A balance uses small metal weights of known mass to determine the mass of a substance. Where would a balance NOT function correctly?
A balance scale.
A.
in a vacuum on Earth
B.
on the Moon's surface
C.
on the Earth's highest mountain
D.
in a zero-gravity environment

Answer:

Transational Motion

Explanation:

A force of 1.5 x 10⁴ N must be applied to the small piston to support the weight of the car.

The hydraulic lift works on the principle of Pascal's law, which states that pressure applied to an enclosed fluid is transmitted uniformly throughout the fluid and acts with equal force on all surfaces of the container. Therefore, the pressure applied to the small piston will be transmitted to the large piston and support the weight of the car.

The pressure applied to the fluid is given by the formula:

pressure = force / area

Since the area of both pistons is the same, the pressure applied to the fluid will be the same on both pistons. Therefore, we can write:

pressure = force on small piston / area of small piston = force on large piston / area of large piston

We know the area of both pistons, so we can rearrange this equation to solve for the force on the small piston:

force on small piston = pressure x area of small piston

The force on the large piston is equal to the weight of the car, which is 1.5 x 10⁴ N. The pressure applied to the fluid is the same on both pistons, so we just need to calculate the pressure using the formula:

pressure = force on large piston / area of large piston

pressure = (1.5 x 10⁴ N) / (0.50 m²) = 3.0 x 10⁴Pa

Now we can calculate the force on the small piston using the formula we derived earlier:

force on small piston = pressure x area of small piston

force on small piston = (3.0 x 10⁴Pa) x (0.50 m²) = 1.5 x 10⁴ N

Therefore, a force of 1.5 x 10⁴ N must be applied to the small piston to support the weight of the car.

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Elite runners follow a rigid training schedule that gradually increases their capacity for the longer distances. Additionally, they run regularly (often 5 to 6 times per week). On the other hand, the typical runner might run significantly more when the weather is favorable or when they have more time.

Running speed is influenced by stride cadence and stride length. The number of steps made in a second is referred to as the stride cadence, and the distance covered by each step is referred to as the stride length.

Therefore, running speed can be mathematically described using the product of these variables.

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No, the potential of a non-uniformly charged sphere cannot be the same as that of a point charge.

The potential of a charged sphere depends on the distribution of charge throughout the sphere, whereas the potential of a point charge depends only on its own charge and the distance from it. A non-uniformly charged sphere has different charges distributed at different distances from a point in space, so the potential at that point will vary depending on the distribution.

In contrast, a point charge has all its charge concentrated at a single point, so the potential at any given distance will be the same regardless of the distribution of charge in the surrounding space. Therefore, the potential of a non-uniformly charged sphere cannot be the same as that of a point charge.

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Answer:

a)  λ = 555.5 m,  λ = 187.5 nm

Explanation:

The velocity of a wave is given by the relation

           c = λ f

           λ = c /f

a) length of the radii AM

            λ = 3 10⁸/540 10⁻⁷

            λ= 5.555 102 m

            λ = 555.5 m

             f = 1600 kHz

            λ = 3 108/1600 103

             λ = 1.875 102 m

            lam  = 187.5 nm

b) light = 760 Thz = 760 10-12 Hz

         λ=  c/f

            λ = 3 108/760 10-12

            λ = 3.947 10-9

           λ= 30000 Thz

           λ= c/f

      λ = 3 10⁸/ 30000 10-12

       λ = 1  m

The average blood pressure in the brain will be higher than the average blood pressure in the feet. the average blood pressure in the brain will be lower than the average blood pressure in the feet.

When the elevator accelerates upward at \(10 ms^{-2}\), the blood pressure in the brain and feet of a person changes.

Similarly, when the elevator accelerates downward with the same acceleration, the blood pressure in the brain and feet of a person changes.

Let's discuss them one by one:Blood Pressure When Elevator Accelerates Upward at \(10 ms^{-2}\)

When the elevator accelerates upward at \(10 ms^{-2}\),  the blood pressure in the brain of a person increases, while the blood pressure in the feet of a person decreases.

This happens due to the gravitational force acting on the body.

Since the gravitational force on the head is greater than the gravitational force on the feet, the blood pressure in the brain increases while the blood pressure in the feet decreases.

