The initial current is 2A, resistance is 2Ω, and inductance is 0.008H. The time for current decay to 1A is found to be around 2.1ms using the natural logarithm.
The current in an LR circuit can be modeled by the equation:
\(I(t) = I0e^{(-Rt/L)}\)
where I(t) is the current at time t, I0 is the initial current, R is the resistance, L is the inductance, and e is the mathematical constant e.
We are given that the initial current is 2.0 A, the resistance is 2 Ω, and the inductance is 8.0 mH (or 0.008 H). We want to find the time it takes for the current to decay to 1.0 A.
Substituting the given values into the equation, we get:
\(1.0 A = 2.0 A \times e^{(-2\Omega t/0.008H)}\)
Simplifying, we can divide both sides by 2.0 A and take the natural logarithm of both sides:
\(ln(0.5) = -2\Omega t/0.008H\)
Solving for t, we get:
\(t = -0.008H \times ln(0.5) / 2\Omega\)
Plugging in the given values, we get:
\(t \approx 0.0021 s\) or 2.1 ms
Therefore, it will take approximately 2.1 ms for the current to decay to 1.0 A.
In an LR circuit, the inductor resists changes in current, so when the switch is thrown and the current starts to decay, the inductor generates a back EMF that opposes the change in current. This causes the current to decay exponentially over time, as described by the above equation.
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Calculate the speed of a periodic wave that has a wavelength of 2.0 m and a frequency of 3.0 Hz.
Answer:
v=wavelength x f = 2 x 3 = 6 m/s
Explanation:
The speed of a wave is the product of its frequency and wavelength. The speed of the periodic wave with the frequency of 3 Hz and wavelength of 2 m is 6 m/s.
What is frequency?Frequency of a wave is the number of wave cycles per unit time. It is the inverse of the time period of the wave. Frequency is inversely proportional to the wavelength of the wave.
The relation between speed, frequency and wavelength of a wave is given by the expression as written below:
c =νλ
where, c is the speed, ν be the frequency and λ be the wavelength.
Given that ν = 3 Hz or 3 s⁻¹
and λ = 2 m
then speed c = 2 m × 3 Hz = 6 m/s
Therefore, the speed of the periodic wave is 6 m/s.
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The A has a mean lifetime of 26 10-10s and decays into p + e- + ve with a branching fraction of 83 10-4. The A+ (udc) has a mean lifetime of 2-1 10-13s. Estimate the branching fraction of the A into A+e+ +ve, comment on how your result compares with the measured value. [m()=2285GeV/c2BR(e+ve)=(2106)%]
The mean lifetime of A is given by τ(A) = 26 × 10⁻¹⁰ s. The A decays into p + e⁻ + ve with a branching fraction of BR(A → p + e⁻ + ve) = 83 × 10⁻⁴.The mean lifetime of A⁺ (udc) is given by τ(A⁺) = 2-1 × 10⁻¹³ s.
The branching fraction of A into A⁺ + e⁺ + ve is given as follows: First, we can calculate the decay constant for A.λ = (1/τ) = (1/26 × 10⁻¹⁰) s⁻¹.The half-life of A is given by t₁/₂ = ln(2) / λ = (ln2 × τ) = 2.667 × 10⁻¹⁰ s. The branching fraction of A → A⁺ + e⁺ + ve is given as follows: BR(A → A⁺ + e⁺ + ve) = 1 - BR(A → p + e⁻ + ve) = 1 - (83 × 10⁻⁴) = 0.99917.
The measured value of the branching fraction of A → A⁺ + e⁺ + ve is BR(e+ve) = 2106 %.This is greater than 100%. Therefore, the value must be a typographical error. The correct percentage is probably 21.06%.The estimated branching fraction of A → A⁺ + e⁺ + ve is 99.917%, which is very close to 100%. This implies that the A mainly decays into A⁺ + e⁺ + ve.
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Two people try to lift a heavy box. Jack pulls upward with a 100-newton
force. Jill pulls upward with a 50-newton force, but neither person moves the
box.
Compare the amount of work done on the box by Jack and Jill.
OA) Jack did twice as much work as Jill.
OB) Jack did fifty times more work than Jill.
OC) Jack and Jill did the same amount of work.
