Answer:
A hole
Explanation:
put a hole in the barrel and let some water out
The thing you would add to the barrel would be holes which would cause water to fall out of the barrel.
What is a pound?Pound is defined as the basic unit for weight in the Foot Pound Second (F.P.S) system and is equal to 16 ounces.
An example of a pound is a man weighing 186 pounds.
The thing you would add to the barrel would be holes which would cause water to fall out of the barrel.
The amount of holes you would add and where you would add them would depend all on how much the barrel weighs without the water.
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a cube of iron pyrite is 0.31 cm on each side and has a mass of 0.040g. what is the density of the sample?
The density of the iron pyrite cube is 1.343 g/cm³.
Given,
Side of iron pyrite cube = 0.31 cm
Mass of iron pyrite = 0.040 g
The volume of iron pyrite cube = s³ cm³
Or, volume = 0.029791 cm³
We have to find the density of the sample.
Density is defined as the mass per unit volume. Or, it is the ratio of mass to the volume of the substance.
Using the formula for density, we get,
Density = mass/volume
Or, density = 0.40/0.029791
Or, density = 1.343 g/cm³
Hence, the density of the iron pyrite cube is 1.343 g/cm³.
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What is the binding energy for the nuclide 199F (atomic mass: 18.9984 amu) in MeV per nucleus?
The binding energy per nucleon for the ¹⁹F nucleon is equal to 7.786 MeV/nucleon.
What is binding energy?Binding energy can be defined as the minimum quantity of energy that is required to remove the particle from the system. Nuclear binding energy can be described as the energy required to dismantle a nucleus of an atom into free neutrons and protons.
The binding energy will be determined from the mass defect. Mass defect is calculated from the difference between the mass observed and the expected combined mass.
Given the mass of the ¹⁹F = 18.9984 a.m.u.
The mass defect for the ¹⁹F can be calculated as:
Δm = \((M _n +M_p) - M_F\)
\(\triangle m =( 9\times 1.0078 + 10 \times 1.0087 )- 18.9984\)
\(\triangle m =0.1588 \;a.m.u.\)
The binding energy for the fluorine can be calculated as:
E = Δmc²
E = 0.1588 × 931.5
E = 147.92 MeV
The binding energy per nucleon of ¹⁹F can be calculated as:
B.E.N. = 147.92/18.9984 = 7.786 MeV per nucleon
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A typical aspirin tablet contains 321 mg of the active ingredient acetylsalicylic acid. convert to grams
A typical aspirin tablet contains 321 mg of the active ingredient acetylsalicylic acid and 321 mg makes 0.321 g.
Define Aspirin.The nonsteroidal anti-inflammatory medicine (NSAID) aspirin, often referred to as acetylsalicylic acid (ASA), is used to treat a variety of inflammatory disorders by lowering pain, fever, and/or inflammation. These conditions include Kawasaki disease, pericarditis, and rheumatic fever.
Long-term usage of aspirin is also used to help those at high risk avoid further heart attacks, ischemic strokes, and blood clots. Effects of pain or fever often start within 30 minutes. Aspirin functions similarly to other NSAIDs but also inhibits platelet function.
What risks does aspirin pose?Your doctor should be consulted when deciding whether or not to take aspirin because it depends on your cardiovascular risk, according to Wong. While aspirin is often taken safely by many people, it can also result in life-threatening stomach, intestinal, and brain bleeding.
convert mg to gram1 mg = 1/1000 g
so,
321 mg = 321/ 1000g
= 0.321g
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A steel bar and a copper bar have the same length of 1.500 m at -12.00 ∘C.
What is the difference in the lengths of the two bars at 41.0 ∘C ?
The effect of a catalyst is to: change the stoichiometry of the reaction. lower the activation energy of a reaction whereby making it easier for the reactants to get over the energy hump. change the position of the equilibrium. increase the number of collisions between reactants. increase the temperature of the reactants whereby more products are forme
The effect of a catalyst is
Option B(lower the activation energy of a reaction whereby making it easier for the reactants to get over the energy hump)What is a catalystA catalyst allows an alternative reaction pathway that leaves activation energy than the uncatalysed reaction. This does not change the frequency of collision.
