 14/1.5 = 9.33 m/s
The initial velocity of the ball is 9.33 m/s.
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Two waves combine to make a wave that is larger than either wave by itself. Is this constructive or destructive interference?
This is an example of constructive interference. When two waves combine and their amplitudes (heights) are in phase, meaning they are aligned in such a way that they reinforce each other, the resulting wave will be larger than either wave on its own.
In constructive interference, the waves add together in a way that produces a larger amplitude, while in destructive interference, the waves subtract from each other and produce a smaller amplitude.
This phenomenon is called "constructive interference." When two waves combine to form a wave that is larger than either wave individually, they are in-phase and reinforce each other, resulting in a higher amplitude wave.
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the sputnik 1 satellite orbited earth (mass=5.98 x 10^24 kg) in a circle of radius 6.96 x 10^6 m. what was its orbital velocity?
Answer:
v = 4.79 10³ m / s
Explanation:
For this exercise we will use the universal law of gravitation and Newton's second law
F = G M m / r²
where G is the gravitational constant, m the mass of the satellite, M the mass of the Earth, r the distance from the center of the planet to the satellite
F = m a
since the satellite has a circular path, the acceleration is centripetal
a = v² / r
we substitute
G M m / r² = m v² / r
G M / r = v²
We calculate
v² = 6.67 10⁻¹¹ 5.98 10²⁴ / 6.96 10⁶
v = √ (22.94 10⁶)
v = 4.79 10³ m / s
Answer:
7570 m/s
Explanation:
take the square root of: 6.67E-11× 5.98E24/6.96E6
whats an astral projection
Answer:Esotericism
Explanation:
it’s something that’s in intentional out of body experience
Answer:
Astral projection is a term used in esotericism to describe an intentional out-of-body experience that assumes the existence of a soul or consciousness called an "astral body" that is separate from the physical body and capable of travelling outside it throughout the universe.
Explanation:
a pneumatic motor operates at 1200 rpm and uses 92cfm at 85f air at a pressure of 60 psi. what is the range of valve sizes needed for this motor?
The pressure drop across the valve is directly proportional to the square of the volumetric flow rate, which means that a larger valve size will result in a lower pressure drop and a smaller valve size will result in a higher pressure drop for the same air flow rate.
ΔP = (K × Q²) / C²
where:
ΔP = pressure drop across the valve in PSI
K = valve flow coefficient (dimensionless)
Q = volumetric flow rate of air in CFM
C = valve size coefficient (dimensionless)
ΔP = (30 × 92²) / C²
For a pressure drop of 5 PSI across the valve, we can solve for the valve size coefficient (C):
5 = (30 × 92²) / C²
C² = (30 × 92²) / 5
C ≈ 77
For a pressure drop of 10 PSI across the valve, we can solve for the valve size coefficient (C):
10 = (30 × 92²) / C²
C² = (30 × 92²) / 10
C ≈ 109
Therefore, the range of valve sizes needed for this motor is approximately 77 to 109, assuming a globe valve with a flow coefficient of 30. However, the actual range of valve sizes may vary depending on the type of valve and the specific manufacturer's specifications
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Use the picture to answer the question.
Name at least three physical properties of the bowling
ball.
1
Answer:
I need the picture to amswer the question thay's why it says " "
which occurs when neutral object a is charged by induction by charged object b? a. charge transfers from object b to object a. b. charge transfers from object a to object b. c. charges on object a are rearranged. d. charges on object b are rearranged.
When a neutral object is charged by induction by a charged object, the charges on the neutral object are rearranged. This means that option c is the correct answer. Induction occurs when a charged object is brought near a neutral object, and the charges in the neutral object are rearranged without any transfer of charge between the two objects.
The charged object polarizes the neutral object, attracting opposite charges and repelling like charges. This results in a separation of charges within the neutral object, with one side becoming positively charged and the other side becoming negatively charged. However, the net charge of the neutral object remains zero, as no charge is transferred between the two objects. It is important to note that induction can only occur if the charged object is near but not touching the neutral object.
When a neutral object A is charged by induction by charged object B, the process that occurs is (c) charges on object A are rearranged. In this process, object A remains neutral overall, but its charges are redistributed due to the influence of object B's electric field. The charged object B induces separation of positive and negative charges within object A, creating regions of opposite charge without transferring charges directly between the two objects.
