Answer:
Velocity of each object is 17.43 cm/s towards the rightExplanation:
Momentum = Mass *velocity
Before Collision
Momentum of 28.5-g object moving to the right at 18.5 cm/s = 28.5 * 18.5
= 527.25 gcm/s
Momentum of 12.5-g object moving to the right at 15.0 cm/s = 12.5 * 15.0
= 187.5 gcm/s
Sum of their momentum before collision = 527.25 + 187.5 = 714.75 gcm/s
After collision
Momentum of the bodies = (28.5+12.5)v = 41v
v = common velocity of both objects
According to law of conservation of momentum, the sum of momentum of the bodies before collision is equal to their sum after collision.
41v = 714.75
v = 714.75/41
v = 17.43 cm/s (since their common velocity is positive, the direction will be to the right)
Since both objects move with the same velocity after collision, each object will have the same velocity which is 17.43 cm/s after the collision
5. Elements combine to form
O compounds
O molecules
atoms
mixtures the gen
Elements combine to form compounds. The correct answer is A.
Elements combine with each other in chemical reactions to form compounds. A compound is a substance composed of two or more different elements chemically combined in a fixed ratio by mass. For example, water is a compound composed of hydrogen and oxygen in a fixed ratio of 2:1 by mass.
B. Molecules are formed when two or more atoms combine chemically, but these atoms can be of the same element or different elements. For example, oxygen gas (O2) is a molecule composed of two oxygen atoms.
C. Atoms are the smallest unit of matter that retains the properties of an element. Atoms do not combine to form other atoms or compounds.
D. Mixtures are composed of two or more substances physically mixed together, but the substances retain their individual properties and can be separated by physical means. Mixtures are not formed by the chemical combination of elements. Examples of mixtures include air and saltwater.
Therefore, The correct answer is option A.
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How many magnetic pole reversals has Earth endured in the last 265 million years if the average time between reversals is 700,000 years?
Explanation:
265 000 000 yrs / 700 000 yrs/reversal = 378.6 reversals
(round as appropriate)
A 5 kg block is released from rest at the top of a quarter- circle type curved frictionless surface. The radius of the curvature is 3.8 m. When the block reaches the bottom o the curvature it then slides on a rough horizontal surface until it comes to rest. The coefficient of kinetic friction on the horizontal surface is 0.02.
a. What is the kinetic energy of the block at the bottom of the curved surface?
b. What is the speed of the block at the bottom of the curved surface?
c. Find the stopping distance of the block?
d. Find the elapsed time of the block while it is moving on the horizontal part of the track.
e. How much work is done by the friction force on the block on the horizontal part of the track?
Answer:
a. 186.2 J b. 8.63 m/s c. 190 m d. 43.2 s e. 186.2 J
Explanation:
a. From conservation of energy, the potential energy loss of block = kinetic energy gain of the block.
So, U + K = U' + K' where U = initial potential energy of block = mgh, K = initial kinetic energy of block = 0, U' = final potential energy of block at bottom of curve = 0 and K' = final kinetic energy of block at bottom of curve.
So, mgh + 0 = 0 + K'
K' = mgh where m = mass of block = 5 kg, g = acceleration due to gravity = 9.8 m/s², h = initial height above the ground of block = radius of curve = 3.8 m
So, K' = 5 kg × 9.8 m/s² × 3.8 m = 186.2 J
b. Since the kinetic energy of the block K = 1/2mv² where m = mass of block = 5 kg, v = velocity of block at bottom of curve
So, v = √(2K/m)
= √(2 × 186.2 J/5 kg)
= √(372.4 J/5 kg)
= √(74.48 J/kg)
= 8.63 m/s
c. To find the stopping distance, from work-kinetic energy principles,
work done by friction = kinetic energy change of block.
