Answers
Answer:
The time it will take the capacitor to loss half of its stored energy is 11.1 s.
Explanation:
Given;
capacitance, C = 4.0-mF = 0.004 F
resistance, R = 4.0-kΩ = 4000 Ω
The voltage of a capacitor at an instant time is given by;
\(V = (V_o)e^{-t/RC}\)
the final voltage, V is half of the initial voltage, V₀ at the time t
V = V₀/2
\(V = (V_o)e^{-t/RC}\\\\\frac{V}{2} = (V_o)e^{-t/RC}\\\\0.5 = e^{-t/RC}\\\\ln(0.5)= ln(e^{-t/RC})\\\\ln(0.5)= \frac{-t}{RC}\\\\ t = -(RC)ln0.5\\\\t = -(4000*0.004)ln(0.5)\\\\t = 11.1 \ s\)
Therefore, the time it will take the capacitor to loss half of its stored energy is 11.1 s.
The time taken by capacitor will be "11.1 s",
Resistor and CapacitorAccording to the question,
Capacitance, C = 4.0 mF or,
= 0.004 F
Resistance, R = 4.0 kΩ or,
= 4000 Ω
As we know the relation,
→ V = (V₀)\(e^{-\frac{t}{RC} }\)
or,
\(\frac{V}{2}\) = (V₀)\(e^{-\frac{t}{RC} }\)
0.5 = \(e^{-\frac{t}{RC} }\)
By taking "log" both sides, we get
ln(0.5) = ln(\(e^{-\frac{t}{RC} }\))
Now,
The time will be:
t = -(RC)ln(0.5)
By substituting the values,
= -(4000 × 0.004)ln(0.5)
= 11.1 s
Thus the above approach is right.
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Related Questions
The net torque of a bod about certain axis of rotation is 150 Nxm. You recalculate the net torque about a different axis of rotation. If your work is correctyou have to find the same number.is this tstemnt true or false?
Answers
Every individual torque acting on the body depends on the axis of rotation, however the net torque is independent of the axis we choose. Therefore, the statement is true.
What causes coastal erosion
Answers
La erosión costera es la pérdida o desplazamiento de tierra, o la remoción a largo plazo de sedimentos y rocas a lo largo de la costa debido a la acción de olas, corrientes, mareas, agua impulsada por el viento, hielo transportado por el agua u otros impactos de marejadas ciclónicas.
The half-life of a radioactive isotope is 210 d. How many days would it take for the decay rate of a sample of this isotope to fall to 0.58 of its initial rate?
Answers
It would take approximately 546 days for the decay rate of the sample of this radioactive isotope to fall to 0.58 of its initial rate.
1. The decay rate of a radioactive isotope is proportional to the number of radioactive atoms present in the sample at any given time.
2. The decay rate can be expressed as a function of time using the formula: R(t) = R₀ * \(e^{(-\lambda t\)), where R(t) is the decay rate at time t, R₀ is the initial decay rate, λ is the decay constant, and e is the base of the natural logarithm.
3. The half-life of a radioactive isotope is the time it takes for half of the radioactive atoms in a sample to decay. In this case, the half-life is given as 210 days.
4. Using the half-life, we can find the decay constant (λ) using the formula: λ = ln(2) / T₁/₂, where ln(2) is the natural logarithm of 2 and T₁/₂ is the half-life.
5. Substituting the given half-life into the formula, we have: λ = ln(2) / 210.
6. Now, we need to find the time it takes for the decay rate to fall to 0.58 of its initial rate. Let's call this time "t".
7. Using the formula for the decay rate, we can write: 0.58 * R₀ = R₀ * e^(-λt).
8. Simplifying the equation, we get: 0.58 = \(e^{(-\lambda t\)).
9. Taking the natural logarithm of both sides, we have: ln(0.58) = -λt.
10. Substituting the value of λ from step 5, we get: ln(0.58) = -(ln(2) / 210) * t.
11. Solving for t, we have: t = (ln(0.58) * 210) / ln(2).
12. Evaluating the expression, we find: t ≈ 546.
13. Therefore, it would take approximately 546 days for the decay rate of the sample of this radioactive isotope to fall to 0.58 of its initial rate.
