Answer:
none of the answers is correct, the time is the same t₁ = t₂ = 0.600 s
Explanation:
This is a kinematics exercise, analyze the situation a bit. The vertical speed in both cases is the same is zero, the horizontal speed in the second case is double (vₓ₂ = 2 vₓ₁)
let's find the time to hit the ground
y = y₀ + I go t - ½ g t²
0 = y₀ - ½ g t²
t = √ 2y₀ / g
with the data from the first launch
y₀i = ½ g t²
y₀ = ½ 9.8 0.6²
y₀ = 1,764 m
with this is the same height the time to descend in the second case is the same
t₂ = 0.600 s
this is because the horizontal velocity change changes the offset on the x axis, but does not affect the offset on the y axis
Therefore, none of the answers is correct, the time is the same
t₁ = t₂ = 0.600 s
Which correctly describes latent heat?
A. The heat of molecules that are under pressure
B. The heat held inside of ice crystals colder than -2°C
C. The heat absorbed or lost by a substance while it's changing state
D. The heat used to change the temperature of a liquid
Option C. The heat absorbed or lost by a substance while it's changing state correctly describes latent heat
Latent heat is the heat absorbed or lost by a substance while it is changing state.
The latent heat is a type of heat that is transferred during phase change, i.e., while a substance undergoes a change of state.
For example, when ice melts into liquid water, or when liquid water evaporates into water vapor, heat is absorbed from the surroundings.
Latent heat is not associated with a temperature change; rather, it's associated with a change of state.
For instance, the temperature of water remains at 100°C while boiling.
When water is boiling, the latent heat of vaporization is absorbed and utilized to break the hydrogen bonds holding water molecules together to change water from the liquid phase to the gaseous phase.
When the water is boiling, adding more heat won't increase the water's temperature, instead, the extra heat will be absorbed to change the phase of water molecules.
Therefore, the correct answer to the given question is option C: The heat absorbed or lost by a substance while it is changing state.
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4. Calculate the total resistance of the circuit if R1=4 Ω, R2=30 Ω, R3=10Ω, R4=5Ω Determine the current strength if the circuit is connected to a voltage source with a voltage of 56 V
The total resistance of the circuit is 49 Ω. The current strength in the circuit, when connected to a voltage source of 56 V, is approximately 1.14 A.
To calculate the total resistance of the circuit, we need to determine the equivalent resistance of the resistors connected in a series.
Given:
R1 = 4 Ω
R2 = 30 Ω
R3 = 10 Ω
R4 = 5 Ω
Calculate the equivalent resistance (RT) of R1 and R2, as they are connected in series:
RT1-2 = R1 + R2
RT1-2 = 4 Ω + 30 Ω
RT1-2 = 34 Ω
Calculate the equivalent resistance (RTotal) of RT1-2 and R3, as they are connected in parallel:
1/RTotal = 1/RT1-2 + 1/R3
1/RTotal = 1/34 Ω + 1/10 Ω
1/RTotal = (10 + 34) / (34 * 10) Ω
1/RTotal = 44 / 340 Ω
1/RTotal ≈ 0.1294 Ω
RTotal ≈ 1 / 0.1294 Ω
RTotal ≈ 7.74 Ω
Calculate the equivalent resistance (RTotalCircuit) of RTotal and R4, as they are connected in series:
RTotalCircuit = RTotal + R4
RTotalCircuit = 7.74 Ω + 5 Ω
RTotalCircuit ≈ 12.74 Ω
Therefore, the total resistance of the circuit is approximately 12.74 Ω.
To determine the current strength (I) when connected to a voltage source of 56 V, we can use Ohm's Law:
I = V / RTotalCircuit
I = 56 V / 12.74 Ω
I ≈ 4.39 A
Therefore, the current strength in the circuit, when connected to a voltage source of 56 V, is approximately 4.39 A (or 1.14 A, considering significant figures).
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A diver jumps from a 3.0 m board with an initial upward velocity of 5.5 m/s. What is the time the diver was in the air?
The answer is that the time the diver was in the air is 1.13 seconds.