Answer:
A ( Jack did twice as much work as Jill
Explanation:
The common element among measures of speed, rate, and latency is _________. group of answer choices performance frequency time reactivity
The common element among measures of speed, rate, and latency is time.
What is time ?The only science that specifically studies time is physics, but even physicists acknowledge that time is one of the most challenging aspects of our universe to comprehend. However, time is typically seen as an ontologically "fundamental" or primary idea and is not composed of or dependent upon anything else, even in the most advanced and sophisticated physical models.
Time is typically defined by its measurement in the sciences; it is only what a clock says. Since physics in particular frequently requires extremely precise time measurements, time must be regarded as an infinitely divisible linear continuum and not as a quantized quantity (i.e. composed of discrete and indivisible units). Time can now be measured accurately to about 1015 seconds thanks to contemporary atomic time standards like TAI and UTC and extremely precise atomic clocks. This is equivalent to about 1 second of error in roughly 30 million years.
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at what distance from a -5.35*10^-6 C charge will the electric potential be -500 v? Please I really need help!
Answer:
What is c and v
Explanation:
Answer:
96.2
Explanation:
I got it right on Acellus
What controls how fast an object falls?
Answer:
gravity
Explanation:
it controls how fast an object falls
A downed pilot fires a flare from a flare gun. The flare an initial speed of 250 m/s and is fired at an angle of 35° to the ground. Find the maximum height the flare will reach. How long does it take for the flare to reach its maximum altitude ? What will be the final vertical velocity ?
Answer:
Maximum Altitude: vi = 250 m/s At the maximum height q = 35° vy,f = vy,i − g∆t = 0 g = 9.81 m/s2 vy,i = vi (sin q) = g∆t ∆t = vi (si g n q) = (250 9 m .8 / 1 s) m (s / i s n 2 35°) ∆t = 15 s
Vertical Velocity: Vyf = 439.09
Explanation:
The time it will take to reach its maximum altitude will be 14.63 seconds, and the final vertical velocity will be 143.4 m/s.
What is Speed?Velocity is the pace and direction of an object's movement, whereas speed is the time rate at which an object is travelling along a path. In other words, speed is a scalar value, but velocity is a vector.
The velocity at time t = 0 is known as the initial velocity (u). It is the rate at which motion initially manifests itself.
On the other hand, the final velocity is a vector number that represents the speed and direction of a moving body after it has experienced its maximum acceleration.
According to the question, the given values are :
Angle, θ = 35°
V₀ = 250 m/s
\(V_o_y=V_osin\theta\)
\(V_o_y\) = (250)(sin 35°)
= 250 × 0.573
\(V_o_y\) = 143.4 m/s.
Now, the time it will take to reach its maximum height will be :
\(t_m_a_x=V_o_y/g\)
= 143.4 / 9.8
\(t_m_a_x\)= 14.63 seconds.
Hence, the time it will take to reach its maximum altitude is 14.63 seconds.
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find the minimum amount of ice at 10 ceIcius needed to bring the temprature at 500 g of water qat 20
The minimum amount of ice needed to bring the temperature of the water at the given temperature is 111.5 g.
What is heat capacity?
The heat capacity of a substance is the quantity of heat needed to raise the entire mass of the substance by 1 kelvin.
Minimum amount of iceThe minimum amount of ice at 10 Celsius needed to bring the temperature at 500 g of water at 20 Celsius is calculated by applying the principle of conservation of energy.
Heat lost by the water = heat gained by the ice
m₁cΔθ₁ = m₂cΔθ₂ + m₂hf
where;
hf is heat of fusion of ice = 333.55 J/gm₂ is mass of icec is specific heat capacity of water500(4.184)(20) = m₂(4.184)(10) + m₂(333.55)
41,840 = 41.84m₂ + 333.55m₂
41,840 = 375.39m₂
m₂ = 41,840 / 375.39
m₂ = 111.5 g
Thus, the minimum amount of ice needed to bring the temperature of the water at the given temperature is 111.5 g.
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wire loop of radius 12 cm and resistance 8.5 o is located in a uniform magnetic field e that changes in magnitude as given in fig. 30-38. the vertical axis scale is set by b, : 0.50 t, and the horizontal axis scale is set by r, - 6.00 s. the loop's plane is perpendicular to e . what emf is induced in the loop during time intervals (a) 0 to 2.0 s., (b) 2.0 s to 4.0 s., and (c) a.0 s to 6.0 s?
