A) 750gm
11. Ifa rectangular solid box of aluminum is heated, which of the following is not true?
A) Its mass remains constant
Cits density increase
B) Its volume increase
Do none of the above​

Answer:

c. gravitational attraction between the sun and earth

The gravitational attraction between the Sun and the Earth is exactly modeled by the tension in the string.  (C)

This is an excellent demonstration !  It shows:

-- If she uses a heavier ball (more mass), she gets more tension in the string, just like planets.

-- If she wants the ball (planet) to revolve faster, she has to increase the tension in the string.

-- If she lets out a longer string, the ball moves slower, and there's less tension in the string, just like planets.

-- The ball stays in the same plane all the way around, just like planets.

Answer:

Specific heat capacity, = 1.43 J/g°C

Explanation:

Given the following data;

Mass = 10 g

Change in temperature = 140°C

Quantity of heat = 2000 J

To find the specific heat capacity;

Heat capacity is given by the formula;

\( Q = mcdt\)

Where;

Making c the subject of formula, we have;

\( c = \frac {Q}{mdt} \)

Substituting into the equation, we have;

\( c = \frac {2000}{10*140} \)

\( c = \frac {2000}{1400} \)

Specific heat capacity, = 1.43 J/g°C

The frequency of protons in the cyclotron are \(1.45 * 10^8 Hz,\)the speed at which protons exit the cyclotron is \(1.63 *10^7 m/s\), the maximum kinetic energy is \(9.66 * 10^{-17} J\), the number of revolutions made by the protons is 6.57.

Let us proceed by solving the sub questions
(a) The cyclotron frequency for the protons in this cyclotron is given by the formula f = qB/2πm where q is the charge of the proton, B is the magnetic field strength and m is the mass of the proton. Substituting the values given in the problem, we get
f = (\(1.6 * 10^{-19} C\))(0.808 T)/(2π)(\(1.67 * 10^{-27 }kg\)) =  \(1.45 * 10^8 Hz,\)

(b) The speed at which protons exit the cyclotron can be found using the formula v = rω where r is the radius of the cyclotron and ω is the angular frequency of the proton. The angular frequency can be found using ω = 2πf where f is the cyclotron frequency found in part (a). Substituting these values, we get
v = (0.351 m)(2π)(\(1.45 * 10^8 Hz\))
= \(1.63 * 10^7 m/s.\)

(c) The maximum kinetic energy of the protons can be found using Kmax = qV where V is the potential difference between the dees. Substituting values given in problem, we get
Kmax = (\(1.6 * 10^{-19} C\))(604 V)
= \(9.66 * 10^{-17} J.\)

(d) The time it takes for a proton to complete one revolution can be found using T = 2πr/v where r is the radius of the cyclotron and v is the speed of the proton found in part (b). Substituting these values, we get
T = (2π)(0.351 m)/(\(1.63 * 10^7 m/s\))
= \(4.52 * 10^{-8} s\) and N = (\(1.45 * 10^8 Hz)\)(\(4.52 * 10^{-8} s\))
≈ 6.57 revolutions.

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Answer:

a. 0.41 m

b. 5.72 m/s

c. i. For part (a), I chose the hand as the reference level since the penny was thrown from the hand and the height of the penny at the hand is zero and also, it is easier to calculate from a zero reference level.

ii. For part (b), I chose the ground as the reference level since the height of the penny above the ground is positive and the height of the penny when the penny hits the ground is zero and also, it is easier to calculate from a zero reference level.

d. 5.72 m/s

Explanation:

a. Use energy to find how high the penny goes above your hand before stopping.

Taking the hand as the ground level, and from the law of conservation of energy, the total mechanical energy at the hand, E equals the total mechanical energy when the penny stops in the air, E'.

