A 60 kg acrobat is in the middle of a 10 m long tightrope. The center of the rope dropped 30 cm in relation to the ends that are attached to fixed supports. What is the tension in each half of the rope?

Answer:

|F| = 393750  N

Explanation:

Given that,

Total mass of the train, m = 750000 kg

Initial speed, u = 84 m/s

Final speed, v = 42 m/s

Time, t = 80 s

We need to find the net force acting on the train. The formula for force is given by :

F = ma

\(F=\dfrac{m(v-u)}{t}\\\\F=\dfrac{750000\times (42-84)}{80}\\\\F=-393750\ N\)

So, the magnitude of net force is 393750  N.

Answer: frequency

Explanation:

amplitude is the max height at which the wave reaches
wavelength distance b/w two waves

the speed at which the wave is oscillating

frequency is no. of oscillations of  a wave per unit length

The weight of the rod is 0.05 kg, or 50 grams.

What is the weight?

Assuming that by "uniform meter" you mean a uniform, thin rod of length 1 meter, and that the rod is hanging vertically from a pivot at its 30 cm mark with a mass of 50g attached to its 0 cm mark, then we can calculate the weight of the rod as follows:

First, we need to find the center of mass of the rod. Since the rod is uniform and thin, its center of mass will be at its midpoint, which is located at the 50 cm mark.

Next, we can consider the rod and the 50g mass as a system and apply the principle of moments. The weight of the rod acts at its center of mass, which is 50 cm away from the pivot, and the weight of the 50g mass acts at the 0 cm mark, which is also 50 cm away from the pivot. The system is in equilibrium, so the clockwise moments must balance the counterclockwise moments:

(clockwise moment) = (counterclockwise moment)

(weight of rod) x (distance from pivot to center of mass) = (weight of 50g mass) x (distance from pivot to 0 cm mark)

Solving for the weight of the rod, we get:

(weight of rod) = (weight of 50g mass) x (distance from pivot to 0 cm mark) / (distance from pivot to center of mass)

(weight of rod) = (0.05 kg) x (0.5 m) / (0.5 m)

(weight of rod) = 0.05 kg

Therefore, the weight of the rod is 0.05 kg, or 50 grams.

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If a surface has a work function of 1.5 ev and photons of energy 2.7 ev are shone on the surface,a possible kinetic energy of the electrons emitted from the surface is 1.2 eV.

The kinetic energy of the emitted electrons can be calculated by subtracting the work function from the energy of the incident photons.

Given:

Work function (Φ) = 1.5 eV

Energy of incident photons (E) = 2.7 eV

The possible kinetic energy (K) of the emitted electrons can be calculated as:

K = E - Φ

K = 2.7 eV - 1.5 eV

K = 1.2 eV

Therefore, a possible kinetic energy of the electrons emitted from the surface is 1.2 eV.

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Answer:

50% of the lunar surface is always illuminated by Sun

Answer:

A simple machine is a device that multiply an applied force by the use of the mechanical advantage built into the machine. Therefore, a simple machine changes the direction in which the applied force acts or the magnitude of the applied force, or both in order to do work

A retractable measuring tape is a device used for length measurement such that the direction of the applied force is reversed during retraction, while the magnitude of the output force is constant and dependent on the coil in the measuring

Therefore, the measuring tape does not have a constant mechanical advantage or act as a force multiplier, and therefore;

It is not a simple machine

Explanation:

Answer:

I just put a random number for the work

Explanation:

I hope it is ok.

According to the data given in the question the net force on the box is of 5 N.

All of the forces that are applied to an object are added up to form the net force. As a consequence of the fact that it (force) is a vector and therefore that two forces with identical magnitudes and opposing directions cancel each other out, the resultant force is the total of the forces, or put another way, the net force is just the total of all the forces.

Given data :

Force on box to the left side (F1) = 15 N

Force on box to the right side (F2) = 20 N

Because both forces are in opposite direction

Hence,

Net force = F2 - F1

Net force = 20 - 15

Net force = 5 N.

