a) A micro-hydro system has a 3 m head. Calculate the power produced in kW if the water
flow rate is 0.15 m3/s, assuming 85% efficiency.
b) Calculate the water volume (m3) of a reservoir that can store 15 kWh. Calculate for water
head of 1, 2, 3,..10 m. Assume 100% efficiency.
c) The water reservoir in (b) has a cubical shape, calculate the wall dimension (L, W, H) for
each calculated water head (1,2,3,..10 m).

Mostly for exhaust bolts we utilize impact wrenches. Impact wrenches exist very reasonably on flywheels because the crankshaft must be set from rotating. Also, impact wrenches exist valid on cars for reducing wheel nuts. The wheels need not be restrained or the brakes need not be used to fix the wheels in position.

Impact wrenches do a great job of tautening and relieving bolts, lug nuts, and rusted fasteners. They deliver a very increased rotational torque that normal drills exist simply not qualified for and have high torque output with minimal effort by the user.

Mostly for exhaust bolts we utilize impact wrenches. Impact wrenches exist very reasonably on flywheels because the crankshaft must be set from rotating. Also, impact wrenches exist valid on cars for reducing wheel nuts. The wheels need not be restrained or the brakes need not be used to fix the wheels in position.

Impact wrenches exist located in the tool chests of mechanics everywhere. They're commonly utilized for reducing lug nuts from cars and trucks, but they can even be utilized in any high-torque situation

Therefore, the correct answer is Neither A nor B.

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Answer: A. Makes a commodity available for sale or exchange

Explanation: hope it helps ^w^

Answer:

20368.917N

Explanation:

Frictional force (F) is the product of the Coefficient of friction and the normal reaction.

F = μN

Coefficient of friction, μ = 0.2

Normal reaction = MgCosθ

Mass, m = 12 tonnes = 12 * 1000 = 12000 kg

N = 12000 * 9.8 * cos30

N = 101844.58

F = 0.2 * 101844.58

F = 20368.917N

Answer:

Visual connectivity refers to the tangible aspects of a space; extent to which a place can be viewed from other places. It is believed that the design properties of a spatial layout of an atrium leaves unobstructed views horizontally and vertically.

Explanation:

Answer:

A

Explanation:

Excessive belt tension or high belt tension in belt result in the bearing of the stress that would lead to the failure of the motor while on the other hand the low tension is the belt represent the main reason of belt slipping that lead to the cause wear in belt. So here the automatic belt tensioner having multiple ribber beld shoiuld be used that we called as the serpentine belt in order to give the proper tension in the belt. In the case when the automatic belt tensioner is become order so it gives the non-proper tension as there is the requirement for replacement

The friction loss in the system is 3.480 kilowatts.

Let suppose that the pump within a distribution system is an open system at steady state, whose mass and energy balances are shown below:

\(\dot m_{in}-\dot m_{out} = 0\) (1)

\(\dot m_{in} = \frac{\dot V_{in}}{\nu_{in}}\) (2)

\(\dot m_{out} = \frac{\dot V_{out}}{\nu_{out}}\) (3)

\(\eta \cdot \dot W_{el} + \dot m_{in}\cdot (h_{in}-h_{out}) - \dot W_{f} = 0\) (4)

Where:

From steam tables we get the following water properties at inlet and outlet:

Inlet

\(p = 100\,kPa\), \(T = 25\,^{\circ}C\), \(\nu = 0.001003\,\frac{kJ}{kg}\), \(h = 104.927\,\frac{kJ}{kg}\), Subcooled liquid

Outlet

\(p = 300\,kPa\), \(T = 25\,^{\circ}C\), \(\nu = 0.001003\,\frac{kJ}{kg}\), \(h = 105.128\,\frac{kJ}{kg}\), Subcooled liquid

If we know that \(\dot V_{in} = 0.05\,\frac{m^{3}}{s}\), \(\nu_{in} = 0.001003\,\frac{m^{3}}{kg}\), \(h_{in} = 104.927\,\frac{kJ}{kg}\), \(h_{out} = 105.128\,\frac{kJ}{kg}\), \(\eta = 0.90\) and \(\dot W_{el} = 15\,kW\), then the friction loss in the system is:

\(\dot W_{f} = \frac{\dot V_{in}}{\nu_{in}}\cdot (h_{in} - h_{out}) + \eta \cdot \dot W_{el}\)

\(\dot W_{f} = \left(\frac{0.05\,\frac{m^{3}}{s} }{0.001003\,\frac{m^{3}}{kg} } \right)\cdot \left(104.927\,\frac{kJ}{kg}-105.128\,\frac{kJ}{kg}\right) + (0.90)\cdot (15\,kW)\)

\(\dot W_{f} = 3.480\,kW\)

The friction loss in the system is 3.480 kilowatts. \(\blacksquare\)

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A career in engineering is interesting and fun. It involves a lifetime of continuous learning to adapt to changes in society and the natural world. It often involves working in multi-disciplinary, multi-cultural, multi-site teams.

The process comprises breaking the truss into individual pieces and analyzing each piece as a separate rigid body.

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Answer:true

Explanation:

Answer:

116,090 Btus

Explanation:

Answer:

To join and reinforce intersecting structural members

Explanation:

The purpose of a gusset or gusset plate used in the construction and repair of aircraft structures is to join and reinforce intersecting structural members

Answer:

L = spindle

M = lower ball joint

part without the letter showing = steering knuckle

Explanation:

The genetic code is crystal clear. Every codon only specifies one amino acid (or start or stop). The genetic code repeats itself. The majority of amino acids are encoded by several codons.

Chromosomes contain genes. A linear array of linked genes is located along chromosomes. Map distances are (approximately) cumulative on a per-person basis. Codons, which are units of three nucleotides, are used to segment this sequence. The four nucleotides included in mRNA — A, U, G, and C — can be combined in a total of 64 distinct ways since codons are three-letter structures. We will go over three main guidelines: A codon's base order must correspond to the direction of translation system, The code doesn't overlap. A fixed reading frame is used to read the code.

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Answer:

B. body on frame

Explanation:

Answer:

A radio telescope can be divided into 4 functional parts. The four parts are: the reflector dish, the antenna, the amplifier and the receiver/recorder.  The large dish that most people associate with a radio telescope is used to focus the radio waves.

Explanation:

An airplane flying across the sky experience drag force determined by the factors including the speed of flight, coefficient of skin friction and the reference surface area

The boundary layer thickness is approximately 0.233 cm

The total skin friction drag, is approximately 265 N

Reason:

First part:

Given parameters are;

Chord length, L = 3 m

Velocity of the plane, V = 200 m/s

Density of the air, ρ = 1.225 kg/m³

Viscosity of the air, μ = 1.81 × 10⁻⁵ kg/(m·s)

The Reynolds number is given as follows;

\(R_{eL} = \dfrac{\rho \times V \times L}{\mu}\)

Therefore;

\(R_{eL} = \dfrac{1.255 \times 200 \times 3}{1.81 \times 10^{-5}} = 4.16022099448 \times 10^7 \approx 4.16 \times 10^7\)

Boundary layer thickness, \(\delta_L\), for laminar flow, is given as follows;

\(\dfrac{ \delta_L }{L}=\dfrac{5.0}{\sqrt{R_{eL} } }\)

\({ \delta_L }=\dfrac{5.0 \times L}{\sqrt{R_{eL} } }\)

Which gives;

\({ \delta_L }=\dfrac{5.0 \times 3}{\sqrt{4.16 \times 10^{7}} } \approx 2.33 \times 10^{-3 }\)

The boundary layer thickness, \(\delta_L\) ≈ 2.33 × 10⁻³ m = 0.233 cm

Second Part

The total skin friction is given as follows;

\(Dynamic \ pressure, q = \dfrac{1}{2} \cdot \rho \cdot V^2\)

Therefore;

\(q = \dfrac{1}{2} \times 1.225 \times 200^2 = 24,500\)

The dynamic pressure, q = 24,500 N/m²

Skin friction drag coefficient, \(C_D\), is given as follows;

\(C_D = \dfrac{1.328}{\sqrt{R_{eL} } }\)

Therefore;

\(C_D = \dfrac{1.328}{\sqrt{4.16 \times 10^7 } } \approx 2.06 \times 10^{-4}\)

Skin friction drag, \(D_f\), is given as follows;

\(D_f\) = q × \(C_D\) × A

Where;

A = The reference area

∴ \(D_f\) = 24,500 N/m² × 2.06 × 10⁻⁴ × 3 m × 17.5 m = 264.9675 N ≈ 265 N

The total skin friction drag, \(D_f\) ≈ 265 N

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The primary goal of political parties in televised presidential debates is to: D. to explain party platforms to voters.