So ΔK = -fd where ΔK = K" - K' where K" = final kinetic energy = 0 J (since the block stops)and K' = initial kinetic energy = 186.2 J, f = frictional force = μmg where μ = coefficient of kinetic friction = 0.02, m = mass of block = 5 kg, g = acceleration due to gravity = 9.8 m/s² and d = stopping distance
ΔK = -fd
K" - K' = - μmgd
d = -(K" - K')/μmg
Substituting the values of the variables, we have
d = -(0 J - 186.2 J)/(0.02 × 5 kg × 9.8 m/s²)
d = -(- 186.2 J)/(0.98 kg m/s²)
d = 190 m
d. Using v² = u² + 2ad where u =initial speed of block = 8.63 m/s, v = final speed of block = 0 m/s (since it stops), a = acceleration of block and d = stopping distance = 190 m
So, a = (v² - u²)/2d
substituting the values of the variables, we have
a = (0² - (8.63 m/s)²)/(2 × 190 m)
a = -74.4769 m²/s²/380 m
a = -0.2 m/s²
Using v = u + at, we find the time t that elapsed while the block is moving on the horizontal track.
t = (v - u)/a
t =(0 m/s - 8.63 m/s)/-0.2 m/s²
t = - 8.63 m/s/-0.2 m/s²
t = 43.2 s
e. The work done by friction W = fd where
= μmgd where f = frictional force = μmg where μ = coefficient of kinetic friction = 0.02, m = mass of block = 5 kg, g = acceleration due to gravity = 9.8 m/s² and d = stopping distance = 190 m
W = 0.02 × 5 kg × 9.8 m/s² × 190 m
W = 186.2 J
The potential energy of the loss of the block will be equal to the kinetic energy gain. The kinetic energy of the block is 186.2 J at the bottom of the curved surface.
The potential energy of the loss of the block will be equal to the kinetic energy gain.
So,
\(U = mgh\)
Where,
\(U\) - potential energy
\(m\) - mass of block = 5 kg
\(g\) - gravitational acceleration = 9.8 m/s²
\(h\) = height = radius of curve = 3.8 m
Put the values in the formula,
\(U = 5 \times 9.8 \times 3.8 \\\\ U = 186.2 \rm \ J\)
Therefore, the kinetic energy of the block is 186.2 J at the bottom of the curved surface.
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A piano has been pushed to the top of the ramp at the back of a moving van. The workers think it is safe, but as they walk away, it begins to roll down the ramp. Neglect the friction between the piano and the ramp.
If the back of the truck is 1.0 m above the ground and the ramp is inclined at 24 ∘, how much time do the workers have to get to the piano before it reaches the bottom of the ramp?
The time the workers have to get to the piano before it reaches the bottom of the ramp is 0.7 second.
What is the distance travelled by the piano?The distance travelled by piano is calculated by applying the following formula as shown below.
sin (24) = h / L
L = h / sin (24)
where;
h is the height of the truck above the groundL is the distance travelled by piano along the rampL = ( 1 m ) / ( sin 24 )
L = 2.46 m
The time taken for the piano to reach the ground is calculated as follows;
s = ut + ¹/₂gt²
where;
u is the initial velocity of the pianot is the time s is the distance travelled = LL = 0 + ¹/₂gt²
t = √ ( 2L / g )
t = √ ( 2 x 2.46 / 9.8 )
t = 0.7 second
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What are the first three elements of a press release?
Answer: headline, dateline, introduction
Explanation: its correct im not explaining
2. A 7 kg. Mass is moved across the table at 25 m/sec. What force caused the acceleration?
A 7 kg mass moving across the table at an acceleration of 25 m\(/s^2\)requires a force of 175 N.
To determine the force required to cause the acceleration of a 7 kg mass moving across the table at 25\(m/s^2\), we can use Newton's second law of motion, which states that the force acting on an object is equal to its mass multiplied by its acceleration.
Given:
Mass (m) = 7 kg
Acceleration (a) = 25 \(m/s^2\)
We can substitute these values into the equation:
Force (F) = mass (m) * acceleration (a)
F = 7 kg * 25 \(m/s^2\)
F = 175 kg·\(m/s^2\)
Therefore, the force required to cause the acceleration of the 7 kg mass is 175 kg·\(m/s^2\).
