A ball is gently dropped from a height of 20 m. If its velocity Increases uniformly at the rate of 10 m s2, with what velocity will it strike the ground? After what time will it strike the ground?​

The force on the bat is also 18,436 newtons. This is because the bat and the ball experience the same force but in opposite directions. When the bat exerts a force on the ball, the ball exerts an equal and opposite force on the bat, according to Newton's third law.

Newton's third law of motion states that for every action, there is an equal and opposite reaction. In other words, when one object exerts a force on another object, the second object exerts an equal and opposite force back on the first object. This law applies to all objects in the universe, from the smallest subatomic particles to the largest celestial bodies.

The forces can be contact forces, such as the force exerted by a person pushing on a wall, or non-contact forces, such as the force of gravity between two objects. For example, when a person jumps, they exert a force on the ground, and the ground exerts an equal and opposite force back on the person, propelling them upwards. Similarly, when a rocket expels gas out of its engines, the gas exerts a force on the rocket, and the rocket exerts an equal and opposite force on the gas, propelling the rocket forward.

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High mass stars produce energy at a faster rate and use carbon in a process that fuses hydrogen to helium.

What is energy ?

Energy, in physics the ability to do work. It can exist in electrical, kinetic, thermal, electrical, chemical, nuclear, or various other forms. There is also heat and work. H. Energy in transfer from one object to another. After transmission, energy is always referred to according to its nature. Thus, the heat transferred can become thermal energy, while the work done can appear as mechanical energy. All forms of energy are associated with movement. For example, any object has kinetic energy when it is in motion. A taut device such as a bow or spring can create motion even when stationary. Because of its composition, it contains potential energy. Similarly, nuclear energy is potential energy as it results from the composition of subatomic particles within the nucleus.

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The customary system of measurement is used, in which a gallon is the closest unit of volume to a liter. Option (A) is correct.

The International unit of volume closest in size to a liter is: Liter. The definition of liter, which is the International System unit of volume is "a volume of 1000 cubic centimeters." Since the International System unit of volume is "a volume of 1000 cubic centimeters," the International unit of volume closest in size to a liter is the liter.

In everyday life, liters are frequently utilized to calculate the volume of liquid or dry matter. The liter is used in science and technology for calculations and information storage. A container that holds 1 liter of water is the same as a 1 liter container that holds oil or flour.A liter is abbreviated as "L" or "l" in scientific notation.

It's also abbreviated as "ℓ" (which looks like a script lowercase letter "L") on the Internet, but this is not widely used. In most countries, the metric system of measurement is used for quantity, weight, and volume. In the United States, Liberia, and Myanmar, however, the customary system of measurement is used, in which a gallon is the closest unit of volume to a liter.

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Using the work done relation, the value of force is 25 Newton.

When a force is applied along a displacement, "work" in physics refers to the energy that is transported to or away from an object. The following situations include work: relocating a table. a door being pulled and pushed. Walking. raising a stone.

The work W that a force F traveling across a distance x exerts on an object is calculated using the formula W=Fs. If the object is moving in the opposite direction from how we expect it to, we add a minus sign.

Work done is equal to displacement times force.

50J = force × 2

f=50/2

Force = 25 Newton.

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Answer:

\(0.62\:\mathrm{s}\)

Explanation:

Since the universal SI unit for velocity is meters/second, let's convert ft/s to m/s:

\(10\:\mathrm{ft/s}=3.048\:\mathrm{m/s}\)

We can use the following kinematics equation to solve this question:

\(v_f=v_i+at\)

What we know:

Solving for \(t\):

\(-3.048=3.048+(-9.8t),\\-6.096=-9.8t,\\t=\frac{-6.096}{-9.8}\approx \boxed{0.62\:\mathrm{s}}\)

Answer:

Explanation:

As the king came near the hermit's hut, he saw the hermit digging the ground in front of his hut. He greeted the king and continued digging. ... (ii) The hermit saw simple people only, so the king put on simple clothes to visit him. (iii) The hermit was digging the ground in front of his hut when the king visited him.

If we throw a socks in to the bowl then it is going with a few unfold situation by means of the projectile and follows the trajectory. Crumpled paper use for the projectile additionally works gud for the simulation.

