Answer:
Explanation:
A)
Density= charge/total volume .......eqn(1)
But volume= 4/3πr^3
r= radius= 20 cm= 0.20m
If we substitute into the volume equation, we have
volume= 4/3 * 3.142 *( 0.20)^3
= 0.0335 m^3
The volume= 0.0335 m^3
Charge=71 nC= 71×10^-9
If we substitute into eqn(1) we have
Density= (71 *10^-9C )/0.0335
= 2.11µc/m^3
B) charge enclose= Density × volume
spheres of radii are
5cm
10 cm
20 cm
Volume for 5cm
V= 4/3 * 3.142 *( 0.05)^3 = 0.0005237 m^3
charge enclose=2.11µc/m^3×0.0005237
charge enclose= 2.110 nC
Volume for 10cm
V= 4/3 * 3.142 *( 0.10)^3 = 0.004189 m^3
charge enclose= 2.11µc/m^3 ×0.004189
=8.9 nC
Volume for 20cm
V= 4/3 * 3.142 *( 0.20)^3 = 0.0335 m^3
charge enclose= 71nC
Problem
THE FLIGHT OF A BALL A ball is launched at 5.5 m/s at 76° above
the horizontal. It starts and lands at the same distance from the
ground. What are the maximum height above its launch level and the
flight time of the ball?
1. The maximum height above its launch level is 1.45 m
2. The time of flight of the ball is 1.1 s
1. How do I determine the maximum height?
From the question given above, the following data were obtained:
Initial velocity (u) = 5.5 m/sAngle of projection (θ) = 76 °Acceleration due to gravity (g) = 9.8 m/s²Maximum height (H) =?The maximum height can be obatianed as follow:
H = u²Sine²θ / 2g
H = [5.5² × (Sine 76)²] / (2 × 9.8)
Maximum height = 1.45 m
How do I determine the time of flight?
The time of flight of the ball can be obtained as follow:
Initial velocity (u) = 5.5 m/sAngle of projection (θ) = 76 °Acceleration due to gravity (g) = 9.8 m/s²Time of flight (T) = ?T = 2uSineθ / g
T = [2 × 5.5 × Sine 76] / 9.8
Time of flight = 1.1 s
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When a skater pulls her arms in, it
reduces her moment of inertia from
2.12 kg m² to 0.699 kg-m². If she was
initially spinning 3.25 rad/s, what is
her final angular velocity?
The skater's final angular velocity is approximately 9.86 rad/s.
The skater's final angular velocity can be calculated using the principle of conservation of angular momentum. The equation for angular momentum is given by:
L = Iω
where L is the angular momentum, I is the moment of inertia, and ω is the angular velocity.
Initially, the skater has an angular momentum of:
L_initial = I_initial * ω_initial
Substituting the given values:
L_initial = 2.12 kg m² * 3.25 rad/s
The skater's final angular momentum remains the same, as angular momentum is conserved:
L_final = L_initial
The final moment of inertia is given as 0.699 kg m². Therefore, the final angular velocity can be calculated as:
L_final = I_final * ω_final
0.699 kg m² * ω_final = 2.12 kg m² * 3.25 rad/s
Solving for ω_final:
ω_final = (2.12 kg m² * 3.25 rad/s) / 0.699 kg m²
Hence, the skater's final angular velocity is approximately 9.86 rad/s.
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11. A 2 kg chunk of clay moving at 3 m/s collides with and sticks to a 10 kg bowling ball that is
initially at rest. What is the total momentum before the collision?_____
What will be the new MOMENTUM of the clay and bowling ball combination AFTER the collision? ____
Answer:
The total momentum before the collision is 6 kg m/s (2 kg x 3 m/s).
The new momentum of the clay and bowling ball combination after the collision is 6 kg m/s (2 kg + 10 kg x 3 m/s / (2 kg + 10 kg) = 6 kg m/s). According to the law of conservation of momentum, the total momentum of a closed system must remain constant, so the total momentum before and after the collision must be the same.
A ball is projected with an initial velocity 50m/s at an angle 30 degree from the top of a tower 55m high.calculate the total time the ball was on the air and the maximum horizontal distance
Time of flight = 1.6 s
Horizontal distance = 64 m
What is a projectile motion?Projectile motion is the form of motion experienced by an object or particle projected into a gravitational field, such as from the surface of the Earth, and moves along a curvilinear path only under the action of gravity.
