The power output of the lightbulb increases by 12.5% during the voltage surge.
To calculate the percentage increase in power output, we need to compare the power at the normal voltage (120 V) with the power at the surge voltage (135 V).
The power consumed by a device can be calculated using the formula:
Power = Voltage x Current
Since we know the power rating of the lightbulb is 75 W, we can calculate the current at each voltage level.
At 120 V:
Power = Voltage x Current
75 W = 120 V x Current
Current = 75 W / 120 V
At 135 V:
Power = Voltage x Current
Power = 135 V x Current
To find the percentage increase, we need to calculate the difference in power output and express it as a percentage of the original power output.
Percentage Increase = ((New Power - Original Power) / Original Power) x 100
Let's calculate it:
Original Power = 75 W
New Power = 135 V x (75 W / 120 V)
Percentage Increase = ((135 V x (75 W / 120 V) - 75 W) / 75 W) x 100
Simplifying the equation:
Percentage Increase = ((135/120) - 1) x 100
Percentage Increase = (1.125 - 1) x 100
Percentage Increase = 0.125 x 100
Percentage Increase = 12.5%
Therefore, the power output of the lightbulb increases by 12.5% during the voltage surge.
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Power output from a lightbulb under a voltage surge can be calculated using the formula for electric power P = V²/R, giving us an increase of approximately 25.78% in this case.
Explanation:The percentage increase in power output due to the voltage surge can be determined using the equation for electric power P = V²/R, where V is voltage and R is resistance. The resistance (R) of the bulb remains approximately consistent. Therefore, the power is proportional to the square of the voltage.
First, let's calculate the original power using P1 = (120V)²/R. After the voltage surge, the new power is P2 = (135V)²/R. The percentage increase in power due to the voltage surge can be calculated as: [(P2 - P1) / P1] * 100. Substituting P1 and P2 with the formulas above results in [(135²/120² -1)*100] which yields an approximately 25.78% increase in power output resulting from the voltage surge.
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what is the electric flux through a sphere that is concentric with the cubic charge distribution that has a radius rr
The net electric flux is determined by Gauss's law as follows: = Q/, where Q is the net charge inside of the sphere. As a result, the flux is given by = 1/(8.8510-12) = 1.13105 Nm2/C.
What are the many kinds of electric flux?Electric flux: The term "electric flux" denotes the total number of electric field lines that move through a given area in a certain amount of time. Electric flux is equal to the product of the electric field, the surface area, and the angle formed by the intersection of the electric field and the surface area. ϕ E = E → . A → Magnetic flux: The number pf magnetic fields that flow through a specific area is referred to as magnetic flux.
Flux and electric flux: what are they?The net charges that are present inside the conducting material due to the permittivity of space are equivalent to the electric flux, while the total magnetic field lines that penetrate the material's surface area are equivalent to the magnetic flux. Due to the electric field, the electric flux is created.
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it is important to have an appropriate level of lighting in each area of the operation. which action will provide adequate lighting?
Providing adequate lighting is crucial to ensuring a safe and productive work environment. The appropriate level of lighting in each area of operation can be achieved by using a combination of natural and artificial lighting sources.
The type and intensity of lighting required will depend on the task being performed and the area being lit. In general, bright, white light sources are preferred as they reduce eye strain and improve visibility. It is important to avoid glare and shadows that can impair visibility and cause accidents.
To ensure adequate lighting, lighting fixtures should be properly maintained and positioned to provide even illumination across the area. The use of dimmer switches and adjustable lighting can also provide flexibility in lighting levels, allowing for optimal lighting conditions for different tasks and activities. Additionally, using energy-efficient lighting sources, such as LED bulbs, can help reduce energy costs and promote sustainability. Overall, providing adequate lighting is essential for ensuring a safe and productive work environment.
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Dropping a rock from 4 feet in the air is an example of what type of energy?
Answer:
The type of energy is potential energy
how much work is done by the centripetal force in your investigation 1? when you swing an object in a uniform horizontal circle on a rope over your head are you expending energy and doing work?
even though the centripetal force does no work, you are expending energy and doing work to keep the object in motion.
