The amount of force the ball applies to the bat is the very same.
What does magnitude of force mean?
The numerical measure of power of force is called its magnitude.
For example, let us say that in the direction of the east, force is 10 N. "towards east" indicates direction, while "10" indicates the magnitude of force. Magnitude is, in essence, the "amount" or "value" of any physical quantity.
How is magnitude calculated?
When given a location vector v=a, b, magnitude is calculated using the equivalent to the angle made with either the y-axis or x-axis.
So, therefore, the amount of force the ball applies to the bat is the very same.
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A toy car with a mass of 8 kg and velocity of 5 m/s to the right collides with a 5.28 kg car moving to the left with a velocity of 1.65 m/s. After the collision, the 8 kg car continues forward with a velocity of 0.5 m/s. What is the new velocity of the 5.28 kg car after the collision?
Afootball is kicked at avelocity of 15 m/s at angle of 25 degree to the horizontal. What is the total flight time
Answer:
the total flight time is 1.29 s
Explanation:
The computation of the total flight time is given below:
The initial velocity is 15 m/s = v
And, the angle from horizontal is \(\theta = 25\ degrees\)
Now the total time is
\(t = \frac{2\times v\times \sin \theta }{g} \\\\= \frac{2\times 15\times sin 25^{\circ}}{9.8} \\\\= 1.29 s\)
Hence, the total flight time is 1.29 s
what is necessary for a convection cell to be set up in a fluid? responses thermal gradient thermal gradient thermal gradient and changes in density thermal gradient and changes in density changes in density changes in density
Thermal gradient and adjustments in density.
The subject of fluid dynamics, a convection cellular is a phenomenon that occurs while density variations exist inside a body of liquid or fuel. these density variations bring about rising and/or falling currents, which might be the important thing characteristics of a convection cellular.
Convection cells are regions within a fluid in which heat material is rising inside the center and cold cloth is sinking. in the ecosystem, those cells can occur at small scales like a sea breeze at the seaside or a great deal large scales.
Convection cells take place all around us. some examples may be found in boiling water, within the ocean, in the clouds, throughout Earth's environment, and at the surface of the solar.
Round Earth there are three main convection cells called Hadley, Ferrel, and Polar stream cells.
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help me pls its for my science class i need to show my work
Answer:
P = 5880 J
Explanation:
Given that,
The mass of the block, m = 30 kg
The block is sitting at a height of 20 m.
The block will have gravitational potential energy. The formula for gravitational potential energy is given by :
\(P=mgh\\\\=30\times 9.8\times 20\\\\=5880\ J\)
So, the required potential energy is equal to 5880 J.
Daisy is going to ride a skateboard down a ramp. The combined mass of Daisy and the skateboard is 19.8 kg. Daisy is initially at rest and rides down the ramp. Daisy starts at a height of 1.21 m. What was Daisy's speed at the bottom of the ramp
The combined mass of Daisy and the skateboard is 19.8 kg. Daisy is initially at rest and rides down the ramp. Daisy starts at a height of 1.21 m. Daisy's speed at the bottom of the ramp was approximately 5.9 m/s.
To find Daisy's speed at the bottom of the ramp, we can use the principle of conservation of energy. At the top of the ramp, Daisy has potential energy, given by the formula PE = mgh, where m is the combined mass of Daisy and the skateboard, g is the acceleration due to gravity, and h is the height. The potential energy at the top of the ramp is then PE = (19.8 kg)(9.8 m/s^2)(1.21 m) = 230.6 J.
At the bottom of the ramp, Daisy's potential energy is zero, as it has been converted to kinetic energy. The kinetic energy is given by the formula KE = (1/2)mv^2, where m is the combined mass of Daisy and the skateboard, and v is the speed at the bottom of the ramp. We can equate the initial potential energy to the final kinetic energy:
PE = KE
mgh = (1/2)mv^2
Simplifying the equation, we have:
19.8 kg * 9.8 m/s^2 * 1.21 m = (1/2) * 19.8 kg * v^2
Solving for v, we get:
v^2 = 19.8 kg * 9.8 m/s^2 * 1.21 m * 2 / 19.8 kg
v^2 = 240.84 m^2/s^2
v ≈ √240.84 m^2/s^2
v ≈ 15.51 m/s
Therefore, Daisy's speed at the bottom of the ramp is approximately 5.9 m/s.
