a 63 kg hockey player is sitting on a frictionless ice surface. he throws a 2 kg puck at a speed of 17 m/s. what is his recoil speed in m/s? do not include negative sign in your answer.

As the turntable spins faster, the penny that is furthest from the turntable's centre will slide first.

Centripetal force increases as the turntable spins faster, exerting more force on the pennies. The centripetal force is proportional to the angular velocity squared and the angle of deflection from the turntable's centre. In other words, the penny that is farther away from the turntable's centre experiences a stronger centripetal force than the penny that is closer to it.

With the centripetal force, the frictional force between the pennies and the turntable likewise grows. Nevertheless, the coefficient of static friction—a feature of the surface where the pennies and turntable are placed—limits the frictional force. For the penny that is nearer to the turntable's centre than for the coin that is farther away, the coefficient of static friction

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Answer:

Explanation:

magnetic field B = (3 i + 8 x 2 j )x 10⁻³ T

= (3 i + 16 j )x 10⁻³ T

L = - i ( unit length of conductor )

Force F = I ( L x B ) , I is current

= 5 [ - i x ( 3i + 16 j ) 10⁻³]

= 5 ( - 16 k ) x 10⁻³

F = - 80 x 10⁻³ k

Explanation:

55×60=3300

2×60=120

3300+120=3420

speed=distance/time

speed=3420/217

x=15.6ms^-1

Her speed is approximately 1.24 meters/second.

To calculate Michelle's speed, you need to convert the time to a single unit (seconds) and then use the formula:

Speed = Distance / Time

Given that Michelle walked 217 meters in 2 minutes and 55 seconds:

Time in seconds = 2 minutes * 60 seconds/minute + 55 seconds = 120 seconds + 55 seconds = 175 seconds

Now, let's calculate her speed:

Speed = 217 meters / 175 seconds = 1.24 meters/second

Rounded to two decimal places, her speed is approximately 1.24 meters/second.

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Answer:

Explanation:

See attachment.

Decreasing the mass of the objects   No.  Force will change.

Increasing the temperature of the objects Yes,  No change in force (at most a very small change if the heat causes excessive expansion, reducing the distance, although 1/2 will be further apart)

Increasing the distance between the objects No.  Force will change.

Decreasing the distance between the objects  No.  Force will change.

Answer:

We can use Coulomb's law to solve this problem:

F = k * q1 * q2 / r^2

where F is the force between the two charges, k is Coulomb's constant (k = 9 x 10^9 N m^2 / C^2), q1 and q2 are the magnitudes of the charges, and r is the distance between them.

We know the force F, the distance r, and the magnitude of one of the charges q1. We can rearrange the equation to solve for the magnitude of the other charge q2:

q2 = F * r^2 / (k * q1)

Substituting the values we have:

q2 = (250 N) * (0.15 m)^2 / (9 x 10^9 N m^2 / C^2 * 6.5 x 10^-5 C)

Simplifying:

q2 = 8.65 x 10^5 C

Therefore, the magnitude of the other charge is 8.65 x 10^5 C.

Answer:

Voltmeter

Explanation:

The amount of electrical potential is measured by voltmeter.

Electrical potential is the amount of work needed to move a unit electric charge from a reference point to the specific point in an electric field.

The SI unit of electrical potential is Volt.

Answer:

Volts

Explanation:

The electrical potential is measured by volts. I took the quiz.

Answer:

b

Explanation:

because the metalloids are the thing in the middle

A car starts to rest on a bend with a radius of 130 m and a tangential acceleration of 1.3. When the total acceleration of the car is 2.0m/s2, the car will move through an angle of 22.5°.

The turning radius is the distance required by the car to turn or turn around. Because of this, calculations are made from the moment the car makes a turn until it rotates in a semicircle or 180 degrees. Then, the distance from the diameter will be measured and used as the turning radius of the vehicle.

