A 3.0 [V] battery powers a flashlight bulb that has a resistance of 6.0 [O]. How much charge moves through the battery in 10 [min]?

The total force on the bottom of the wading pool, considering the weight of the air and the weight of the water, is  3.47 × 10⁵ Newtons.

To calculate the total force on the bottom of the wading pool, we need to consider the weight of the air and the weight of the water.

Weight of the air:

The pressure contribution from the atmosphere is given as 1.0 × 10⁵ N/m². Since the pressure acts equally in all directions, we can assume it applies uniformly over the surface of the wading pool.

The force due to the weight of the air can be calculated using the formula:

Force = Pressure × Area

Weight of the air:

Area = π × (1.0 m)²

Area = π m²

Force_air = (1.0 × 10⁵ N/m²) × (π m²)

Force_air = 3.14 × 10⁵ N

Weight of the water:

The weight of the water can be calculated using the formula:

Weight = Mass × Acceleration due to gravity

The mass of the water can be determined using its density and the volume of the pool:

Volume = Area × Depth

Volume = π m² × 1.0 m = π m³

Mass = (1000 kg/m³) × (π m³)

Mass = 1000π kg

Weight_water = (1000π kg) × (9.8 m/s²)

Weight_water ≈ 9800π N

Total force on the bottom of the pool:

Total force = Force_air + Weight_water

Total force ≈ 3.14 × 10⁵ N + 9800π N

Total force ≈ 3.14 × 10⁵ N + 30794 N

Using the approximation π ≈ 3.14:

Total force ≈ 3.47 × 10⁵ N

Therefore, the total force on the bottom of the wading pool is approximately 3.47 × 10⁵ Newtons.

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Answer:

Ultrasound imaging (sonography) uses high-frequency sound waves to view inside the body.

Explanation:

The atmospheric pressure of a gas is proportional to the number of gas molecules present in the system. The partial pressure is calculated from the total pressure of a mixture of gases by multiplying the mole fraction of a specific gas in the mixture by the total pressure.

The equation for calculating partial pressure is as follows: Partial pressure = Mole fraction x Total pressureHere, we are required to find the partial pressure of nitrogen in air at an atmospheric pressure of 0.84 atm. The nitrogen in air is approximately 78%, while the remaining 21% is oxygen.

The remaining 1% is made up of several other gases. It implies that the total mole fraction of nitrogen in the air is 0.78. Mole fraction is the ratio of the number of moles of one component to the total number of moles of all components in the mixture.

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The partial pressure of nitrogen in air at an atmospheric pressure of 0.84 atm is calculated by multiplying the total atmospheric pressure by the gas's percent content in the mixture. Using this formula results in a partial pressure of approximately 0.6552 atm for nitrogen.

The partial pressure of a gas in a mixture can be determined using the formula P = (Patm) X (percent content in mixture). The total atmospheric pressure (Patm) is the sum of all the partial pressures of the gas components added together. In the case of nitrogen in the air, which makes up about 78.0% of the content, the partial pressure can be calculated as follows:

P = (0.84 atm) X (78.0%)

Converting the percentage to a decimal ratio gives, P = (0.84 atm) X (0.780)

Therefore, the partial pressure of nitrogen in air at an atmospheric pressure of 0.84 atm would be approximately 0.6552 atm.

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Answer:

11.1

Explanation:

2 hours 15 mins = 2 1/4 hours

2 1/4 hours = 25 miles

1 hour = 25 ÷ 2 1/4 = 25 ÷ 9/4 = 25 x 4/9 = 11.1 miles

Answer:

A manometer is a device similar to a barometer that can be used to measure the pressure of a gas in a vessel. An enclosed pressure gauge is a U-shaped tube with one arm closed, another arm that connects to the electricity to be measured, and a permanent liquid (usually mercury) in between.

This means that the string is vibrating at a fundamental frequency of 340.5 Hz when it is in its first harmonic state.

The fundamental frequency of a string is the lowest frequency at which it vibrates, and is sometimes referred to as the first harmonic. The higher harmonics are integer multiples of the fundamental frequency, so if you know the frequency of one of the higher harmonics, you can find the fundamental frequency.

In this case, you have measured the fourth harmonic, with a frequency of 1,362 Hz. Therefore, the fundamental frequency can be found by dividing the harmonic frequency by the harmonic number:

fundamental frequency = harmonic frequency / harmonic number

fundamental frequency = 1,362 Hz / 4 = 340.5 Hz

The higher harmonics are multiples of the fundamental frequency, so the fourth harmonic will have a frequency of 4 times the fundamental frequency.

