Answer:
The baker made 12 muffins
Step-by-step explanation:
if for every one cup of batter you get one muffin, you divide the total amount of batter used by each muffin and get 12/1 then divide to get 12
09) The ratio of the number of jackfruit in baskets P, Q
and R is 6:2:5. The total number of jackfruit
in basket Pis 48 more than the number of
jackfruit in basket Q. Calculate the total number
of jackfruits in the three baskets.
A 121 B 144 C 156 D 169
Answer:
156 jackfruits
Step-by-step explanation:
Let there are 6x jackfruit in baseket P, 2x in basket Q and 5x in basket R.
The total number of jackfruit in basket P is 48 more than the number of jackfruit in basket Q. ATQ,
6x = 48 + 2x
Solving for x.
6x - 2x = 48
4x = 48
x = 12
Jackfruits in basket P = 6x = 6(12) = 72
Jackfruits in basket Q = 2x = 2(12) = 24
Jackfruits in basket R = 5x = 5(12) = 60
Total no of jackfruits = 72 + 24 + 60
= 156
So, there are 156 jackfruits in the three baskets.
The sum of a number and two is equal to negative seven. Translate this sentence to an equation and then find the number.
5
9
-9
-5
Answer:
its C
Step-by-step explanation:
Solve the simultaneous equation, will give out brainliest answer
a=bcd
a+b=cd
a+b+c=d
a+b+c+d=1
Answer:
a = 1/42, b = 1/7, c = 1/3 and d = 1/2
Step-by-step explanation:
a = bcd (1)
a + b = cd (2)
a + b + c = d (3)
a + b + c + d = 1 (4)
Substituting equation (3) into equation (4), we have
a + b + c = d (3)
a + b + c + d = 1 (4)
(a + b + c) + d = 1 (4)
d + d = 1 (5)
2d = 1
dividing through by 2, we have
d = 1/2
Taking equation (2) and equation (3), we have
a + b = cd (2)
a + b + c = d (3)
substituting equation (2) into equation (3), we have
a + b = cd (2)
(a + b) + c = d (3)
cd + c = d
Factorizing, we have
c(d + 1) = d
dividing through by d + 1, we have
c = d/(d + 1)
substituting d = 1/2 into the equation, we have
c = d/(d + 1)
c = 1/2 ÷ (1/2 + 1)
c = 1/2 ÷ 3/2
c = 1/2 × 2/3
c = 1/3
Taking equations (1) and (2), we have
a = bcd (1)
a + b = cd (2)
Substituting equation (1) into (2), we have
a = bcd (1)
a + b = cd (2)
bcd + b = cd (2)
Factorizing, we have
b(cd + 1) = cd
dividing through by (cd + 1), we have
b = cd/(cd + 1)
substituting the values of c and d into the equation,, we have
b = cd/(cd + 1)
b = 1/3 × 1/2/(1/3 × 1/2 + 1)
b = 1/6/(1/6 + 1)
b = 1/6 ÷ 7/6
b = 1/6 × 6/7
b = 1/7
Since a = bcd, substituting the values of b,c and d into the equation, we have
a = bcd
a = 1/7 × 1/3 × 1/2
a = 1/42
So, a = 1/42, b = 1/7, c = 1/3 and d = 1/2
I set z=t=0(x,y,z,t)
and I got a partial solution (0,1,0,0).
I solved two homogeneous matrices once for z=1
and t=0
, then for z=0
and t=1
and I got two solutions (1,1,1,0)
and (1,1,0,1).
Then, I got (0,1,0,0)+a∗(1,1,1,0)+b∗(1,1,0,1
)
Therefore, all possible results are (0,1,0,0),(1,0,1,0),(1,0,0,1),(0,1,1,1)
Would this be correct?
The correct set of possible results would be (0, 1, 0, 0), (1, 2, 1, 0) and (1, 2, 0, 1).
Your approach seems to be correct, but there seems to be a minor mistake in your final list of possible solutions. Let's go through the steps to clarify.
Given the initial conditions z=t=0, you obtained a partial solution (0,1,0,0).
Next, you solved the homogeneous equations for z=1 and t=0, which resulted in a solution (1,1,1,0).
Similarly, solving the homogeneous equations for z=0 and t=1 gives another solution (1,1,0,1).
To find the general solution, you combine the partial solution with the solutions obtained in the previous step, using parameters a and b.
