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Related Questions
An airplane was 300 km [N] of Toronto airport, 3 hours later the airplane 600 km [S]
of Toronto airport, calculate.
a. The airplane’ total displacement relative the Toronto airport.
b. The airplane average velocity.
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Answer:
Explanation:
a) 300 + 600 = 900 km S
b) 900 / 3 = 300 km/hr
The part of earth where all living things are found is called the
Answers
Answer:
Hey Dude....
Explanation:
This is ur answer.....
The biosphere is made up of the parts of Earth where life exists. The biosphere extends from the deepest root systems of trees to the dark environment of ocean trenches, to lush rain forests and high mountaintops.
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2.2 Verify the Law of Conservation of Mass by calculating the relative masses before and after the reaction.
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Baby we biult this house of memories take my pic now shake it till u see it=House of memories
a pound of body fat stores in the amount of chemical energy equivalent to 3500 calories. When sleeping the average adult burns on and expends about 0.45 Cal/h How many calories would a 150 lb person burn during 8 hours of sleep?How how long would the personhave to sleep continuously to lose one pound of body fat
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We know that
• The average is 0.45 calories per hour.
,• The energy stored is 3500 calories per pound of body fat.
,• The mass is 150 pounds.
,• The hours of sleep are 8.
First, we have to multiply the mass 150 lb by the average rate
\(150lb\times0.45=67.5\text{cal}/hr\)This means that this person burns 67.5 calories per hour. Now, we have to multiply this rate by 8 hours.
\(67.5\times8=540\text{cal}\)Therefore, a 150 lb person would burn 540 calories during 8 hours of sleep.Now, we know that 1 pound of body fat is equivalent to 3500 calories. So, let's use a rule of three to find the period of time would take this person to lose one pound of body fat (3500 cal).
\(\frac{67.5\text{cal}}{1hr}=\frac{3500\text{cal}}{x}\)Let's solve for x
\(\begin{gathered} x=\frac{3500}{67.5}hr \\ x\approx51.9hr \end{gathered}\)Therefore, this person would have to sleep continuously for 51.9 hours to lose one pound of body fat.What amount of heat is required to raise the temperature of 5 kg of water through 20°C?
Answers
Answer:
419,000 Joules(J) or 419 kilojoules (kJ)
Explanation:
The mount of heat energy required to raise the temperature of water of mass m kg through Δt degrees centigrade is given by
q = mcΔt
where c is the specific heat of water = 4190 Joules/(kg*°C)
Substituting these values we get
q = 5 x 4190 x 20 = 419,000 Joules(J) = 419 kilojoules (kJ)
What is the force of gravity (in newtons) acting between the earth and a 5 kg bowling ball that is resting on the surface of the earth
Answers
Answer:
49 N
Explanation:
F = m a
= 5 * 9.81 =~ 49 N
A cylindrical Benzene tank is 12ft high and 32in in diameter. How many kilograms of benzene can the tank store? help please make it good
Answers
Answer:
1670 kg
Explanation:
Convert the dimensions to cm.
12 ft × (12 in/ft) × (2.54 cm/in) = 365.76 cm
32 in × (2.54 cm/in) = 81.28 cm
Calculate the volume.
V = πr²h
V = π (81.28 cm / 2)² (365.76 cm)
V = 1,897,813.27 cm³
V = 1,897,813.27 mL
V = 1,897.81 L
Density of benzene is 0.88 kg/L.
m = (0.88 kg/L) (1,897.81 L)
m = 1670 kg
A lump of clay with a mass of .50.0 g is moving south at a speed of 20.0 cm/s. It collides head on with a second lump of clay with a mass of 70.0 g that is moving north at a speed of 40.0 cm/s. The two lumps stick together, and no external horizontal forces act on the system. What is the velocity of the combined lump after the collision?
Answers
The velocity of the combined lump after the collision is 39.5 cm/s, which is the average velocity of the two lumps before the collision.
To solve this problem, we can use the principle of conservation of momentum, which states that the total momentum of a system before a collision is equal to the total momentum of the system after the collision, provided there are no external horizontal forces acting on the system.