The EMF induced in the loop of radius 12 cm and resistance 8.5 Ω is located in a uniform magnetic field e that changes in magnitude during 0 s to 2 s is - 0.011 mV, 2 s to 4 s is 0 and 4 s to 6 s is 0.011 mV
ε = - dΦ / dt
Φ = B A
ε = - - dBA / dt
ε = - B dA / dt - A dB / dt
Since the area is constant through time,
ε = - A dB / dt
ε = - π r² dB / dt
a ) For 0 to 2.0 s,
ε = - π ( 0.12 )² ( ( 0.5 - 0 ) / ( 2 - 0 ) )
ε = - 1.1 * 10⁻² V
ε = - 0.011 mV
b ) For 2.0 s to 4.0 s,
ε = - π ( 0.12 )² ( ( 0.5 - 0.5 ) / ( 4 - 2 ) )
ε = 0
c ) For 4.0 s to 6.0 s,
ε = - π ( 0.12 )² ( ( 0 - 0.5 ) / ( 6 - 4 ) )
ε = 1.1 * 10⁻² V
ε = 0.011 mV
Therefore, the EMF induced in the loop during time intervals,
a ) 0 s to 2 s is - 0.011 mV
b ) 2 s to 4 s is 0
c ) 4 s to 6 s is 0.011 mV
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You are sharing a house with a few roommates. One of them plays on the basketball team, and is exactly 200 cm tall. The heights of you and the other roommates are 188 cm, 175 cm, and 160 cm. You want to buy the minimum height mirror that will allow all of you to see your entire selves, when the mirror is mounted in a fixed position on the wall. Assume each person's eyes are at a level 95% of their height. How tall a mirror should you buy
Answer:
119 cm
Explanation:
Given heights : 200cm , 188 cm , 175 cm, 160 cm
since the eyes are at 95% level
95% of 200 cm = 190 cm
95% of 160 cm = 152 cm
hence the allowable height of mirror = 200 - ( 5 + 76 ) = 119 cm
and The mirror should be hung 75cm from the floor
At time t = 0, a bottle of juice at 90 degree F is stood in a mountain stream whose temperature is 53 degree F. After 5 minutes, its temperature is 80 degree F. Let H(t) denote the temperature of the juice at time t, in minutes. (a) Write a differential equation for H(t) using Newton's Law of Cooling. (Do not solve for k.)
(b) Solve the differential equation. (Round your value of k to five decimal places.)
(a) To write a differential equation for H(t) using Newton's Law of Cooling, we can use the formula:
H'(t) = -k(H(t) - T_s)
where H'(t) represents the derivative of H with respect to time, k is the cooling constant, H(t) is the temperature of the juice at time t, and T_s is the temperature of the surrounding medium (mountain stream in this case).
The negative sign in front of the equation indicates that the temperature of the juice decreases over time.
(b) This is the differential equation. H(t) = (90 - T_s) * e^(-kt) + T_s
To solve the differential equation, we need initial conditions. In this case, we know that at t = 0, the temperature of the juice is 90 degrees F, so we have the initial condition:
H(0) = 90
Now, let's solve the differential equation:
H'(t) = -k(H(t) - T_s)
Separate variables and integrate:
1 / (H(t) - T_s) dH = -k dt
Integrating both sides:
∫1 / (H(t) - T_s) dH = -k ∫dt
ln|H(t) - T_s| = -kt + C
Exponentiate both sides:
|H(t) - T_s| = e^(-kt + C)
Since the absolute value can be eliminated, we can write:
H(t) - T_s = ± e^C * e^(-kt)
Let A = ± e^C, which is a positive constant. Therefore:
H(t) - T_s = A * e^(-kt)
Rearrange the equation:
H(t) = A * e^(-kt) + T_s
Now, we can apply the initial condition H(0) = 90:
90 = A * e^(-k * 0) + T_s
90 = A + T_s
A = 90 - T_s
Substituting A back into the equation, we have:
H(t) = (90 - T_s) * e^(-kt) + T_s
This is the solution to the differential equation. The value of k can be determined by using the given information about the temperature of the juice after 5 minutes (t = 5).