To determine the time the diver was in the air, we can use the kinematic equation:
Δy = viΔt + 1/2at²,
where Δy is the displacement, vi is the initial velocity, a is the acceleration due to gravity (g), and t is the time.The initial velocity, vi, is given as 5.5 m/s, and since the diver jumps upwards, the displacement, Δy, is equal to the height of the board, which is 3.0 m. The acceleration due to gravity, a, is -9.8 m/s² (negative because it acts downwards).Substituting the known values into the equation:3.0
m = (5.5 m/s)t + 1/2(-9.8 m/s²)t²
Simplifying, we get:
4.9t² + 5.5t - 3.0 = 0
We can solve for t using the quadratic formula:
t = (-5.5 ± √(5.5² - 4(4.9)(-3.0))) / (2(4.9))= (-5.5 ± 1.59) / 9.8= -0.47 s or 1.13 s
Since time cannot be negative, the time the diver was in the air is 1.13 seconds.
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What feature does not require a planet to have any particular characteristics?
Stream Beds
Dunes
Impact Craters
Volcanic Lava Flows
What is the correct answer?
Answer:
Impact Craters.
Explanation:
An impact crater can be defined as a circular depression that is caused by impact on any planet or asteroids or any other celestial body's surface. When smaller body in galaxy impacts these larger bodies, they form a circular depression on it's surface.
This is a major feature found in solid object such as the Moon, Mercury, etc.
Therefore, the feature that a planet does not require is an impact crater. As other features are important to define a planet. Thus correct option is C.
Using your own life experience, can you provide examples of environmentally influenced learned behaviors? Read More >> Using your own life experience, can you provide examples of environmentally influenced learned behaviors?
Read More >>
I have observed and experienced behaviors that are learned as a result of environmental influences, and I can furnish examples to support this assertion.
What is one good example?Recycling serves as a noteworthy instance. During my childhood, I acquired the habit of recycling owing to the teachings and guidance of my parents and educators, which became firmly established in me.
Water conservation serves as another illustration. Having experienced repeated droughts in my locale, I developed a sense of awareness about the utilization of water and inculcated practices such as shutting off the tap while brushing my teeth.
My daily habits have been influenced by the environmental elements in my surroundings and have now become ingrained in my routine.
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Which statement describes the way in which energy moves between a
system of reacting substances and the surroundings?
OA. The potential energy of the system and its surroundings
increases.
B. The thermal energy of the system and its surroundings increases.
C. Molecular collisions create energy that is then released into the
surroundings.
D. Molecular collisions transfer thermal energy between the system
and its surroundings.
The correct statement is Molecular collisions transfer thermal energy between the system and its surroundings. Thus, option D is correct.
The energy moves between a system of reacting substances and the surroundings by the collision of molecules. The transfer of heat or thermal energy between the system and its surroundings by the process of Conduction. Conduction is the process of transmitting the heat to the neighboring atoms or collisions by the process of collisions.
The conduction takes place more steadily in solids and liquids where the molecules are closer together. When the molecules are collided with the nearby molecules, the potential energy is converted into kinetic energy and hence the heat energy is transferred between the system and its surroundings.
Hence, Molecular collisions transfer thermal energy between the system and its surroundings. Thus, the correct option is D.
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What is the fastest possible speed called in our universe and what is the equation for it?
Answer:
The speed of light traveling through a vacuum is exactly 299,792,458 meters (983,571,056 feet) per second. That's about 186,282 miles per second — a universal constant known in equations as "c," or light speed.
\(s\frac{d}{t}\)
Explanation:
hope this helps you my friend
A person holds onto an object for 2 minutes but doesn't move the object. Is work done
on the object?
Answer:
No
Explanation:
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1 point
A cluster of stars are forming in a nebula. There are red stars, blue stars,
yellow stars, and white stars. Which of those stars are moving away from
the solar system? *
science
The slope of a speed vs.time graph is equal to the object’s
Answer:
acceleration
Explanation:
speed=v,
In speed vs time graph, slope = dv/dt = acceleration
Interesting fact about the rib
Answer:
YOU CAN SNEEZE YOUR WAY TO A RIB FRACTURE.
Explanation:
URGENT
A force of 35 N is used to stretch a spring 15 cm beyond its normal length. What is the
increase in the spring's energy?
Answer:
5.25 J
Explanation:
W = PE = (f)(x)
PE = 35N*0.15m
PE = 5.25 N*m
1 N*m = 1 J
PE = 5.25 J
Please help me out! I will pay real money to whoever solves this
Answer:
I KNOW THE ANSWER IT WILL COST 30$
Explanation:
Sometimes earthquakes occur at a boundary between the Indian and Eurasian Plates. The collisions of these two continental plates formed the Himalayan mountain range.