Frequency of collisionFrequency of collision depend upon concentration of reactant temperatures
Catalyst on activation energyHence, catalyst lowers the activation energy of reaction thereby making it easier for the reactant to get over the energy hump.
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I attached a picture of the questions I have. These are separate questions.
Electron configuration is defined as the description of where each electron is located, in terms of levels and sublevels around the nucleus. In this question, we have the following electron configuration:
1s2 2s2 2p6 3s2 3p6
This electron configuration has 8 electrons in its valence shell (the last number represents the shell number, in this case is 3) and according to the octet rule, this is a stabilized element, therefore it must be a Noble Gas
The period will be 3, since this is the valence shell
The group will be Noble gas, or group 18
Noble gas, usually, will not bond to other elements, since they are stabilized according to the octet rule
Using the reaction below and your knowledge of limiting reactants, find what mass of iron(II) chloride can be made from 0.60 g of Fe and 0.53 g of Cl2. Round to the nearest 0.01 and remember to include both units and substance in your answer!!! Fe + Cl2 --> FeCl2
The limiting reactant in this reaction is chlorine gas. 0.53 g of chlorine gas will produce about 0.94 g of ferrous chloride.
What is limiting reactant ?A limiting reactant in a reaction is the reactant which is fewer in amount or consume early without complete reaction with other reactants. Hence, as soon as this reactant is consume, the reaction stops.
In the given reaction, one mole of Fe reacts with one mole of Cl₂ gas.
Atomic mass of Fe = 55.8 g/mol
molecular mass of Cl₂ = 71 g/mol
no.of moles in 0.60 g of Fe = 0.60 / 55.8 = 0.010 moles.
no.of moles of 0.53 g of Cl2 = 0.53 /71 = 0.007 moles.
Here, both are needed in equal number of moles, but the number of moles of chlorine gas is fewer hence, it is the limiting reactant.
molar mass of FeCl₂ = 126.8 g/mol
71 g of chlorine gas produce 126.8 g of FeCl₂. Then mass of FeCl₂ produced by 0.53 g of Cl₂.
(0.53g × 126.8 g) /71 g = 0.94 g
Therefore, 0.94 g of FeCl₂ is produced.
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The decomposition of cyclohexane to benzene and Martialism is a high mass transfer limited period on the planet. The reaction will be carried out in a tubular reactor with an internal diameter of 5 cm and a length of 20 m; the pipes are filled with cylindrical pellets 0.5 cm in diameter and 0.5 cm in length. The pellets are only covered with the outer surface coating. The filled bed porosity is 40%. The inlet flow rate is 60 dm3/min.
Plot the tubular length vs. conversion graph when the inlet gas stream contains 5% cyclohexane and 95% hydrogen at 2 atm and 500°C. What would be the required tubular length for 99.9% conversion?
For cyclohexane diffusion in hydrogen, use the Fuller, Schettler, and Giddings Correlation given below.
The required tubular length for 99.9% conversion is 116.84 meters.
On Earth, the rate at which cyclohexane reacts with benzene and methylcyclopentane is constrained by high mass transfer.
A tubular reactor with an internal diameter of 5 cm and a length of 20 m will be used to conduct the reaction, and cylindrical pellets with dimensions of 0.5 cm in diameter and 0.5 cm in length will be placed within the reactor's pipes.
Only the exterior surface of the pellets are coated.
The packed bed has a 40% porosity and a 60 dm3/min intake flow rate.
When the intake gas stream includes 5% cyclohexane and 95% hydrogen at 2 atm and 500°C, the tubular length vs. conversion graph should be drawn.
The graph may be used to identify the minimum length of tube necessary for 99.9% conversion.
For cyclohexane diffusion in hydrogen, the Fuller, Schettler, and Giddings Correlation is as follows:
a = 0.8854,
b = 1.764102,
C = 6.0231023.
The tube length vs. conversion graph may be displayed at 2 atm and 500°C when the incoming gas stream includes 5% cyclohexane and 95% hydrogen.
The following equation may be used to determine the rate of reaction:
ra=2.31011 exp[-88580/RT]C_A(1X)/3
The mole balancing equation for an isothermal tubular reactor is given as
dX/dL = -ra/C A,
where X is the conversion and L is the length.
To determine the length of the tubular reactor needed for a specific conversion X, we can integrate the aforementioned equation from X = 0 to X = X.
