a 1.8-m3 rigid tank contains steam at 2208c. one-third of the volume is in the liquid phase and the rest is in the vapor form. determine (a) the pressure of the steam, (b) the quality of the saturated mixture, and (c) the density of the mixture.

Answer:

One mole of O₂ weighs 32 g

Explanation:

The computation in the question results in the production of 21 g of NF3.

Because it is the reactant that is totally consumed during the reaction, the limiting reactant specifies the maximum amount of product that can be created in a chemical process.

F2 molecular weight is 16.5 g/38 g/mol.

= 0.43 moles

N2 molecular weight is 16.5 g/28 g/mol.

= 0.59 moles

Now;

If 3 moles of F2 and 1 mole of N2 react,

N2 interacts with 0.59 moles at 0.59 * 3/1.

= 1.77 moles of F2

Thus F2 is the limiting reactant

2 moles of NF3 are created from 3 moles of F2.

When using 0.43 moles of F2, you get 0.43 * 2/3.

= 0.29 moles

NF3 mass generated is 0.29 moles * 71 g/mol.

= 21 g

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When solid sodium nitrite (NaNO₂) is added to water (H₂O), it undergoes a dissociation reaction to form ions. The reaction can be represented as follows:

NaNO₂ (s) + H₂O (l) → Na⁺ (aq) + NO₂⁻ (aq)

In this reaction, the solid sodium nitrite dissociates into its respective ions: sodium cations (Na⁺) and nitrite anions (NO₂⁻). The water molecules surround the ions, separating them and allowing them to move freely in the solution.

The resulting solution contains sodium cations and nitrite anions, both of which are capable of conducting electric current.

This behavior is characteristic of a strong electrolyte, where the compound readily dissociates into ions in water, facilitating the flow of electric charges.

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Answer:

The change from a liquid phase to a gaseous phase occurs when the vapor pressure of the liquid is equal to the atmospheric pressure exerted on the liquid.

Explanation:

Boiling is a physical change and molecules are not chemically altered during the process.

The molarity of the silver nitrate solution is approximately 0.382 M.

To calculate the molarity of the silver nitrate solution, we need to determine the number of moles of AgNO₃ present in the solution and then divide it by the volume of the solution in liters.

Given;

Mass of AgNO₃ = 65.00 grams

Volume of solution = 3.0 L

First, we need to calculate the number of moles of AgNO₃ using the molar mass of AgNO₃, which is the sum of the atomic masses of its constituent elements.

Molar mass of AgNO₃;

Ag = 107.87 g/mol

N = 14.01 g/mol

O = 16.00 g/mol (x3, since there are three oxygen atoms in AgNO₃)

Molar mass of AgNO₃ = 107.87 + 14.01 + (16.00 × 3) = 169.87 g/mol

Next, we calculate the number of moles of AgNO₃;

moles of AgNO₃ = mass of AgNO₃ / molar mass of AgNO₃

moles of AgNO₃ = 65.00 g / 169.87 g/mol

Now, we divide the number of moles of AgNO₃ by the volume of the solution in liters to calculate the molarity;

Molarity (M) = moles of solute / volume of solution in liters

Molarity (M) = moles of AgNO₃ / 3.0 L

Substituting the calculated value for the moles of AgNO₃;

Molarity (M) = (65.00 g / 169.87 g/mol) / 3.0 L

Simplifying and calculating this expression, we find;

Molarity (M) ≈ 0.382 M

Therefore, the molarity of the silver nitrate solution is approximately 0.382 M.

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Using the Henderson-Hasselbalch equation, we find that to prepare a pH 10.0 buffer solution using 1.0 M ammonia (NH3) and 1.0 M ammonium chloride (NH4Cl), add 25 mL of the ammonium chloride solution to a 50 mL beaker. No volume of the ammonia solution is required.

The Henderson-Hasselbalch equation is :

pH = pKa + log ([A-]/[HA])

Where:

pH = desired pH (10.0 in this case)

pKa = pKa value of the conjugate acid/base pair (ammonium ion, NH4+)

[A-] = concentration of the base (ammonia, NH3)

[HA] = concentration of the acid (ammonium chloride, NH4Cl)

First, we calculate the ratio of [A-] to [HA] using the Henderson-Hasselbalch equation:

10.0 = 9.245 + log ([A-]/[HA])

Rearranging the equation:

log ([A-]/[HA]) = 10.0 - 9.245

log ([A-]/[HA]) = 0.755

Now, we convert the logarithmic expression back into the ratio:

[A-]/[HA] = 10^(0.755)

[A-]/[HA] = 5.623

Since we want to prepare a 25 mL buffer solution, we set up the following equation based on the molarities of the solutions:

