A 2 kg block slides down a 30 degrees incline as shown above with an acceleration of 2 m/s?
10°
Which of the following correctly indicates the magnitudes of the forces acting up and down the incline?

Answer:

Umm, where is the pic

Explanation:

Answer:

no attachment

Explanation:

Please add attachment so I can answer

The difference between the string's tension at the bottom of the circle and at the top of the circle is 2mg.

Given the mass of the ball is m

radius of circle = r and constant speed is maintained = v

At the top of the circle, ΣF = FT + mg = mv^2/r, where F is the force acting on the string, T is tension, m is mass and g is gravitational acceleration.

Here as the ball moves in circle it carries centripetal force = mv^2/r.

Then FT = mv^2/r – mg.

At the bottom of the circle, ΣF = FT – mg = mv^2/r, So

FT = mv^2/r + mg

By comparing these two equations we get:

The difference is (mv^2/r + mg) – (mv^2/r – mg) = 2mg.

Hence the  required difference is 2mg.

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There is a 2mg difference in string tension between the circle's bottom and top points.

the mass of the ball is m

radius of circle = r and constant speed is maintained = v

At the top of the circle, ΣF = FT + mg = mv^2/r, where F is the force acting on the string, T is tension, m is mass and g is gravitational acceleration.

Here as the ball moves in circle it carries centripetal force = mv^2/r.

Then FT = mv^2/r – mg.

At the bottom of the circle, ΣF = FT – mg = mv^2/r, So

FT = mv^2/r + mg

By comparing these two equations we get:

The difference is (mv^2/r + mg) – (mv^2/r – mg) = 2mg.

Hence the  required difference is 2mg.

When the centripetal force and the gravitational force are exactly equal at the peak of the swing, the minimum speed will occur. The tension would then be exactly zero, and the ball would hardly be able to keep rolling in a circle.

The weight of the body operates vertically downward while the centrifugal force acts vertically downward at the lowest position. As a result, the string's tension is at its highest. The weight of the body acts vertically downward and the centrifugal force acts vertically upward at the highest point.

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Answer:

A) vectors: veloicty, force

scalar:  speed, work

B)  t = 1.75 s,  C)   v = - 17 2 m / s

Explanation:

We answer each part separately

A) A vector magnitude has magnitude and direction instead a scalar magnitude has only magnitude

vector quantities: the speed of a car number is the magnitude and direction is where it goes

Force, the number is the magnitude and above that applies gives direction

Scalar magnitude: how quickly the number of the speedometer of the car

Temperature, work

B) I = 15 m height to the soil and get to calculate time = 0

        y = y₀ + v₀ t - ½ g t²

as the ball is loose its initial velocity is zero

       0 = 0 +0  - ½ g t²

       t = \(\sqrt{2y_o/g}\)

       t = \(\sqrt{2 \ 15/ 9.8}\)

       t = 1.75 s

C) the velocity to the reach the floor

      v = vo - g t

      v = 0 - g t

      v = - 9.8 1.74

       v = - 17 2 m / s

The negative signt iindicates that the speed goes down

The particle is moving toward the wall and is being deflected at the same time.

The time to reach the wall will be 18.4/7.2  =2.56 sec. The direction of the acceleration is not specified but since the ask for how high  we will assume it is upward. S=1/2 at^2  t= 2.56.

s = 0.5X 1.7 m/s 2 x 2.56*2.56 = 5.5 meters. Two velocities on x one way  the up velocity  is 1.7*2.56 = 4.3 m/s or the arctan of  4.3/7.2 =30.8 degrees.

Vertical gardens, sometimes known as "green walls," are large-scale plant arrangements that are affixed to wall-mounted structures. They serve as an effective ornamental element while also being quite practical because they improve the indoor air quality and the comfort level of the surrounding area.

Therefore, The particle is moving toward the wall and is being deflected at the same time.

