Velocity v = 2.06 m/s due east : This means that the combined vehicles will continue moving in the same direction, but at a slower speed than the truck was initially traveling.
When the truck collides head-on with the car, the two vehicles will experience a large force due to their combined momentum.
This force will cause the vehicles to deform and absorb some of the kinetic energy of their motion. The direction of the force will be towards the east, as that is the direction the truck was traveling before the collision.
To understand the effects of this collision, we need to calculate the momentum of each vehicle before and after the collision. The momentum of the truck before the collision can be calculated as:
Momentum = mass x velocity = 4149 kg x 12 m/s = 49,788 kg*m/s due east
Similarly, the momentum of the car before the collision can be calculated as:
Momentum = mass x velocity = 899 kg x -40 m/s = -35,960 kg*m/s due west
After the collision, the two vehicles stick together and move in the same direction. We can calculate their combined momentum as:
Momentum = (mass of truck + mass of car) x velocity = (4149 kg + 899 kg) x v
where v is the velocity of the combined vehicles after the collision. Since momentum is conserved, we can equate the before and after momentum to get:
49,788 kg*m/s - 35,960 kg*m/s = (4149 kg + 899 kg) x v
Solving for v, we get:
v = 2.06 m/s due east
The force of the collision will cause the vehicles to deform and absorb some of their kinetic energy, resulting in a decrease in velocity.
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A child is pushing a merry-go-round. The angle through which the merty-go-round has turned varies with time according to θ(t)-7t + 3 where γ = 0.367 rad/s and 140-10-2 rad/sCalculate the angular velocity of the merry-go-round as a function of time Express your answer in terms of the variables β, γ, and t. Part BWhat is the initial value of the angular velocity?Part CCalculate the instantaneous value of the angular velocty w, at t 550 rad/s Part DCalculate the average angular velocity wfor the time interval t = 0 to t = 5.50s
Now, 0.65 rad/s and 0.7 rad/s are different. Average angular velocity is defined as total displacement divided by total displacement time.
What is the straightforward meaning of velocity?
The displacement that an object or particle experiences with respect to time is expressed vectorially as velocity. The meter per second (m/s) is the accepted unit of velocity magnitude (also known as speed).
How do velocity and speed differ?
Velocity is the pace and direction of an object's movement, whereas speed is the time rate at which an object is travelling along a path. In other words, velocity is a vector, whereas speed is a scalar value.
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The initial value of the angular velocity is -6.633 rad/s. The instantaneous value of the angular velocity is -3.817 rad/s.
What is the simple definition of velocity?In terms of time, an object or particle's movement is expressed vectorially as velocity. The recognized measurement of velocity magnitude is the meter per second (m/s) (also known as speed).
Part A:
The angular velocity of the merry-go-round as a function of time is the derivative of the angle with respect to time.
Angular velocity, w(t) = dθ(t) / dt = -7 + 0.367
Part B:
The initial value of the angular velocity is the value of the angular velocity at t = 0.
w(0) = -7 + 0.367 = -6.633 rad/s
Part C:
To find the instantaneous value of the angular velocity at a specific time, we need to substitute that time into the angular velocity equation.
w(t) = -7 + 0.367t
w(5.50) = -7 + 0.367(5.50) = -3.817 rad/s
Part D:
To find the average angular velocity for a time interval, we can use the following formula:
average angular velocity = (final angle - initial angle) / (final time - initial time)
Given the time interval t = 0 to t = 5.50s,
average angular velocity = (θ(5.50s) - θ(0)) / (5.50s - 0s)
θ(t) = -7t + 3
average angular velocity = (-7*5.50 + 3 - 3)/5.50 = -7 rad/s
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Bailey is plagued with sleep problems at least a couple of times a week. She often feels tired at work and doesn't do her best work because she is "just so tired." According to the lesson, it can be said that __________ adults have some of the same problems with sleep that Bailey does. A. few B. many C. no D. all
Option (B) many
According to the lesson, it can be said that many adults have some of the same problems with sleep that Bailey does.