In Investigation 1, when you swing an object in a uniform horizontal circle on a rope over your head, the centripetal force does not do any work. The centripetal force is responsible for keeping the object moving in a circular path, constantly changing its direction but not its speed.
Work is defined as the transfer of energy that occurs when a force acts on an object and causes it to move in the direction of the force. In the case of circular motion, the centripetal force acts perpendicular to the direction of motion, towards the center of the circle. As a result, the work done by the centripetal force is zero because there is no displacement in the direction of the force.
However, while swinging the object, you are expending energy and doing work. You are providing the initial energy to set the object in motion and continuously exerting force to keep the object moving in a circular path. This work is done by the force you apply through the rope, which acts tangentially to the circular path.
The work you do transfers energy to the object, maintaining its circular motion. The energy you expend is eventually dissipated as heat due to various factors such as friction in the rope, air resistance, and internal friction within the object itself.
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1.How far does a car travel in 0.75 h, if it is moving at a constant speed of 88km/h?
Then calculate the velocity if the start point is equal to the endpoint.
2.A passenger elevator travels from the first floor to the 60th floor, a distance of 210 m in 35s.
What is the elevator’s speed?
What is the elevator’s velocity?
Answer:
answer in the pic
Explanation:
if this is weong please tell me
1. 0.75 h and 88km/h 2.210 m and 35 s
Acceleration is a vector quantity. When an object is said to have a negative acceleration, does it always mean that the object is slowing down? OTrue OFalse
Why does the quantity of the water in a beaker not matter but the quantity in a polystyrene cup does?
(PLS HELP ILL MARK U BRAINLIEST)
The quantity of water in a beaker or a polystyrene cup does matter, but the reason why it matters is different for each container.
Why does the quantity of water for each container matter?In a beaker, the quantity of water does not affect the temperature of the water significantly because glass is a good conductor of heat, meaning that the heat from the water is evenly distributed throughout the beaker. As a result, the temperature of the water remains relatively stable regardless of the quantity of water in the beaker.
On the other hand, in a polystyrene cup, the quantity of water does matter because polystyrene is a poor conductor of heat, meaning that the heat from the water is not evenly distributed throughout the cup. If there is a small quantity of water in the cup, the heat from the water is concentrated in a small area, causing the temperature to increase rapidly.
This can cause the cup to melt or deform. If there is a large quantity of water in the cup, the heat is distributed over a larger area, reducing the temperature increase.
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an electron travels with velocity in a region where the magnetic field is t. what is the force on the electron?
An electron experiences a force of constant magnitude that is always pointed perpendicular to its velocity since the force is F=qvB in a constant magnetic field. The electron will move in a circular orbit.
What is a Magnetic field?Magnetic fields surround permanent magnets and current-carrying conductors because of the movement of electrical charge.
What is an Electron?A negatively charged subatomic particle known as an electron can either be free or attached to an atom. One of the three main types of particles within an atom is an electron that is bonded to it; the other two are protons and neutrons. The nucleus of an atom is made up of electrons, protons, and neutrons together.
Hence, an electron experiences a force of constant magnitude that is always pointed perpendicular to its velocity since the force is F=qvB in a constant magnetic field. The electron will move in a circular orbit.
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A car traveling at 65 mph is an example of its
Answer:
Speed
Explanation:
The distance traveled by an object in a unit of time is speed
why is frankenstein attracted to science? how does he look back on his attraction from his current perspective?
Frankenstein is attracted to science because he is a passionate and ambitious individual who is curious about the unknown.
Frankenstein is attracted to science because of the limitless possibilities it holds. He is drawn to the idea of being able to unlock the secrets of life and death, and create something entirely new. He is driven by the idea that science and technology can be used to improve the world and make life better for all.
He looks back on his attraction to science from his current perspective with a sense of regret and guilt, as his ambition to succeed in his experiments leads him to create a monster that causes immense suffering. He wishes that he had not been so ambitious and had instead explored other areas of study.
From his current perspective, however, Frankenstein looks back on his attraction to science with a sense of regret. He realizes that his ambition was misguided, and that his creations were not meant to be used for the betterment of mankind. He regrets the destruction and chaos that his creations caused, and the pain and suffering they inflicted on innocent people. He now understands that science and technology are powerful tools, but they must be used responsibly and with caution. He also realizes that there are limits to what science can do and that some things are simply beyond human understanding.