Therefore, the average blood pressure in the brain will be higher than the average blood pressure in the feet.

Blood Pressure When Elevator Accelerates Downward at  \(10 ms^{-2}\) When the elevator accelerates downward at \(10 ms^{-2}\), the blood pressure in the brain of a person decreases, while the blood pressure in the feet of a person increases.

This also happens due to the gravitational force acting on the body. Since the gravitational force on the head is less than the gravitational force on the feet, the blood pressure in the brain decreases while the blood pressure in the feet increases.

Therefore, the average blood pressure in the brain will be lower than the average blood pressure in the feet.

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Answer:

Trawler B should set off on a course of 120°.

Trawler A is traveling at 20km/h on a bearing of 60°. This means that Trawler A is traveling north-east. Trawler B is traveling at 25km/h. In order to intercept Trawler A, Trawler B must travel on a bearing of 120°. This means that Trawler B must travel south-east.

The two trawlers will eventually meet at a point that is 40km east of Trawler A's starting position and 20km north of Trawler B's starting position.

Answer:

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

force = 50 × 0.85

We have the final answer as

Hope this helps you

Answer:

17.3 m

Explanation:

Given that,

Mass of a hammer is 0.58 kg

Velocity with which the hammer slides is 6.69 m/s at constant speed.

The roof makes an angle of 18 ◦ with the horizontal, and its lowest point is 18.2 m from the ground. We need to find the horizontal distance traveled by the hammer between the time is leaves the roof of the house and the time it hits the ground. Firstly, we will find the time taken by the hammer when it reaches ground in vertical direction.

\(y=y_0+v_ot +\dfrac{1}{2}gt^2\)

Putting all the values,

\(0=18.2+6.69t-\dfrac{1}{2}\times 9.8t^2\\\\-4.9t^2+6.69t+18.2=0\\\\t=\dfrac{-6.69+\sqrt{6.69^{2}-4\cdot-4.9\cdot18.2}}{2\cdot-4.9}, \dfrac{-6.69-\sqrt{6.69^{2}-4\cdot-4.9\cdot18.2}}{2\cdot-4.9}\\\\t=-1.36\ s\ \text{and}\ t=2.72\ s\)

Neglecting negative value,

To find horizontal distance, multiply 2.72 s with the horizontal component of velocity.

\(d=2.72\times 6.69\times \cos(18)\\\\d=17.3\ m\)

Answer:

two identical

Explanation:

The quantity of heat energy that must be transferred to 2.25 kg of brass to raise its temperature from 20 °C to 240 °C is 195030 J

First, we shall list out the given parameters from the question. This is shown below:

The quantity of heat energy that must be transferred can be obtained as follow:

Q = MCΔT

= 2.25 × 394 × 220

= 195030 J

Thus, we can conclude quantity of heat energy that must be transferred is 195030 J

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Hello!

\(\large\boxed{F = 100N}\)

Use the equation F = m · a (Newton's Second Law) to solve. Substitute in the given values:

F = 5 · 20

F = 100N

Answer:

λ = 5.773 x 10⁻⁷ m = 577.3 nm

Explanation:

In order to solve this problem we will use the grating equation:

mλ = d Sin θ

where,

m = order = 3

λ = wavelength of light = ?

d = slit separation = 2 μm = 2 x 10⁻⁶ m

θ = angle = 60°

Therefore,

(3)λ = (2 x 10⁻⁶ m)Sin 60°

λ = 1.732 x 10⁻⁶ m/3

λ = 5.773 x 10⁻⁷ m = 577.3 nm

The purpose of the lab is to learn how to classify minerals and rocks based on their physical and chemical properties.

Here is an example of a detailed report:

The lab aims to teach students the techniques and criteria used to identify minerals and rocks, such as their hardness, color, luster, cleavage, and crystal structure. By studying the physical and chemical properties of minerals and rocks, students can classify them into different groups and gain a better understanding of their composition and origin.

Summarize the procedure.

In the lab, students first learned how to identify minerals based on their physical properties, such as hardness, streak, color, luster, and cleavage. They then moved on to identifying rocks based on their mineral composition and texture. The lab also included the use of specialized tools, such as a hand lens, streak plate, and hardness scale, to aid in mineral identification. Students were required to observe and record their findings, and to use their observations to classify the minerals and rocks they encountered.