Sleeplessness is one of the most common issues, every second adult or a teenager is facing now a days. Due to a lot of responsibilities, we end up having little time for sleep and this in turn affects our body functions.
A sleep disorder can affect our overall health, safety and quality of life. Lack of sleep can affect your ability to drive safely and increase our risk of other health problems.Sleep plays a key role in thinking and learning. Lack of sleep impairs these cognitive processes in a number of ways.Good sleep hygiene is often recommended to improve sleep quality, which also helps in alleviating anxiety due to work load and responsibilities.
Answer is Option (B) many
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the wavelength of radiation is ____ proportional to the energy carried per wave.
The wavelength of radiation is inversely proportional to the energy carried per wave.
The wavelength of radiation refers to the distance between successive peaks or troughs of a wave. It is commonly denoted by the symbol λ (lambda). The energy carried by a wave is directly related to its frequency, which represents the number of wave cycles per unit of time.
According to the wave-particle duality concept in physics, electromagnetic radiation can be viewed as both a wave and a particle. The energy of a single particle or photon of radiation is directly proportional to its frequency, and inversely proportional to its wavelength. This relationship is expressed by the equation
E = hν,
where E represents the energy, h is Planck's constant, and ν is the frequency of the radiation.
Since frequency and wavelength are inversely related (ν = c/λ, where c is the speed of light), it follows that the wavelength of radiation is inversely proportional to the energy carried per wave. Therefore, shorter wavelengths correspond to higher energy radiation, while longer wavelengths correspond to lower energy radiation.
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A wavelength of light is 1,800 m. What is the frequency?
Answer:
Frequency= 0.16655137
Explanation:
may i be brainliest?
True or False?
Phishing is not often responsible for PII data breaches.
It is incorrect that phishing is often responsible for PII breaches. Users are required to follow the guidelines outlined in applicable Systems Security Plans, DOL policies, and agency directives.
Loss of control, compromise, unauthorized disclosure, unauthorized acquisition, unauthorized access, or any other phrase with a similar connotation that describes circumstances in which individuals other than authorised users and for purposes other than those authorised have access to or potentially have access to personally identifiable information is referred to as a PII breach. The following security guidelines are specified by DOL internal policy for the protection of PII and other sensitive data: It is the user's obligation to safeguard any data they have access to. Cookies are frequently used by servers and browsers to collect non-PII data. Examples of non-PII include device type, browser kind, plugin information, language preference, time zone, and screen size.
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the question is confusing
Alpha particles have highest mass.
Alpha particles are most ionising.
Gamma particles are the most penetrating.
Beta particles are negatively charged.
Gamma particles have the highest speed.
Comparing the three types of ionizing radiation-alpha particles have the greatest mass. Alpha particles have approx 4 times the mass of a proton or neutron and 8,000 times the mass of a beta particle. Ionising power of alpha particle is very high due to double positive charge, large mass as compared to a beta particle. Alpha particles can cause multiple ionisations within a very small distance. Beta radiation is more penetrating than alpha radiation. beta radiation can pass through the skin, but it is absorbed by a few cm of tissue of the body or a few mm of aluminum. Gamma radiation is the most penetrating of the three radiations. Alpha particles are positively charged, while beta particles are negatively charged, and gamma radiation is electrically neutral. Gamma rays are similar to visible light but they have higher energy. Gamma rays are emitted along with alpha or beta particles during radioactive decay.learn more about gamma rays here:
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Find the next charge on an object with an excess of 2. 15x10^20 protons (extra protons)
According to the given statement , the next charge on the object with an excess of 2.15 x 10²⁰ protons is 3.44 C (coulombs).
The next charge on an object can be determined by considering the excess protons it has. Each proton has a charge of +1.6 x 10⁻¹⁹ coulombs.