The momentum of an object is equal to its mass multiplied by its velocity. Therefore, we can calculate the total momentum of the system before the collision as:
Total momentum before collision = (0.50 g) × (-20.0 cm/s) + (70.0 g) × 40.0 cm/s
= -10.0 g·cm/s + 2800.0 g·cm/s
= 2790.0 g·cm/s
Since the two lumps stick together after the collision, their masses combine to form a single lump. Let's call the velocity of the combined lump after the collision "v". We can then calculate the total momentum of the system after the collision as:
Total momentum after collision = (0.50 g + 70.0 g) × v
= 70.50 g × v
According to the principle of conservation of momentum, the total momentum before the collision is equal to the total momentum after the collision. Therefore, we can equate these two expressions and solve for "v":
Total momentum before collision = Total momentum after collision
2790.0 g·cm/s = 70.50 g × v
v = 2790.0 g·cm/s ÷ 70.50 g
v = 39.5 cm/s
This result can be explained by the fact that, in the absence of external horizontal forces, the momentum of the system is conserved, and the total mass of the system remains constant.
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Consider an earthquake caused by a single disturbance, which sends out both transverse and longitudinal waves. These waves travel with distinctly different speeds in the ground.
a. According to the image, which type of wave travels the fastest? Use the data above to support your answer.
b. Which type of wave only travels through the mantle? Use the data
above to support your answer.
c. According to the image, how deep can s-waves travel? How deep can p-waves travel?
Answers
The P-wave is capable οf traveling apprοximately 5,800 km deep, while the S-wave can travel apprοximately 800 km deep.
S-wave: what is it?An earthquake prοduces a type οf seismic wave knοwn as an S-wave, which is alsο knοwn as a shear wave. It is a wave that carries energy and travels alοng the earth's surface, causing the grοund tο vibrate frοm side tο side.
The S-wave οnly travels thrοugh sοlid material, in cοntrast tο the P-wave (primary wave), which is an energy-carrying wave that travels directly thrοugh the earth. As a result, the S-wave is unable tο traverse gases οr liquids.
B. The fastest wave is the transverse wave, οr S-wave. This is as a result οf the S-wave's greater velοcity than the P-wave's, which is apprοximately 4.6 km/s in cοmparisοn tο the P-wave's apprοximately 7.2 km/s.
C. The mantle is the οnly place where the transverse wave (S-wave) can travel. This is as a result οf the S-wave's significantly lοwer velοcity than the P-wave's, which is apprοximately 4.6 km/s in cοmparisοn tο the P-wave's apprοximately 7.2 km/s.
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a plane wall is 250mm thick and it's wall area is 4.5m^2. if the thermal conductivity is 9.35w/m°c and surface temperature are steady at 150°c and 40°c. calculate the heat flow across the plane wall and the temperature gradient in the flow direction
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The temperature gradient in the flow of direction is 294525 W.
What is Temperature gradient?A temperature gradient is the gradual variance in temperature with distance. The slope of the gradient is consistent within a material. A gradient is established anytime two materials at different temperatures are in physical contact with each other.
Q= T/( L/ KA)
Q= ( 1500 − 450) / 0.15 / 9.35v * 4.35)
= 294525 W
Units of measure of temperature gradients are degrees per unit distance, such as °F per inch or °C per meter.
Many temperature gradients exist naturally, while others are created. The largest temperature gradient on Earth is the Earth itself. Q= T/Ka.
Therefore, The temperature gradient in the flow of direction is 294525 W.
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chandani was intrested in researching the plant by mixing things in soil she decided to test the effect of lime eurea table salt and compost on the soil the she put that soil then she bought a bucket of good soil from the garden and mixed it well she put that soil in 12 equal size vases she put two spoons urea each time two spoond of compost of table salt each in another three vases and two spoons of compost each each in three vases after that she planted the seed in all the vases everyday and measure the height of each plant daily and keep record then identify dependent ,indrpendent and controlled variable
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The dependent, independent, and controlled variables are as follows:
1. Dependent - The effect of lime urea table salt and compost on the soil
2. Independent - The soil on which the elements are incorporated.
3. Controlled variable - The height of the plants.
What is the dependent, independent, and controlled variable?The dependent variable is that which is tested in the experiment and in this experiment, Chandani is testing the effect of lime, urea, table salt, and compost on the soil.
The independent variable is the altered element in the experiment and for this experiment, this is the soil that receives different additives. Finally, the controlled variable is that which remains constant and that is the height of each plant that the researcher checks.
