a 2.50-m segment of wire supplying current to the motor of a submerged submarine carries 1000 a and feels a 4.00-n repulsive force from a parallel wire 5.00 cm away. what is the direction of the current in the other wire?

The answer is b. 16 N.

The tension in the string at the top of the path is 16 N.

At the top of the path, the rock is moving at its highest speed. The tension in the string is providing the centripetal force that keeps the rock moving in a circular path. The centripetal force is equal to the mass of the rock times its velocity squared, divided by the radius of the circle.

F_c = m * v^2 / r

In this case, the mass of the rock is 0.30 kg, the velocity of the rock is 12.0 rad/s, and the radius of the circle is 0.25 m. Substituting these values into the formula above, we get:

F_c = 0.30 kg * (12.0 rad/s)^2 / 0.25 m = 16 N

Therefore, the tension in the string is 16 N.

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The initial kinetic energy increases by the square of the ratio of the masses. The work done by the force increases by the ratio of the masses.

What is kinetic energy?
The amount of work an object performs as a result of its motion is measured in terms of kinetic energy. Kinetic energy is used in everyday motions like walking, jumping, throwing, as well as falling. Let's get acquainted with the idea of kinetic energy in this article. We must exert force on an object to accelerate it. We have to put in the effort to use force. Energy is transferred when work is done on to an object, and the object then moves at a new, constant speed. The energy that is transferred is referred to as kinetic energy, and it is influenced by the mass and speed attained.

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Answer:

D

Explanation:

the answer is D to me

the answer is D to me

Explanation:

Energy conservation is the effort made to reduce the consumption of energy by using less of an energy service. This can be achieved either by using energy more efficiently (using less energy for a constant service) or by reducing the amount of service used (for example, by driving less). Energy conservation is a part of the concept of Eco-sufficiency. Energy conservation reduces the need for energy services and can result in increased environmental quality, national security, personal financial security and higher savings.It is at the top of the sustainable energy hierarchy. It also lowers energy costs by preventing future resource depletion.

Energy can be conserved by reducing wastage and losses, improving efficiency through technological upgrades and improved operation and maintenance. On a global level energy use can also be reduced by the stabilization of population growth.

Energy can only be transformed from one form to other, such as heat energy to motive power in cars, or kinetic energy of water flow to electricity in hydroelectric power plants. However machines are required to transform energy from one form to other. The wear and friction of the components of these machine while running cause losses of very high amounts of energy and very high related costs. It is possible to minimize these losses by adopting green engineering practices to improve life cycle of the components.

Hope this helps u ......Explanation:

The answer is The boiling Point as the transition from liquid to gas occurs at the boiling point.

The actuality that it changes from liquid to vapor indicates that you are working with the substance's boiling point.

The material is pure if its temperatures does not change when it turns phases. Since water turns liquid at 100°C in this situation, water is likely the culprit.

The temperature at which a specific liquid will boil is known as its boiling point. For instance, water reaches its boiling point at 1 atm, or 100 degrees Celsius. The temperature of the liquid, the pressure of the atmosphere, and the pressure of the vapor all affect its boiling point.

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The velocity of the object is  23.24 m/s.

An attribute of an object moving in a circular route is centripetal acceleration. Any object moving in a circle with an acceleration vector pointing in the direction of the circle's center is said to be experiencing centripetal acceleration.

Given that an object is experiencing a centripetal acceleration of 36m/s^2.

Radius of the circle: r = 15 m.

Then, the velocity of the object is = √(36×15) m/s = 23.24 m/s.

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20 degrees.

Sound travels faster when the medium (something to travel through) is less dense.

For example, Air is less dense than water, water is less dense than a solid.

In this case, since we are working with water, the colder the temperature of water, the denser it is. Likewise, the hotter the temperature of water, it gets less denser.

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The sound travels slowest through 20 degree temperature of water. The correct option is a.

A sound wave is a result of compression and rarefaction, by which sound is propagated in a material medium such as air.

Sound travels faster when the medium is less dense. In case of air, which is less dense than water.

When the temperature is increased, the object becomes less dense than previous state of the object. The sound wave travels faster in rarer medium than the denser medium.

So, sound travels slowest through 20 degree temperature of water.

Thus, the correct option is a.

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Answer:

The values of gravitational force and gravitational constant become same or equal when product of masses involved equals the square of distance between them.

Answer:

1.911665 x10^2

Explanation:

if u have a scientific calculator such as casio fx-991ES plus

just do shift mode 7 7

Answer:

but I can tomorrow if you have time can you come to the meeting tonight but yyyy the person who is this and what

Explanation:

gyyyyyyyyyyyyyyyyy the number of the person who is this and what is the

The mass hung from it is also doubled,  4% much stretching will be observed.

