A 325.0 g piece of gold at 427.0°C is dropped into 200.0 mL of water at 22.0°C. The specific heat capacity of gold is 0.131 J/g°C and water is 4.184 J/g°C. Calculate the final temperature of the mixture.

Answer:  

Therefore, 12 moles of hydrogen makes 8 moles of ammonia.

Using the proportions of the amount of the molecules, we can convert from any reagent or product to any other reagent or product. In the context of this reaction, for every mole of N2 and every 3 moles of H2 we obtain 2 moles of NH3.

Explanation:

;)’ hola

A chemical equation is a symbolic representation of a chemical reaction where reactants are represented on the left, and products on the right.

A chemical equation is said to be balanced when the number of atoms of each element on both sides of the equation are the same.

According to this question, chlorine gas reacts with pottasium iodide to produce iodine and pottasium chloride as follows:

Cl₂ + 2KI → 2KCl + I₂

Therefore, the answers to the questions are as indicated in the main answer part.

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The potential of a standard hydrogen electrode (SHE) can be calculated using the Nernst equation, that is : E(SHE) = E°(SHE) + (0.0592/n) * log([H₂]/[H⁺]).

Here, [H₂] is the concentration of hydrogen gas, [H⁺] is the concentration of hydrogen ions, E°(SHE) is the standard electrode potential of the SHE (which is 0 V), and n is the number of electrons transferred in the reaction.

Given [H₂] = 2.2 atm and [H⁺] = 0.84 M, and assuming n = 2, we can substitute these values into the Nernst equation to calculate E(SHE).

Hence,  potential of a standard hydrogen electrode (SHE) can be calculated using the Nernst equation as : E(SHE) = E°(SHE) + (0.0592/n) * log([H₂]/[H⁺]).

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PDK1 catalyzes the addition of phosphate to the hydroxyl functional group. PDK1, also known as 3-Phosphoinositide-dependent protein kinase 1, is an enzyme that plays a role in signaling pathways within cells.

It is activated when it binds to a phosphatidylinositol-3,4,5-trisphosphate (PIP3) lipid, leading to the transfer of a phosphate group to an activating site on the enzyme.

PDK1 then catalyzes the transfer of phosphate from ATP to a hydroxyl group on serine or threonine residues on a variety of other proteins.

This phosphorylation modulates the function of the protein, often leading to its activation.

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Actually Welcome to the Concept of the Chemical bonds.

Due to the presence of dipole-dipole forces, polar covalent molecules like water tend to be _____ at room temperature.

The answer is Liquids

Water tends to be liquids at the room temperature.

Gamma radiation is the most penetrating. It can penetrate air, paper or thin metal. It may only be stopped by many centimetres of lead or many metres of concrete.

Half life, as stated, is a measurement of the rate at which radioactive material decays.

This process can be artificially produced by people, such as within a nuclear reactor, but can also occur spontaneously in nature. Depending on the particles or energy generated during the reaction, there are many kinds of radioactivity. Alpha particles, beta particles, and gamma rays are the three categories.

Average and half-life are two characteristics that may be used to describe the decay constant. Moments are used as the measuring unit in both scenarios. The average lifespan of such an element, as indicated by its name, may be expressed in the form of the following affirmation:

Nt=N₀ * e^(−λt).

The duration of time that is defined by how long it takes for half of a material to degrade is known as its half-life (both radioactive and non-radioactive elements). All through process of decay, its rate of decay is constant. It may be seen by:

Nt=N₀* (1/2)^(t/t₁₂).

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Answer:

Sulphuric Acid + Iron (II) Hydroxide → Iron (II) Sulphate + Water. H2SO4 + Fe(OH)2 → FeSO4 + 2H2O. Nitric Acid + Iron (II) Hydroxide → Iron (II) Nitrate + Water

Answer: Zn2+

Explanation:

The standard reduction potential of the given species is as follows:-

\(\begin{aligned}&Z_{(aq)}^{2+}+2 e^{-} \longrightarrow {Zn}(\mathrm{s}) \quad E^{\circ}=-0.76 \mathrm{~V}\\&\mathrm{Mn}_{(\text {aq) }}^{2+}+2 e^{-} \longrightarrow \mathrm{Mn}(\mathrm{s}) \quad E^{\circ} = -1.03 \mathrm{~V}\\&\mathrm{Na}^{+}_{(\text {aq) }} + e^{-} \longrightarrow \mathrm{Na}\text{(s)} \quad E^{\circ}=-2.71 \mathrm{~V}\end{aligned}\)

\(\begin{aligned}&\mathrm{Al}_{(\text {aq) }}^{3+}+3 e^{-} \longrightarrow \text {Al}\text{(s)}\quad E^{0}=-1.66 \mathrm{~V}\\&\mathrm{Li}^{+}(aq)+{e}^{-} \longrightarrow \mathrm{Li}\text{(s)} \quad E^{0}=-3.05 \mathrm{~V}\end{aligned}\)

In the electrochemical series, the species having the lowest electromotive force—the lowest negative value—will be reduced first and the species having the highest negative value will be reduced last

Therefore, Zn2+ will be reduced first and Li+ will be reduced last

The reduction has been defined as the loss of electrons. The species of molten salt that reduces first has been zinc ion in electrolysis.

