Answer:
it is quicker
Explanation:
An object of mass M on string is whirled with increasing speed in a horizontal circle_ as shown above. When the string breaks; the object has speed vo and the circular path has radius R and is height h above the ground. Neglect air friction. Determine the following; expressing all answers in terms of y Vo, and g. A) The time required for the object to hit the ground after the string breaks. B) The horizontal distance the object travels from the time the string breaks until it hits the ground: C) Determine the tension in the string just before the string breaks. Express your answer in terms of M Vo, and g.
The time required for the object to hit the ground after the string breaks, we can use the equation of motion in the vertical direction. Since the object is initially at height h above the ground and is in free fall.
The equation can be written as:
h = (1/2)gt^2
Solving for t:
t = sqrt((2h) / g)
So, the time required for the object to hit the ground after the string breaks is given by the square root of 2h divided by g.
The horizontal distance the object travels from the time the string breaks until it hits the ground, we can use the horizontal velocity of the object. The horizontal velocity remains constant since there is no horizontal force acting on the object.
The horizontal distance can be calculated using the equation:
d = v * t
where v is the horizontal velocity and t is the time calculated previously.
The tension in the string just before it breaks can be determined using the centripetal force required to keep the object in circular motion. The tension in the string provides this force. The centripetal force can be calculated using the equation:
F = (M * v^2) / R
where M is the mass of the object, v is the speed of the object, and R is the radius of the circular path.
So, the tension in the string just before it breaks is given by the mass of the object multiplied by the square of its speed, divided by the radius of the circular path.
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what is the maximum tangential speed max of the child if she rides on the edge of the platform?
The maximum tangential speed (max) of the child if she rides on the edge of the platform is max = √(r ×g) .
The centrifugal force on the child is equal to the product of the child's mass (m) and the radial acceleration (a) due to the spinning platform. The radial acceleration is equal to the square of the tangential speed (v) divided by the radius of the platform (r), so the centrifugal force on the child can be written as:
Fc = m * (v² / r)
The maximum tangential speed (max) that the child can attain without falling off the platform is when the centrifugal force is equal to the weight of the child, which is given by:
Fg = m × g
where g is the acceleration due to gravity.
Equating the two equations and solving for the maximum tangential speed gives:
max = √(r × g)
Therefore, the maximum tangential speed (max) of the child if she rides on the edge of the platform is given by the square root of the product of the radius of the platform and the acceleration due to gravity.
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A -F capacitor ( ) is charged to V and then disconnected. One can model the charge leakage of the capacitor with a RC circuit with no voltage source and the resistance of the air between the capacitor plates. On a cold dry day, the resistance of the air gap is ; on a humid day, the resistance is . How long will it take the capacitor voltage to dissipate to half its original value on each day?
The capacitor voltage dissipates to half its original value in 0.693RC seconds. The time depends on the resistance of the air gap, which is different on a dry and humid day.
The process of a charged capacitor losing its charge due to the resistance of the air between its plates is modelled by an RC circuit. The time constant of an RC circuit is given by the product of the resistance and capacitance values, which determines the rate at which the capacitor discharges. On a cold, dry day, the resistance value is high, and the time constant is larger, resulting in a slower discharge rate. On a humid day, the resistance is lower, and the time constant is smaller, resulting in a faster discharge rate. The half-life of a capacitor discharge is equal to one time constant, so the time it takes for the capacitor voltage to dissipate to half its original value will be longer on a cold, dry day compared to a humid day.
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if n = 1.28, what is the largest angle of incidence, θa , for which total internal reflection will occur at vertical face?
The largest angle of incidence, θa , for which total internal reflection will occur at vertical face is any angle greater than 51.06°.
To find the largest angle of incidence (θa) for total internal reflection at the vertical face, you need to use the critical angle formula:
Critical Angle (θc) = arcsin(1/n)
Where n is the refractive index.
In this case, n = 1.28. Plug the value into the formula:
θc = arcsin(1/1.28)
θc ≈ 51.06°
For total internal reflection to occur, the angle of incidence (θa) must be greater than the critical angle. Therefore, the largest angle of incidence for which total internal reflection will occur at the vertical face is any angle greater than 51.06°.
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I think this is physics?
A student wants to calculate the density of the two objects shown below:
A Metal Cube and a Small Statue.
Describe the methods that the student should use to calculate the densities of the two objects.