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is the NW section of the Earth experiencing day OR night and winter OR summer in Position 1?
photo is attached below
options:
- day,winter
-night,winter
-day,summer
-night,summer
pls help
The the NW section of the Earth is experiencing night and winter in Position 1.
Option 3 is correct.
What determines when a location experiences day or night?Day and night are due to the Earth rotating on its axis, not its orbiting around the sun.
The term 'one day' is determined by the time the Earth takes to rotate once on its axis and includes both day time and night time. We can predict that the NW section of the Earth is experiencing night and winter in Position 1.
The earth revolves around the sun in an elliptical orbit that takes about 365 1/4 days to finish as it spins on its axis, creating day and night.
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Explain in your own words, what would happen to the size of the squirrel population if
all of the badgers in the environment were eliminated? why
Answer:
the reason I ask is that you are not even going to be a little late to the party but
describe the motions of a baseball thrown from a height of 10 ft versus a ball that was just dropped from a height of 10 ft at the same time.
When comparing the motions of a baseball thrown from a height of 10 ft and a ball that is simply dropped from the same height, there are distinct differences.
The thrown baseball exhibits a combination of vertical and horizontal motion. It follows a curved path due to the initial throwing velocity and the force of gravity, resulting in a parabolic trajectory. In contrast, the dropped ball experiences only vertical motion, falling straight down toward the ground in a vertical line. While both objects are affected by gravity, the thrown baseball's additional horizontal velocity allows it to cover a longer distance and follow a more complex path compared to the vertically descending dropped the ball.
Therefore, the thrown baseball exhibits both vertical and horizontal motion, following a curved trajectory due to the combination of the initial throwing velocity and the force of gravity. The dropped ball, on the other hand, experiences only vertical motion, falling straight down toward the ground along a vertical line.
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What is the difference between a star and a planet.
Answer: In the planet there is life and the star is a store of energy where the planet gets its light, life and energy.
Explanation:
Two charged particles near each other are released. As they move, the force on each particle increases. Therefore, the particles haveA) the same sign.B) the opposite sign.C) not enough information
ANSWER
B) the opposite sign
EXPLANATION
The force between charged particles is inversely proportional to the square of the distance between particles, from Coulomb's law:
\(F=k_e\cdot\frac{q_1\cdot q_2}{r^2}\)If the force increases it can mean two things: either one or both particles are gaining charge - which is not the case of this problem, or the distance between them is decreasing. In this case, the distance must be decreasing for the force to increase. This means that the particles are moving towards each other, they are being attracted by each other. Since only particles with opposite signs attract, the answer is option B, they have opposite sign.
What is the mass of an object if it takes a net force of 2,400 Newtons
to accelerate it at a rate of 60 m/s??
Answer:
40 kg
Explanation:
F = ma
F / a = m
2400 / 60 = 40 kg
help as soon u can pls! due in 45 mins!!
Which statement correctly represents a mineral?
1. any naturally forming substance made from one element
2. any chemical substance which forms naturally in the Earth
3. an element which is made into an object
4. any substance which develops in the ground
Minerals are any chemical substance which forms naturally in the Earth
Define mineral.
Minerals are those substances found in foods and in the earth that our systems require for healthy growth and development. Calcium, phosphate, potassium, sodium, chloride, magnesium, iron, zinc, iodine, chromium, copper, fluoride, molybdenum, manganese, and selenium are among the nutrients that are crucial for good health.
Compounds found only in living creatures are typically not considered minerals according to geological definitions. However, some minerals, like calcite, are frequently biogenic or, in terms of chemistry, are organic molecules (such as mellite). Additionally, living things frequently produce inorganic crystals (like hydroxylapatite), which are also found in rocks.
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If the total force on the object is not zero, its motion will
how slow would a 60,000 kg freight car have to roll to have the same momentum as an 80 kg person running 6.5 m/s
(8 and 2/3) millimeters per second.
That's about 0.02 mile per hour.
You decide to hike up Mt. Everest so you can experience what it is like to be above roughly 75% of the air in the atmosphere. If the pressure at the surface is 1000 mb, what is the most reasonable approximation of the pressure at the summit (top of the mountain)?
