a 66-kg k g skier starts from rest at the top of a 1200-m m -long trail which drops a total of 290 m m from top to bottom. at the bottom, the skier is moving 11 m/s m / s .

Answers

Answer 1

A 66 kg skier starts from rest at the top of a 1200 m long trail which drops a total of 290 m from top to bottom. At the bottom, the skier is moving 11 m/s.

The initial velocity of the skier is zero. The final velocity of the skier is 11 m/s.The distance covered by the skier is 1200 m. The height from the top to the bottom of the trail is 290 m.The gravitational potential energy is given bymghWhere,m = mass of the skier = 66 kgg = acceleration due to gravity = 9.8 m/s2h = height through which the skier falls = 290 mInitial gravitational potential energy = mgh = 66 × 9.8 × 290 = 191976 J.

The kinetic energy of the skier is given by(1/2)mv²Where,v = final velocity of the skier = 11 m/s Kinetic energy of the skier = (1/2)mv² = 0.5 × 66 × 11² = 3993 JAt the bottom, all of the gravitational potential energy is converted into kinetic energy. Therefore,191976 = 3993 + (1/2) × 66 × v²191976 - 3993 = 33v²191976 - 3993 = 33v²151983 = 33v²v² = 151983/33v = 74.51 m/s. Therefore, the speed of the skier at the end of the trail is 74.51 m/s.

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Related Questions

Cold air is more dense than hot air. When I filled a 9 centimeter diameter balloon with cold air the mass was 1 gram and when I measured the mass of the same size balloon with hot air it was 0.5 grams. When molecules are cooled they move closer together and when they are heated up they move farther apart. Because of this more molecules can fit into a balloon when the air going in is cold than when the air going in is warm. (Please explain this to me)

Answers

sorry this might not be great but when the air is cold the molecules are dense which means they are much closer together and hit each other but when they air is hot the molecules aren’t as dense which means they are more spread out. so as the cold air molecules are closer together, more of them could fit inside the balloon but with hot air since the molecules are so far apart not as many can fit in as they take up more as they spread and hit the side of the balloon

What is the mass amount of a Proton and a Neutron?

Answers

The masses amount of a proton and neutron are 1.0087 and 1.0073 amu respectively.

What is a Proton?

This is defined as  sub atomic particle which is positively charged and is present in the nucleus while the neutron is also a particle present in the nucleus but has a neutral charge.

Electrons on the other hand are found outside the nucleus and are negatively charged. It is the sub atomic particle which is actively involved in a chemical reaction.

The masses of neutron and proton are 1.0087 and 1.0073 amu respectively and was discovered by scientists thereby making it the most appropriate choice.

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i need the answer to this question

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Answer:

You need to provide the question and (if it has them) answer options for the question. Once you have done that, delete my response so I may be able to answer your question faster than normal.

Explanation:

Will Mark Brainliest PLZ!!!!!!!!!! If an apple has 18 Joules of potential energy when it is dropped, how much kinetic energy will it have when it has fallen to one third its original height?

Answers

Answer: 6 Joules

Explanation:

You are given that the potential energy P.E of the apple = 18 Joules

PE = mgh

Where g = 9.8 m/s^2

18 = mgh

Initially, The mechanical energy of the apple = 18 Joule.

According to conservative of energy

the total energy of the apple will be 18 Joules. That is,

K.E + P.E = 18 Joules

when the apple has fallen to one third its original height, the remaining height from the ground upward will be:

height h = 1 - 1/3 = 2/3

The new Potential energy will be

P.E = 2/3 × 18

P.E = 12 Joules

The potential energy lost must have been converted to the kinetic energy according to conservative of energy

K.E + 12 = 18

Make K.E the subject of formula

K.E = 18 - 12 = 6 Joules

Therefore, the apple will have 6 Joules of kinetic energy when it has fallen to one third its original height.

A substance that heats up relatively quickly has a low specific heat capacity. Select one: O True O False

Answers

As the given statement is False. As a substance that heats up relatively quickly must has a high specific heat capacity.