(0,1,0,0) + a(1,1,1,0) + b(1,1,0,1)
Expanding this expression, you get:
(0+a+b, 1+a+b, 0+a, 0+b)
Simplifying, you obtain the following set of solutions:
(0, 1, 0, 0)
(1, 2, 1, 0)
(1, 2, 0, 1)
Therefore, the correct set of possible results would be:
(0, 1, 0, 0)
(1, 2, 1, 0)
(1, 2, 0, 1)
Note that (0, 1, 1, 1) is not a valid solution in this case, as it does not satisfy the initial condition z = 0.
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the city's pr manager, who never took statistics, claimed the mean score of all ninth graders in the city was the average of 77, 91, and 71, which is 79.7. of course, that is incorrect. what is the mean score for all ninth graders in the city? round to one decimal place.
The mean score of the given three scores is approximately 26.6, which is not the mean score for all ninth graders in the city.
To find the mean score for all ninth graders in the city, we need more information than just three scores. Without additional data, we cannot accurately determine the mean score for all ninth graders in the city.
However, we can calculate the mean of the given scores to verify that it is not 79.7 as claimed by the PR manager:
Mean = (77 + 91 + 71) / 3 = 79.7/3 = 79.7 ÷ 3 ≈ 79.7/3 ≈ 26.6
So the mean score of the given three scores is approximately 26.6, which is not the mean score for all ninth graders in the city.
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Find the critial path between A and L in the diagram below. You should explain the order in which you assign labels to each vertex and how you find the critical path from the labels which you have assigned. [12 marks]
The critical path is the longest path in a network diagram, which determines the shortest time needed to complete a project. It also represents the sequence of tasks that cannot be delayed without affecting the completion time of the project.
In this context, the critical path between A and L can be found by assigning labels to each vertex and then identifying the longest path. To do this, the following steps can be followed:
- Assign an initial label of zero to vertex A.
- Determine the earliest start time (EST) for each vertex by adding the duration of the previous activity to its earliest start time. This can be represented by the formula EST = max(EFT of predecessors).
- Assign the EST to each vertex.
- Determine the earliest finish time (EFT) for each vertex by adding its duration to its EST. This can be represented by the formula EFT = EST + duration.
- Assign the EFT to each vertex.
- Determine the latest finish time (LFT) for each vertex by subtracting its duration from the LFT of its successor. This can be represented by the formula LFT = min(LST of successors) - duration.
- Assign the LFT to each vertex.
- Determine the latest start time (LST) for each vertex by subtracting its duration from its LFT. This can be represented by the formula LST = LFT - duration.
- Assign the LST to each vertex.
- Calculate the slack time for each vertex by subtracting its EST from its LST. This can be represented by the formula Slack = LST - EST.
- Identify the critical path by selecting the longest path from A to L, which has zero slack time.
By following these steps, the critical path between A and L in the diagram can be determined. It is important to note that the labels assigned to each vertex represent the earliest start time (EST), earliest finish time (EFT), latest start time (LST), latest finish time (LFT), and slack time for each vertex.
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20 POINTS!!! Use the quadratic formula above to solve for h(t) = -4.9t^2 + 8t + 1 where h is the height of the ball in meters and t is time in seconds. Round to the nearest hundredth second!
Answer:
Two solutions: -0.12 and 1.75.
Step-by-step explanation:
The quadratic formula is:
\(\begin{array}{*{20}c} {\frac{{ - b \pm \sqrt {b^2 - 4ac} }}{{2a}}} \end{array}\). Assuming that the x² term is a, the x term is b, and the constant is c, we can plug the values into the equation.
\(\begin{array}{*{20}c}{\frac{{ - 8 \pm \sqrt {8^2 - 4\cdot-4.9\cdot1} }}{{2\cdot-4.9}}} \end{array}\)
\(\begin{array}{*{20}c}{\frac{{ - 8 \pm \sqrt {64 + 19.6} }}{{-9.8}}} \end{array}\)
\(\begin{array}{*{20}c}{\frac{{ - 8 \pm \sqrt {83.6} }}{{-9.8}}} \end{array}\)
\(\begin{array}{*{20}c}{\frac{{ - 8 \pm \sqrt {9.14} }}{{-9.8}}} \end{array}\)
\(\frac{-8 + 9.14}{-9.8} = -0.12\)
\(\frac{-8-9.14}{-9.8} =1.75\)
Hope this helped!
a ferry traveled 1/6 of the distance between 2 ports 3/7 hour. The ferry travels at a constant rate.
