Answer:
16oz Package of rice.
Step-by-step explanation:
if you get 2 16oz packages of rice you'll end up with 32oz for only $1.58. Which is less then half the price
Therefore the better buy is the 16oz package of rice.
The following data shows the daily production of cell phones. 7, 10, 12, 15, 18, 19, 20. Calculate the Mean, Variance and Standard Deviation of production of cell phones. Show your work in the space provided for: a) Mean b) Variance per Day c) Standard Deviation 16 SB
The following data shows the daily production of cell phones. 7, 10, 12, 15, 18, 19, 20. Mean The formula for finding the mean is: mean = (sum of observations) / (number of observations).
Therefore, the mean for the daily production of cell phones is: Mean = (7+10+12+15+18+19+20) / 7
= 101 / 7
Mean = 14.43
Variance The formula for finding the variance is: Variance = (sum of the squares of the deviations) / (number of observations - 1) Where the deviation of each observation from the mean is: deviation = observation - mean First, calculate the deviation for each observation:7 - 14.43
= -7.4310 - 14.43
= -4.4312 - 14.43
= -2.4315 - 14.43
= 0.5718 - 14.43
= 3.5719 - 14.43
= 4.5720 - 14.43
= 5.57
Now, square each of these deviations: 56.25, 19.62, 5.91, 0.33, 12.75, 20.9, 30.96 The sum of these squares of deviations is: 56.25 + 19.62 + 5.91 + 0.33 + 12.75 + 20.9 + 30.96
= 147.72
Therefore, the variance for the daily production of cell phones is: Variance = 147.72 / (7-1) = 24.62 Standard deviation ) Mean = 14.43b) Variance per Day = 24.62c) Standard Deviation = 4.96
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Morgan flipped a coin 100 times and 44 of the 100 flips were tails. She wanted to see how likely a result of 44 tails in 10C flips would be with a fair coin, so Morgan used a computer simulation to see the proportion of tails in 100 flips, repeated 100 times.
Create an interval containing the middle 95% of the data based on the data from the simulation, to the nearest hundredth, and state whether the observed proportion is within the margin of error of the simulation results.
The interval containing the middle 95% of the simulation data is approximately 0.3426 to 0.5374.
To create an interval containing the middle 95% of the data based on the simulation results, we can use the concept of confidence intervals. Since the simulation was repeated 100 times, we can calculate the proportion of tails in each set of 100 flips and then find the range that contains the middle 95% of these proportions.
Let's calculate the interval:
Calculate the proportion of tails in each set of 100 flips:
Proportion of tails = 44/100 = 0.44
Calculate the standard deviation of the proportions:
Standard deviation = sqrt[(0.44 * (1 - 0.44)) / 100] ≈ 0.0497
Calculate the margin of error:
Margin of error = 1.96 * standard deviation ≈ 1.96 * 0.0497 ≈ 0.0974
Calculate the lower and upper bounds of the interval:
Lower bound = proportion of tails - margin of error ≈ 0.44 - 0.0974 ≈ 0.3426
Upper bound = proportion of tails + margin of error ≈ 0.44 + 0.0974 ≈ 0.5374
Therefore, the interval containing the middle 95% of the simulation data is approximately 0.3426 to 0.5374.
Now, we can compare the observed proportion of 44 tails in 100 flips with the simulation results. If the observed proportion falls within the margin of error or within the calculated interval, then it can be considered consistent with the simulation results. If the observed proportion falls outside the interval, it suggests a deviation from the expected result.
Since the observed proportion of 44 tails in 100 flips is 0.44, and the proportion falls within the interval of 0.3426 to 0.5374, we can conclude that the observed proportion is within the margin of error of the simulation results. This means that the result of 44 tails in 100 flips is reasonably likely to occur with a fair coin based on the simulation.
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QUICK PLEASE!!!
Consider f(x) Equals StartFraction 8 (x minus 1) Over x squared + 2 x minus 3 EndFraction.
Which statements describe the existence of vertical asymptotes at x = –3 and x = 1?