What is specific heat capacity?

A physical property of matter is specific heat capacity. The quantity of heat energy required to raise a substance's temperature per unit of mass is known as the specific heat capacity. It serves as an illustration of a large property. Since the scale of the system under study directly affects it. Therefore, it is the amount of heat absorbed by the substance per unit mass when its temperature is elevated. Specific Heat Capacity is measured in J/(kg K) or J/(kg °C) units.

As heating is quick when the substance have high specific heat capacity and the heating will be slow when the substance have less specific heat capacity.

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GUYS COULD SOMEONE PLEASE HELP ME?
PLEASE ASAP

Write a summary of how the eye works:

Answers

Answer:

Eye function renders you the sense of sight. They convert light into electrical signals. Afterwards, the brain deciphers these electrical signals into images. Properly working healthy eyes are able to perform the following functions.

Explanation:

As you drive, a passenger in your car records your speed at 10-second intervals. The passenger records the following data: {(0 s, 18 m/s), (10.0 s, 18 m/s), (20.0 s, 18 m/s),
(30.0 s, 18 m/s), (40.0 s, 18 m/s)}. Using a graph of the velocity as a function of time, determine your displacement between t = 10.0 s and t = 35.0 s.

Answers

The velocity as a function of time is 0, and displacement between t = 10.0 s and t = 35.0 s is 0.

How to find velocity and displacement?

The vector quantity velocity (v), denoted by the equation v = s/t, quantifies displacement (or change in position, s), over change in time (t).

as S= 0, then

\(V_{total}\) = \(\frac{ Final Speed - initial speed}{total_time }\)

V=0.

Displacement is defined as the final position minus the starting position.

Displacement = Final distance- initial distance

S= 0

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A soccer player kicks a ball horizontally at 25.0 m/s from a bridge, and the ball hits
the ground after 1.5 s.
2
How high is the bridge?

Answers

Answer: 11.025 meters.

Explanation:

Ok, we know that the initial velocity is only horizontal, so it does not affect the vertical problem.

Looking only at the vertical problem (because we want to know how high is the bridge) we have that:

The acceleration is the gravitational acceleration, g = 9.8m/s^2

A(t) = -9.8m/s^2

Where the negative sign is because this acceleration is downwards.

For the vertical velocity we integrate over time, as we do not have an initial vertical velocity, there is no constant of integration.

V(t) = (-9.8m/s^2)*t

For the position we integrate over time again, here the constant of integration is the initial vertical position, H, that is the height of the bridge.

P(t) = 0.5* (-9.8m/s^2)*t^2 + H.

Now we know that the ball hits the ground 1.5s after it was kicked, then:

p(1.5s) = 0m

With that we can find the value of H.

0 = 0.5* (-9.8m/s^2)*(1.5s)^2 + H.

H = 0.5*(9.8m/s^2)*(1.5s)^2 = 11.025m

a boy is enjoying a ride on giant wheel which is moving with a constant speed of 10 metre per second it implies a he is

Answers

Answer:

in accelerated motion

Explanation: tbh I just guessed if im wrong sorry

The activation energy of a certain reaction is 47.1kJ/mol . At 20C , the rate constant is 0.0170s^{-1} . At what temperature in degrees Celsius would this reaction go twice as fast? Given that the initial rate constant is 0.0170s^-1> at an initial temperature of 20C , what would the rate constant be at a temperature of 140 C for the same reaction described in Part A?

Answers

The activation energy of a certain reaction is used to find the temperature at which the reaction would go twice as fast.  while the Arrhenius equation can be used to find the rate constant at a different temperature for the same reaction.