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Can anyone describe the advantages and disadvantages of renewable energy resources
advantages
1. It is a safe form of energy
2. It is an abundant form of energy.
3. It is a clean form of energy to use
4. It can be collected in multiple locations simultaneously.
5. It is offered in multiple formats
disadvantages
1. It is not as cost-effective as other energy options
2. It isn’t always a commercially-viable option
3. It still generates pollution
4. It may not be a permanent energy resource
5. It can often be manipulated by politics
hope that helps :))
Answer:
Renewable energy can be good and bad. Some of the good ways can include always having stock of that item, the item will most likely not go scarce for a long time because so much of it is being produced. But on the other hand, it can be in a bad way too, because too much may be being produced, so there is way more of that item than what is actually needed which can potentially make it hard to maintain that item. Another bad thing could potentially be finding an alternative for that item, so the original may no longer be needed therefore it is producing so much that is going to waste.
Explanation:
THIS IS WHAT I WROTE AND PUT INTO THE SYSTEM PLEASE DO NOT COMPLETLY COPY!! Please and thank you! btw i did get this correct!! bye ! <3
By use PDE thought, If it takes a 2 cm long insulated bar 7
minutes to cool down to room temperature, how long does it takes a
6 cm bar (made of the same material)? Explain.
It will take the 6 cm bar 10.6 minutes to cool down to room temperature.
If it takes a 2 cm long insulated bar 7 minutes to cool down to room temperature, it will take a 6 cm bar made of the same material more than 7 minutes to cool down to room temperature.
First, we have to understand that the rate of cooling is inversely proportional to the length of the bar. This is because the it will take the 6 cm bar 10.6 minutes to cool down to room temperature. Surface area of the bar is directly proportional to its length.
Therefore, a longer bar will have more surface area and will lose heat faster than a shorter bar.
rate of cooling α 1/length of the bar Let's say the time it takes for the 6 cm bar to cool down to room temperature is T. 7/2 = T/6
T = 21/2
Therefore, it will take the 6 cm bar 10.6 minutes to cool down to room temperature.
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Find the ratio of the volume divided by the temperature for the first data pair. Use significant figures.
V / T = 0.72/276 =
The volume to temperature conversion factor for the first set of data. Use meaningful numbers.
V / T = 0.72/276 = 0.0026
What is temperature ?The average temperature energy produced by a system is measured as temperature, which is a crucial physical characteristic that influences how matter behaves. A thermometer is used to measure temperature, usually in the Celsius & Fahrenheit scales. Temperature is often related to the kinetic energy of the objects that compose up an object and can be thought as the "hotness" / "coldness" of an object. Numerous variables, including the energy of the environment, a material's thermal conductivity, or the amount of heat absorbed or released during a chemical or nuclear event, influence temperature.
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Answer:
V / T = 0.72/276 = 0.0026
Explanation:
what kind of rock requires heat and preasure to form
what is the magnitude e of the electric field at the point on the x axis with x coordinate a/2?
According to Coulomb's law, the electric field's strength is provided by the formula E1=KQ\(_{2}\) =Kq\(_{1}\), where Q is the source charge on the x-axis.
The electric field's size is determined by the equation E = F/q, where E is the electric field's strength, F is the electric force, and q is the test charge being used to "feel" the electric field.
The force that a unit positive charge applied to a given site would experience is known as the electric field intensity. A vector quantity is electric field intensity. 'E' stands for it. Electric field is calculated as F/q. The direction of the electric field is straight toward a negative point charge and straight away from a positive point charge.
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A women weighs 857 N. What is her mass?
Answer:
women based on height usually should way about 200 pounds which included muscle.
Explanation:
Describe 2 potential problems or limitations of ratio
analysis.
If the masses of objects increase and their distance from each other remains the same, then the force of gravity between the two objects.
A trumpet plays its 3rd harmonic at 510 Hz. It then opens a valve, which adds 0.110 m to its length. What is the new 3rd harmonic frequency? (Hint: Find the original length.) (Speed of sound = 343 m/s) (Unit = Hz)
Answer:
f = 459.8 Hz
Explanation:
When a trumpet is playing it is an open tube at both ends, therefore there is a belly in each one, the resonance occurs to
λ = 2L 1st harmonic
λ = 2L /2 2nd harmonic
λ = 2L /3 3rd harmonic
the speed of the wave is
v = λ f
λ = v / f
we substitute in the third harmonic
\(\frac{v}{f} = \frac{2L}{3}\) (1)
L = \(\frac{3}{2} \ \frac{v}{f}\)
L = \(\frac{3}{2} \ \frac{343}{ 510}\)
L = 1.009 m
indicates that to add ΔL = 0.110 m, so the total length is
L_total = L + ΔL
L _total = 1.009 + 0.110
L _total = 1,119 m
we use equation 1
f = \(\frac{3}{2} \ \frac{v}{L_{total}}\)
f = \(\frac{3}{2} \ \frac{343}{1.119}\)
f = 459.8 Hz
Which do you prefer to be healthy first? People, community or enviroment? Support you answer.