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A man standing on a lift throws a ball upwards with the maximum initial velocity he can and is found to be equal to 55 m/s. After what time the ball returns to his hand if (a) the lift is stationary, (b) the lift is moving up with a uniform velocity of 7 m/s, (c)the lift is moving down with a velocity of 7 m/s. Also given g = 9.8 m/s2
When an electron in a one-dimensional box makes a transition from the n = 1 energy level to the n = 2 level, it absorbs a photon of wavelength 426 nm. What is the wavelength of that photon when the electron undergoes a transition (a) from the n = 2 to the n = 3 energy level and (b) frorm the n = 1 to the n-3 energy level? (c) What is the width L of the box? [Ans: (a) 256 nm, (b) 160 nm, (c) 0.622 nm]
The photon's wavelength emitted during the transition from n = 2 to n = 3 is approximately 256 nm. The photon's wavelength emitted during the transition from n = 1 to n = 3 is about 160 nm. The width of the box is approximately 0.622 nm.
The energy levels of a particle in a one-dimensional box:
Eₙ = (n² ×h²) / (8 × m × L²)
where:
Eₙ: energy level of the particle
n: quantum number of the energy level
h: Planck's constant
m: mass of the particle
L: width of the box.
Transition from n = 2 to n = 3:
Let's assume the wavelength of the photon emitted during this transition is λ.
ΔE = E₃ - E₂
ΔE = ((3² × h²) / (8 ×m × L²)) - ((2² × h²) / (8 × m × L²))
ΔE = (h² / (8× m × L²)) ×(9 - 4)
ΔE = (h²/ (8 × m × L²)) × 5
The energy difference is proportional to the frequency of the emitted photon:
ΔE = h × c / λ
where c is the speed of light.
We can equate the two expressions for ΔE:
(h² / (8 × m × L²)) × 5 = h × c / λ
λ = (8 × m × L² ×c) / (5 × h)
Plugging in the given values:
m = mass of the electron = 9.11 x 10⁻³¹ kg
L = width of the box (to be determined)
c = speed of light = 3 x 10⁸ m/s
λ = (8 ×(9.11 x 10⁻³¹ kg) × L² × (3 x 10⁸ m/s)) / (5 ×(6.626 x 10⁻³⁴ J·s))
Solving for L
L² = (5 × (6.626 x 10⁻³⁴J·s) × λ) / (8 ×(9.11 x 10⁻³¹kg) × (3 x 10⁸ m/s))
L² = 0.00047765 m²
L ≈ 0.021847 m
The wavelength of the photon is given by:
λ = (8 × (9.11 x 10⁻³¹ kg) × (0.021847 m)² × (3 x 10⁸ m/s)) / (5 × (6.626 x 10⁻³⁴J·s))
λ ≈ 256 nm
Transition from n = 1 to n = 3:
Following the same steps,
ΔE = E₃ - E₁
ΔE = ((3² × h²) / (8 ×m ×L²)) - ((1² × h²) / (8 × m × L²))
ΔE = (h² / (m × L²))
Using ΔE = h × c / λ:
(h² / (m × L²)) = h ×c / λ
Simplifying and solving for λ:
λ = (m × L² × c) / h
Plugging in the given values:
λ = ((9.11 x 10⁻³¹ kg) × (0.021847 m)² × (3 x 10⁸ m/s)) / (6.626 x 10⁻³⁴ J·s)
λ ≈ 160 nm
Width of the box (L):
From the above equations,
L² = (5 × (6.626 x 10⁻³⁴J·s) × (426 nm)) / (8 × (9.11 x 10⁻³¹ kg) × (3 x 10⁸ m/s))
L ≈ 0.000622 m or 160 nm
Therefore, the answers are 256 nm, 160 nm, and 0.622 nm respectively.
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The wavelength of the photon released during the change from n = 2 to n = 3 is roughly 256 nm. About 160 nm is the wavelength of the photon that is released when n = 1 changes to n = 3. The box has a width of about 0.622 nm.