ASAP please this piece of work is already late XD
Answer:
Okay
Explanation:
First we should quickly remind ourselves of the equation for density:density= mass/ volumeTo calculate the density we need a method of measuring the mass of each object and another method for measuring the volume of each object. To measure the mass in both cases we can simply use a measuring balance. To measure the volume we will need to use 2 separate methods. For the cube we can simply measure the length, height and depth with a ruler, multiply our measurements and we obtain the volume. The statue is a little more tricky because it has an irregular shape so we can't use the ruler anymore. Instead we should use graduated tank/trough of water. First of all measure the amount of water in the tank before putting in the statue. Then submerge the statue in the water and take another measurement of the volume of water in the tank. The statue will displace the water in the tank giving a higher value. We finally subtract the initial volume from the final volume and we should obtain the volume of the statue.We now have all the measurements necessary to calculate the density of both objects!
What is the acceleration of the object?
suppose you are observing a distant galaxy whose light has taken 12 billion years to reach us. what is the maximum age that this galaxy could have been when it emitted the light we are observing now? (assume the age of the universe is about 14 billion years.) suppose you are observing a distant galaxy whose light has taken 12 billion years to reach us. what is the maximum age that this galaxy could have been when it emitted the light we are observing now? (assume the age of the universe is about 14 billion years.) about 4 billion years old about 2 billion years old about 10 billion years old about 12 billion years old
The maximum age that this galaxy could have been when it emitted the light we are observing now is about 2 billion years old.
If the light from a distant galaxy has taken 12 billion years to reach us, and we assume the age of the universe is about 14 billion years, we can calculate the maximum age that this galaxy could have been when it emitted the light we are observing now.
The maximum age of the galaxy when it emitted the light we observe now can be calculated by subtracting the time it took for the light to reach us from the current age of the universe.
Maximum age of the galaxy = Age of the universe - Time taken for light to reach us
Maximum age of the galaxy = 14 billion years - 12 billion years
Maximum age of the galaxy = 2 billion years.
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If a riding lawnmower engine exerts 19 hp in one minute to move the mower, how much work is done? (Hint convert: 1 watt equals 0.00135962 hp)
Answer:
Work done = 838470 Joules.
Explanation:
Given the following data;
Power = 19 hp
Time = 1 minute to seconds = 60 seconds.
Next, we would convert the unit of power in "hp" to "Watt."
1 Watt = 0.00135962 horsepower
x Watt = 19 horsepower
Cross-multiplying, we have;
19 = 0.00135962x
x = 19/0.00135962
x = 13974.5 Watts.
Now, to find the work done in moving the mower;
Work done = power * time
Substituting into the formula, we have;
Work done = 13974.5 * 60
Work done = 838470 Joules.
Describe and identify problems relating to data management
Problems with data management may have a detrimental impact on a variety of issues. Bad risk management choices, data loss, information leakage, unauthorised, data pyramids, compliance with laws, an unsafe environment, a shortage of resources, etc. are instances among these.
What issues surround the handling of data?
These are a few potential issues in managing scientific, financial, or administration data that have been briefly explained.
Technical information not adequately recorded.
The administration of performance specifications is not under the PI's control.
Data not kept on file by the organization.
improper maintenance of financial or administrative data.
What would you say is data management?
Data administration is the act of gathering, arranging, and using data to job in an effective, economy, and judgement call.
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what two factors affect how much gravitational potential energy an object-earth system has?
Answer:
height and mass
Explanation:
gpe = mass x height x gravitational field strength
what are metals?
I need accurate answers
Answer:
Metals are elements that forms positive ions by losing one or more electrons in a chemical reaction
Explanation:
Please help!!! use the information in table 3 to determine the mass in kilograms of each subatomic particle
proton - mass 1.6726 times 10 -24
neutron 1.6749 times 10 - 24
electron 9.1093 times 10 -28
Thanks
The mass of a proton is 2.7827 x 10^-27 kg, the mass of a neutron is 2.8149 x 10^-27 kg, and the mass of an electron is 1.5107 x 10^-30 kg.
What are subatomic particles?A subatomic particle is a particle that is smaller than an atom, and it is the building block of an atom. The term "subatomic" refers to the particles that make up an atom, namely protons, neutrons, and electrons.
Protons and neutrons are found in the nucleus of an atom, while electrons are found in the electron shells surrounding the nucleus. Protons have a positive charge, electrons have a negative charge, and neutrons have no charge. The number of protons in the nucleus of an atom determines what element the atom is, while the number of neutrons and electrons can vary within an element, resulting in different isotopes and ionization states.