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When, a diver leaves the diving board 10.0m above water, at a velocity of 12.0m/s, 60 degree above the horizontal. If he takes 0.75 sec to complete a somersault. Then, the diver can complete 2 somersaults before hitting the water.

We can start by using the kinematic equations to find the time it takes for the diver to reach the water;

Vertical motion equation: y = y₀ + \(V_{0t}\) + 1/2 at²

where y = -10.0 m (taking upward direction as positive)

y₀ = 0

v₀ = 12.0 m/s sin(60°) = 10.4 m/s (taking upward direction as positive)

a = -9.81 m/s² (taking upward direction as positive)

Solving for t, we get; t = 1.50 s

Horizontal motion equation; x = x₀ + \(V_{0t}\) + 1/2 at²

where x = 0 (the diver starts from the diving board)

x₀ = 0

v₀ = 12.0 m/s cos(60°) = 6.00 m/s

a = 0 (assuming no horizontal acceleration)

Solving for t, we get: t = 0.00 s

The time it takes for the diver to complete a somersault is given as 0.75 s, so the number of somersaults the diver can complete before hitting the water is;

Number of somersaults = (time to reach water) / (time per somersault)

= 1.50 s / 0.75 s

= 2.00 somersaults

Therefore, the diver can complete 2 somersaults before hitting the water.

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Answer:

Distancia, S = 2.84 metros

Explanation:

Dados los siguientes datos;

Velocidad inicial = 55 m/s

Velocidad final = 115 m/s

Deceleración = 14500 m/s²

Para encontrar qué tan lejos viajaría el automóvil, usaríamos la tercera ecuación de movimiento;

V² = U² + 2aS

115² = 55² + 2*14500*S

13225 = 3025 + 29000S

29000S = 13225 - 3025

29000S = 10200

S = 29000/10200

Distancia, S = 2.84 metros

The linear speed of the electron is 7.03 x 10¹³ m/s and the angular speed of the electron is 5.6 x 10¹³ rev/s.

The speed of the electron is calculated as follows;

F = ma = mv²/r  ---(1)

F = qvB  ----- (2)

mv²/r = qvB

mv/r = qB

mv = qBr

v = qBr/m

where;

v = (1.6 x 10⁻¹⁹ x 2 x 10³ x 0.2) / (9.1 x 10⁻³¹)

v = 7.03 x 10¹³ m/s

ω = v/r

ω = (7.03 x 10¹³ m/s) / (0.2 m) = 3.51 x 10¹⁴ rad/s

ω = 3.51 x 10¹⁴ rad/s  x 1 rev/2π rad

ω = 5.6 x 10¹³ rev/s

Thus, the linear speed of the electron is 7.03 x 10¹³ m/s and the angular speed of the electron is 5.6 x 10¹³ rev/s.

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Answer:

The answer is d i think so yea

Explanation:

hope u hae  a really good  day

a. The electric potential of the proton at the position of the electron is 2.3 x \(10^4\) volts.

b. The electron's potential energy is -2.2 x \(10^{-18}\) joules.

a. The electric potential of the proton at the position of the electron can be calculated using the formula:

V = kQ/r

where V is the electric potential, k is Coulomb's constant (9.0 x \(10^9\) N × m²/C²), Q is the charge of the proton (1.6 x \(10^{-19}\) C), and r is the distance between the proton and electron (0.053 nm = 5.3 x \(10^{-11}\) m).

Plugging in the values, we get:

V = (9.0 x \(10^9\) N × m²/C²) × (1.6 x \(10^{-19}\) C) / (5.3 x \(10^{-11}\) m) = 2.3 x \(10^4\) V

Therefore, the electric potential of the proton at the position of the electron is 2.3 x \(10^4\) volts.

b. The electron's potential energy can be calculated using the formula:

U = -kQq/r

where U is the potential energy, k is Coulomb's constant, Q is the charge of the proton, q is the charge of the electron (-1.6 x \(10^{-19}\) C), and r is the distance between the proton and electron.

Plugging in the values, we get:

U = -(9.0 x \(10^9\) N×m²/C²) × (1.6 x \(10^{-19}\) C) × (-1.6 x \(10^{-19}\) C) / (5.3 x \(10^{-11}\) m) = -2.2 x \(10^{-18}\) J

Therefore, the electron's potential energy is -2.2 x \(10^{-18}\) joules. The negative sign indicates that the electron is bound to the proton and has a lower potential energy than if it were infinitely far away.