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Answer 55.5mph

explanation

Answer:

The value is  \(k = 0.7239\)

Explanation:

From the question we are told that

   The angle between the transmission axes of the polarizer \(\theta = 42^o\)

Gnerally the intensity light emerging from the first polarizer is  

             \(I_1 = \frac{I_o }{2}\)

Generally according to  malus's law the intensity of light emerging from the second polarizer is mathematically represented as

                    \(I_2 = I_1 * cos^{2} (\theta )\)

=>                  \(I_2 = \frac{I_o }{ 2} * cos^{2} (42 )\)

=>                  \(I_2 = 0.2761 I_o\)

Generally  the incident intensity is BLOCKED by the polarizers is mathematically represented as

           \(I = I_o - I_2\)

=>        \(I = I_o - 0.2761 I_o\)

=>      \(I = 0.7239 \ I_o\)

Hence the  fraction of the incident intensity is BLOCKED by the polarizers is  

      \(k = 0.7239\)

Answer:

-67 m/s

Explanation:

We are given that

Mass of ball,m=0.4 kg

Initial speed,u=14 m/s

Impulse,I=-32.4 N-s

Time,t=27 ms=\(27\times 10^{-3} s\)

We have to find the mass's velocity in the x- direction.

We know that

\(Impulse=mv-mu\)

Substitute the values

\(-32.4=0.4v-0.4(14)\)

\(-32.4+0.4(14)=0.4 v\)

\(-26.8=0.4v\)

\(v=\frac{-26.8}{0.4}=-67m/s\)

Answer:

Answer d) Lab B's reading is less precise than Lab A's

Explanation:

Recall that accuracy is a measure of how close to the actual physical quantity the experiment leads to. In this case, we don't know what the true age is,so we cannot tell which reading is more accurate.

But we can tell which reading is more precise given the value of their reported errors. Since Lab A shows a smaller error in years (+/- 20 years versus 30 years), as well as a smaller percent error (3.9% versus 5.1%), we can say that Lab's A reading is more precise than Lab B's reading.

This agrees with answer labeled d).

Dimentional analysis is very important in physics, because it allows finding errors in equations. We find that the following true equations

a) F= m a

b) x = 2 a t²

c) E = \(\frac{1}{2} }\ m \ a \ x\)

d) E = m a x

The fundamental units in mechanics are;

the length [L] whose unit is the meter

The time [T] that has the second as a unit

The mass [M] with fundamental unit the kilogram (kg)

all other quantities are derived from these three fundamental units, for example velocity is

     v = x / t

we replace the units

     [v] = [L] / [T]

so the units of velocity are the distance between time.

This exercise uses the units of various quantities and asks to find if the equations are dimensionally correct.

Let's substitute the units in each expression

a) F = m a

    [M] [L] / [[T] ² = [M] [L] / [T] ²

the two sides of the expression are equal therefore the equation is correct

b) x = 2 a t²

scalar quantities have no units

    [L] = [L] / [T] ² [T] ²

    [L] = [L]

the two sides are equal, therefore the equation is correct

c) E = ½ m a x

    [M] [L] ² [T] ² = [M] [L] [T] ² [L]

    [M] [L] ² [T] ² = [M] [L] ² [T] ²

the two sides are equal the equation is correct

d) E = m a x

since scalar quantities have no units, this expression is equivalent to the expression in part c, therefore it is correct

e) F = F x / m

    [M] [L] / [T] ² = [M] [L] / [T] ² [L] / [M]

    [M] [L] / [T] ² = [L] ² / [T] ²

the two sides are different so the equation is false

In the dimensional analysis we find that expressions are true a, b, c, d  and we see that the expression e is false

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1. The electron experiences acceleration and moves independently in the y-direction.

2. The y-component of the electron's displacement after 2.40 μs in the electric field is -8.11 μm.

3.  The x-component of displacement remains zero.

To calculate the y-component and x-component of the electron's displacement, we need to consider the motion of the electron in the electric field. Let's break it down step by step:

1. Acceleration of the Electron:

The electric field causes a force on the electron given by the equation: F = qE, where F is the force, q is the charge of the electron, and E is the electric field.

