a 170-ml, 1.28-m solution of h2so4 is diluted to 3.27 l by the addition of more solvent. determine the molarity of the solution after the dilution.

450 grams of water are formed when 250g of ethane combusts with 300 g of oxygen.

Combustion, or burning, is a high-temperature exothermic redox chemical response among a fuel and an oxidant, generally atmospheric oxygen, that produces oxidized, frequently gaseous products, in a mixture termed as smoke.

calculation:-

C₂H₆ + 7/2O₂ => 2CO₂ + 3H₂O

30 gram of ethane produce = 54 gram of water

250 gram of ethane produces  = 54/30 × 250

                                                     = 450 grams of water  

Combustion, a chemical reaction between materials, commonly consisting of oxygen and typically observed by way of the generation of heat and light in the form of flame. Combustion is the clinical phrase that burns. throughout a combustion response, the fabric reacts with oxygen from the air and contributes energy to the surroundings as light and warmth. the products of the reaction to combustion are referred to as oxides.

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Answer: The molecular formula will be \(C_6H_6O\)

Explanation:

Molecular formula is the chemical formula which depicts the actual number of atoms of each element present in the compound.  

Empirical formula is the simplest chemical formula which depicts the whole number of atoms of each element present in the compound.

The empirical formula is \(C_6H_6O\)

The empirical weight of \(C_6H_6O\) = 6(12)+6(1)+1(16) = 94 g.

The molecular weight = \(2\times \text{vapour density}=2\times 47=94\)

Now we have to calculate the molecular formula.

\(n=\frac{\text{Molecular weight}}{\text{Equivalent weight}}=\frac{94}{94}=1\)

The molecular formula will be=\(1\times C_6H_6O=C_6H_6O\)

Answer: should be c. clouds :)

Explanation: condensation is the change of water to a gaseous form. it generally occurs in the atmosphere when warm air rises, cools, and loses its capacity to hold the water vapor. excess water vapor condenses to form cloud droplets.

Answer: clouds

Explanation: theyre air and water

The amount of heat released is 45.89kj.

Heat of formation is the amount of heat absorbed or released by a mole of elements during chemical reaction.

The process involved in the reaction are

1.H20(314k)

2. H20 in solid form at 263k

Q= [m×Cpl ×Tfinal -Tinitial) + ∆H fussion

Q= amount of heat released = ?

m = mass of water = 27 g

cp(l) = specific heat of liquid water = 4.184 J/gk

Cp(s) = specific heat of solid water = 2.093 J/gk

∆H fussion = enthalpy change for fusion = 40.7 KJ/mole = 40700 J/mole.

Therefore, Q= 27 × 4.184j/gk × (314-2173k) + 40700j + (27g × 2.093j/gk ×273-263k).

Q = 45896.798 J

Therefore, the amount of heat released is 45.89 KJ.

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Answer:

q1= 4.63 KJ

q2= 61.1 KJ

q3= .565 KJ

q4= -66.3 KJ

Explanation:

The person above is kinda confusing so here.

Answer:

The pH scale measures whether there is more hydronium or hydroxide in a solution. In other words, it tells us how basic or acidic the solution is. A lower pH means something is more acidic, also known as a stronger acid. A higher pH means it is more alkaline or a stronger base.

The cycle of citric acid Hydrogen atoms are transported to FAD during the conversion of succinate to fumarate. This process is catalyzed by a succinate dehydrogenase enzyme.

During the process of succinate dehydrogenation, succinate is oxidized to fumarate by losing electrons, which are transferred to FAD, reducing it to FADH2. This transfer of electrons from succinate to FAD is an oxidation-reduction reaction, also known as redox reaction. The energy released during this reaction is harnessed to generate ATP, which is an important energy currency for the cell. Succinate dehydrogenase is an enzyme complex that contains multiple subunits and cofactors, including flavin adenine dinucleotide (FAD) and iron-sulfur clusters. It is located in the inner mitochondrial membrane, which allows it to transfer electrons to the electron transport chain, leading to the production of ATP. It's important to note that the citric acid cycle is a crucial metabolic pathway that takes place in the mitochondria of eukaryotic cells, and it is also known as the TCA cycle or Krebs cycle. The cycle is a series of chemical reactions that converts acetyl-CoA, derived from carbohydrates, fats, and proteins, into carbon dioxide and water, releasing energy in the form of ATP, hydrogen atoms other high-energy molecules.