The electrolysis has been defined as the process of the ionization of the salt under the influence of the electric field.

The species with the lowest reduction potential will reduce first. The reduction potential of the following is:

Zinc has the lowest reduction potential and thus is the reduced first among the others.

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Answer:

78.7%

Explanation:

The δh° for the process SB (s) + Cl2 (g) → SbCl5 (s) is -394 kJ using Hess's-Law.

Hess's Law states that the enthalpy change of a reaction is independent of the pathway taken and depends only on the initial and final states. By combining the given reactions, we can cancel out the intermediate compound (SbCl3) and obtain the desired reaction. The enthalpy change for the first reaction (SB (s) + Cl2 (g) → SbCl3 (s)) is -314 kJ, and for the second reaction (SbCl3 (s) + Cl2 (g) → SbCl5 (s)) is -80 kJ. By adding these two reactions, we obtain the overall reaction with a δh° of -394 kJ.

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Answer: a vacuum

Explanation: light travel as a wave but unlike sound waves or water it doesn’t need any matter or material to carry its energy along.this means that light can travel through a vacuum which means a completely airless space the wall is vacuum :) hope this helped

Answer:

10.2 mol

Explanation:

given,pressure=240kpa

volume=31L

temperature=87.65°c

req,mole=?

now we have the equation

pv=nRt

When,p=pressure

v=volume

n=moles

R=gas constant

t=temperature

gas constant(R)=8.314L.kpa/k.mol

solution

from the first equation we have an equation

n=pv/Rt

=240×31/8.314×87.65

=7440/728.72

=10.2 mol

The molecular formula of a compound refers to the actual number of atoms of each element present in a molecule of that compound. The empirical formula, on the other hand, provides the simplest whole-number ratio of atoms in a compound. In this case, the empirical formula of the compound is C3H5O2. To determine the molecular formula, we need to know the molar mass of the compound.

We can calculate the molecular formula by finding the ratio of the molar mass of the compound to the molar mass of the empirical formula. The molar mass of the empirical formula C3H5O2 is:

(3 x 12.01 g/mol for C) + (5 x 1.01 g/mol for H) + (2 x 16.00 g/mol for O) = 73.08 g/mol

To find the molecular formula, we divide the molar mass of the compound (146 g/mol) by the molar mass of the empirical formula (73.08 g/mol):

146 g/mol ÷ 73.08 g/mol = 2

This tells us that the compound has two times the number of atoms in the empirical formula. Therefore, the molecular formula of the compound is:

(C3H5O2)2 = C6H10O4

So, the molecular formula of the compound with a molar mass of 146 g/mol and an empirical formula of C3H5O2 is C6H10O4.

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The half life of a certain radioactive sample is 1 hr. if the mass of the sample is 1 gram at noon, what will be the mass of the sample at 3pm?

The half-life is the time it takes for one-half of the radioactive element to decay. The value of the half-life given here is one hour.

After one hour (1 PM) there would only be

(1/2)*(1 g)= 0.5 g of the element remaining.

After three hours (3 PM) there would only be

(1/2)*(1/2)*(1/2)*(1 g) = (1/8)g remaining.

Half-life is the time required for a quantity to reduce to half of its initial value. The term is commonly used in nuclear physics to describe how quickly unstable atoms undergo radioactive decay or how long stable atoms survive. The term is also used more generally to characterize any type of exponential decay.

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2.8 × 10²⁶ moles Al

Math

Pre-Algebra

Order of Operations: BPEMDAS

Chemistry

Atomic Structure

Stoichiometry

Step 1: Define

[Given] 1.7 × 10⁵⁰ particles Al

[Solve] moles Al

Step 2: Identify Conversions

Avogadro's Number

Step 3: Convert

Step 4: Check

Follow sig fig rules and round. We are given 2 sig figs.

2.82298 × 10²⁶ moles Al ≈ 2.8 × 10²⁶ moles Al

Answer:

ily

Explanation:

Based on the Henderson-Hasselbalch equation, with an NH3:NH4 ratio of 0.4 moles:0.6 moles, the approximate pH of the ammonia buffer is calculated to be 9.075.

The Henderson-Hasselbalch equation, pH = pKa + log([A-]/[HA]), is applicable to the given scenario where NH3 acts as the base (A-) and NH4 serves as the conjugate acid (HA). The pKa value for the NH4/NH3 system is 9.25. By considering the NH3:NH4 ratio of 0.4 moles:0.6 moles in a 1-liter buffer solution, we can determine the concentrations of NH3 and NH4.