What is mass?

A substance or object's mass is a measurement of how much matter there is in it. Smaller masses can be measured in grams instead of kilograms (kg), which is the standard SI unit for mass (g). You would use a balance to calculate mass.

What is modulus?

The ratio of the stress that a material experiences under an applied strain is known as the Young's modulus. The strain is the percentage of the starting length that represents the amount of material deformation, such as the change in length in an extensional experiment.

Therefore,  the mass hung from it is also doubled,  4% much stretching will be observed.

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Answer:

D. Alpha

This is because it's unlikely for it to reach living cells inside the body

For a refrigerant 134-a refrigerator, maintaining a refrigerated space at -10°C requires a specific evaporator pressure to achieve the desired cooling effect. In this case, we are asked to recommend between 0.12 or 0.14 MPa for the evaporator pressure and provide a justification for our choice.


Based on the refrigerant pressure-temperature chart for 134-a, we can see that the saturation temperature for -10°C is approximately -23.4°C. To achieve this temperature, we need to ensure that the evaporator pressure is below the corresponding saturation pressure for -23.4°C, which is 0.139 MPa. Therefore, a pressure of 0.12 MPa would be sufficient to maintain the refrigerated space at -10°C.

A refrigerant 134-a refrigerator that needs to maintain a refrigerated space at -10°C should have an evaporator pressure of 0.12 MPa. This pressure level is sufficient to achieve the desired temperature without risking damage to the system or compromising its efficiency and performance.

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Answer:

Half

Explanation:

You only have to exert a force equal to half the weight of the load to lift it.

Answer:

A: Half

Explanation:

Electromyography (EMG) measures muscle response or electrical activity in response to a nerve's stimulation of the muscle. The test is used to help detect neuromuscular abnormalities.

Electromyography (EMG) :

(EMG) detects the electrical activity that occurs when a muscle is stimulated by a nerve. The test is used to identify aberrant neuromuscular function. One or more tiny needles, commonly known as electrodes, are introduced through the skin and into the muscle during the test. An oscilloscope is then used to display the electrical activity that the electrodes picked up (a monitor that displays electrical activity in the form of waves). In order to hear the activity, an audio amplifier is employed. The electrical activity of muscles during rest, a light contraction, and a strong contraction is measured by EMG. At rest, muscle tissue doesn't typically create any electrical signals. A brief period of activity can be seen on the oscilloscope when an electrode is introduced, but there should be no signal beyond that.

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Distance traveled up the slope by the disk: 0.190 meters. Distance traveled up the slope by the ring: 0.196 meters.

To solve this problem, we can use the principles of conservation of energy and rotational kinetic energy.

Given:

Mass of the disk (m_disk) = 750 g = 0.75 kg

Mass of the ring (m_ring) = 760 g = 0.76 kg

Diameter of both disk and ring (d) = 15 cm = 0.15 m

Initial velocity (v) = 1.7 m/s

Angle of the slope (θ) = 13°

Part A:

For the disk:

The moment of inertia of a disk about its center is given by I_disk = (1/2) * m_disk * (r_disk)^2,

where r_disk is the radius of the disk. Since the diameter is given, we can calculate the radius as r_disk = d/2.

For the disk, the total kinetic energy (KE_disk) is the sum of translational and rotational kinetic energy:

KE_disk = (1/2) * m_disk * v^2 + (1/2) * I_disk * ω^2,

where ω is the angular velocity.

For rolling without slipping, the linear velocity is related to the angular velocity by v = ω * r_disk.

At the highest point of the slope, the disk will momentarily stop before rolling back down. At this point, the kinetic energy is converted into potential energy.

Setting KE_disk = 0.75 * 9.8 * h_disk, where h_disk is the height the disk travels up the slope, we can solve for h_disk.

Part B:

For the ring:

The moment of inertia of a thin ring about its center is given by I_ring = m_ring * (r_ring)^2,

where r_ring is the radius of the ring.

Using similar calculations as in Part A, the total kinetic energy (KE_ring) is given by:

KE_ring = (1/2) * m_ring * v^2 + (1/2) * I_ring * ω^2.

At the highest point of the slope, the ring will momentarily stop before rolling back down. Again, the kinetic energy is converted into potential energy.

Setting KE_ring = 0.76 * 9.8 * h_ring, where h_ring is the height the ring travels up the slope, we can solve for h_ring.