You decide to hike up Mt. Everest so you can experience what it is like to be above roughly 75% of the air in the atmosphere, the pressure at the summit is mathematically given as
P= 250mb
What is the most reasonable approximation of the pressure at the summit (top of the mountain)?Generally, the equation for pressure at the summit is mathematically given as
P= (100-75) * pressure at the surface
Therefore
P= (25/100) x 1000
P= (0.25 x 1000)mb
P= 250mb
In conclusion, the pressure at the summit
P= 250mb
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what is atomic weight
Answer:
Its also know as atomic mass its the mass of isotopes.
Explanation:
relative atomic masses of sources in the local environment of the Earth's crust and atmosphere as determined by the atomic weight.
Newt noticed that It hurt his body more when he Jumped off a high diving board than It did when he Jumped off the lower board. What law of newton is this and why
Answer:
Newton's 3rd law of motion
Explanation:
According to the question, Newt noticed that It hurt his body more when he Jumped off a high diving board than It did when he Jumped off the lower board. What law of newton is this and why
By the time Newt want to jump, for him to do so, he has to push himself against the ground according to the Newton's 3rd law of motion.
The law states that in every action, there will be equal and opposite reaction.
The force at which he pushes himself against the ground will determine the force at which he will carry himself to jump off the high diving board.
The reaction towards the high diving board will be greater than the reaction towards the low diving board.
Therefore, Newt will hurt his body more when he Jumped off a high diving board than It did when he Jumped off the lower board. And the law of newton that is responsible for this is Newton's third law of motion.
Juan rides his horse with a constant
speed of 18 km/h. How far can he travel
in 1/2 hour?
Answer:
He traveled 9km
Explanation:
To do this problem you need to use the equation which is Speed= distance/time and this problem gives you the speed which is 18 km/h and it gives you the time 1/2 hour so you write the equation 18= d/ 1/2 which his distance is 9km
URGENT!! ILL GIVE
BRAINLIEST! AND 100 POINTS
Which statement about the event above is NOT correct?
Answer:
i think its A
Explanation:
The International Space Station (ISS) orbits the Earth every 90 minutes. The Earth has an average radius of 6371 km and an approximate mass of m = 5.97 × 1024 kg. The gravitational force between two massive objects is calculated using the following formula: =∙m1m2,where=6.674×10−11m3⁄kg∙s2 If we assume the Earth to be spherical and the ISS orbit perfectly circular: a) Calculate the angular velocity of the ISS. (1) b) Calculate the height above the Earth’s surface at which the ISS orbits. (5) c) Calculate the tangential (linear) speed the ISS must travel to maintain this orbit. 2 Give your answer in km/h, rounded to the nearest whole number.
The angular velocity of the ISS is 0.012 rad/s. the height above the Earth's surface at which the ISS orbits is 408 km. the tangential speed of the ISS is 7 km/s.
a) Calculate the angular velocity of the ISS.
The angular velocity of the ISS can be calculated using the following formula:
ω = v / r
where:
ω is the angular velocity in radians per second
v is the tangential velocity in meters per second
r is the radius of the orbit in meters
The tangential velocity of the ISS is the speed at which it travels along the circumference of its orbit. The radius of the ISS's orbit is the distance from the center of the Earth to the ISS.
In this case, the tangential velocity of the ISS is 7.66 kilometers per second. The radius of the ISS's orbit is 6371 kilometers. Therefore, the angular velocity of the ISS is:
ω = 7.66 km/s / 6371 km = 0.012 rad/s
b) Calculate the height above the Earth’s surface at which the ISS orbits.
The height above the Earth's surface at which the ISS orbits can be calculated using the following formula:
h = r * (1 - (1 - e^2)^(1/2))
where:
h is the height above the Earth's surface in meters
r is the radius of the Earth in meters
e is the eccentricity of the orbit
The eccentricity of the ISS's orbit is 0.016. Therefore, the height above the Earth's surface at which the ISS orbits is:
h = 6371 km * (1 - (1 - 0.016^2)^(1/2)) = 408 km
c) Calculate the tangential (linear) speed the ISS must travel to maintain this orbit.