A political party can be defined as an organized group of individuals (people) who presumably share common political ideologies, aims, goals, vision, and strategies on how a country should be governed.

This ultimately implies that, a political party ​is an organization of people that are sharing similar political ideologies and it provides a platform for a chosen candidate to run as its sole representative in an election category.

In this context, the primary goal of political parties in televised presidential debates is to explain party platforms to the electorates or voters.

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It's D I just took the test

Edge 2023 :)

Answer:

Trash rack

Open channel

Fore bay

Pen stock

Inlet valve

Turbine

Tailrace

Generator

Power house

Answer:

\(\triangle h=4.935m\)

Explanation:

From the question we are told that:

Liquid density \(\rho=800\)

Diameter of pipe \(d=4cm \approx 0.004m\)

Diameter of venture \(d=10cm \approx 0.010m\)

Specific weight of mercury P_mg \(133 kN/m^3\)

Flow rate \(r=0.05 m^3/s\)

Area A:

            \(A_1=\frac{\pi}{4}0.1^2\\A_1=0.00785m^2\\A_2=\frac{\pi}{4}0.04^2\\A_2=0.001256m^2\\\)

Generally the Bernoulli's equation is mathematically given by

\(\frac{P_1}{\rho_1g}+\frac{V_1^2}{2g}=\frac{P_2}{\rho g}+\frac{V_2^2}{2g}\\\)

Where

\(V_1=\frac{r}{A_1} \\\\ &V_1=\frac{r}{A_2}\)

Therefore

\(P_1-P_2=\frac{Pr^2}{2}(\frac{A_1^2-A_2^2}{A_1^2A_2^2})\)

Generally the equation for pressure difference b/w manometer fluid is given as

\(P_1-P_2=(p_mg-pg)\triangle h\)

Therefore

\((p_mg-pg)\triangle h=\frac{Pr^2}{2}(\frac{A_1^2-A_2^2}{A_1^2A_2^2})\)

\(\triangle h=\frac{\frac{Pr^2}{2}(\frac{A_1^2-A_2^2}{A_1^2A_2^2})}{(p_mg-pg)}\)

\(\triangle h=\frac{\frac{(800)(0.05)^2}{2}(\frac{(0.1)^2-(0.4)^2}{(0.1)^2(0.04)^2})}{(1.33*10^3-800*9.81)}\)

\(\triangle h=4.935m\)

Therefore elevation change is mathematically given by

\(\triangle h=4.935m\)

The axial forces in members BC, BI, and BJ are -1200 kN, 636 kN, and 300 kN, respectively.

To determine the axial forces in members BC, BI, and BJ using the method of joints, we need to follow these steps:

Step 1: Draw the free-body diagram of the entire truss and apply the equations of static equilibrium to determine the reactions at the supports. Since the truss is symmetrical, the reactions at the supports are equal and opposite and have a magnitude of 750 kN.

Step 2: Identify the joints in the truss and assign them unique labels. There are 5 joints in the Pratt truss, labeled A, B, C, I, and J.

Step 3: Draw a free-body diagram of each joint and label the forces acting on each joint. The forces acting on each joint are the external load (F = 300 kN), the axial forces in the truss members, and the reaction forces at the supports.

Step 4: Apply the equations of static equilibrium to each joint. Since we have three unknown axial forces in each joint, we need to write three equilibrium equations for each joint.

For joint B, we have:

ΣF_x = 0: -BC - BI = 0

ΣF_y = 0: -F + BJ + 2750 = 0

ΣF_z = 0: BCcos(45) - BJ*cos(45) = 0

Solving these equations, we get:

BC = -1200 kN

BI = 636 kN

BJ = 300 kN

Therefore, the axial forces in members BC, BI, and BJ are -1200 kN, 636 kN, and 300 kN, respectively.