For the given case,
h = vt + ¹/₂gt²
h = height of tower
v = initial velocity
t = time of flight
55 = 50sin30t + ¹/₂9.8t²
55 = 25t + 4.9t²
4.9t² + 25t - 55 = 0
t = 1.6 s
X = vₓt
X = horizontal distance
vₓ = horizontal velocity
t = time of flight
X = (50 x cos30) x 1.6
X = 64 m
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can the average speed ever be zero explain
Explanation : The average speed of a moving body can never be zero but the average velocity of a moving body can be zero.
upon leaving her club, the golf ball moved upward to a height above the surrounding trees. is the ke and pe increasing, decreasing, or staying the same?
ANSWER
PE increases and KE decreases
EXPLANATION
As described, the golf ball is moving and changing its height, like in the following diagram,
By the law of conservation of energy, the total energy when the ball starts moving and during the whole motion until it stops, must be the same. This total energy is the sum of the potential energy and the kinetic energy.
When the club hits the ball, it gives it a certain amount of kinetic energy but no potential energy. As the ball starts going uphill, the potential energy starts to increase, since it depends on the height of the object. Therefore, to maintain the total energy constant, the kinetic energy must decrease.
in fig. 9-21, suppose that the projectile has an initial momentum of 6 kg m/s, a final x component of momentum of 4 kg m/s, and a final y component of momentum of 3 kg m/s. for the target, what then are (a) the final x component of momentum and (b) the final y component of momentum?
The formula used by the momentum calculator is p=mv, or momentum (p) equals mass (m) equals velocity (v).
What is the initial and ultimate momentum formula?The Momentum-Impulse Theorem for just a single item yields the final momentum by adding the beginning momentum and the impulse: pi + p Equals p f p I Plus p. Impulse is measured in the same units as momentum, which are kgms=Ns s n g m s =0 N s.
What is an object's final momentum?The mass of the both balls multiplied by the final velocity, or (4+6), would give the final momentum (vf). The conservation of momentum allows us to find vf; the final momentum must equal the sum of the original momentum values. As a result of their opposing directions, ball B's velocity was negative.
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A body of mass 12kg travelling at 4.2m/s² collides with a second body of mass 18kg at rest. Calculate their common velocity of the two bodies coalesce after collision
When a body of mass 12kg travelling at 4.2m/s² collides with a second body of mass 18kg at rest, their common velocity after the collision is 1.68 m/s.
When two objects of different masses collide, they can exchange momentum. An object's mass and velocity together make up its momentum. When two objects collide, their momentum is conserved, meaning that the total momentum of the two objects before the collision equals the total momentum of the two objects after the collision. This principle can be used to calculate the velocity of the two objects after a collision.A body of mass 12 kg is travelling at a velocity of 4.2 m/s and collides with a second body of mass 18 kg at rest. The total mass of the system is 12 kg + 18 kg = 30 kg. To determine the velocity of the two objects after the collision, we need to use the conservation of momentum principle. Before the impact, the system's entire momentum is:momentum before = \((mass_1 x velocity_1) + (mass_2 x velocity_2)\)where mass1 is the mass of the first object, velocity1 is the velocity of the first object, \(mass_2\) is the mass of the second object, and \(velocity_2\) is the velocity of the second object. In this case,\(mass_1 = 12 kg, velocity_1 = 4.2 m/s, mass_2 = 18 kg\), and \(velocity_2 = 0\) (because the second object is at rest). Substituting these values into the equation above, we get: momentum before = (12 kg x 4.2 m/s) + (18 kg x 0)momentum before = 50.4 kg m/sFollowing the collision, the system's overall momentum is:momentum after =\((mass_1 + mass_2) * velocity\)where mass1 + mass2 is the total mass of the system, and velocity is the velocity of the two objects after the collision. Let's call this velocity "v". Substituting the values we know into the equation above, we get: momentum after = (12 kg + 18 kg) x vmomentum after = 30 kg x vUsing the conservation of momentum principle, we know that momentum before = momentum after. Therefore, we can set these two equations equal to each other and solve for v.50.4 kg m/s = 30 kg x vv = 50.4 kg m/s ÷ 30 kgv = 1.68 m/sFollowing the impact, the two bodies' common velocity is 1.68 m/s. Hence, the answer to this problem is that when a body of mass 12kg travelling at 4.2m/s² collides with a second body of mass 18kg at rest, their common velocity after the collision is 1.68 m/s.For more questions on collision
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NO ONE WILL HELP, PLEASE PLEASE HELP, I HAVE AN HOUR TO GET 4 PAGES DONE! Find the average speed of a marble that takes 6 seconds to roll 30 m across a gymnasium floor.