We can use the Arrhenius equation, which relates the rate constant of a reaction to the activation energy and temperature. We know the rate constant at 20C and the activation energy, so we can set up the equation as follows:

k2 = 2k1
ln(k2/k1) = Ea/R * (1/T1 - 1/T2)
T2 = Ea/R * (1/T1 - ln(k2/k1)/Ea)

Plugging in the given values, we get:

T2 = 47.1 kJ/mol / (8.314 J/mol*K) * (1/293 K - ln(2)/(47.1 kJ/mol))
T2 ≈ 358 K or 85 C

For the second part of your question, we can use the same equation to find the rate constant at 140 C:

ln(k2/k1) = Ea/R * (1/T1 - 1/T2)
k2 = k1 * e^(Ea/R * (1/T1 - 1/T2))

Plugging in the given values, we get:

k2 = 0.0170 s^-1 * e^(47.1 kJ/mol / (8.314 J/mol*K) * (1/293 K - 1/413 K))
k2 ≈ 1.81 s^-1.

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a person lifted the barbell from the ground. the mass of the barbell was 100 kg. it took him 0.5 seconds to move the barbell through a vertical displacement of 1.5 m. what was the average power output during the lift (g

Answers

The average power output during the lift is 2940w.

Given,

a person lifted the barbell from the ground.

The mass of the barbell = 100kg

time taken = 0.5s

displacement = s = 1.5m

we know,

w = mgs

= 100 × 0.5 × 1.5 = 1470j

As we know ,power = work done / unit time

P = 1470j/0.5s = 2940w

Hence,the average power output during the lift is 2940w.

what is power?

Power is always a function of labour output, therefore if a person works at a variable rate depending on the time of day, his power will likewise vary. The idea of average-power enters the picture at this point. Let's study about power, average power, unit, and formula in this session.

Average power is calculated by dividing the total energy used by the total time required. The average quantity of work completed or energy converted per unit of time is known as average power.

The rate at which work is performed on an object is referred to as its power. Power is a temporal concept. It has to do with how quickly a task gets completed.

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use atoms and molecules in a sentence

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Answer:

An atom is the smallest part of an element by itself, while molecules are built of multiple atoms.

What is the magnitude of the gravitational force between an electron and a proton separated by a distance of 1.0 x 10-10 meter?

Answers

A proton and electron separated by 1.0 x 10-10 meters exert 1.0 x 10-47N of gravitational force on each other.

What exactly is gravitational, in simple terms?

The gravitational force will bring together any two mass-containing objects. The gravitational force is described as attracting because it consistently tries to draw masses together and never tries to push them apart. In reality, you and every other item in the universe are pulling toward one another.

What is the origin of gravity?

All of the mass on Earth is what creates gravity. The cumulative gravitational attraction of all of its mass exerts pressure on all of the body's mass. Your weight is determined by that. Furthermore, your weight would be lower if you were on a planet with a lower mass than Earth.

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How hard is ap physics 1

Answers

Answer:

It depends if your smart

Explanation:

Also, I plead the 5th

Cual es el cambio de energía cinética de un cuerpo de 800kg que disminuye su velocidad de 90 km/h a 50 km/h

Answers

I don’t really like physics that much

Newton's 3rd Law of Motion
For every__________ (or force), there is an ____________ and __________ action (or force).

Answers

Answer:

Explanation:

For every action (or force), there is an equal and opposite action (or force).

Explain why a person travelling in a bus falls forward when bus stops suddenly

Answers

Answer:

Cause of Inertia of Motion

Explanation:

It can be explained as follows...when the moving bus suddenly stops, the lower part of the body of the passenger contact with the bus suddenly comes to rest while the upper part of the body tends to retain its state of motion due to inertia. As a result, the passenger is thrown forward.

a car is moving at a constant tangential speed of 50.0 m/s and takes one lap around a circular track in a time of 74.4 s. what is the magnitude of the acceleration of the car?

Answers

Answer: 0.0541

Explanation:

If the car took a time of 74.4 seconds to complete one lap around a circular track, the circumference of the track is 50.0 m/s * 74.4 s = <<50.0*74.4=3720>>3720 m.

The radius of the circular track is half the circumference, so it is 3720/2 = <<3720/2=1860>>1860 m.

The acceleration of a body moving in a circle with constant speed is given by the formula a = v^2/r, where a is the acceleration, v is the speed, and r is the radius of the circle.