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In a system of 2 large round objects, R1 and R2 (R1 is larger), what properties will affect the force of gravity between them? (select all that apply)
Answers
According to Newton's Law of Universal Gravitation, if two particles with masses M and m are located a distance r from each other, an attractive force between them appears, and its magnitude is given by:
\(F=G\frac{Mm}{r^2}\)Where G is the gravitational constant:
\(G=6.67\times10^{-11}N\frac{m^2}{\operatorname{kg}^2}\)From the equation, we can see that the properties that affect the force between them are their masses and the distance between them.
Then, the correct choices are:
- Mass of R1
- Mass of R2
- Distance from the center of R1 to the center of R2.
If two point masses 1kg & 4kg are seperated by a distance of 2m. Magnitude of gravitational force exerted by 1kg on 4kg is ?
(A) G/4
(B) G
(C) G/2
(D) G/3
Answers
Answer:
F = G NewtonsExplanation:
Given:
Mass of 1st body = \(1\:kg\)Mass of 2nd body = \(4\:kg\)To Find:
Magnitude of gravitational forceSolution:
Here, we have a formula
\(F=\dfrac{G.M_{1}.M_{2}}{r^{2}}\)Substituting the values
\(\implies\:\:F = \dfrac{G(1)(4)}{2^{2}}\)
\(\implies\:\:F = \dfrac{4G}{4}\)
\(\implies\:\:F = \dfrac{\cancel{4}G}{\cancel{4}}\)
\(\implies\:\:\red{F = G}\)
Know More:
The applied formula for the above solution is
\({\boxed{F_{G}=\dfrac{G.M_{1}.M_{2}}{r^{2}}}}\)
where,
F\(_{G}\) = Gravitational forceG = Gravitational constantM\(_{1}\) = mass of 1st bodyM\(_{2}\) = mass of 2nd bodyr = distance between two bodiesYou are driving at 15.0 m/s when you suddenly slam on the brakes to avoid a collision. You come to a complete stop. When you stop your acceleration
is determined by your tires and the road conditions, and it is a constant -10.3 m/s2. The skidmarks you leave behind can be measured to determine
your displacement. How long will your skid marks be?
A. 14.3 m
B. 32.7 m
C. 10.9 m
D. 28.6 m
Answers
Please find attached photograph for your answer. The answer is c. 10.9 m.
The skidmarks you leave behind can be measured to determine
your displacement, the skid mark would be 10.9 meters long, therefore the correct answer is option C.
What is acceleration?The rate of change of the velocity with respect to time is known as the acceleration of the object.
As given in the problem, you are driving at 15.0 m/s when you suddenly slam on the brakes to avoid a collision. You come to a complete stop. When you stop your acceleration is determined by your tires and the road conditions, and it is a constant -10.3 m/s2. The skidmarks you leave behind can be measured to determine your displacement.
Now using the third equation of motion,
v² - u² = 2×a×s
0 - 15² = 2 ×(-10.3)×s
s = 10.9 meters
Thus, the skid mark would be 10.9 meters long, therefore the correct answer is option C.
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A body sets off from rest with a constant acceleration of 8 m/s^2. what distance will it have covered after 3 s?
Answers
Answer:36
Explanation:
distance = initalvelocity(time) + 0.5(acceleration)(time^2)
d = 0(3) + (0.5)(8)(3^2)
d = 0 + (4*9)
d = 36 meters
40 POINTS I’ve been stuck on this for hours please help :(
Answers
Answer:
Explanation:
Particle Relative Mass Charge Location
Proton 1 + Nucleus
Electron 0 - Outside rings (not nucleus)
Neutron. 1 No Charge Nucleus
.................................. uh ya
A block of mass 10 kg on a 30° inclined plane is being pushed by a horizontal force F as shown in the figure below. Find: 1) II) iii) the time it takes to move the block up the incline by a distance of 2 m, if the block starts from rest and the surface of the inclined plane is smooth and F = 100 N. [5] the horizontal force needed to move the block 2 m up the incline in a time of 1 s, if the surface is rough with coefficient of kinetic friction of 0.2 between it and the block and the block starts from rest. [8] the time the block will take to reach a speed of 5 ms¹ starting from rest at the top when the force F is removed and the surface is smooth. [7] F=100N 10 kg 30
Answers
The diagram and specific values for angle, mass, and force are missing from the question, making it difficult to provide exact numerical solutions. However, the provided solution approach should help you solve the problem once you have the necessary values.