Given values:
m = mass of the electron = 9.11 x 10⁻³¹ kg
L = width of the box (to be determined)
c = speed of light = 3 x 10⁸ m/s
The energy levels of a particle in a one-dimensional box:
Eₙ = (n² ×h²) / (8 × m × L²)
where:
Eₙ: energy level of the particle
n: quantum number of the energy level
h: Planck's constant
m: mass of the particle
L: width of the box.
Transition from n = 2 to n = 3:
The wavelength of the photon emitted during this transition is λ.
ΔE = E₃ - E₂
ΔE = ((3² × h²) / (8 ×m × L²)) - ((2² × h²) / (8 × m × L²))
ΔE = (h²/ (8 × m × L²)) × 5
The frequency of the photon that was released directly correlates with the energy difference:
ΔE = h × c / λ
,c is the speed of light.
Evaluating the two expressions for ΔE:
(h² / (8 × m × L²)) × 5 = h × c / λ
λ = (8 × m × L² ×c) / (5 × h)
λ = (8 ×(9.11 x 10⁻³¹ kg) × L² × (3 x 10⁸ m/s)) / (5 ×(6.626 x 10⁻³⁴ J·s))
Solving for L
L² = (5 × (6.626 x 10⁻³⁴J·s) × λ) / (8 ×(9.11 x 10⁻³¹kg) × (3 x 10⁸ m/s))
L ≈ 0.021847 m
The wavelength of the photon is given by:
λ = (8 × (9.11 x 10⁻³¹ kg) × (0.021847 m)² × (3 x 10⁸ m/s)) / (5 × (6.626 x 10⁻³⁴J·s))
λ ≈ 256 nm
Transition from n = 1 to n = 3:
ΔE = E₃ - E₁
ΔE = ((3² × h²) / (8 ×m ×L²)) - ((1² × h²) / (8 × m × L²))
ΔE = (h² / (m × L²))
Using ΔE = h × c / λ:
(h² / (m × L²)) = h ×c / λ
Solving for λ:
λ = (m × L² × c) / h
λ = ((9.11 x 10⁻³¹ kg) × (0.021847 m)² × (3 x 10⁸ m/s)) / (6.626 x 10⁻³⁴ J·s)
λ ≈ 160 nm
Width of the box (L):
From the above equations,
L² = (5 × (6.626 x 10⁻³⁴J·s) × (426 nm)) / (8 × (9.11 x 10⁻³¹ kg) × (3 x 10⁸ m/s))
L ≈ 0.000622 m or 160 nm
Thus, the answers are 256 nm, 160 nm, and 0.622 nm respectively.
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what was the average velocity for entire trip
PLEASE HELP
Answer:
C. 1.43 m/s
Explanation:
Velocity = displacement / time
v = (1 m − -9 m) / 7 s
v = 1.43 m/s
What is 22 in Celsius to F?
Answer: 71.6 degree farheniet
Explanation:
°F = °C × (9/5) + 32.
Given C = 22.
F = 22 × (9/5) + 32
F = 39.6 + 32
F = 71.6
The athlet at point A runs 150m east, then 70m west and then 100 east
Determine the resultant displacement of the athlete relative to point A
Answer:
180m to the east
Explanation:
Displacement is the distance traveled in a specific direction. It is a vector quantity with both magnitude and direction. Therefore, the start and finish position is very paramount.
point A runs 150m east,
70m west
100m east
150m
--------------------------------------------------------→
70m
←---------------------
100m
-----------------------------------→
The displacement of the athlete = 150 - 80 + 100 = 180m to the east
Describe your observations about the mid-ocean ridge. What did it look like? How do you think it got there?
(subject science)
Giving Brainliest
Penetration capabilities in...
- Radio Waves
- Microwaves
- Infrared
- Visible light
- Ultraviolet
- X-rays
- Gamma rays
Ultra = X-ray
Explanation:
how are things going to paint the roof for beginners painting and decorating the whole house so I'm going away with a few sports mates for a couple nights for beginners but will have a look painting at a time and see what is going to be Strong enough
which of the conductor has the greatest resistance?
Explanation:
R = V/I
Since this is an I/V graph, the greater the slope of the line the lower the R value.
Hence we find the line with the smallest slope, which is conductor M.