Answer:
A
Step-by-step explanation:
edge 2021
Answer:
It is A
Step-by-step explanation:
I got it right on the test Edge 2022.
Consider the given pseudo code. Write the function T(n) in terms of the number of operations, and then give the asymptotic (big Oh) complexity of the algorithm, show all the work you do. [ write the summation formula and solve it, or use the "Look for pattern"method. a. Matrix Multiplication
The function T(n) in terms of the number of operations is:
T(n) = 2n^3 + 3n^2 + 2n + 1 and the asymptotic complexity of the matrix multiplication algorithm is O(n^3).
To analyze the provided pseudo code for matrix multiplication and determine the function T(n) in terms of the number of operations, we need to examine the code and count the number of operations performed.
The pseudo code for matrix multiplication may look something like this:
```
MatrixMultiplication(A, B):
n = size of matrix A
C = empty matrix of size n x n
for i = 1 to n do:
for j = 1 to n do:
sum = 0
for k = 1 to n do:
sum = sum + A[i][k] * B[k][j]
C[i][j] = sum
return C
```
Let's break down the number of operations step by step:
1. Assigning the size of matrix A to variable n: 1 operation
2. Initializing an empty matrix C of size n x n: n^2 operations (for creating n x n elements)
3. Outer loop: for i = 1 to n
- Incrementing i: n operations
- Inner loop: for j = 1 to n
- Incrementing j: n^2 operations (since it is nested inside the outer loop)
- Initializing sum to 0: n^2 operations
- Innermost loop: for k = 1 to n
- Incrementing k: n^3 operations (since it is nested inside both the outer and inner loops)
- Performing the multiplication and addition: n^3 operations
- Assigning the result to C[i][j]: n^2 operations
- Assigning the value of sum to C[i][j]: n^2 operations
Total operations:
1 + n^2 + n + n^2 + n^3 + n^3 + n^2 + n^2 = 2n^3 + 3n^2 + 2n + 1
Therefore, the function T(n) in terms of the number of operations is:
T(n) = 2n^3 + 3n^2 + 2n + 1
To determine the asymptotic (big O) complexity of the algorithm, we focus on the dominant term as n approaches infinity.
In this case, the dominant term is 2n^3. Hence, the asymptotic complexity of the matrix multiplication algorithm is O(n^3).
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a quiz consists of five multiple-choice questions. each question has four possible responses. let's assume that you are guessing the answers and, therefore, all outcomes are equally likely. round your answers to five decimal places. a) what is the probability that you will correctly guess all five questions? b) what is the probability that you will correctly guess at least one question?
The probability of a. guessing all five questions is 0.00098. b. at least one question correctly is 0.76270.
What does probability theory's multiplication rule entail?According to the multiplication rule, which is part of probability theory, the likelihood that two or more independent events will occur together depends on the sum of their respective probabilities. The Bayes theorem, conditional probabilities, and issues involving independent occurrences are only a few areas of probability theory and statistics where the multiplication rule is applied.
Given that, probability of correctly guessing one question is 1/4.
The probability of guessing 5 questions correct is:
P(all correct) = (1/4) = 0.00097656
Hence, the probability of correctly guessing all five questions is 0.00098.
b. The probability of not guessing any question correctly is (3/4)^5.
Then, P of atleast one correct is:
P(at least one correct) = 1 - P(none correct) = 1 - (3/4)^5 = 0.76269531.
Hence, the probability of guessing at least one question correctly is 0.76270.
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Time for a mental field trip. You are off to the amusement park. After going on a couple of rides. you are hungry and thirsty. You've decided that you will purchase either a chili dog or popcorn for a snack. For a drink, you must decide between lemonade, an energy drink, and water. How many different ways can you select a snack and a beverage?
You have a total of six different ways to select a snack and a beverage at the amusement park.
To determine the number of different ways you can select a snack and a beverage, we can use the concept of combinations.
Let's analyze the options:
Snack: You can choose either a chili dog or popcorn. This gives us 2 choices for the snack.
