The force constant of the spring is \(-7.03 * 10^5 N/m\) calculated using the force applied to the subway train during the deceleration process.
The force applied to the subway train can be determined using Newton's second law, which states that force (F) is equal to mass (m) multiplied by acceleration (a). In this case, the acceleration can be calculated using the formula
\(a = (v^2 - u^2) / (2s)\),
where v is the final velocity (0 m/s), u is the initial velocity (0.5 m/s), and s is the distance travelled (0.4 m).
First, calculate the acceleration:
\(a = (0 - 0.5^2) / (2 * 0.4) = -0.625 m/s^2\)
Next, calculate the force using Newton's second law:
\(F = m * a = 4.50 * 10^5 kg * -0.625 m/s^2 = -2.81 * 10^5 N\)
Since the force exerted by the spring is equal in magnitude and opposite in direction to the force applied to the subway train, the force constant of the spring (k) can be calculated using Hooke's law:
F = -k * x,
where x is the displacement (0.4 m).
Rearranging the equation,
\(k = F / x = (-2.81 * 10^5 N) / (0.4 m) = -7.03 * 10^5 N/m\)
Therefore, the force constant of the spring is \(-7.03 * 10^5 N/m\).
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How is the answer D?
The graph that corresponds to 0.1 s in one complete cycle is graph D.
option D is the correct answer.
What is the period of a wave?The period of a wave is the time for a particle on a medium to make one complete vibrational cycle. Period, being a time, is measured in units of time such as seconds, hours, days or years.
Also, the period of a wave is the amount of time it takes for a wave to complete one wave cycle or wavelength.
From the given parameter, the coil rotates 10 times in one second. The period of the coil is calculated as;
Period = 1 s / 10
Period = 0.1 s
From the graphs, the only option that has one complete cycle in one second is option D.
Check option D, half cycle is 0.05 s and one full cycle is 0.1 s.
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A 750 kg car is at rest at a red light. If the light turns green and it zooms away with an acceleration of 7. 8 m/s2 how fast will it be traveling in 7 seconds? express your answer in meters per second.
A 750kg car with an acceleration of 7.8m/s^2 will be as fast as 54.6m/s when it travels for 7 seconds.
It is a rate at which velocity changes with time, in terms of both speed and direction. A point or an object moving in a straight line is accelerated if it speeds up or slows down.
How to calculate the speed of 750kg car when traveling in 7 seconds?
Vf = Vo + a*t
Vo = initial speed = 0 (the car is at rest at a red light)
Vf = final speed
a = acceleration = 7.8m/s^2
t =time = 7s
Vf = Vo + a*t
Vf = 0 + 7.8 * 7
Vf = 54.6m/s
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What is a normal line? (a) A line parallel to the boundary between two media (b) A vertical line separating two media (c) A line perpendicular to the boundary between two media
A normal line is a line that is perpendicular to the boundary between two media. It is often used in optics to describe the behavior of light as it interacts with different surfaces.
When a light ray hits a boundary between two media at an angle, it will be refracted or reflected based on the angle of incidence and the properties of the media. The normal line is a reference line that is drawn perpendicular to the boundary at the point where the light ray hits it. This line helps to determine the angle of incidence and angle of reflection or refraction. It is important to note that the normal line is not always a straight line, but can be curved or angled depending on the shape of the surface it is interacting with. Therefore, the correct answer to the question is C) A line perpendicular to the boundary between two media.
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complete question:
What is a normal line? A) A line parallel to the boundary B) A vertical line separating two media C) A line perpendicular to the boundary between two media D) A line dividing incident ray from reflected or refracted ray E) Two of the above are possible
What units are used to measure the magnitude of a vector?
-Grams
-Newtons
-Liters
-Pounds
Answer:
Newtons
Explanation:
Its units are newtons because force has both magnitude and direction.
Which of the following is closest in size (radius) to a white dwarf? A) the Earth B) a small city. C) a football stadium D) a basketball. E) the Sun.
