Before bouncing back, the ball achieved a maximum height of 5.1 m.
How to calculate height?The initial velocity of the ball when it was thrown downwards, u = 10 m/s
The displacement of the ball when it hit the ground, s = -1 m (negative because it is in the downward direction)
When the ball bounces back, its final velocity is the same as the initial velocity. So, the final velocity, v = 10 m/s
Let's use the equation for motion with constant acceleration to find the time taken by the ball to hit the ground:
s = ut + (1/2)at²
-1 = 10t + (1/2)(-9.8)t² (taking acceleration due to gravity as -9.8 m/s²)
-1 = 10t - 4.9t²
4.9t² - 10t - 1 = 0
Using the quadratic formula:
t = (10 ± √(10² - 4(4.9)(-1))) / (2(4.9))
t ≈ 1.02 s (ignoring the negative root as time cannot be negative)
Now, let's use the equation for motion with constant acceleration again to find the maximum height reached by the ball:
v² = u² + 2as
10² = 0² + 2(-9.8)s (taking upward direction as positive)
s = 5.1 m
Therefore, the ball reached a maximum height of 5.1 m before bouncing back.
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two cars are initially (2.50 c) km apart on a straight road. if the cars are moving toward each other, car 1 with a speed of (7.50 a) m/s and car 2 with a speed of (5.40 b) m/s, how many seconds will it take before the cars meet? round your answer to three significant figures.
The time by which the two cars initially 2.50km apart and moving towards each other meet is 194 seconds.
The two cars are initially 2.50km apart. So the distance between the two cars,d= 2.50km. The speed of car 1 is v₁=7.50 m/sec. The speed of car 2 is v₂=5.40 m/sec. Let t be the time at which the two cars meet. Then at time t, the distance traveled by the two cars will be equal to the distance between them initially.
So, the distance d₁ traveled by car1 is 7.50×t m. The distance d₂ traveled by car 2 is 5.40×t m. Now d₁+d₂=2500, 7.5×t+5.4×t=2500, 12.9×t=2500, t= 2500/12.9, t=193.8 secs. So the time by which the two cars meet is 194 secs.
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What is the new period if the pendulum is taken to a planet that has 4 times the mass and 4 times the radius of earth
The new period of the pendulum when it is taken to the new planet is double of its period on Earth.
Period of a pendulumThe period of a pendulum is given by the following formula;
\(T = 2\pi \sqrt{\frac{l}{g} }\)
where;
g is acceleration due to gravity of the pendulumL is length of the pendulumAcceleration due to gravity of the new planetThe acceleration due to gravity of the new planet is calculated as follows;
\(g_E = \frac{GM_E}{R_E^2} = 9.81 \ m/s^2 \\\\g(new \ planet) = \frac{G(4M_E)}{(4R_E)^2} = \frac{4GM_E}{16R_E^2} = \frac{GM_E}{4R_E^2} = \frac{9.81}{4} = 2.45 \ m/s^2\)
New period of the pendulum\(T = 2\pi \sqrt{\frac{l}{g} } \\\\T =\frac{2\pi \sqrt{l} }{\sqrt{g} } \\\\T_1\sqrt{g_1} = T_2\sqrt{g_2} \\\\T_E\sqrt{g_E} = T\sqrt{g} \\\\T = \frac{T_E\sqrt{g_E}}{\sqrt{g} } \\\\T = \frac{T_E \times \sqrt{9.81} }{\sqrt{2.45} } \\\\T = 2T_E\)
Thus, the new period of the pendulum when it is taken to the new planet is double of its period on Earth.
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Please help asdfghjkll=
Answer:
Oh god
i have nooooo idea
People hoping to travel to other worlds are faced with huge challenges. One of the biggest is the time required for a journey. The nearest star is 4.1×1016m 4.1 × 10 16 m away. Suppose you had a spacecraft that could accelerate at 1.5 g g for two thirds of a year, then continue at a constant speed. (This is far beyond what can be achieved with any known technology.)How long would it take you to reach the nearest star to earth?