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The main difference between corrosion and rust is that corrosion occurs as a result of the chemical influence and it affects a lot of materials whereas rusting is only accelerated by certain chemicals and usually affects iron substances

Hopes this helps :)

Answer:

1). In the periodic table as suggested by Mendeleev, elements were

the periodic table as suggested by Mendeleev, elements werearranged in the order of increasing atomic number.

--> T

2). Sodium (Z=11) is a member of a group called alkaline earth

Sodium (Z=11) is a member of a group called alkaline earthmetals.

--> T

3). Elements to the extreme right of the periodic table are metals.

--> F

They are non-metals .

4). Metalloids have properties of metals and non-metals.

--> T

Answer:

first identify the cation and write down its symbol and charge. Then, identify the anion and write down its symbol and charge.

Explanation:

For I₂ under the harmonic oscillator approximation at 300 K, the ratio of molecules in the first excited state (n=1) to the ground state (n=0) can be calculated using the Boltzmann distribution equation. The vibrational energy levels are assumed to be equally spaced, and the proportion of molecules in the first excited state compared to the ground state can be determined.

Additionally, the temperature at which the population in the first excited state is half of that in the ground state can be found by setting up an equation based on the Boltzmann distribution.

The ratio of molecules in the first excited state to the ground state for I₂ at 300 K using the harmonic oscillator approximation, we can use the Boltzmann distribution equation. The energy levels of a harmonic oscillator are given by E = (n + 1/2)hν, where n is the vibrational quantum number, h is Planck's constant, and ν is the vibrational frequency.

a) Ratio of molecules in the first excited state to the ground state:

Since the energy levels are equally spaced, the energy difference between adjacent levels is ΔE = hν. Using the formula ΔE = √(k/μ), where k is the force constant and μ is the reduced mass, we can calculate the vibrational frequency (ν) for I₂.

μ = m1 * m2 / (m1 + m2)  (reduced mass equation)

Plugging in the mass of iodine (I) as 126.9 amu and applying the reduced mass equation, we can find μ.

Once we have ν, we can calculate the energy difference (ΔE) and determine the ratio of molecules in the first excited state (n=1) to the ground state (n=0) using the Boltzmann distribution equation.

b) Temperature at which the population in the first excited state is half of that in the ground state:

To find this temperature, we can set up an equation where the ratio of molecules in the first excited state (n=1) to the ground state (n=0) is 1:2. We can solve for the temperature (T) using the Boltzmann distribution equation.

With the given force constant (k=170 N/m) and the calculated vibrational frequency (ν), we can determine the temperature at which the population in the first excited state will be half of that in the ground state.

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Answer:

A covalent bond is a chemical bond that involves the sharing of electron pairs between atoms. These electron pairs are known as shared pairs or bonding pairs, and the stable balance of attractive and repulsive forces between atoms, when they share electrons, is known as covalent bonding.

Explanation:

hope it helps, please mark as brainliest

Answer:

I prob can bc I'm a bad b*tch

lol

Answer:

Slytherine

Explanation:

I hope you have a wonderful rest of your day!!!! :)

Option (d), P=ATC=MR=MC, accurately represents the long-run equilibrium condition for perfect competition, reflecting the balance between price and cost for firms operating in a competitive market.

The long-run equilibrium condition for perfect competition is that price (P) is equal to average total cost (ATC), which is also equal to marginal cost (MC), and marginal revenue (MR).

Option (d), P=ATC=MR=MC, best represents the long-run equilibrium condition for perfect competition. In perfect competition, firms operate at the minimum point of their average total cost curve, where price equals both average total cost and marginal cost. This condition ensures that firms are earning zero economic profit and are producing at an efficient level.