Let's calculate the values for both parts:

Part A:

r_disk = 0.15/2 = 0.075 m

I_disk = (1/2) * 0.75 * (0.075)^2 ≈ 0.00202 kg·m^2

KE_disk = (1/2) * 0.75 * 1.7^2 + (1/2) * 0.00202 * ω^2

Setting KE_disk = 0.75 * 9.8 * h_disk, we can solve for h_disk.

Part B:

r_ring = 0.15/2 = 0.075 m

I_ring = 0.76 * (0.075)^2 ≈ 0.00317 kg·m^2

KE_ring = (1/2) * 0.76 * 1.7^2 + (1/2) * 0.00317 * ω^2

Setting KE_ring = 0.76 * 9.8 * h_ring, we can solve for h_ring.

By solving the equations and plugging in the values, we can find the respective heights traveled by the disk and the ring up the slope.

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Answer:

3 767 400 joules

Explanation:

4.186 J/g-C   is the specific heat of water

25  to 115  is 90 degrees C change

10 000 g   is 10 kg of water

10 000 * 90 * 4.186 = 3 767 400 Joules

Answer: 570 J

Explanation:

The amount of heat gained by the piece of zinc can be calulctaed using   ∆Q = mc∆T

=> ∆T = 36-26 = 10°C

m = 0.15 kg, s = 380J/kg/°C

=> ∆Q = 0.15 x 380 x 10

= 570J

Answer:the object does not have displacement

Explanation:

The charge Q inside the box, after applying Gauss's law is ε₀ \(E a^2\).

Since the electric field is uniform and vertically directed, the electric field lines will be parallel to each other, as shown in the figure.

Let's apply Gauss's law to a cube with a length of side x, where x < a. The cube is shown in blue in the figure. The electric flux through the top and bottom faces of the cube are \(E x^2\) and \(2E x^2\), respectively, since the electric field is uniform on each face.

By Gauss's law, the electric flux through any closed surface is equal to the charge enclosed by the surface divided by the permittivity of free space (ε₀). The cube encloses a charge Q, so the electric flux through the cube is Q/ε₀. Therefore, we have:

\(E x^2 + 2E x^2 = Q/ε₀\)

Simplifying, we get:

Q = ε₀\(E a^2\)

Therefore, the charge Q inside the box is ε₀ \(E a^2.\)

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When light passes from air to a silica fiber with an index of refraction of 1.44, and the incident angle is 38 degrees, the refracted angle can be calculated using Snell's law.

The refracted angle in this case would be approximately 24.2 degrees. If the light were coming from a region with an index of refraction of 1.33 (such as water), the refracted angle would be different.

Snell's law relates the angles of incidence and refraction to the indices of refraction of the two media involved. It can be expressed as n1sin(θi) = n2sin(θr), where n1 and n2 are the indices of refraction of the two media, θi is the angle of incidence, and θr is the angle of refraction.

For the first scenario, where the light is coming from air and entering a silica fiber with n = 1.44, and the incident angle is θi = 38 degrees, we can solve Snell's law for the refracted angle. Plugging in the values, we get:

1sin(38) = 1.44sin(θr)

sin(θr) = (1*sin(38))/1.44

θr ≈ 24.2 degrees

Therefore, the refracted angle in this case would be approximately 24.2 degrees.

For the second scenario, where the light is coming from a region with n = 1.33 (such as water) and entering the silica fiber with n = 1.44, the refracted angle would be different. The specific value of the refracted angle would depend on the incident angle, which is not provided in the question. However, we can determine that the refracted angle would be smaller compared to the first scenario because water has a lower index of refraction than air. This means that light would bend less when entering the fiber from water compared to air.

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At t = 10.0 s, the height of the rocket above the surface of the earth is 200 m. the speed of the rocket when it is 205 m above the surface of the earth is 20.64 m/s.

To calculate height of the rocket, we can use the equation of motion: s = 1/2*a*t^2. Therefore, the height of the rocket is: s = 1/2*2.90m/s^2*(10.0s)^2 = 200 m

To calculate the speed of the rocket when it is 205 m above the surface of the earth, we can use the equation of motion: v^2 = 2as

Therefore, the speed of the rocket when it is 205 m above the surface of the earth is v = sqrt(2*2.90m/s^2*205m) = 20.64 m/s.

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Knowing that all engines waste some energy helps engineers build a better engine because it allows them to identify and minimize energy losses, leading to improved efficiency and performance.

Here is a step-by-step explanation:

1. Understanding energy waste: By recognizing that all engines inherently waste some energy during their operation, engineers can focus on identifying the specific areas where energy is being lost.