At this rate, what fraction of the distance between the two ports can the ferry travel in one hour?
The two ports can the ferry travel the distance of 7/18 in one hour.
What is Average speed?Average speed is defined as the ratio of the total distance traveled by a body to the total time taken for the body to reach its destination.
We have been given that a ferry traveled 1/6 of the distance between 2 ports 3/7 hour.
Since the ferry travels at a constant rate.
We have to determine the distance between the two ports can the ferry travel in one hour.
So, the average speed = (1/6) / (3/7) = (1/6) × (7/3) = 7/18
So the distance between the two ports can the ferry travel in one hour.
⇒ distance = time × average speed = 1 × 7/18 = 7/18
Thus, the two ports can the ferry to travel the distance of 7/18 in one hour.
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the sum of 47 and 39 is 22 more than a number. what is the number?
Answer: 64
Step-by-step explanation:
(47 + 39) - 22
= 86 - 22
= 64
How many solutions does this system of equations have? 2y-x=10
And 2x-4y=-20
System of equations 2y-x=10 and 2x-4y=-20 have infinitely many solutions.
What is Equation?Two or more expressions with an Equal sign is called as Equation.
The given equations are 2y-x=10...(1)
and 2x-4y=-20...(2)
From equation 1, 2y-10=x
Now plug in x value in equation 2
2(2y-10)-4y=-20
4y-20-4y=-20
0=0
So the system of equation has infinitely many solutions.
Hence, system of equations 2y-x=10 and 2x-4y=-20 have infinitely many solutions.
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Write the equation in standard form for the circle passing through ( – 2,4) centered at the origin.
To write the equation in standard form for the circle passing through (–2, 4) centered at the origin, we need to find the radius and the center of the circle.
Since the circle passes through (–2, 4), we can use the distance formula to find the radius, which is the distance from the origin to (–2, 4).
The distance formula is given by:
distance = sqrt((x2 - x1)^2 + (y2 - y1)^2)
In this case, x1 = 0, y1 = 0, x2 = –2, and y2 = 4. So, the radius is:
radius = sqrt((-2 - 0)^2 + (4 - 0)^2) = sqrt(20) = 2sqrt(5)
The center of the circle is the origin, since the circle is centered at the origin. Therefore, the equation of the circle in standard form is:
x^2 + y^2 = (2sqrt(5))^2 = 20
So, the equation of the circle passing through (–2, 4) centered at the origin is x^2 + y^2 = 20.
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I need help with these four
Answer:
True, b), c), b)Step-by-step explanation:
Q1
TrueQ2
b) sin = opposite/hypotenuseQ3
Cos A = 0.1908A = arccos 0.1908A = 79° ⇒ Option c)Q4
tan A = 16/19A = arctan 16/19A = 40° ⇒ Option b)A six-sided die is rolled. (Enter your probabilities as fractions.) (a) What is the probability that a 3 will result? 9/24 (b) What is the probability that a 10 will result? 0 (c) What is the probability that an even number will result?
Answer: 50%
Step-by-step explanation:
For an even # to result, the fraction would be 3/6 or 1/2 which would become 0.5 or 50%.
(a) The probability of rolling a 3 is 1/6.
(b) The probability of rolling a 10 is 0 since a standard six-sided die only has numbers from 1 to 6.
(c) The probability of rolling an even number is 3/6 or 1/2. This is because there are three even numbers (2, 4, and 6) out of the six possible outcomes.
(a) The probability of rolling a 3 on a six-sided die is 1/6. There are 6 possible outcomes when rolling a die, and only 1 of those outcomes is a 3.
(b) The probability of rolling a 10 on a six-sided die is 0. There are no possible outcomes when rolling a die that will result in a 10.
(c) The probability of rolling an even number on a six-sided die is 1/2. There are 3 possible outcomes when rolling a die that will result in an even number: 2, 4, and 6.
Here are the answers in mathematical notation:
(a) P(3) = 1/6
(b) P(10) = 0
(c) P(even) = 1/2
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Given the e(t) = 1.8t + 25
How many feet had Evie ran after 14 seconds? Round to the nearest whole second.