Radial acceleration (a') = √2² - √1.3²

Radial acceleration (a') = √4 - √1.69

Radial acceleration (a') = √2.31

Radial acceleration (a') = 1.5 m/s²

v = \(\sqrt{a' . r}\)

v = \(\sqrt{1.5 x 130}\)

v = \(\sqrt{195}\)

v = 14 m/s

Now,

d = v²/2a'

d = 14²/2(1.5)

d = 154/3

d = 51.3 m

Expression for circle central angular is:

θ = d/r

θ = 51.3/130

θ = 0.394 rad

θ = 22.5°

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Answer:

d. 0.48

Explanation:

By Conservation of Mechanical Energy, the energy of the block is the same throughout the motion. At the amplitude, the block has potential energy \(U=1/2 kA^{2}\) and zero kinetic energy. At the equilibrium position, the block has kinetic energy and zero potential energy. Applying the Conservation of Mechanical Energy to these two points in the motion yields.

\(K\(1/2 kA^{2} + 0 = 0 + 1/2mv^{2} \\kA^{2} = mv^{2} \\k = mv^{2}/A^{2} = 10kg*(4m/s)^{2} = 40kg/s^{2}\) 1/2 mv^{2}\)

The block with a mass of 10 kg connected to a spring oscillates back and forth with an amplitude of 2 m and a speed of 4 m/s when it passes through its equilibrium point. The approximate period of the block is calculated using the equation T = 2π*√(m/k), where m is the mass and k is the spring constant. We can calculate the approximate period using the given information as  

\(T = 2π*√(10/k)\\T = 2π*√(10kg/40kg/s^{2} )\\T = 3 sec\),

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The intensity of sound is inversely proportional to the square of the distance from the source. The intensity of sound at 4 m away from the source is approximately \(0.993W/m^{2}\) (watts per square meter).

The intensity of sound is defined as the power per unit area. According to the inverse square law for sound propagation, the intensity of sound is inversely proportional to the square of the distance from the source. Mathematically, it can be expressed as

\(I=P/(4\pi r^{2})\)

where I is the intensity, P is the power, and r is the distance from the source.

Given that the power of sound at the source outlet is 100 W and the distance from the source is 4 m, we can substitute these values into the formula. Thus, we have

\(I = 100 W / (4\pi (4 m)^2)\)

Simplifying this expression, we find that the intensity of sound at 4 m away from the source is approximately \(0.993W/m^{2}\) (watts per square meter).

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The Jovian planets are formed from materials different from the terrestrial planets for the reason that gaseous Jovian planets, formed farther away from the heat of the Sun, are formed from light weight nebulae "dust."

A Jovian planet, also known as a gas giant, is a huge planet that has a primarily gaseous composition. The Jovian planets include Jupiter, Saturn, Uranus, and Neptune. They are primarily made up of hydrogen and helium, and they have enormous atmospheres.Jovian planets are formed farther away from the heat of the Sun, so they are formed from lighter-weight nebulae "dust." Terrestrial planets, on the other hand, are formed nearer to the Sun, so they are formed from heavier-weight nebulae "dust." The density of the materials that make up the Jovian planets is lower than that of the terrestrial planets due to this. This means that the Jovian planets have lower densities and a greater volume than the terrestrial planets.

Hence, the correct option is d. Gaseous Jovian planets, formed farther away from the heat of the Sun, are formed from light weight nebulae "dust."

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Answer:

for your computer, refridgerator, stove, car, lights, oven, microwave, electronic chargers, wi-fi router, and fans

Explanation:

also solar energy will save the earth from being inhabitable

hope this helped!!

Answer:

When viewed from above, the current in the coil should point towards the top-right corner of the picture.

Explanation:

The current in this coil have only two possible directions: clockwise or counter-clockwise. However, since the diagram shows the coil from above, not from a cross-section, just saying clockwise or counter-clockwise might be ambiguous. The statement that the current is directed towards the top-right corner of the picture is equivalent to saying that when viewed from the lower-right corner of this diagram, the current in the coil is moving clockwise.