E = E'

U + K = U' + K' where U = initial potential energy at hand level = mgh where h = height at hand level = 0, K = initial kinetic energy at hand level = 1/2mv² where v = speed at hand level = 2.85 m/s, U' = final potential energy at stopping level = mgh' where h' = height at stopping level, K = final kinetic energy at stopping level = 1/2mv'² where v = speed at stopping level = 0 m/s (since the penny momentarily stops)

So, U + K = U' + K'

mgh + 1/2mv² = mgh' + 1/2mv'²

substituting the values of the variables into the equation, we have

mg(0) + 1/2m(2.85 m/s)² = mgh' + 1/2m(0 m/s)²

0 + 1/2m(8.1225 m²/s²) = mgh' + 0

m(4.06125 m²/s²) = mgh'

h' = 4.06125 m²/s² ÷ g

h' = 4.06125 m²/s² ÷ 9.8 m/s²

h' = 0.41 m

(b) The penny then falls to the floor, 1.26 m below your hand. Use energy to find its speed just before it hits the floor.  

Taking the hand as the ground level, and from the law of conservation of energy, the total mechanical energy when the penny stops in the air, E'  equals the total mechanical energy on the ground, E"

E' = E"

U' + K' = U" + K" where U' = initial potential energy at stopping level = mgh" where h' = height at stopping level = height of penny above hand, h' + height of hand above ground = 0.41 m + 1.26 m = 1.67 m, K = initial kinetic energy at stopping level = 1/2mv'² where v = speed at stopping level = 0 m/s (since the penny momentarily stops), U = final potential energy at ground level = mgh₁ where h₁ = height at ground level = 0, K = final kinetic energy at ground level = 1/2mv"² where v" = speed at ground level,

So, U' + K' = U' + K'

mgh" + 1/2mv'² = mgh₁ + 1/2mv"²

substituting the values of the variables into the equation, we have

mg(1.67 m) + 1/2m(0 m/s)² = mg(0) + 1/2mv"²

1.67mg + 0 = 0 + 1/2mv"²

1.67mg = 1/2mv"²

1.67g = 1/2v"²

v"² = 2(1.67g)

v" = √[2(1.67g)]

v" = √[2(1.67 m × 9.8 m/s²)]

v" = √[2(16.366 m²/s²)]

v" = √[32.732 m²/s²)]

v" = 5.72 m/s

(c) Explain your choice of reference level for parts (a) and (b).

i. For part (a), I chose the hand as the reference level since the penny was thrown from the hand and the height of the penny at the hand is zero and also, it is easier to calculate from a zero reference level.

ii. For part (b), I chose the ground as the reference level since the height of the penny above the ground is positive and the height of the penny when the penny hits the ground is zero and also, it is easier to calculate from a zero reference level.

(d) Choose a different reference level and repeat part (b)

Taking the hand as the ground level, and from the law of conservation of energy, the total mechanical energy when the penny stops in the air, E'  equals the total mechanical energy on the ground, E"

E' = E"

U' + K' = U" + K" where U' = initial potential energy at stopping level = mgh' where h' = height at stopping level = 0.41 m, K = initial kinetic energy at stopping level = 1/2mv'² where v' = speed at stopping level = 0 m/s (since the penny momentarily stops), U = final potential energy at ground level = mgh₁ where h₂ = height of hand above the ground level = height of ground below hand = -1.26 m(it is negative since the ground is below the hand), K = final kinetic energy at ground level = 1/2mv"² where v = speed at ground level,

So, U' + K' = U' + K'

mgh' + 1/2mv'² = mgh₂ + 1/2mv"²

substituting the values of the variables into the equation, we have

mg(0.41 m) + 1/2m(0 m/s)² = mg(-1.26 m) + 1/2mv"²

0.41mg + 0 = -1.26 mg + 1/2mv"²

0.41mg + 1.26mg = 1/2mv"²

1.67mg = 1/2mv"²

1.67g = 1/2v"²

v"² = 2(1.67g)

v" = √[2(1.67g)]

v" = √[2(1.67 m × 9.8 m/s²)]

v" = √[2(16.366 m²/s²)]

v" = √[32.732 m²/s²)]

v" = 5.72 m/s

Answer:

Advantages. It is suitable to measure low temperatures because of its freezing point is low. It is less toxic than mercury thermometer and hence high on safety factor for human and environment. It has a greater value of temperature coefficient of expansion than a mercury thermometer.