Section II: Observations and Conclusions

The lab included the use of various charts and tables to aid in mineral and rock identification, such as the Mohs hardness scale and the rock identification chart. Students also observed different types of minerals and rocks, such as quartz, feldspar, granite, and basalt, and learned how to distinguish between them based on their physical and chemical properties.

In conclusion, the lab provided a hands-on approach to learning about mineral and rock classification. By using the techniques and criteria discussed in class, students were able to identify and classify different minerals and rocks. The lab also provided an opportunity for students to practice their observation and record-keeping skills. To improve the investigation, it would be helpful to include more samples of minerals and rocks, and to provide additional information on their geological origins.

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The skater's final angular velocity is approximately 9.86 rad/s.

The skater's final angular velocity can be calculated using the principle of conservation of angular momentum. The equation for angular momentum is given by:

L = Iω

where L is the angular momentum, I is the moment of inertia, and ω is the angular velocity.

Initially, the skater has an angular momentum of:

L_initial = I_initial * ω_initial

Substituting the given values:

L_initial = 2.12 kg m² * 3.25 rad/s

The skater's final angular momentum remains the same, as angular momentum is conserved:

L_final = L_initial

The final moment of inertia is given as 0.699 kg m². Therefore, the final angular velocity can be calculated as:

L_final = I_final * ω_final

0.699 kg m² * ω_final = 2.12 kg m² * 3.25 rad/s

Solving for ω_final:

ω_final = (2.12 kg m² * 3.25 rad/s) / 0.699 kg m²

Hence, the skater's final angular velocity is approximately 9.86 rad/s.

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ANSWER:

The Moon's gravity is less than Earth's.

STEP-BY-STEP EXPLANATION:

When you jump, you fall back to the ground. Apples or leaves also fall: we are all attracted to the Earth. It is the terrestrial attraction due to the force of gravity.

The force of gravity also exists on the Moon. But since the Moon is smaller than the Earth, the attraction felt on the Moon is smaller than the Earth's attraction.

As the gravity is less, you can do things such as the one shown in the image.

As the force of attraction is less, the weight is less on the Moon, which can cause things that would be impossible on Earth.

The volume (in gallon) of water that have the same mass as the bar of gold is 0.153 gallon

We'll begin by obtaining the mass of the gold bar. This is given below:

Density = mass / volume

Cross multiply

Mass = Density × Volume

Mass of gold bar = 19300 × 0.00003

Mass of gold bar = 0.579 Kg

Finally, we shall determine the volume of water having the same mass as 0.579 Kg of the gold bar. Details below:

Volume = mass / density

Volume of water = 0.579 / 1000

Volume of water = 0.000579 m³

Multiply by 264.172 to express in gallon

Volume of water = 0.000579 × 264.172

Volume of water = 0.153 gallon

Thus, we can conclude that the volume of the water is 0.153 gallon

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Answer: They will repel each other.

Explanation:

Two inflated balloons when rubbed with woolen cloth will lead to repeal each other because of the similar charges on both the balloons.

Rubbing both the balloons together by the woolen cloth will introduce negative charge in the balloons.

As, we know that the same charges repeal each other both of the balloons with be apart from each other.

This is due to the static electricity, the negatively charged particles jump to the positive one. When balloons are rubbed they become negatively charged.

Answer:

Sample Response: Sonia observed that the two balloons repelled each other. This is because both balloons acquired the same charge when she rubbed them with the piece of wool, and like charges repel each other.

Explanation:

Did it on Egde 2020

After the impact, the two players are moving side by side at a speed of roughly 4.12 m/s.

Momentum is never created or destroyed inside a problem domain, according to the principle of momentum conservation. Momentum is only changed by the action of forces as they are described by Newton's equations of motion.

\(p1 = m1 * v1 + m2 * v2\)

\(p1 = 165 kg * 0 m/s + 178 kg * 8 m/s = 1424 kg*m/s\)

\(p2 = (m1 + m2) * v\)

Substituting the values, we get:

\(p2 = (165 kg + 178 kg) * v = 343 kg * v\)

Since the total momentum is conserved, we can equate p1 and p2:

p1 = p2

\(165 kg * 0 m/s + 178 kg * 8 m/s = 343 kg * v\)

\(v = (165 kg * 0 m/s + 178 kg * 8 m/s) / 343 kg ≈ 4.12 m/s\)

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The mass of a substance is not directly related to latent heat. Instead, latent heat is a parameter that describes the amount of energy required or released during a phase shift of a substance.