(1.0 M ammonia)(V1) + (1.0 M ammonium chloride)(V2) = (5.623)(1.0 M ammonia)(V1) + (1.0 M ammonium chloride)(V2) = (25 mL)(1.0 M)

Now, we solve this equation to find the volumes of ammonia and ammonium chloride required:

5.623V1 + V2 = 25

To simplify the calculation, we assume V2 = x:

5.623V1 + x = 25

We know that V1 + V2 = 25 mL, so we rewrite the equation as:

5.623V1 + (25 - V1) = 25

Simplifying further:

4.623V1 = 0

V1 = 0 mL

Since V1 is zero, it means we don't need to add any volume of the 1.0 M ammonia solution.

Now, let's calculate the volume of the 1.0 M ammonium chloride solution (V2):

V2 = 25 - V1

V2 = 25 - 0

V2 = 25 mL

Therefore, to prepare a pH 10.0 buffer solution, you need to add 25 mL of the 1.0 M ammonium chloride solution (NH4Cl) to a 50 mL plastic beaker. No volume of the 1.0 M ammonia solution (NH3) is required in this case.

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C. Reducing the temperature, is the two changes would make this reaction reactant-favored 2H₂+O₂ 2H₂O + energy

To make the given reaction reactant-favored, we need to shift the equilibrium towards the left side, favoring the formation of reactants (H₂ and O₂) rather than products (H₂O). This can be achieved by considering the impact of pressure and temperature on the reaction.

A. Reducing the pressure:

Reducing the pressure would not favor the reactants. According to Le Chatelier's principle, decreasing the pressure will shift the equilibrium towards the side with a higher number of moles of gas. In this case, both sides of the reaction have the same number of moles of gas (two moles), so reducing the pressure will not have a significant effect.

B. Increasing the pressure:

Increasing the pressure would not favor the reactants either. Again, according to Le Chatelier's principle, increasing the pressure will shift the equilibrium towards the side with fewer moles of gas. As both sides have the same number of moles of gas, changing the pressure will not impact the equilibrium.

C. Reducing the temperature:

Reducing the temperature would favor the reactants. The reaction is exothermic (releases energy), and according to Le Chatelier's principle, decreasing the temperature favors the reaction that produces heat. Therefore, reducing the temperature would shift the equilibrium towards the reactants (H₂ and O₂) side.

D. Increasing the temperature:

Increasing the temperature would not favor the reactants. In an exothermic reaction, increasing the temperature would shift the equilibrium towards the products (H₂O) side to absorb the additional heat.

In conclusion, reducing the temperature (option C) would make the reaction reactant-favored, favoring the formation of H₂ and O₂ rather than H₂O. Therefore, Option C is correct.

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From Hess law, the missing enthalpy is −198 kJ.

The Hess law of constant heat summation is used to determine the heat absorbed or evolved in a reaction as a sum of the heat absorbed or evolved over a sequence of reactions.

Looking at the reactions as shown, the missing enthalpy can be obtained from the other two which will give us the value of −198 kJ.

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Answer:

b) −198 kJ

Explanation:

Answer:

0.75 M

Explanation:

M1 = 0.15 M

V1 = 125 mL or 0.125 L

M2 = Y

V2 = 25 mL or 0.025 L

0.15 M x 0.125 mL = Y x 0.025 L

Y =  0.15 M x 0.125 mL / 0.025 L

Cancel out the mL

Y = 0.01875M /  0.025 L

Y = 0.75M

Answer:

0.125 M

Explanation:

M₁V₁ = M₂V₂

125 mL / 1000 = 0.125 L = V₁

25 + 125 = 150 mL / 1000 = 0.150 L = V₂

0.15 M = M₁

M₁ × V₁ / V₂ = M₂

(0.15) × (0.125) / (0.150) = 0.125 M

0.125 M is the answer

molar mass of KHP ( C8H5O4K)= 8*12+5+4*16+39=204

( atomic weights : C=12, H=1, K=39 and O= 16)

moles of KHP= mass/molar mass =  1.513/204 =0.0074

The reaction between KHP and NaOH is

KHC8H4O4(aq) + NaOH(aq) => KNaC8H4O4(aq) + H2O(l)

1 mole of KHP requires 1 mole of NaOH;

moles of KHP=0.0074

moles of NaOH= 0.0074

concentration of NaOH= moles/ Volume in L, 1000ml= 1L, 14.8ml= 14.8/1000L=0.0148L

concentration of NaOH=0.0074/0.0148=0.5M

The molarity of NaOH is 0.5M

Molar Mass:

In chemistry, the molar mass of a compound is defined as the mass of a sample of that compound divided by the amount of substance. This is the number of moles of that sample measured in moles.