To understand the calculation, we need to know that force is a measure of how much an object accelerates when a certain amount of mass is acted upon by that force. In this case, the mass of the object is 7 kg, and it is experiencing an acceleration of 25\(m/s^2\).
By multiplying the mass and acceleration together, we find that the force required is 175 kg·\(m/s^2\). This unit, also known as a Newton (N), represents the force required to accelerate a 1 kg mass at a rate of 1 \(m/s^2\)
In summary, the force required to cause the acceleration of the 7 kg mass across the table at 25 \(m/s^2\) is determined to be 175 kg·\(m/s^2\). This calculation follows Newton's second law of motion and shows the relationship between mass, acceleration, and force.
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state Newton's first law of motion in words
Answer:
An unmoving object will remain unmoving and a moving object in motion will continue to be in motion with the same velocity unless an external force acts upon it.
a car accelerate at 9 m/s squared. Assuming the car starts from rest how far will it travel in 10 seconds
Answer:
450m
Explanation:
\(s = ut + \frac{1}{2} a {t}^{2} \\ s = 0 + t + \frac{1}{2} a {t}^{2} \\ \frac{1}{2 } \times 9 \times {10}^{2} = 450m\)
A carousel is (more or less) a disk of mass, 15,000 kg, with a radius of 6.14. What torque must be applied to create an angular acceleration of 0.0500 rad/s^2?round to 3 significant figures
(Plssss help me im suffering from severe brainrot)
To calculate the torque required to create an angular acceleration, we can use the formula:
Torque = Moment of Inertia × Angular Acceleration
The moment of inertia of a disk can be calculated using the formula:
Moment of Inertia = (1/2) × Mass × Radius^2
Given:
Mass = 15,000 kg
Radius = 6.14 m
Angular Acceleration = 0.0500 rad/s^2
First, calculate the moment of inertia:
Moment of Inertia = (1/2) × Mass × Radius^2
Moment of Inertia = (1/2) × 15,000 kg × (6.14 m)^2
Next, calculate the torque:
Torque = Moment of Inertia × Angular Acceleration
Torque = Moment of Inertia × 0.0500 rad/s^2
Now, let's plug in the values and calculate:
Moment of Inertia = (1/2) × 15,000 kg × (6.14 m)^2
Moment of Inertia ≈ 283,594.13 kg·m^2
Torque = 283,594.13 kg·m^2 × 0.0500 rad/s^2
Torque ≈ 14,179.71 N·m
Rounding to three significant figures, the torque required to create an angular acceleration of 0.0500 rad/s^2 is approximately 14,180 N·m.
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What happens to the interference fringes if coherent sources is replaced by the headlight of
vehicles?
Answer:
headlight of vehicles use less energy and gives light to very limited area hence electricity can be conserved by doing this
A ball is initially at rest and travels 7.8 m. The ball travels at an acceleration of 6.4 m/s². What is the final velocity of the ball? Give your answer to 1 decimal place.
The final velocity of the ball to one decimal place is approximately 10.0 m/s.
What is the final velocity of the ball?From the third equation of motion:
v² = u² + 2as
Where v is final velocity, u is initial velocity, a is acceleration and s is the distance covered.
Given that:
Ball was initially at rest, initial velocity u = 0acceleretaion a = 6.4 m/s²distance traveled s = 7.8 mFinal velocity v = ?Plug the given values into the abovr formula and solve for the final velocity v.
v² = u² + 2as
v² = 0² + ( 2 × 6.4 m/s² × 7.8 m )
v² = 2 × 6.4 m/s² × 7.8 m
v² = 99.84 m²/s²
v = √( 99.84 m²/s² )
v = 10.0 m/s
Therefore, the final velocity is 10.0 m/s.
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2. The muscles on the right side of your body are controlled by what part of your brain? the right cortex the right hemisphere the left cortex the left hemisphere
Answer:
Motor cortex
Both hemispheres have a motor cortex, with each side controlling muscles on the opposite side of the body (i.e, the left hemisphere controls muscles on the right side of the body).