Based on this information, which type of boundary exists between the Indian and Eurasian Plates?
continental-continental convergent
continental-continental divergent
oceanic-continental divergent
oceanic-continental convergent
Answer:
Continental Continental convergent.
Explanation:
Continental Continental convergent is a type of earthquakes that occur between boundaries of two continents in which the tectonic plates move closer to each other or converge.
Eurasian plates refers to tectonic plates that is found in the Continent of Eurasia which include Asian and Europe excluding India subcontinent.
From the question, the earthquake occur between boundaries of two continents India and Eurasia and this converging and collision of the two continental plates formed the Himalayan mountain range.
Therefore, it is continental continental convergent.
Answer:
A
Explanation:
Apply what is the momentum of a bicycle with a mass of 18 kg traveling at 20 m/s?.
Answer:
Below
Explanation:
Momentum = m v
= 18 kg * 20 m/s = 360 kg m/s
I'm not sure about how can solve this problem. Please help me!!
The magnitude of the power dissipated in resistor R4 is approximately 10,028 watts.
How to find magnitude?To find the power dissipated in resistor R4, use the formula:
P = I² × R
where P = power, I = current flowing through the resistor, and R = resistance of the resistor.
The total resistance, Rt, can be calculated using the formula:
1/Rt = 1/R1 + 1/R2 + 1/R3
Substituting the given values:
1/Rt = 1/3 + 1/0.8 + 1/2
Simplifying the equation:
1/Rt ≈ 1.6667
Rt ≈ 0.6 Ω
Next, calculate the total voltage, Vt, by summing the individual voltage sources:
Vt = ε1 + ε2 + ε3
Substituting the given values:
Vt = 9 + 6 + 4
Vt = 19 V
Now calculate the current flowing through resistor R4 using Ohm's Law:
I = Vt / Rt
Substituting the calculated values:
I = 19 / 0.6
I ≈ 31.6667 A
Finally, calculate the power dissipated in resistor R4:
P = I² × R4
Substituting the calculated values:
P = (31.6667)² × 10
P ≈ 10,028 W
Therefore, the magnitude of the power dissipated in resistor R4 is approximately 10,028 watts.
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Which two elements make up most of the Sun’s mass?
Question 4 options:
Hydrogen and oxygen
Carbon and nitrogen
Oxygen and carbon
Hydrogen and helium
Answer:
hydrogen and helium
Explanation:
i got it 100 percent. Hope this Helps!
A student mixed two clear liquids together in a beaker. A solid and a new liquid formed. The student forgot to write down the mass of one of the reactants. The
rest of the data are shown in the table below.
What is the mass of liquid reactant A?
A 1.0 g
B 8.0 g
C 9.0 g
D 11.0 g
E 20.0 g
Besides toxic pollution, the other types of pollution are sediment pollution, nutrient pollution, and bacterial pollution.
a. True
b. False
Answer:
a. True
Explanation:
Pollution can be defined as the physical degradation or contamination of the environment through an emission of harmful, poisonous and toxic chemical substances.
Aside from toxic pollution, the other types of pollution includes the following;
I. Sediment pollution.
II. Nutrient pollution.
III. Bacterial pollution.
Furthermore, particulate pollution is a form of pollution that is responsible for the degradation of the environment.
Particulate matter is also referred to as particle pollution or atmospheric aerosol particles and it can be defined as a complex microscopic mixture of liquid droplets and solid particles that are suspended in air. Other forms of particle pollution includes space debris and marine debris.
Some examples of particulate pollution are dusts, soot, dirt, smoke, etc.
Answer:a
Explanation:
See the attachment included with this note
The angular velocity of the propeller is 136.1 rad/s; linear velocity is 153.1 m/s; centripetal acceleration 20835.2 m/s² and 2123.8 g.
What is the angular velocity of the propeller?
The angular velocity of the propeller in rad/s is given as follows:
1 rev/m = 2π/60 rad/s.1300 rev/min = 1300 * 2π/60 = 136.1 rad/s.
b. The linear velocity, v = radius * angular velocity
Linear velocity, v = 2.25/2 * 136.1
v = 153.1 m/s
c. Centripetal acceleration, \(a = \frac{v^{2}}{r}\)
\(a = \frac{(153.1)^{2}}{1.125} = 20835.2\:ms^{2}\)
Centripetal acceleration in terms of g; \(g = \frac{20835.2}{9.81} = 2123.8 g\)
Therefore, the angular velocity of the propeller is 136.1 rad/s; linear velocity is 153.1 m/s; centripetal acceleration 20835.2 m/s² and 2123.8 g.