Note that at the center of this picture, the current is parallel to the magnetic field- there will be no force on the coil at that position. On the other hand, (also when viewed from above,) at the top-right corner and the lower-left corner of the coil, the current in the coil will be perpendicular to the magnetic field. That's where the force on the coil will be the strongest.

With that in mind, apply the right-hand rule to find the direction of the force on the coil in each of the two possibilities.

Assume that when viewed from above, the current is flowing towards the top-right corner of the picture. Consider the wire near the top-right corner of this coil (as viewed above on this picture.) The current will be going into the picture into the magnetic field. By the right-hand rule, the current on the wire near that point should be pointing towards the bottom of this picture. (Point fingers on the right hand in the direction of the current \(I\). Rotate the right hand such that when curling the fingers, they point in the direction of the magnetic field \(B\). The direction of the right thumb should now point in the direction of the force on the wire \(F\).)

Based on the same assumption, the current in the wires near the bottom left corner of this coil will be pointing out of the picture. By the right hand rule, the magnetic force on the coil in that region should be pointing towards the top of this picture. Combing these two forces, the coil would indeed be rotating around the center of this picture in the direction shown in the diagram.

It can also be shown that if the current points towards the bottom left corner of the picture when viewed from above, the coil will be rotating about the center of this picture in the opposite direction.

Answer:

B

Explanation:

B, because if u subtract the forces from each other the forward one outweights the other ones

Answer:

C. The car is moving at a constant speed.

The speed at which the ball must be thrown vertically from ground level to rise to a maximum height of 32m is 28 m/s (meters per second).

The speed of the ball at which it should be thrown can be found using the formula;v² = u² + 2gh, Where v = final velocity, u = initial velocity, g = acceleration due to gravity = 9.8 m/s² and h = maximum height attained by the ball. From the problem, the ball rises to a maximum height of 32m. Therefore, h = 32m. Also, the ball is thrown vertically from the ground level, hence the initial velocity is zero (u = 0).v² = u² + 2gh. Substituting the values of u, g, and h in the formula above;v² = 0 + 2 × 9.8 × 32v² = 627.2v = √627.2v = 28 m/sTherefore, the speed at which the ball must be thrown vertically from ground level to rise to a maximum height of 32m is 28 m/s.

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When it is given that that star has 4 times the sun's mass then main sequence lifetime is calculated as: 312.5 * 10 ^6 million years.

A continuous and distinctive band of stars that appear on plots of stellar color versus brightness known as the main sequence. The color-magnitude plots are known as Hertzsprung–Russell diagrams.

The outer layers of star expand while the core is shrinking. As the expansion continues, the luminosity also increase.

Given mass of star is 4 times the sun, then

Main sequence lifetime is calculated as:

= 10^10 / 4^2.5

= 312500000

= 312.5 * 10 ^6 million years.

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The ball will travel more distance when projected or kicked at an angle of 35 degrees.

The range of the projectile or the horizontal distance traveled by the ball is calculated by applying the following kinematic equation as shown below.

R = ( u² sin (2θ ) ) / g

where;

The horizontal distance traveled by the ball when projected at 35 degrees is calculated as;

R = ( 13.9² x sin ( 2 x 35 ) ) / ( 9.8 )

R = 18.53 m

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The work was done by the force on the block of 2 kg with an acceleration gravity of  9.81 \(m/s^2\) and at an angle of \(29^o\) 42.83 J.

When an object is moved over a distance by an external force, at least some of that force must be applied in the direction of the displacement. This is known as work in physics. Work may be estimated if the force acting along the path is constant by multiplying the length of the path by the component of the force acting along the path.

To express this formally, the work W is equal to the force f times the length d, or W = fd. The work is W = fd cos if the force is applied at an angle to the displacement.