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1
3
Which describes how to calculate density?
O mass divided by volume
O volume divided by mass
O mass added to volume
volume subtracted from mass
return
Answer:
the answer is mass divided by volume
Answer:
Mass divided by volume
Explanation:
Edgen answer 2020-2021
the tidal volume and breaths per minute increased with increased metabolism because
Breaths per minute increase with increased metabolism to meet the higher oxygen demand.
How does increased metabolism affect tidal volume and breaths per minute?
When increased metabolism, the body requires more energy to sustain its physiological processes. This increased energy demand is typically met by an increase in oxygen consumption. To accommodate this increased need for oxygen, the body adjusts its respiratory parameters, including tidal volume and breaths per minute.
Tidal volume refers to the amount of air that is inhaled or exhaled during a normal breath. As metabolism increases, the body responds by increasing the tidal volume. This means that with each breath, a larger volume of air is drawn into the lungs, allowing for a greater exchange of oxygen and carbon dioxide.
Additionally, the body also increases the respiratory rate, which is measured in breaths per minute. By increasing the number of breaths per minute, the body can deliver more oxygen to the tissues and remove carbon dioxide more efficiently. This ensures an adequate supply of oxygen for the increased metabolic demands and facilitates the removal of metabolic waste products.
Overall, the increase in tidal volume and breaths per minute with increased metabolism is a physiological response aimed at maintaining oxygen delivery and facilitating gas exchange to support the body's heightened energy requirements.
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The tidal volume and breaths per minute increase with increased metabolism due to the body's need for increased oxygen intake and carbon dioxide removal.
Metabolism is the process by which the body converts food into energy. During increased metabolism, the body requires more energy, which means an increased demand for oxygen. The body responds to this increased demand by increasing the tidal volume and breaths per minute.
Tidal volume refers to the amount of air that is inhaled and exhaled during normal breathing, while breaths per minute refers to the number of breaths taken in a minute.
Increasing the tidal volume and breaths per minute allows more oxygen to be taken into the lungs and transported to the body's tissues. The increased respiratory rate also helps to remove the excess carbon dioxide produced by the increased metabolism.
Therefore, the increased tidal volume and breaths per minute help to meet the body's increased demand for oxygen and removal of carbon dioxide during increased metabolic activity.
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What potential energy is acquired by a hammer with a mass of 0.75 kg when raised 0.35 m?
Answer:
0.75kg into gram = 0.75 * 1000 = 750g
potential energy = mgh
potential energy = 750 * 10 * 0.35
potential energy = 2625 joules
The Si unit of potential difference is a) volt b) JA⁻¹s⁻¹ c)JC⁻¹ d) All the above
Answer:
a) Volt
Explanation:
The standard metric unit on electric potential difference is the volt.
answer
all of the above
explanation
as we know that the si unit of potential difference is volt
which is equal to j/c and j/c is equal to j/a.s so the correct answer is all of the above
there are two types of regular options (calls and puts). how many types of barrier options are there?
There are several types of barrier options, including up-and-out, up-and-in, down-and-out, and down-and-in options. These options add an additional barrier condition that must be met for the option to become active or to be knocked out. The exact number of barrier option types may vary depending on specific variations and combinations. These barrier options provide additional flexibility
Barrier options are a type of exotic option that have a specified barrier level. The barrier level acts as a trigger, determining whether the option is activated or nullified. Barrier options can have different types of barrier conditions, which can be set above or below the underlying asset's price.
The four common types of barrier options are:
Up-and-out option: The option is knocked out if the price of the underlying asset moves above a predetermined barrier level.