2. Energy loss sources: Engineers can analyze different components and processes within the engine to determine the sources of energy waste. These sources can include friction, heat transfer, exhaust gases, and inefficient combustion.

3. Minimizing friction: Friction between moving parts can cause energy loss. Engineers can employ techniques such as using high-quality lubricants, optimizing bearing surfaces, and reducing unnecessary mechanical contact to minimize friction and enhance efficiency.

4. Improving heat transfer: Heat transfer inefficiencies can result in energy loss. Engineers can develop strategies to improve the transfer of heat within the engine, such as using advanced cooling systems, optimizing heat exchangers, and incorporating insulation where appropriate.

5. Enhancing combustion efficiency: Inefficient combustion processes can lead to energy waste. Engineers can work on optimizing fuel-air mixture ratios, ignition timing, and combustion chamber designs to ensure more complete and efficient burning of the fuel.

6. Utilizing exhaust gas energy: Exhaust gases contain a significant amount of energy that is often wasted. Engineers can incorporate technologies such as turbochargers or waste heat recovery systems to capture and reuse this energy, thus improving overall engine efficiency.

7. Conclusion, Knowing that all engines waste some energy allows engineers to identify and minimize energy losses, resulting in the development of better engines with improved efficiency and performance.

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Answer: 9

Explanation: because you would add 13+4=17, then you would add 27+5=33, so then 4+5=9 so there's your answe

Space telescopes have the advantage of being above the blurring effects of the Earth's atmosphere.

A surrounding is a layer of fuel or layers of gases that envelop a planet and is held in a region through the gravity of the planetary frame. A planet retains its surroundings whilst the gravity is exceptional and the temperature of the surroundings is low. A stellar ecosystem is the outer area of a celeb, which includes the layers above the opaque photosphere; stars of low temperature may have outer atmospheres containing compound molecules.

The atmosphere of Earth consists of nitrogen (78%), oxygen (21%), argon (0.9%), carbon dioxide (0.04%), and trace gases. most organisms use oxygen for breathing; lightning and bacteria perform nitrogen fixation to provide ammonia that is used to make nucleotides and amino acids; flora, algae, and cyanobacteria use carbon dioxide for photosynthesis.

The layered composition of the ecosystem minimizes the damaging results of daylight, ultraviolet radiation, solar wind, and cosmic rays to defend organisms from genetic harm. The modern composition of the atmosphere of the Earth is made from billions of years of biochemical modification of the paleo atmosphere by residing organisms.

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To estimate the distance to star p, we need more information. The angular distance between stars A and B gives us an idea of their separation on the sky, but we also need to know their actual physical separation and distance from Earth.

Assuming that stars A and B are physically close to each other and at roughly the same distance from Earth, we can use their angular separation to estimate their physical separation.

For small angles, we can use the approximation that the angular separation (in radians) is approximately equal to the physical separation divided by the distance to the objects:

θ ≈ d/D

where θ is the angular separation, d is the physical separation, and D is the distance to the objects.

If we assume that the physical separation between stars A and B is about the same as the distance between star p and the line connecting stars A and B, then we can use the same formula to estimate the distance to star p:

θ ≈ d/Dp

where θ is the angular separation between stars A and B (0.5 arcseconds), d is the physical separation between stars A and B, and Dp is the distance to star p.

Without more information about the physical separation between stars A and B, we cannot estimate the distance to star p.

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The resistance of the gold wire cannot be determined with the information given. The resistance of a wire depends on several factors, including its length, cross-sectional area, and resistivity.

While we know the resistance of the aluminum wire, we do not know any of these other factors for the gold wire. Additionally, the resistivity of gold is different from that of aluminum, so even if we did know all the other factors, we could not simply use the same resistance value for the gold wire.

Therefore, to determine the resistance of the gold wire, we would need more information, such as its length and cross-sectional area.

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Answer:

We can use Coulomb's law to solve this problem:

F = k * q1 * q2 / r^2

where F is the force between the two charges, k is Coulomb's constant (k = 9 x 10^9 N m^2 / C^2), q1 and q2 are the magnitudes of the charges, and r is the distance between them.

We know the force F, the distance r, and the magnitude of one of the charges q1. We can rearrange the equation to solve for the magnitude of the other charge q2:

q2 = F * r^2 / (k * q1)

Substituting the values we have:

q2 = (250 N) * (0.15 m)^2 / (9 x 10^9 N m^2 / C^2 * 6.5 x 10^-5 C)

Simplifying:

q2 = 8.65 x 10^5 C

Therefore, the magnitude of the other charge is 8.65 x 10^5 C.