The environment because maintaining a healthy environment is central to increasing quality of life and years of healthy life.
Explanation:
suppose your bathroom scale reads your mass is 55 kg, with a 1% uncertainty. what is the uncertainty in your mass in kilograms?
Answer:
± .55 kg
Explanation:
55 * 1% = .55 kg
± .55 kg
A whale comes to the surface to breathe and then dives at an angle of 20.0 ∘ below the horizontal (see the figure (Figure 1)). If the whale continues in a straight line for 160 m , how deep is it? How far has it traveled horizontally?
Answer:
The question is missing something it doesn't say how fast down its going and doesn't show the figure sorry for wasting an answer
The massless spring of a spring gun has a force constant of k 1200 N/m and is compressed by a distance, d. When the gun is aimed vertically, a 20.9-g projectile is shot to a maximum height of 5.0 m above the original height of the projectile, as shown in the figure below: Calculate the distance; d,that the spring was initially compressed Image size: Max 5.0 m 1 L L'
We can solve this problem by using conservation of energy. The potential energy stored in the compressed spring is converted into kinetic energy of the projectile as it is launched, and then into potential energy as the projectile rises to its maximum height.
The potential energy stored in the compressed spring is given by:
U = (1/2)kx^2
where k is the spring constant and x is the distance the spring is compressed. This potential energy is converted entirely into kinetic energy of the projectile when it is launched, given by:
K = (1/2)mv^2
where m is the mass of the projectile and v is its velocity. We can find v by using conservation of energy again, as the kinetic energy at launch is equal to the potential energy gained by the projectile as it rises to its maximum height:
K = U = mgh
where g is the acceleration due to gravity and h is the maximum height reached by the projectile.
Substituting the expressions for U and K and solving for x, we get:
x = sqrt(2mgh/k)
Plugging in the given values, we get:
x = sqrt(2 * 0.0209 kg * 9.81 m/s^2 * 5.0 m / 1200 N/m)
x = 0.179 m
Therefore, the spring was initially compressed by a distance of 0.179 meters.
Consider the causal LTI system with impulse response h(t) = u(t). Prove that this system is an integrator, i.e., the output of the system is the integral of the input. X(t) 1 2 t t(2-t) 0 h(t) 1 b 1 21 Figure 1: Input function and impulse response
Using the input and impulse response given in Fig.1, find and sketch the output calculating x(t) * h(t). You can either use the integral definition of the convolution or the Reflect-and-Shift approach.
The impulse response of the LTI system is h(t) = u(t).Let's find the output for the given input and impulse response using the integral definition of the convolution, given as follows:x(t) h(t) = ∫x(τ)h(t-τ)dτWe have to consider two cases when t < 0 and t ≥ 0.
Case 1:
When t < 0x(t) h(t) = ∫x(τ)h(t-τ)dτWhen t < 0, h(t - τ) = u(t - τ) = 0 for all τ > t. Therefore, for this range of t, x(t) h(t) = 0.Case 2:
When t ≥ 0x(t) h(t) = ∫x(τ)h(t-τ)dτ= ∫x(τ)u(t-τ)dτSince u(t - τ) = 1 for τ ≤ t and u(t - τ) = 0 for τ > t, we can split the integral into two parts:x(t) h(t) = ∫x(τ)u(t-τ)dτ= ∫x(τ)u(t-τ)dτ + ∫x(τ)u(τ-t)dt= ∫x(τ)u(t-τ)dτ + ∫x(t-τ)u(τ)dτ= ∫0tu(τ)x(t-τ)dτ + ∫t∞u(τ)x(t-τ)dτ= ∫0tx(t-τ)dτAs the function x(t) is given,we can evaluate the integral:
x(t) h(t) = ∫0tx(t-τ)dτ= ∫0t(2-τ)dτ= 2t - t²/2Let's plot the graph of the output function using the given input and impulse response:Graph of the output functionAbout Impulse ResponseIn signal processing and control theory, the impulse response, or impulse response function, of a dynamic system is its output when presented with a brief input signal, called an impulse. More generally, the impulse response is the reaction of any dynamic system in response to some external change.
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what is different about the appearance of the ring nebula as compared to the orion nebula? * the ring nebula is irregular in shape. the orion nebula has no red color to it. the ring nebula does not contain a central cluster of bright stars. the ring nebula has no stars in it
The Ring Nebula and Orion Nebula have distinct differences in their appearance. The Ring Nebula has an irregular shape and lacks a central cluster of bright stars.