The closest in size (radius) to a white dwarf is option A) the Earth.
A white dwarf is a stellar remnant, typically having a radius similar to that of Earth. While they vary in size, white dwarfs are generally much smaller than the Sun, and larger than a small city, football stadium, or basketball.
White dwarfs are the final evolutionary stage of low-to-intermediate-mass stars, formed when these stars exhaust their nuclear fuel and shed their outer layers. Although their size is similar to Earth, their mass is typically close to that of the Sun, making them incredibly dense objects. It is important to note that the comparison in size is not an exact match, as white dwarfs can differ in size depending on factors such as their mass and temperature, but on average, they are closest in size to Earth among the options provided.
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An airplane is traveling at an altitude of 15,490 meters. A box of supplies is dropped from its cargo hold. What is the cargo's velocity when it hits the ground? (Show your work and do not forget units)
Answer :
556.59 m/s.
Explanation:
Given that,
An airplane is traveling at an altitude of 15,490 meters.
A box of supplies is dropped from its cargo hold. We need to find the velocity of cargo when it hits the ground.
The initial velocity of the box is 0 as it as at rest. Let v is the velocity of cargo when it hits the ground. We can find it using third equation of motion as follows :
\(v^2-u^2=2as\)
Put u = 0 and a = g
\(v^2=2gs\\\\v=\sqrt{2gs} \\\\v=\sqrt{2\times 10\times 15490 } \\\\v=556.59\ m/s\)
So, when it hits the ground its velocity is 556.59 m/s.
wavelengths of large-scale objects are much smaller than any aperture through which the objects could pass.
When discussing the wavelengths of large-scale objects, we are referring to their de Broglie wavelengths. According to the de Broglie hypothesis, all objects exhibit wave-like behavior, with their wavelength inversely proportional to their momentum. As the mass and speed of an object increase, its wavelength decreases.
Large-scale objects, such as cars or boulders, have substantial mass and therefore their de Broglie wavelengths are extremely small. This means that their wave-like properties are insignificant in comparison to their particle-like properties.
Apertures are openings or holes through which objects can pass. When an object's de Broglie wavelength is much smaller than the aperture, its wave-like behavior has no observable effects, and the object's particle-like behavior dominates. In this case, the object would not exhibit any noticeable wave-like properties, such as diffraction or interference, while passing through the aperture.
In summary, large-scale objects have very small de Broglie wavelengths, making their wave-like properties negligible compared to their particle-like properties. As a result, these objects' wavelengths are much smaller than any aperture through which they could pass, and their behavior is dominated by their particle-like characteristics.
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The following three questions are predictions and points will not be deducted if they are incorrect. We will test our hypothesis based on results from the lab experiment for credit in future questions.
HYPOTHESIS 01 - Total current will be greater when a circuit is connected in:
Choose one points
a. Series
b. Parallel
Hypothesis 01, which states that the total current will be greater when a circuit is connected in parallel, is true
When a circuit is connected in parallel, the total current will be greater because in a parallel circuit, each component has the same voltage across it, allowing each component to pass current based on its resistance. This results in an increased total current in the circuit.
Parallel circuits have benefits such as powering multiple appliances while keeping them isolated from each other, as the voltage remains the same for all devices. This allows them to operate independently. Additionally, if one component fails or becomes disconnected, the other components in the parallel circuit will continue to work normally.
Hypothesis 01, which states that the total current will be greater when a circuit is connected in parallel, is true based on the explanation above. Therefore, Hypothesis 01 is correct.
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A small sphere with mass 1.50ghangs by a thread between two large parallel verticalplates 5.00{\rm cm}apart. The plates are insulating and have uniformsurface charge densities+ \sigmaand- \sigma. The charge on the sphere isq= 7.00×10−6C
The calculation demonstrates how the electric field and surface charge density affect the motion of a charged object in an electric field.