Latent heat can be thought of as hidden energy that is supplied or extracted to change the state of a substance without changing its temperature or pressure.

Latent heat is energy released or absorbed, by a body or a thermodynamic system, during a constant-temperature process—typically a first-order phase transition.

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Answer:

a.5.85 s b i. 15.7 m/s ii. 21.1m/s c. 61.62 m

Explanation:

(a) when b will overtake a,

Using s = ut + 1/2at² we express the distance moved by each automobile.

Since both automobiles start at rest, their initial speed, u = 0 m/s, a = acceleration of automobile and t = time of travel or overtaking

So s = 0 × t + 1/2at²

s = 0 + 1/2at²

s = 1/2at²

Let time, t be the time the automobile b start, and its acceleration a = 3.6 m/s²

So, s = 1/2 × 3.6 m/s² × t² = 1.8t²

Since automobile a starts 2 seconds earlier, its time of travel is (t + 2) s. Since its acceleration, a = 2 m/s²,

s = 1/2 × 2 m/s² × (t + 2)²

s = (t + 2)²

Since both distances are equal at overtaking

(t + 2)² = 1.8t²

t² + 4t + 4 = 1.8t²

1.8t²- t² - 4t - 4 = 0

0.8t² - 4t - 4 = 0

dividing through by 0.8, we have

0.8t²/0.8 - 4t/0.8 - 4/0.8 = 0

t² - 5t - 5 = 0

Using the quadratic formula to find t,

\(t = \frac{-(-5) +/-\sqrt{(-5)^{2} - 4 X 1 X (-5)} )}{2 X 1} \\t = \frac{5 +/-\sqrt{25 + 20} )}{2} \\t = \frac{5 +/-\sqrt{45} )}{2} \\t = \frac{5 +\sqrt{45} )}{2} or \frac{5 -\sqrt{45} )}{2}\\t = \frac{5 + 6.708 )}{2} or \frac{5 - 6.708)}{2}\\t = \frac{11.708 )}{2} or \frac{-1.708}{2}\\t = 5.854 sor -0.854 s\)

t ≅ 5.85 or -0.85

We take the positive answer since t cannot be negative.

So, t = 5.85 s

So, b will overtake a 5.85 s later.

(b) the speed of each automobile at that time,

Using v = u + at for each automobile, where u =initial speed of automobile = 0 m/s (since they both start from rest), a = acceleration of automobile and t = time of travel of automobile

i. Speed of automobile a

For automobile a, its time of travel is (t + 2) s = 5.85 s + 2 s = 7.85 s and its acceleration is 2 m/s²

So, v = u + at

= 0 m/s + 2 m/s² × 7.85 s

= 0 m/s + 15.7 m/s

= 15.7 m/s

ii. Speed of automobile b

For automobile a, its time of travel is t  s = 5.85 s and its acceleration is 3.6 m/s²

So, v = u + at

= 0 m/s + 3.6 m/s² × 5.85 s

= 0 m/s + 15.7 m/s

= 21.06 m/s

≅ 21.1 m/s

c) the location where b overtakes a relative to the traffic signal. -truck

The location where b overtakes a relative to the traffic signal is the distance each automobile moves before overtaking. In section (a), we foundthat distance s = 1/2at² = (t + 2)² = 1.8t²

Using s = (t + 2)²

= (5.85 + 2)²

= 7.85²

= 61.6225 m

≅ 61.62 m

Answer:

A

Explanation:

The angular momentum of a system of particles around a point in a fixed inertial reference frame is conserved if there is no net external torque around that point:

d

→

L

d

t

=

0

or

→

L

=

→

l

1

+

→

l

2

+

⋯

+

→

l

N

=

constant

.

Note that the total angular momentum

→

L

is conserved. Any of the individual angular momenta can change as long as their sum remains constant. This law is analogous to linear momentum being conserved when the external force on a system is zero.