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The expression to be simplified is, A + BC + ABCD. Using De Morgan's theorem, we can convert complementation bars extending over multiple variables into complementation bars over single variables. The De Morgan's theorem states that the complement of a product is equal to the sum of complements. De Morgan's Theorem:

 1.   (AB) = A + B2.  (A + B) = A B The steps to simplify the given expression using De Morgan's theorem are as follows: A + BC + ABCD = A + (BC + ABCD) = A + (BC). (ABCD) = A + (B + C) (A + B + C + D) = A + AB + AC + BC + BD = A + AC + BC + BD.

Hence, the simplified expression is A + AC + BC + BD. Thus, using DeMorgan's Theorem and other applicable rules of Boolean algebra, the given expression is simplified to A + AC + BC + BD.

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When the friction coefficient between a road and the tyre of a vehicle is 4/3, the maximum incline that the road may have would be 16° so that when brakes are applied, the vehicle stops within 5 m.

The ratio of the frictional force to the normal force is called as the coefficient of friction (COF), which has no dimensions. The ratio that is present between the normal force pressing two surfaces together and the frictional force preventing motion between the two surfaces.

It is mostly represented by using the Greek letter mu (μ) Those materials are said to be as lubricous only if their COF is less than 0.1.

The present Surface roughness and the kind of COF are related to the nature of the materials.

Then we see that,

S=5m,

Friction coefficient (μ)=4/3,

g=10m/\(s^{2}\)

speed u=36km/h=10m/s

v=0 a=\(\frac{v^{2}-u^{2} }{2s}\) = \(\frac{0-10^{2} }{2*5}\) = 10 m/\(s^{2}\)

Then,

R−mgcosθ = 0

⇒ R = mgcosθ

then, ma+mgsinθ−μR = 0

⇒ ma+mgsinθ−μmgcosθ = 0

⇒ a + gsin\(\theta\\\) - μgcosθ = 0

⇒ 10 + 10sinθ - \(\frac{4}{3}\) x 10cosθ = 0

⇒ 30+30sinθ -40cosθ = 0

⇒ 4cosθ - 3sinθ = 3

⇒ 4\(\sqrt{1-sin^{2}\theta }\) = 3+3sinθ

if we square both sides, we have,

sinθ = \(\frac{18+\sqrt{18^{2}-4(25)(-7) } }{2*25}\)

= 14/50 = 0.28

⇒ θ = \(sin^{-1}\) (0.28) = 16°

Hence maximum inclination

θ= 16°

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The force is the rate of change of momentum, we can conclude that the force exerted on the rocket is 3.85 x 10^7 N.

To calculate the force exerted on the rocket, we can use Newton's second law of motion, which states that force (F) is equal to the rate of change of momentum (dp/dt). In this case, the momentum change is caused by the expulsion of the propelling gases.

The momentum change (dp) is given by the equation: dp = m * Δv, where m is the mass of the propelling gases expelled per second and Δv is the change in velocity of the gases.

The force exerted on the rocket is then obtained by dividing the momentum change by the time interval during which the gases are expelled: F = dp/dt.

Substituting the given values of m = 1100 kg/s and Δv = 3.5 x 10^4 m/s:

dp = (1100 kg/s) * (3.5 x 10^4 m/s),

dp = 3.85 x 10^7 kg·m/s.

Since the force is the rate of change of momentum, we can conclude that the force exerted on the rocket is 3.85 x 10^7 N.

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The siren has a lower pitch as it moves away because crests of the sound are farther apart. Details about sound waves can be found below.

Sound wave is thee longitudinal wave of pressure that is transmitted through any plastic material.

A sound wave like every other type of wave posseses wave like features such as wavelength, period etc.

According to this question, as a siren moves away, the pitch gets lower. This can be attributed to the distant crest of the sound wave.

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The example that is NOT an example of Simple Harmonic Motion is:

A ball rolling down a hill.

Simple Harmonic Motion is a type of periodic motion where the restoring force is proportional to the displacement from equilibrium and is directed towards the equilibrium point. The classic example of simple harmonic motion is the motion of a mass attached to a spring that is oscillating back and forth. Other examples of simple harmonic motion include a pendulum swinging back and forth and the vibration of a guitar string.