Why will be the charge on the sphere isq?The electric field between the two plates is uniform and directed vertically from the positive plate to the negative plate. Let's assume that the small sphere is positively charged.
The electric force acting on the small sphere is given by:
\(F = qE\)
where q is the charge on the sphere and E is the electric field.
The electric field between the plates can be calculated using Gauss's law:
\(E = σ/ε0\)
where σ is the surface charge density and ε0 is the permittivity of free space.
The force on the sphere due to the electric field is balanced by the weight of the sphere, so we have:
\(F = mg\)
where m is the mass of the sphere and g is the acceleration due to gravity.
Setting these two equations equal to each other, we get:
\(qE = mg\)
Substituting for E and solving for m, we get:
\(m = qσ/ε0g\)
Substituting the given values, we get:
m = (7.00×10⁻⁶ C)(-σ)/(8.85×10⁻¹² C²/N·m²)(9.81 m/s²)
where we have used -σ because the electric field is directed downwards.
We need to find the magnitude of the surface charge density, so we can use the electric field between the plates:
\(E = σ/ε0\)
Solving for σ, we get:
\(σ = Eε0\)
Substituting the given values, we get:
σ = (5.00×10⁴ N/C)(8.85×10⁻¹² C²/N·m²)
Therefore, the magnitude of the surface charge density is:
|σ| = 4.43×10⁻⁷ C/m²
Substituting this value into the expression for the mass of the sphere, we get:
m = (7.00×10⁻⁶ C)(-4.43×10⁻⁷ C/m²)/(8.85×10⁻¹² C²/N·m²)(9.81 m/s²)
m ≈ -1.29×10⁻¹² kg
The negative sign indicates that the sphere has a net downward force, so it will move downwards. However, the thread will prevent it from falling further, and it will come to rest at a certain point between the plates.
Note that the mass of the sphere is extremely small, so this situation is difficult to observe in practice.
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A rock on the roof of a building is 45m high. the rock weighs 20n. the rock has _____ energy
The rock on the roof of the building has potential energy. Potential energy is the energy that an object possesses due to its position or state. In this case, the rock is at a height of 45m, which gives it potential energy.
The formula to calculate potential energy is
PE = mgh, where m is the mass of the object, g is the acceleration due to gravity (approximately 9.8 m/s^2), and h is the height.
However, the mass of the rock is not given in the question, so we cannot calculate the exact value of potential energy. But we know that the rock weighs 20N, which is its weight.
Weight is the force due to gravity acting on an object, and it is equal to the mass of the object multiplied by the acceleration due to gravity. So, the rock has potential energy due to its position on the roof of the building.
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Another piece of copper has a volume of 7 cm3 what is its mass?
The mass of a piece of copper that has volume of 7\(cm^{3}\) is 62.58g.
A piece of copper has a volume of 7 \(cm^{3}\), find what is its mass?The element copper (Cu) is a reddish, very ductile metal belonging to Periodic Group 11 that has an exceptional ability to conduct heat and electricity. In nature, copper can be found in its free metallic state.
Given,
Volume = 7 cm^3
we know that,
The density of copper is 8.960g/cm^3 in room temperature.
Density = mass / volume
Mass = Density x Volume
Mass = 8.960 x 7
Mass = 62.72 g
Mass of copper has a volume of 7 cm^3 is 62.72g.
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A scooter is running at a constant speed of 15 m/s . how much distance will it cover in 45 seconds ? a. 610 m b. 620 m c. 675 m
Question :-
A Scooter is Running at a Constant Speed of 15 m/s . How much Distance will it cover in 45 sec ?610 meter620 meter675 meterAnswer :-
Distance covered by the Scooter in 45 seconds is 675 meter .Explanation :-
As per the provided information in the given question, we have been given that the Speed of scooter is 15 m/s . And, we have been asked to calculate the Distance , covered by the scooter in 45 seconds .