In the long run, if firms are earning economic profit, new firms will enter the market, increasing competition and driving prices down. Conversely, if firms are experiencing losses, some firms may exit the market, reducing competition and causing prices to rise. This process continues until firms reach a state where price equals average total cost, marginal cost, and marginal revenue, ensuring a long-run equilibrium.

Therefore, option (d), P=ATC=MR=MC, accurately represents the long-run equilibrium condition for perfect competition, reflecting the balance between price and cost for firms operating in a competitive market.

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Answer:

List 4 functions of proteins.

1.Growth and Maintenance.

2.Balances Fluids.

3.Bolsters Immune Health.

4.Transports and Stores Nutrients.

If the specific rotation of your isolated sample is -20° and the literature value for the single (S)-enantiomer is -40°, it can be concluded that the resolution was only partially successful in separating the enantiomers.

The specific rotation is a measure of the optical activity of a compound, which indicates the extent to which a compound rotates the plane of polarized light. The sign and magnitude of the specific rotation are used to determine the absolute configuration (R or S) of a chiral compound. To check the success of the resolution:

1. Compare the specific rotation of your isolated sample (-20°) to the literature value for the single (S)-enantiomer (-40°).
2. Since the isolated sample's specific rotation is half of the literature value, it suggests that the sample likely contains a 50:50 mixture of the (S)-enantiomer and its mirror image, the (R)-enantiomer.
3. This indicates that your resolution was partially successful, as it did not completely separate the enantiomers.

Therefore, further optimization of the resolution method might be necessary to achieve a more successful separation of the enantiomers.

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Answer:

95.2 - 40.8 = 54.4 g of oxygen

number of moles = mass (g)/ Mr

no. of moles of carbon = 40.8/12 = 3.4

no. of moles of oxygen = 3.4

divide both by smallest value which is 3.4 and you’ll get 1 mole of carbon and 1 mole of oxygen therefore the empirical formula is CO

Explanation:

hope this helps :)

The empirical formula will be CO.

The simplest entire numeric ratio of elements in a chemical molecule would be its empirical formula.

Calculation of empirical formula

Mass of carbon = 95.2 g

Mass of oxygen = 95.2 - 40.8 = 54.4 g of oxygen

Moles can be determined by using the formula:

number of moles = mass (g)/ Mr

no. of moles of carbon = 40.8/12 = 3.4

no. of moles of oxygen = 3.4

The empirical formula would be CO by dividing mostly by the smallest value, which would be 3.4. This will give you 1 mole of carbon but also 1 mole of oxygen.

Therefore, the empirical formula will be CO.

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The temperature needed for 41 grams of O₂ to expand to a volume of 2L under a pressure of 1 atm is approximately 19.023 Kelvin.

We know that the ideal gas equation is:

PV = nRT ......(i)

where P ⇒ pressure

V ⇒ volume of the gas

n ⇒ number of moles of the gas

T ⇒ temperature in Kelvin

R ⇒ ideal gas constant = 0.082057 (L·atm/(mol·K))

Now, as per the question:

Mass of O₂ = 41 grams

The volume of expanded gas, V = 2 L

Pressure, P = 1 atm

We need to determine the temperature needed for the gas to expand to 2 L.

For that, we need to calculate the number of moles of O₂ gas first.

Since,

no. of moles = mass of the gas / molar mass of the gas

(∵ molar mass of O₂ = 32 g)

moles = 41 g / 32 g/mol

moles ≈ 1.28125 mol

Now,  to solve for temperature (T),

The ideal gas equation can be written as:

\(T=\frac{PV}{nR}\)  ......(ii)

Now, substituting the given values in the equation (ii):

\(T = \frac{(1)*(2)}{(1.28125)*(0.082057)} \frac{(atm).(L)}{(mole).(L.atm/mol.K)}\)

\(T = \frac{2}{0.105136} \frac{atm.L}{(L.atm)/K}\)

T ≈ 19.023 K

Thus, the temperature needed for 41 grams of O₂ to expand to a volume of 2 L under a pressure of 1 atm is approximately 19.023 Kelvin.

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327.8 g of NaCl react with 275.0 g of H₂SO4, and 873.6 g of Na₂SO4 are produced from 12.3 mol of HCl.