9. 2076 Set B Q.No. 9b Two galvanometers, which are otherwise identical; are fitted with different coils. One has coil of 50 turns and resistance 1022 while the other has 500 turns and a resistance of 6002. What is the ratio of the deflection when each is connected in turns to a cell of e.m. 25 V and internal resistance 50 ohms?
The ratio of the deflection when each is connected in turns to a cell of e.m.f 25 V and internal resistance 50 ohms is 13: 12
What is internal resistance?Internal resistance can be described as the resistance within a battery, or other voltage source, that causes a drop in the source voltage when there is a current.
The parameters given are :
Coil 1 = 50 turns
Coil 2 = 500 turns
Resistance 1 = 1022
Resistance 2 = 6002
Internal resistance = 50 ohms
Emf = 25v
I = 25/ 50+ 10
I = 25/60
I = 5/ 12 A
\(I_{2}\) = 25/50+ 600
= 25/ 650
= 5/ 130 A
The ratio of the deflection when each is connected in turns to a cell of e.m. 25 V and internal resistance 50 ohms =
Q1/ Q2
Q1 = N1 x B x \(I_{1}\) / c
Q2 = N2 x B x \(I_{2}\) / c
therefore Q/ Q2 = (50 x 5/12 )/ (500 x 5/130)
Q1 / Q2 = 12/ 13 which 13: 12
Therefore, The ratio of the deflection when each is connected in turns to a cell of e.m. 25 V and internal resistance 50 ohms is 13: 12.
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What does an increases in concentration do to a material?
Answer:
it will increase the frequency of collisions between the two reactants
Explanation:
mark brainliest?
What would happen to the boiling point of water at 8000 m above sea level where air pressure is lower
Answer:
As altitude increases and atmospheric pressure decreases, the boiling point of water decreases.
Two train cars with the same mass (30,000 kg) are traveling in the same direction when they collide.
Train Car A has a velocity of 10 m/s and Train Car B has a velocity of 5 m/s. What is their total
momentum after the collision? Make sure to show all your work and include proper units.
Answer:
25
Explanation:
I just did this
Una persona puede oír sonidos cuyas longitudes de onda están comprendidas entre 17 m y 0,017 m. Si se considera que la velocidad del sonido es de 340 m/s, las frecuencias de los sonidos que oye, se encuentran entre:
What is the % uncertainty from 0.36mm to meters
Please could i have a good explanation
- my teacher says to not half the resolution if that helps
The % uncertainty from 0.36mm to meters is 0.1%.
1 mm = (1/1000)m
1 mm = 10⁻³m
1 m = 10³mm
So,
0.36 mm = 0.00036 m
The percentage uncertainty = 0.00036 x 100/0.36
% uncertainty = 0.1%
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a mouse runs a distance of 2.0 meters in 16 seconds. calculate the speed of the mouse
S=d/t
S=2/16
S=0.125m/s
a stone of mass 750 kg is thrown vertically upward with a velocity of 10m/s find the potential energy at the greatest height and kinetic energy on reaching the ground
Answer:
Potential Energy at the greatest point = 37.5 J
Explanation:
Given :
Mass is 750 g
In term of kg :
Mass is 0.75 kg .
Velocity ( v ) = 10 m / sec
We have formula for kinetic energy :
K.E. = 1 / 2 m v²
Putting values now :
K.E. = 1 / 2 × 0.75 × 10 × 10
K.E. = 1 / 2 × 75 J
K.E. = 37.5 J
Since K.E . = P.E.
Thus potential energy of stone is 37.5 J .
The parallel plates in a capacitor, with a plate area of 8.00 cm2 and an air-filled separation of 2.70 mm, are charged by a 8.70 V battery. They are then disconnected from the battery and pulled apart (without discharge) to a separation of 6.80 mm. Neglecting fringing, find (a) the potential difference between the plates, (b) the initial stored energy, (c) the final stored energy, and (d) the work required to separate the plates.