Up-and-in option: The option becomes active only if the price of the underlying asset moves above a predetermined barrier level.
Down-and-out option: The option is knocked out if the price of the underlying asset moves below a predetermined barrier level.
Down-and-in option: The option becomes active only if the price of the underlying asset moves below a predetermined barrier level.
These barrier options provide additional flexibility and complexity compared to regular options, as their payoff and activation depend on whether the barrier levels are breached or not.
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Physics WebAssign Project. Work would be awesome if you could send that too!
a). Fe*cos32 = 799 N.
Fe = 799 / cos32 = 948 N. = Force exerted.
b). W = Fe * d = 948 * 22 = 20,856 J.
c). P = W / t = 20,656 / 8 s. = 2607 J/s
= 2607 Watts = 2.607 KW.
What is the formula for horizontal force?A horizontal force is one that moves in a path perpendicular to the sky. The magnitude and direction of the horizontal forces are both equivalent. The horizontal net force is zero because they are symmetrical. The absence of horizontal motion is indicated by this. Equal in magnitude and moving in the opposing direction are the vertical forces.
The normal force on a horizontal surface is an illustration of any item maintained on a horizontal surface, such as a flat table, a stand, or just the earth. Keeping literature on a bookshelf or computers on a desk at work are two examples. Gravitational force is measured in g.
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5. Why did people change the Bronx River in the past?
when a glacier came through the Bronx approximately 240,000 years ago it blocked part of the original path of the Bronx river and subsequently reshaped and modified the path of the river over the past 200 years the rivers course has been altered dramatically by human impact and industry.
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A vector has initial point at (3, –5) and terminal point at (–2, 3). what are the characteristics of this vector? the magnitude is startroot 13 endroot, and the direction angle is about 58°. the magnitude is startroot 13 endroot, and the direction angle is about 122°. the magnitude is startroot 89 endroot, and the direction angle is about 58°. the magnitude is startroot 89 endroot, and the direction angle is about 122°.
The magnitude of this vector is 9.43 and the direction angle of the vector is 58°.
The initial point and the terminal point of the vectors are (3 - 5) and (-2, 3) respectively.
The characteristics of the vector mainly includes the magnitude and the direction of the angle of the vector.
The magnitude of this vector will be given by,
M = √((-2-3)²+(3+5)²)
M = √(25+64)
M = √89
M = 9.43
The direction angle of this vector with the x-axis will be given by,
Tan A = (8/-5)
Tan A = -1.6
A = 58°.
The direction angle of this vector is 58 degree.
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Answer: D. The magnitude is StartRoot 89 EndRoot, and the direction angle is about 122°.
Explanation:
D
Cuestion 2
1 pts
A hotwheels car is rolled from 0.72 meters to the 1.51 meter mark. What is the displacement of the toy car?
(do not enter units into your answer in canvas)
Answer:
it is d]
Explanation:
The displacement of the toy car will be 0.79 meters.
What is displacement?The shortest route between two points is displacement.
It is a vector quantity to be displaced. This suggests that it has a size and a direction, and that it may be thought of as an arrow pointing from one place to another.
Distance is never less than displacement; it must always be more than or equal to it.
Displacement can be zero if the starting and end point are the same.
According to the question, the Hot wheel car rolled from 0.72 meters to the 1.51-meter mark.
So, the displacement of the toy car will be :
⇒1.51-0.72
=0.79
Hence, the total displacement will be 0.79 meters.
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What is the smallest particle of an element that still retains of that element
A.compound
B.molecule
C.atom
D.mixture
Answer:
atom
Explanation:
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What happens when an unstoppable meets an immovable object.
The question "What happens when an unstoppable force meets an immovable object?" is a paradox that cannot be resolved logically.
If an unstoppable force is moving towards an immovable object and collides with it, the force will stop moving. Similarly, if an immovable object is struck by a force, it will not move.