To solve the given problems, we need to use principles of Newton's laws of motion and the equations of motion. Here are the solutions to each part:
To find the time it takes to move the block up the incline by a distance of 2 m, we need to consider the forces acting on the block. The force component acting parallel to the incline is F_parallel = F * sin(30°). The force component perpendicular to the incline is F_perpendicular = F * cos(30°). The net force acting up the incline is F_net = F_parallel - frictional force.
Using Newton's second law, F_net = m * a, we can calculate the acceleration of the block. Then, we can use the equation of motion, d = v_i * t + (1/2) * a * t^2, where d is the distance (2 m) and v_i is the initial velocity (0 m/s) to solve for time (t).
To find the horizontal force needed to move the block 2 m up the incline in 1 second, considering a rough surface with a coefficient of kinetic friction (μ = 0.2), we need to calculate the frictional force. The frictional force can be determined as F_friction = μ * N, where N is the normal force. The normal force can be found as N = m * g * cos(30°). Then, we can find the net force acting up the incline as F_net = F - F_friction and use the same approach as in part 1 to find the required force.
To find the time it takes for the block to reach a speed of 5 m/s starting from rest at the top, when the force F is removed and the surface is smooth, we need to use the equation of motion, v_f = v_i + a * t, where v_f is the final velocity (5 m/s), v_i is the initial velocity (0 m/s), and a is the acceleration due to gravity (g). Rearranging the equation, we can solve for time (t).
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Which of the following is true at the point where you reach the top of your jump on a trampoline?
The mechanical energy is zero
he potential energy is at maximum
The kinetic energy and potential energy are equal.
The potential energy is zero.
Answers
The potential energy is at the maximum when you reach the top of your jump on a trampoline. The correct answer is option B.
What is Potential EnergyPotential Energy is the type of energy an object possesses by virtue of its position relative to others, stresses within itself, electric charge, and other factors. Potential energy exists in various forms, including gravitational potential energy, elastic potential energy, chemical potential energy, and electrical potential energy.
This type of energy can be converted into another type of energies. Examples, a charged battery has potential energy and it can be used as electrical potential energy. Petrol, diesel and and gas have chemical potential energy and be used as kinetic energy.
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Please help! I'm really desperate.
Could anyone at least give some sketch ideas or advice?
I'm not sure how to set it out..
Answers
Answer:
make a pineapple schematic
Explanation:
Which of the following is an
example of thermal energy?
A. turning on a lamp so you can read
B. rubbing your hands together to get warm
C. kicking a ball
Answers
A 20-g bullet is shot vertically into an 2.8-kg block. The block lifts upward 9 mm. The bullet penetrates the block and comes to rest in it in a time interval of 5 ms. Assume the force on the bullet is constant during penetration and that air resistance is negligible. What is the speed of the bullet just before the impact
Answers
Answer:
The speed of the bullet just before the impact is 701 m/s
Explanation:
Given;
mass of the bullet, m₁ = 20 g = 0.02 kg
mass of the block, m₂ = 2.8 kg
displacement of the block, d = 9 mm = 9 x 10⁻³ m
duration of motion of the bullet, t = 5 ms = 5 x 10⁻³ s
Apply the principle of conservation of energy;
The final kinetic energy of the bullet = maximum potential energy of the block
\(\frac{1}{2} m_1v^2 = m_2gh\\\\v^2 = \frac{2m_2gh}{m_1} \\\\v= \sqrt{\frac{2m_2gh}{m_1} } \\\\v = \sqrt{\frac{2 \times 2.8 \times 9.8 \times (9\times 10^{-3})}{0.02} } \\\\v = 4.97 \ m/s\)
Apply the principle of conservation of linear momentum, to determine the initial velocity of the bullet before the impact.