In a drum-buffer-rope system, the lot size that moves from one work center to another for additional processing is a "batch" size.

The drum-buffer-rope (DBR) system is a manufacturing scheduling method that aims to maximize throughput while minimizing inventory and operating expenses. In this system, the "drum" represents the bottleneck work center that determines the production rate for the entire system, and the "buffer" is a quantity of inventory strategically placed before the bottleneck to prevent downtime.

The "rope" refers to the mechanism used to synchronize production with demand, typically through a pull-based system that only allows material to be released to the next work center when the previous work center has completed its processing. This approach ensures that production is driven by actual demand and that inventory is minimized throughout the system, resulting in improved efficiency and profitability.

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--The complete question is, in a drum-buffer-rope system, the lot size that moves from one work center to another for additional processing is ______.--

The correct options based on the information will be:

In regards to this endeavor, a control group is one where variables are retained as a form of comparison against an experimental group that has alterations made.

As such, Group B serves as the untouched element here and remains unaltered in terms of culinarian, crust firmness, topping selection, and cooking duration, while Group A is the subject in question whose variable being tested is the variation in approaches for preparing their pizza (like brick-oven heating versus conventional ovens).

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The weight of a person on the moon given that the mass of the person on Earth is 105 lbm is 17.3 lbf.

Force is defined as the influence that produces a change in motion of an object. The unit of force is newton (N), which is defined as the amount of force that can accelerate a mass of 1 kg at a rate of 1 meter per second squared (m/s²).

The weight of an object is the gravitational force acting on the object. It is directly proportional to the mass of the object and the acceleration due to gravity. The unit of weight is newton (N).

Formula to calculate weight:

Weight (N) = mass (kg) × acceleration due to gravity (m/s²)

Conversion from lbm to kg:1 lbm = 0.453592 kg

Acceleration due to gravity on the moon is 1.622 m/s².

Therefore, Weight (N) = mass (kg) × acceleration due to gravity (m/s²)

Weight on Earth = 105 lbm

= 47.63 kg

Weight on Moon = 47.63 × 1.622

Weight on Moon = 77.19 N

= 17.3 lbf

Therefore, the weight of a person on the moon given that the mass of the person on Earth is 105 lbm is 17.3 lbf.

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The resistance of the light bulb can be determined using Ohm's Law, which states that the resistance (R) is equal to the ratio of the potential difference (V) across the bulb to the current (I) passing through it:

R = V / I

Given:

Potential difference (V) = 120 V

Current (I) = 0.83 A

Substituting these values into the formula:

R = 120 V / 0.83 A

R ≈ 144.58 Ω (rounded to two decimal places)

Therefore, the resistance of the light bulb is approximately 144.58 Ω.

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All three experience the same uboyant force.

What is buoyant force?

Upthrust, often known as buoyancy, is an upward force applied by a fluid against the weight of an object that is partially or completely submerged. The weight of the fluid on top causes pressure in a fluid column to rise with depth.

All three objects experience the same buoyant force because their volumes are equal the buoyant force on an object in a liquid depends on the volume of the submerged object, the density of the liquid, and the acceleration caused by gravity but not on the density of the object.

Hence, all will experience the same buoyant force.

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a) The frequency of the wave emitted by the cellular phone is approximately 8.69×10⁸ Hz.

The frequency (f) of a wave is the number of complete cycles that occur per unit of time. In this case, the wavelength (λ) of the wave is given as 34.5 cm. The speed of light (c) in a vacuum is approximately 3.00×10⁸ m/s.