Crumpled paper has irregular form and mild in weight and it is able to divert in a way by air force or by means of any other motive mild weight. hence simulation and projectile interest are interlinked to every different.

Projectile motion is used in many real-life applications such as designing rockets, ballistic missiles, and artillery, as well as in sports such as baseball, golf, and archery. The concept of projectiles is also relevant in fields such as engineering, military science, and sports. For example, the design of a projectile such as a bullet or missile can affect its accuracy and effectiveness, while knowledge of projectile motion can aid in the design of sports equipment such as golf clubs or javelins.

When a projectile is launched, it follows a curved path known as a trajectory, which is determined by the initial velocity, angle of launch, and the gravitational and atmospheric forces acting on it. The motion of projectiles is studied in physics, where concepts such as projectile motion, trajectory, range, and maximum height are analyzed.

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The current if 55C of charge pass a particular point in a circuit in 5 seconds is 11A.

One kind of electrical charge carrier that moves as current are electrons. From negative to positive areas, current flows. The ampere is the SI unit used to measure electric current (A). One coulomb of electrical charge travelling over a given region in one second is referred to as an ampere of current.

Similar to how current is widely employed in relation to electronic circuits, voltage is also. Voltage is measured using volts (V). Similar to how current and current are related, voltage and the flow of electrons in a circuit are as well. Current is the flow of electrons, whereas voltage is the amount of force driving the flowing electrons.

At higher voltages, current flows more freely; at lower voltages, current is weaker.

Given,

Electrical charge = 55 C

Time = 5 secs

Therefore current = 55 / 5 A

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Answer:

B) –1.1 × 1011 N

Explanation:

Since the second charge is 2 m away and is labeled q₂ = - 4 Coulombs. The third charge is 1 m away and is labeled q₃ = + 3 Coulombs, the electrical force between q₂ and q₃ is -1.1 × 10¹¹ N

To answer the question, we need to find the electrical force of attraction between two charges and this is given by Coulomb's law

This states that the electrical force of attraction between two charges, F is directly proportional to the product of the charges q and Q and inversely proportional to the square of their distance apart, d.

So, mathematically F = kqQ/d²

Now, given that there are three charges are on a line. A positive charge is on the far left labeled q₁ = + 6 Coulombs. The second charge is 2 m away and is labeled q₂ = - 4 Coulombs. The third charge is 1 m away and is labeled q₃ = + 3 Coulombs.

So, the electrical force of attraction between q₂ and q₃ is F = kq₂q₃/d² where

Substituting the values of the variables into the equation, we have

F = kq₂q₃/d²

F = 8.99 × 10⁹ Nm²/C² × (-4 C) × (+ 3 C)/(1 m)²

F = 8.99 × 10⁹ Nm²/C² × (-12 C²)/(1 m)²

F = -107.88 × 10⁹ Nm²/1 m²

F = -1.0788 × 10¹¹ N

F ≅ -1.1 × 10¹¹ N

Since the second charge is 2 m away and is labeled q₂ = - 4 Coulombs. The third charge is 1 m away and is labeled q₃ = + 3 Coulombs, the electrical force between q₂ and q₃ is -1.1 × 10¹¹ N

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A one-time pad is a type of encryption that is completely unbreakable if it is done correctly. It works by generating a random key that is at least as long as the message being encrypted. The key is then combined with the message using an XOR operation.

This produces a ciphertext that cannot be decrypted without the key. The key is used only once and then discarded, hence the name "one-time pad". A one-time pad is completely unbreakable because there is no pattern to the key that can be used to decrypt the message. Each character in the key is generated randomly and independently of the other characters. Therefore, the key is completely unpredictable. Even if an attacker knows the key length and has access to the ciphertext, they cannot use any techniques to decrypt it.

This is because there is no pattern to the ciphertext that can be used to determine the key.The only way to decrypt a one-time pad is to have the key. If an attacker tries to brute-force the encryption by trying all possible keys, they will generate every possible message that is the same length as the original message. This means that the ciphertext is completely meaningless without the key. It is therefore important to keep the key secret and ensure that it is only used once. ,Message: yellow stone Key: wolf To encrypt the given message using the vigenere cipher, we follow the steps below:Step 1: Write the message and key in a tabular form as shown below. To keep the process organized, we use the letters of the key to label the columns.