m₁u₁ + m₂u₂ = v(m₁ + m₂)
where;
u₁ is the initial velocity of the bullet
u₂ is the initial velocity of the block = 0
m₁u₁ + 0 = v(m₁ + m₂)
m₁u₁ = v(m₁ + m₂)
0.02u₁ = 4.97(2.8 + 0.02)
0.02u₁ = 14.02
u₁ = 14.02 / 0.02
u₁ = 701 m/s
Therefore, the speed of the bullet just before the impact is 701 m/s
Two blocks, 1 and 2, are connected by a massless string that passes over a massless pulley. 1 has a mass of 2.25 kg and is on an incline of angle 1=42.5∘ that has a coefficient of kinetic friction 1=0.205. 2 has a mass of 5.55 kg and is on an incline of angle 2=33.5∘ that has a coefficient of kinetic friction 2=0.105
. The figure illustrates the configuration.
A system of two blocks connected by a rope passing over a pulley. The system sits atop a scalene triangle whose long edge forms the base. The pulley is attached to the apex of the triangle. Box M subscript 1 rests on the triangle edge to the left of the pulley, which makes an angle of theta subscript 1 with the base of the triangle. The coefficient of friction between box M sub 1 and the surface is mu subscript 1. Box M subscript 2 rests on the triangle edge to the right of the pulley, which makes an angle of theta subscript 2 with the base of the triangle. The coefficient of friction between box M sub 2 and the surface is mu subscript 2.
Answers
The force acting on the system of two blocks connected by a rope passing over a pulley is -13.26 N.
The system of two blocks connected by a rope passing over a pulley are M1 and M2, where M1 rests on the triangle edge to the left of the pulley, which makes an angle of theta subscript 1 with the base of the triangle. The coefficient of friction between box M1 and the surface is mu subscript 1. M2 rests on the triangle edge to the right of the pulley, which makes an angle of theta subscript 2 with the base of the triangle.
The coefficient of friction between box M2 and the surface is mu subscript 2. The system sits atop a scalene triangle whose long edge forms the base. The pulley is attached to the apex of the triangle.M1 has a mass of 2.25 kg and is on an incline of angle 1=42.5∘ that has a coefficient of kinetic friction 1=0.205. M2 has a mass of 5.55 kg and is on an incline of angle 2=33.5∘ that has a coefficient of kinetic friction 2=0.105.The free-body diagram of M1 shows that the weight of M1 acts straight downwards (vertically) and the normal force acts perpendicular to the slope.
The force of friction opposes the motion and acts opposite to the direction of motion.M1 = 2.25 kgTheta subscript 1 = 42.5 degreesMu subscript 1 = 0.205g = 9.81 m/s²In the free-body diagram of M2, the normal force acts perpendicular to the incline of the slope, the weight of the object acts vertically downwards and parallel to the incline, and the force of friction opposes the motion and acts opposite to the direction of motion.M2 = 5.55 kgTheta subscript 2 = 33.5 degreesMu subscript 2 = 0.105g = 9.81 m/s²The tension in the string is the same throughout the rope. Since the masses are being pulled by the same rope, the acceleration of the objects is the same as the acceleration of the rope.
The tension in the string is directly proportional to the acceleration of the objects and the rope.A system of two blocks connected by a rope passing over a pulley has a total mass of M. The acceleration of the system is given by the formula below:a = [(m1-m2)gsin(θ1) - μ1(m1+m2)gcos(θ1)] / (m1 + m2)Where, μ1 = 0.205 is the coefficient of friction of block M1θ1 = 42.5 degrees is the angle of the incline of block M1M1 = 2.25 kg is the mass of block M1M2 = 5.55 kg is the mass of block M2g = 9.81 m/s² is the acceleration due to gravitysinθ1 = sin 42.5 = 0.67cosθ1 = cos 42.5 = 0.75The acceleration of the system is:a = [(2.25-5.55)(9.81)(0.67) - (0.205)(2.25+5.55)(9.81)(0.75)] / (2.25 + 5.55)a = -1.7 m/s² (the negative sign indicates that the system is accelerating in the opposite direction).