Beverage: You can choose either lemonade, an energy drink, or water. This gives us 3 choices for the beverage.
To calculate the total number of combinations, we multiply the number of choices for the snack by the number of choices for the beverage. Therefore, the number of different ways to select a snack and a beverage is 2 (choices for snack) multiplied by 3 (choices for beverage), which equals 6.
In other words, there are six different combinations possible:
Chili dog and lemonade
Chili dog and energy drink
Chili dog and water
Popcorn and lemonade
Popcorn and energy drink
Popcorn and water
So, when considering all the options, you have a total of six different ways to select a snack and a beverage at the amusement park.
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when the angle of an incline with a block resting on it increases the normal support force? A) decreases B) increases C) stays the same
Answer:
normal force decreases
Step-by-step explanation:
N=mgcosθ, and cosine decreases as theta increases
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Answer:
A) decreases
Step-by-step explanation:
As the angle of the incline increases, the normal force decreases, which decreases the frictional force. The incline can be raised until the object just begins to slide.
Who invented algebra
Answer: Some assface who needs to commit toaster bath.
Step-by-step explanation: (the answer is actually Al-Khwarizmi)
Whats the value of x?
First, y = 40, since they are vertical angles.
Second, I assume the two angles with red marks are the same measure. The notation I learned would put a tick mark to formally indicate that, but without those being the same, you couldn't answer the question.
So, assuming that's correct, you'd have 2x + 2x + 40 = 180, since the measures of the angles of the left triangle have to add to 180º.
Solving 2x + 2x + 40 = 180, you'd get 4x = 140, or x = 35º.
Hope that helps.
In a classroom, there are 3 boxes of the exact same size and shape resting on a shelf. One box contains 1.0 kg of pencils, one contains 1.2 kg of paperclips, and one contains 0.5 kg of rubber bands. Which box has the greatest inertia?
Box 2 containing 1.2 kg of paperclips has the greatest mass, and thus the greatest inertia among the three boxes.
Inertia is a property of a body due to which it resists any change in its state of rest or motion.
When we talk about the greatest inertia among three boxes of the exact same size and shape, it is important to know that inertia is directly proportional to mass.
So, the box that has the greatest mass will have the greatest inertia.
Now, we have to find the box that has the greatest mass.
The mass of the boxes are as follows:
Box 1 containing 1.0 kg of pencils
Box 2 containing 1.2 kg of paperclips
Box 3 containing 0.5 kg of rubber bands
Therefore, Box 2 containing 1.2 kg of paperclips has the greatest mass, and thus the greatest inertia among the three boxes.
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The scores of a random sample of 8 students on a physics test are as follows: (a) Test to see if the sample mean is significantly different from 85 at the 0.05 level. Report the t and p values. Are these scores significantly different from 85 at the 0.05 level? A. Yes B. No C. Maybe
The given problem is asking for a test to see if the sample mean is significantly different from 85 at the 0.05 level. To solve the problem, we can use the following formula:$$t = \frac{\bar{x} - \mu}{\frac{s}{\sqrt{n}}}$$where$\bar{x}$ = sample mean$\mu$ = population mean$s$ = sample standard deviation$n
$ = sample sizeTo calculate the t-value, we need to calculate the sample mean and the sample standard deviation. The sample mean is calculated as follows:$$\bar{x} = \frac{\sum_{i=1}^{n} x_i}{n}$$where $x_i$ is the score of the $i$th student and $n$ is the sample size.
Using the given data, we get:$$\bar
{x} = \frac{78+89+67+85+90+83+81+79}{8}
= 81.125$$The sample standard deviation is calculated as follows:$$
s = \sqrt{\frac{\sum_{i=1}^{n} (x_i - \bar{x})^2}{n-1}}$$Using the given data, we get:$$
s = \sqrt{\frac{(78-81.125)^2+(89-81.125)^2+(67-81.125)^2+(85-81.125)^2+(90-81.125)^2+(83-81.125)^2+(81-81.125)^2+(79-81.125)^2}{8-1}}
= 7.791$$Now we can calculate the t-value as follows:$$
t = \frac{\bar{x} - \mu}{\frac{s}
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How should i explain 37.287-15=22.287
Answer:
22.287
Explanation:
This is because 15 is a whole number.