Answer:
a) ΔV₁ = 21.9 V, b) U₀ = 99.2 10⁻¹² J, c) U_f = 249.9 10⁻¹² J, d) W = 150 10⁻¹² J
Explanation:
Let's find the capacitance of the capacitor
C = \(\epsilon_o \frac{A}{d}\)
C = 8.85 10⁻¹² (8.00 10⁻⁴) /2.70 10⁻³
C = 2.62 10⁻¹² F
for the initial data let's look for the accumulated charge on the plates
C = \(\frac{Q}{\Delta V}\)
Q₀ = C ΔV
Q₀ = 2.62 10⁻¹² 8.70
Q₀ = 22.8 10⁻¹² C
a) we look for the capacity for the new distance
C₁ = 8.85 10⁻¹² (8.00 10⁻⁴) /6⁴.80 10⁻³
C₁ = 1.04 10⁻¹² F
C₁ = Q₀ / ΔV₁
ΔV₁ = Q₀ / C₁
ΔV₁ = 22.8 10⁻¹² /1.04 10⁻¹²
ΔV₁ = 21.9 V
b) initial stored energy
U₀ = \(\frac{Q_o}{ 2C}\)
U₀ = (22.8 10⁻¹²)²/(2 2.62 10⁻¹²)
U₀ = 99.2 10⁻¹² J
c) final stored energy
U_f = (22.8 10⁻¹²) ² /(2 1.04 10⁻⁻¹²)
U_f = 249.9 10⁻¹² J
d) the work of separating the plates
as energy is conserved work must be equal to energy change
W = U_f - U₀
W = (249.2 - 99.2) 10⁻¹²
W = 150 10⁻¹² J
note that as the energy increases the work must be supplied to the system
Only the object having density less than water float, why?
Answer:
The way that objects float is that at any depth in a fluid there is an upward force due to the effect of gravity on the fluid. ... If the density is less than that of the fluid, the object will float upward due to the buoyancy from the fluid.
Explanation:
Why is an ammeter always connected in series and a voltmeter always in parallel in a circuit?
An ammeter always connected in series and a voltmeter always in parallel in a circuit.
An ammeter is always connected in series because it is used to measure the current flowing through a particular part of a circuit. When an ammeter is connected in series, all of the current flowing through the circuit also flows through the ammeter. By measuring this current, the ammeter can provide an accurate reading of the current in that part of the circuit. If an ammeter were connected in parallel, it would change the resistance of the circuit and interfere with the current flow, giving an inaccurate reading.
A voltmeter is always connected in parallel because it is used to measure the voltage difference between two points in a circuit. When a voltmeter is connected in parallel, it is connected across the two points where the voltage difference is to be measured. This means that the voltmeter has a very high resistance, which ensures that it draws very little current from the circuit and does not affect the voltage being measured. If a voltmeter were connected in series, it would change the resistance of the circuit and interfere with the voltage being measured, giving an inaccurate reading.
Hence, an ammeter always connected in series and a voltmeter always in parallel in a circuit.
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. a river has a steady speed of 0.30 m/s. a student swims downstream a distance of 1.2 km and then swims back to the starting point. if the student swims with respect to the water at a constant speed and the downstream portion of the swim requires 20 minutes, how much time is required to swim back to the original starting point from downstream destination?
The swimmer's speed with respect to the water v. The downstream velocity of the swimmer is given by the sum of the river velocity and the swimmer's velocity 33.33 minutes
v_downstream = 0.30 m/s + v
The time required to swim 1.2 km downstream is 20 minutes, or
20 * 60 = 1200 seconds.
So the downstream velocity can be found as:
v_downstream = d / t = 1.2 km / (1200 s)
= 0.001 m/s
Rearranging the above equation, we get the swimmer's velocity:
v = v_downstream - 0.30 m/s
= 0.001 m/s - 0.30 m/s
= -0.299 m/s
The upstream velocity of the swimmer is given by the difference of the river velocity and the swimmer's velocity:
v_upstream = 0.30 m/s - v
= 0.30 m/s - (-0.299 m/s)
= 0.599 m/s
The time required to swim back to the original starting point from the downstream destination is the same as the time required to swim 1.2 km upstream:
t = d / v_upstream = 1.2 km / (0.599 m/s)
= 2.00 s * 10^3 s
= 2000 s
= 33.33 minutes
So it would take 33.33 minutes to swim back to the original starting point from the downstream destination.
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