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Write the differences between rest and motion
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Answer:
Depends on position
Explanation:
Rest:
A body is said to be at rest, if it does not change its position with respect to its surroundings.
Motion:
A body is said to be in motion, if it changes its position with respect to its surroundings.
The state of rest and motion is relative
a car is moving 5.82 m/s when it accelerates at 2.35 m/s2 for 3.25, what is its final velocity
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The final velocity of the car can be calculated using the formula: final velocity = initial velocity + acceleration * time. Plugging in the values you provided, we get: final velocity = 5.82 m/s + 2.35 m/s² * 3.25 s = 13.44 m/s.
Which objects cannot be observed in detail without a microscope?
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Answer:
partecls
Explanation:
because they are to small to see with plain eyes
List ten examples of the following.
1.Translucent object
2.Transparent object
3.Opaque object
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Transparent - Diamond, water, air, prism, cellophane sheet, frosted glass, glasses, clear tape, non colored plastic, lenses
Translucent - Butter paper, parchent paper, plastics, clouds, thin fabrics, colored plastics, tinted glass
Opaque - Computer, phone, book, box, file, stone, can, paper cup, cupboard (wood/steel)
The density of diamond is 3.51 g/cm^3, and the density of platinum is 21.43 g/cm^3. If equal masses of diamond and platinum are transferred to equal volumes of water in separate graduated cylinders, which graduated cylinder would have the greatest volume change? Explain or show with a sample calculation.
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The graduated cylinder with the greatest volume change is the one containing the diamond, as it displaced more water than the cylinder containing the platinum.
To determine which graduated cylinder would have the greatest volume change, we need to calculate the volume of water displaced by each object. The volume of water displaced is equal to the volume of the object, as water is displaced to make room for the object.
The graduated cylinder with the greatest volume change will have the larger volume of water displaced.
The formula for calculating the volume of an object is:
Volume = Mass / Density
Let's assume we have 1 gram of diamond and 1 gram of platinum. Using the given densities, we can calculate the volumes of the objects as follows:
Volume of diamond = 1 g / 3.51 g/cm^3 = 0.284 cm³
Volume of platinum = 1 g / 21.43 g/cm^3 = 0.047 cm³
Then, in separate graduated cylinders, we transfer equal masses of diamond and platinum to equal volumes of water. As previously stated, the volume of water displaced by each object is equal to the volume of the object. As a result, for each graduated cylinder, the volume change equals the volume of water displaced by the object. Using the previously calculated volumes, we get:
Volume change for diamond = 0.284 cm³
Volume change for platinum = 0.047 cm³
Therefore, the graduated cylinder with the greatest volume change is the one containing the diamond, as it displaced more water than the cylinder containing the platinum.
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Mathias is going to do some informational interviewing. What is one of the main benefits of doing these interviews?
O A.
OB.
O C.
O D.
A.He will gain insight about a new career opportunity.
B.He will likely be offered a position with a company.
C.He will be able to ask questions about job openings.
D.He will find out how much money everyone earns.
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Answer:
A
Explanation:
One of the main benefits of informational interviewing is that it allows the person conducting the interviews to gain insights and information about a particular career or industry.
If you stood atop a ladder on Earth that was as tall as Earth's radius (so you were twice as far from
Earth's center) your weight atop the ladder would be
a.half its normal value
b. one-eighth its normal value
C. one-quarter its normal value d.
d.none of the above
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Your weight at the top of the ladder would be one-quarter of its normal value. The correct option is C.
What is the acceleration due to gravity?The gravitational pull of the Earth, denoted by g, is the net acceleration imparted to objects by the combined effect of gravitation and centrifugal force. It is a vector quantity whose direction corresponds to a plumb bob and whose strength or magnitude is determined by the norm.
The formula for gravity is,
g = GM / R²
g = 1 / R²
gt = 1 / (2R)²
gt / g = R² / 4R²
gt = 1 / 4g
Therefore, at the top of the ladder, your weight would be one-quarter of its normal value.
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Universal Gravitation Problem Set
Highlight Given information in GREEN. Highlight what you are solving for in YELLOW.
Formula: Fg= G*M,*M,/d? G= 6.67 * 10-11 N*M°/Kg?
The distance between Earth and its moon is 3.84 x 10 meters. Earth's mass is
m = 5.98 x 1024 kilograms and the mass of the moon is 7.36 x 1022 kilograms.