The maximum speed that the small-mass object attains when it leaves the trebuchet horizontally is approximately 28.3 m/s.

To find the maximum speed that the small-mass object attains when it leaves the trebuchet horizontally, we can apply the principle of conservation of mechanical energy.

Initially, the trebuchet is at rest, so its total mechanical energy is zero. As the small-mass object leaves the trebuchet horizontally, it gains kinetic energy. At this point, all of the potential energy of the system is converted into kinetic energy.

The potential energy of the system can be calculated as the sum of the gravitational potential energies of the two masses:

PE = m1 * g * h1 + m2 * g * h2

Since the trebuchet is released from rest in a horizontal orientation, the initial height h1 is zero. The height h2 can be calculated as the perpendicular distance between the pivot point and the center of mass of the larger mass m2:

h2 = 13.0 cm = 0.13 m

Therefore, the potential energy simplifies to:

PE = m2 * g * h2

The kinetic energy of the small-mass object can be calculated as:

KE = (1/2) * m1 * v^2

where v is the maximum speed of the small-mass object.

Since the total mechanical energy is conserved, we have:

PE = KE

m2 * g * h2 = (1/2) * m1 * v^2

Plugging in the given values, such as g = 9.8 m/s^2, m1 = 0.115 kg, m2 = 68.5 kg, and h2 = 0.13 m, we can solve for v:

(68.5 kg * 9.8 m/s^2 * 0.13 m) = (1/2) * 0.115 kg * v^2

Solving for v, we find:

\(v^2 = (68.5 kg * 9.8 m/s^2 * 0.13 m) / (0.115 kg)\)

\(v^2 = 800\)

v ≈ 28.3 m/s

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Answer:

i think its D

Explanation:

Answer:

The highness or lowness of a sound is perceived as pitch. Pitch is a perceptual property of sound that allows us to distinguish between sounds that have the same loudness and duration, but differ in their frequency content. The pitch of a sound is determined by the frequency of the sound wave, with higher frequencies producing higher pitches and lower frequencies producing lower pitches. The pitch is what makes a sound distinguishable and is important in music, language, and communication.

Answer:

the scientific study of natural forces such as light, sound, heat, electricity, pressure, etc.

Explanation:

mark as brainliest

A block of wood resting on a steel desk experiences a force of friction that opposes the applied force. The force of friction depends on the coefficients of friction and the normal force acting on the block.

At time t=0, the force applied on the block is 15.8 N. Since the block is at rest, the frictional force must be equal and opposite to the applied force to maintain static equilibrium. Therefore, the force of friction acting on the block at t=0 is:

Ffriction = Fapplied = 15.8 N

Now, when the applied force is greater than the maximum static frictional force (i.e., Fs > μsN), the block will start to move, and the frictional force acting on the block will be the kinetic frictional force. The kinetic frictional force is given by:

Ffriction = μkN

where μk is the coefficient of kinetic friction and N is the normal force acting on the block.

The normal force N acting on the block can be calculated using Newton's second law, which states that the net force acting on an object is equal to its mass times its acceleration:

ΣF = ma

Since the block is moving horizontally, its acceleration in the vertical direction is zero, and the normal force N is equal to the weight of the block:

N = mg

where m is the mass of the block and g is the acceleration due to gravity.

Substituting the given values, we get:

N = 5.760 kg × 9.81 m/s^2 = 56.47 N

The maximum static frictional force Fs can be calculated using:

Fs = μsN

Substituting the given values, we get:

Fs = 0.455 × 56.47 N = 25.68 N

Since the applied force is greater than the maximum static frictional force, the block will start to move, and the frictional force acting on the block will be the kinetic frictional force. The kinetic frictional force can be calculated using:

Ffriction = μkN

Substituting the given values, we get:

Ffriction = 0.205 × 56.47 N = 11.56 N

Therefore, the force of friction acting on the block at t=0 is 15.8 N, and the force of friction acting on the block when it starts to move is 11.56 N.

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There is not enough information to determine the work done. Option iv

Let us note that we say that there is work done when the force that has been applied moves a distance in the direction of the force. In this case, we have been told that there is the combination of the works that is done by the object.

Now, we also have to note that we do not have other information to determine the work done such as the magnetic feild and the mass of the electron. All these are lacking in the question.

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