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It is the final seconds of an ice hockey game between the Flyers and the Bruins. The Bruins are down by 1 point. With 20 s left in the game, the Bruins pull the goalie and have him play as a forward in an attempt to tie the game. The Flyers successfully defend their goal for 9 s. With only 1.25 s remaining on the game clock, a Flyer shoots the puck on the ice past the skates and sticks of the other players and toward the Bruins' goal. The puck is 37 m from the goal when it leaves the stick with an initial horizontal velocity of 30 m/s. The shot is perfectly directed toward the empty goal, but the ice slows the puck down at a constant rate of 0.50 m/s2 as it slides toward the goal. None of the Bruins can stop the puck before it reaches the goal.
A. Where is the puck when the game clock reaches zero and the horn sounds to end the game?
B) Do the flyers win the game by 1 or 2 points?
Answer:
A
\(k = 0.11 \ m \) beyond the goal post
B
Given that the goal was score against the Bruins it then means that the Flyer won the game with 2 points
Explanation:
From the question we are told that
The amount of time left in the game is \(t = 20 \ s\)
The amount of time the goal was defended is \(t_1 = 9 \ s\)
The time remaining when the shot was made is \(t_2 = 1.25 \ s\)
The distance of the pluck from the goal is \(d = 37 \ m\)
The initial velocity of the pluck is \(u = 30 \ m/s\)
The acceleration of the pluck is \(a = -0.50 \ m/s^2\)
Generally the distance travel at the remaining time is mathematically represented as
\(D = u * t _2 + \frac{1}{2}* a* t_2\)
\(D = 30 * 1.25 - \frac{1}{2}* 0.50* 1.25^2\)
\(D = 37.11 \ m \)
So the position of the pluck when the game clock reaches zero is
\(k = D - d\)
=> \(k = 37.11 - 37\)
=> \(k = 0.11 \ m \) beyond the goal post
Given that the goal was score against the Bruins it then means that the Flyer won the game with 2 points
14. Ball A, weighing 30 N, experiences a gravitational force of 8.7 x 10-10 N from Ball B that is
at rest 3.0 m away. What is the mass of Ball B?
The mass of the Ball B is 1.35 x 10⁻⁶ kg.
Understanding Gravitational ForceGravitational Force is described by Newton's law of universal gravitation, which states that the force between two objects is directly proportional to the product of their masses and inversely proportional to the square of the distance between them.
The law of universal gravitation is important in many fields, including astronomy, physics, and engineering.
The gravitational force F between two objects of masses m1 and m2 separated by a distance r is given by:
F = G(m₁m₂)/r²
where G is the gravitational constant.
We can rearrange the equation to solve for the mass of Ball B:
m₂ = Fr²/Gm₁
Substituting the given values, we get:
m₂ = (8.7 x 10⁻¹⁰ N)(3.0 m)²/(6.6743 x 10¹¹ N(m^2/kg²))(30 N)
m₂ = 1.35 x 10⁻⁶ kg
Therefore, the mass of Ball B is approximately 1.35 x 10⁻⁶kg.
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If velocity is positive, which would most likely yield a negative acceleration?
O A final velocity that is gfaster than an initial velocity.
O Atime that is less than a half hour.
O An initial velocity that is faster than a final velocity.
O A time that is greater than a half hour.
The correct answer for velocity if acceleration is opposite is:
* An initial velocity that is faster than a final velocity
The given parameters are acceleration and initial velocity, it is asked to find the final speed of the body
In kinematics, position, velocity, and acceleration are quantities that are related.
The magnitude and direction of the acceleration are given by the resultant force on the body, in many cases the resultant force is constant in various time intervals, therefore the is acceleration is constant in these intervals even though it may have a different value in each one.
The velocity of the body is defined by the change in position of the body in the unit of time, in the most common case of a system with constant acceleration the velocity is given by
\(v_f\) = v₀ + a t
where v₀ and \(v_{f}\) are the initial and final velocities of the body, a is the acceleration and t is a time scalar: the bold letters indicate vectors.
If the velocity has a direction and the acceleration is contrary to the equation, we can see that the final velocity must decrease as time advances. Therefore the correct statement is: O An initial velocity that is faster than a final velocity.