This paradox raises the issue of what happens when two opposing ideas are brought together.
What occurs when an unstoppable force meets an immovable object is a paradox. The question is illogical, and no answer can be given with certainty.
The term "unstoppable force" indicates something that cannot be stopped, while the term "immovable object" refers to something that cannot be moved.
When put together, the two phrases contradict each other.
In this scenario, if an unstoppable force encounters an immovable object, it would imply that the force cannot move forward and the immovable object cannot move or be moved.
Hence, it is a paradox.
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a ball with a horizontal speed of 1.25 m/s rolls off a bench 1.00 m above the floor. you may want to review (page) . part a how long will it take the ball to hit the floor?
The ball to hit the floor time at t = 0.342 seconds.
Will how quickly the ball lands this time on the ground depend on its speed?The speed of the ball has no bearing on how long it takes to strike the ground. The fact that the ball is traveling along the horizontal axis means that it will only reach the end of the table faster.
y = v*t + 0.5*a*t^2
where:
y = vertical distance is = -1 m
v = initial velocity is = 1.25m/s
a = acceleration is= 9.81 m/s^2
t = time
Required: t
so,
y = v*t + 0.5*a*(t^2)
1 = (1.25)*t + 0.5*9.81*(t^2)
0 = -1 + 1.25t + 4.905(t^2)
Applying completing square, we get
t = 0.342 s or - 0.597s
so, we don't have time with negative value Thus, ball to hit the floor is t = 0.342 seconds.
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if we could have turned a receiver toward the heavens in hopes of observing the cosmic microwave radiation four and a half billion years ago, at the time the solar nebula was forming, what would we have found?
In order to observe the cosmic microwave radiation four and a half billion years ago, we would have seen a blackbody curve with the same shape as we see now but with a peak intensity at a wavelength shorter than 1 mm.
blackbody Curves Planck's Law can be used to apply a curve to represent the intensity of blackbody emission over a variety of wavelengths on the light spectrum.
The green region of the spectrum, close to the human eye's maximal sensitivity, has a peak emission per nanometer (of wavelength) at a wavelength of about 500 nm, according to Wien's equation.
In physics, the wavelength is the length over which a periodic wave repeats, or its spatial period.
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The distance a toy car travels over time is shown in the graph.
Motion of a Toy Car
Distance (m)
Time (1)
Which table best shows the average speed of the toy car at different time intervals?
А
Time (s)
Time (5)
Average
Speed (m/s)
1.0
Average
Speed (m/s)
2.0
0-2
0-2
2-4
0.5
2-4
3.0
4-6
0
4-6
3.0
Time (s)
Average
Speed (m/s)
Time (s)
Average
Speed (m/s)
0-2
2.0
1.0
2-4
0.75
2-4
0.75
4-6
0.75
4-6
0
Answer:
a toy car speed is about 2.5 to 3.5 mph
In hydraulic machine, how can you lift heavier load by using small magnitude of force?
Hello, yes it is possible to lift heavier load using small magnitude of force.
How? let's see.
Do you know on which principle does hydraulic machine work? Yes, it's Pascal's Principle. So in order to understand how hydraulic machine will lift heavier weight using small magnitude of force we will have to take a look at Pascal's law.
Pascal's law : It sates that in a closed container filled with fluid when pressure is applied to any point that intensity of pressure transfers in all direction equally.
Now look at diagram,
Consider the left piston as X and Right Piston as Y.
the area of piston X is small (A1) and applied force (F1) is also less and the resultant pressure is P.
\(P = \frac{F_1}{A_1}\)
This same amount of pressure will be exerted at Piston Y having area (A2) and resultant output force (F2)
\(P = \frac{F_2}{A_2}\)
So consider I have 5 N force and I have to lift a heavier rock weighing 50 N. take an example the area of Piston X is 1 m² & area of piston Y is 10 m²
So when I will apply 5 N force on piston X it will exert 50 N force on piston Y.