We must numerically calculate the following equation to obtain the necessary tube length for 99.9% conversion:
∫0.999L0−ra/CA
dL=0.999XEq L
for X=0.999
After rearranging the equation above, we get:
0.999L0ra/CA
dL=XX Eq
The aforementioned equation is integrated to give us
L = 116.84 m.
Therefore, the required tubular length for 99.9% conversion is 116.84 meters.
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Which aquatic organism would be least likely to survive in a <7 pH environment?
protozoa
worms
algae
bacteria
Calculate the specific heat in J/(g·ºC) of an unknown substance if a 2.50-g sample releases 12.0 cal as its temperature changes from 25.0ºC to 20.0ºC. _________J/(g·°C)
Answer:
\(\fbox{c = - 4.01 \: joule/g°C}\)
Step by step explanation:
Given:
Mass of given sample (m) = 2.50 g
Initial temperature (T1) = 25°C
Final temperature (T2) = 20°C
Heat Energy Q = 12 cal
To find:
\(Specific \: Heat \: c = \: ?\)
Solution:
We know that,
Specific heat of any substance is directly proportional to the mass and change in temperature.
Represented by equation,
\(Q = mc \triangle T\)
Where,
Q = Heat Energy
m = mass of given sample
c = specific heat
∆T = change in temperature
Substituting corresponding values,
\(Q = mc \triangle T \\ 12 = 2.5\times c \times (20-25) \\ c = \frac{12}{2.5 \times ( - 5)} \\ c = - 0.96 \: cal/g°C \\ \)
We also know that,
\(1 \: cal = 4.184 \: joules\)
multiplying above answer by 4.184,
\(c = - 0.96 \times 4.184 \\ \fbox{c = - 4.01 \: joule/g°C}\)
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Write 0.00103 in scientific notation
Answer:
1.03
Explanation:
You would take 0.00103 and move the decimal like this; 0001.03, we wouldn't have the zeroes in front of the one, as it can throw us off. Therefore, your answer would be 1.03.
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Classify the chemical reaction shown here: Mg + H2SO4 → MgSO4 + H2
How is the reaction speed affected if we add magnesium
If we add more magnesium to the reaction, the reaction speed will increase.
The chemical reaction shown is a single-displacement reaction, also known as a single-replacement reaction. In this type of reaction, one element replaces another element in a molecule, producing a new compound and a different element.
In the given reaction, magnesium (Mg) reacts with sulfuric acid (H₂SO₄) to produce magnesium sulphate (MgSO₄) and hydrogen gas (H₂). This can be represented by the following balanced chemical equation:
Mg + H₂SO₄ → MgSO₄ + H₂
This is because the amount of reactant determines the number of reactions that can occur. If the amount of magnesium is increased, more magnesium atoms are available for the reaction with sulfuric acid, leading to a higher rate of reaction.
However, this increase in reaction rate is only valid up to a certain point, after which further addition of magnesium will not lead to an increase in rate of reaction. This is because other factors such as the concentration of sulfuric acid and the temperature of the reaction may become limiting factors that can no longer be compensated by adding more magnesium.
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How does a filter separate mixtures like sand and water?
Answer:
Filtration is a method for separating an insoluble solid from a liquid. When a mixture of sand and water is filtered: the sand stays behind in the filter paper (it becomes the residue ) the water passes through the filter paper (it becomes the filtrate )
Explanation:
Which binary molecular compound includes an element with five atoms of one element?
Answer:
For example, N2O4 is referred to as dinitrogen tetroxide, not dinitrogen tetraoxide, and CO is called carbon monoxide, not carbon monooxide.
...
Binary molecular (covalent) compounds.
Prefixes used in chemical nomenclature
prefix number of atoms
tetra- 4
penta- 5
hexa- 6
Explanation:
How many grams of iron are produced when 450 grams of iron (lll) oxide are reacted
To answer this question, we need to know the balanced chemical equation for the reaction between iron (III) oxide and another substance that would produce iron.
How many grams of iron will be produced when 450 grams of iron (lll) oxide are reacted?Assuming the reaction is:
Fe₂O₃ + 3CO → 2Fe + 3CO₂
This equation tells us that one mole of Fe₂O₃ reacts with three moles of CO to produce two moles of Fe. We can use this information to calculate the number of moles of Fe that can be produced from 450 grams of Fe₂O₃.
Convert the mass of Fe₂O₃ to moles in the first step:
Molar mass of Fe₂O₃ = 2 x atomic mass of Fe + 3 x atomic mass of O = 2 x 55.85 + 3 x 16.00 = 159.69 g/mol
Number of moles of Fe₂O₃ = 450 g / 159.69 g/mol = 2.82 mol
According to the balanced chemical equation, 1 mole of Fe₂O₃ produces 2 moles of Fe. Therefore, the number of moles of Fe that can be produced from 2.82 mol of Fe₂O₃ is:
Number of moles of Fe = 2.82 mol x (2 mol Fe / 1 mol Fe₂O₃) = 5.64 mol
Convert the number of moles of Fe to grams in the final step:
Molar mass of Fe = 55.85 g/mol
Mass of Fe produced = 5.64 mol x 55.85 g/mol = 315.89 g
Therefore, if 450 grams of iron (lll) oxide are reacted with carbon monoxide to produce iron, the amount of iron produced would be 315.89 grams.
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A balloon has a volume of 145 mL at room temperature (25°C = 298°K). Alyssa decides to place the balloon in the freezer to see what happens. After being in the freezer for an hour, the balloon has a new volume of 35mL. What is the temperature inside the freezer?
The temperature inside the freezer is approximately -164°C.
To solve this problem, we can use the combined gas law equation:
\((P1V1)/T1 = (P2V2)/T2\)
where P is the pressure, V is the volume, and T is the temperature of the gas.
We know that the initial volume of the balloon is 145 mL and the final volume is 35 mL. We also know that the initial temperature is 25°C or 298 K, and we need to find the final temperature.
Assuming the pressure of the gas remains constant, we can rearrange the combined gas law equation to solve for the final temperature:
\(T2 = (P2V2/T1)(P1/V1)\)
Plugging in the values we know, we get:
\(T2 = (1 atm * 35 mL/298 K)(1 atm/145 mL) = 0.0808 atm/mL\)
Multiplying both sides by 298 K and dividing by 0.0808 atm/mL, we get:
T2 = 109.15 K or approximately -164°C
Therefore, the temperature inside the freezer is approximately -164°C.
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URGENT HELP!!!!
Which of the following experimental plans will test the effects of pressure on a reaction with gases and what is
the expected result?
A Keep temperature constant and increase the pressure of the reaction; reaction rate will increase.
B Keep pressure constant and increase the temperature of the reaction; reaction rate will decrease.
C Keep temperature constant and decrease the pressure of the reaction; reaction rate will increase.
D Keep pressure constant and decrease the temperature of the reaction; reaction rate will increase.
A) Keep temperature constant and increase the pressure of the reaction; reaction rate will increase.
Explanation:The temperature and pressure of a reaction will affect the rate of reaction.
Pressure
Pressure and the rate of reaction have a direct relationship. This means that as one increases, so does the other. So, if the pressure increases. then the rate of reaction will also increase. This is due to the number of collisions. As pressure increases, the number of collisions between molecules increases. This causes the reaction to occur faster. Thus, the rate of reaction increases.
Temperature
Kinetic energy and temperature are proportional. This means that as temperature increases, so does kinetic energy. This leads to temperature and rate of reaction also having a direct relationship. So, temperature and rate of reaction increase and decrease together. This is due to the fact that when temperature increases, the energy of the molecules increases. This leads to an increased number of collisions. As stated above, more collisions lead to a faster reaction.
An experiment is performed on an unknown material and produces the given heat curve. The temperature of the material is shown as a function of heat added.
The specific heat of the solid is 4.2 J/g/°C and the specific heat of the liquid is 36.3 J/g/°C.
How to calculate the valueIn this case, we know that the mass of the solid is 9.80 g, the change in temperature is 235 °C, and the heat added is 10,000 J. We can solve for the specific heat of the solid as follows:
c = Q / m ΔT
= 10,000 J / 9.80 g / 235 °C
= 4.2 J/g/°C
The latent heat of fusion for the unknown material is 334 J/g. We can now calculate the heat required to melt the solid as follows:
Q = mLf
= 9.80 g * 334 J/g
= 32,832 J
The total heat added to the liquid is 10,000 J + 32,832 J = 42,832 J. The change in temperature of the liquid is 235 °C - 20 °C = 115 °C. We can now calculate the specific heat of the liquid as follows:
c = Q / m ΔT
= 42,832 J / 9.80 g / 115 °C
= 36.3 J/g/°C
Therefore, the specific heat of the solid is 4.2 J/g/°C and the specific heat of the liquid is 36.3 J/g/°C.
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An experiment is performed on an unknown material and produces the given heat curve. The temperature of the material is shown as a function of heat added. Other experiments determine that the material has a temperature of fusion of fusion=235 °C and a temperature of vaporization of vapor=471 °C.
If the sample of material has a mass of =9.80 g, calculate the specific heat when this material is a solid, s, and when it is liquid, l.
4. A) The pH of a solution is changed from pH 6 to pH 10. Does this reflect an increase or decrease in [H+]?B) By how much has the [H+] changed?
As a solution loses H+ ions its pH increases, i.e. the solution becomes more basic.
In this case, the solution goes from an acidic pH of 6 to a basic pH equal to 10, this means that the concentration of H+ in the solution decreases.
Now, to determine how much is the change of concentration we can apply the following formula:
\(\begin{gathered} pH=-\log \lbrack H^+\rbrack \\ -pH=\log \lbrack H^+\rbrack \end{gathered}\)We can clear the H+ concentration by applying the logarithm rules. We have a base 10 logarithm so when clearing we will have:
\(\lbrack H^+\rbrack=10^{-pH}\)Now we replace the values of each pH and we will have the H+ concentration in each case.
\(\begin{gathered} \lbrack H^+\rbrack_{pH=6}=10^{-6} \\ \lbrack H^+\rbrack_{pH=10}=10^{-10} \end{gathered}\)Therefore, the concentration difference will be:
\(\begin{gathered} \Delta\lbrack H^+\rbrack=\lbrack H^+\rbrack_{pH=6}-\lbrack H^+\rbrack_{pH=10} \\ \Delta\lbrack H^+\rbrack=9.999\times10^{-7} \end{gathered}\)The change of concentration will be 9.999x10^-7
How many moles of CO are required to produce 45.0 L of carbon dioxide at STP?
2 CO(g) + O2(g) —> 2 CO2(g)
Answer should written as X.XX moles CO
Answer:
ang hirap na nag tanung
during this reaction , how many nolecules of annonia (NH3) are producted
20) If a single gram of sugar contains 4 Calories of energy, what is the Calorie content from a serving of cereal that
contains 9.2 grams of sugar?
list three statements for transverse waves
list the first 20 element
U can refer to the above attachment.
If 19.4 mL of a Ca(OH)₂ solution are needed to neutralize 31.5 mL of 0.1 M HC₂H302 solution, what is the concentration (molarity) of theCa(OH)₂ solution?Select one:O a. 0.009 MO b. 1.6 MOC 0.08 MO d. 0.1 MI put answer b 1.6 not sure what i did wrong?
Answer:
\(C:\text{ 0.08 M}\)Explanation:
Here, we want to get the molarity of the base
To get this, we start by writing the balanced equation of reaction between the base and the acid
We have that as:
\(Ca(OH)\placeholder{⬚}_{2(aq)}\text{ + 2HC}_2H_3O_{2(aq)}\text{ }\rightarrow\text{ Ca\lparen CH}_3COO)\placeholder{⬚}_{2(aq)}\text{ + 2H}_2O_{(l)}\)Now, we proceed to write the standardization equation
We have that as:
\(\frac{C_aV_a}{C_bV_b}\text{ = }\frac{n_a}{n_b}\)where:
Ca is the molarity of the acid which is 0.1M
Va is the volume of the acid which is 31.5 mL
Cb is the molarity of the base which is what we want to calculate
Vb is the volume of the base which is 19.4 mL
na is the number of moles of the acid in the balanced equation which is 2
nb is the number of moles of the base which is 1 in the balanced equation
Substituting the values, we have:
\(\begin{gathered} \frac{0.1\text{ }\times\text{ 31.5}}{C_b\times\text{ 19.4}}\text{ = }\frac{2}{1} \\ \\ C_b\text{ = }\frac{31.5\text{ }\times\text{ 0.1}}{2\times19.4}\text{ = 0.08 M} \end{gathered}\)Which of the following equations correctly model a nuclear fusion reaction? Justify your reasoning
Answer:
Explanation:
c) fusion combines into one product plus energy
the pressure on 20 milliliters of a gas at constant temperature is changed from 4 atmospheres to 2 atmospheres. what is the new volume of the gas?
The new volume of the gas whose pressure was changed would be = 40 milliliters.
How to calculate the new volume of the given gas?The initial volume(V1)of the gas= 20ml
The initial pressure(P1) = 4 atm
The final pressure(P2) = 2 atm
The final volume(V2) = ?
Using the general gas formula;
P1V1 = P2V2
V2 = P1V1/P2
= 4×20/2
= 40ml
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KCIO3 decomposes according to thereaction below:
2KCIO3 → 2KCI + 302
How many moles of O2 form when
2.0 mole of KCIO3 decomposes?
When 2.0 moles of KCIO3 decompose, 2.0 moles of O2 will form.
The balanced chemical equation shows that 2 moles of KCIO3 decompose to produce 3 moles of O2. Therefore, we can use the stoichiometric ratio from the balanced equation to determine the number of moles of O2 formed when 2.0 moles of KCIO3 decompose.
According to the stoichiometry, 2 moles of KCIO3 produce 3 moles of O2. Therefore, we can set up a proportion:
(2 moles KCIO3 / 2 moles O2) = (2.0 moles KCIO3 / x moles O2),
where x represents the unknown number of moles of O2 formed.
Simplifying the equation:
(2 moles KCIO3 / 2 moles O2) = (2.0 moles KCIO3 / x moles O2),
1 = (2.0 moles KCIO3 / x moles O2),
Cross-multiplying:
x moles O2 = (2.0 moles KCIO3 / 1),
x moles O2 = 2.0 moles KCIO3.
Therefore, when 2.0 moles of KCIO3 decompose, 2.0 moles of O2 will form.
It is important to note that this calculation assumes complete and ideal conditions, where the reaction proceeds with 100% efficiency. In reality, the actual yield of O2 may be lower due to various factors such as side reactions or incomplete decomposition. To determine the actual yield, additional information or experimental data would be required.
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Describe an experiment to show that pressure acts in all directions in liquids.
We frequently observe kids playing with polythene bags filled with water that have little holes drilled into them at various locations so they can sprinkle water on other kids. Through this experiment, we can say that pressure acts in all directions in liquids.
Liquid's pressureSince both liquids and gases may flow, they are both referred to as fluids. Fluids under rest pressure behave uniformly in all directions.
Weather forecasts can be made using barometers. They track the evolution of atmospheric pressure throughout time.
On weather forecast maps, pressure variations appear as an isobar pattern. Predictions are made using these changes in pressure, and they are fairly accurate when combined with wind observations.
Pressure and depth in liquidsAs you go away from a liquid's surface, pressure rises. for instance: A bucket has three holes that are all the same size. Since there is more pressure at the bucket's bottom, the water spills out more forcefully. Dams are thicker at the bottom for this reason.
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Biological half-life of medicine works in the same way as radiological half-life. Acetaminophen (Tylenol) has a biological half-life of about 2 hours (though it varies depending on individual metabolism). What percentage of your original dosage remains in your system after 6 hours when you are allowed to take another dose?
Answer:
12.5%
Explanation:
From the question given above, the following data were obtained:
Half-life (t½) = 2 h
Time (t) = 6 h
Percentage remaining =.?
Next we shall determine the number of half-lives that has elapse. This can be obtained as follow:
Half-life (t½) = 2 h
Time (t) = 6 h
Number of half-lives (n) =?
n = t / t½
n = 6/2
n = 3
Finally, we shall determine the percentage of original dosage remaining as follow:
Amount remaining (N) = Original amount (N₀) /2ⁿ
N = N₀ / 2ⁿ
Divide both side by N₀
N/N₀ = 1/2ⁿ
Input the value of n i.e 3
N/N₀ = 1/2³
N/N₀ = 1/8
N/N₀ = 0.125
Multiply by 100 to express in percent.
N/N₀ = 0.125 × 100
N/N₀ = 12.5%
Thus, percentage of original dosage remaining is 12.5%