Convert km into cm
10 points available
MHS Student Bookmarks Kami Export - How10.4 ReviewA group of 80 trees in a forest aren't growing properly. A botanist determines:• 68 of the trees have a disease or are being damaged by insects• 54 of the trees have a disease• 30 of the trees are being damaged by insectsWhat is the probability that a randomly selected tree has both a disease and is being damaged by insects?0꾧00 %0o1720ΟΟΟRE10123 9 5
Let the event that a tree has disease be D and the event that tree is being damaged by insects be I.
Therefore,
\(\begin{gathered} |D|=54 \\ |I|=30 \\ |D\cup I|=68 \\ \end{gathered}\)Recall that:
\(\begin{gathered} |D\cup I|=|D|+|I|-|D\cap I| \\ 68=54+30-|D\cap I| \\ \text{ Therefore,} \\ |D\cap I|=84-68=16 \end{gathered}\)The required probability is given by:
\(\frac{|D\cap I|}{80}=\frac{16}{80}=20\%\)Hence, the required probability is 20%=0.2
How do you write the equation of a line in point slope form and slope intercept form given point (6, -3) and has a slope of 1/2?
The equation of the line in point-slope form is y + 3 = (1/2)(x - 6), and in slope-intercept form is y = (1/2)x - 6.
To write the equation of a line in point-slope form and slope-intercept form given a point (6, -3) and a slope of 1/2:
1. Point-Slope Form:
The point-slope form of a linear equation is given by: \(y - y_1 = m(x - x_1)\), where (\(x_1, y_1\)) is a point on the line and m is the slope.
Substituting the values into the equation:
y - (-3) = 1/2(x - 6)
y + 3 = 1/2(x - 6)
2. Slope-Intercept Form:
The slope-intercept form of a linear equation is given by: y = mx + b, where m is the slope and b is the y-intercept.
Using the given slope (1/2) and the point (6, -3), we can solve for the y-intercept (b).
-3 = (1/2)(6) + b
-3 = 3 + b
b = -6
The equation in slope-intercept form is:
y = 1/2x - 6
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What is the solution set to the inequality 5 x 2 )( x 4 0 ?.
The solution set to the given inequality is
(-∞, -4) U (2,∞)
What is inequality?
An inequality in mathematics depicts the connection between two values in an algebraic statement that are not equal. One of the two variables on the two sides of the inequality may be greater than, greater than or equal to, less than, or less than or equal to another value, according to inequality signals.
5(x – 2)(x + 4) > 0
First we solve for x, we replace the inequality sign by = sign
5(x – 2)(x + 4) = 0
Divide both sides by 5
(x – 2)(x + 4) = 0
Now we set each factor =0 and solve for x
x-2 =0 , so x= 2
x+4 =0, so x= -4
Now we use number line and make three intervals
First interval -infinity to -4
second interval -4 to 2
third interval 2 to infinity
Now we check each interval with our inequality
First interval -infinity to -4, pick a number in this interval and check with our inequality. lets pick -5
5(-5 – 2)(-5 + 4) > 0
35>0 is true
second interval -4 to 2, pick a number in this interval and check with our inequality. lets pick 0
5(0– 2)(0 + 4) > 0
-40>0 is false
Third interval 2 to infinity, pick a number in this interval and check with our inequality. lets pick 3
5(3 – 2)(3 + 4) > 0
35>0 is true
solution set are the intervals that make the inequalities true
(-∞, -4) U (2,∞)
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Question:
What is the solution set to the inequality 5(x – 2)(x + 4) > 0?
Which of the following is equal to the opposite of -45?
O-(-45)
O-45
O-1-451
O-145!
Step-by-step explanation:
A o option
-(-45)
hope it helps
5x^2+14x=x+6
HURRYY SOLVE BY FACTORING EXPLAIN AND SHOW EVER STEP
Answer:
(x+3) and (5x-2)
Step-by-step explanation:
first get everything onto one side
5x^2+13x-6=0
then multiply 5 by 6 to get 30 and 15 times 2 is thirty and 15-2=13
5x^2+15x-2x-6=0
then split in half and factor both sides
5x^2+15x factored is 5x(x+3)
-2x-6 factored is -2(x+3)
so the answer is (x+3) and (5x-2)
The amount of money in a saving account after t years is represented by the function f(t) = 650(1.027)
What does the value 650 represent in this situation?
The amount of money in the savings account increases by $650 each year.