Answer:
It would take 8.22037 hrs away. Wouldn't it?
Explanation:
Because
4.11016
4.11016
15
= 8.22037
A car goes from rest to 25 m/s in 10 seconds. Determind the acceleration of the car.
Answer:
2.5m/s^2
Explanation:
a=velocity/time
a=25m/s/10s
a=2.5m/s^2
In a photovoltaic system, an inverter is required______. A) to Convert AC from the solar panel into DC of the grid B)connect the DC current of the solar panel to the AC current of an electrical grid. C) directly convert surplus electricity into heat. D) generate electricity from solar energy.
In a photovoltaic system, an inverter is required to connect the DC current of the solar panel to the AC current of an electrical grid. The correct option is B.
The solar panels in a photovoltaic system generate DC (direct current) electricity. However, most electrical grids operate on AC (alternating current) electricity.
The role of the inverter is to convert the DC electricity produced by the solar panels into AC electricity that can be fed into the electrical grid or used to power electrical devices.
The inverter performs the important function of converting the type of current to match the requirements of the grid, enabling the efficient utilization of solar energy and facilitating the integration of solar power systems with the existing electrical infrastructure.
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What is the mass of a book if it’s weight is 30N and the acceleration due to gravity is 9.8 m/s2
Acceleration due to gravity is 9.8 m/s² then the book weighs 3.06 kg in total.
How is the gravity of 9.8 m s2 determined?where d denotes the separation between the object's and the earth's centers. The acceleration of gravity is denoted by the symbol g in the first equation above. Its value on Earth is 9.8 m/s2. Alternatively put, the acceleration of gravity at sea level on earth's surface is 9.8 m/s2. Weight of a body on the moon is calculated as follows: mass of the body x lunar gravitational acceleration (30 x 1.62 = 48 N).
Mass times Gravitational Acceleration equals weight.
Weight plus gravitational acceleration equals mass.
mass = 30N ÷ 9.8 m/s²
mass = 3.06 kg
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suppose that the internal energy of a system has been increased, resulting in an increase in the temperature of the system. which of the following is the cause of this change?
No, according to the first law, whether a certain amount of energy is added by doing work on the system or by adding heat, the internal energy will change in the same way.
A thermodynamic system's total internal energy is defined as the energy it possesses. It consists of both internal kinetic energy and potential energy contributions, and it is the energy required to develop or prepare the system in its current internal condition. The system's energy gains and losses resulting from modifications to its internal state are tracked by this mechanism. It excludes all external energies from surrounding force fields as well as the kinetic energy of the system's overall motion. The first law of thermodynamics, which is based on the idea that an isolated system's internal energy is constant, is stated as the law of conservation of energy. An vast quality is the internal energy.
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please help i'm going to throw up from stress
Water at 20.0 °C is mixed with 120.0 g of ethyl alcohol at 10.0 °C in a thermally insulated container. If the final mixture has a temperature of 16.0 °C, how much water was added?
No links istg
Answer:
Explanation:
First of all, I used the specific heat of water as 4182 J/(kgC) and the specific heat of ethyl alcohol (EtOH) as 2440 J/(kgC); that means that we need the masses in kg, not g.
120.g = .1200 kg of ethyl alcohol. Now for the formula:
\(t_f=\frac{(m_{H2O}*spheat_{H2O}*temp_{H2O})+(m_{EtOH}*spheat_{EtOH}*temp_{EtOH})}{(m_{H2O}*spheat_{H2O})+(m_{EtOH}*spheat_{EtOH})}\) where spheat is specific heat.
Filling that horrifying-looking formula in with some values:
\(16.0=\frac{(x*4182*20.0)+(.1200*2440*10.0)}{(x*4182)+(.1200*2440)}\) and
\(16.0=\frac{83640x+2928}{4182x+292.8}\) and
16(4182x + 292.8) = 83640x + 2928 and
66912x + 4684.8 = 83640x + 2928 and
1756.8 = 16728x so
x = .105 kg and the amount of water added is 105 g
A standing sound wave in a pipe has five nodes and five antinodes. What is the harmonic number for this standing wave?