Since the charge of an electron is -1.6 × \(10^-^1^9\) C, and the electric field is 201 N/C, we can calculate the force:

F = (-1.6 × \(10^-^1^9\)C) * (201 N/C)

  = -3.216 × \(10^-^1^7\) N

Using Newton's second law, F = ma, we can find the acceleration (a) of the electron:

a = F / m

  = (-3.216 × \(10^-^1^7\) N) / (9.109 ×\(10^-^3^1\) kg)

  = -3.530 × \(10^1^3 m/s^2\)

2. Displacement in the y-direction:

Since no other forces act on the electron, its motion in the y-direction is independent of the electric field. The equation for displacement (y) under constant acceleration is:

y = (1/2) * a *\(t^2\)

Substituting the values, where the time (t) is 2.40 μs (2.40 ×\(10^-^6\) s), we can calculate the y-component of displacement:

y = (1/2) * (-3.530 ×\(10^1^3 m/s^2\)) * (2.40 ×\(10^-^6 s)^2\)

  = -8.11 μm

Therefore, the y-component of the electron's displacement 2.40 μs after entering the electric-field region is -8.11 μm.

3. Displacement in the x-direction:

Since the electron's velocity is only in the y-direction initially, the x-component of the displacement remains zero. Without any forces acting in the x-direction, the electron continues to move in the y-direction without changing its x-position.

Hence, the x-component of the electron's displacement 2.40 μs after entering the electric-field region is 0 meters.

Please note that the calculations provided are based on the given values and the provided formulas for displacement and acceleration.

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In order to find by how much is the car magnified, first let's find the position of the image using the formula below:

Where f is the focal length, do is the object position and di is the image position.

After converting all measures to meters, we have:

Now, to find the magnification factor, we use the formula below:

The car is magnified by a factor of 0.356 (that is, the image is smaller than the object)

Now, for the second part of the question, let's use the first formula again, with f = 0.0316 m and di = 0.1534 m:

Therefore the object should be put at 3.98 cm.

The weight of a male African elephant on the moon would be approximately 11,470.2 Newtons.

To calculate the weight of a male African elephant on the moon, we need to use the formula:

Weight = mass × acceleration due to gravity

The mass of the elephant is given as 7,000 kg. However, the acceleration due to gravity on the moon is approximately 1/6th (0.1667) of the acceleration due to gravity on Earth, which is approximately 9.8 m/s².

Weight on the Moon = 7,000 kg × 0.1667 × 9.8 m/s²

Weight on the Moon = 7,000 kg × 1.6386 m/s²

Weight on the Moon ≈ 11,470.2 Newtons

Therefore, the weight of a male African elephant on the moon would be approximately 11,470.2 Newtons.

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The resistance of the copper wire at 80°C is r = 5.952 ohms

Given copper cable length is 1.2 km

The area of cross section given is 5 mm^2

Thus the equation for resistivity is:

p (t) = p (0) × ( 1 + a × ( change in temperature )

p(t) = 0.02 × 10^-6 × ( 1 + 0.004 × 60 )

p (t) = 2.48 × \(10^-^8\) ohm m

r = ( p × l ) ÷ a

r = (  2.48 × \(10^-^8\) × 1200 ) ÷ 5 × \(10^-^6\)

r = 5.952 ohms

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Answer:

10 mph

Explanation:

Answer:

A. gravitational force always true.

B, C and D could be true under the correct conditions

Answer:

Explanation:

The magnitude of the net force acting on an object is equal to the mass of the object multiplied by the acceleration of the object, as shown in this formula. We find its magnitude using the Pythagorean Theorem or the distance formula, and we find its direction using the inverse tangent function. Given a position vector →v=⟨a,b⟩, the magnitude is found by |v|=√a2+b2. The direction is equal to the angle formed with the x-axis, or with the y-axis, depending on the application.