The relationship between frequency, wavelength, and speed of light is given by the equation c = fλ.

Rearranging the equation, we have f = c/λ.

Plugging in the values, we find f ≈ (3.00×10⁸ m/s)/(34.5×10⁻² m) ≈ 8.69×10⁸ Hz.

b) The magnetic-field amplitude of the wave is approximately 2.06×10⁻¹⁰ T.

The electric-field amplitude (E) and magnetic-field amplitude (B) of an electromagnetic wave are related by the equation B = E/c, where c is the speed of light.

Given the electric-field amplitude as 6.20×10⁻² V/m,

we can calculate the magnetic-field amplitude as B ≈ (6.20×10⁻² V/m)/(3.00×10⁸ m/s) ≈ 2.06×10⁻¹⁰ T.

c) The intensity of the wave is approximately 8.79×10⁻¹⁰ W/m².

The intensity (I) of an electromagnetic wave is the power per unit area carried by the wave. It is given by the equation I = (1/2)ε₀cE², where ε₀ is the vacuum permittivity and E is the electric-field amplitude.

Plugging in the values, we have I ≈ (1/2)(8.85×10⁻¹² C²/N·m²)(3.00×10⁸ m/s)(6.20×10⁻² V/m)² ≈ 8.79×10⁻¹⁰ W/m².

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Answer:

Let the momentum of the orange train be positive

P = 100 * 8 - 200 * 1 = 600 kg-m/s

P(final) = 600 kg-m/s

P / M = 600 kg-m/sec / 300 kg = 2 m/s    

Answer-B     final momentum = 600 kg-m/s

The starting of a snowboarder's motion is explained by Newton's third law of motion.

According to this law, every action has an equal and opposite reaction. Thus, forces always operate in pairs.

The first object exerts force, which is the person's foot pushing against the ground. The snowboarder then experiences a pushback from the ground as a result of the equal and opposite reaction force on the foot. The ground's reaction propels the person forward. Always of equal magnitude to the action force, the response force acts in the opposite direction.

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The relationship between voltage and current (amperes) is Ohm's law V=IR.

In welding, the relation between voltage and amperage is a complex one that depends on several factors, including the type of welding process being used, the properties of the metal being welded, and the welding equipment being used. In general, voltage can be thought of as the driving force behind the welding process, providing the energy needed to heat and melt the metal. Amperage, on the other hand, represents the amount of current flowing through the circuit, which is related to the heat being generated by the welding process. For most welding processes, an increase in voltage results in an increase in amperage, which in turn increases the heat being generated. This increase in heat can help to overcome any resistance to welding that may be encountered, such as the thickness of the metal or the presence of contaminants. However, too much voltage or amperage can lead to excessive heat and potentially harm the metal or the welding equipment. Therefore, it is important to carefully control the voltage and amperage levels during welding in order to achieve a high-quality weld while also protecting the metal and equipment.

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People may experience:

Headache: can be acute or persistent

Whole body: blackout, fatigue, or poor balance

Cognitive: amnesia, disorientation, or mental confusion

Sleep: sleep disturbances or sleepiness

Gastrointestinal: nausea or vomiting

Also common: irritability, mild depression, ringing in the ears, or sensitivity to light

Hopes this helps, please follow me. Thanks

Answer:

headache, dizziness, disorientation, and nausea.

Explanation:

A concussion is any sudden impact to the head or acceleration or deceleration without impact. A concussion disrupts normal brain activity and can be dangerous. The symptoms include headache, dizziness, disorientation, and nausea.

The distance at which the crane lift a crate is 0.0781 m.

Distnace is the lenght between two points.

To determine the distance the crane can lift the crate, we use the formula below.

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

Hence, the distance is 0.0781 m.

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Answer:

B: 273 K

Explanation:

see answer.

The dimensions in the equation are consistent.