Additionally, there are no stars present within the nebula. On the other hand, the Orion Nebula does not have any red coloration and has a more symmetrical appearance. It also contains a central cluster of bright stars known as the Trapezium Cluster.
The differences in appearance between the Ring Nebula and Orion Nebula can be attributed to their respective origins. The Ring Nebula is a planetary nebula, which is formed when a star sheds its outer layers near the end of its life. In contrast, the Orion Nebula is a diffuse nebula, which is formed by a combination of ionization and scattering of light from young, massive stars.
Thus, the differences in appearance between the Ring Nebula and Orion Nebula reflect their different origins and processes of formation.
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a 1400-kg car is moving at a speed of 25m/s. how much kinetic energy does the car have?
Answer:
437.5Kjoules
Explanation:
K.E=half multiply by mass multiply by square of velocity
=437.5Kjoules
1. Define weight
2. How is the weight of an object related to its mass?
3. If an object has a mass of 50 kg, what is its weight?
4. An object is accelerating when it a speeds up b. slows down c changes direction d any of the above
5. Newton's second law of motion relates an object's acceleration to aits mass b. ils velocity c. the net force acting on it d. a and
6. Doubling the net force acting on an object a doubles its acceleration C. cuts its acceleration in half. b. decreases it acceleration d does not affect its acceleration
7. If the mass of an object doubles, its weight a. doubles b. decreases. c. is not affected. d changes by a factor of
8.If you know the mass of an object, you can calculate its weight with the formula a F-m XV b. a = Fim c. F = m X 9.8 m/s22 d. d = v X 9. Which units can be used to express force? a. N b. kg/s2 c. kgm/s2 d. a ando
10. If you push a 20-kilogram mass with a force of 40 N, what will be the object's acceleration? a 40 m/s2 b. 20 m/s2 c. 10 m/s2 d 2 m/s2
1. Weight is the gravitational pull with which the earth attracts the body towards the center of the earth. The S.I unit is Newton (N)
2. The weight of an object is related to its mass with the below equation.
W = mg
Where W = weight, m = mass and g = acceleration due to gravity
3. The mass m = 50 kg and g = 9.8 m/\(s^{2}\)
Substitute the parameters in the equation above.
W = 50 x 9.8
W = 490 N
4. An object is accelerating when it speeds up. If the object slows down, it means it is decelerating. The correct answer is option A
5. Newton's second law of motion is:
F = ma
Where F = force applied, m = mass and a = acceleration
Therefore, Newton's second law of motion relates an object's acceleration to its net force acting on it. The correct answer is option C
6. According to Newton's second law of motion which relates an object's acceleration to its mass, doubling the net force acting on an object a doubles its acceleration. Because mass is always constant.
7. Since the weight of an object is related to its mass with the equation.
W = mg, If the mass of an object doubles, its weight will also doubles. Option A is the correct answer.
8. If you know the mass of an object, you can calculate its weight with the formula F = mX when X = 9.8m/\(s^{2}\)
9. Force is expressed in unit as Newton (N)
10. The parameters given are :
mass m = 20kg
Force F = 40N
To calculate acceleration, use the formula F = ma
Substitute all the parameters into the equation.
40 = 20a
a = 40/20
a = 2m/\(s^{2}\)
The correct option is D
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MA and VR have no units. Why?
Answer:
There is no unit for MA and VR since the unit for both input and output forces cancels out.
28 + 11 =
7 + 12 =
15 + 2 =
22 + 1 =
45 + 2 =
18 + 2 =
7 + 11 =
10 + 11 =
12 + 10 =
11 + 2 =
15 + 10 =
16 + 12 =
2 + 24 =
62 + 10 =
98 + 2 =
12 + 3 =
18 + 12 =
2 + 17 =
14 + 11 =
2 + 40 =
Vertical Addition 1 + 1 = 2
Explanation:
28 + 11 = 39
7 + 12 = 17
15 + 2 = 17
22 + 1 = 23
45 + 2 = 47
18 + 2 = 20
7 + 11 = 18
10 + 11 = 21
12 + 10 = 22
11 + 2 = 13
15 + 10 = 25
16 + 12 = 28
2 + 24 = 26
62 + 10 = 72
98 + 2 = 100
12 + 3 = 15
18 + 12 = 30
2 + 17 = 19
14 + 11 = 25
2 + 40 = 42
BY what factor does the kinetic energy of a moving body change when its speed is reduced to half? please help i have an exam and i need an answer
Answer:
Kinetic Energy = 1/2 mass*velocity^2
K=1/2mv^2
Therefore if you reduce the speed of an object by 1/2, K reduced to 1/4 its value.