Given that the object has an excess of 2.15 x 10²⁰ protons, we can calculate the total charge by multiplying the number of protons by the charge of each proton:
Total charge = (2.15 x 10²⁰ protons) * (1.6 x 10⁻¹⁹ C/proton)
To perform this calculation, we can use scientific notation. When multiplying numbers in scientific notation, we add the exponents and multiply the coefficients:
Total charge = 2.15 * 1.6 x 10²⁰ * 10⁻¹⁹ C
Now, let's simplify the multiplication:
Total charge = 3.44 x 10 C
The next charge on the object with an excess of 2.15 x 10²⁰ protons is 3.44 C (coulombs).
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Explain how a helicopter lifts itself up, from a Newton's 3rd Law perspective,
One is a bun, two is a shoe, three is a tree, etc. is an example of what?
Answer:
A popular set of Peg-Words
What is a Peg-Word?
They're easy to remember because they rhyme with the names of the first ten natural numbers, is: one is a bun, two is a shoe, three is a tree, four is a door, five is a hive, six is sticks, seven is heaven, eight is a gate, nine is wine, ten is a hen.
In trial 1 of an experiment, a cart moves with speed v0 on a frictionless, horizontal track and collides elastically with another cart that is initially at rest. In trial 2, the setup is identical except that the carts stick together during the collision. How does the speed of the two-cart system’s center of mass change, if at all, during the collision in each trial?answer choicesTrial 1: Does not changeTrial 2: Does not changeTrial 1: Does not changeTrial 2: DecreasesTrial 1: DecreasesTrial 2: Does not changeTrial 1: DecreasesTrial 2: Decreases
The speed of the two-cart system’s center of mass during the collision in Trial 1: Does not change, and in Trial 2: Decreases.
In Trial 1 of the experiment, the carts collide elastically and the speed of the two-cart system's center of mass does not change during the collision. In Trial 2, the carts stick together and the collision is inelastic. Some of the kinetic energy is converted into internal energy, resulting in a decrease in kinetic energy and the speed of the center of mass. In conclusion, the speed of the center of mass does not change during the collision in Trial 1, but, decreases in Trial 2 as a result of a decrease in the kinetic energy.
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You work in a materials testing lab and your boss tells you to increase the temperature of a sample by 34.1 C. The only thermometer you can find at your workbench reads in degrees Fahrenheit. Part A If the initial temperature of the sample is 62.4 °F, what is its temperature in degrees Fahrenheit when the desired temperature increase has been achieved? Express your answer in degrees Fahrenheit to three significant figures.
The final temperature of the sample in degrees Fahrenheit when the desired temperature increase has been achieved is `123.78°F.`
The initial temperature of the sample is 62.4 °F. The boss instructs us to raise the temperature by 34.1°C. We need to determine the final temperature of the sample. Here's how we can do it.
Step 1: Use the conversion formula for Celsius to Fahrenheit.
C = (F - 32) x 5/9F = (C x 9/5) + 32where C is the temperature in Celsius and F is the temperature in Fahrenheit.
Step 2: Convert the initial temperature of the sample from Fahrenheit to Celsius.
C = (F - 32) x 5/9`C = (62.4 - 32) x 5/9``C = 16.89`°C The initial temperature of the sample is 16.89°C.Step 3: Add 34.1°C to the initial temperature of the sample to obtain the final temperature in Celsius. Final temperature in Celsius = 16.89 + 34.1``Final temperature in Celsius = 50.99`°CStep 4: Convert the final temperature in Celsius to Fahrenheit.
F = (C x 9/5) + 32`F
= (50.99 x 9/5) + 32`F
= 123.78`°F
Therefore, the final temperature of the sample in degrees Fahrenheit when the desired temperature increase has been achieved is `123.78°F.`
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Un cuerpo de 480 g de masa es atraído con una fuerza de 3.9 E-6 N por otro cuerpo de 196 g de masa. Calcula la distancia a la que se encuentran.
Answer:
La distancia entre los dos cuerpos es aproximadamente 1.269 milímetros.
Explanation:
Asumamos que ambos cuerpos son partículas, la fuerza de atracción (\(F\)), en newtons, entre ambos cuerpos se define mediante la Ley de Newton de la Gravitación Universal, cuya ecuación es:
\(F = G \cdot \frac{m_{1}\cdot m_{2}}{r^{2}}\) (1)
Donde:
\(G\) - Constante de la gravitación universal, en metros cúbicos por kilogramo-segundo cuadrado.