It is also 15.000
37.287
-15.000\(\\\)
22.287
(5 3/8+4.625)x(-1.8+4 1/4) x 1/8
Answer: 3.0625 would be the answer you just have to put it in a calculator.
Which statement best represents the distance on a number line between -14 and -5?
Answer:
C my dude. have a merry christmassss
Answer:
A
Step-by-step explanation:
Both are negative, and largest is always first.
Emika has a monthly budget for her cell phone bill.
Last month she spent 120% of her budget, and the bill
was $60.
What is Emika's monthly budget?
Emika's monthly budget is $60.
A percentage can be described as the fraction of a number multiplied by 100. The sign used to represent percentages is %.
Let Emika's cell phone bill budget be represented with x.
In order to determine his monthly budget, divide $60 by 120%
x = $60 / 120%
x = $60 / 1.20
x = $50
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What u have to do: rename ads fractions with common denominators and compare by using < or >
Problem: 5/8 ⬜️ 3/4
Answer:
<
Step-by-step explanation:
First, let's find common denominators:
Multiply 3/4 by 2.
Product is 6/8.
Next, let's compare both fractions:
5/8 ? 6/8
5/8 is less than 6/8.
Therefore 5/8 < 6/8.
At a high school, the probability that a student is a senior is 0.25. The
probability that a student plays a sport is 0.20, The probability that a student
IS a senior and plays a sport is 0.08,
What is the probability that a randomly selected student plays a sport, given
that the student is a senior?
A. 0.17
B. 0.08
C. 0.32
D. 0.25
Answer:
B) 0.08
Step-by-step explanation:
because it says the probability of them being a senior and playing a sport is 0.08.
If x = √3 − √2 , find the value of ( −1/x)root 2
hello
\(\dfrac{-1}{x}\sqrt{2}=\dfrac{-\sqrt{2}}{\sqrt{3}-\sqrt{2}}=\dfrac{-\sqrt{2}(\sqrt{3}+\sqrt{2})}{(\sqrt{3}-\sqrt{2})(\sqrt{3}+\sqrt{2})}\\\\=\dfrac{-\sqrt{2}(\sqrt{3}+\sqrt{2})}{3-2}\\\\=-\sqrt{6}-2\)
hope this helps
PLS HELP ME WITH THIS QUESTION, IM LITERALLY SO FRUSTRATED PLSSSS, WILL MARK BRAINEST, AND PLS EXPLAIN HOW U GOT THE ANSWER PLS PLS PLS!!!!!!
Answer:
64:1
It doubles every 10 minutes, so it multiplies by two 6 times in an hour. 1x2x2x2x2x2x2 = 64
20.) Lines m and n cross to form Z1, 22, 23, and 24, where m 1 = 50. Z1 and /4 are supplementary. m L
m <4. What is m /2?
The measure of m∠2 is given as 130
How to solve for the angleSince ∠1 and ∠4 are supplementary, their sum equals 180°:
m∠4 = 180° - m∠1
m∠4 = 180° - 50°
m∠4 = 130°
Now, we need to find m∠2. Since lines m and n cross, forming vertical angles, m∠1 is vertical to m∠3 and m∠2 is vertical to m∠4. Vertical angles are equal, so:
m∠2 = m∠4
m∠2 = 130°
Thus, m∠2 is 130°.
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Evaluate the function
Answer:
92
Step-by-step explanation:
plug -4 into the function
3(-4)²-10(-4)+4
48+40+4
92
Answer:
92
Step-by-step explanation:
f(-4)=3(-4)^2-10(-4)+4
=3(16)-10(-4)+4
=48+40+4
=92
what percentage of persons who lose weight are able to maintain it for more than a year?