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What can be said of the size of the event horizon for a 10Msun black hole?
-larger than that of a 1Msun black hole.
-smaller than that of a 1Msun black hole.
-the same size as for a 1Msun black hole (because the escape velocity for both is the speed of light).
The event horizon of a black hole is the boundary beyond which nothing, not even light, can escape its gravitational pull. The size of the event horizon is directly related to the mass of the black hole.
Specifically, the Schwarzschild radius formula can be used to determine the size of the event horizon, which is given by Rs = 2GM/c^2, where Rs is the Schwarzschild radius (event horizon radius), G is the gravitational constant, M is the mass of the black hole, and c is the speed of light. For a 10Msun black hole, the event horizon will be larger than that of a 1Msun black hole. This is because the mass term (M) in the formula directly affects the event horizon size. When comparing a 10Msun black hole to a 1Msun black hole, the 10Msun black hole has 10 times the mass, which will result in a correspondingly larger event horizon. The escape velocity for both black holes is indeed the speed of light, but their event horizons will differ in size due to the variation in mass.
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A material that can be magnetized
A. has magnetic domains.
B. is called ferromagnetic.
C. must contain iron.
D. two of the above
04
Touch-screen phones are made of many different materials.
Figure 3 shows the main materials in a touch-screen phone.
Figure 3
other
15%
iron
20%
plastic
45%
copper
7%
glass
Calculate the percentage by mass of glass in a touch-screen phone. *
1 point
Answer:
Please attach the picture
a water balloon is thrown vertically downwards at a speed of 14 m/s from the top of a tall building. assuming the water balloon does not bang into anything or burst, how fast is it moving 1.8 s after it was thrown?
31.64 m/s with velocity fast is it moving 1.8 s after it was thrown vertically downwards at a speed of 14 m/s from the top of a tall building.
V= u + gt= 14 + 9.8×1.8 = 14 + 17.64 = 31.64 m/s
When a body is travelling in a straight line, its estimated "rate of change of displacement in relation to time" is referred to as its velocity.
Speed is a scalar number since it lacks a direction and the value it receives from the distance-to-time ratio simply indicates its magnitude. It doesn't provide any guidance information. Because it always has a direction, velocity is a vector. As a result, when the displacement to time ratio for linear velocity is determined, it provides both the direction and the magnitude.
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Andy is taking a Dynamic Study Module and answers a question incorrectly. He immediately sees this:
However, he doesn't see the Explanation until he after he has answered several more questions.
Why do Dynamic Study Modules do this?
Dynamic Study Modules delay showing the explanation to give the brain time to engage (or"to give the brain time to store information") in retrieval practice and strengthen its memory of the incorrect answer, which can ultimately enhance long-term retention and learning.
By delaying the explanation, the brain is prompted to engage in retrieval practice, which involves recalling information from memory, thereby strengthening memory traces and facilitating long-term retention. Retrieval practice has been shown to be an effective learning strategy, and Dynamic Study Modules utilize this by providing opportunities for students to practice retrieving information before providing explanations.
This approach encourages active learning and can ultimately enhance students' ability to remember and apply what they've learned.
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A boat travels at 15 m/s in a direction 45° east of north for an hour. The boat then turns and travels at 18 m/s in a direction 5° north of east for an hour. What is the magnitude of the boat’s resultant velocity? Round your answer to the nearest whole number. m/s What is the direction of the boat’s resultant velocity? Round your answer to the nearest whole degree. ° north of east
The first blank is 31m/s
The second blank is 23°
The boat’s resultant velocity is v = 31.0 m/s, and the direction of the boat’s resultant velocity is 23.2 degrees north of east.
What is the distance?Distance is a numerical representation of the distance between two items or locations. Distance refers to a physical length or an approximation based on other physics or common usage considerations.