Where is the potential energy equal to zero?
Answer:
im sure your already past this but it's E.
Explanation:
This is because in this case potential energy is linear to height, which means that the higher the more potential energy.
While an object is in projectile motion (with upward being positive) with no air resistance.
Its vertical acceleration is equal to -g, while the horizontal component of its velocity is unchanged.
This is due to the projectile's dual components of vertical and horizontal velocities. But when the item moves, its vertical component of velocity changes but its horizontal component does not.
The projectile's horizontal component of velocity remains constant, therefore it only has a vertical component of acceleration and no horizontal component. The horizontal component of velocity remains unchanged as a result.
Since the only vertical force acting on the object is the weight, the vertical component of acceleration is equal to -g.
Therefore, the vertical component of its acceleration is equal to -g, while the horizontal component of its velocity remains constant.
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The first P-wave of an earthquake travels 5600 kilometers from the epicenter and arrives at a seismic station at 10:05 a.m. At what time did this earthquake occur?
Ahhhhhh I have a Regent's test in 2 hours and I don't know how to solve this type of question! Any help would be appreciated.
Anyone know what the steps to do this are? I dont even need an answer, just how to get to it. Thank you!
The earthquake would occur 13 minutes before 10:05 a.m. which will be at 9.52 am.
The p-waves travel with a constant velocity of 7 km/s
The time can be calculated by using the formula
t = d / v
where
T1 = 10:05 a.m
d is the distance they take to travel from the epicenter
v is the speed of the p-waves
On average, the speed of p-waves is
v = 7 km/s
d = 5600 km (given)
Substituting the values in the formula;
t = d / v
t = 5600 ÷ 7
t = 800 seconds
Converting into minutes,
t = 800 ÷ 60
t = 13.3
≈ 13 mins
T1 - 13 mins = T2
10:05 - 13 mins = 9.52 am
It means the earthquake occurred prior 13 minutes, that is at 9.52 am.
Therefore, the earthquake occurred at 9.52 am.
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question 1+1677-789909
Answer:
your answer is -788231
Explanation:
1+1677=1678
1678-789909=-788231
The graph describes the motion of an object.
The object moves with
CBD.
from A to B. It
from B to C. It moves with
from
The graph describes the motion of an object.
The object moves with CBD
From A to B It is moving in a straight line it means it's velocity is constant
From B to C it is not changing it's position with respect to time so velocity is zero because initial and final position are same so there is no displacement
From C to D it is again moving in a straight line it means it's velocity is constant
What is Position time graph ?An object's distance from its beginning position at any given moment since it began moving is displayed on a position-time graph. The greater the slope of the line and the faster the object's speed changes, the steeper the line is.
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what is the work done on the box from x = 0m to 16m
Answer:
Explanation:
The Workdone is the product of force and distance, Hence, the Workdone on the box from distance x = 0 meters and x = 16 meters is 0 Joules.
Using the graph given :
The work done from x = 0 to x = 16 metres ;
The distance can be split evenly into :
(x = 0 to x = 8) and (x = 8 to x = 16)
Workdone = Force × distance
Workdone from ; x = 0 to x = 8 ;
Force at a distance of 8 meters = - 40N
Workdone = - 40N × 8 m = -320 Nm
Workdone from ; x = 8 to x = 16 ;
Force at a distance of 16 meters = 40 N
Workdone = 40 N × 8 m = 320 Nm
The total workdone :
(-320 + 320) Nm = 0 J
.
Therefore, the Workdone ls 0 Joules.
An airplane, starting at rest, takes off on a 600. m long runway accelerating at a rate of 12 m/s/s. How many seconds does it take to reach the end of the runway?
Answer:
10 seconds
Explanation:
As it starts from rest, then u=0
and by III rd equation of motion:
What is the displacement Δx of the particle?
The change in the displacement is 70 m
What is the change in displacement?Recall that the displacement is obtained as the product of the velocity and time. We have the velocity at two intervals.