A ball rolling down a hill does not exhibit simple harmonic motion because it does not have a restoring force that is proportional to the displacement from equilibrium. The motion of the ball is affected by the force of gravity, which is not directed towards the equilibrium point, and the frictional force between the ball and the surface of the hill, which is not proportional to the displacement from equilibrium. Therefore, it is not an example of simple harmonic motion.

The energy separation between adjacent levels for a hydrogen atom in the 5g state placed in a magnetic field of 0.550 T in the z-direction is approximately 5.101 × 10⁻²⁴ J.

The energy separation between adjacent levels for a hydrogen atom in the 5g state placed in a magnetic field of 0.550 T in the z-direction is given by the formula ΔE = μB * B, where ΔE is the energy separation, μB is the Bohr magneton, and B is the magnetic field strength.
The Bohr magneton (μB) is a physical constant that represents the magnetic moment of an electron orbiting a nucleus. For a hydrogen atom in a magnetic field, the energy separation between adjacent levels depends on this constant and the strength of the magnetic field.
In this case, the magnetic field strength (B) is 0.550 T. The Bohr magneton (μB) is approximately 9.274 × 10⁻²⁴ J/T.
To find the energy separation (ΔE), use the formula:
ΔE = μB * B = (9.274 × 10⁻²⁴ J/T) * (0.550 T)

Thus, the energy separation between adjacent levels for a hydrogen atom in the 5g state placed in a magnetic field of 0.550 T in the z-direction is approximately 5.101 × 10⁻²⁴ J.

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The object absorbed approximately 155.469 J of heat during the temperature increase from 23.8∘C to 33.9∘C.

An object with a mass of 5.45g and a specific heat of 2.82 J/g∘C undergoes a temperature increase from 23.8∘C to 33.9∘C. The amount of heat absorbed by the object is calculated using the formula Q = mcΔT, where Q is the heat, m is the mass, c is the specific heat, and ΔT is the change in temperature.

To determine the amount of heat absorbed by the object, we can use the formula Q = mcΔT, where Q represents the heat, m represents the mass, c represents the specific heat, and ΔT represents the change in temperature.

Given that the mass of the object is 5.45g and the specific heat is 2.82 J/g∘C, and the temperature increase is from 23.8∘C to 33.9∘C, we can calculate the heat absorbed.

First, we calculate the change in temperature: ΔT = final temperature - initial temperature = 33.9∘C - 23.8∘C = 10.1∘C.

Next, we substitute the values into the formula: Q = (5.45g)(2.82 J/g∘C)(10.1∘C).

Simplifying the expression, we find that the heat absorbed is approximately equal to 155.469 J.

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Answer:

(3rd Question about the Black Widow Pulsar)

J1311 is a fast spinning neutron star, which means it emits strong beams of radiation from it's poles.

As the beam of the pulsar sweeps across the surface of the companion star, it heats it up and blows its material outward into space, thus decreasing its mass.

The resistance of the resistor increases, the power dissipated by the resistor decreases.

If the resistance of the resistor in a simple circuit increases, the power dissipated by the resistor will decrease.

The power dissipated by a resistor can be calculated using the formula:

P = (I^2) * R

Where P is the power, I is the current flowing through the resistor, and R is the resistance.

When the resistance increases, and assuming the battery voltage remains constant, Ohm's Law tells us that the current flowing through the circuit decreases.

As a result, the square of the current (I^2) decreases.

Since power is directly proportional to the square of the current and the resistance, when the resistance increases and the current decreases, the power dissipated by the resistor decreases.

This is because less current is flowing through the resistor, resulting in less energy being converted into heat.

Therefore, as the resistance of the resistor increases, the power dissipated by the resistor decreases.

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If a ball is given a push so that it has an initial velocity of 2 m/s down a certain inclined plane, then the distance it has rolled after t seconds is s = 2t + t². Then it takes 11 seconds for the velocity to reach 24 m/s. The correct option is D.

To find the time it takes for the velocity of the ball to reach 24 m/s, we need to solve for the time when the velocity function equals 24 m/s.