Therefore, the magnitude of the acceleration of the car is 50.0^2/1860 = <<50.0^2/1860=0.0541>>0.0541 m/s^2

A building contractor buys 70​% of his cement from supplier A and 30​% from supplier B. A total of 95​% of the bags from A arrive​ undamaged, and a total of 90​% of the bags from B arrive undamaged. Find the probability that a damaged bag is from supplier Upper A.

Answers

The probability that a damaged bag is from supplier A is approximately 0.54.

What is probability?

Probability is a measure of the likelihood or chance of an event occurring. It is a numerical value between 0 and 1, where 0 represents an impossible event and 1 represents a certain event. The probability of an event is calculated by dividing the number of favorable outcomes by the total number of possible outcomes.

Let's define some events:

A: buying cement from supplier AB: buying cement from supplier BD: a bag of cement is damaged

We want to find the probability that a damaged bag is from supplier A, given that a bag is damaged:

\(P(A|D)= \dfrac{P(D|A).P(A)}{P(D)}\)

To calculate the values for this formula, we need to use the given probabilities:

$P(A) = 0.7$$P(B) = 0.3$$P(D | A) = 0.05$ (since 95% of the bags from A arrive undamaged, the probability that a bag from A is damaged is 1-0.95=0.05)$P(D | B) = 0.1$ (since 90% of the bags from B arrive undamaged, the probability that a bag from B is damaged is 1-0.9=0.1)

To find $P(D), we can use the law of total probability:

P(D)=P(D∣A)⋅P(A)+P(D∣B)⋅P(B)

Plugging in the values:

P(D) = 0.05⋅0.7+0.1⋅0.3

P(D) = 0.065

Now we can calculate the conditional probability:

\(P(A|D )= \dfrac{P(D|A).P(A)}{P(D)}\)

\(P(A|D) = \dfrac{0.05\times 0.7} { 0.065}\)

P(A|D) ≈ 0.54

Therefore, the probability that a damaged bag is from supplier A is approximately 0.54.

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in which graph is the velocity 0

Answers

there isn’t a picture
Velocity=0 find a point where the slope of the graph is equal to zero. We can see that slope of the graph is zero at point D (tangent drawn at d will be parallel to x-Asus hence slope 0)

why does making the slit smaller make the spot larger

Answers

When the slit is made smaller, the spot becomes larger because of the phenomenon known as diffraction.

Diffraction is the bending of light waves around small obstacles and the spreading out of light waves past small openings. When the slit is made smaller, the amount of diffraction increases, causing the spot to become larger. This is because the smaller the slit, the more the light waves spread out as they pass through it, creating a larger spot on the other side. This is an example of the wave nature of light and is described by the Huygens-Fresnel principle.

In mathematical terms, the size of the spot is inversely proportional to the size of the slit. This means that as the slit size decreases, the spot size increases, and vice versa.

In conclusion, making the slit smaller causes the spot to become larger due to the phenomenon of diffraction, which causes light waves to spread out more as they pass through the smaller slit.

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Question:Which of the following statements is true?a. State functions do not depend on the path taken to arrive at a particular state.b. Energy is neither created nor destroyed, excluding nuclear reactions.c. ΔHrxn can be determined using constant pressure calorimetry.d. ΔErxn can be determined using constant volume calorimetry.e. All of the above are true.State or Path Functions:The state functions are the variable such as density, pressure, etc. that are calculated by subtracting initial values from final values. Path function necessarily relies on the path followed. In thermodynamics, only two heat and work are depicted as path functions.

Answers

Statement (e), "All of the above are true," is true.

State functions do not depend on the path taken to arrive at a particular state. Energy is a state function and it is conserved, meaning it is neither created nor destroyed, excluding nuclear reactions. ΔHrxn, the change in enthalpy, can be determined using constant pressure calorimetry, which measures the heat flow into or out of a system at constant pressure. ΔErxn, the change in internal energy, can be determined using constant volume calorimetry, which measures the heat flow into or out of a system at constant volume. In thermodynamics, state functions, such as enthalpy, internal energy, and entropy, are defined by their values at a particular state and are not dependent on the path taken to arrive at that state. On the other hand, heat and work are considered path functions because they depend on the path taken to arrive at a particular state.

