A 9.0-V battery (with nonzero resistance) and switch are connected in series across the primary coil of a transformer. The secondary coil is connected to a light bulb that operates on 120 V. Determine the ratio of the secondary to primary turns needed for the bells transformer. Determine the ratio of the secondary to primary turns needed for the bells transformer. Ns/Np=?

The potential energy of the roller coaster is 176,400 J (joules).

The potential energy of an object is given by the formula PE = mgh, where PE is the potential energy, m is the mass of the object, g is the acceleration due to gravity, and h is the height or vertical position of the object.

In this case, the roller coaster is at a peak of 20m and has a mass of 900kg. The acceleration due to gravity, g, is approximately 9.8 \(m/s^2\).

Using the formula, we can calculate the potential energy:

PE = mgh

= (900 kg)(9.8 \(m/s^2\))(20 m)

= 176,400 J

Therefore, the potential energy of the roller coaster is 176,400 J (joules).

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Answer:800 Joules

Explanation: Energy = Power × Time = 100∗8100∗8 = 800 joules

We are given the following information

Mass of Cart 1 = m₁ = 1 kg

Mass of Cart 2 = m₂ = 3 kg

Initial velocity of Cart 1 = u₁ = 5 m/s

Initial velocity of Cart 2 = u₂ = -2 m/s

Final velocity of Cart 1 = v₁ = -4 m/s

Final velocity of Cart 2 = v₂ = ?

Please note that velocity is taken positive when moving right and negative when moving left.

Recall that the total momentum before the collision must be equal to the momentum after the collision.

Mathematically,

Substitute the given values and solve for v₂

Therefore, the final speed of the 3.0 kg cart is 1 m/s

Also, note that cart 2 will be moving right after the collision since the speed is positive.

A. The average speed you can use to pull the safe is 1.02 m/s

B. The time needed to pull the safe up is 17.65 s

First, we shall obtain the force. This is shown below:

F = mg

F = 60 × 9.8

F = 588 N

Finally, we shall obtain the average speed. Details below:

Power = force × average speed

600 = 588 × average speed

Divide both sides by 588

Average speed = 600 / 588

Average speed = 1.02 m/s

The time needed to pull the safe up can be obtained as follow:

Time = Total distance / average speed

Time = 18 / 1.02

Time = 17.65 s

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Complete question:

You know you can provide 600 W

of power to move large objects. You need to move a 60-kg

safe up to a storage loft, 18 m

above the floor.

Part A

With what average speed can you pull the safe straight up?

Part B

What is the time needed to pull the safe up?

Explanation:

This is called the DEDUCTIBLE   .... the part you must deduct from your bill and pay....the rest insurance pays  ( although there may be co-pays)

Answer:

When accounting for threats to validity in their study design, researchers must make assumptions about their environment. If any of these assumptions prove to be false, then it is more difficult to properly interpret the results of the experiment.

Explanation:

Answer:

P = 2893.95 [kPa]

Explanation:

The manometric pressure can be calculated by means of the following equation.

\(P=Ro*g*h\)

where:

Ro = density of the water = 1000 [kg/m³]

g = gravity acceleration = 9.81 [m/s²]

h = deep = 295 [m]

Now replacing:

\(P = 1000*9.81*295\\P = 2893950 [Pa]\\P = 2893.95 [kPa]\)

Answer:

Y = 5.03 x 10⁻³ m = 5.03 mm

Explanation:

Using Young's Double-slit formula:

\(Y = \frac{\lambda L}{d}\)

where,

Y = Fringe Spacing = Width of bright fringe = ?

λ =  wavelength = 633 nm = 6.33 x 10⁻⁷ m

L = Screen distance = 3.1 m

d = slit width = 0.39 mm = 3.9 x 10⁻⁴ m

Therefore,

\(Y = \frac{(6.33\ x\ 10^{-7}\ m)(3.1\ m)}{3.9\ x\ 10^{-4}\ m}\)

Y = 5.03 x 10⁻³ m = 5.03 mm

Answer:

the learning which is gained through observation and experimentation

With the use of formula, he car's centripetal acceleration is 0.43 m/s²

Angular velocity is the angle turned by a body per time taken. It is measured in radian per second. That is, rad/s

Given that a race car goes around a level, circular track with a diameter of 1.00 km at a constant speed of 75 km/h. What is the car's centripetal acceleration in m/s²

Centripetal Acceleration a = v² / r

Where

Substitute the two parameters into the equation

a = 20.83² / 1000

a = 434.03 / 1000

a = 0.43 m/s²

Therefore, the car's centripetal acceleration is 0.43 m/s²

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Answer:

454 km

Explanation:

227 km/h * 2 h = 454

The magnitude of the force on the 4.00-kg block is 3.47 N.