The velocity function is the derivative of the distance function, so we'll first find the derivative of the distance function s = 2t + t² with respect to time t:

ds/dt = d/dt(2t + t²)

ds/dt = 2 + 2t

Now we can set the velocity function equal to 24 m/s and solve for t:

2 + 2t = 24

Subtracting 2 from both sides:

2t = 22

Dividing both sides by 2:

t = 11

Therefore, it takes 11 seconds for the velocity to reach 24 m/s.

The correct answer is (d) 11 seconds.

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The velocity of the sled at the bottom of the incline is 28 m/s.

To determine the velocity of the sled at the bottom of the incline, we need to use conservation of energy principles. At the top of the incline, the sled has gravitational potential energy due to its height above the ground. As the sled slides down the incline, this potential energy is converted to kinetic energy.

The first step is to calculate the gravitational potential energy of the sled at the top of the incline. We can use the formula E = mgh, where E is the potential energy, m is the mass of the sled, g is the acceleration due to gravity (\(9.8 m/s^2\)), and h is the height of the sled above the ground. The height h can be calculated using trigonometry, as h = 80 sin(30°) = 40 m. Therefore, the potential energy of the sled is E = (20 kg)(\(9.8 m/s^2\))(40 m) = 7840 J.

Next, we need to determine the work done by friction as the sled slides down the incline. The force of friction is given by f = µN, where µ is the coefficient of friction and N is the normal force. The normal force is equal to the component of the weight of the sled that is perpendicular to the incline, which can be calculated as N = mg cos(30°) = (20 kg)(\(9.8 m/s^2\)) cos(30°) = 166.4 N. Therefore, the force of friction is f = (0.2)(166.4 N) = 33.28 N.

The work done by friction is equal to the force of friction multiplied by the distance over which it acts, which is 80 m. Therefore, the work done by friction is W = f d = (33.28 N)(80 m) = 2662.4 J.

The final step is to use conservation of energy to relate the initial potential energy of the sled to its final kinetic energy at the bottom of the incline. According to the principle of conservation of energy, the total energy of the system must remain constant. Therefore, we can write:

Ei = Ef

\($mgh = \frac{1}{2}mv^2 + W$\)

where Ei is the initial energy (potential energy), Ef is the final energy (kinetic energy plus work done by friction), and v is the velocity of the sled at the bottom of the incline.

Substituting in the values we have calculated, we get:

\($(20 \textrm{ kg})(9.8 \textrm{ m/s}^2)(40 \textrm{ m}) = \frac{1}{2}(20 \textrm{ kg})v^2 + (33.28 \textrm{ N})(80 \textrm{ m})$\)

Simplifying and solving for v, we get:

\($v = \sqrt{2gh - 2\mu gd}$\)

\($v = \sqrt{2(9.8 \textrm{ m/s}^2)(40 \textrm{ m}) - 2(0.2)(9.8 \textrm{ m/s}^2)(80 \textrm{ m})}$\)

\($v = \sqrt{784}$\)

v = 28 m/s

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Complete question:

A 20 kg sled rests at the top of an incline 80 m long and 30° inclination. If µ = 0.2, what is the velocity at the bottom of the incline?

Answer:

The mass number of this carbon atom is 12.

Explanation:

Mass number = Number of protons + Number of neutrons  =  6 + 6  = 12

Brainlist pls!

Answer:

6

Explanation:

Answer:

the answer is main sequence star

Answer:

4. A 10-kilogram sled at rest

Explanation:

The object with most inertia is a 10-kilogram sled at rest.

Inertia is the tendency of a body to remain at rest or continue with uniform motion.

Now, this is better highlighted by Newton's first law of motion which states that "an object will remain in a state of rest or of uniform motion unless it is acted upon by an external force".

The statement that express object with most inertia is 4: A 10-kilogram sled at rest.

Therefore, option 4, is correct.

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On average, lightning claims more lives in the united states a year in the U.S.

An electrical discharge which is caused by imbalances between storm clouds and the ground is Lightning. Lightning mostly occurs within the clouds.

Lightning is not only spectacular, but it’s also dangerous. On average nearly 2,000 people's life is claimed worldwide by lightning each year. Even though hundreds may survive strikes but suffer from a difference of lasting symptoms, which include dizziness, numbness, weakness, memory loss,  and other life-altering ailments.