Other subatomic particles include quarks, leptons, and bosons, which are the particles that makeup protons, neutrons, and electrons, and which mediate fundamental forces such as the strong and weak nuclear forces, and the electromagnetic force. The study of subatomic particles is called particle physics.
Here in the Question,
To determine the mass of each subatomic particle in kilograms, we simply need to convert the values given in the table from scientific notation to standard notation by multiplying by 10 raised to the power of the exponent. We can then multiply this value by the appropriate conversion factor to obtain the mass in kilograms. The conversion factor for atomic mass units (amu) to kilograms is 1.66054 x 10^-27 kg/amu.
Using this conversion factor, we have:
1. Proton: (1.6726 x 10^-24 amu) x (1.66054 x 10^-27 kg/amu) = 2.7827 x 10^-27 kg
2. Neutron: (1.6749 x 10^-24 amu) x (1.66054 x 10^-27 kg/amu) = 2.8149 x 10^-27 kg
3. Electron: (9.1093 x 10^-28 amu) x (1.66054 x 10^-27 kg/amu) = 1.5107 x 10^-30 kg
Therefore, the mass of a proton is 2.7827 x 10^-27 kg, the mass of a neutron is 2.8149 x 10^-27 kg, and the mass of an electron is 1.5107 x 10^-30 kg.
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what effect does an unbalanced force have on an object?
Answer:
An unbalanced force can change an object's motion. An unbalanced force acting on a still object could make the object start moving. An unbalanced force acting on a moving object could make the object change direction, change speed, or stop moving.
suppose someone would like to lease state-owned lands for oil and gas production. with whom should they negotiate?
If someone would like to lease state-owned lands for oil and gas production, they should negotiate with the appropriate government agency responsible for managing the lands.
In the United States, this agency is typically the Bureau of Land Management (BLM), which manages millions of acres of federal lands, including lands with potential for oil and gas development. The BLM offers competitive leasing programs that allow individuals and companies to bid on leasing rights for specific parcels of land. The leasing process typically involves submitting an application, conducting an environmental analysis, participating in a lease sale auction. Ultimately, negotiation and leasing of state-owned lands for oil and gas production is subject regulations and oversight by government agency responsible for managing lands.
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Can someone tell me which is which on what i put i dont know what i should put
an organism that cannot make its own food called
Answer:
heterotroph
Explanation:
Answer:
a predator cannot make its own food
What are two ways the brain can be manipulated
Answer:
Meditation and Positive Thinking
Explanation:
what does a pair of shoes weigh on mars?
Answer:
0.76 lbs (if shoes 2lbs)
Explanation:
Gravity on Mars is only ~38% as strong as it is on Earth, so objects would only weigh ~38% of their Earth weight.
Two resistors, A and B, are connected in series to a 6.0 V battery. A voltmeter connected across resistor A measures a potential difference of 4.0 V. When the two resistors are connected in parallel across the 6.0 V battery, the current in B is found to be 2.0 A. Find the resistances of A and B.
Answer:
Resistance of resistor A = 6.0 Ω and resistance of resistor B = 3.0 Ω
Explanation:
When the two resistors are in series, let V₁ = voltage in resistor A and R₁ = resistance of resistor A and V₂ = voltage in resistor B and R₂ = resistance of resistor B.
Given that V₁ + V₂ = 6.0 V and V₁ = 4.0 V,
V₂ = 6.0 V - V₁ = 6.0 V - 4.0 V = 2.0 V
Also, let the current in series be I.
So, V₁ = IR₁ and V₂ = IR₂
I = V₁/R₁ and I = V₂/R₂
equating both expressions, we have
V₁/R₁ = V₂/R₂
4.0 V/R₁ = 2.0 V/R₂
dividing through by 2.0 V, we have
2/R₁ = 1/R₂
taking the reciprocal, we have
R₂ = R₁/2
R₁ = 2R₂
From the parallel connection, let V₁ = voltage in resistor A and R₁ = resistance of resistor A and V₂ = voltage in resistor B and R₂ = resistance of resistor B. Since it is parallel, V₁ = V₂ = V = 6.0 V
Also, V₂ = I₂R₂ where I₂ = current in resistor B = 2.0 A and R₂ = resistance of resistor B
So, R₂ = V₂/I₂
= 6.0 V/2.0 A
= 3.0 Ω
R₁ = 2R₂
= 2(3.0 Ω)
= 6.0 Ω
So, resistance of resistor A = 6.0 Ω and resistance of resistor B = 3.0 Ω
The resistance of A is 6Ω while for B is 3Ω.