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Answer:

Non functional

Explanation:

The correct code that fixes this bug-filled python code is:

from random import randint

class Character:

   def __init__(self):

       self.name = ""

       self.health = 1

       self.health_max = 1

   def do_damage(self, enemy):

       damage = min(

           max(randint(0, self.health) - randint(0, enemy.health), 0),

           enemy.health)

       enemy.health = enemy.health - damage

       if damage == 0:

           print("%s evades %s's attack." % (enemy.name, self.name))

       else:

           print("%s hurts %s!" % (self.name, enemy.name))

       return enemy.health <= 0

class Enemy(Character):

   def __init__(self, player):

       Character.__init__(self)

       self.name = 'a goblin'

       self.health = randint(1, player.health)

class Player(Character):

   def __init__(self):

       Character.__init__(self)

       self.state = 'normal'

       self.health = 10

       self.health_max = 10

   def quit(self):

       print(

           "%s can't find the way back home, and dies of starvation.\nR.I.P." % self.name)

       self.health = 0

   def help(self): print(Commands.keys())

   def status(self): print("%s's health: %d/%d" %

                           (self.name, self.health, self.health_max))

   def tired(self):

       print("%s feels tired." % self.name)

       self.health = max(1, self.health - 1)

   def rest(self):

       if self.state != 'normal':

           print("%s can't rest now!" % self.name)

           self.enemy_attacks()

       else:

           print("%s rests." % self.name)

           if randint(0, 1):

               self.enemy = Enemy(self)

               print("%s is rudely awakened by %s!" %

                     (self.name, self.enemy.name))

               self.state = 'fight'

               self.enemy_attacks()

           else:

               if self.health < self.health_max:

                   self.health = self.health + 1

               else:

                   print("%s slept too much." % self.name)

                   self.health = self.health - 1

   def explore(self):

       if self.state != 'normal':

           print("%s is too busy right now!" % self.name)

           self.enemy_attacks()

       else:

           print("%s explores a twisty passage." % self.name)

           if randint(0, 1):

               self.enemy = Enemy(self)

               print("%s encounters %s!" % (self.name, self.enemy.name))

               self.state = 'fight'

           else:

               if randint(0, 1):

                   self.tired()

   def flee(self):

       if self.state != 'fight':

           print("%s runs in circles for a while." % self.name)

           self.tired()

       else:

           if randint(1, self.health + 5) > randint(1, self.enemy.health):

               print("%s flees from %s." % (self.name, self.enemy.name))

               self.enemy = None

               self.state = 'normal'

           else:

               print("%s couldn't escape from %s!" %

                     (self.name, self.enemy.name))

               self.enemy_attacks()

   def attack(self):

       if self.state != 'fight':

           print("%s swats the air, without notable results." % self.name)

           self.tired()

       else:

           if self.do_damage(self.enemy):

               print("%s executes %s!" % (self.name, self.enemy.name))

               self.enemy = None

               self.state = 'normal'

               if randint(0, self.health) < 10:

                   self.health = self.health + 1

                   self.health_max = self.health_max + 1

                   print("%s feels stronger!" % self.name)

           else:

               self.enemy_attacks()

   def enemy_attacks(self):

       if self.enemy.do_damage(self):

           print("%s was slaughtered by %s!!!\nR.I.P." %

                 (self.name, self.enemy.name))

Commands = {

   'quit': Player.quit,

   'help': Player.help,

   'status': Player.status,

   'rest': Player.rest,

   'explore': Player.explore,

   'flee': Player.flee,

   'attack': Player.attack,

}

p = Player()

p.name = input("What is your character's name? ")

print("(type help to get a list of actions)\n")

print("%s enters a dark cave, searching for adventure." % p.name)

while(p.health > 0):

   line = input("> ")

   args = line.split()

   if len(args) > 0:

       commandFound = False

       for c in Commands.keys():

           if args[0] == c[:len(args[0])]:

               Commands[c](p)

               commandFound = True

               break

       if not commandFound:

           print("%s doesn't understand the suggestion." % p.name)

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n

e

g

r

o

means black in spanish!