Explanation:
Coasting due west on your bicycle at 8 m/s, you encounter a sandy patch of road 7.2m
across. When you leave the sandy patch your speed has been reduced to 6.5 m/s. Assuming
the bicycle slows with constant acceleration, what was its acceleration in the sandy patch?
Give your answer in m/s2 and round to the nearest tenth. (0.0)
Answer:
V = (v1 + v2) / 2 = (8 + 6.5) / 2 = 7.25 m/s average speed
t = 7.2 / 7.25 = .993 sec time to cross patch
a = (v2 - v1) / t = (6.5 - 8) / .993 = -1.51 m/s^2 or 1.5 m/s^2
The average velocity for the race is 7.25 m/s if and the acceleration is 1.5 m/s², and the time is 0.99 seconds.
What is linear acceleration?It is defined as the rate of change in linear velocity with respect to time. It is also known as linear acceleration.
It is given that:
Coasting due west on your bicycle at 8 m/s, you encounter a sandy patch of road 7.2 m across.
The bicycle slows with constant acceleration.
As we know,
V = (v1 + v2)/2
Here V is the average velocity
v1 = 8 m/s
v2 = 6.5 m/s
V = (v1 + v2)/2 = (8 + 6.5)/2
V = 7.25 m/s
t = 7.2/7.25
t = 0.993 sec
a = (v2 - v1)/t = (6.5 - 8)/0.993
a = -1.51 m/s²
a = 1.5 m/s²
Thus, the average velocity for the race is 7.25 m/s if the acceleration is 1.5 m/s², and the time is 0.99 seconds.
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A certain satellite travels in an approximately circular orbit of radius 8.8 × 10^6 m with a period of 6 h 12 min. Calculate the mass of its planet from this information.
The mass of the planet is 5.98 × 10^24 kg.
To calculate the mass of the planet, we can use Kepler's Third Law of Planetary Motion. This law states that the square of the period of revolution of a planet around the sun is directly proportional to the cube of the semi-major axis of its orbit.
First, we need to convert the period of the satellite's orbit to seconds. We know that there are 60 minutes in an hour, so the period can be expressed as (6 × 60 + 12) minutes, which equals 372 minutes. Multiplying this by 60 seconds, we get a period of 22,320 seconds.
Next, we need to find the semi-major axis of the orbit. In a circular orbit, the semi-major axis is equal to the radius of the orbit. Therefore, the semi-major axis is 8.8 × 10^6 m.
Now, we can apply Kepler's Third Law to calculate the mass of the planet. The formula is T^2 = (4π^2/GM) × a^3, where T is the period of revolution, G is the gravitational constant, M is the mass of the planet, and a is the semi-major axis of the orbit.
Rearranging the formula, we can solve for the mass of the planet:
M = (4π^2/G) × a^3 / T^2
Plugging in the values, we get:
M = (4 × π^2 / 6.67430 × 10^-11) × (8.8 × 10^6)^3 / (22,320)^2
Evaluating this expression, we find that the mass of the planet is approximately 5.98 × 10^24 kg.
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A wire 48 m long carries a current of 18 A from west to east. If a magnetic field of 8.3 x 10-4 T directed toward the
south is acting on the wire, find the direction and magnitude of the magnetic force. (Remember F = BIL)
0.72 N left
-0.72 N left
0.72 N downward
-0.72 N downward
Using the right-hand rule, we can determine that the magnetic force will be directed upward, perpendicular to both the direction of current and the direction of the magnetic field.
The magnitude of the magnetic force can be calculated using the formula F = BIL, where B is the magnetic field strength, I is the current, and L is the length of the wire. Substituting the given values, we get:
F = (8.3 x 10^-4 T) x (18 A) x (48 m) = 0.72 N
Therefore, the direction and magnitude of the magnetic force is 0.72 N upward. However, the question asks for the direction of the magnetic force, which is to the left (in the westward direction) according to the right-hand rule. Therefore, the answer is -0.72 N left.