Equation of motion, is a mathematical formula that describes the position, velocity, or acceleration of a body relative to a given frame of reference.

x = at²

where;

x (m) = a(m/s²) x t²(s²)

multiple m/s² with s² = m

x(m) = at²(m)

Thus, the dimensions in the equation are consistent.

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The principle of operation of a pressurized garden sprayer is as follows;

A pressurized garden sprayer is a chamber which is filled with a liquid which can be a lubricant, paint or chemical, then filled with compressed air to allow the liquid to be sprayed at high pressure.

As it is pumped by hand, the compressed air with which it is filled serves the primary purpose of allowing the liquid to be sprayed at high pressure - an important requirement for performance characteristics of the sprayer.

Flammable liquids must not be used with such equipment.

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Answer:it takes approximately 148.8 seconds to achieve. The average person in a free-fall will hit the ground going at 9.66 m/s from the top of the Empire State Building.

Explanation:

Answer:

10-0÷2=5 that's the answer

When weighing chemicals on a balance, the term "tare" is used. Pressing the tare button enables you to record only the weight of the substance being measured, not the weight of the container it is being measured in.

Weighing by difference is automatically accomplished by tarring a balance. When a balance is tared with an object on the balance pan, the weight of the object is automatically subtracted from each reading up until the balance is re-tared or zeroed.

Testing a balance is crucial because you want an accurate result when you weigh an object. The calculations could all be off if a balance is not set to zero.

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Answer:

C = 1.01

Explanation:

Given that,

Mass, m = 75 kg

The terminal velocity of the mass, \(v_t=60\ m/s\)

Area of cross section, \(A=0.33\ m^2\)

We need to find the drag coefficient. At terminal velocity, the weight is balanced by the drag on the object. So,

R = W

or

\(\dfrac{1}{2}\rho CAv_t^2=mg\)

Where

\(\rho\) is the density of air = 1.225 kg/m³

C is drag coefficient

So,

\(C=\dfrac{2mg}{\rho Av_t^2}\\\\C=\dfrac{2\times 75\times 9.8}{1.225\times 0.33\times (60)^2}\\\\C=1.01\)

So, the drag coefficient is 1.01.

Using Newtons law

\(\\ \sf\longmapsto Force=Mass\times Acceleration\)

\(\\ \sf\longmapsto Mass=\dfrac{Force}{Acceleration}\)

\(\\ \sf\longmapsto Mass=\dfrac{340}{3.8}\)

\(\\ \sf\longmapsto Mass=89.4kg\)

Answer:

no

Explanation:

it's a graph

Answer:

It specifically is not a element but it has plenty of elements in it

Explanation:

The most accurate definition of a behavior is that a behavior is an action that can be observed and measured (option C).

A behavior is an observable response produced by an organism.

The behavior of a person is the way the person acts or reacts to something, for example, a child throwing a tantrum is an example of bad behavior.

This suggests that an individual's behavior can be observed and measured using certain procedures.

Therefore, the most accurate definition of a behavior is that a behavior is an action that can be observed and measured.

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The ant's resultant velocity is 0.51 m/s at 78.7°

Since the ant is moving with a velocity of 0.1 m/s in the +x direction relative to the treadmill, and the treadmill is moving 0.5 m/s in the +y direction, the magnitude of the resultant velocity of the ant relative to the ground (since both directions are perpendicular) is thus

V = √(x² + y²)

= √[(0.1 m/s)² + (0.5 m/s)²]

= √[0.01 m²/s² + 0.25 m²/s²]

= √(0.26 m²/s²)

= 0.51 m/s.

The direction is Ф = tan⁻¹(y/x)

= tan⁻¹(0.5 m/s ÷ 0.1 m/s)

= tan⁻¹(5)

= 78.69°

≅ 78.7°

The ant's resultant velocity is 0.51 m/s at 78.7°

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Answer:

Message me i know the answer