First, let's balance the chemical equation:

2NaCl + H₂SO4 → 2HCl + Na₂SO4

a) From the balanced equation, we can see that the molar ratio of NaCl to H₂SO4 is 2:1. We can use this ratio to find the moles of NaCl that react with 275.0 g of H₂SO4:

molar mass of H₂SO4 = 98.08 g/mol

moles of H₂SO4 = 275.0 g / 98.08 g/mol = 2.802 mol

moles of NaCl = 2.802 mol H₂SO4 × 2 mol NaCl / 1 mol H₂SO4 = 5.604 mol NaCl

To find the mass of NaCl, we can use its molar mass:

molar mass of NaCl = 58.44 g/mol

mass of NaCl = 5.604 mol NaCl × 58.44 g/mol = 327.8 g

Therefore, 327.8 g of NaCl react with 275.0 g of H₂SO4.

b) From the balanced equation, we can see that the molar ratio of HCl to Na₂SO4 is 2:1. We can use this ratio to find the moles of Na₂SO4 that are produced from 12.3 mol of HCl:

moles of HCl = 12.3 mol

moles of Na₂SO4 = 12.3 mol HCl × 1 mol Na₂SO4 / 2 mol HCl = 6.15 mol Na₂SO4

To find the mass of Na₂SO4, we can use its molar mass:

molar mass of Na₂SO4 = 142.04 g/mol

mass of Na₂SO4 = 6.15 mol Na₂SO4 × 142.04 g/mol = 873.6 g

Therefore, 873.6 g of Na₂SO4 are produced from 12.3 mol of HCl.

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Answer:

I think that temperature will be cut in half.

When volume increases, pressure decreases. As pressure decreases, temperature decreases. So if you double volume, pressure is halved and so will the temperature. I'm new to this, but I think that's the answer . Tell me if I'm right good luck!

Answer:

this question is so hard

Explanation:

it was in my exam and I'm still trying to figure out if I should do calculation

or just answer it with words

The mass of the other product, water, formed in the reaction is 72.06 g

From the question, we are to determine the mass of water formed

First, we will write the balanced chemical equation for the reaction,

The balanced chemical equation for the reaction is

C₃H₈ + 5O₂ → 3CO₂ + 4H₂O

This means

1 mole of propane reacts with 5 moles of O₂ to produce 3 moles of CO₂ and 4 moles of H₂O

Now, we will determine the number of moles of CO₂ formed.

From the formula,

\(Number\ of\ moles = \frac{Mass}{Molar\ mass}\)

Molar mass of CO₂ = 44.01 g/mol

Then,

Number of moles of CO₂ formed = \(\frac{132}{44.01}\)

Number of moles of CO₂ formed = 3 moles

Considering the balanced chemical equation,

Since 3 moles of CO₂ was formed, then 4 moles of H₂O will be formed.

Now, for the mass of H₂O formed

Using the formula,

Mass = Number of moles × Molar mass

Molar mass of H₂O = 18.015 g/mol

Therefore,

Mass of water formed = 4 × 18.015

Mass of water formed = 72.06 g

Hence, the mass of the other product, water, formed in the reaction is 72.06 g.

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When the kidneys detect a chronic decrease in oxygen, they initiate a series of physiological responses to restore oxygen balance and maintain homeostasis.

The primary mechanism by which the kidneys respond to low oxygen levels is through the release of a hormone called erythropoietin (EPO). EPO stimulates the production of red blood cells in the bone marrow, increasing the oxygen-carrying capacity of the blood.

In response to chronic hypoxia, the kidneys produce and release more EPO, which enters the bloodstream and travels to the bone marrow. EPO then stimulates the differentiation and proliferation of red blood cell precursors, leading to an increased production of mature red blood cells. This response helps to enhance oxygen delivery to tissues and organs throughout the body.

Additionally, the kidneys play a role in regulating blood pressure. In situations of chronic hypoxia, the kidneys can activate the renin-angiotensin-aldosterone system (RAAS) to increase blood volume and improve tissue perfusion. This mechanism involves the release of renin, an enzyme that initiates a series of reactions leading to the production of angiotensin II, a potent vasoconstrictor. Angiotensin II stimulates the release of aldosterone, which promotes sodium and water retention, leading to increased blood volume and elevated blood pressure.