Answer:

The centripetal acceleration for the first radius; 2.0 m = 50 m/s²

The centripetal acceleration for the second radius; 4.0 m = 25 m/s²

The centripetal acceleration for the third radius; 6.0 m = 16.67 m/s²

The centripetal acceleration for the fourth radius; 8.0 m = 12.5 m/s²

The centripetal acceleration for the fifth radius; 10.0 m = 10 m/s²

Explanation:

Given;

mass of the object, m = 1 kg

velocity of the object, v = 10 m/s

different values of the radius, 2.0 m 4.0 m 6.0 m 8.0 m 10.0 m

The centripetal acceleration for the first radius; 2.0 m

\(a_c = \frac{v^2}{r} \\\\a_c_1= \frac{(10)^2}{2} \\\\a_c_1= 50 \ m/s^2\)

The centripetal acceleration for the second radius; 4.0 m

\(a_c_2= \frac{(10)^2}{4} \\\\a_c_2= 25 \ m/s^2\)

The centripetal acceleration for the third radius; 6.0 m

\(a_c_3= \frac{(10)^2}{6} \\\\a_c_3= 16.67 \ m/s^2\)

The centripetal acceleration for the fourth radius; 8.0 m

\(a_c_4= \frac{(10)^2}{8} \\\\a_c_4= 12.5 \ m/s^2\)

The centripetal acceleration for the fifth radius; 10.0 m

\(a_c_5= \frac{(10)^2}{10} \\\\a_c_5= 10 \ m/s^2\)

The wave which carries energy twice as the energy of the wave shown is the wave in option c. The amplitude of the wave and wave cycles increased twice in the wave in option c.

The amplitude of a wave is the distance from the center of a baseline under the crest to the top of the crest. The amplitude of the wave is the measure of its intensity.

The amplitude and energy of a wave is directly proportional to the frequency of the wave. Hence, as the frequency increases, the amplitude of the wave increases.

Here, the frequency of the wave is 3 Hz. For the wave in option b, the number of wave cycles per second or the frequency is 6 Hz. Hence, it will have twice energy as the wave shown.

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ANSWER:

d) There is not enough information to determine this answer

STEP-BY-STEP EXPLANATION:

Given:

Frequency 1 (f1) = 440 Hz

We have the following:

We don't know the beats, therefore we can't determine the missing frequency.

This means that the correct answer is d) There is not enough information to determine this answer

Answer:

Ussually, soft metals. or solid objects that allow the flow of eletrons.

Explanation:

Electric Current is the flow of electrons through a wire or solution. In a solid the electrons are passed from one positively charged metallic atom to next but in solution the electron is carried by the ions present in the solution. A solution capable of carrying charge is called an electrolyte.

In solid conductors, electron mobility is responsible for the flow of electrical current.

Electron mobility is principally responsible for the flow of electrical current in solid conductors. The subatomic particles known as electrons orbit the atomic nuclei of atoms and are negatively charged. The outermost energy levels of the atoms in a solid conductor, such as a metal like copper or aluminum, have numerous free or loosely bound electrons.

The conductor experiences an electric field that pulls on the free electrons when an electric potential difference (voltage) across its ends is applied (for example, by connecting it to a battery or power source). The electrons are propelled by this force toward the direction of the electric field.

Hence, in solid conductors, electron mobility is responsible for the flow of electrical current.

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Answer: 51

Explanation:

Given

Output is 23 V

The square armature side is \(a=5.1\ cm\)

Magnetic field \(B=0.5\T\)

Rate of revolution \(n=55\ rev/s\)

Angular speed

\(\omega =2\pi n\\\omega=2\pi \times 55=110\pi\ rad/s\)

Peak voltage is given by

\(E_{peak}=NB\omega A\quad [\text{N=Number of windings; A=area of cross-section}]\\\\N=\dfrac{E_{peak}}{B\omega A}\\\\N=\dfrac{23}{0.5\times 110\pi\times (0.051)^2}\approx 51\)

So, there are approximate 51 loops

Answer: 849.15NM/S

P= F'.V' ,

WHERE V' IS THE VELOCITY OF THE PROJECT OF THE OBJECT ON WHICH THE FORCE ACTS . THUS,

P= F'.V. = COSФ

P = (135N) (7.4M/S)COS31° = 849.15NM/S

The electrical potential energy between two point charges is given by:

where:

k is the electrical constant

q, Q are the point charges

r is the distance between them

Protons have the same electric charge which is:

Lets plug the information in the formula above:

So our fina answer is:

The magnitude of the electric field is \(2.67*10^6 N/C\), and its direction is westward.