At v1, the displacement can be obtained from;
x1 = 0.5 * 20 = 10 m
At v2, the displacement can be obtained as;
x2 = 2 * 40 = 80 m
Now
Δx = 80 m - 10 m = 70m
Thus the change in the displacement is 70 m
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Calculate the total Av required to transfer between two coplanar circular Earth orbits of radii r 1 parameters p = 13,457 km and e = 0.76. Ans.: 7.086 km/s 12,750 km and r2 = 31,890 km, respectively, using a transfer ellipse having parameters p=13.475 km and e=0.76
The total velocity required (Av) to transfer from one circular orbit to another is 7.086 km/s
The total velocity required (Av) to transfer from one circular orbit to another is given by Av = √(μ/p)(2/r1 - 1/r2), where μ is the standard gravitational parameter of the central body and p is the semi-latus rectum of the transfer ellipse.
Given the parameters for the two circular orbits, r1 = 12,750 km and r2 = 31,890 km, and for the transfer ellipse, p = 13,475 km and e = 0.76, we can calculate the total velocity required to transfer between the two orbits as follows:
Av = √(μ/p)(2/r1 - 1/r2)
Av = √(3.986E+13/13,475)(2/12,750 - 1/31,890)
Av = √(2.946E+10)(0.0690 - 0.0314)
Av = √(2.946E+10)(0.0375)
Av = 7.086 km/s
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Suppose headphones were placed on a student, and a 500-Hz sound was fed to the left ear
slightly later than to the right ear. The student will discern the source of sound to be at about 45°
to the right of center. Why?
What is the approximate time delay in the response of the left ear?
Answer:
0.05 ms
Explanation:
The speed of sound in air is about 343 m/s. If the sound waves are coming from a source that is 1 meter away, then it will take about 3.43 microseconds for the sound waves to reach the right ear and about 3.53 microseconds for the sound waves to reach the left ear. This is a difference of about 0.097 microseconds, which is about 0.05 ms.
The human brain is very good at detecting small differences in time, and it uses this information to determine the direction of a sound source. When the sound waves reach the left ear slightly later than the right ear, the brain interprets this as a sound coming from the right side. The greater the difference in time, the further to the right the brain will perceive the sound to be.
In the case of a 500 Hz sound, the brain will perceive the sound to be coming from about 45° to the right of center if the sound waves reach the
A car traveling west at 15 m/s and speeds up to 20 m/s west in 5 seconds. Why is the acceleration of the car?
Answer:
1 m/s
Explanation:
5m/s change in velocity, divided by 5 seconds= 1 meter/second/second
change in velocity/change in time
Acceleration = (change in velocity) / (time for the change)
that's = (change in speed and its direction) / (time for the change)
Change in velocity = (ending velocity) - (starting velocity)
Change in velocity = (20 m/s west) - (15 m/s west)
Change in velocity = 5 m/s west
Acceleration = (5 m/s west) / (5 seconds)
Acceleration = 1 m/s west
Describe the environment of Antarctica.
Answer:
Antarctica is a desert. It does not rain or snow a lot there. When it snows, the snow does not melt and builds up over many years to make large, thick sheets of ice, called ice sheets. Antarctica is made up of lots of ice in the form of glaciers, ice shelves and icebergs.
A reversible reaction is in
_______ when forward and reverse
directions of the reaction occur at the same rate so there is no overall change in the
amounts of reactants and products.
Answer:
Equilibrium
Explanation:
Equilibrium is a special situation or stage of a reactionAt equilibrium the concentrations of reactants and products are equalThe rate of change of forward and backward reaction is also sameA cat pushes a porcelain statue off a bookshelf with a speed of 0.5 m/s and it smashed on the floor 0.85 sec later.
Answer:
167?
Explanation:
i added both
A student in gym class swings from a rope and they are moving 5 m/s at the bottom of their swing. What is the height they reach above the floor before swinging back down?
1/2v^2=gh g = 9.8 m/s^2
A 2.55 m
B. 1.28 m
c. 5m
D. 12.5 m
Answer:
A
Explanation:
A wholesale club sells eggs by the dozen .Does the table show a proportional relationship between the number of dozen of eggs cost?
Answer:
12 dozen
Explanation:
Answer:
The table is proportional.
Explanation:
You would do 21/6 to get 3.5. Then 28/8 to get 3.5. After 35/10 to get 3.5. Finally 49/14 to get 3.5. If each answer (3.5) is the same than it is proportional.
hope i helped
If you are driving 80 km/h along a straight road and you look to the side for 1.7 s , how far do you travel during this inattentive period?
Express your answer using two significant figures.
Given the speed of the driver and the time elapsed, distance traveled during his inattentive period is 0.037 kilometers.
How far did the driver travel during the inattentive period?Speed is simply referred to as distance traveled per unit time.