\(m_{1}, m_{2}\) - Masas de los cuerpos, en kilogramos.
\(r\) - Distancia entre los cuerpos, en metros.
Si sabemos que \(G = 6.674\times 10^{-11}\,\frac{m^{3}}{kg\cdot s^{2}}\), \(m_{1} = 0.48\,kg\), \(m_{2} = 0.196\,kg\) y \(F = 3.9\times 10^{-6}\,N\), entonces la distancia entre los dos cuerpos es:
\(r = \sqrt{\frac{G\cdot m_{1}\cdot m_{2}}{F} }\)
\(r \approx 1.269\times 10^{-3}\,m\)
Es decir, la distancia entre los dos cuerpos es aproximadamente 1.269 milímetros.
Ball A, moving towards the right, collides with
stationary ball B. Ball A bounces back; B moves
off slowly to the right. Which has the greater
mass, A or B?
Answer:
ball b has the greater mass.
Explanation:
b only moved because a bumped into it. if a bounced back, it had less mass and b moved slowly.
2. Compare the difference in the calculated system entropy change for two moles of a gas that are heated from 400 K to 500 K under the following assumptions. (4 pts)Assumption #1: the heat capacity of the gas is 31 JK^-1Assumption #2: the heat capacity of the gas is a function of temperature and follows this functional formCp = 31.0+0.01T
The calculated system entropy change for both assumptions is very similar, with assumption #2 resulting in a slightly smaller entropy change which is 19.41J/K
Assumption #1: The entropy change can be calculated using the formula:
ΔS = nCln(T_f/Ti)
Where n is the number of moles of gas, C is the heat capacity, and Ti and T_f are the initial and final temperatures respectively. Plugging in the values, we get:
ΔS = 2 x 31 J/K/mol x ln(500 K/400 K) = 19.42 J/K
Assumption #2: In this case, the heat capacity is a function of temperature and we need to integrate it to get the entropy change:
ΔS = n∫(Cp/T)dT from Ti to f
Substituting the functional form of Cp, we get:
ΔS = n∫[(31.0 + 0.01T)/T]dT from 400 K to 500 K
Evaluating the integral, we get:
ΔS = n[(31.0 ln(T(f)/Ti) + 0.01(T(f) - Ti))/T(f)]
Plugging in the values, we get:
ΔS = 2[(31.0 ln(500/400) + 0.01(500 - 400))/500] = 19.41 J/K
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A strong weightless rope has a mass, m, hanging from the middle of it. The tension force on each rope is 25 N, and the rope droops at an angle of 20.0 degrees. How much mass is hanging from the rope?
By using Lami's theorem, Mass m = 1.75 kg approximately
Given that a strong weightless rope has a mass, m, hanging from the middle of it. If the tension force on each rope is 25 N, and the rope droops at an angle of 20.0 degrees to the horizontal.
By using Lami's theorem, we can get how much mass is hanging from the rope.
Let the angle between the rope = α = 180 - 40
α = 140 degrees
The angle between one of the rope and mass = β = 20 + 90
β = 110 degrees
The angle between the mass and the other rope = γ = 360 - (140 + 110)
γ = 360 - 250
γ = 110 degrees
W/ sinα = T/ sinβ = T/sinγ
W/ sinα = T/ sinβ
Substitute all the necessary parameters
W/sin140 = 25/sin 110
W / 0.643 = 25 / 0.939
W = 17.1 N
Weight W = mg
17.1 = 9.8m
mass m = 17.1/9.8
Mass m = 1.7455 kg
Mass m = 1.75 kg approximately
Therefore, 1.75 kg mass is hanging from the rope.
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Draw a force diagram for the softball player who is slowing as she slides into the base. Label the forces and use equality marks on the force vectors.
I have done what I thought it is, but I do not have trust in myself and feel like this is not correct.