The force acting on the system is given by:F = MaWhere M is the total mass of the system and a is the acceleration of the system. The total mass of the system is:M = m1 + m2M = 2.25 + 5.55M = 7.8 kgThe force acting on the system is:F = 7.8(-1.7)F = -13.26 N (the negative sign indicates that the force is acting in the opposite direction).
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state Newton's first law of motion.
Answers
Answer:
Newton's first law states that if a body is at rest it will remain at rest and if a body is in motion it will remain in motion until an external force is applied on the body.
Newton's first law of motion states that an object will continue in a state of rest or uniform motion in a straight line unless acted upon by an external force.
What is Newton's first law of motion?Newton's first law of motion states that an object will continue in a state of rest or uniform motion in a straight line unless acted upon by an external force.
Newton's first law of motion is also known as law of inertia.
The inertia of every object is the reluctance of the object to start moving or stop moving once the object is in motion.
Inertia depends on mass of the object.
Thus, Newton's first law of motion is also known as law of inertia.
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Use the drop-down menus to complete each sentence.
The height of the cylinder is manipulated. This is the
variable.
The temperature of the water changes as the height of the cylinder changes. The temperature of the water is therefore the
variable.
A “constant” is a parameter that stays the same regardless of the variables. One parameter of the system that is held constant is the
.
Answers
One parameter of the system that is held constant that can be considered is the mass of the water.
What is a constant?In science, the constant is a type of unmodified variable that remains equal along with the experimental procedure.
The constants of a particular system must be considered and they cannot change in experiments or observations.
In conclusion, one parameter of the system that is held constant that can be considered is the mass of the water.
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The gravitational force exerted by the Sun on the Earth holds the Earth in an orbit around the Sun. Let us assume that the orbit is perfectly circular. The work done by this gravitational force during a short time interval in which the Earth moves through a displacement in its orbital path is (a) zero (b) positive (c) negative (d) impossible to determine
Answers
The work done by this gravitational force during a fast time interval in which the Earth drives through a displacement in its orbital path is (a) zero.
What is the unit of gravitational force?Gravitational Force
The kilogram force (kgf) is a gravitational unit of force. The force exercised by the earth on a body of mass 1 kg is regarded as 1 kgf. Force = Mass × Acceleration. 1 kgf = 9.8 N.
The gravitation force and perpendicular to the path of movement
hence angle between gravitational force [ F ]and displacement (d)=90°
work done (W)= F d cos 90°
= 0
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A tennis ball and a bag filled with sand have the same mass. They are dropped from the same height and they hit the ground. The bag of sand stays on the ground, while the tennis ball rebounds. Which experiences the larger impulse from the ground?
Answers
Answer:
The bag of sand
Explanation:
I think it is the bag of sand because according to the definition of impulse, impulse is the average force acting on a particule when an external force is being acted on it.
Microevolution three mechanisms that cause allelic frequencies to change in a population: gene flow, genetic drift, natural selection bottleneck effect founder effect population gene pool stabilizing, directional and disruptive selection hardy-weinberg equilibrium five conditions that must be met in order for population to be in hardy-weinberg equilibrium adptive evolution relative fitness sexual selection sexual dimorphism intrasexual selection intersexual selection neutral variation balancing selection heterozygote advantage hardy-weinberg problems
Answers
Microevolution refers to the evolution occurring at species-level involves three mechanisms that cause allelic frequencies to change in a population: gene flow, genetic drift, and natural selection.
Changes in the environment can affect population gene pools on both a small- and large-scale. Microevolution is the process of population-level changes in allele frequency. Some alterations take place at the species level or lower. There are hence variations in allele frequencies between or within groups.
Natural selection is one of the mechanisms of microevolution. It serves as an editor for allele frequency in populations to determine whether individuals with particular features have a higher or lower chance of surviving and procreating. Populations' gene pools can occasionally shift as a result of individuals leaving or entering the community. This transfer of alleles between populations is referred to as gene flow. Genes can "flow" from one area to another just like water does in a river.