The given parameters:

\(a = \frac{F}{m_1 + m_2} \\\\a = \frac{5.2}{2 + 4} \\\\a = \frac{5.2}{6} \\\\a = 0.867 \ m/s^2\)

The magnitude of the force on the 4.00-kg block is calculated as follows;

F = ma

F = 4 x 0.867

F = 3.47 N

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At a divergent boundary, heat and pressure can cause metamorphism, magma can solidify to form igneous rocks, and sediments can accumulate and lithify to form sedimentary rocks. These three processes contribute to the formation of various types of rocks.

At a divergent boundary, three main processes occur that can lead to the formation of metamorphic, igneous, and sedimentary rocks:

1. Metamorphic rocks: Heat and pressure from the divergent boundary can cause existing rocks to be metamorphosed, or transformed, into new rocks with different textures and mineral compositions. This process is called metamorphism.

2. Igneous rocks: Magma, which is molten rock, can rise to the surface at a divergent boundary and cool and solidify to form igneous rocks. This process is called solidification or crystallization.

3. Sedimentary rocks: Sediments, such as sand and mud, can accumulate in the low-lying areas near a divergent boundary, such as in rift valleys or on the continental shelf. Over time, these sediments can be compacted and cemented together to form sedimentary rocks. This process is called lithification.

Hence, Heat and pressure at a divergent boundary can produce metamorphism, solidify magma to create igneous rocks, and accumulate and lithify sediment to create sedimentary rocks. Different sorts of rocks are formed as a result of these three processes.

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Answer:

i think it should be 18

Explanation:

Mirrors are a common tool used by painters to depict a variety of viewpoints and nuanced interactions between the observer and the artist.

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Answer:

A

Explanation: took the test

Answer:

8 divided by 12 is 1.6

Explanation:

. .......

It would take approximately 546 days for the decay rate of the sample of this radioactive isotope to fall to 0.58 of its initial rate.

1. The decay rate of a radioactive isotope is proportional to the number of radioactive atoms present in the sample at any given time.

2. The decay rate can be expressed as a function of time using the formula: R(t) = R₀ * \(e^{(-\lambda t\)), where R(t) is the decay rate at time t, R₀ is the initial decay rate, λ is the decay constant, and e is the base of the natural logarithm.

3. The half-life of a radioactive isotope is the time it takes for half of the radioactive atoms in a sample to decay. In this case, the half-life is given as 210 days.

4. Using the half-life, we can find the decay constant (λ) using the formula: λ = ln(2) / T₁/₂, where ln(2) is the natural logarithm of 2 and T₁/₂ is the half-life.

5. Substituting the given half-life into the formula, we have: λ = ln(2) / 210.

6. Now, we need to find the time it takes for the decay rate to fall to 0.58 of its initial rate. Let's call this time "t".

7. Using the formula for the decay rate, we can write: 0.58 * R₀ = R₀ * e^(-λt).

8. Simplifying the equation, we get: 0.58 = \(e^{(-\lambda t\)).

9. Taking the natural logarithm of both sides, we have: ln(0.58) = -λt.

10. Substituting the value of λ from step 5, we get: ln(0.58) = -(ln(2) / 210) * t.

11. Solving for t, we have: t = (ln(0.58) * 210) / ln(2).

12. Evaluating the expression, we find: t ≈ 546.

13. Therefore, it would take approximately 546 days for the decay rate of the sample of this radioactive isotope to fall to 0.58 of its initial rate.