For calculating the Distance , we will use the Formula :-
\( \bigstar \: \: \boxed{ \sf{ \: Distance \: = \: Speed \: \times \: Time \: }} \)
Therefore , by Substituting the given values in the above Formula :-
\( \dag \: \: \: \sf { Distance \: = \: Speed \: \times \: Time \: } \)
\( \longmapsto \: \: \: \sf { Distance \: = \: 15 \: \times \: 45 \: } \)
\( \longmapsto \: \: \textbf {\textsf { Distance \: = \: 675 meter}} \)
Hence , 3 Option is correct !\( \underline {\rule {180pt} {4pt}} \)
A wave has a period of 4 seconds. Find it’s frequency.
Answer:
4 x the frequncy
Explanation:
So 4 x the number
the chapley-curtis debate concerned the location of the chapley-curtis debate concerned the location of the milky way galaxy. center of the universe. the sun within the milky way galaxy. spiral nebulae.
Yes , Astronomer Edwin Hubble was able to determine the distance .
What is Shapley-Curtis debate ?
The dispute between Shapley and Curtis centered on the existence of other galaxies, with Curtis asserting the existence of other galaxies and Shapley asserting that the other nebulae observed were part of the Milky Way. The argument came to a final conclusion when Hubble was able to show that the Andromeda galaxy is over a million light years away and not part of our galaxy. We were able to determine the distance to a variable star in the Andromeda galaxy more than a year away.
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select one: a. snow straw b. snow roller c. snow cannon d. snow barrel e. a botched attempt at making a snowman
The best option for making a snowman would be option e. a botched attempt at making a snowman.
A botched attempt at making a snowman implies that there was an initial intention to construct a snowman but something went wrong or it did not turn out as expected. This option suggests that the person making the snowman encountered challenges or made mistakes during the process, which adds an element of creativity, humor, and relatability to the answer.
Making a snowman can be a fun and creative activity, and many people have experienced the frustration of trying to shape the perfect snowman, only to have it fall apart or not meet their expectations. This option acknowledges the reality that not every attempt at making a snowman is successful, and it resonates with the common experiences and struggles people face when engaging in this winter tradition.
In conclusion, option E, a botched attempt at making a snowman, is the most suitable choice for making a snowman as it captures the relatable experiences and challenges associated with this activity.
Therefore the correct answer is e. a botched.
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.Part A. What is the magnitude of the current in the 30 ohm resistor in the figure? answer in Amperes
Part B. What is the direction of the current?
Part A: To calculate the magnitude of the current in the 30-ohm resistor in the figure, we need to apply Ohm's Law, which states that the current flowing through a conductor is directly proportional to the voltage applied across it and inversely proportional to its resistance.
The voltage across the resistor is given as 6 volts (from the battery) and the resistance of the resistor is 30 ohms. Therefore, the magnitude of the current can be calculated as: Current (I) = Voltage (V) / Resistance (R) = 6V / 30Ω = 0.2 Amperes. So, the magnitude of the current in the 30-ohm resistor is 0.2 Amperes. Part B: To determine the direction of the current, we need to apply Kirchhoff's Current Law (KCL), which states that the algebraic sum of the currents entering and leaving any node in a circuit must be zero. In the given circuit, we can see that the current flowing through the 30-ohm resistor is leaving the node and entering into the negative terminal of the battery. Therefore, the direction of the current in the 30-ohm resistor is from left to right.
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If you are on a boat in the trough of a wave on the ocean, and the wave amplitude is 1 meter, what is the wave height from your position?
Group of answer choices
4 meters 2 meters .5 meters 1 meter
Answer:
2 meters
Explanation:
In oceanography, the term "wave height" refers to the vertical distance between the crest (the highest point) and the trough (the lowest point) of a wave. If you are situated in the trough of a wave, the wave height would be double the wave amplitude.
In this case, you mentioned that the wave amplitude is 1 meter. Therefore, the wave height from your position in the trough would be 2 meters.