PLEASE HELP!!
What did Michael Faraday Discover?
A. The unit for measuring electric currents
B. Gravity
C. Electricity
D. Electric current can create magnetic field
Answer:
D
Explanation:
Michael Faraday is probably best known for his discovery of electromagnetic induction, his contributions to electrical engineering and electrochemistry or due to the fact that he was responsible for introducing the concept of field in physics to describe electromagnetic interaction.
Electromagnetic or magnetic induction is the production of an electromotive force across an electrical conductor in a changing magnetic field.
Electrical engineering is an engineering discipline concerned with the study, design and application of equipment, devices and systems which use electricity, electronics, and electromagnetism.
Electrochemistry is the branch of physical chemistry that studies the relationship between electricity, as a measurable and quantitative phenomenon, and identifiable chemical change, with either electricity considered an outcome of a particular chemical change or vice versa.
if the rest of the solar system were to disappear, the moon would
Answer:
Of course the moon would disappear
Explanation:
The Moon is part of the solar system.
Car P travels due East along a straight highway at a constant speed of 30 m/s. At 9:00
a.m., P passes Exit 17. At precisely the same moment, car Q passes Exit 16, traveling due
West at a constant 26 m/s. Slightly later, car P and car Q pass the same point. Knowing
the exits are exactly 7 km apart, determine how many minutes past 9:00 a.m. the cars pass
each other.
Knowing the exits are exactly 7 km apart, the cars pass each other at 9:29 and 15 seconds a.m.
How to calculate time?The relative velocity of the cars is 30 m/s - 26 m/s = 4 m/s.
The distance between the cars is 7 km = 7000 m.
The time it takes for the cars to pass each other is 7000 m / 4 m/s = 1750 seconds.
1750 seconds is 29 minutes and 15 seconds.
To calculate the time in minutes;
Let:
v_p = the speed of car P (m/s)
v_q = the speed of car Q (m/s)
d = the distance between the cars (m)
t = the time it takes for the cars to pass each other (s)
Given that:
v_p = 30 m/s
v_q = 26 m/s
d = 7000 m
Use the equation for relative velocity to find the velocity of the cars relative to each other:
v_r = v_p - v_q
v_r = 30 m/s - 26 m/s = 4 m/s
Use the equation for distance to find the time it takes for the cars to pass each other:
d = v_r × t
7000 m = 4 m/s × t
t = 7000 m / 4 m/s = 1750 s
Convert 1750 seconds to minutes and seconds:
1750 s = 29 minutes and 15 seconds
Therefore, the cars pass each other at 9:29 and 15 seconds a.m.
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Highway safety engineers want to design roadside barriers that will crumple
in the event that a car drives off the road and collides with them, slowing
down the car more gradually. The average person has a mass of 68 kg and
travels on a highway at a velocity of 27 m/s. If the engineers know that the
maximum force that a person can safely withstand is 1650 N, approximately
how much time is required to crumple the barrier to safely slow the person
with this force?
A 1.5s
B. 0.7 s
C. 1.1 s
D. 2.1 s
The time required to crumple the barrier and safely slow down the person with a force of 1650 N is approximately C, 1.1 seconds.
How to find time?To determine the time required to crumple the barrier and safely slow down the person with a maximum force of 1650 N, use the equation of motion:
F = m × a
where:
F = force
m = mass
a = acceleration
Given:
m = 68 kg
F = 1650 N
Find the acceleration (a) first. Rearranging the equation:
a = F / m
Substituting the values:
a = 1650 N / 68 kg
a ≈ 24.26 m/s²
Now, use the equation of motion to find the time (t):
v = u + at
where:
v = final velocity (0 m/s as the person comes to a stop)
u = initial velocity (27 m/s)
a = acceleration (24.26 m/s²)
t = time
Rearranging the equation:
t = (v - u) / a
Substituting the values:
t = (0 m/s - 27 m/s) / 24.26 m/s²
t ≈ -27 m/s / 24.26 m/s²
t ≈ -1.11 s
The negative sign indicates that the time is in the opposite direction to the initial velocity. Taking the absolute value, the time required to crumple the barrier and safely slow down the person with a force of 1650 N is approximately 1.11 seconds.