To determine the magnitude and direction of the electric field at the point where the small ball is suspended, we can use the formula for the electric field:

Electric field (E) = Force (F) / Charge (q)

Given:

Charge of the ball (q) = \(-3.0*10^{(-12)} C\)

Force experienced by the ball (F) = \(8.0*10^{(-6)}\) N (eastward)

Plugging in the values into the formula:

E = F / q

E = \((8.0*10^{(-6) }N) / (-3.0*10^{(-12)} C)\)

Let's calculate the electric field:

E = -\(2.67*10^6 N/C\)

The magnitude of the electric field is\(2.67*10^6 N/C\). The negative sign indicates that the electric field is pointing in the opposite direction to the force experienced by the ball, which in this case is westward.

Therefore, the magnitude of the electric field is \(2.67*10^6 N/C\), and its direction is westward.

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As the temperature of the balloon is lowered, its volume will decrease as well.

The kinetic theory of matter  says that all matter consists of many, very small particles which are constantly moving or in a continual state of motion.

According to Charles law, the volume of a fixed mass of a gas is directly proportional to its absolute temperature.

Based on Charles law, as the temperature of the balloon is lowered, its volume will decrease as well because the average kinetic energy of the gas molecules has reduced, the rate of gas collision decreased, which will cause a drop in the volume of the balloon.

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Answer:

A

Explanation:

power =  energy/time

200 = energy / t

200 = 4000/t

t = 4000/200= 20 sec

(a) The minimum force F he must exert to get the block moving is 38.9 N.

(b) The acceleration of the block is 0.79 m/s².

The minimum force F he must exert to get the block moving is calculated as follows;

Fcosθ = μ(s)Fₙ

Fcosθ = μ(s)mg

where;

F = [0.1(36)(9.8)] / [(cos(25)]

F = 38.9 N

F(net) = 38.9 - (0.03 x 36 x 9.8) = 28.32

a = F(net)/m

a = 28.32/36

a = 0.79 m/s²

Thus, the minimum force F he must exert to get the block moving is 38.9 N.

The acceleration of the block is 0.79 m/s².

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The net force on particle q₁ is approximately +25.6 N.

The electrostatic forces between particle q1 and the other two particles, q2 and q3, must be taken into account in order to determine the net force on particle q1. Coulomb's Law describes the electrostatic force between two charged particles:

F = k * |q₁ * q₂| / r²

F is the force, k is the electrostatic constant (9 x 109 N m2/C2), q1 and q2 are the charges' magnitudes, and r is the distance separating them.

Let's first determine the force between q1 and q2:

F₁₂ = k * |q₁ * q₂| / r₁₂²

F₁₂ = (9 x 10^9 N m²/C²) * |(-29.6 μC) * (+37.7 μC)| / (0.630 m)²

F₁₂ = (9 x 10^9 N m²/C²) * (29.6 x 10^-6 C) * (37.7 x 10^-6 C) / (0.630 m)²

F₁₂ ≈ -7.45 N

The absence of a positive sign suggests an attractive force between q1 and q2.

Let's next determine the force between q2 and q3:

F₂₃ = k * |q₂ * q₃| / r₂₃²

F₂₃ = (9 x 10^9 N m²/C²) * |(+37.7 μC) * (-10.8 μC)| / (0.315 m)²

F₂₃ = (9 x 10^9 N m²/C²) * (37.7 x 10^-6 C) * (10.8 x 10^-6 C) / (0.315 m)²

F₂₃ ≈ +33.05 N

The presence of a positive sign suggests a repulsive force between q2 and q3.

We must now add all the forces in order to determine the net force on q1:

Net force = F₁₂ + F₂₃

Net force ≈ -7.45 N + 33.05 N

Net force ≈ +25.6 N

The presence of a positive sign implies that the net force is pointing to the right, in the same direction as particle q2.

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