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Answer:

Explanation:

total weight acting downwards

= 3g + 10g

13 g

volume of lead = 10 / 11.3 = .885 cm³

Let the volume of bobber submerged in water be v in floating position . buoyant force on bobber  = v x 1 x g

Buoyant force on lead =  .885 x 1 x g

total buoyant force = vg + .885 g

For floating

vg + .885 g  = 13 g

v = 12.115 cm³

total volume of bobber

= 4/3 x 3.14 x 2³

= 33.5 cm³

fraction of volume submerged

= 12.115  / 33.5

= .36  

= 36 %

The fraction of the bobber's volume submerged as a percent of the total volume is 36.2 %.

The given parameters;

The volume of the bobber is calculated as follows;

\(V = \frac{4}{3} \pi \times r^3\\\\V = \frac{4}{3} \pi \times (2)^3\\\\V = 33.52 \ cm^3\)

The buoyant force experienced by the bobber due to the volume submerged is calculated as follows;

\(F _b= \rho Vg\\\\F_b = 1 \times V \times g\\\\F_b = Vg\)

The volume of the lead is calculated as follows;

\(V = \frac{mass}{density} \\\\V = \frac{10}{11.3} \\\\V = 0.885 \ cm^3\)

The buoyant force experienced by the lead due to the volume submerged is calculated as follows

\(F_b = \rho Vg\\\\F_b = 0.885 g\)

The total buoyant force is calculated as;

\(Vg + 0.885g = (3+ 10)g\\\\g(V + 0.885) = 13g\\\\V+ 0.885 = 13\\\\V = 13 -0.885\\\\V = 12.12 \ cm^3\)

The fraction of the bobber's volume submerged as a percent of the total volume is calculated as follows;

\(= \frac{12.12}{33.52} \times 100\%\\\\= 36.2 \ \%\)

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Sunlight to chemistry energy conversion, energy transfer as from sun to plants, kinetic energy is created by converting thermal energy. when wood is burned, mechanical energy is converted to thermal energy.

Chemical, electrical, infrared, mechanical, thermal, et nuclear energy are the six main types of energy. Different research may focus on other forms, such as electric, acoustic, electromagnetic, and some others.

Energy transition describes the change in the global energy industry away from fossil-based methods of hydropower, such as oil, natural gas, and coal, and toward rechargeable batteries with renewable sources of electricity like wind and solar.

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Answer:

The precision corresponds to the least count of the measurements, which is 0.1 cm 0.1 c m for the length of the box. In a similar manner, the precision of the volume is 0.01×103 cm3=10 cm3 0.01 × 10 3 c m 3 = 10 c m 3 .

Answer:

Graph C

Explanation:

This is the answer because it is the only one that shows the vehicle accelerate to a constant speed before stopping and slowing down.

Answer:

211.2 kg:m/s

Explanation:

Mark brainily

When the thistle funnel is moved upwards towards the surface of the liquids, the height (h) decrease.

What happens when the thistle funnel is moved upward?

An important principle outlined by Pascal's law states that any fluid (in this instance, liquids) experiences equal transmission of force in every direction within it. Hence, there is an intimate relationship between the height of a liquid column and its pressure.

Raising a thistle funnel reduces this height causing loss of weight from above this point thus decreasing its pressure.

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See complete question in the attached image.

Answer:

Explanation:

The answer is **(c) 9.39 m/s** for the velocity of the bullet-block system after it's hit, and **(g) 209.39 m/s** for the bullet's velocity before it hit the box.

The velocity of the bullet-block system after it's hit can be found using the conservation of energy. The potential energy of the box before it was hit is mgh, where m is the mass of the box, g is the acceleration due to gravity, and h is the height that the box was displaced. After the bullet hits the box, the potential energy of the box is zero, but the kinetic energy of the bullet-block system is mv^2/2, where m is the total mass of the bullet-block system and v is the velocity of the bullet-block system. Setting these two expressions equal to each other, we get:

```

mgh = mv^2/2

```

Solving for v, we get:

```

v = sqrt(2mgh)

```

In this case, we have:

* m = 0.05 kg + 1.3 kg = 1.35 kg

* g = 9.8 m/s^2

* h = 4.5 m

So, the velocity of the bullet-block system after it's hit is:

```

v = sqrt(2 * 1.35 kg * 9.8 m/s^2 * 4.5 m) = 9.39 m/s