The amount of money in the savings account is 650 times the amount of the previous year.
The amount of money in the savings account decreases by $650 each year.
The initial amount in the account is $650.
Answer: The initial amount in the account is $650.
Step-by-step explanation:
The formula for compound interest is:
Future value = P * (1 + i)^t
Where,
P = Initial amount
i is the interest rate
t is the time period
The equation in the question takes the same format which means that the $600 is the initial amount in the account. It will then be compounded by the interest rate in the brackets over the amount of years the cash will be in that savings account.
Danika live 5 block from her chool. If he walk to and from chool 5 day each week how many block doe he walk in one week?
Danika walks 50 blocks in one week.
Multiplication is a mathematical operation that embodies the fundamental concept of repeated addition of the same integer. The multiplied numbers are known as the factors, and the outcome of the multiplication of two or more numbers is known as the product of those numbers. Multiplication is used to make repetitive adding of the same number easier. It is used for combining groups of identical size.
As per the data given,
We have,
Danika lives at 5 blocks from her school.
As Danika walks 5 blocks to and from school, making her round trip
So, total distance covered by Danika will be: 5 blocks + 5 blocks = 10 blocks.
As Danika walks to and from school 5 days a week,
Hence, she walks 10 blocks * 5 days = 50 blocks in one week.
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Find the 15th term of the arithmetic sequence whose common difference is d= 7 and whose first term is a1 = 5
Answer:
The 15th term is 103
Step-by-step explanation:
Arithmetic Sequence
An arithmetic sequence is a list of numbers with a definite pattern by which each term is found by adding or subtracting a fixed quantity to the previous term. If n is the number of the term, then:
\(a_n=a_{n-1}+d\)
Where d is called the common difference. If we know the first term, the nth term is calculated by:
\(a_n=a_1+(n-1)*d\)
The question asks us to find the term n=15 of an arithmetic sequence with a common difference d=7 and first term a1=5.
Applying the formula above:
\(a_{15}=5+(15-1)*7\)
\(a_{15}=5+14*7\)
\(a_{15}=5+98=103\)
The 15th term is 103
A cylindrical cup and a cone both have a radius of 5 cm and a height of 8 cm. What is the approximate difference between the volume of the cup and the volume of the cone? A 133 cm B. 267 cm C. 419 cm D. 628 cm
Answer:
419
Step-by-step explanation:
Which choices are equivalent to the fraction below
Answer:
B. 1/2, and D. 5/10.
Step-by-step explanation:
All the equivalent fractions are:
1/2, 2/4, 4/8, 8/16, 5/10, 10/20, 6/12, and 3/6.
A triangular prism is 8 yards long. It has a triangular face with a base of 12 yards. The volume of the prism is 720 cubic yards. What is the height of its triangular face
The height of the triangular face is 15 yards.
To find the height of the triangular face, we will use the formula for the volume of a triangular prism:
Volume = (1/2) * Base * Height * Length.
We are given the following values:
- Volume (V) = 720 cubic yards
- Length (L) = 8 yards
- Base (B) = 12 yards
We need to find the height of the triangular face (H).
Let's plug in the given values into the formula and solve for H:
720 = (1/2) * 12 * H * 8
First, simplify the equation:
720 = 6 * H * 8
720 = 48 * H
Now, divide both sides by 48 to find the value of H:
H = 720 / 48
H = 15 yards.
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Find the difference. use your answer in the simplest terms, using the slash ( / ) as the fraction bar.
1/2 - 1/4
Answer:
1/4
Step-by-step explanation:
You cannot subtract (or add) a fraction with different denominators so first, you need to find a common denominator. You can do this by finding the least common multiple (LCM).
Here the denominators are 2 and 4 so the LCM is 4.
After you find the LCM you need to multiply the denominator by a number that equals the LCM. Then multiply the numerator by that same number.
So convert both 1/2 and 1/4
1/4 x 1/1 = 1/4
1/2 x 2/2 = 2/4
Now we can just subtract the numerator from each other.
2/4 - 1/4 = 1/4
We cannot simplify the difference any more so keep it the same.
Multiply the starting price by the right term that uses the compound average to show that the arithmetic mean does not recover the final price while the geometric and continuous means do. Convert the percent averages to fractions.