What is the force between Earth and the moon?
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Answer:
The force between Earth and the moon is 1.99x10²⁶ N.
Explanation:
The force between Earth and the moon can be found using the Gravitational Force equation:
\( F_{g} = \frac{Gm_{E}m_{m}}{d^{2}} \)
Where:
d: is the distance between Earth and the moon = 3.84x10⁵ m
G: is the gravitational constant = 6.67x10⁻¹¹ Nm²/kg²
\(m_{E}\): is the Earth's mass = 5.98x10²⁴ kg
\(m_{m}\): is the moon's mass = 7.36x10²² kg
Hence, the force is:
\( F_{g} = \frac{Gm_{E}m_{m}}{d^{2}} = \frac{6.67 \cdot 10^{-11} Nm^{2}/kg^{2}*5.98\cdot 10^{24} kg*7.36\cdot 10^{22} kg}{(3.84\cdot 10^{5} m)^{2}} = 1.99 \cdot 10^{26} N \)
Therefore, the force between Earth and the moon is 1.99x10²⁶ N.
I hope it helps you!
which of the following statements is valid? which of the following statements is valid? if the field at a particular point is zero, the potential at that point must be zero. if the potential at a particular point is zero, the field at that point must be zero. if the potential throughout a particular region is constant, the field throughout that region must be zero. if the field throughout a particular region is constant, the potential throughout that region must be zero. request answer provide feedback
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If the potential throughout a particular region is constant, the field throughout that region must be zero.[CORRECT]
Characteristics of Potential EnergyThe following are the characteristics of potential energy
Gravitational potential energy is possessed by an object due to its position relative to the earth Any object that has gravitational potential energy can do work when it moves towards the surface of the earth If an object has the potential to do business, then the object has potential energy. Potential energy is energy stored in an object because of its height. Potential energy is also affected by the acceleration due to gravity and the height of an object. The higher and the greater the mass of the object, the greater the potential energy. Vice versa, if the mass of the object is smaller and the height of the object is lower, the potential energy is smaller. If the object lies above the ground, then the potential energy is zero. So potential energy is always related to the height of the object.Learn more about potential energy at
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A slanted surface used to raise an object is a(n)
Answers
Answer:
Inclined Plane
Explanation:
What are the three factors discussed in our live session that can lead to success through challenging physical activities:
Talent, flexibility, and stamina
Strength, balance, and endurance
Knowledge, attitude, and fitness level
Attitude, motivation, and determination
Answers
Answer:
Attitude, motivation and determination
Explanation:
Let me know if I'm right.
The factors leading to the success through the challenging physical activities are Attitude, motivation and determination.
Although the information regarding the live session is not mentioned, but as a general point of view, the major factors that need to considered while undergoing through the challenging physical activities are as follows:
Attitude - Attitude is one of the major factor leading to the management of challenges. A positive attitude always creates a base to face the initials of physical activities.Motivation - Motivation is another aspect that needs to be considered while undergoing the physical activities. Motivation comes from some sort of positive words from a specific person, thereby reducing the changes of poor start.Determination - The half battle is conquered with self-determination, a highly determined person is always has an add-on advantage for the task that he/she is going to start.Thus, we can conclude that the factors leading to the success through the challenging physical activities are Attitude, motivation and determination.
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.a car increases its speed from 10 m/s to 20/s in 2.5. seconds calculate it’s acceleration
Answers
Answer:
\(\boxed {\boxed {\sf 4\ m/s^2}}\)
Explanation:
Acceleration is the rate of change of an object with respect to time. It is the change in velocity over the time.
\(a= \frac{v_f-v_i}{t}\)
The car starts at 10 meters per second and increases to 20 meters per second in 2.5 seconds.
\(v_f\)= 20 m/s \(v_i\)= 10 m/s t= 2.5 sSubstitute the values into the formula.
\(a= \frac{ 20 \ m/s - 10 \ m/s}{2.5 \ s }\)
Solve the numerator.
\(a= \frac{10 \ m/s}{2.5 \ s}\)
Divide.
\(a= 4 \ m/s/s\)
\(a= 4\ m/s^2\)
The acceleration of the car is 4 meters per second squared.
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How are stationary waves formed on a string?
Answers
Answer:
hey, please open my account and see my question, please help me solve the task, I have to send it to the teacher soon.