Answer: 20%
Step-by-step explanation:
An object of height 2.8 cm is placed 5.0 cm in front of a converging lens of focal length 20 cm and observed from the other side. Where and how large is the image?
The image is located 6.7 cm behind the lens, and is 3.7 cm tall (1.34 times the height of the object).
Using the thin lens equation, we can find the position of the image formed by the lens:
1/f = 1/d0 + 1/di
where f is the focal length of the lens, d0 is the object distance (the distance between the object and the lens), and di is the image distance (the distance between the lens and the image).
Substituting the given values, we get:
1/20 = 1/5 + 1/di
Solving for di, we get:
di = 6.7 cm
This tells us that the image is formed 6.7 cm behind the lens.
To find the height of the image, we can use the magnification equation:
m = -di/d0
where m is the magnification (negative for an inverted image).
Substituting the given values, we get:
m = -(6.7 cm)/(5.0 cm) = -1.34
This tells us that the image is 1.34 times the size of the object, and is inverted.
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The negative sign indicates an inverted image. Thus, the image formed is located 8.0 cm from the lens and has a height of 1.6 times that of the object, making it 4.48 cm in height.
In this scenario, an object with a height of 2.8 cm is positioned 5.0 cm in front of a converging lens with a focal length of 20 cm. To determine the location and size of the image formed by the lens, we can use the lens formula and magnification formula.
The lens formula states that 1/f = 1/v - 1/u, where f is the focal length, v is the image distance, and u is the object distance. Substituting the given values into the lens formula, we find:
1/20 = 1/v - 1/(-5.0)
Simplifying this equation yields:
1/v = 1/20 + 1/5.0
Solving for v, we obtain:
v = 8.0 cm
The positive value indicates that the image is formed on the opposite side of the lens. The magnification formula, M = -v/u, allows us to calculate the magnification of the image:
M = -8.0/-5.0 = 1.6
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The volume of the given prism is 192 cubic units what is the volume of rectangular pyramid
The dimensions of the rectangular pyramid itself or the relationship between the prism and the pyramid (for example, if the pyramid is a component of the prism).
The volume of a rectangular pyramid can be expressed as (1/3)Bh, where B is the area of the base and h is the height. To find the volume of the rectangular pyramid, we need to know the dimensions of its base and height. However, the given information only provides the volume of a prism, which is not necessarily related to the pyramid. Without additional information, we cannot determine the volume of the rectangular pyramid. We would need to know either the dimensions of the rectangular pyramid itself or the relationship between the prism and the pyramid (for example, if the pyramid is a component of the prism).
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describe the shape of the cross section formed by the intersection of the plane and the solid
Answer:
What are the Answers?
Step-by-step explanation:
Rectangle is the shape of the cross section formed by the intersection of the plane and the solid.
If a plane intersects a cylinder in a perpendicular manner, such that the plane is parallel to one of the bases of the cylinder, the resulting cross-section will be a rectangle.
The rectangle's dimensions will depend on the dimensions of the cylinder and the specific position of the plane within the cylinder.
The length of the rectangle will be equal to the circumference of the cylinder, and the width will be equal to the height or the diameter of the cylinder.
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The height of the probability density function f(x) of the uniform distribution defined on the interval [a, b] is 1/(a-b). True False
The statement "The height of the probability density function f(x) of the uniform distribution defined on the interval [a, b] is 1/(a-b)" is False.
In a uniform distribution, the probability density function (PDF) is constant within the interval [a, b]. The height of the PDF represents the density of the probability distribution at any given point within the interval. Since the PDF is constant, the height remains the same throughout the interval.
To determine the height of the PDF, we need to consider the interval length. In a uniform distribution defined on the interval [a, b], the height of the PDF is 1/(b - a) for the PDF to integrate to 1 over the entire interval. This means that the total area under the PDF curve is equal to 1, representing the total probability within the interval [a, b].
Therefore, the correct statement is that the height of the probability density function f(x) of the uniform distribution defined on the interval [a, b] is not 1/(a - b), but rather it is a constant value necessary for the PDF to integrate to 1 over the interval, i.e., 1/(b - a).