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According to section 7.2 of the text, if you ignore atmospheric effects, the temperatures at the surface of objects in the solar system decreases approximately in proportion to the square root of the distance from the sun. In other words, if the temperature on earth is 300 kelvins, the temperature at the surface of an object located at 946 AU from the sun is roughly______Kelvins.
9.8
If the temperature on earth is 300 kelvins, the temperature at the surface of an object located at 946 AU from the sun is roughly 9.8 Kelvins.
How does the temperature at the surface of objects in the solar system varies with the distance from the sun?In general, when a planet gets further from the Sun, its surface temperature drops. The farther a planet is from the Sun, the colder its surface temperatures tend to be. Venus is an exception, as it has the highest surface temperature in our solar system due to its close closeness to the Sun and its thick atmosphere.
The geothermal gradient, or increase in temperature as one moves closer to the center of the Earth The rate at which the temperature of the Earth rises with depth is known as the geothermal gradient.
In the given question it is given that temperatures at the surface of objects in the solar system decreases approximately in proportion to the square root of the distance from the sun then if the distance from the sun is 946 AU then the temperature will be 9.8 K.
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answer and solution to this question
Frequency= 30 Hz, Period= 0.0333 s, Wave Number=15.708 rad/m, Wave Function= y(x, t) = 0.05 sin(15.708x - 94.248t), Transverse displacement= -0.013 m, Time= 0.297 s.
How to calculate the frequency?(a) To find the frequency (f), we can use the equation: wave speed = frequency x wavelength. Rearranging this equation, we get:
frequency = wave speed / wavelength
Substituting the given values, we get:
frequency = 12 m/s / 0.4 m = 30 Hz
Therefore, the frequency of the wave is 30 Hz.
To find the period (T), we can use the equation:
period = 1 / frequency
Substituting the frequency value we just calculated, we get:
period = 1 / 30 Hz = 0.0333... s (rounded to four decimal places)
Therefore, the period of the wave is approximately 0.0333 s.
To find the wave number (k), we can use the equation:
wave number = 2π / wavelength
Substituting the given values, we get:
wave number = 2π / 0.4 m = 15.708 rad/m (rounded to three decimal places)
Therefore, the wave number of the wave is approximately 15.708 rad/m.
(b) The wave function for a transverse wave on a string is given by:
y(x, t) = A sin(kx - ωt + φ)
where A is the amplitude, k is the wave number, x is the position of the point on the string, t is the time, ω is the angular frequency, and φ is the phase constant.
We already know the values of A, k, and ω from the previous calculations. To find φ, we can use the given initial condition: "at t = 0 end of the string has zero displacement and is moving upward". This means that y(0,0) = 0 and ∂y/∂t(0,0) > 0. Substituting these conditions into the wave function, we get:
0 = A sin(0 + φ)
∂y/∂t = -Aω cos(0 + φ)
Since sin(0 + φ) = sin(φ) = 0 (because sin(0) = 0), we get:
φ = nπ, where n is an integer
Since cos(0 + φ) = cos(φ) = 1 (because cos(0) = 1) and ∂y/∂t(0,0) > 0, we get:
n = 0 or 2
Therefore, the possible values of φ are 0 or 2π.
Substituting the values of A, k, ω, and φ, we get:
y(x, t) = 0.05 sin(15.708x - 94.248t)
Therefore, the wave function describing the wave is:
y(x, t) = 0.05 sin(15.708x - 94.248t)
(c) To find the transverse displacement of a wave at x = 0.25 m and t = 0.15 s, we can use the wave function we just found:
y(0.25, 0.15) = 0.05 sin(15.708(0.25) - 94.248(0.15))
y(0.25, 0.15) ≈ -0.013 m (rounded to three decimal places)
Therefore, the transverse displacement of the wave at x = 0.25 m and t = 0.15 s is approximately -0.013 m.
(d) To find how much time must elapse from the instant in part (c) until the point at x = 0.25 m has zero displacement,
From part (c), we know that the transverse displacement of the wave at x = 0.25 m and t = 0.15 s is approximately -0.013 m. We need to find the time it takes for this point to return to zero displacement.