Answer:
When waves are generated and they reflect off a fixed end, the reflected waves are completely out of phase. The reflected waves and the incident waves interfere with each other along the path and results in the formation of nodes and anti-nodes. Nodes are points of completely out of phase interference and anti-nodes are points of completely in phase interference.
g the total mechanical energy of the satellite-Earth system when the satellite is in its current orbit is E. In order for the satellite to orbit Earth in a new stable circular orbit at an altitude of 12RE, the energy of the satellite-Earth system must be
Answers
Answer:
The correct answer is "\(\frac{4E}{3}\)".
Explanation:
According to the question,
Energy of satellite,
⇒ \(E_s=-\frac{GM_sM_E}{2r}\)
For the very 1st case:
\(r = R_E+R_E\)
\(=2R_E\)
or,
⇒ \(E=-\frac{GM_sM_E}{4R_E}\)...(1)
For the new case:
\(r = R_E+\frac{R_E}{2}\)
\(=\frac{3R_E}{2}\)
then,
⇒ \(E'=-\frac{GM_sM_E}{2 \frac{3R_E}{2} }\)
\(=-\frac{GM_sM_E}{3R_E}\)...(2)
From equation (1) and (2), we get
⇒ \(E'=\frac{1}{3}(4E)\)
\(=\frac{4E}{3}\)
Hint: sin2θ + cos2θ = 1 .
Consider the 692 N weight held by two
cables shown below. The left-hand cable had
tension 570 N and makes an angle of θ2 with
the ceiling. The right-hand cable had tension
530 N and makes an angle of θ1 with the
ceiling. a) What is the angle θ1 which the righthand cable makes with respect to the ceiling?
Answer in units of ◦.
b) What is the angle θ2 which the left-hand
cable makes with respect to the ceiling?
Answer in units of ◦.
Answers
a) The angle θ1 which the righthand cable makes with respect to the ceiling is sin^(-1)(692 N / 530 N).
b) The angle θ2 which the left-hand cable makes with respect to the ceiling is sin^(-1)(692 N / 570 N).
We may utilise the tension of the right-hand cable as well as its vertical and horizontal components to determine the angle 1. θ2 = sin^(-1)(692 N / 570 N).
We may apply the ideas of trigonometry and vector addition to address this issue.
a) The tension of the right-hand wire as well as its vertical and horizontal components can be used to determine the angle 1.
T1sin(1) calculates the vertical component of the right-hand cable's tension, which is equal to the object's weight (692 N).
T1sin(θ1) = 692 N
We may rearrange the equation to find 1:
θ1 = sin^(-1)(692 N / T1)
We can find 1 by substituting the given tension value, T1 = 530 N:
θ1 = sin^(-1)(692 N / 530 N)
b) Similarly, we can use the formula to determine the angle 2 the left-hand cable's tension and its vertical and horizontal components.
The vertical component of the left-hand cable's tension is given by T2sin(θ2), and it should also be equal to the weight of the object (692 N).
T2sin(θ2) = 692 N
To find θ2, we can rearrange the equation:
θ2 = sin^(-1)(692 N / T2)
Substituting the given tension value T2 = 570 N, we can solve for θ2:
θ2 = sin^(-1)(692 N / 570 N)
Calculating these angles using the given tension values will provide the answers in degrees.
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7. A rock of mass 5 kg is pushed over the edge of a cliff which is 200 m high. a) Ignore air resistance and calculate the speed of the rock at the bottom of the cliff. In reality, air resistance cannot be ignored. The rock eventually reaches terminal velocity of 30 m.s-¹.
b) Calculate the kinetic energy of the rock at the bottom of the cliff.
c) Calculate the work done by air resistance.
d) Calculate the average force exerted by the air on the rock.
Answers
Speed of the rock at the bottom of the cliff is 44.3 m/s.
Kinetic energy of the rock at the bottom of the cliff is 4915 J.
Work done by air resistance is -2250 J
Average force exerted by the air on the rock is 11.25 N.
How to determine kinetic energy and speed?a) The speed of the rock at the bottom of the cliff can be calculated using the equation:
v = √(2gh)
where v = final velocity, g = acceleration due to gravity (9.81 m/s²), and h = height of the cliff (200 m).