The harmonic number for this standing wave is 9th harmonic. When equal number of nodes and antinodes occur in a close pipe, It result to ninth harmonic.
How to determine the harmonic number?To determine the harmonic number for a standing wave containing both nodes and antinodes requires us to add one to their collective amount.
Thus when examining a particular example featuring five each of these points resulting in an overall count of ten in conjunction with this principle reveals that this specific instance has a working harmony value equivalenting nine.
Therefore, the harmonic number for this standing wave is 9th harmonic.
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Small pieces of tissue are attracted to a charged comb. Soon after sticking to the comb, the pieces of tissue are repelled from it. Explain.
The reason for small pieces of tissue being attracted to a charged comb is that the comb gains an electrical charge when it is rubbed against another material such as hair or cloth. This electrical charge causes the comb to have an excess of electrons, making it negatively charged.
The small pieces of tissue have a neutral charge and are attracted to the comb because opposites attract. However, once the tissue comes into contact with the comb, it receives some of the excess electrons, causing it to become negatively charged as well. This causes the tissue to become repelled from the comb since like charges repel each other.
Therefore, the small pieces of tissue are first attracted to the charged comb but then repelled from it due to the transfer of electrons.
When a charged comb comes in contact with small pieces of tissue, the pieces are initially attracted to it due to electrostatic forces. As the pieces touch the comb, they acquire the same charge through a process called charging by contact. Once the pieces have the same charge as the comb, they are repelled from it due to the like charges repelling each other.
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An airplane flies 1,592 miles east from phoenix, Arizona, to Atlanta, Georgia, in 3.68 hours. What is the average velocity of the plane? Round your answer to the nearest whole number
Answer:
433 mph
Explanation:
We know that
\(Velocity =\frac{Distance}{Time }\)...Eq(1)
Here,
Distance =1,592 miles
Time=3.68 hours
Putting the value of distance and Time in the Eq(1) We get
Velocity =\(\frac{1592\ miles}{3.68\ hours}\)
\(Velocity = 432.608\ mph\\Velocity = 433 mph\)
therefore Average velocity is 433 mph
a model helicopter pulls into a tight circular curve of radius 30.0 m. the 300 g helicopter is traveling at 90.0 km/h. what is the helicopter's centripetal force?
The centripetal force on the model helicopter is 6.25N.
The radius of the curve of the model helicopter is 30m and the mass of the helicopter is 300g, it is travelling with a speed of 90km/h.
Converting the speed into m/s, speed is 25m/s.
The centripetal force on a body is given by,
F = Mv²/r
Where,
F is the force,
V is the speed,
r is the radius,
So, putting values for helicopter,
F = 0.3 x 25 x 25/30
F = 6.25 N.
So, the centripetal force is 6.25 N.
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The chart lists four different kinds of atoms.
A chart titled Different Kinds of Atoms with the entries calcium, gold, argon, iodine.
What is true about all of these atoms?
They cannot be solids.
They are the largest units of matter.
They are the only types of atoms that exist.
They cannot be divided and still keep the properties of the element.
They cannot be divided and still keep the properties of the element true about all of these atoms. Option D is corect.
What is an atom?The atom consists of matter that may be split without releasing electrical charges.
It's also the smallest unit of matter with chemical element features. As a result, the atom is the fundamental unit of science.
In the nucleus proton and the neutron is exists. The condition of the atom to be electrically neutral is that the number of the proton and electron should be the same.
They cannot be separated while still maintaining the element's characteristics for each and every one of these atoms.
Hence, option D is corect.
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Answer:
The correct answer is d, they cannot be divided and still keep the properties of the element.
Explanation:
You're welcome :)
A 2 kg object with a weight of 20 N is being pulled up by a rope with a tension of 12N what is the acceleration of the object
Answer:
The object accelerates downward at 4 m/s² since the tension on the rope is less than weight of the object.
Explanation:
Given;
mass of the object, m = 2 kg
weigh of the object, W = 20 N
tension on the rope, T = 12 N
The acceleration of the object is calculated by applying Newton's second law of motion as follows;
T = F + W
T = ma + W
ma = T - W
\(a = \frac{T-W}{m} \\\\a = \frac{12 - 20}{2} \\\\a = -4 \ m/s^2\) (the negative sign indicates deceleration of the object)
The object accelerates downward at 4 m/s² since the tension on the rope is less than weight of the object.
A 2-kg object is moving at 3 m/s. A 4-N force is applied in the direction of motion and if the object has a final velocity 7m/s. calculate the distance that the object moves
1. Which of the following statements is false? A) During a reaction, electrons move from an electrophile to a nucleophile B) Homolytic bond cleavage yields neutral radicals in which each atom gains on
The false statement is B) Homolytic bond cleavage yields neutral radicals in which each atom gains one electron.
In homolytic bond cleavage, each atom retains one electron from the shared pair of electrons, resulting in the formation of two neutral radicals, where each atom retains its original number of electrons.
No atoms gain or lose electrons in this process.
In a homolytic bond cleavage, a covalent bond is broken, and the shared pair of electrons is split equally between the two atoms involved in the bond.
This results in the formation of two neutral radicals, with each atom retaining one of the electrons from the shared pair.
A radical is a chemical species characterized by the presence of an electron that is unpaired, meaning it does not have a partner electron with which it forms a complete pair. When a covalent bond is homolytically cleaved, each atom involved in the bond gains one electron, resulting in the formation of two radicals.
These radicals are highly reactive due to the presence of the unpaired electron, which makes them prone to participate in further chemical reactions.
It's important to note that in homolytic bond cleavage, there is no transfer of electrons from one atom to another.
Instead, the bond is broken in a way that allows each atom to retain one of the electrons, leading to the formation of two neutral radicals.
Therefore, statement B, which suggests that each atom gains one electron, is false.
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hii i am satyam from India and i m having doubt in this question according to me answer should be 20 % but in answer key it's 21 % how??
The formula relating kinetic energy and momentum of a particle is expressed as
KE = p^2/2m
let the actual momentum be p. Since the error measurement is 10%, the measurement of the momentum would be
p + 0.1p = 1.1p
Percentage error in the measurement of the kinetic energy is obtained by the formula,
% error = (KEf - KEi)/KEi x 100
where
KEf is the final kinetic energy measured error
KEi is the initial kinetic energy measured without error
Thus,
% error = [(1.1p)^2/2m - p^2/2m)]/p^2/2m x 100
% error = p^2/2m(1.1^2 - 1)/(p^2/2m) x 100
% error = 100(1.1^2 - 1)
% error = 21%
What are the two groups of planets based on composition?
star a has a radius r and temperature t. at the same distance from earth, star b has a radius 4r and temperature t/2. which star appears to be brighter?
Star B appears to be brighter because its larger radius (4 times that of Star A) results in a greater surface area, allowing it to emit more light. The temperature difference does not affect brightness perception at the same distance.
The brightness of a star is determined by its luminosity, which is related to its radius and temperature. In this scenario, Star A has a radius of "r" and a temperature of "t," while Star B has a radius of "4r" and a temperature of "t/2".
The luminosity of a star is proportional to the surface area of the star. Since Star B has a larger radius (4 times that of Star A), its surface area is 16 times larger. This means Star B can emit more light and appears brighter than Star A, even though the temperature difference between the two stars does not impact their perceived brightness at the same distance. Therefore, Star B appears to be brighter due to its larger radius and resulting larger surface area for light emission.
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a) A cell of dry air is moved vertically from its original position under adiabatic conditions. Depending on the temperature profile of the surrounding atmosphere, this gas cell can keep on moving in the same direction, or it may come back to its original position. Considering the temperature profile of the atmosphere, change of the air cell temperature as it moves up and down in the surrounding atmosphere, as well as relative densities of the air cell and atmosphere, explain why and when the atmosphere is considered to be convectively stable and convectively unstable. In answering this question, use diagrams of temperature change with altitude. (13 marks) b) Explain why the adiabatic lapse rate of dry air is different from the adiabatic lapse rate of wet saturated air. Show them both in a diagram. (5 marks) c) Wet unsaturated air rises from the ocean surface. The ambient lapse rate is higher than the adiabatic lapse rate for dry air. There is a temperature inversion layer at higher altitudes. Show in a schematic diagram how the temperature of the wet air changes with altitude, in comparison with the ambient temperature. Explain at what altitudes the cumulus clouds are formed and why. (7 marks)
The question addresses the stability of the atmosphere and the factors that determine convective stability or instability. It also explains the difference between the adiabatic lapse rate of dry air and wet saturated air.
a) The stability of the atmosphere is determined by the temperature profile and relative densities of the air cell and atmosphere. If the temperature of the surrounding atmosphere decreases with altitude at a rate greater than the adiabatic lapse rate of the air cell, the atmosphere is considered convectively stable.
In this case, the air cell will return to its original position. Conversely, if the temperature of the surrounding atmosphere decreases slower than the adiabatic lapse rate of the air cell, the atmosphere is convectively unstable. The air cell will continue moving in the same direction.
b) The adiabatic lapse rate refers to the rate at which temperature decreases with altitude for a parcel of air lifted or descending adiabatically (without exchanging heat with its surroundings). The adiabatic lapse rate of dry air is higher (around \(9.8^0C\) per kilometer) compared to the adiabatic lapse rate of wet saturated air (around 5°C per kilometer).
This difference arises because when water vapor condenses during the ascent of saturated air, latent heat is released, reducing the rate of temperature decrease. A diagram can illustrate the difference between the two lapse rates, showcasing their respective slopes.
c) When wet unsaturated air rises from the ocean surface, its temperature decreases at a rate equal to the dry adiabatic lapse rate. However, if the ambient lapse rate (temperature decrease with altitude) is higher than the adiabatic lapse rate for dry air, a temperature inversion layer forms at higher altitudes.
In this inversion layer, the temperature increases with altitude instead of decreasing. A schematic diagram can depict the temperature changes of the wet air in comparison to the ambient temperature, showing the inversion layer.
Cumulus clouds form at the altitude where the rising moist air reaches the level of the temperature inversion layer. These clouds are formed due to the condensation of water vapor as the air parcel cools to its dew point temperature.
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Which best describes the energy of a sound wave as it travels through a medium?
It increases.
lt decreases.
It remains the sam.
It depends on the medium,
Answer:
it depends on the medium :D
when is the best time to do a quick inspection of your work area in an effort to identify potential hazards
The question asks about the best time to conduct a quick inspection of the work area to identify potential hazards.
The best time to perform a quick inspection of the work area to identify potential hazards is before starting any task or activity. Prior to beginning work, it is crucial to conduct a visual assessment of the surroundings to identify any existing or potential hazards. This proactive approach allows for early detection and mitigation of risks, ensuring a safer work environment.
By conducting a pre-task inspection, workers can identify potential hazards such as spills, loose wires, obstructed pathways, or any other unsafe conditions that may pose a risk to their safety or the safety of others. Addressing these hazards before commencing work minimizes the chances of accidents or injuries and promotes a more secure work environment.
Taking the time to regularly assess the work area for hazards is a fundamental aspect of maintaining a safe workplace. It is essential to remain vigilant throughout the workday, promptly addressing any new hazards that may arise and promptly resolving them. By continuously monitoring and inspecting the work area, potential hazards can be identified and rectified promptly, helping to prevent accidents and maintain a safe and healthy working environment.
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A 472-g glider on a horizontal, frictionless air track is attached to an ideal spring whose force constant is 712 N/m. At one point in time, the glider is moving at 0.49 m/s and is 9.16 cm from the equilibrium point. What is the amplitude of motion
Answer:
0.09 m
Explanation:
The best way to solve this would be by comparing energy.
Build conservation of energy formula.
\(K+U=E\\\)
Find kinetic energy:
\(1/2mv^2=K\\1/2*0.472*0.49^2=K\\0.057=K\)
Now find the potential spring energy at 9.16cm:
\(1/2KA^2=Us\\1/2*712*0.0916^2=Us\\2.987 = Us\)
Since all energy must come from potential energy, we can substitute values:
\(0.057+2.987=1/2kA^2\\3.04400=712/2*A^2\\0.008=A^2\\0.089=A\\0.09=A\)
good morning how ya'll doing today
Answer:
good
Explanation:
Answer:
fine
Explanation:
make me as brainliast
Suppose a piece of food is on the edge of a rotating microwave oven plate. Does it experience nonzero tangential acceleration, centripetal acceleration, or both when: (a) The plate starts to spin
Answer:
the only acceleration it has is radial (centripetal)
Explanation:
The microwaves plate rotates at a constant speed after a very short period of acceleration.
Therefore we can apply Newton's second law
F = m a
where the acceleration is centripetal
a = v2 / r = w2 r
therefore as it rotates constant speed it cannot have a tangential acceleration since it changes the modulus of the speed.
Consequently the only acceleration it has is radial (centripetal)
How much power does a machine have that does 15204 J of work in 40 seconds?
Explanation:
since P=W/t
P=15204/40
P=380.1 Watt
Energy Changes Form Energy originating from the young stars is being emitted by the nebula; however the nebula still has excess énergy that it did not emit as light. Give one possible example of what happened to some of that energy. HINT: Remember that energy can not be created or destroyed; it can only be converted into different forms.
Some of the excess energy from a nebula that was not emitted as light may have been converted into heat.
When young stars are formed within a nebula, they emit energy in the form of light as a result of nuclear fusion processes occurring in their cores. However, not all of the energy generated by the young stars is radiated away as light. Some of it can be converted into different forms of energy, such as heat.
The excess energy in a nebula can arise due to several factors. For instance, when the nebula is dense, it can trap some of the energy emitted by the young stars, preventing it from escaping as visible light. This trapped energy may then be absorbed by the surrounding gas and dust, leading to an increase in their temperatures.
Furthermore, interactions between the energetic particles, such as electrons and ions, within the nebula can generate heat through various processes. These interactions can include collisions between particles or the release of energy during magnetic reconnection events. In these scenarios, the excess energy that was not emitted as light can be converted into thermal energy, thereby raising the temperature of the nebula.
In conclusion, one possible outcome for the excess energy in a nebula, which was not emitted as light, is its conversion into heat. This conversion can occur due to the trapping of energy within the dense nebular environment or through particle interactions, leading to an increase in the nebula's temperature.
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A solid right circular cylinder of a substance has a radius 10. 0 cm and a height 12. 0 cm. The mass of the cylinder is 4. 00 kg. What is the density of the substance?
The density of the substance is 1.06 g/cm³.
What is density?The mass-to-volume ratio of a substance is known as its density.
It is represented as
Density = Mass/Volume
Given,
Radius = 10 cm
Height = 12 cm
Mass = 4 kg = 4000 g
We know that the volume(V) of a solid right circular cylinder is πr²h.
Putting the given values, we get
V = (22/7)(10)²(12), {π = 22/7}
V = (22×1200)/7
V = 3771.4 cm³
Now substituting the values of mass and volume in the formula for density,
Density = 4000/3771.4 g/cm³
Density = 1.06 g/cm³
Therefore, the density of the substance is 1.06 g/cm³.
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If you increase the pressure on a gas sample by decreasing the volume, the
particles will speed up. True False
Answer: True
If you increase the pressure on a gas sample by decreasing the volume, the particles will speed up.