We can use the wave function we found in part (b) and set y(0.25, t) = 0:
0 = 0.05 sin(15.708(0.25) - 94.248t)
Since sin(θ) = 0 when θ = nπ (where n is an integer), we get:
15.708(0.25) - 94.248t = nπ
Solving for t, we get:
t = (15.708(0.25) - nπ) / 94.248
To find the smallest positive value of t that satisfies this equation, we need to use the smallest positive value of n that makes the right-hand side of the equation positive (because we want to find the time it takes for the point at x = 0.25 m to return to zero displacement, which happens after the point has completed a full cycle). We can see from the equation that n must be an even integer to make the right-hand side positive. The smallest even integer greater than zero is 2. Substituting n = 2, we get:
t = (15.708(0.25) - 2π) / 94.248
t ≈ 0.297 s (rounded to three decimal places)
Therefore, the time it takes for the point at x = 0.25 m to return to zero displacement is approximately 0.297 s.
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Find a unit vector in the direction of the resultant of vectors A = 21-3) + k, B = i +} + 2k and C = 3î - 2ĵ + 4k
The unit vector in the direction of the resultant of vectors A, B, and C is: (6i - j + 3k) / √46
To find a unit vector in the direction of the resultant of vectors A, B, and C, we need to calculate the sum of these vectors and then normalize the resulting vector.
Given:
Vector A = (2i + 1j - 3k)
Vector B = (i + j + 2k)
Vector C = (3i - 2j + 4k)
To find the resultant vector R, we add these vectors together:
R = A + B + C
= (2i + 1j - 3k) + (i + j + 2k) + (3i - 2j + 4k)
= (2i + i + 3i) + (1j + j - 2j) + (-3k + 2k + 4k)
= 6i - j + 3k
Now, to obtain a unit vector in the direction of R, we divide R by its magnitude:
Magnitude of R = √(6² + (-1)² + 3²)
= √(36 + 1 + 9)
= √46
Unit vector in the direction of R = R / Magnitude of R
= (6i - j + 3k) / √46
Therefore, the unit vector in the direction of the resultant of vectors A, B, and C is:
(6i - j + 3k) / √46
It's important to note that the unit vector represents the direction of the resultant vector, while its magnitude is always 1. By normalizing the resultant vector, we obtain a unit vector that points in the same direction but has a magnitude of 1, providing information solely about the direction of the resultant.
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If the ice-point and the steam-point temperatures on an unknown scale X are 50°X and 200°X, respectively, then what is the reading in °X for a temperature of 60°C?
Answer:
Answer:
140 degree X is the reading in °X for a temperature of 60°C
Explanation:
As we know that the temperature scale is always linear scale
So we can compare two scales with the linear variation
\frac{T - 0}{100 - 0} = \frac{T_X - 50}{200 - 50}100−0T−0=200−50TX−50
now we have
\frac{T}{100} = \frac{T_X - 50}{150}100T=150TX−50
now we know in degree Celcius the temperature is given as
T = 60 ^oCT=60oC
so we have
\frac{60}{100} = \frac{T_X - 50}{150}10060=150TX−50
T_X = 140 ^oXTX=140oX
#Learn
Topic : Temperature Scale
In a dart gun, a spring with k = 400.0 N/m is compressed 8.0 cm when the dart (mass m = 20.0 g) is loaded.
(a) What is the muzzle speed of the dart when the spring is released? Ignore friction.
(b) If the dart gun is located on a table top 2.2 m above the ground, and once the spring is released, it remains compressed by 4 cm, what is the final speed of the dart as it hits the ground?
The muzzle speed of the dart when the spring is released is 11.3 m/s
The given parameters are
k = spring constant = 400 N/m
m = mass = 20 g = 0.02 kg
Compression = x = 8 cm = 0.08 m
According to the question,
When the dart is loaded, the potential energy is converted into kinetic energy.
Potential Energy (P.E.)
\(P.E. =\frac{1}{2} kx^{2}\)
Putting the values,
\(P.E. =\frac{1}{2} *400*(0.08)^{2} = 1.28\)
Now, Kinetic Energy (K.E.)
K. E. = \(\frac{1}{2} mv^{2}\) = \(\frac{1}{2} *0.02*v^{2}= 0.01 v^{2}\)
Now, P.E. = K.E.
\(0.01 v^{2} = 1.28 \\\\v^{2} =\frac{1.28}{0.01} \\\\v^{2} = 128\\ \\v = 11.3\)
Hence, the muzzle speed of the dart when the spring is released is 11.3 m/s
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How can people reconcile technology with environmental preservation?