The force diagram of the player has been shown in the image attached here.
How would the force diagram of a player sliding to a stop look like?The force diagram of a player sliding to a stop depends on the specific situation and factors such as the player's mass, velocity, and the surface on which they are sliding. However, we can make some generalizations based on common assumptions and considerations.
We know that the force of kinetic friction that is sliding the player to a stop would tend to have a higher magnitude as shown by the force diagram.
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A sample of water changes states from liquid to solid. The______ of the water, when it is a liquid, is the same as when it is solid what word completes the sentence
Answer:
Mass is the answer
Explanation:
Because of law of conservation of mass which states that mass remains same during change of state
A sample of water changes states from liquid to solid. The mass of the water, when it is a liquid, is the same as when it is solid what word completes the sentence.
What is law of conservation of mass?According to the rule of conservation of mass, mass is neither generated nor destroyed during a chemical process. For instance, when coal is burned, the carbon atom in it transforms into carbon dioxide.
The carbon atom transforms from a solid to a gas, yet its mass remains constant. Similar to this, according to the rule of conservation of energy, energy cannot be created or destroyed.
For instance, kinetic energy is converted to potential energy when a toy vehicle is rolled down a ramp and collides with a wall. Further, the law of conservation of mass states is mass is conserved from reactants to products, no matter the type of chemical reaction that occurs.
Therefore, A sample of water changes states from liquid to solid. The mass of the water, when it is a liquid, is the same as when it is solid what word completes the sentence.
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A car has a speed of 2 m/s and a mass of 1500kg. What is the car’s kinetic energy
Answer:
3,000 m/s
Explanation:
3,000 m/s
A fuel-filled rocket is at rest. It burns its fuel and expels hot gas. The gas has a momentum of 1,500 kg m/s backward. What is the momentum of the rocket?
A fuel-filled rocket is at rest. It burns its fuel and expels hot gas. The gas has a momentum of 1,500 kg m/s backward. So, The momentum of the rocket is -1500 kg m/s.
According to the law of conservation of momentum, in a closed system, the total momentum before and after a process remains constant.
A fuel-filled rocket that is initially at rest expels hot gas as it burns its fuel. The gas has a momentum of 1500 kg m/s backward.
We are required to determine the momentum of the rocket.
Consider the fuel-filled rocket as a system.
We have: Momentum before the burn = 0 kg m/s (since the rocket was at rest initially)Momentum after the burn = momentum of the expelled gas
We can therefore say that the initial momentum of the system was zero (0), and after the burn, the total momentum of the system remains the same as the momentum of the expelled gas.
Therefore: Momentum of rocket = - momentum of expelled gas
The negative sign signifies that the rocket's momentum is in the opposite direction of the expelled gas.
Hence, the momentum of the rocket is -1500 kg m/s.
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What will not produce a pitching moment?a.) A camber airfoil that is developing zero liftb.) A camber airfoil that is at a POSITIVE Angle of Attackc.) symmetrical airfoil at a zero AOAd.)
A pitching moment is produced when there is a difference in pressure on the top and bottom surfaces of an airfoil. The pressure difference creates a torque around the aircraft's lateral axis, causing the aircraft to pitch up or down.
In other words, any situation that causes a difference in lift between the two wings or between the front and rear of the aircraft will produce a pitching moment.
Therefore, option A, a camber airfoil that is developing zero lift, will not produce a pitching moment since there is no difference in pressure between the top and bottom surfaces. Option B, a camber airfoil at a positive angle of attack, will produce a pitching moment since the difference in pressure between the top and bottom surfaces increases as the angle of attack increases. Option C, a symmetrical airfoil at a zero AOA, will not produce a pitching moment since the airfoil has no camber and there is no difference in pressure between the top and bottom surfaces.
In summary, a situation where there is no difference in pressure between the top and bottom surfaces of an airfoil will not produce a pitching moment.
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what is whether or not each type of glassware can be heated?
Whether or not each type of glassware can be heated depends on the specific type of glassware and the method of heating.