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Match the following waves on the EM Spectrum with the correct letter;
Visible Light, Radio Waves, and X Rays

Match the following waves on the EM Spectrum with the correct letter;Visible Light, Radio Waves, and

Answers

Answer:

(D) is visible light

Explanation:

(F) is xray and (B) is radio

at constant temperature and pressure, how is âsuniv related to âgsys?

Answers

At constant temperature and pressure, ΔSuniv and ΔGsys are related through the Gibbs free energy equation, with positive ΔSuniv indicating a spontaneous process and negative ΔSuniv indicating a non-spontaneous process.

The relationship between âsuniv and âgsys at constant temperature and pressure can be explained through the second law of thermodynamics. âsuniv represents the total change in entropy of a system and its surroundings, while âgsys represents the change in entropy of the system alone. Therefore, the relationship between âsuniv and âgsys can be expressed as âsuniv = âgsys + âssurr, where âssurr represents the change in entropy of the surroundings.

The change in the total entropy of the universe (âsuniv) is equal to the change in entropy of the system (âgsys) plus the change in entropy of the surroundings (âssurr). This relationship highlights the importance of considering not only the system being studied, but also its interaction with the surrounding environment.  At constant temperature and pressure, the relationship between âsuniv and âgsys can be described as âsuniv = âgsys + âssurr, emphasizing the significance of the second law of thermodynamics in understanding the behavior of thermodynamic systems. This relationship can be further explored and applied in various fields such as chemistry, physics, and engineering.

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5 different energy stores
i got
chemical, kinetic, internal, nuclear
what am i missing?

Answers

Answer: There are seven main stores of energy: magnetic

internal (thermal)

chemical

kinetic

electrostatic

elastic potential

gravitational potential

Explanation: So you can have any of these

which of these might be carried by the wind, which causes the weathering of rocks?

A. fog

B. mud

C. pollen

D. sand




BTW SCIENCE ISN'T IN SUBJECTS JUST SAYING​

Answers

A .

Explanation:

Tiny water drops hovering in the air are called fog. Fog is like a cloud, but it is near the ground, not high in the sky. Thick fog makes it difficult to see the surrounding landscape

we have that from the Question"which of these might be carried by the wind, which causes the weathering of rocks? " it can be said that  

Which of these might be carried by the wind, which causes the weathering of rocks will bepollen Option C

From the Question we are told

which of these might be carried by the wind, which causes the weathering of rocks?

A. fog

B. mud

C. pollen

D. sand

Generally

wind carry light and thing above the earth or at a higher altitudewhen pollen's are carried over a distance and germinate the root them self into rocks and as the grow bigger the crack rocks  thereby causing the weathering of rock

Therefore

Which of these might be carried by the wind, which causes the weathering of rocks will be

pollen

Option C

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Show your work on the following problems.
1.
An airplane accelerates down a run-way at 3.20 m/s? for 32.8 s until is finally lifts off the ground
Determine the distance traveled before take-off.
2.A race car accelerates uniformly from 18.5 m/s to 46.1 m/s in 2.47 seconds. De
acceleration of the car and the distance traveled.
3.
A race car accelerates uniformly from 18.5 m/s to 46.1 m/s in 2.47 seconds. Determine the
acceleration of the car and the distance traveled.
4.
A bullet leaves a rifle with a muzzle velocity of 521 m/s. While accelerating through the barrel of
the rifle, the bullet moves a distance of 0.840 m. Determine the acceleration of the bullet (assume a
uniform acceleration).

Show your work on the following problems.1.An airplane accelerates down a run-way at 3.20 m/s? for 32.8

Answers

The distance travelled by the airplane before takeoff is 1721 m.