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Answer:

Object D

Explanation:

Use Newton's Second Law to determine the acceleration that each object has.

The force applied in both cases is 50 N, but the mass for object C and object D is different.

Let's start with object C first:

The acceleration object C undergoes is 5 m/s².  

Now let's calculate object D next:

The acceleration object D undergoes is 25 m/s².

Object D has greater acceleration because it has a smaller mass. The object with a smaller mass will accelerate more in order to satisfy Newton's 2nd Law.

Step-Step Explanation:-

As the system is at equilibrium, this means that the reading on the scales have to add to the weight of the student, which means that:-

\(F^{l} + F^{r} = W\)

or

\(F^{l} =W - F^{r} \)As we know that momentum of the system have to be zero, this means that the momentum for each scale is equal and then we have:-

\(1.5F^{l} = 0.5F^{r} \)

Plugin this in the equation for forces, we have:-

\( \frac{0.5}{1.5}F^{r} =W - F^{r}\)

\( = > F^{r} + \frac{0.5}{1.5} = W\)

\( = > \frac{1.5 + 0.5}{1.5}F^{r} = W\)

\( = > F^{r} = \frac{1.5 W}{1.5 + 0.5} \)

\( = > F^{r} = \frac{1.5 W}{2} \)

\( = > \frac{1.5}{2} \times 62 \times 9.8\)

\( = > F^{r} = 455.7\)

Now we know the reading on the right scale, we plug it on the equation for the left scale.

\(F^{l} = W - F^{r} \)

\( = > F^{l} = 62 \times 9.8 - 455.7\)

\( = > F^{l} = 151.9\)

Therefore, the reading on left scale is 151.9 N and the reading on right scale is 455.7 N.

The force of reaction at the left will be  \(F_c=152.057\ N\) and at the right side will be \(F_D=456.165\ N\)

It is given that

Mass of the body m=62kg

Now the Force of the body

\(F_{body} =mg=62\times 9.81=608.22\ N\)

Now to find the effect of this force on the scale we will suppose the left point is C and the right point will be D.

Now to find the at Point D (right side ) Take a moment about point A

So the equation will become

\(F_D\times2=F_{body}\times 1.5\)

\(F_D=\dfrac{F_{body}\times 1.5}{2}\)

\(F_D=\dfrac{ 608.22\times 1.5}{2}\)

\(F_D=456.165\ N\)

Now to find the force on the left side by the equilibrium of the forces

The algebraic sum of all the forces will be zero

\(F_D+F_C-F_{body}=0\)

\(F_C=F_{body}-F_D\)

\(F_C=608.22-456.16=152.05N\)

Thus the force of reaction at the left will be  \(F_c=152.057\ N\) and at the right side will be \(F_D=456.165\ N\)

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Answer:

4 kg at 30 m/s

Explanation:

comparing in pair, the 3rd is more than the 1st, and the 4th is more than the 2nd, so it boils down to the lasts two. calculate, and im pretty sure you get 4 kg at 30 m/s...

Momentum of a ball of mass 2 kg moving at 30 m/s = 2 kg × 30 m/s = 60 kg m/s

Momentum of a ball of mass 3 kg moving at 20 m/s = 3 kg × 20 m/s = 60 kg m/s

Momentum of a ball of mass 4 kg moving at 30 m/s = 4 kg × 30 m/s = 120 kg m/s

Momentum of a ball of mass 5 kg moving at 20 m/s = 5 kg × 20 m/s = 100 kg m/s

So, highest momentum is of a ball of mass 4 kg moving at 30 m/s (120 kg m/s).

Answer:

Cellulose

Explanation:

Cellulose is the carbohydrate which is unable to be digested by body. Adding fiber's (cellulose)  to one's diet reduces blood cholesterol level because soluble fiber  dissolves in water to form a gel, which moves slowly through the intestines binding up fat, dietary cholesterol, bile salts, and sugar to be excreted. Once excreted, these are no longer available to build more cholesterol. Also cellulose remains undigested but is effectively making one gain more calories, so it helps prevents over eating.

To estimate the maximum error in the calculated value of R, we can use the formula for error propagation. Since the resistances R1 and R2 have possible errors of 2%, we can calculate the maximum error in R using the following formula:

where ΔR1 and ΔR2 are the errors in R1 and R2, respectively.

Given:

Let's calculate the maximum error in R:

ΔR1 = 2% of R1 = 0.02 * 20 = 0.4Ω

ΔR2 = 2% of R2 = 0.02 * 55 = 1.1Ω

ΔR/R = sqrt((ΔR1/R1)^2 + (ΔR2/R2)^2)

Therefore, the estimate of the maximum error in R is approximately 0.028Ω.