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Peyton wanted to buy a new game. The game costs $65.00 before sales tax. If the sales tax is 8%, how much will she pay for the game?
Answer:
73
Step-by-step explanation:
lori jeffrey is a successful sales representative for a major publisher of college textbooks. historically, lori obtains a book adoption on of her sales calls. viewing her sales calls for one month as a sample of all possible sales calls, assume that a statistical analysis of the data yields a standard error of the proportion of . use the z-table. a. how large was the sample used in this analysis? that is, how many sales calls did lori make during the month?
The sample size used in the analysis was 300 sales calls for the given standard error.
What is standard error?The standard error (SE) is a statistical sample population's approximate standard deviation. The difference between the population's computed mean and one that is widely regarded as correct is described by the standard error. The standard error tends to be reduced the more data points included in the mean computations.
Given that, Lori obtains a book adoption on 20%, and the proportion of 0.400.
The Standard error is given as:
SE = √[p(1-p)/n]
Rearranging for n we have:
n = p(1-p)/(SE²)
n = 0.20(1-0.20)/(0.0400)²
n = 300.25
Hence, the sample size used in the analysis was 300 sales calls.
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The complete question is:
Which of the following could be a real-world description of 5x − 18?
$18 in addition to the cost of 5 hot dog combos
The cost of 18 people splitting 5 hot dog combos
The cost of hot dog combos less an $18 coupon split by 5 people
$18 less than the cost of 5 hot dog combos
Answer:
$18 less than the cost of 5 hot dog combos
Step-by-step explanation:
First, we see from the minus sign that this will be subtraction. PEMDAS (order of operations) says we do the multiplication first, then the subtraction.
Select the correct answers from multiple drop-downs for the differential equation x2dx2d2y−3xdxdy+3y=0. Verify that the functions x and x3 are solutions of the above differential equation. (a) A Wronskian is formed to check if these solutions are linearly independent. What is the value of the Wronskian at x=2 ? (First find the Wronskian and then substitute x=2 in it.) Wronskian at x=2 is: (b) Represent the general solution of the above differential equation as a linear combination of the basis fuctions and solve for the scalars using initial conditions y(1)=0 and y′(1)=−2. Evaluate the particular solution at x=2 and select the correct value of y(2). y(2)=
The value of y(2) is -14.
(a) To verify if x and x^3 are solutions of the given differential equation, we need to find the Wronskian.
The Wronskian is given by W(x) = x^3 * (d/dx)(x) - x * (d/dx)(x^3). Simplifying this expression, we get W(x) = 3x^2 - 3x^2 = 0.
Substituting x = 2 into the Wronskian, we find W(2) = 3(2)^2 - 3(2)^2 = 0.
Therefore, the value of the Wronskian at x = 2 is 0.
(b) To find the general solution of the differential equation, we'll assume y(x) = C1*x + C2*x^3, where C1 and C2 are constants.
Taking the derivatives, we have y'(x) = C1 + 3*C2*x^2 and y''(x) = 6*C2*x. Substituting these derivatives into the differential equation, we get x^2*y''(x) - 3*x*y'(x) + 3y(x) = 0.
Plugging in the values, we get (6*C2*x) - 3*x*(C1 + 3*C2*x^2) + 3*(C1*x + C2*x^3) = 0. Simplifying this expression, we find that it holds true for any values of C1 and C2.
Hence, the general solution of the given differential equation is y(x) = C1*x + C2*x^3.
Using the initial conditions y(1) = 0 and y'(1) = -2, we can solve for the values of C1 and C2. Substituting x = 1 into the general solution, we get C1 + C2 = 0.
Differentiating the general solution and substituting x = 1, we get C1 + 3*C2 = -2. Solving these two equations simultaneously, we find C1 = 2 and C2 = -2.
Finally, plugging x = 2 into the particular solution, we get y(2) = 2*2 + (-2)*(2)^3 = 2 - 16 = -14.
Therefore, the value of y(2) is -14.
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