What is method of heating?The method of heating refers to the various ways in which heat energy can be transferred to an object or substance to raise its temperature. Some common methods of heating include:
Conduction: This involves transferring heat through direct contact between two objects or substances. For example, heating a pan on a stove by placing it directly on the burner.Convection: This involves transferring heat through the movement of fluids, such as air or water. For example, a forced-air heating system that circulates warm air through a building.Radiation: This involves transferring heat through electromagnetic waves, such as infrared radiation. For example, the sun heating the earth through radiation.Induction: This involves transferring heat through an electromagnetic field, which induces an electric current and produces heat. For example, an induction cooktop that heats a pot through an electromagnetic field.Whether or not each type of glassware can be heated depends on the specific type of glassware and the method of heating. Some types of glassware, such as borosilicate glass, are designed to withstand high temperatures and are commonly used for heating applications, while other types of glassware may be more susceptible to cracking or breaking when exposed to heat.
Glassware that is designed for heating applications will be labeled as such and will typically have a higher temperature tolerance than glassware that is not intended for heating. Some common types of glassware that are designed for heating include Pyrex, Kimax and Vycor glass.
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We will define the angular momentum only from the exchange relationship, and investigate the nature of the eigenvalue based on the exchange relationship. If you write the generalized angular momentum
Angular momentum is a fundamental concept that arises from the exchange relationship in physics, and its eigenvalues carry important information about the nature of a system. In quantum mechanics, the angular momentum operator L is represented by a vector operator with three components: L = (Lx, Ly, Lz).
The components Lx, Ly, and Lz correspond to the angular momentum's different directions and have direct relationships with position and momentum. Conservation of angular momentum occurs when no external torque acts on an object, and it plays a crucial role in various areas of physics, ranging from subatomic to cosmological scales.
In quantum mechanics, the angular momentum operator L is defined as the cross product of the position operator and the momentum operator: L = r × p. It serves as the generator of rotations, meaning it describes the rotational motion of a system.
The eigenvalues of the angular momentum operator represent the quantized angular momentum of a particle, indicating that angular momentum is quantized in discrete levels. The magnitude of the angular momentum is given by |L| = √(Lx² + Ly² + Lz²).
In summary, the generalized angular momentum is a vector operator that describes the rotational motion of a system and consists of three components. Its eigenvalues represent the quantized angular momentum of particles, and its conservation law has wide-ranging implications in physics.
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A spherical shell of radius 5.6 m is placed
in a uniform electric field with magnitude
1070 N/C.
Find the total electric flux through the
shell.
Answer in units of N m²/C. Answer in
units of N. m²/C.
Answer:
The total electric flux thru the shell is zero.
If you represent the electric field by vectors, for each vector entering the shell a corresponding vector will leave the shell for a net input of zero within the shell.
QUESTION 1
Describe the motion of the car in the following picture.
The car is slowing down.
The car is not moving.
The car is speeding up
The car is moving at a constant velocity
Answer:the car is speeding up
Explanation:
What two horizontal forces are present as a car is pushed down the driveway?(1 point)
push, velocity
power, friction
power, weight
push, friction
The two horizontal forces that are present as a car is pushed down the driveway are push and friction.
A force refers to that which produces or opposes motion. When force(s) is/are acting on a body, they either cause motion to occur or prevent motion from occurring. An example of a force which opposes motion is friction.
For a car being pushed along a driveway, the two possible horizontal forces that act on it are push which moves it forward and friction which resists its motion.
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Answer:
Push and friction
Explanation:
As per Newton's third law
Every action has an equal and opposite reaction.Here the car is pushed so the force applied is pushing force
The opposition force is frictional force
Option D
A common activity like cooking a meal can use many natural _________.
A common activity like cooking a meal can use many natural Ingredients
Ingredients
Ingredients are substances combined to make a particular mixture such as a meal. most of the ingredients used for the preparation of a meal are sourced naturally.
In cooking different recipes of a meal the use of specific ingredients for each recipe differentiates the recipes.