NH3 concentration = 0.4 moles / 1 liter = 0.4 M

NH4 concentration = 0.6 moles / 1 liter = 0.6 M

Substituting these values into the Henderson-Hasselbalch equation:

pH = 9.25 + log([0.4]/[0.6])

pH = 9.25 + log(0.667)

After evaluating the logarithm, the calculation continues as:

pH = 9.25 - 0.175

pH ≈ 9.075

Therefore, the pH of the ammonia buffer, with an NH3:NH4 ratio of 0.4 moles:0.6 moles, is approximately 9.075.

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Molality of a solution is defined as the number of moles of solute per kilogram of solvent. The formula for molality is given by the following equation:molality (m) = moles of solute / mass of solvent (in kg)In order to calculate the molality of a 12 percent urea solution, we need to first determine the mass of urea present in the solution.

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The compound that liberates the most heat upon hydrogenation is the one with the most negative enthalpy of hydrogenation.

The enthalpy of hydrogenation is the heat released when one mole of an unsaturated compound reacts with hydrogen to form a saturated compound. It is a measure of the stability of the unsaturated compound, with more stable compounds releasing less heat upon hydrogenation.

Hydrogenation is the process of adding hydrogen atoms to a molecule, usually involving the reduction of unsaturated bonds (double or triple bonds) to single bonds. The compound that releases the most heat during hydrogenation is the one with the least stable initial structure, as it will undergo a more significant change in energy when hydrogen is added.
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The products of the reaction are calcium citrate, carbon dioxide gas, and water.

The products of the reaction between citric acid (C6H8O7) and calcium carbonate (CaCO3) are:

Calcium citrate (Ca3C12H10O14): This is the compound formed by the combination of citric acid and calcium carbonate. It is a salt that is soluble in water and can be easily washed away.

Carbon dioxide gas (CO2): This gas is released as a byproduct of the reaction between citric acid and calcium carbonate. It is a colorless and odorless gas.

Water (H2O): Water is also produced as a byproduct of the reaction. It is formed when the hydrogen atoms from citric acid and the hydroxide ion from calcium carbonate combine.

So, the products of the reaction are calcium citrate, carbon dioxide gas, and water.

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6.00 moles of barium perchlorate contains the same number of ions as 6.00 moles of barium ions (Ba²⁺) and 12.00 moles of perchlorate ions (ClO₄⁻).

In barium perchlorate (Ba(ClO₄)₂), each formula unit consists of one barium ion (Ba²⁺) and two perchlorate ions (ClO₄⁻). The subscript "2" in the formula indicates that there are two perchlorate ions for every one barium ion.

For every mole of barium perchlorate, there is one mole of barium ions (Ba²⁺) and two moles of perchlorate ions (ClO₄⁻). Therefore, when we have 6.00 moles of barium perchlorate, we also have 6.00 moles of barium ions and 12.00 moles of perchlorate ions.

It is important to note that in this case, the number of ions is directly related to the number of moles of the compound. The stoichiometry of the compound determines the ratio of ions present in a given amount of the compound.

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°ΔG rxn = -1108.7

Maybe the question is like this

the value of ΔG° at 25 °C for the formation of POCl₃

Reaction

P₂(g)+O₂(g)+3Cl₂(g)⇒2POCl₃(g)

Formula

\(\tt ^o\Delta G_{rxn}=^o\Delta G_f~product-^o\Delta G_f~reactants\)

You can find table to find ΔG° at 25 °C(298 K)

°ΔG POCl₃ = -502.5 kJ/mol

°ΔG O₂ and °ΔG Cl₂ = 0

°ΔG P₂ = 103.7 kJ/mol

\(\tt ^o\Delta G_{rxn}=2.^o\Delta G~POCl_3-^o\Delta GP_2\\\\^\Delta G_{rxn}=2.(-502.5)-103.7=-1108.7~kJ/mol\)

Answer:

What occurs when the temperature of 10.0 grams of water is changed from 15.5°C to 14.5°C? [Specific Heat of Water = 4.18 J/g •k] 1) The water absorbs 41.8 joules. 2) The water absorbs 155 joules.

Explanation:

Take a look at the specific heat of water. As you know, a substance's specific heat tells you how much heat is needed in order to increase the temperature of 1 g of that substance by 1∘C . In water's case, you need to provide 4.18 J of heat per gram of water to increase its temperature by 1∘C .

Answer:

Backbone help us to be straight ,walk ,sleep etc

Explanation:

Backbone is the part of human body which is located back of our body.

It effort helps us to be straight do various work

The spine or the backbone is the central structure of the vertebrate body and it serves a few imperative capacities:

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