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Answer:

The correct option is;

B. Earth is currently experiencing a period of global warming

Explanation:

From the graph, we have;

1) From 1880 to 1900 the temperature anomaly (°C) averages a few degrees below the average surface temperature

2) The decrease below the average surface temperature is larger from  1900 to 1920

3) The surface temperature rises more steadily from below average to a little above average from 1920 to 1940

4) Between 1940 to 1980, the temperature hovers around the average surface temperature

5) The Earth's surface temperature is more or less steadily increasing from 1960 to present

Therefore, the Earth is experiencing a period of global warming

The energy per photon associated with a frequency of 1260 kHz is 2.10×10^-25 J.

To calculate the energy per photon, we can use the equation: E = hf, where E represents the energy, h is the Planck's constant (6.62607015 × 10^-34 J·s), and f is the frequency of the photon. Given that the frequency is 1260 kHz, we need to convert it to hertz (Hz) by multiplying it by 10^3:

Frequency = 1260 kHz × 10^3 = 1.26 × 10^6 Hz

Now, we can substitute the values into the equation:

E = (6.62607015 × 10^-34 J·s) × (1.26 × 10^6 Hz)

E = 8.33929859 × 10^-28 J

The answer is given in scientific notation as 8.34 × 10^-28 J. However, the question specifically asks for the answer in the format of 0.00×10^0. To achieve this, we can multiply the result by 10^3 and adjust the exponent accordingly:

E = (8.33929859 × 10^-28 J) × (10^3)

E = 8.33929859 × 10^-25 J

Thus, the energy per photon associated with a frequency of 1260 kHz is 2.10×10^-25 J.

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Answer:

Forces come in pairs, so the force of gravity (9.8 N) with the mans weight (794N) on the earth is counteracted with the normal force ( the force of the earth back on the man) which is the same

Explanation:

Forces are available in pairs, so the force of gravity (nine.8 N) with the man's weight (794N) on the planet is counteracted with the everyday force ( the pressure of the earth again on the man) that's identical.

Gravitational force is a pressure that draws any items with mass. We name the gravitational force appealing as it constantly attempts to tug loads collectively, it never pushes them apart. In reality, every item, together with you, is pulling on each other objects inside the complete universe.

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A current flows down a vertical wire in a straight line.  Using right hand thumb rule,the magnetic field is directed southward to the east of this wire.

Define right hand thumb rule ?      

The relationship between the movements of the magnetic field surrounding a specific conductor and its current direction can be found in a straightforward manner. This method would be known as the right-hand thumb rule. According to the right-hand rule, the magnetic field lines produced by a wire carrying current may be oriented in a manner similar to that of a person's right hand's folded fingertips, with the thumb pointing in the direction of the current flow.

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Answer:

6 v

Explanation:

The parakeets swing with a frequency of approximately 1.14 Hz.

The frequency at which the two parakeets swing on the swing can be determined by considering the relationship between the period of oscillation and the length of the pendulum.

The period of a pendulum is the time it takes for one complete oscillation, while the frequency is the reciprocal of the period, representing the number of oscillations per unit time.

In this case, we are given the distance of the combined center of mass of the parakeets below the pivot, which is 19.5 cm.

To find the frequency, we need to calculate the length of the equivalent pendulum, which is the distance from the pivot point to the combined center of mass of the parakeets.

Assuming the length of the equivalent pendulum is L, we can substitute the given values into the formula for the period of a pendulum, T = 2π√(L/g), where π is a constant (approximately 3.14159) and g is the acceleration due to gravity (approximately 9.8 m/s^2).

Converting the distance from centimeters to meters, we have L = 0.195 m. Substituting the values into the formula, we obtain T = 2π√(0.195/9.8).

Simplifying the equation, we have T = 2π√(0.02), which evaluates to approximately 0.879 s.

To calculate the frequency, we take the reciprocal of the period: f = 1/T = 1/0.879 ≈ 1.14 Hz.