Therefore we can conclude that cooking a meal requires the use of natural ingredients.
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What is the work done when 1 mole of a gas expands isothermally from 25 to 250 l at a constant pressure of 1 atm and a temperature of 300k?
"The work done when 1 mole of a gas expands isothermally from 25 L to 250 L at a constant pressure of 1 atm and a temperature of 300 K is -5744 J."
Given that,
Initial volume V₁ = 25 L
Final volume V₂ = 250 L
Number of moles n = 1
Temperature T = 300 K
We know that, Gas constant R = 8.314 J mol⁻¹ K⁻¹
W = -nRT ln( V₂/V₁)
When the values are entered into the formula, we have
⇒ -1 × 8.314 × 300 × ln(250/25) = -5744 J
Thus, the work done is calculated to be -5744 J.
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An electrical resistor immersed in a liquid produces 65. 0 W of electrical energy for 120
seconds, which heats the 0. 780 kg mass of liquid, causing it to rise in temperature from
18. 55°C to 22. 54°С. Find the average specific heat capacity of the liquid in this temperature
range. Assume that negligible heat is transferred to the container that holds the liquid and that
no heat is lost to the surroundings
The average specific heat capacity of the liquid in this temperature is 2506 J/kg/C
The specific heat capacity, or massic heat capacity, of a substance is calculated using thermodynamics as the heat capacity of a sample of the substance divided by the mass of the sample.A substance's specific heat capacity may be substantially higher when heated in an open vessel that permits expansion than when heated in a closed vessel that prevents expansion, especially when the substance is a gas (specific heat capacity at constant pressure) (specific heat capacity at constant volume).
the amount of heat input to the liquid is 65W x 120s = 65(J/s) x 120s = 7800J
then we have that
Q = \(m\times c \times \delta t\) so that
c = (\(\frac{Q}{m\times\delta t}\)) = \(\frac{7800J}{0.78kg * 3.99C}\) = 2506 J/kg/C
if some of the energy heated the container or surroundings, then less energy actually went into heating the liquid; if less energy caused the 3.99C temp increase, the specific heat must be less, so the value we just calculated is an overestimate.
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If you throw a ball up with a velocity of 7 m/s, how long will it take for the ball to reach the top of its path?
A. 0.11 Seconds
B. 0.41 Seconds
C. 0.71 Seconds
D. 1.01 Seconds
Answer:
c. 0.71 [s]
Explanation:
To solve this problem we must use the following equation of kinematics.
\(v_{f} =v_{o} -g*t\)
where:
Vf = final velocity = 0 (because when the ball reaches the top, there is no movement)
Vo = initial velocity = 7 [m/s]
g = gravity acceleration = 9.81 [m/s²]
t = time [s]
Note: The negative sign of the equation means that the movement is againts the direction of the gravity acceleration.
\(0 = 7 - (9.81*t)\\t = 0.713 [s]\)
Practice Problems
31. Follow-up Suppose the coefficient of kinetic friction is equal to
0.120. What is the acceleration of the salt shaker in this case?
32. A baseball player slides into third base with an initial speed of
40 m/s. If the coefficient of kinetic friction between the player and the
(a) The acceleration of the salt shaker is 1.18 m/s².
(b) The distance traveled by the baseball player before coming to rest is 204.1 m.
Acceleration of the salt shakerThe acceleration of the salt shaker at the given coefficient of kinetic friction is determined as follows;
a = μg
a = 0.12 x 9.8
a = 1.18 m/s²
Acceleration of the baseball player is calculated as follows;
a = μg
a = 0.4 x 9.8
a = 3.92 m/s²
Distance traveled by the baseball playerThe distance traveled by the baseball player before coming to rest is calculated as follows;
v² = u² - 2as
0 = 40² - 2(3.92)s
0 = 1600 - 7.84s
7.84s = 1600
s = 204.1 m
The complete question is below:
A baseball player slides into third base with an initial speed of 40 m/s. If the coefficient of kinetic friction between the player and the ground is 0.40, how far does the player slide before coming to rest?
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