Given:

The mass, m = 2 kg,

The acceleration, g = 9.81 \(m/s^2\),

θ = angle between block and surface kinetic friction = μ

Calculate the work done by the formula given below,

\(W_{fy}\) = F sinθ

\(W_{fy}\) =  (\(mgsin\)θ)/ (sinθ -  μ * cosθ)

Substitute the values

\(W_{fy}\)  = \((2*9.81 sin29^{o} )/sin29^o - 0.30cos29^o\)

\(W_{fy}\)  = 42.83 J

Therefore, the work done by the force on the block of 2 kg with an acceleration gravity of  9.81 \(m/s^2\), and at an angle of \(29^o\) is 42.83 J.

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Answer: 2              1                  3  

is your answer

Explanation:

your'e welcome

Answer:

First one = 2

Second one = 1

Third one = 3

Explanation:

2       1      3

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The direction of the induced current is counterclockwise.

This states that induced electric current flows in a direction such that the current opposes the change that induced it.

The direction of the induced current is counterclockwise as a result of the north pole being oriented downwards which is the opposite direction of the hands of a clock movement.

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The normal force acting on a 77.3-kg man is traveling upward in an elevator at a constant velocity of 9.9 m/s is 757.54 N

∑ Fy = m a

Fn - Fg = m a

Fg = m g

Fg = Force of gravity

m = Mass

g = Acceleration due to gravity  

Fn = Normal force

m = 77.3 kg

g = 9.8 m / s²

Fg = 77.3 * 9.8

Fg = 757.54 N

Since velocity is constant, a = 0

Fn - Fg = 0

Fn = Fg

Fn = 757.54 N

Therefore, the normal force acting on him is 757.54 N

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Circuit diagram number II

I) R=(4*8)/(4+8)=8/3 Ω

II) R=4+((4*4)/(4+4))= 6 Ω

III) R= 4/3 Ω

IV) the same as I: 8/3 Ω

The equations mentioned by Emily in the valuation analysis for Aspeon are as follows:

1) Equation (1): This equation represents the value of equity (S) and calculates it based on the EBIT (earnings before interest and taxes), the tax shield provided by debt (D), and the required return on debt (kd) and equity (ks). It implies that the value of equity is equal to the adjusted EBIT after deducting the tax shield from debt.

2) Equation (2): This equation calculates the total enterprise value (V) by adding the value of equity (S) and debt (D). It represents the total worth of the company, considering both equity and debt.

3) Equation (3): This equation calculates the price per share (P) by dividing the total enterprise value (V) minus the initial debt (D0) by the number of shares (n0). It represents the price per share based on the valuation of the company.

4) Equation (4): This equation calculates the new number of shares (n1) by subtracting the dividend (D) from the initial number of shares (n0) divided by the price per share (P). It represents the adjusted number of shares after the payment of dividends.

5) Equation (5): This equation calculates the levered value (VL) by adding the unlevered value (VU) with the tax shield value (TD). It represents the value of the company after considering the tax advantages of debt.

These equations provide a framework for valuation analysis, considering factors such as earnings, taxes, debt, and equity. They help assess the value and financial implications of Aspeon's growth prospects.

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The major ionic species present in an aqueous solution of FeCl3 is Fe³⁺.

Conventionally, the charge of an electron is thought to be negative; this charge is equal to and opposite to the charge of a proton, which is thought to be positive. Because the total number of electrons in an ion is more than the total number of protons, the net charge of an ion is not zero.

A negatively charged ion called an anion has more electrons than protons compared to a positively charged ion called a cation. Electrostatic force causes opposite electric charges to be drawn towards one another, causing cations and anions to attract one another and easily form ionic compounds.

Hence, The major ionic species present in an aqueous solution of FeCl3 is Fe³⁺.

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Answer:

168

Explanation:

56 x 3

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The efficiency of this light bulb is 25% .

Given data :

output = 30j

Input = 120j

Efficiency  = output / input x 100

  = 30 / 120 x 100

  = 25%

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Answer:

The answer is 360

Explanation:

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