Cardiac arrest and severe burns can also be caused by Strikes, but 9 of every 10 people survive. About a 1 in 5,000 chance of being struck by lightning during a lifetime is noticed by average Americans.

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If you have two points in an electric field, one at point "ua" and one at the origin (or "uo"), the potential energy at point "ua" will be larger than the potential energy at the origin.

The electric potential energy at a point in an electric field is defined as the amount of work required to move a point charge from the origin to that point. The electric potential energy increases as you move away from the origin in the direction of the electric field.

Therefore, if you have two points in an electric field, one at point "ua" and one at the origin (or "uo"), the potential energy at point "ua" will be larger than the potential energy at the origin. This is because it takes more work to move a point charge from the origin to point "ua" than it does to move it from the origin to the origin.

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Answer:

the correct answer is D

Explanation:

Given equation

\(\\ \sf\longmapsto N_2+3H_2\longrightarrow 2NH_3\)

Nitrogen on product side:-

\(\\ \sf\longmapsto 2(1)=2\)

Hydrogen on reactant side:-

\(\\ \sf\longmapsto 3(2)=6\)

According to the question,

The Equation is

\( \sf \: N_2 + 3H_2 \: \longrightarrow2NH_3\)

Let's balance the equation (Excluded)

\(\sf \longmapsto \: N_2 + 3 H_2 = 2 NH_3\)

Hydrogen atoms on product side:

\(\sf \longmapsto2 \times 1\)

\(\sf \longmapsto \: 2\)

Nitrogen atoms on the reactant side:

\(\sf \longmapsto \: 3 \times 2\)

\(\sf \longmapsto \: 6\)

There fore,

Product side

\( \sf \: 2\)

Reactant side

\( \sf6\)

The light travels through water and gets reflected off on the glass surface into the water. There had been a 180° phase change between the incident and the reflected wave. This is called Total internal reflection (TIR).

In total internal reflection, in physics, a ray of light in a medium such as water or glass is completely reflected back into the medium from the surrounding surfaces. This phenomenon occurs when the angle of incidence is greater than a certain critical angle called the critical angle.

TIR only occurs when both of the following two conditions are met

Thus, the phases which include the TIR are the incident and the reflected phase and the incident light hits the surface while the reflected light reflects back.

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Answer:

Resistance is inversely proportional to current because R = V/I

Explanation:

From ohms law,  The relation between resistance and current is, resistance is inversely proportional to current.

Ohm's law describes the relation between applied voltage and current flow in the conductor. It was proposed by Sir Georg Simon Ohm. The current flows in the conductor are directly proportional to the potential difference between two points.

It remains constant at room temperature. V ∝ I.  V represents the applied voltage or potential difference between two points and its unit is volt(V). I represent the current flow in the conductor and its unit is ampere(A).

Generally, Ohm's law is written as V = IR. R represents resistance that opposes the current flow in the circuit. The unit of resistance is the ohm(Ω). Resistance is inversely proportional to the current flow.

The relation of Ohm's law is written as R = V / I.  At constant voltage,                 R ∝ 1 / I. When resistance increases, current flow decreases, and current flow increases with the decrease in resistance.  

Hence, Resistance is inversely proportional to the current from the ohms law relation, R = V / I.

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Answer:

vB' = 0.075[m/s]

Explanation:

We can solve this problem using the principle of linear momentum conservation, which tells us that momentum is preserved before and after the collision.

Now we have to come up with an equation that involves both bodies, before and after the collision. To the left of the equal sign are taken the bodies before the collision and to the right after the collision.

\((m_{A}*v_{A})+(m_{B}*v_{B})=(m_{A}*v_{A'})+(m_{B}*v_{B'})\)

where:

mA = 0.355 [kg]

vA = 0.095 [m/s] before the collision

mB = 0.710 [kg]

vB = 0.045 [m/s] before the collision

vA' = 0.035 [m/s] after the collision

vB' [m/s] after the collison.

The signs in the equation remain positive since before and after the collision, both bodies continue to move in the same direction.

\((0.355*0.095)+(0.710*0.045)=(0.355*0.035)+(0.710*v_{B'})\\v_{B'}=0.075[m/s]\)