Definition of potential differencePotential difference is the amount of work done in moving a unit charge from one point to another.
When the two resistors are connected in parallel across the 6.0 V battery, the current in B is found to be 2.0 A, hence:
2 * Rb = 6 V
Rb = 3Ω
For the series connection:
I * 3 = (6 - 4)
I = 2/3 A
Hence:
(2/3) * Ra = 4
Ra = 6Ω
The resistance of A is 6Ω while for B is 3Ω.
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how long would it take a radio wave whose frequency is 7.25 × 105 hz to travel from mars to earth if the distance between the two planets is approximately 8.00 × 107 km? 1
It would take a radio wave whose frequency is 7.25 × 10⁵ Hz to travel from Mars to Earth approximately 266.67 seconds or 4.44 minutes.
The speed of light is 3 × 10⁸ m/s. You can use this information to calculate the time it would take a radio wave to travel from Mars to Earth if the distance between the two planets is approximately 8.00 × 10⁷ km. Given that the frequency of the radio wave is 7.25 × 10⁵ Hz, we can find its wavelength by using the formula:
c = λfwhere λ is the wavelength, c is the speed of light, and f is the frequency.
Substituting the given values: c = 3 × 10⁸ m/sf = 7.25 × 10⁵ Hz, we can find the wavelength:λ = c / f = 3 × 10⁸ / 7.25 × 10⁵ = 413.79 m
So the wavelength of the radio wave is 413.79 m. Now, we can use the formula for the speed of light to calculate the time it would take the radio wave to travel from Mars to Earth: d = vt where d is the distance, v is the speed, and t is the time.
Substituting the given values: d = 8.00 × 10⁷ km = 8.00 × 10¹⁰ m (converting km to m)v = c = 3 × 10⁸ m/st = d / v = (8.00 × 10¹⁰) / (3 × 10⁸) = 266.67 s
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HELP THIS IS DUE TODAY who ever answers first (correctly and gives explanation will get brainly)
How much power does a cordless phone use if it draws 0.50 A of current at 6.0 V?
i need it in watts so please write it in forms of Watt
Answer:
3.0 W
I actually had this question before BUT I have no clue how to explain it. I haven't done this in so long. I apologize but that is the correct answer.
Answer:3.0 W
Explanation:
P=VI
P= (6.0 V) (5.0 A)
P= 3.0 W
As an aeroplane decelerates, its kinetic energy decreases. Suggest what happens to this energy
they are converted into thermal and sound energy as well as the kinetic energy in the air
Compile and share a list of "highly applicable tips" (8-10
points) related to organizational behavior and leadership. To
format your points properly, position yourself as a management
consultant who i
Each organization is unique, so tailor these tips to fit your specific context and needs. As a management consultant, I recommend assessing your organization's current state and identifying areas for improvement to implement these tips effectively.
As a management consultant, here is a compiled list of highly applicable tips related to organizational behavior and leadership:
1. Foster a positive organizational culture: Create a work environment that values collaboration, open communication, and employee well-being. Encourage a culture of respect, trust, and support.
2. Lead by example: As a leader, set a positive example through your actions and behaviors. Demonstrate the values and behaviors you expect from your team members.
3. Effective communication: Communication is crucial for building strong relationships and ensuring clarity. Practice active listening, provide constructive feedback, and encourage open and honest communication channels within the organization.
4. Empower and delegate: Trust your team members and empower them to take ownership of their work. Delegate tasks effectively, matching responsibilities with individuals' strengths and skills.
5. Encourage innovation and creativity: Foster an environment that encourages new ideas, creativity, and innovation. Provide opportunities for employees to contribute their ideas and reward innovative thinking.
6. Develop and support talent: Invest in employee development and provide opportunities for growth and learning. Offer training programs, mentorship, and coaching to help employees reach their full potential.
7. Build strong teams: Focus on building cohesive and high-performing teams. Foster collaboration, encourage diversity of thought, and promote teamwork to achieve collective goals.
8. Embrace change and adaptability: Organizational success often relies on the ability to adapt to changing circumstances. Encourage a mindset of flexibility, adaptability, and continuous improvement.
9. Practice ethical leadership: Uphold high ethical standards and lead with integrity. Make ethical decisions, promote fairness, and hold yourself and others accountable for ethical conduct.
10. Recognize and appreciate employees: Acknowledge and appreciate the contributions of your team members. Celebrate achievements, provide recognition, and offer rewards and incentives to motivate and retain talent.