Plugging in the values:
v = √(2 x 9.81 x 200) = 44.3 m/s
Therefore, the speed of the rock at the bottom of the cliff is 44.3 m/s.
b) The kinetic energy of the rock at the bottom of the cliff can be calculated using the equation:
KE = (1/2)mv²
where KE = kinetic energy, m = mass of the rock (5 kg), and v = velocity (44.3 m/s).
Plugging in the values:
KE = (1/2) x 5 x (44.3)² = 4915 J
Therefore, the kinetic energy of the rock at the bottom of the cliff is 4915 J.
c) The work done by air resistance can be calculated using the work-energy principle:
Work done by air resistance = KE_initial - KE_final
where KE_initial = initial kinetic energy of the rock, and KE_final = final kinetic energy of the rock (at terminal velocity).
Since the rock was initially at rest, its initial kinetic energy is zero. At terminal velocity, the kinetic energy of the rock is:
KE_final = (1/2)mv_terminal²
where m = mass of the rock (5 kg), and v_terminal = terminal velocity (30 m/s).
Plugging in the values:
KE_final = (1/2) x 5 x (30)² = 2250 J
Therefore, the work done by air resistance is:
Work done by air resistance = 0 - 2250 = -2250 J
The negative sign indicates that the work done by air resistance is in the opposite direction to the motion of the rock.
d) The average force exerted by the air on the rock can be calculated using the equation:
Work done by air resistance = Force x Distance
where Force = average force exerted by air on the rock, and Distance = distance travelled by the rock.
Rearrange the equation to solve for Force:
Force = Work done by air resistance / Distance
Plugging in the values:
Force = -2250 / 200 = -11.25 N
Therefore, the average force exerted by the air on the rock is 11.25 N. The negative sign indicates that the force is in the opposite direction to the motion of the rock.
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A two-slit experiment with red light produces a set of bright fringes. (a) Will the spacing between the fringes increase, decrease, or stay the same if the color of the light is changed to blue? (b) Choose the best explanation from among the following:
I. The spacing between the fringes will increase because blue light has a greater frequency than red light.
II. The fringe spacing decreases because blue light has a shorter wavelength than red light.
III. Only the wave property of light is important in producing the fringes, not the color of the light. Therefore the spacing stays the same
Answers
a) The spacing between the fringes will decrease if the color of the light is changed to blue.
b) II. The fringe spacing decreases because blue light has a shorter wavelength than red light.
The two-slit experiment is a fundamental experiment in wave optics that demonstrates the wave-like behavior of light. When a beam of light is shone through two small slits, it produces a diffraction pattern on a screen behind the slits. This pattern consists of a series of bright and dark fringes, which are caused by the interference of the light waves passing through the two slits.
Answer to (a) is that, if the color of the light is changed to blue, the spacing between the fringes will decrease. This is because the spacing between the fringes is inversely proportional to the wavelength of the light, and blue light has a shorter wavelength than red light.
As for the reason behind it, the best explanation is (b) II. The fringe spacing decreases because blue light has a shorter wavelength than red light. The wave property of light is important in producing the fringes, and the color of the light does play a role in the spacing of fringes, which is why the spacing decreases when the color of the light is changed to blue.
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The 'bar-and-gauge' experiment is designed to show the effect clearly. It is difficult to see the expansion of a metal even when it is heated by several hundred degrees. The bar-and-gauge' experiment is often used to show that a metal expands when heated. Write a brief script for a teacher who wants to use this demonstration of thermal expansion and who also wants to show that metals contract on cooling. Include practical instructions.
Answers
Thermal expansion is defined as the property of metals to expand when they are heated.
The metal expands when heated because the atoms move apart more.
An excellent method to demonstrate the concept of thermal expansion is using the bar and gauge experiment.
Both the diameter and the length are precisely comparable when both are at room temperature.
The bar will not fit within the gauge once it has been heated and cooled. Similar to the last instance; the bar will no longer fit flush inside the gauge if the gauge is heated and the bar is cooled.
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HELPPPPPP!!!! Jupiter has a gravity that is 2.4 times that of Earth. A person has a mass of 60kg. What is the mass of this person on Jupiter?
60 kg
144 kg
600N
1440N
Answers
60
because mass of an object never change
but weight can change for example if it's
mass is 60kg 5he wieght will be 60kg * 9.8m/s²
=588N