2. The acceleration of the race car is 11.2 m/s², and Distance travelled by the car is 79.9 m.

3. The acceleration of the bullet is 1.62 * 10⁵ m/s².

What is the distance travelled by the airplane before takeoff?

The distance travelled by the airplane before takeoff is determined using the formula:

s = ut + ¹/₂at²

u = 0; a = 3.20 m/s², t = 32.8 s

s = 0 * 32.0 +  ¹/₂ * 3.2 * 32.8²

s = 1721 m

2. The acceleration of the race car is calculated as follows:

a = (v - u)/t

v = 46.1 m/s, u = 18.5 m/s, t = 2.47 s

a = (46.1 - 18.5)/2.47

a = 11.2 m/s²

Distance travelled, s = 18.5 * 2.47 + ¹/₂ * 11.2 * 2.47²

s = 79.9 m

3. The acceleration of the bullet is calculated as follows:

a = (v² - u²)/2s

where v = 0 m/s, u = 521 m/s, s = 0.840 m

a = (0² - 521²)/2 * 0.840

a = 161572.0238

a = 1.62 * 10⁵ m/s²

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A mass of. 0kg is hung off spring which extends 2cm determine the energy stored in the spring

Answers

The energy stored in the spring with a mass of 0 kg hung off it which extends 2 cm is 0.001 J.

To determine the energy stored in the spring, the equation E = 0.5kx² can be used, where E is the energy stored, k is the spring constant and x is the displacement from the equilibrium position.

As the mass hung off the spring is 0 kg, the spring constant can be calculated using the formula k = F/x, where F is the force applied and x is the displacement from the equilibrium position. As the mass is not moving, the force applied is equal to the weight of the mass, which is 0 N. Therefore, k = 0 N/cm.

Now, x is given as 2 cm. Substituting the values in the formula E = 0.5kx², we get E = 0.5(0 N/cm)(0.02 m)² = 0 J. This shows that there is no energy stored in the spring when the mass hung is 0 kg.

However, the extension in the spring indicates that some energy has been stored. This is due to the elastic potential energy in the spring which causes it to extend when a force is applied to it.

As the spring returns to its equilibrium position, this energy is released. Therefore, the energy stored in the spring when a mass of 0 kg hung off it which extends 2 cm can be said to be approximately 0.001 J.

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Pilings are driven into the ground at a building site by dropping a 2250 kg object onto them. What change in gravitational potential energy does the object undergo if it is released from rest 16.0 m above the ground and ends up 1.30 m above the ground ? Change in gravitational potential energy:

Answers

Answer: 324.135 kJ

Explanation:

Given

Mass of dropping is \(m=2250\ kg\)

The initial height of dropping is \(h_1=16\ m\)

The final height of dropping \(h_2=1.3\ m\)

Gravitational potential energy is the function of height i.e.

\(\Rightarrow \text{G.E.}=mgh\)

Change in Gravitational Energy is

\(\Rightarrow \Delta \text{G.E.}=mg(h_1-h_2)=2250\times 9.8\times (16-1.3)\\\\\Rightarrow \Delta \text{G.E.}=3,24,135\ J\approx 324.135\ kJ\)

when we speak of the large-scale structure of the universe, we mean

Answers

According to the given statement the correct answer is when we speak of the large-scale structure of the universe, we are referring to the distribution and arrangement of matter and energy on the largest scales, such as galaxy clusters and superclusters.

This includes the overall cosmic web of filaments and voids, as well as the patterns of cosmic microwave background radiation that provide insights into the early universe. Understanding the large-scale structure is crucial for investigating the origins and evolution of the universe.When we refer to the large-scale structure of the universe, we are talking about the distribution of matter and galaxies on a very large scale. This includes the arrangement of clusters and superclusters of galaxies, as well as the vast cosmic voids that separate them. The large-scale structure of the universe is studied in the field of cosmology, and understanding its properties can provide insight into the origin, evolution, and future of the universe. Some of the tools used to study the large-scale structure of the universe include telescopes, surveys of galaxy positions, and computer simulations.

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