We'll use east as the positive x-direction and north as the positive y-direction. Then, both velocities must be resolved into their corresponding components:
v(x1) = 15 sin45 = 10.6 m/s
v(y1) = 15 cos45 = 10.6 m/s
v(x2) = 18 cos5 = 17.9 m/s
v(y2) = 18 sin5 = 1.6 m/s
The components of the resultant velocity:
v(x) = v(x1) + v(x2) = 10.6 + 17.9 = 28.5 m/s
v(y) = v(y1) + v(y2) = 10.6 + 1.6 = 12.2 m/s
The magnitude of the velocity:
v = √((28.5)² + (12.2)²
v = 31.0 m/s
The direction:
Φ = tan⁻¹(12.2/28.5)
Φ = 23.2 degrees north of east.
Thus, the boat’s resultant velocity is v = 31.0 m/s, and the direction of the boat’s resultant velocity is 23.2 degrees north of east.
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An athlete spins in a circle and throws a 1.6-kg discus. The radius of the discus's path is 1.0 m, and he releases it with an angular speed of 15.0 rad/s. The athlete spins for a total of 1.2 s before releasing the discus.
– What is the tangential speed of the discus at release?
– What is the centripetal acceleration of the discus?
– What is the centripetal force on the discus?
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(a) The tangential speed of the discus at the release is 15 m/s.
(b) The centripetal acceleration of the discus is 225 m/s².
(c) The centripetal force on the discus is 360 N.
The given parameters;
mass of the discus, m = 1.6 kgradius of the path, r = 1 mangular speed, ω = 15 rad/stime of motion, t = 1.2 sThe tangential speed of the discus at the release is calculated as follows;
\(v = \omega r\\\\v = 15 \ rad/s \ \times 1 \ m\\\\v = 15 \ m/s\)
The centripetal acceleration of the discus is calculated as follows;
\(a_c = \frac{v^2}{r} \\\\a_c = \frac{15^2}{1} \\\\a _c = 225 \ m/s^2\)
The centripetal force on the discus is calculated as follows;
\(F_c = ma_c\\\\F_c = 1.6 \times 225\\\\F_c = 360 \ N\)
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secondary (s) waves of an earthquake can travel through all areas of the earth except the
Secondary (S) waves of an earthquake cannot travel through the Earth's outer core.
S-waves, also known as shear or transverse waves, are a type of seismic wave that move by shearing or shaking particles at right angles to the direction of wave propagation. Unlike primary (P) waves, which can travel through all types of materials, S-waves can only travel through solid materials.
The Earth's outer core is primarily composed of liquid iron and nickel, preventing S-waves from passing through it. As a result, there is an S-wave shadow zone on the opposite side of the Earth from the earthquake's epicenter where no S-waves are detected.
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A large solar panel on a spacecraft in Earth orbit produces 2.5 of power when the panel is turned toward the sun.
Main answer: 27 W
Supporting answer: Gravitational force
The attractive force exerted on a body by another body, as a result of their masses and the distance between them is called as gravitational force.
In physics, power is the amount of energy transferred or converted per unit time. Thus, in the medium of gravity the satellites power due to their force can be resisted by the power of the sun.
We have the relationship between power, energy and gravity as:
\(p=\frac{f_{g} d}{t}\) where we have \(f_{g}\) to be the force of gravitation and d is the distance between the planets and t tis the time of revolution/rotation respectively.
Here, in this problem we have P=2.5kW from earth to sun and we need to find the power it is producing when it is producing from the Saturn.
We use the relation,
\(P_{2} =\frac{P_{1} }{n_{1} ^{2} }\)
\(=\frac{2.5*10^{3} }{9.5^{2} }\\ =0.027*10^{3} \\=27W\)
Therefore, the power Saturn can produce is 27W when it is 9.5 times as farther as the sun.
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how long does it take a car to come to a complete stop if it is going 30 m/s and can accelerate at a rate of -6 m/s²?
Answer: t=10s
Explanation:
v=u+at
⟹0=30+(−3)×t
⟹0=30−3t
⟹3t=30
⟹t=303
⟹t=10s.