Molarity:

Molarity is used to describe the concentration of a solution. Molarity, also called molarity, is the number of moles of solute (dissolved substance) per liter of solution.

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Answer:

SO₄⁻² (aq)  +  Mg²⁺ (aq)  ⇄  MgSO₄ (s) ↓

Precipitation reaction

Explanation:

Mg²⁻ is one of the metals at group 2 in the Perodic Table. This group is called, the alkaline earth metals.

To make precipitate the Mg²⁺ we can use a salt of sulfate, either flouride or phosphate. Those are three salts that can precipitate this metal.

We use sodium as cathion so, first of all we dissociate them:

Na₂SO₄ (aq) →  2Na⁺  (aq)  +  SO₄⁻² (aq)

NaF (aq) →  Na⁺ (aq) +  F⁻ (aq)

Na₃PO₄ (aq) →  3Na⁺ (aq)  +  PO₄⁻³ (aq)

In all cases, the reaction is of the precipitation type and is conditioned by the Kps, the solubility product constant. Let's bond the anions with Mg²⁺.

SO₄⁻² (aq)  +  Mg²⁺ (aq)  ⇄  MgSO₄ (s) ↓    Kps

2F⁻ (aq)  +  Mg²⁺ (aq)  ⇄   MgF₂ (s) ↓      Kps

2PO₄⁻³ (aq)  +  3Mg²⁺ (aq)  ⇄  Mg₃PO₄ (s) ↓   Kps  

Answer:

Explained below.

Explanation:

First of all, the orbital path of electron is mostly parabolic in electric field.

In an electric field, electrons behave very similar to a projectile. Thus, Electrons have a parabolic path in an electric field simply because the speed of the electrons in a direction which is perpendicular to the electric field is constant since there is no force. Therefore, there will be no acceleration along that perpendicular direction. However there will be an acceleration that is constant in the direction of the electric field which makes it act in a similar manner to a projectile under gravity.

Answer:

4 I believe is false and 5 is D I think

Answer:

4.) A. (TRUE)

5.) B. (THE WEATHER AND CLIMATE)

Explanation:

I HOPE IT HELPS YOU;)

Answer:

Apparent magnitude

Explanation:

By definition, Apparent magnitude which is usually denoted by "m" is the measure of the brightness of a star or even other astronomical objects that are observed from Earth. Meanwhile the absolute magnitude is defined as the intrinsic luminosity emitted by a star or other astronomical objects.

Thus, apparent magnitude is correct.

Answer:

A

Explanation:

i did this and its right

the equilibrium constant for the given reaction at 298 K is 8.96 x 10^-7.

The equilibrium constant for the given reaction, CIO(g) + O2(g) → Cl(g) + O3(g), at 298 K can be determined using the Gibbs free energy of the reaction and the following equation:ΔG° = - RT lnK

where ΔG° is the standard Gibbs free energy change, R is the gas constant, T is the temperature in Kelvin, and K is the equilibrium constant.

The equation can be rearranged to solve for K:K = e^(-ΔG°/RT)where e is the natural logarithmic base, and all other variables are the same as in the previous equation.Substituting the given values,

we have:ΔG° = 34.5 kJ/molR = 8.314 J/(mol·K)T = 298 K

Using these values, we get:-

ΔG°/RT = (-34.5 × 10^3 J/mol) / (8.314 J/(mol·K) × 298 K)

= -13.19e^(-ΔG°/RT) = e^(-13.19) = 8.96 × 10^-7

Therefore, the equilibrium constant for the given reaction at 298 K is 8.96 x 10^-7.

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The chemical P2 refers to the diphosphorus molecule, which is a compound made up of two phosphorus atoms bonded together.

Diphosphorus, also known as P2, is a chemical compound composed of two phosphorus atoms covalently bonded together. It is a highly reactive and unstable molecule that is rarely encountered in its pure form. Diphosphorus is an allotrope of phosphorus, meaning it is a different structural form of the same element.

At room temperature, diphosphorus exists as a colorless, odorless gas with a molecular weight of 60.98 g/mol. It is highly reactive and can easily ignite when exposed to air, making it a fire and explosion hazard. Diphosphorus is also highly toxic and can cause severe burns and respiratory problems if inhaled.

Diphosphorus has a unique electronic structure with a triple bond between the two phosphorus atoms. This triple bond makes the molecule highly reactive and unstable, as it seeks to break apart and form more stable bonds with other atoms. As a result, diphosphorus is a useful starting material for the synthesis of other phosphorus-containing compounds.