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the ring and the disk shown above have identical masses, radii, and velocities, and are not attached to each other. if the ring and the disk each roll without slipping up an inclined plane, how will the distances that they move up the plane before coming to rest compare?
The ring will move farther than will the disk.
The torque required to achieve a desired angular acceleration about a rotational axis depends on the moment of inertia of a rigid body.
The moment of inertia of a ring is given by the following equation \(I=mr^{2}\)
similarly, the moment of inertia of a disk is \(I=m\frac{r^{2} }{2}\)
Where, m and r is the mass and the radii of the ring and the disc.
The body's mass distribution and the axis selected to affect the moment of inertia, with larger moments requiring more torque to change the rotation rate. The object with the lowest moment of inertia will descend to the bottom first because it is resistance to rotational motion.
Therefore the disc will reach the bottom first, but due to the higher moment of inertia than the disc the ring will move farther than the disc.
The question is incomplete. The correct question is
A ring and a disk have identical masses, radii and velocities and are not attached to each other. If they each roll without slipping up an inclined plane, how will the distances that they move up the plane before coming to rest compare?
a. The ring will move farther than the disk.
b. The disk will move farther than the ring.
c. The ring and the disk will move equal distances.
d. The relative distances depend on the angle of elevation of the plane.
e. The relative distances depend on the length of the plane.
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The average kinetic energy of the molecules of an ideal gas at 10∘C has the value K10. At what temperature T1 (in degrees Celsius) will the average kinetic energy of the same gas be twice this value, 2K10? Express the temperature to the nearest integer. View Available Hint(s) T1 T 1 T_1 = nothing ∘C Part B The molecules in an ideal gas at 10∘C have a root-mean-square (rms) speed vrms. At what temperature T2 (in degrees Celsius) will the molecules have twice the rms speed, 2vrms? Express the temperature to the nearest integer. View Available Hint(s) T2 T 2 T_2 = nothing ∘C
Answer:
A) T1 = 566 k = 293°C
B) T2 = 1132 k = 859°C
Explanation:
A)
The average kinetic energy of the molecules of an ideal gas is givwn by the formula:
K.E = (3/2)KT
where,
K.E = Average Kinetic Energy
K = Boltzman Constant
T = Absolute Temperature
At 10°C:
K.E = K10
T = 10°C + 273 = 283 K
Therefore,
K10 = (3/2)(K)(283)
FOR TWICE VALUE OF K10:
T = T1
Therefore,
2 K10 = (3/2)(K)(T1)
using the value of K10:
2(3/2)(K)(283) = (3/2)(K)(T1)
T1 = 566 k = 293°C
B)
The average kinetic energy of the molecules of an ideal gas is given by the formula:
K.E = (3/2)KT
but K.E is also given by:
K.E = (1/2)(m)(vrms)²
Therefore,
(3/2)KT = (1/2)(m)(vrms)²
vrms = √(3KT/m)
where,
vrms = Root Mean Square Velocity of Molecule
K = Boltzman Constant
T = Absolute Temperature
m = mass
At
T = 10°C + 273 = 283 K
vrms = √[3K(283)/m]
FOR TWICE VALUE OF vrms:
T = T2
Therefore,
2 vrms = √(3KT2/m)
using the value of vrms:
2√[3K(283)/m] = √(3KT2/m)
2√283 = √T2
Squaring on both sides:
(4)(283) = T2
T2 = 1132 k = 859°C
A) The temperature at which the average kinetic energy will have a value of 2K10 is; T1 = 293 °C
B) The temperature at which the molecules have twice the rms speed, 2vrms is; T2 = 859 °C
A) We are given;
Initial temperature; T = 10°C = 283 K
Initial kinetic energy; KE = K10
Final kinetic energy; KE1 = 2K10
Now,formula for average kinetic energy of the molecules of an ideal gas is given as;
KE = (3/2)kT
Where;
k is Boltzmann constant
T is temperature
We are told that in the second case, KE = 2K10. Thus;
2K10 = (3/2)kT1
K10 = ¾kT1 - - - (eq 2)
In the first instance, we have;
K10 = (3/2)kT - - - (eq 1)
Put (3/2)kT for K10 in eq 2 to get;
(3/2)kT = ¾kT1
k will cancel out to get;
(3/2)T = ¾T1
Make T1 the subject to get;
T1 = 2T
Thus;
T1 = 2 × 283
T1 = 566 K
Converting to °C gives;
T1 = 293 °C
B) We want to find the temperature T2 (in degrees Celsius) at which the molecules will have twice the rms speed, 2v_rms.