Mathematically, Speed = Distance ÷ time.
Given the data in the question;
Speed = 80 km/hTime = 1.7sDistance travelled = ?First, convert 1.7 seconds to hours.
Time = 1.7s = (1.7 / (60×60)hr = 1.7/3600 hrs
Now, find the distance traveled during the inattentive period.
80 km/h = Distance ÷ 1.7/3600 hrs
Distance = 80 km/h × 1.7/3600 hrs
Distance = 136/3600 km
Distance = 0.037 km.
Given the speed of the driver and the time elapsed, distance traveled during his inattentive period is 0.037 kilometers.
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A boy throws an arrow at an original speed of 2m / s to create an angle 0 referring to the balloon at a distance of 3m from the departure point. Calculate the angle 0 and the height of the arrow. Let g = 10m / s2.
Calculate the horizontal component of the velocity. The horizontal component of the velocity is given by:
v_x = v * cos(theta)
where v is the original speed of the arrow and theta is the angle of projection.In this case, v = 2 m/s and theta is unknown. Solving for theta, we get:
theta = arccos(v_x / v)
theta = arccos(2 / 2) = 45 degrees
Calculate the vertical component of the velocity. The vertical component of the velocity is given by:
v_y = v * sin(theta)
In this case, v = 2 m/s and theta = 45 degrees. Solving for v_y, we get:
v_y = 2 * sin(45 degrees) = 1.414 m/s
Calculate the time of flight. The time of flight is given by:
t = 2 * v_y / g
In this case, v_y = 1.414 m/s and g = 10 m/s^2. Solving for t, we get:
t = 2 * 1.414 / 10 = 0.283 seconds
Calculate the height of the arrow. The height of the arrow is given by:
y = v_y * t - 0.5 * g * t^2
In this case, v_y = 1.414 m/s, t = 0.283 seconds, and g = 10 m/s^2. Solving for y, we get:
y = 1.414 * 0.283 - 0.5 * 10 * 0.283^2 = 0.303 meters
Therefore, the angle of projection is 45 degrees and the height of the arrow is 0.303 meters.
Draw the electromagnetic (EM) spectrum in a long bond paper then arranged from longest to shortest wavelength and arranged from lowest to highest frequency.
ANSWER:
STEP-BY-STEP EXPLANATION:
The electromagnetic spectrum (EM) is the range of all types of radiation. Radiation is energy that travels and spreads out as it goes: visible light from a lamp in your house and radio waves from a radio station are two types of electromagnetic radiation. The other types of EM radiation that make up the electromagnetic spectrum are microwaves, infrared light, ultraviolet light, X-rays, and gamma rays.
We can organize them as follows:
A coil with 50 turns of wire is wrapped around a hollow tube with an area of 3.6 m2. Each turn has the same area as the tube. A uniform magnetic field is applied at a right angle to the plane of the coil. If the field increases uniformly from 0.00 T to 0.88 T in 1.85 s, find the magnitude of the induced emf in the coil. If the resistance in the coil is 5.0 Ω, find the magnitude of the induced current in the coil.
Hi there!
Using Faraday's and Lenz's Law:
\(\epsilon = -N\frac{d\Phi_B}{dt}\)
ε = Induced emf (V)
N = number of loops/turns
Φ = Magnetic flux (Wb)
Magnetic flux is given as:
\(\Phi_B = \oint B \cdot dA = B\cdot A\)
Since the area of the loops remains constant, we can take area out of the time derivative. Thus:
\(\frac{d\Phi_B}{dt} = A * \frac{dB}{dt} = A * \frac{\Delta B}{\Delta t}\)
Also, since the magnetic field is applied at a right angle to the plane of the coil, that means that the field is PARALLEL to the area vector of the plane of the coil. (points normal to the surface). This means we can disregard the dot product since cos(180) = 1.
Plug in the given values.
\(\epsilon = - 50 * 3.6 * \frac{0.88 - 0}{1.85} = -85.622 V\)
The negative sign simply means that the induced emf is in the opposite direction in order to oppose the increase in magnetic flux, so the magnitude is simply:
\(\epsilon = \boxed{85.622 V}\)
For the current, we can use Ohm's Law:
\(i = \frac{\epsilon}{R}\\\\i = \frac{85.622}{5} = \boxed{17.124 A}\)
please help very easy 5th grade work giving brainliest
Answer:
the answer is option B because opposit sides of the magnets attract each other