What happens when light from the Sun passes through any type of matter? The light slows down.
The light speeds up.
Most of the light is absorbed.
Most of the light is reflected.
Answer:
A
Explanation:
THE LIGHT SLOWS DOWN
When light from the Sun passes through any type of matter the light slows down.
Interaction of sunlight with matter:The behavior of light from the Sun as it interacts with any matter depends on the matter and its properties.
Since it comes through a vacuum and enters our atmosphere which is a denser medium and has a definite refractive index, the light slows down.
This also happens when light falls on material such as glass, water, and other transparent and translucent media. When it emerges out of such medium to a rarer medium like air, it speeds up to its initial speed.
A portion of the sunlight is absorbed by almost all the matter present on earth that's why something heats up when exposed to sunlight. While a considerable portion of the sunlight is reflected by the matter.
But the question says what happens when it passes through any matter. The answer is:
It slows down while passing through the matter since any matter is optically denser than the vacuum.
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What is the combining capacity of element called?
[1 marks]
atomic number
valency
molecular formula
proton
the combining capacity of an element is known as its valency
A parachute on a racing dragster opens and changes the speed of the car from 93 m/s to 45 m/s in a period of 5.3 seconds. What is the acceleration of the dragster?
Answer:
\(-9.06\:\mathrm{m/s^2}\)
Explanation:
We can use the following kinematics equation to solve for acceleration:
\(v_f=v_f+at\).
Solving for \(a\):
\(45=93+5.3a,\\-48=5.3a,\\a\approx \boxed{-9.06\mathrm{m/s^2}}\)
*Note: Since acceleration is a vector quantity, it has both magnitude and direction. The negative sign implies that the acceleration is in the opposite direction of the racing dragster's movement.
SOO EASYY Can you please fill this in properly with complete sentences?
The fill up of the terms explanations with complete sentences is given below.
How does satellite communication work?Communication
Radio waves are used by satellites to transmit signals to antennas on Earth. These signals are subsequently picked up by the antennas, who then process the data they contain.
In its working on earth, Communications satellites are used to transport signals around the curved surface of the Earth, enabling communication between distant geographic locations. Satellites for communication use a variety of radio and microwave frequencies.
Tracking devices
To exactly place their location, GPS trackers acts to connect to a constellation of the satellites. The tracker employs a technique known as trilateration to calculate latitude, longitude, elevation, as well as time by comparing its location to that of three or more satellites in the Global Navigation Satellite System (GNSS) network and calculating its separation from them.
In its working on earth, a network of satellites and receiving equipment called the global positioning system (GPS) is used to locate objects on Earth. The location of some GPS receivers may be determined to within one centimeter (0.4 inches). Location is provided by GPS receivers in terms of latitude, longitude, and altitude.
Remote sensing and Digital imaging
Digital photography has a unique application in satellite images. Satellite sensors may gather electromagnetic spectrum radiation bands that are reflected back into space from the Earth's surface and record them digitally as pixels.
In its working on earth, Scientists can track volcanic eruptions' harmful dust and ash for aviation using satellite remote sensing. Pilots can more effectively analyze risks and make knowledgeable decisions before takeoff if they have access to more thorough, up-to-date information on dangers in their flight path.
Real-time imaging
The electromagnetic radiation reflected from the Earth is captured by satellites using a variety of sensors. The Earth and the Sun both emit radiation, which passive sensors collect without the use of energy. Active sensors generate their own radiation, which they then examine after it is reflected back to them by the Earth.
Therefore, in its working on earth, the data that satellites gather about the surface and ocean of the earth is known as satellite imagery. Both land cover and usage analyses using satellite imagery are employed in the analysis and forecasting of weather.
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why does relative humidity increase at night and decrease during the day?
The change in relative humidity throughout the day and night is primarily influenced by two factors: temperature and the diurnal cycle of atmospheric moisture.
The relative humidity refers to the amount of water vapor present in the air compared to the maximum amount of water vapor the air can hold at a particular temperature. The change in relative humidity throughout the day and night is primarily influenced by two factors: temperature and the diurnal cycle of atmospheric moisture.
During the day, as the Sun heats the Earth's surface, the temperature rises. Warmer air can hold more water vapor, so the air's capacity to hold moisture increases. However, this does not necessarily mean that the actual amount of water vapor in the air increases proportionally. As the air warms up, it becomes less dense and can rise, leading to vertical mixing and dispersion of moisture. Additionally, the warmer air can enhance the evaporation of water from surfaces, including bodies of water and vegetation. These processes tend to result in a decrease in relative humidity during the day.
At night, the opposite occurs. As the Sun sets and the temperature drops, the air cools down. Cooler air has a lower capacity to hold moisture, so the relative humidity tends to increase. The cooler air reduces the rate of evaporation and allows moisture to condense, leading to an accumulation of water vapor in the air. The reduced temperature also lowers the air's ability to disperse moisture through vertical mixing. As a result, relative humidity tends to be higher during the night.
It's important to note that local geographic and meteorological conditions can also influence relative humidity patterns, so variations may occur depending on the specific location and climate.
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A mountain climber has a mass (with all of their equipment) of 95, point, 0, k, g,95.0kg. If they were perfectly efficient, and ate 500, g,500g of chocolate (providing 11, point, 1, M, J,11.1MJ of chemical energy), how high could they climb?
Answer:
11900 meters
Explanation:
Use the Potential energy = mgh formula, substituting these in to get 11.1x10^6 = 95 x 9.81 x h.
Rearrange to make h the subject and the answer given is 11900 (3sig.fig.)
The maximum height to which he can climb will be 1.168 x 10⁴ meters.
What is potential energy?
The potential energy of a body is the energy of the body due it position. The potential energy always exist for two bodies which are in mutual interaction with each other for example by a force. For body a on earth, the potential energy of the body - earth system is -
E[P] = mgh
Given is a mountain climber that has a mass of 95 kg.
We can write -
Mass of climber = [M] = 95 kg
Energy gained by eating the chocolate = [E] = 11.1 MJ = 1.11 x 10⁷ joules
Assume that the height achieved achieve by the climber is [h] meters
Therefore, the potential energy gained at that height will be equal to 11 MJ
Therefore -
mgh = 1.11 x 10⁷
95 x 10 x h = 1.11 x 10⁷
95 x 10 x h = 1110 x 10⁴
h = (1110 x 10⁴)/950
h = 1.168 x 10⁴ meters
Therefore, the maximum height to which he can climb will be 1.168 x 10⁴ meters.
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Which quantity must equal zero if a car is moving at a constant rate along a straight line?
A. direction of the car
B. energy of the car
C. speed of the car
D. acceleration of the car
The acceleration of the car must equal zero if a car is moving at a constant rate along a straight line.
What forces are acting on a car moving at a constant speed?A car moving at a constant speed (uniform motion) has all forces acting on it balanced. In this case, the two backward forces (air resistance and friction) perfectly balance the applied force of the wheels on the road in the opposite direction.
When the car is moving at a constant speed?Acceleration is defined as the rate of change in speed. So if the car is moving at a constant speed that means the rate of change in speed is zero. Hence, acceleration is zero.
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the magnitude of the force of a 400-n/c electric field on a 0.02-c point charge is:
The magnitude of the force exerted on the 0.02 C point charge in a 400 N/C electric field is 8 N. It is important to note that the force is a vector quantity, meaning it has both magnitude and direction. In this case, the direction of the force would depend on the polarity of the charge and the direction of the electric field.
The magnitude of the force exerted on a point charge in an electric field can be determined using the formula:
F = q * E
Where: F is the force exerted on the charge, q is the magnitude of the charge, and E is the magnitude of the electric field.
In this case, the magnitude of the electric field is given as 400 N/C, and the magnitude of the point charge is 0.02 C.
Substituting these values into the formula, we get:
F = (0.02 C) * (400 N/C)
Calculating this, we find:
F = 8 N
Therefore, the magnitude of the force exerted on the 0.02 C point charge in a 400 N/C electric field is 8 N. It is important to note that the force is a vector quantity, meaning it has both magnitude and direction. In this case, the direction of the force would depend on the polarity of the charge and the direction of the electric field.
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A funnel is dipped into a liquid soap solution. State and explain what happens to the soap bubble when the funnel is removed
Answer: When a funnel is dipped into a liquid soap solution, soap molecules from the solution stick to the surface of the funnel and form a thin film. As the film becomes thinner, it reaches a point where it can no longer support its own weight, and gravity causes it to detach from the funnel and form a soap bubble.
When the funnel is removed, the soap bubble remains intact due to the surface tension of the soap film. Soap molecules have hydrophilic (water-attracting) and hydrophobic (water-repelling) ends, which enable them to form a stable film at the surface of the liquid. The surface tension of the soap film creates a force that tries to minimize the surface area of the bubble, which is why soap bubbles tend to form spherical shapes.
However, the soap bubble is not stable and will eventually burst due to a number of factors, such as evaporation of the liquid, changes in temperature or humidity, or contact with other objects. When the soap bubble bursts, the soap film breaks apart and the soap molecules mix with the surrounding air or liquid.
Explanation:
When a funnel is dipped into a soap solution and removed, a soap bubble forms due to the surface tension of the soap solution. As air is blown into it, the bubble expands until it pops when the soap film can't withstand the pressure difference anymore.
Explanation:When a funnel is dipped into a liquid soap solution and then removed, a soap bubble forms at the end of the funnel. This phenomenon occurs due to a property of liquids known as surface tension. Surface tension is the force that causes the liquid surface to contract, thus forming a shape with the minimum possible area, a sphere.
After the funnel is dipped into the soap solution, a thin film of soap solution forms inside it. When the horn is removed and the air is blown from the other end, the air trapped inside the thin soap film expands to include a bubble.
Eventually, gravity causes the liquid soap to flow downwards, thinning the top of the bubble, and the bubble will pop when the film is too thin to sustain the pressure difference between the inside and outside. So, stating and explaining what happens to the bubble when the funnel is removed can also take into consideration the effect of gravity in this process.
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Target zone means that is your minimum amount of work you do when training.
(1 Point)
True
False
Answer:
False
Explanation:
Target zone is generally approximatly 70% (maybe 80%) of your maximum amount of work you can do.
Which one of the following is NOT acceleration
A.
a change in mass
B.
a change in direction
C.
an increase in velocity
D.
a decrease in velocity
Answer:
change in direction
Explanation:
ans maybe correct
Why can’t security gates detect plastic bomb ?
Answer:
The plastic is too much like other things that are allowed. Sometimes it is too thin, as well. Or sometimes the gates are just not that modern and advanced enough to detect them.
please fast
The system shown in the figure below uses three chain comveyors. Each chain has a hydraulic motor: The torque that drives the motors is T: =1500 N.m
1 T2 =700 Nm and, T3 = 300Nm. The displactment volume of the motors is V01 =1000 cm3/rev V02 =1000 cm3/rev and, V09 =500 cm3 /rex. The motss have a volumetric efficiency of 0.9 and an overall efficiency of 0.85. The leakage of the bydraulic motors 1 and 3 is internal completely and the leakage of the hydraulic motor 2 is external completely. The pump produces a constant volumetric flow rate of 6.3U/min.
The orifice of the flow control valve has a 0.5 mm diameter. The pressure fosses through the pipes are neglected. The capacity coefficient of the needie valve is 07. The volumetric Alow rate through the needle valve is given by: Q=C×A2 ×ΔF/rho where C is the capacity coefficient, A is the area of the orifice, ΔP is the difference of pressure through the needle valve and, rho is the density of the fiuid.
The density of the oil used in the hydraulic system is 860 kg/m3 . Determine the rotational speed of the motor 3 in rpm. a. 8 b. 92 c. 67 d. 42 e. 34 E. 56
The rotational speed of the motor 3 in rpm. b. 92
The figure shows a hydraulic circuit that uses three chain conveyors. The torque that drives the motors is T: =1500 N.m. T2 =700 Nm and, T3 = 300Nm.The volumetric flow rate produced by the pump is 6.3 liters per minute. The displacement volume of the motors is V01 =1000 cm3/rev. V02 =1000 cm3/rev and, V09 =500 cm3/rex.
The motors have a volumetric efficiency of 0.9 and an overall efficiency of 0.85. The leakage of hydraulic motors 1 and 3 is internal completely, while the leakage of hydraulic motor 2 is external completely.The orifice of the flow control valve has a diameter of 0.5 mm. The capacity coefficient of the needle valve is 0.7.
The pressure losses through the pipes are ignored. The volumetric flow rate through the needle valve is Q = C × A2 × ΔP / ρ where C is the capacity coefficient, A is the area of the orifice, ΔP is the pressure difference through the needle valve, and ρ is the density of the fluid. The density of the oil used in the hydraulic system is 860 kg/m3. We need to determine the rotational speed of motor 3 in rpm.
So,Let’s first determine the volumetric flow rate required by hydraulic motor 3. Using the expression of volumetric flow rate through the needle valve, we have Q = C × A2 × ΔP / ρ… (i)We are given that the capacity coefficient of the needle valve is 0.7. Its orifice diameter is 0.5 mm.
Hence, the area of the orifice is given byA2 = π d2 / 4where d is the diameter of the orifice. So, A2 = π × (0.5 mm)2 / 4 = 0.196 mm2 = 1.96 × 10-7 m2Using equation (i), we haveQ = C × A2 × ΔP / ρNow, we will calculate ΔP. To do this, we need to determine the flow rates Q1, Q2, and Q3.Let Q’ be the total volumetric flow rate through the system.
Since the overall efficiency of the system is given as 0.85, we haveQ’ = 0.85 × 6.3 l/min = 5.355 l/min = 5.355 × 10-3 m3/minWe know that the volume of fluid passing through the hydraulic motors is equal to their displacement volume multiplied by the number of revolutions per unit time.So, we haveQ1 = V01 × n1 … (ii)Q2 = V02 × n2 … (iii)Q3 = V03 × n3 … (iv)where V01, V02, and V03 are the displacement volumes of hydraulic motors 1, 2, and 3, respectively.
We are given that V01 = V02 = 1000 cm3/rev and V03 = 500 cm3/rev, which gives V01 = V02 = 1 × 10-6 m3/rev and V03 = 0.5 × 10-6 m3/rev.Substituting equations (ii), (iii), and (iv) in equation (i), we haveQ = C × A2 × (Q1 + Q2 - Q3) / ρSolving for Q3, we getQ3 = (Q1 + Q2 - Q) / C × A2 × ρPutting the given values in the above expression, we haveQ1 = V01 × n1 = (1 × 10-6 m3/rev) × n1Q2 = V02 × n2 = (1 × 10-6 m3/rev) × n2Q3 = V03 × n3 = (0.5 × 10-6 m3/rev) × n3Q = 5.355 × 10-3 m3/min = 5.355 × 10-3 / 60 m3/s = 8.925 × 10-5 m3/sA2 = 1.96 × 10-7 m2C = 0.7ρ = 860 kg/m3
Substituting the above values, we get8.925 × 10-5 = (1 × 10-6 × n1 + 1 × 10-6 × n2 - 0.5 × 10-6 × n3) / (0.7 × 1.96 × 10-7 × 860)Solving for n3, we have n3 = 91.6 rpmSo, the correct option is b. 92.
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