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The mass of NaCl that can be produced from 9.8 moles of HCl is 572.712 g

2Na + 2HCl --> 2NaCl + H₂

From the balanced equation above,

2 moles of HCl reacted to produced 2 moles of NaCl.

Therefore,

9.8 moles of HCl will also react to produce 9.8 moles of NaCl

Mass = mole × molar mass

Mass of NaCl = 9.8 × 58.44

Mass of NaCl = 572.712 g

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0.5 moles of the mole fraction of vinyl chloride and vinylacetate in a co-polymer having a molecular weight of 10520 g/mol.

Given,

mass= 10,000 g/mol

DP= 200

mass of vinyl chloride = 62.5 g/mol

mass of vinyl acetate =  86 g/mol

Lets the mole fraction be X

required mole fraction be (1-x)

Mass of  vinyl chloride=62.5 x

Mass of  vinyl acetate =86(1-x)

mass of monomer = 62.5 x + 86 (1-x)  

weight of polymer = DP x Mass of monomer

= 10,000 =200(62.5 x + 86 - 86 x)

= 23.5 x = 36

x=0.5

Polymeric compounds which are built up of two different types of monomer units in their chain are called ―Copolymers or ―Mixed polymer polymers with three different types of nonnumeric units are sometimes called as ter-polymer.

Copolymers are further classified as alternating copolymers or statistically regular (where both repeating bunits are joined side by side) and random copolymers or statistically irregular (where there is no regularity in the joining of units of two different monomers.

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Answer:

This is false: Meiosis is what happens when body cells divide to form identical body cells.

Explanation:

Meiosis is what happens when body cells divide to form identical body cells

When conducting an experiment using hydrogen gas, you would expect the relationship between the number of moles and the volume of hydrogen to follow Avogadro's law. According to Avogadro's law, at constant temperature and pressure, equal volumes of gases contain an equal number of moles.

Since hydrogen is lighter than propane, it means that the same volume of hydrogen gas would have a higher number of moles compared to propane. For example, let's say you have a certain volume of propane gas and an equal volume of hydrogen gas. The hydrogen gas would contain a higher number of moles because it is lighter and occupies the same volume. This is because the molar mass of hydrogen is lower than that of propane.

In summary, the relationship between the number of moles and the volume of hydrogen gas would be that as the volume increases, the number of moles of hydrogen gas would also increase.

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Answer:

no

Explanation:

because

Answer:

Peroxide is a polyatomic ion consisting of two bonded oxygen atoms. This ion can form a compound with another atom,one of which is hydrogen Peroxide.

Typically two oxygen atoms make a neutral compound, which is oxygen gas. Peroxide can be written as 0-22

1/6 moles of fe2 (aq) reacted with the cr2o7 2-.

A redox couple's ability to reduce gets stronger with a larger H+ concentration, making the reduction process simpler. The presence of so many H+ ions facilitates the reduction reaction since the reducing element desires them throughout the reduction process.

By supposing that almost all bonds to the atoms in molecules are ionic, we may use the oxidation numbers that are assigned to them to detect redox processes. In a reaction, oxidation is shown by a rise in the number of oxidations, whereas reduction is indicated by a drop.

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A. The abundance of the 2nd isotope is 48.119%

B. The mass of the 2nd isotope is 108.905 amu

Let the 1st isotope be A

Let the 2nd isotope be B

A. Determination of the abundance of the 2nd isotope

Abundance of isotope A = 51.881%.

Abundance of B = 100 – A

Abundance of B = 100 – 51.881

B. Determination of the mass of the 2nd isotope

Atomic mass of silver = 107.868 amu.

Mass of 1st isotope (A) = 106.906 amu

Abundance of isotope A (A%) = 51.881%.

Abundance of isotope B (B%) = 48.119%

\(atomic \: mass = \frac{mass \: of \:A \times \:A\%}{100} + \frac{mass \: of \:B \times \:B\%}{100} \\ \\ 107.868 = \frac{106.906\times \ \: 51.881}{100} + \frac{mass \: of \:B \times \:48.119}{100} \\ \\ 107.868 = \: 55.464 + 0.48119 \times mass \: of \:B \\ \\ collect \: like \: terms \\ \\ 0.48119 \times mass \: of \:B = 107.868 - 55.464 \\ \\ divide \: both \: side \: by \: 0.48119 \\ \\ mass \: of \:B = \frac{107.868 - 55.464 }{0.48119} \\ \\ mass \: of \:B =108.905 \: amu \\ \\ \)

Therefore, the mass of the 2nd isotope is 108.905 amu

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