Value is a tool that shows the basic reason that "a certain way of execution or end state is socially preferable to the opposite way of doing or end state. Value contains elements of judgment that carry an individual's ideas about what is right, good, or wanted.

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Answer:

.75

Explanation:

To find the density of something you simply divide its m by volume. The equation for this looks like; \(d=m/v\)

Plug it in;

12/16=.75

Hope this helps! Have a good rest of your day:)

the answer is 0.75 or 750

Astronomers must use infrared and radio telescopes to examine protostars because of their low temperature and surrounding dust and gas.

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Energy yield is likely to have come from a fission or fusion reaction is 1.4×10^11 kj/mol.

Nuclear fission and nuclear fusion are the two types of nuclear reactions. A large amount of energy is released in both nuclear reactions, but there is a significant difference between the two in terms of the amount of energy generated and the radioactive waste produced.

Nuclear fission and nuclear fusion are two types of nuclear reactions.

Nuclear fission is a nuclear reaction in which a large nucleus is split into two smaller nuclei, releasing a large amount of energy.

Nuclear fusion is a nuclear reaction in which two smaller nuclei combine to form a larger nucleus, releasing a large amount of energy.

This type of reaction is also referred to as thermonuclear fusion since it only occurs at extremely high temperatures. Now, let us determine the energy yield that is likely to have come from a fission or fusion reaction.

From the energy yields given, it is clear that the energy yield of 1.4×10^11 kj/mol is the only one that is likely to have come from a fusion reaction, not a fission reaction.

Fission reactions generate a much smaller amount of energy.

Therefore, the answer to the question is 1.4×10^11 kj/mol.

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Answer:

I would say tension force the last one because the gravitational force brinsg it down more.

Explanation:

Dont mind if its wrong im sorry

Explanation:

HELP PLS

Hang time is the time it takes to reach the peak of your jump.

False

Answer :B: Bulbs B and C will remain lit.

If the switch is closed and Bulb A is removed, Bulbs B and C will remain lit. Option B is correct.

An electric bulb is a gadget that uses electricity to create visible light. It is the most popular type of artificial lighting and is necessary for modern society.

The light bulb is connected to a switch in a parallel configuration. The switch is open, which means there will be a lot of resistance and no current will flow via this route.

Across the parallel connection, the battery would create the same potential difference. Because the current would not go via the open switch, it would instead flow through the light bulb, causing it to illuminate.

If the switch is closed, the circuit get completed, hence the current starts flowing in the circuit and the bulb start glowing.

When one bulb in a series circuit is removed out, the rest of the bulbs stop shining and shut off.

But if bulb A is removed,in that condition the only connected bulb can glow. If the switch is closed and Bulb A is removed, Bulbs B and C will remain lit.

Hence, option B is correct.

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Answer:

Tension is the force that pulls things apart while compression is what squeezes things together.

Unlike velocity, speed is scalar, which means it is described by magnitude only.

A scalar quantity is a quantity that can be defined by its magnitude alone. Magnitude has enough information to describe the quantity.

Examples of scalar quanitites;

Vector quantities refer to the physical quantities that can be described by both magnitude and direction.

Examples of vector quantities include;

Thus, unlike velocity, speed is scalar, which means it is described by magnitude only.

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Answer:

The two philosophers furthermore seem to share the same conception of the conditions of human freedom. For Hegel as well as Kant, a theory of morality and political right devoted to advancing the cause of freedom must require more than just the absence of obstacles preventing the satisfaction of our animal passions.

Explanation:

Hope that help ;)

The velocity of the wave is calculated as to be equal to 100 m/s. To calculate the velocity of a wave, we use the formula as : v = fλv.

The velocity of a wave that has a frequency of 200 Hz and a wavelength of 0.50 m is 100 m/s. The formula for calculating the velocity of a wave is given by:

v = fλ, where v is the velocity of the wave, f is the frequency of the wave, and λ is the wavelength of the wave.

To calculate the velocity of a wave, we use the formula : v = fλv

Substituting the given values into the formula

= (200 Hz)(0.50 m)v

= 100 m/s

Therefore, the velocity of the wave is 100 m/s.

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We have that the exception from the Memory phase is

Timing

From the question we are given

A. encoding

B. storage

C. timing

D. decoding

Generally

Therefore

The the exception from the Memory phase is Timing

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