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Developer a model diagram that shows how different amounts of GPE are stored in the earth-ball system when the ball is raised to different heights on the ramp
The ball's gravitational potential energy may be calculated in proportion to the velocity obtained by the ball as it rolls down the ramp.
The following is a model of the ball's GPE;
The height of the ball is related to the square of the velocity attained when rolling down the ramp.h ∝ v²
Which is the method used to obtain the model for the GPE of the ball?The gravitational potential energy, GPE, is given as follows;
GPE = m·g·Δh
Where;
m = The mass of the ball
g = The acceleration due to gravity
Δh = The change in elevation of the ball
The gravitational energy of the ball at the ramp's beginning (lowest) point, when h = 0, is 0
When a modest amount of energy is provided to the ball by moving it slowly, it advances up the ramp for a short distance before stopping.
When more energy is provided to the ball, it moves to a higher position on the ramp.
When energy is given to the ball, it is transformed into gravitational potential energy, and the height of the ball reflects the quantity of gravitational potential energy in the ball.
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Put the numbers in the right box
Answer: 2134
Explanation:
I just had this question on my exam
3. Observe: An organelle is a cell structure that performs a specific function. Observe the samples below under the highest magnification. Click the Show labels checkbox to label the organelles. List the organelles and approximate size of the cells in each sample.
Organelles are specialized structures within cells that perform specific functions, such as energy production, protein synthesis, and waste removal.
Some examples of organelles include mitochondria, which produce energy for the cell, and ribosomes, which are involved in protein synthesis.
The size of cells can vary widely depending on the organism and the type of cell. For example, human cells can range from 10 to 30 micrometers in diameter, while bacterial cells are typically much smaller, ranging from 1 to 5 micrometers in diameter.
In summary, organelles are specialized structures within cells that perform specific functions, and the size of cells can vary widely depending on the organism and the type of cell.
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what is the amount of force required to keep a 6 kg object that is in outer space moving with a constant velocity of 2 m/s is _ N
The amount of force required is (V) is v(t) = at.
What is velocity?
The speed of something in a given direction. Velocity is the directional speed of to an object in motion as an indication of its rate of the change in position as in observed from a particular to frame of reference and it's as measured by a particularly standard of time.
Sol-As per the newton's first law of motion.
Vt= vo+at
Here,
velocity at time t is v(t).
Initial velocity is vo.
Acceleration is a and the time is t.
The initial velocity is zero. Put the 0 for vo in above equation.
v(t) = 0+at
v(t)= at
Thus, the acceleration of a falling body (a), the time it takes to fall (t), and its instantaneous velocity when it hits the ground.
(V) is v(t) = at.
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g Design an experiment you can use to determine the mass of the metal cylinder. When you explain your experiment, be sure to mention: What is the underlying model (equation) that you can use to determine the mass from your measurements
Answer:
m = \(\frac{k}{g}\) x,
graph of x vs m
Explanation:
For this exercise, the simplest way to determine the mass of the cylinder is to take a spring and hang the mass, measure how much the spring has stretched and calculate the mass, using the translational equilibrium equation
F_e -W = 0
k x = m g
m = \(\frac{k}{g}\) x
We are assuming that you know the constant k of the spring, if it is not known you must carry out a previous step, calibrate the spring, for this a series of known masses are taken and hung by measuring the elongation (x) from the equilibrium position, with these data a graph of x vs m is made to serve as a spring calibration.
In the latter case, the elongation measured with the cylinder is found on the graph and the corresponding ordinate is the mass
Do we know which has more potential energy? object A or B? Best answer with reasoning gets brainliest.
Answer:
Object C has the most potential energy.
Between A and B, we do not know which has more potential energy.