$53. 07 x (1 + arith mean) 3 = 53.07 x (1 + #21 %) 3 = #22
$53. 07 x (1 + geom mean) 3 = 53.07 x (1 + #23 %) 3 = $ #24
$53. 07 x e cont mean x 3 = 53.07 x e #25 % x 3 = $ #26
I need help filling out numbers #21 through #26
The values for numbers #21 through #26 are as follows:
#21: 2.33% or 0.0233. #22: $56.4842. #23: 1.85% or 0.0185. #24: $56.4148. #25: 3.64% or 0.0364. #26: $57.4397
#21: 2.33% (arithmetic mean as a fraction: 0.0233)
#22: $56.4842 (result of the calculation)
#23: 1.85% (geometric mean as a fraction: 0.0185)
#24: $56.4148 (result of the calculation)
#25: 3.64% (continuous mean as a fraction: 0.0364)
#26: $57.4397 (result of the calculation)
To fill out numbers #21 through #26, we need to calculate the values for each term using the given information and convert the percentages to fractions.
#21: The arithmetic mean is given as a percentage. Convert it to a fraction by dividing by 100. Therefore, #21 = 2.33% = 0.0233.
#22: Multiply the starting price ($53.07) by the compound factor (1 + arithmetic mean)^3. Substitute the value of #21 into the calculation. Therefore, #22 = $53.07 x (1 + 0.0233)^3 = $56.4842.
#23: The geometric mean is given as a percentage. Convert it to a fraction by dividing by 100. Therefore, #23 = 1.85% = 0.0185.
#24: Multiply the starting price ($53.07) by the compound factor (1 + geometric mean)^3. Substitute the value of #23 into the calculation. Therefore, #24 = $53.07 x (1 + 0.0185)^3 = $56.4148.
#25: The continuous mean is given as a percentage. Convert it to a fraction by dividing by 100. Therefore, #25 = 3.64% = 0.0364.
#26: Multiply the starting price ($53.07) by the continuous factor e^(continuous mean x 3). Substitute the value of #25 into the calculation. Therefore, #26 = $53.07 x e^(0.0364 x 3) = $57.4397.
Hence, the values for numbers #21 through #26 are as calculated above.
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8. Textbook Q1.35, p30: Do we really need financial
accounting theory if all we
are interested in do
Yes, we need financial accounting theory even if we are only interested in 'doing'.
Financial accounting theory provides a conceptual framework for financial accounting. It is an important tool that helps to understand the concepts and principles that guide financial accounting practice.Even if a person is only interested in doing financial accounting, they still need to have an understanding of the theory underlying the practice to make informed decisions.
Financial accounting theory explains the underlying assumptions and concepts that govern the practice of financial accounting. It provides a framework for understanding the principles of financial accounting, which can then be applied to real-world situations.
For example, if an individual is only interested in doing financial accounting for a small business, they still need to have an understanding of the accounting principles and concepts that guide the practice.
This knowledge will enable them to make informed decisions when recording financial transactions and preparing financial statements. Without an understanding of financial accounting theory, the person may make errors or misinterpretations that could lead to incorrect financial statements.
Financial accounting theory is essential even if one is only interested in 'doing' financial accounting. It provides the underlying principles and concepts that guide the practice of financial accounting, enabling individuals to make informed decisions when recording financial transactions and preparing financial statements.
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A gla in the form of a right circular cylinder i half full of water. It bae radiu i 3cm and height i 8cm. The volume of water i:
The volume of filled water in half of a right circular cylinder glass is 113.04 cm³.
What Is a Right Circular Cylinder?A right cylinder is a cylinder with two congruent parallel circular bases, and each line segment that is part of a side or curved surface is perpendicular to the bases. The volume of a right cylinder is the number of unit cubes that fit inside it. The unit of volume is "cube". Expressed in m³, cm³, km³, etc., depending on the unit specified. Let's see how to find the formula for the volume of a right cylinder.
V = base area × height = πr²× h = πr²h
where, π is special constant, π = 3.14 or 22/7
We have, a glass in form of right circular cylinder
Base radius of cylinder, R = 3 cm
Height of cylinder, h = 8 cm
cylinder is half of full water i.e volume of water is half of volume of right circular cylinder.
Let us assume "V" be volume of right circular cylinder. We have to calculate the volume of water. For this, V = π R²h/2
=> V = π(3)²×(8)/2
=> V = 72π/2 = 36× 3.14
=> V = 113.04 cm³
Hence, required volume is 113.04 cm³.
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