Overall, the kidneys respond to chronic hypoxia by increasing erythropoiesis through the release of EPO and by activating the RAAS to regulate blood pressure and optimize tissue perfusion. These responses help to restore oxygen balance and ensure adequate oxygen supply to the body's tissues and organs.

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Given 5 grams of H₂, 80 grams of CH₄ are produced by From the equation, we can see that for every 2 moles of CH₄, 1 mole of H2 is consumed.

To determine the amount of CH₄ produced from 5 grams of H₂, we need to consider the balanced chemical equation for the reaction between H₂ and CH₄. From the equation stoichiometry, we can calculate the stoichiometric ratio between H₂ and CH₄ and use it to find the mass of CH₄ produced.

The balanced chemical equation for the reaction between H₂ and CH₄ is:

H₂ + 2CH₄ → 4H₂ + C

To find the mass of CH₄ produced, we need to convert the mass of H2 to moles using its molar mass (2 g/mol) and then use the stoichiometric ratio to calculate the moles of CH₄ produced. The molar mass of CH₄ is 16 g/mol.

First, we convert the mass of H₂ to moles:

5 g H₂ * (1 mol H2 / 2 g H₂) = 2.5 mol H2

Since the stoichiometric ratio is 1:2 for H2 to CH₄, we have:

2.5 mol H₂ * (2 mol CH₄ / 1 mol H₂) = 5 mol CH₄

Finally, we convert the moles of CH₄ to grams:

5 mol CH₄ * (16 g CH₄ / 1 mol CH₄) = 80 g CH₄

Therefore, 5 grams of H₂ will produce 80 grams of CH₄.

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92.4 mL of 0.725 M HCl is required to neutralize 3.55 grams of sodium carbonate.

At the point when a corrosive responds with a base, they kill one another, and the subsequent item is a salt and water. For this situation, sodium carbonate (Na2CO3) is the base, and hydrochloric corrosive (HCl) is the corrosive. The response between them is as per the following:

2HCl(aq) + Na2CO3(aq) → 2NaCl(aq) + H2O(l) + CO2(g)

We are given the mass of sodium carbonate as 3.55 g, yet we really want to change it over completely to moles to decide how much corrosive expected to kill it. The molar mass of sodium carbonate is 105.99 g/mol, so:

3.55 g Na2CO3 × (1 mol Na2CO3/105.99 g Na2CO3) = 0.0335 mol Na2CO3

From the fair condition, we see that two moles of hydrochloric corrosive respond with one mole of sodium carbonate. In this manner, how much hydrochloric corrosive required is:

0.0335 mol Na2CO3 × (2 mol HCl/1 mol Na2CO3) = 0.0670 mol HCl

At last, we can utilize the molarity of the hydrochloric corrosive to decide the volume required:

0.0670 mol HCl × (1 L/0.725 mol HCl) = 0.0924 L = 92.4 mL

Consequently, 92.4 mL of 0.725 M HCl is expected to kill 3.55 grams of sodium carbonate.

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When \(CO_{2}\) and \(H_{2} CO_{3}\) are both horizontal lines, the rate of the forward reaction is the same as the rate of the reverse reaction. The reaction is occurring at equilibrium, with no net change in the concentrations of reactants and products over time.

When the concentration of carbon dioxide \(CO_{2}\) and the concentration of carbonic acid \(H_{2} CO_{3}\) are both horizontal lines, it indicates that their concentrations remain constant over time. In such a scenario, the rate of the forward reaction is the same as the rate of the reverse reaction. A horizontal line on a concentration-time graph suggests that the concentrations of the reactants and products are not changing, implying that the reaction has reached equilibrium. At equilibrium, the rate of the forward reaction equals the rate of the reverse reaction. This is a fundamental principle of chemical equilibrium, described by the principle of microscopic reversibility.

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Answer:

9

Explanation:

7 is neutral anything higher than 7 is a base anything lower than 7 is an acid.

Answer:They are less dense near the top of the atmosphere.

Explanation: