A 5.0 kg object suspended on a spring oscillates such that its position x as a function of time t is given by the equation x (t ) = A cos(ωt ), where A = 0.80 m and ω = 2.0 s-1 . What is the magnitude of the maximum net force on the object during the motion?

Answer:

The energy that is changing during a phase change is potential energy. During a phase change, the heat added (PE increases) or released (PE decreases) will allow the molecules to move apart or come together. Heat absorbed causes the molecules to move farther apart by overcoming the intermolecular forces of attraction.

Answer and Explanation:

a. The computation of the percent difference between the measurements is shown below:-

The first value of g is 9.67 and the second value is 9.88

So, difference = 9.88 - 9.67

= 0.21

Percentage difference in measurement is

\(= \frac{0.21}{9.88}\times100\)

= +/-2.13

Percent difference with 9.88

Difference =  9.88 - 9.81

= 0.07

\(= \frac{0.07}{9.81}\times100\)

= +/-0.71%

b. The Computation of percent error of their mean is shown below:-

Mean of two values is

= \(\frac{9.67 + 9.88}{2}\)

= 9.775

Difference = 9.81 - 9.775

= 0.035

Percentage difference is

\(= \frac{0.035}{9.81}\times 100\)

= +/- 0.36%

Answer:

0 j

Explanation:

The work done by the employee on the box at the given zero displacement is 0 J.

The given parameters;

The work done by the employee on the box is calculated as follows;

W = Fd

where;

Since the employee sits on the box without moving it, the distance moved by the box = 0

W = 500 x 0

W = 0 J

Thus, the work done by the employee on the box is 0 J.

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The Phase shift is a shift in sound wave frequency that happens when the originator of the acoustic pressure is moving in relation to a listener who is stationary.

As an observer and a mobile source of waves come closer together, there appears to be an upward shift in frequency, and when they move apart, there appears to be a downward movement in frequency. This phenomenon is known as the Doppler effect.

Doppler shift is frequently demonstrated by the change in pitch that occurs as a car approaches and moves away from a viewer while sounding its horn. The received frequency increases during proximity, identical at the time of passing by, and lower when matched to the emitted frequency.

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The equation E = F/q can be used to determine the strength of the electric field (E) at the location denoted by the dot.

The force applied per unit of positive charge is referred to as the electric field's strength, or E. It may be shown from the equation E = F/q. Volts per meter (V/M) or Newton per Coulomb are its SI units.

You should be aware that an electric field is strongest where the lines are close and weakest when the lines are far apart.

The technique above can be used to determine the answer even though the whole question is not given.

The equation E = F/q where gives the magnitude of the electric field (E) at the location denoted by the dot: E = F/q where;

F = Force exerted per unit and

q = The electric charge there is positive.

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Answer:

The speed stays constant after the force stops pushing.

Explanation:

Speed always stays constant when the force stops pushing it.

Answer:

Refer to the step-by-step Explanation.

Step-by-step Explanation:

Simplify the equation with given substitutions,

Given Equation:

\(mgh+(1/2)mv^2+(1/2)I \omega^2=(1/2)mv_{_{0}}^2+(1/2)I \omega_{_{0}}^2\)

Given Substitutions:

\(\omega=v/R\\\\ \omega_{_{0}}=v_{_{0}}/R\\\\\ I=(2/5)mR^2\)\(\hrulefill\)

Start by substituting in the appropriate values: \(mgh+(1/2)mv^2+(1/2)I \omega^2=(1/2)mv_{_{0}}^2+(1/2)I \omega_{_{0}}^2 \\\\\\\\\Longrightarrow mgh+(1/2)mv^2+(1/2)\bold{[(2/5)mR^2]} \bold{[v/R]}^2=(1/2)mv_{_{0}}^2+(1/2)\bold{[(2/5)mR^2]}\bold{[v_{_{0}}/R]}^2\)

Adjusting the equation so it easier to work with.\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2} \Big[\dfrac{2}{5} mR^2\Big]\Big[\dfrac{v}{R} \Big]^2=\dfrac12mv_{_{0}}^2+\dfrac12\Big[\dfrac25mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\)

\(\hrulefill\)

Simplifying the left-hand side of the equation:

\(mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2} \Big[\dfrac{2}{5} mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\)

Simplifying the third term.

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2} \Big[\dfrac{2}{5} mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2}\cdot \dfrac{2}{5} \Big[mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\)

\(\\ \boxed{\left\begin{array}{ccc}\text{\Underline{Power of a Fraction Rule:}}\\\\\Big(\dfrac{a}{b}\Big)^2=\dfrac{a^2}{b^2} \end{array}\right }\)

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v^2}{R^2} \Big]\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2 \cdot\dfrac{v^2}{R^2} \Big]\)

"R²'s" cancel, we are left with:

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v^2}{R^2} \Big]\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5}mv^2\)

We have like terms, combine them.

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v^2}{R^2} \Big]\\\\\\\\\Longrightarrow mgh+\dfrac{7}{10} mv^2\)

Each term has an "m" in common, factor it out.

\(\Longrightarrow m(gh+\dfrac{7}{10}v^2)\)

Now we have the following equation:

\(\Longrightarrow m(gh+\dfrac{7}{10}v^2)=\dfrac12mv_{_{0}}^2+\dfrac12\Big[\dfrac25mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\)

\(\hrulefill\)

Simplifying the right-hand side of the equation:

\(\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac12\cdot\dfrac25\Big[mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15\Big[mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15\Big[mR^2\Big]\Big[\dfrac{v_{_{0}}^2}{R^2}\Big]\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15\Big[mR^2\cdot\dfrac{v_{_{0}}^2}{R^2}\Big]\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15mv_{_{0}}^2\Big\\\\\\\\\)

\(\Longrightarrow \dfrac{7}{10}mv_{_{0}}^2\)

Now we have the equation:

\(\Longrightarrow m(gh+\dfrac{7}{10}v^2)=\dfrac{7}{10}mv_{_{0}}^2\)

\(\hrulefill\)

Now solving the equation for the variable "v":

\(m(gh+\dfrac{7}{10}v^2)=\dfrac{7}{10}mv_{_{0}}^2\)

Dividing each side by "m," this will cancel the "m" variable on each side.

\(\Longrightarrow gh+\dfrac{7}{10}v^2=\dfrac{7}{10}v_{_{0}}^2\)

Subtract the term "gh" from either side of the equation.

\(\Longrightarrow \dfrac{7}{10}v^2=\dfrac{7}{10}v_{_{0}}^2-gh\)

Multiply each side of the equation by "10/7."

\(\Longrightarrow v^2=\dfrac{10}{7}\cdot\dfrac{7}{10}v_{_{0}}^2-\dfrac{10}{7}gh\\\\\\\\\Longrightarrow v^2=v_{_{0}}^2-\dfrac{10}{7}gh\)

Now squaring both sides.

\(\Longrightarrow \boxed{\boxed{v=\sqrt{v_{_{0}}^2-\dfrac{10}{7}gh}}}\)

Thus, the simplified equation above matches the simplified equation that was given.  

Answer:

D. X-rays have more energy than ultraviolet waves.

The stretch of the spring is proportional to the weight of the mass hung from it. Since the spring stretches by 5.9 cm when a 1.6 kg mass is hung from it, we can use this information to find the stretch when a 2.1 kg mass is hung from it.

The stretch of the spring is given by:

stretch = (mass x gravity x length) / (spring constant)

where mass is the mass hung from the spring, gravity is the acceleration due to gravity (9.81 m/s^2), length is the stretch of the spring, and the spring constant is a measure of the stiffness of the spring (measured in N/m).

We can rearrange this equation to solve for the stretch of the spring:

stretch = (mass x gravity x length) / (spring constant)

length = (spring constant x stretch) / (mass x gravity)

Substituting the given values, we get:

length = (spring constant x 0.059 m) / (1.6 kg x 9.81 m/s^2)

Simplifying, we get:

length = 0.236 m

Therefore, the stretch of the spring when a 2.1 kg mass is hung from it is 0.236 m.

The power used, given that a force of 20 N is used to push the shopping cart 3.5 m in 2 seconds is 35 W

First, we shall determine the work done in pushing the cart. Details below:

Wd = Fd

Wd = 20 × 3.5

Wd = 70 J

Finally, we shall determine the power used in pushing the cart. Details below:

P = Wd / t

P = 70 / 2

P = 35 W

Thus, we can conclude that the power used is 35 W

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Answer:

Photovoltaic detection is a technique that converts light into electrical energy. It is a process that involves the use of a photovoltaic cell, which is made up of semiconductor materials, to generate an electric current when exposed to light.

The photovoltaic cell absorbs the photons of light, which then knock electrons out of their orbits, creating a flow of electricity. The amount of electricity produced is proportional to the intensity of the light. The photovoltaic cell is commonly used in solar panels to generate electricity from sunlight. The efficiency of the photovoltaic cell is dependent on several factors, including the type of semiconductor material used, the purity of the material, and the thickness of the cell.

The photovoltaic cell has many applications, including in solar power generation, telecommunications, and remote sensing. The technique of photovoltaic detection is an important area of research, as it has the potential to provide a clean and renewable source of energy that can help mitigate climate change.

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Answer:

The tissue that holds bones together at movable joints is ligaments. Ligaments are strong, fibrous connective tissues that connect bones to other bones, providing stability and limiting excessive movement at the joints. They help to maintain the proper alignment and function of the joints while allowing for controlled movement.

Explanation:

The tissue that holds bones together at movable joints is ligaments. Ligaments are strong, fibrous connective tissues that connect bones to other bones, providing stability and limiting excessive movement at the joints. They help to maintain the proper alignment and function of the joints while allowing for controlled movement.

Answer:

The answer is ligaments!

Explanation:

Hope this helps!! :)

The impulse given to the ball by the floor is 0.2865 kg.m/s.

The change in momentum is equal to the product of impact force applied while colliding and time for that impact.

Impulse F. t = m (Vf -Vi)

where, Vf is the final velocity and Vi is the initial velocity.

A ball of mass 500g is dropped from a height 1.5m . It rebounds the floor and reached the height 1.2m.

The initial velocity u = √2x 9.81 x 1.5 = 5.425 m/s

The final velocity v = √2x 9.81 x 1.2 = 4.852 m/s

Substitute the values into the expression, we get

Impulse = m(v- u)

Impulse=0.5 x (4.852- 5.425 )

Impulse = - 0.2865 kg.m/s

Thus, the magnitude of impulse given to the ball by the floor is 0.2865 kg.m/s.

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Answer:

D

Explanation:

Mass is the amount of matter your body has ....does not change on the Moon.

there is less gravity .....so your WEIGHT would decrease

The charge on the 6 μF capacitor is 10.29 μC.

What is the charge of capacitor?

The charge of a capacitor is the amount of electric charge stored on its plates due to the potential difference (voltage) between them. The charge is directly proportional to the capacitance and the voltage across the capacitor, according to the formula Q = CV, where Q is the charge, C is the capacitance, and V is the voltage.

First, we can calculate the equivalent capacitance of the two capacitors connected in parallel:

\(C_{parallel}\)= C1 + C2 = 6 μF + 8 μF = 14 μF

Next, we can calculate the total equivalent capacitance of the circuit, which is the capacitance of the parallel combination in series with the 14 μF capacitor:

1/\(C_{total}\) = 1/ \(C_{parallel}\) + 1/C3

1/\(C_{total}\) = 1/14 μF + 1/14 μF

1/\(C_{total}\) = 1/7 μF

\(C_{total}\) = 7 μF

Using the formula Q = CV, we can calculate the charge on the 6 μF capacitor:

Q = C × V = 6 μF × 12 V / 7 μF = 10.29 μC

Therefore, the charge on the 6 μF capacitor is 10.29 μC.

What is capacitance?

Capacitance is the ability of a capacitor to store electric charge when a voltage is applied across its terminals. It is defined as the ratio of the electric charge stored in the capacitor to the voltage applied to it, and its unit is the farad (F). A capacitor with a high capacitance value can store more charge for a given voltage than a capacitor with a lower capacitance value.

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(a) The work done by the 150 N force is 877.5 Joules.

(b) The coefficient of kinetic friction between the crate and the surface is approximately 0.437.

To answer this problem, we must take into account the work done by the applied force as well as the work done by friction.

(a) The applied force's work may be estimated using the following formula:

Work = Force * Distance * cos(theta)

where the force is 150 N and the distance is 5.85 m. Since the force is applied horizontally and the displacement is also horizontal, the angle theta between them is 0 degrees, and the cosine of 0 degrees is 1.

As a result, the applied force's work is:

Work = 150 N * 5.85 m * cos(0) = 877.5 J

So, the work done by the 150 N force is 877.5 Joules.

(b) Frictional work is equal to the force of friction multiplied by the distance. The work done by friction is identical in amount but opposite in direction to the work done by the applied force since the crate travels at a constant speed.

The frictional work may be estimated using the following formula:

Work = Force of Friction * Distance * cos(theta)

The net force applied on the crate is zero since it is travelling at a constant pace. As a result, the friction force must be equal to the applied force, which is 150 N.

Thus, the work done by friction is:

Work = 150 N * 5.85 m * cos(180) = -877.5 J

Since the work done by friction is negative, it indicates that the direction of the frictional force is opposite to the direction of motion.

The coefficient of kinetic friction may be calculated using the following equation:

Friction Force = Kinetic Friction Coefficient * Normal Force

The normal force equals the crate's weight, which may be computed as:

Normal Force = mass * gravity

where the mass is 35.0 kg and the acceleration due to gravity is approximately 9.8 m/s^2.

Normal Force = 35.0 kg * 9.8 m/s^2 = 343 N

Now, we can rearrange the equation for the force of friction to solve for the coefficient of kinetic friction:

Force of Friction = coefficient of kinetic friction * Normal Force

150 N = coefficient of kinetic friction * 343 N

coefficient of kinetic friction = 150 N / 343 N ≈ 0.437

As a result, the kinetic friction coefficient between the container and the surface is roughly 0.437.

In summary, the work done by the 150 N force is 877.5 Joules, and the coefficient of kinetic friction between the crate and the surface is approximately 0.437.

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Answer:

The total cost in petrol will be: RM 28.43

Explanation:

The distance to be covered is: 330 km

The car does 60 mi per 1 gallon

so we convert this into km per liter as

60 mi/gal = 60 * 1.61 / 4.5 = 21.47 km/liter

Then, if 1 liter is needed to cover 21.47 km, then to cover 330 km one would need:

330 / 21.47 liters = 15.37 liters

Since each liter costs RM 1.85, then the cost in gas will be:

1.85 * 15.37 = RM 28.43

The steps of the experiment "Sky is Falling" are listed below:

This refers to the systemic activity that is done in order to make a discovery or to test a hypothesis, usually through the use of the scientific method.

Hence, we can see that the steps to perform the "Sky is Falling" experiment is listed above and they are:

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Answer:

A

Explanation:

The sun is an emits energy in the form of light and heat.

The planets absorb this energy which helps keep them in motion. The closer they are to the sun, the more energy, the more speed and less the time it takes a planet to orbit the sun.

The gravitational pull of the Sun contributes motion of the planets because here the gravitational pull of the sun is balanced by the centrifugal force produced by the revolution of planets. The correct option Is A.

Centrifugal force is the pseudo-force that occurs only in the rotating frame of reference (non-inertial frame). it is directed away from the center. Its magnitude is,

F=\(\frac{mv^{2} }{r}\)

where m= mass of the body in kg.

v= velocity f the body in m/s.

r = radius in m.

The star sun has a  gravitational pull that is about 274 m/s²  which is greater than the other planets. Due to this pull the planets tend to pull toward the sun but it does not happen because the pull force is balanced by the centrifugal force that is produced by the revolution of the planets around the sun.

Hence The Sun's gravitational pull contributes to the motion of the planets.

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Answer:

\(option \: c. \: is \: correct\)

Explanation:

\(C. \\ Electrical \: Energy → Potential \: Energy→ Chemical \: Energy\)

♨Rage♨

Answer:

 B that is Potential Energy → Electrical Energy → Heat Energy because, the energy is always stored in the form of potential energy because it is not in static form, so in this case it is going to be in a form of CHEMICAL POTENTIAL ENERGY now when it is connected with the load, the energy stored in the battery will move in the form of electrical energy, now you should remember Electrical energy is a type of kinetic energy caused by moving electric charges, so if it says kinetic energy, you should it is talking about electrical energy. So finally the static electrical energy is converted in the form of heat energy. We could take the EXAMPLE of heater.

In the heater chemical potential energy is converted into Heat Energy.

Answer:

≈159.15

Explanation:

So displacment is the fastest, or shortest way to get somewhere

Youd take your circumference (500) and find the diameter from that using the 2 formulas

C=2πr

d=2r

your answer would be ≈159.15

If im incorrect please correct me! Im only just relearning this stuff (im a freshman)

Answer:

Two tuning forks with frequencies of 256 Hz and 512 Hz are struck. Which of the sounds will move faster through the air? Neither, the speed of sound is constant in air.

The angular distance traveled in degree, radian and revolution are : 49°, 0.273 radian and 0.14 revolution respectively

The angular distance traveled around a circular path is the number of radians the path subtends.It can also be defined as the angle made by a body while moving in a circular path.

From the definition, angular distance (theta) = distance moved/radius.

radius = diameter/2

radius= 10.50/2= 5.25inches

angular distance= 258/5.25= 49.14°

in revolution , = 49.14/360=0.14 revolution

in radian ,= 49.14/180= 0.273radian

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Answer:

The magnitude of the normal force: 75.1 N

Explanation:

The free-body diagram showing all forces acting on the box is:

Here is a little explanation of the diagram. What we are doing is we are refinding our coordinate system such that the y axis is along the normal force Fn and the x-axis is along with the tangential force Ft. Remember that in this coordinate system, we have to decompose the gravitation force Fg into normal and tangential components.

Now the Normal force acting on the box is Fn. What is its magnitude? We can easily find it using some trigonometry.

which evaluates to give

Hence, the normal force on the box is 75.1 newtons.

The correct answer is option D. That is, the branch of Physics that study the particles movement at any speed, including very high speeds is Relativity

Kinematic is a branch of Physics that deal with a study of particle's motion without considering the cause of the motion. While dynamics deals with the motion of a particle as well as the causes of the motion.

The branch of Physics that study the particles movement at any speed,

including very high speeds is Relativity.

We have relativity of mass, relativity of time and relativity of length. All deal with the speed of light which is the fastest speed on earth as of now.

Therefore, the correct answer is option D. That is, the branch of Physics that study the particles movement at any speed, including very high speeds is Relativity.

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The tank division's total displacement from the base is approximately 75.9 miles at a bearing of W67.4S.

To calculate the total displacement of the tank division, we need to find the vector sum of the two legs of their journey.

We can see that the tank division travelled 30 miles to the west (W30) and then 70 miles to the north (N70), so their total displacement is the vector sum of these two legs.

To add vectors, we need to break them down into their horizontal and vertical components.

For the first leg, the tank division travelled 30 miles to the west, so its horizontal component is -30 (since it's to the left of the base) and its vertical component is 0 (since it didn't travel up or down).

For the second leg, the tank division travelled 70 miles to the north, so its horizontal component is 0 (since it didn't travel left or right) and its vertical component is 70 (since it travelled directly north).

Now we can add these components to get the total displacement:

Horizontal component = -30 + 0 = -30

Vertical component = 0 + 70 = 70

So the total displacement is a vector with a horizontal component of -30 and a vertical component of 70.

We can use the Pythagorean theorem to find the magnitude of this vector:

|displacement| = √((-30)² + 70²) ≈ 75.9 miles

And we can use trigonometry to find the direction of this vector:

\(\theta = tan^{-1}\dfrac{70} { -30}\)

θ ≈ -67.4°

So the tank division's total displacement from the base is approximately 75.9 miles at a bearing of W67.4S.

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(D)

Explanation:

This kind of bond where the electrons are transferred is called ionic bond. This bond occurs between a metallic and non-metallic elements. The other kind of bond (covalent) involves the sharing of electrons and this happens between non-metallic elements.