Therefore, the parakeets swing with an approximate frequency of 1.14 Hz.

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The melting point of a substance is the temperature at which the substance changes its phase from solid to liquid.

The freezing point is the temperature at which the substance changes its phase from liquid to solid.

The melting point of a substance is the same as the freezing point. That is when the temperature of the substance in the liquid form is increased continuously, the temperature at which the substance turns into a solid is equal to the temperature at which the substance will turn into liquid from solid if the temperature is decreased continuously, from a higher temperature.

We have a power cycle that works between two reservoirs, one at 600K and the other at 300K. The cycle produces a power output of 0.45 MW and receives energy from the hot reservoir at a rate of 1 MW. The power cycle has an efficiency of 45%, meaning that 45% of the energy received from the hot reservoir is converted to useful work, while the remaining 55% is rejected to the cold reservoir through heat transfer at a rate of 0.55 MW.

We need to determine the efficiency and the rate at which energy is rejected by heat transfer to the cold reservoir, in MW. So, the steps are as follows :

Step 1: Calculate the efficiency of the power cycle.
Efficiency (η) = Power Output / Energy Input
η = 0.45 MW / 1 MW
η = 0.45

Step 2: Convert the efficiency to a percentage.
Efficiency (%) = η × 100%
Efficiency (%) = 0.45 × 100%
Efficiency (%) = 45%

Step 3: Calculate the rate of energy rejected by heat transfer to the cold reservoir.
Energy Rejected = Energy Input - Power Output
Energy Rejected = 1 MW - 0.45 MW
Energy Rejected = 0.55 MW

In conclusion, the efficiency of the power cycle is 45%, and the rate at which energy is rejected by heat transfer to the cold reservoir is 0.55 MW.

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Answer:

Magnitude = 14 metres

Direction = eastward.

Explanation:

A cross-country skier moves 36 meters eastward, then 44meters westward, and finally 22 meters eastward.

Whats the Magnitude and Direction?

The magnitude and direction will be the displacement of the cross country skier.

Let the east ward be positive and the west ward be negative.

Since the skier moves 36 meters eastward, then 44meters westward, and finally 22 meters eastward. Then, that will be:

36 - 44 + 22 = 14

Since the answer is positive, the magnitude is 14 and the direction is east ward.

Answer:

it is a the answer is a btw

Explanation:

The mass of the object that weighs 47.3 lbf on the surface of Planet Quixon, where the acceleration of gravity is one-third that on Earth, is approximately 141.6 lbm.

The weight of an object on Planet Quixon can be calculated using the formula:

w = m * g

where:

w = weight of the object

m = mass of the object

g = acceleration due to gravity

On Planet Quixon, the acceleration due to gravity is one-third the value on Earth. Therefore, the value of g is:

g = (1/3) * 32.2 = 10.73 ft/s²

To find the mass of the object, we rearrange the equation as:

m = w / g

Given that the weight of the object on Planet Quixon is 47.3 lbf, we can convert this to pounds-mass using the conversion factor 1 lbf = 1 lbm * g, where g is the acceleration due to gravity on Earth. Therefore, the weight in pounds-mass is:

47.3 lbf = 47.3 lbm * 32.2 ft/s² / 1 lbf = 1521.06 lbm

Now, we can find the mass of the object on Planet Quixon:

m = w / g = 1521.06 lbm / 10.73 ft/s² ≈ 141.6 lbm

Thus, the mass of the object that weighs 47.3 lbf on the surface of Planet Quixon, where the acceleration of gravity is one-third that on Earth, is approximately 141.6 lbm.

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Answer:

D.It stays the same as the object falls.

Answer:

The answer would be 10.8 billion light years

Answer:

10.8 billion light years is most likely the distance between the Milky Way and another galaxy.

Hope this helps :)

Answer:

Temperature is not a measure of the total kinetic energy of all the molecules in a substance. Two liters of boiling water have twice as much kinetic energy as one liter. The temperatures are the same because the average kinetic energy of molecules in each is the same.

The distances are mentioned below.

What is distance?