Explanation:
We know the object with the most potential energy and this is the object at C.
Potential energy is the energy due to the position of a body above the ground surface.
The higher a body is above ground, the more its potential energy.
Potential energy = mass x acceleration due to gravity x height
So;
Object C has the most potential energy.
Between A and B, we do not know which has more potential energy.
This is because, the height and mass of the objects are not quantified using numbers.
Potential energy is a function of mass and height and acceleration due to gravity but acceleration due gravity is a constant.
1. Write down the readings on the side of Figs. 6 (a), (b) and (c) respectively. What is the least count of instrument scale for each of the three measurement tools? Fig. 6 (a) Meterstick (cm)
Fig. 6 (b) Vernier Caliper (cm)
Fig. 6 (c) Micrometer (mm)
2. What is the difference between the measured values 1.05 m and 1.050 m? What factor of a
measurement tool determines the significant figures of a measured value?
Explanation:
This should be right. if any doubt post a comment.
Which describes one feature of the image formed by a convex mirror?????
Answer:
The image formed by a convex mirror will always have its smaller than the size of the object no matter what the position of the object.
Explanation:
The image formed by a convex mirror will always have its smaller than the size of the object no matter what the position of the object.
Also notice that convex mirror always makes virtual images.
Another feature of the convex mirror is that an upright image is always formed by the convex mirror.
An important mirror formula to remember which is applicable for both convex and mirrors
1/f= 1/u + 1/vHere:
'u' is an object which gets placed in front of a spherical mirror of focal
length 'f' and image 'u' is formed by the mirror.
Answer:
right side up
Explanation:
You toss a ball up in the air with an initial velocity of 20.9m/s. How fast will the ball be traveling after 1.2 seconds?
The final velocity of the object is 8.24 m/s.
What is the final velocity?
We have to note that we have to use the equations of motion to be able to obtain the velocity of the object after the said time.
Let us recall that we have that;
Initial velocity = 20.9m/s.
Final velocity = ?
Time taken = 1.2 seconds
Acceleration due to gravity = 9.8 m/s^2
We would then have that;
v = u - gt
v = 20 - (9.8 * 1.2)
v = 8.24 m/s
Thus it would have a final velocity of about 8.24 m/s
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an electricity company claims to generate all of its electricity from environmently friendly energy sources.
the energy sources used by the company are shown in the pie chart
Do you think that the claim made by the company is correct?
The claim made by the company is not correct because gas and nuclear are energy source of pollution.
It is sometimes referred to as a non-conventional or renewable source of energy. For instance, geothermal energy, solar energy, and wind energy. Conventional Source of Energy – Energy sources that are finite and exhaustible are referred to as conventional sources of energy. For instance, fossil fuels like coal, petroleum, etc.
Wind mills may use the kinetic energy that the wind has in large amounts. The windmill's rotation is programmed to drive the turbine, which ultimately produces electricity. In Denmark, more than 25% of all electrical needs are met by electricity. It is referred to as the "country of winds" since a massive network of windmills is used to generate the energy.
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An engine develops a power of 750watts while moving a car at constant velocity 3m/s therefore the work exerted on the car by the engine is. And please I need the solution
The work exerted on the car by the engine is 250 Joules.
What is Work?
Work is a physical quantity that is defined as the force applied to an object over a distance. It is a scalar quantity and is measured in units of joules (J) in the International System of Units (SI). The formula for work is W = F x d, where F is the force applied and d is the distance over which the force is applied.
The work exerted on the car by the engine can be calculated using the formula:
Work = Power x Time
Since the car is moving at a constant velocity, we can calculate the time it takes for the engine to exert the given power by using the formula:
Velocity = Work / Time
So, we can find time by using:
Time = Work / Velocity
Substituting the given values, we have:
Time = (750 watts) / (3m/s)
Therefore, the work exerted on the car by the engine is:
Work = Power x Time
Work = 750 watts x (750 watts / 3m/s)
Work = 750 * 250 Joules
So, the work exerted on the car by the engine is 250 Joules.
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