```

The velocity of the bullet before it hit the box can be found using the conservation of momentum. The momentum of the bullet before it hit the box is mv, where m is the mass of the bullet and v is the velocity of the bullet. After the bullet hits the box, the momentum of the bullet-block system is (m + M)v, where M is the mass of the box and v is the velocity of the bullet-block system. Setting these two expressions equal to each other, we get:

```

mv = (m + M)v

```

Solving for v, we get:

```

v = mv/(m + M)

```

In this case, we have:

* m = 0.05 kg

* M = 1.3 kg

* v = 9.39 m/s

So, the velocity of the bullet before it hit the box is:

```

v = 0.05 kg * 9.39 m/s / (0.05 kg + 1.3 kg) = 209.39 m/s

```

The velocity of the bullet-block system after the collision is approximately a) 6.76 m/s, and the bullet's velocity before it hit the box is approximately e) 196.76 m/s.

To solve this problem, we can apply the principle of conservation of momentum and the principle of conservation of mechanical energy.

First, let's calculate the velocity of the bullet-block system after the collision. We can use the principle of conservation of momentum, which states that the total momentum before the collision is equal to the total momentum after the collision.

Let m1 be the mass of the bullet (0.05 kg) and m2 be the mass of the box (1.3 kg). Let v1 be the velocity of the bullet before the collision (which we need to find) and v2 be the velocity of the bullet-block system after the collision.

Using the conservation of momentum:

m1 * v1 = (m1 + m2) * v2

0.05 kg * v1 = (0.05 kg + 1.3 kg) * v2

0.05 kg * v1 = 1.35 kg * v2

Now, let's calculate the velocity of the bullet-block system (v2). Since the system goes up by a height of 4.5 m, we can use the principle of conservation of mechanical energy.

m1 * v1^2 = (m1 + m2) * v2^2 + m2 * g * h

0.05 kg * v1^2 = 1.35 kg * v2^2 + 1.3 kg * 9.8 m/s^2 * 4.5 m

Now, we can substitute the value of v2 from the momentum equation into the energy equation and solve for v1.

By solving these equations, we find that v1 is approximately 196.76 m/s.

Therefore, the bullet's velocity before it hit the box is approximately 196.76 m/s. (e) 196.76 m/s

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To calculate the torque required to create an angular acceleration, we can use the formula:

Torque = Moment of Inertia × Angular Acceleration

The moment of inertia of a disk can be calculated using the formula:

Moment of Inertia = (1/2) × Mass × Radius^2

Given:

Mass = 15,000 kg

Radius = 6.14 m

Angular Acceleration = 0.0500 rad/s^2

First, calculate the moment of inertia:

Moment of Inertia = (1/2) × Mass × Radius^2

Moment of Inertia = (1/2) × 15,000 kg × (6.14 m)^2

Next, calculate the torque:

Torque = Moment of Inertia × Angular Acceleration

Torque = Moment of Inertia × 0.0500 rad/s^2

Now, let's plug in the values and calculate:

Moment of Inertia = (1/2) × 15,000 kg × (6.14 m)^2

Moment of Inertia ≈ 283,594.13 kg·m^2

Torque = 283,594.13 kg·m^2 × 0.0500 rad/s^2

Torque ≈ 14,179.71 N·m

Rounding to three significant figures, the torque required to create an angular acceleration of 0.0500 rad/s^2 is approximately 14,180 N·m.

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The motion of the box changes as it will move slower because as the mass increases, the force of friction between the surface also increases. Thus, the correct option is A.

Force of friction is a type of contact force. Frictional force is the force which resists the motion when the surface of one object comes in contact with the surface of another object. Example of frictional force is the force of friction between two stones which are rubbed with each other. The SI unit of frictional force is Newton (N).

Frictional force can be calculated by the formula:

f = μN

where, f = frictional force,

μ = coefficient of friction,

N = Normal force

The mass of the objects (normal force - mg) which are in motion is directly proportional to the magnitude of the frictional force. As more books are added to the box while the force of push remains same the motion of the box will change and it will move slower because as mass increases, the force of friction between the surface also increases.

Therefore, the correct option is A.

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