Distance refers to the measure of the separation between two points in space. The distance between two points can be determined using mathematical formulas, such as the distance formula in Euclidean space or the great-circle distance formula in a curved space. Distance can also be thought of as a scalar quantity, meaning it has only a magnitude and no direction.

Part A:

To find the closest distance that the coin can be held and still be in focus, we can use the lens equation 1/f = 1/d_o + 1/d_i where f is the focal length of the lens, d_o is the object distance, and d_i is the image distance.

We know that f = 11 D and d_i = 1.7 cm

Therefore,

1/f = 1/d_o + 1/d_i

1/11D = 1/d_o + 1/(1.7cm)

Solving for d_o,

d_o = 1/(1/11D - 1/(1.7cm))

The closest possible distance that Anna can hold the coin to have it appear in focus is d_o. The unit will be in cm.

Part B:

The size of the image that the lens forms on the retina is determined by the lens equation:

1/f = 1/d_o - 1/d_i

where f is the focal length of the lens, d_o is the distance from the lens to the object, and d_i is the distance from the lens to the image.

We know that f = 11 D and d_o = closest possible distance found in Part A.

Therefore,

1/d_i = 1/f - 1/d_o

Solving for d_i, the distance from the lens to the image, will give us the size of the image of the coin on Anna's retina. The unit will be in cm.

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The book value of the car washing machine at the end of year 3 would be $3,266.66.

The book value of an asset at the end of its useful life can be calculated using the MACRS depreciation method. MACRS stands for Modified Accelerated Cost Recovery System, which is a tax depreciation method used in the United States.

To calculate the book value at the end of year 3, we need to know the depreciation rate for a 3-year asset under MACRS. The depreciation rate for a 3-year asset is 33.33% for each year.

Using this depreciation rate, we can calculate the depreciation expense for each year. In this case, the machine cost $9,800. So, the depreciation expense for year 1 would be $9,800 * 33.33% = $3,266.67. Similarly, the depreciation expense for year 2 would be $9,800 * 33.33% = $3,266.67.

To find the book value at the end of year 3, we need to subtract the total depreciation expense for the first 3 years from the original cost of the machine. The total depreciation expense for 3 years would be $3,266.67 + $3,266.67 = $6,533.34.

Therefore, the book value at the end of year 3 would be $9,800 - $6,533.34 = $3,266.66.

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Answer:

well they make the siren go beacaus eyou are doing somthing wrong so what were you thinking

Explanation:

(a)Path Difference -  1.93 × 10^-6 m; (b) In terms of lambda -  3.00 ;(c) P corresponds to maximum condition

d=0.150mm, L=140cm, λ=643nm, and y=1.80cm.

(a) Path difference δ for the rays from the two slits arriving at

P :δ = dsinθ = d/sin(θ) = d/L * yδ = (0.150 mm / (1400 mm)) * 1.8 cmδ = 1.93 × 10^-6 m

(b) The path difference in terms of λ :δ/λ = (1.93 × 10^-6 m) / (643 × 10^-9 m)δ/λ = 3.00

(c) P corresponds to a maximum, a minimum, or an intermediate condition.

In this experiment, the distance between the two slits and the screen is enormous compared to the wavelength of light, and so the light waves can be thought of as travelling in parallel lines (θ ≈ tanθ = y/L). Since the paths are in phase, constructive interference occurs when δ = mλ, where m is an integer.

Thus, P corresponds to a maximum as constructive interference occurs.

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Less than 1.0 Hz is the new oscillation frequency when the automobile bounces on the springs with the driver and 4 passengers inside.

The frequency of a spring-mass system is given by the equation:

f = (1/2π) √(k/m)

where f is the frequency, k is the spring constant, and m is the mass.

Assuming that the mass of the car remains constant, the only thing that changes when the driver and 4 friends get in the car is the total weight of the car.

The spring constant of the car's suspension system remains the same.

The frequency of oscillation of the car is inversely proportional to the square root of the mass. When the total weight of the car and its occupants increases, the mass increases and the frequency decreases.

Therefore, the new frequency of the oscillation when the car bounces on the springs with the driver and 4 friends in the car is less than 1.0 Hz.

So, the answer is (C) less than 1.0 Hz.

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