The tangential speed of the ISS can be calculated using the following formula:
v = ω * r
where:
v is the tangential speed in meters per second
ω is the angular velocity in radians per second
r is the radius of the orbit in meters
The angular velocity of the ISS is 0.012 rad/s. The radius of the ISS's orbit is 6371 kilometers. Therefore, the tangential speed of the ISS is:
v = 0.012 rad/s * 6371 km = 7.66 km/s
rounded to the nearest whole number: 7 km/s
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Describe the language of the following PDA (z is the stack end symbol) (the figure can be located under a, z/bbz X, z/z b,6/1 ۸, 2/2 90 91 92 a, b/bbb 1 b,b/1
The language of the given pushdown automaton (PDA) can be described as follows:
The PDA has a stack alphabet consisting of symbols 'a', 'b', 'z', '6', '1', '۸', '2', '9', '0', 'x', 'y'. 'z' represents the stack end symbol.
The transitions of the pushdown automaton (PDA) are as follows:
(a, z, z) -> (X, z): This transition allows the PDA to replace an 'a' at the input with an 'X' on the stack while maintaining the stack end symbol 'z'.(z, b, z) -> (z, z): This transition allows the PDA to pop a 'b' from the input without modifying the stack.(z, z, b) -> (6, 1): This transition allows the PDA to push '6' and '1' onto the stack when encountering a 'b' on the input.(6, 1, b) -> (۸, 2): This transition allows the PDA to replace the '6' and '1' on the top of the stack with '۸' and '2' respectively when another 'b' is read from the input.(x, y, b) -> (b, b, b): This transition allows the PDA to replace 'x' and 'y' on the top of the stack with 'b', 'b', and 'b' when a 'b' is read from the input.(b, b, b, b) -> (1, b): This transition allows the PDA to replace the 'b', 'b', and 'b' on the top of the stack with '1' and 'b' when another 'b' is encountered.(1, b, b) -> (1, 1): This transition allows the PDA to replace the '1' and 'b' on the top of the stack with '1' and '1' when another 'b' is read from the input.(1, 1, z) -> (z, z): This transition allows the PDA to pop '1' from the stack without modifying the input.Thus, the language accepted by this PDA is characterized by a sequence of 'a's followed by a sequence of 'b's, where the number of 'b's is three times the number of 'a's, and each 'b' is followed by a corresponding sequence of '90', '91', '92', 'a', 'b', 'b', 'b', '1', 'b', 'b', '1', and ending with '1'.
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Light travels in a straight line at a constant speed of 300000 m/s. What is the acceleration of light?
Answer:
As light travels in a straight line at a constant speed, it's acceleration is 0 m/s².
There is no rate of change of speed, so there is no acceleration.
0 m/s² is the right answer.an nmos transistor having vt = 1v is operated in the triode region with vds small. with vgs = 1.5v, it is found to have a resistance rds of 1kω. what value of vgs is required to obtain rds = 200ω?
The value of Vgs required to obtain Rds = 200Ω in an NMOS transistor operated in the triode region with small Vds is approximately 0.9V.
To calculate the required Vgs, we can use the equation that relates Rds to the transistor parameters. In this case, we assume the electron mobility (μn), oxide capacitance per unit area (Cox), and the width-to-length ratio (W/L) of the transistor to be constant.
By rearranging the equation and substituting the given values, we find that Vgs - Vt is inversely proportional to Rds. Since we know the initial value of Vgs (1.5V) and Rds (1kΩ), we can calculate the new value of Vgs using the proportionality.
By solving the equation, we find that Vgs ≈ 0.9V is required to achieve Rds = 200Ω in the given NMOS transistor.
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A car’s brakes decelerate it at a rate of -1.70 m/s2. What is the time, in seconds, required to slow the car from 15 m/s to 9.0 m/s?
Answer:
t = 3.52 s
Explanation:
Given that,
The deceleration of a car is, a = -1.7 m/s²
The initial velocity of the car, u = 15 m/s
Final velocity of the car, v = 9 m/s
We need to find the time that is required to slow the car from 15 m/s to 9 m/s. The definition of acceleration is :
\(a=\dfrac{v-u}{t}\\\\t=\dfrac{v-u}{a}\\\\t=\dfrac{9-15}{-1.7}\\\\t=3.52\ s\)
So, it will take 3.52 seconds to slow the car from 15 m/s to 9 m/s.