Formula for kinetic energy is also;
KE = ½mv²
Thus;
½m(v_rms)² = (3/2)kT
v_rms = √(3kT/m) - - - (eq 1)
When rms speed is 2v_rms, we have;
½m(2v_rms)² = (3/2)kT2
v_rms = √(¾kT2/m) - - - (eq 2)
Thus;
√(3kT/m) = √(¾kT2/m)
Square both sides to get;
(3kT/m) = (¾kT2/m)
4T = T2
T2 = 283 × 4
T2 = 1132 K
Converting to °C gives;
T2 = 859 °C
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An individual electron can be thought of as a spinning sphere of negative charge. A charged spinning sphere will generate a magnetic field, whose direction is indicated by the magnetic moment of the object, vector mu. In what direction will the electron rotate, based on the direction of its magnetic moment and the direction of the uniform magnetic field that it is immersed in?
Answer:
based on the direction of its magnetic moment and the direction of the uniform magnetic field that it is immersed in, the electron will rotate in a clockwise direction
Does voltage quantify the electrical potential energy?
Answer:
electric potential energy per unit charge
Explanation:
I think im not quite sure
if the jet in ngc 5128 is traveling at 5000 km/s and is 40 kpc long, how long will it take for gas to travel from the core of the galaxy to the end of the jet?
It would take approximately 2.4688 × 10^17 seconds or 7.82 million years for gas to travel from the core of the galaxy to the end of the jet, assuming a constant speed of 5000 km/s.
To calculate the time it would take for gas to travel from the core of the galaxy to the end of the jet, we need to use the formula: time = distance / speed.
Given that the jet in NGC 5128 is traveling at 5000 km/s and is 40 kpc (kiloparsecs) long, we first need to convert the distance from kpc to km. 1 kpc = 3.086 × 10^16 meters, which means 1 kpc = 3.086 × 10^19 km.
Therefore, the length of the jet in kilometers is 40 x 3.086 × 10^19 km = 1.2344 × 10^21 km.
Now we can calculate the time it would take for gas to travel from the core of the galaxy to the end of the jet as follows:
time = distance / speed
time = 1.2344 × 10^21 km / 5000 km/s
time = 2.4688 × 10^17 seconds
So, it would take approximately 2.4688 × 10^17 seconds or 7.82 million years for gas to travel from the core of the galaxy to the end of the jet, assuming a constant speed of 5000 km/s.
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One type of slingshot can be made from a length of rope and a leather pocket for holding the stone. The stone can be thrown by whirling it rapidly in a horizontal circle and releasing it at the right moment. Such a slingshot is used to throw a stone from the edge of a cliff, the point of release being 25.6 m above the base of the cliff. The stone lands on the ground below the cliff at a point X. The horizontal distance of point X from the base of the cliff (directly beneath the point of release) is 34.4 times the radius of the circle on which the stone is whirled. Determine the angular speed of the stone at the moment of release
Answer:
the angular speed of the stone at the moment of release is 15.05 rad/s
Explanation:
Given the data in the question;
The point of release ( height ) h = 25.6 m
the time of the fall of the stone will be;
⇒√( 2h/g )
we know that g = 9.81 m/s
so we substitute
t = √( (2 × 25.6 m) / 9.81 m/s )
t = √( 51.2 / 9.81 m/s )
t = √( 5.219164 s )
t = 2.285 s
Now, let v represent velocity at the time of release
them v × t ~ v × 2.285 s is the horizontal distance traveled.
Given that; The horizontal distance of point X from the base of the cliff (directly beneath the point of release) is 34.4 times the radius of the circle.
so
v × 2.285 = 34.4 × radius
Now, if the angular speed is ω then velocity at the time of release will be;
v = radius × ω
hence;
(radius × ω) × 2.285 = 34.4 × radius
radius cancels each other out and we have;
ω × 2.285 = 34.4
ω = 34.4 / 2.285
ω = 15.05 rad/s
Therefore, the angular speed of the stone at the moment of release is 15.05 rad/s
The gray whale travels an average of 120 km per day as it migrates
A gray whale travels an average of 120 km per day as it migrates is an example of Speed.
Speed is the ratio of distance to time taken. It is given by:
Speed = Distance / time
Speed is a scalar quantity, hence it has magnitude and no direction.
Hence, A gray whale travels an average of 120 km per day as it migrates is an example of Speed since the direction of the whale is not given.
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