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A soccor ball lies still on the grass until it is kicked by a player. This desribes which of Newton's Laws?
Answers
A 70 kg stunt pilot begins pulling out of a dive into a vertical circle. If the plane's speed at the lowest point of the circle is 80 m/s, what is the apparent
weight of the pilot at the lowest point of the pullout? The pilot experiences a force of 5g from the centripetal acceleration at the bottom of the dive.
O
3880 N
о
3430 N
0
4116 N
3986 N
Answers
Answer:
Apparent weight of pilot due to centripetal acceleration:
m v^2 / R = 5 g m = 5 * 70 * 9.8 = 3430 N
Weight of pilot = 70 * 9.8 = 686 N
Total = 3430 + 686 = 4116 N
A boy throws a stone straight upward with an initial
speed of 17.0 m/s.
Part A
What maximum height will the stone reach before falling back down?
Answers
Answer:
14.8m
Explanation:
Given parameters:
Initial speed = 17m/s
Unknown:
Maximum height = ?
Solution:
At the maximum height, the final speed will be 0m/s;
We use of the kinematics equation to solve this problem.
V² = U² - 2gH
V is the final velocity
U is the initial velocity
g is the acceleration due to gravity
H is the height
0² = 17² - (2 x 9.8 x h )
0 = 289 - (9.6h)
-289 = -19.6h
h = 14.8m
supergiant stars
a.) form from red giants
b.) fuse hydrogen into carbon
c.) form planetary nebulae
d.) form supernovas
Answers
Answer:
d.) form supernovas
Explanation:
Learned this in physical school last year
6. Mikey can kick the ball to Sage with a force of 20 N, making it travel 60m. Give the work done on the ball.
Answers
Answer:
Explanation:
Given:
F =20 N
D = 60 m
________
W - ?
W = F·D = 20·60 = 1 200 J
What is the potential gravitational energy of a 2 kg ball thrown up in the air to a height of 7 m?
Answers
Answer:
PE = 137.2931 J
Explanation:
PE = 137.2931 J
A boat on a river is moving with a steady speed. The engine is running.
What would happen if the engine was turned off?
Answers
If the engine of a boat on a river is turned off while the boat is moving with a steady speed, several things would happen Loss of propulsion,Drifting,Loss of steering control and Potential hazards.
Loss of propulsion: Without the engine running, the boat would lose its power source for propulsion. The boat would gradually slow down and eventually come to a stop unless other external forces, such as currents or wind, continue to move it.
Drifting: Once the boat comes to a stop, it would start to drift with the current of the river or be affected by wind forces. The direction and speed of the drift would depend on the strength and direction of the current or wind.
Loss of steering control: When the engine is turned off, the boat's steering mechanism, such as a rudder, would also lose power. Without the ability to steer, the boat would follow the course determined by the river's current or the wind direction.
Potential hazards: Depending on the surroundings and the current conditions, there could be potential hazards for a boat that is no longer under power. These hazards might include other vessels, obstacles, shallow areas, or strong currents. The boat's crew would need to take appropriate actions to ensure the safety of the boat and its occupants.
It's important to note that the specific behavior of the boat after the engine is turned off can vary depending on factors such as the size and design of the boat, the strength and direction of the current, and the presence of wind or other external forces.
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The average speed of an object is the _______ that an object moves divided by the _______ of the movement.
Question 1 options:
Total distance; direction
Total time; total force
Total area; total force
Total distance; total time
Answers
Answer:
Bottom choice
Explanation:
Average speed is total distance / total time
The value found for the universal gravitational constant, G, will vary depending on the materials used for the balls of a Cavendish balance. Is this true or false
Answers
False
The value of G is a constant for a variety of materials
A sample of iodine is easiest to ship asa powder because it is
Answers
A tree limb is blown loose from a tree during a storm. As it falls, it gains
speed. Which type of energy is the tree limb gaining as it falls?
O A. Kinetic energy
B. Gravitational potential energy
O C. Nuclear energy
OD. Light energy
Answers
Answer:
B Gravitational potential energy
Explanation: