a baseball player is dashing toward home plate with a speed of 4.7 m/s when she decides to hit the dirt. she slides for 1.5 s , just reaching the plate as she stops (safe, of course).

Answer:

it's 220 J

the second one

The kinetic energy of the circular disc in initial state is,

\(K^{1r} = \frac{1}{2}I^{t}ω^{ \frac{2}{i} } \)

The initial kinetic energy of the other disc dropped on the first disc is,

\(K^{2r} = \frac{1}{2}I^{b}(0)^{2}\)

\( = > K^{2r} = 0J\)

As both the disc in the final state are moving with the same angular velocity, thus, the net kinetic energy in the final state is,

\(E^{f} = \frac{1}{2}(I^{t} + I^{b})ω^{ \frac{2}{f} }\)

The net kinetic energy in the initial state is,

\(E^{i} = K^{1r} + K^{2r}\)

\( = > E^{i} = \frac{1}{2} I^{t}ω^{ \frac{2}{i} } + 0\)

\( = > E^{i} = \frac{1}{2} I^{t}ω^{ \frac{2}{i} }\)

Thus, the change in the kinetic energy during the change of state is,

\(dE = E^{f} - E^{i}\)

\( = > dE = \frac{1}{2} (I^{t} + I^{b})ω^{ \frac{2}{f} } - \frac{1}{2}I^{t}ω^{ \frac{2}{i} } \)

\( = > dE = \frac{1}{2} I^{t}(ω^{ \frac{2}{f} } - ω^{ \frac{2}{i} }) + \frac{1}{2}I^{b}ω^{ \frac{2}{f} } \)

This change in value of energy is the energy lost initially rotating the disk to friction.

Hence, the energy lost in the given case is \(dE = \frac{1}{2} I^{t}(ω^{ \frac{2}{f} } - ω^{ \frac{2}{i} }) + \frac{1}{2}I^{b}ω^{ \frac{2}{f} } \)

The energy lost initially by the rotating disk to friction is equal to \(\frac{1}{2}I_t (\omega_f^2 - \omega_i^2)+\frac{1}{2} I_b\omega_f^2\)

Given the following data:

At the initial state, the kinetic energy of the circular disc is given by this formula:

\(K.E = \frac{1}{2} I_t\omega_i^2\)

For the second disc, the initial kinetic energy is given by this formula:

\(K.E_2 = \frac{1}{2} I_b\omega_f^{2 }\\\\K.E_2 = \frac{1}{2} I_b(0)^{2 }\\\\K.E_2 = 0\)

At the final state, the discs would move with the same angular velocity and the net kinetic energy is given by this formula:

\(E_f = \frac{1}{2} (I_t + I_b)\omega_f^2\)

For the energy lost:

Also, the change in the kinetic energy is given by this formula:

\(\Delta E = E^f - E^i\\\\\Delta E = \frac{1}{2} (I_t + I_b)\omega_f^2 - \frac{1}{2} I_t\omega_i^2\\\\\Delta E = \frac{1}{2}I_t (\omega_f^2 - \omega_i^2)+\frac{1}{2} I_b\omega_f^2\)

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The terminal speed of the marble is 0.588 m/s.

The term "force" has a specific meaning in science. At this level, calling a force a push or a pull is quite appropriate. A force is not something an item "has in it" or that it "contains." One thing experiences a force from another. There are both living things and non-living objects in the concept of a force.

We know that,

F = mg                          ......(1)

where,

F = force

m = mass

g = acceleration due to gravity

Also,

v = F/k                            ......(2)

where,

v = terminal speed

k = proportionality constant

Substituting the value of F from equation (1) in equation (2)

v = mg/k                             .......(3)

Given,

m = 30 g = 0.030 kg

k = 0.500 kg/s

g = 9.8 m/s²

To find,

v =?

Put the values in equation (3)

v = mg/k        

v = 0.03(9.8)/ 0.500

= 0.294/0.500

= 0.588 m/s

​

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The attenuation coefficient in soft tissue varies approximately between 0.5 and 1 dB/cm-MHz. This means that for every 1 centimeter of soft tissue, the intensity of an ultrasound wave will be reduced by 0.5 to 1 decibel per megahertz of frequency.

The attenuation coefficient is a measure of how much a material absorbs or scatters radiation. In the case of soft tissue, the attenuation coefficient is mainly due to the scattering of ultrasound waves by the water molecules in the tissue. The attenuation coefficient increases with frequency, which means that ultrasound waves with higher frequencies will be attenuated more than ultrasound waves with lower frequencies. This is why ultrasound imaging systems use lower frequencies for imaging deeper tissues. The attenuation coefficient also varies with the type of soft tissue. For example, fat has a higher attenuation coefficient than muscle, so ultrasound waves will be attenuated more in fat than in muscle.

The attenuation coefficient is an important factor in ultrasound imaging, as it determines the depth to which ultrasound waves can penetrate tissue. By knowing the attenuation coefficient of a tissue, ultrasound imaging systems can be designed to optimize the penetration of ultrasound waves into tissue.

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The magnetic flux through one turn of the wire making the circular solenoid is 1.26 x 10^(-5) T-m².

The magnetic flux through a single turn of a solenoid can be calculated using the formula:

ΦB = μ₀ * N * I * A

where ΦB is the magnetic flux, μ₀ is the permeability of free space \(\(4\pi \times 10^{-7} \, \text{T-m/A}\)\), N is the number of turns, I is the current, and A is the cross-sectional area.

In this case, the solenoid has 100 turns (N = 100), a current of 2 amps (I = 2 A), and a radius of 1 cm (0.01 m). The cross-sectional area of the solenoid can be calculated as A = π * r², where r is the radius.

Substituting the values into the formula, we have:

\(\(\Phi_B = (4\pi \times 10^{-7} \, \text{T-m/A}) \times 100 \times 2 \, \text{A} \times (\pi \times (0.01 \, \text{m})^2)\)\(= (4\pi \times 10^{-7} \, \text{T-m/A}) \times 100 \times 2 \, \text{A} \times (\pi \times 0.0001 \, \text{m}^2)\)\(= 0.0002513 \, \text{T-m}^2\)\)

Rounding to the appropriate number of significant figures, the magnetic flux through one turn of the wire making the solenoid is 1.26 x 10^(-5) T-m².

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Answer:

B

Explanation:

Laboratories are usually controlled: however, in public places, there are way too many factors that could change an experiment

The kinematic energy of the positive charge is 2 10⁻⁸ J

This electrostatics exercise must be done in parts, the first part: let's start by finding the charge of the capacitor, the capacitance is defined by

        C = \(\frac{Q}{\Delta V}\)

        C = ε₀ \(\frac{A}{d}\)

we solve for the charge (Q)

        \(\frac{Q}{\Delta V} = \epsilon_o \frac{A}{d}\)

indicates that for the initial point d₁ = 3 mm = 0.003 m and the voltage is DV₁ = 12

         Q = \(\epsilon_o \ \frac{A \ \Delta V_1 }{d_1}\)

Now the voltage source is disconnected so the charge remains constant across the ideal capacitor.

For the second part, the condenser is separated at d₂ = 5mm = 0.005 m

         Q = \epsilon_o \  \frac{A \ \Delta V_2 }{d_2}

we match the expressions of the charge and look for the voltage

          \(\frac{\Delta V_1}{d_1} = \frac{\Delta V_2}{d_2}\)

          ΔV₂ = \(\frac{d_2}{d_1 } \ \Delta V_1\)

The third part we use the concepts of conservation of energy

starting point. With the test load (q = 1 nC = 1 10⁻⁹ C) next to the left plate

          Em₀ = U = q DV₂

          Em₀ = q  \frac{d_2}{d_1 } \ \Delta V_1

final point. Proof load on the right plate

         Em_f = K

energy is conserved

         Em₀ = em_f

         q  \frac{d_2}{d_1 } \ \Delta V_1 = K

we calculate

         K = 1 10⁻⁹  12  \(\frac{0.005}{0.003}\)  

         K = 20 10⁻⁹ J

In this exercise, as the conditions at two different points of separation give, the area of ​​the condenser is not necessary and with conservation of energy we find the final kinetic energy of 2 10⁻⁸ J

White color is the result of adding various combinations of red, green, and blue primary light colors in equal intensities.

The three primary colors are Red, green, and blue. This implies that by additively combining the colors red, green, and blue in varied proportions the different color is obtained.

Practically all other colors may be made, and when the three primaries are mixed together in equal amounts, white is produced.

Hence white color is the result of adding various combinations of red, green, and blue primary light colors in equal intensities.

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Answer:

AMPERE - A unit of measure for the flow of current in a circuit. One ampere is the amount of current flow provided when one volt of electrical pressure is applied against one ohm of resistance. The ampere is used to measure electricity much as "gallons per minute" is used to measure water flow.

Explanation:

hope it helps

A unit of electrical flow is known as ampere

Answer:

The Luminosity of a star depends on BOTH its temperature and its radius (surface area): L is proportional to R2 T4. A hotter star is more luminous than a cooler one of the same radius. A bigger star is more luminous than a smaller one of the same temperature.

Answer:

The Luminosity of a star depends on BOTH its temperature and its radius (surface area): L is proportional to R2 T4. A hotter star is more luminous than a cooler one of the same radius. A bigger star is more luminous than a smaller one of the same temperature.

Explanation:

hope it helps

help me out by going to my page and answering some questions

The highest flow rate that this filter can process is 2,160 gpm.

The maximum filtration rate allowed for a filter depends on the filter's size and the permissible flow rate per unit area of the filter. In this case, the filter has an area of 18 feet x 20 feet = 360 square feet.

The surface area of the filter is:

18 feet x 20 feet = 360 square feet

To determine the maximum flow rate, we need to multiply the surface area by the maximum filtration rate allowed:

360 square feet x 6.0 gpm/ft2 = 2,160 gallons per minute (gpm)

Therefore, the highest flow rate that this filter can process is 2,160 gpm.

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The charge on the sphere is approximately -28.1 nC. Note that the negative sign indicates the opposite charge polarity compared to the disk.To determine the charge on the sphere, we can use the principle of charge conservation.

Since the sphere and the disk are connected by a conducting wire, they will reach an equilibrium state where the charges distribute themselves evenly on their surfaces.

The total charge on the system remains constant, which means the sum of the charges on the sphere and the disk is equal to the charge on the disk:

Q_total = Q_S + Q_D

We are given the charge on the disk, Q_D = 28.1 nC. To find Q_S, we rearrange the equation:

Q_S = Q_total - Q_D

Substituting the given values, we have:

Q_S = 0 - 28.1 nC

Since there is no charge initially on the system, the charge on the sphere is simply the negative of the charge on the disk:

Q_S = -28.1 nC

Therefore, the charge on the sphere is approximately -28.1 nC. Note that the negative sign indicates the opposite charge polarity compared to the disk.

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The expression for the energy stored (E) in a stretched wire of original length (L), cross-sectional area (A), tension (T), and Young's modulus (Y) is given by E = Y * e * ln(L) * A

The work done to stretch the wire can be calculated by integrating the force applied over the displacement. In this case, the force applied is the tension (T) in the wire, and the displacement is the change in length (ΔL) from the original length (L) to the stretched length (L + ΔL).

The tension in the wire is given by Hooke's law, which states that the tension is proportional to the extension of the wire:

T = Y * (ΔL / L)

where Y is the Young's modulus of the material of the wire.

Now, let's calculate the work done to stretch the wire:

dW = T * dL

Integrating this expression from L to L + ΔL:

W = ∫ T * dL = ∫ Y * (ΔL / L) * dL

W = Y * ΔL * ∫ (dL / L)

W = Y * ΔL * ln(L) + C

Here, C is the constant of integration. Since the energy stored in the wire is zero when it is unstretched (ΔL = 0), we can set C = 0.

Finally, the expression for the energy stored in the wire (E) is:

E = W = Y * ΔL * ln(L)

or, if we substitute the cross-sectional area (A) and strain (e) of the wire, where e = ΔL / L:

E = Y * e * ln(L) * A

Thus, the expression for the energy stored (E) in a stretched wire of original length (L), cross-sectional area (A), tension (T), and Young's modulus (Y) is given by:

E = Y * e * ln(L) * A

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Answer:

\(h=3.18\times 10^{-9}\ m\)

Explanation:

Given that,

The volume of a drop, \(V=10^{-10}\ m^3\)

The radius of the circular film, \(r=10^{-1}\ m\)

We need to find the thickness of the film.

We know that,

Volume, \(V=\pi r^2 h\)

So,

\(h=\dfrac{V}{\pi r^2}\\\\h=\dfrac{10^{-10}}{\pi \times (10^{-1})^2}\\\\h=3.18\times 10^{-9}\ m\)

So, the thickness of the file is equal to\(3.18\times 10^{-9}\ m\).

It's not. What it is, often, is easier.

You should know by now that you need to be working with a consistent set of units. This means that your unit for velocity is your unit for length divided by your unit for time…and your unit for acceleration is your unit for velocity divided by your unit for time…and your unit for force is your unit for acceleration multiplied by your unit for mass…and your unit for energy is your unit for force multiplied by your unit for length…and your unit for power is your unit for energy divided by your unit for time…and so on.

In this way, your calculations will automatically yield answers in the correct units.

SI makes things very easy because of everything being consistent and base 10 with the metric prefixes. It also was standardized nicely from the start. It also is based upon a number of important physical constants…so, for example, water at room temperature is about 1g/cc and it has a a specific heat of 1 calorie per gram and 100 degrees between freezing and boiling.

These days, all other systems of measurement are based on SI units, anyway, so you'll be hard pressed to find a better and easier system to work with.

The \(1.9 * 10^4\) joules of work is being done by the construction worker. The correct answer is option D.

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The correct question would be as

A construction worker is carrying a load of 40 kilograms over his head and is walking at a constant velocity. If he travels a distance of 50 meters, how much work is being done?

A. 0 joules

B. 2.0 × 102 joules

C. 2.0 × 103 joules

D. 1.9 × 104 joules ...?

Answer:

blue

Explanation:

blue is the only color being reflected, meaning it's the only one that will be visible

Answer:

please help

Explanation:

¿Cuál es la diferencia entre ciencia y tecnología?

La ciencia se refiere al proceso de explorar nuevos conocimientos metódicamente a través de la observación y los experimentos.

La tecnología se refiere al proceso de aplicar el conocimiento científico en aplicaciones prácticas para varios propósitos.

What is the difference between science and technology?

Science refers to the process of exploring new knowledge methodically through observation and experiments.

Technology refers to the process of applying scientific knowledge in practical applications for various purposes.

Answer: c) The line shows a change in speed if its angle changes.

I'm not sure

Explanation:

Answer:

50.37 m/s and 40ms object

B) The correct answer is "turning a coil of wire in a magnetic field." An electric generator converts mechanical energy into electrical energy through electromagnetic induction.

When a coil of wire is rotated in a magnetic field, the magnetic field lines cut across the wires, inducing a voltage in the wire and generating an electric current. This process is similar to the way a motor works, but in reverse. In a motor, electrical energy is converted into mechanical energy by using the magnetic fields to produce a rotational force.

The other answer choices, forming chemical bonds, breaking chemical bonds, and making electrons move at nearly the speed of light, all involve chemical or physical changes in the material. While these processes can release energy and generate electrical currents in certain circumstances, they are not the primary mechanism by which an electric generator works.

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Complete Question:

an electric generator works by group of answer choices forming chemical bond to release energy.

A. causing electric charge to flow.

B. turning a coil of wire in a magnetic field.

C. making electrons move at nearly the speed of light in a wire.

D. breaking chemical bond to release energy.

It is given that:

dependent source = A-0.2Vo

Answer:

 freezing melting sublimating  x y

 x and

Explanation:

To drop a table of states of matter the best headings must be

table name: matter state

    freezing melting sublimation x y

This order goes from the solid state to the gaseous state, which is obtained by introducing heat into the system

Answer: D on edge

X: Heat Is Absorbed

Y: Heat Is Released

Explanation:

sublimation and melting are both absorbing heat(aka getting warmer)as they change state while freezing and deposition are releasing heat(aka getting colder)as they change state

Number of photons detected per second = 3.2 × 108 per sec  we need to find total energy = 1 hour, energy of photon is given by E = h x f where h is Planck’s constant = 6.626 × 10-34 J s f is frequency of radiation.

The relationship between frequency and wavelength is given by c = f x λ where c is the speed of light which is constant = 3 × 108 m/sλ is the wavelength of radiation .In order to find the energy of photons in one hour, we will first calculate the energy of one photon.

Given wavelength and number of photons detected, we can find the frequency and hence energy of one photon using the above mentioned relationships. c = f x λ ⇒ f = c / λ = 3 × 108 / 5.5 × 10-7 = 5.4545 × 1014 Hz E = h x f = 6.626 × 10-34 x 5.4545 × 1014= 3.608 × 10-19 J.

Now, energy detected per second = 3.2 × 108 x E= 3.2 × 108 x 3.608 × 10-19= 1.154 × 10-10 Joules Total energy detected in 1 hour = energy per second x 3600 seconds= 1.154 × 10-10 x 3600= 4.154 × 10-7 Joules Hence, the total energy of the photons detected in one hour is 4.154 × 10-7 Joules.

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The answer cannot be provided in one row without knowing the radius of the disk or additional information about its geometry

To determine the angular velocity of the disk after 3 seconds, we need to consider the conservation of angular momentum. Since the cord is wrapped around the outer surface of the disk, it provides a torque that causes the disk to rotate.

The equation for angular momentum is:

L =\(I * ω\)

Where L is the angular momentum, I is the moment of inertia, and ω is the angular velocity.

In this case, the cord exerts a torque on the disk, causing it to rotate. The torque can be calculated as the tension in the cord multiplied by the radius of the disk:

τ =\(T * r\)

Since the disk is released from rest, the initial angular velocity (ω_initial) is 0. We can then relate the initial and final angular momenta as follows:

L_initial =\(I * ω_\)initial = 0

L_final =\(I * ω\)_final

Since the torque acting on the disk is constant, we can use the formula for torque and angular acceleration to relate the torque and angular momentum:

τ =\(I * α\)

Since the disk is released from rest, the angular acceleration (α) is constant. Therefore, we can write:

\(τ = I * α = I * (ω_final - ω_initial) / t\)

Simplifying the equation:

\(τ = I * α = I * ω_final / t\)

Rearranging the equation to solve for ω_final:

ω_final = (τ * t) / I

Now we can substitute the known values into the equation to calculate the angular velocity (ω_final) after 3 seconds.

Given:

Mass of the disk (m) = 3 kg

Radius of the disk (r) = ? (not provided)

Time (t) = 3 seconds

To calculate the moment of inertia (I), we need to know the radius of the disk. Since it's not provided, we cannot determine the exact angular velocity. However, we can discuss the possible options based on the given choices:

omega = 138.9 rad/s

omega = 163.3 rad/s

omega = 245.0 rad/s

omega = 490.0 rad/s

Without knowing the radius, we cannot determine the correct angular velocity. The moment of inertia depends on the distribution of mass around the axis of rotation, which is directly related to the radius of the disk.

To find the correct angular velocity, we would need the radius of the disk or additional information about the disk's geometry.

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The electric iron with a power rating of 500 watts will consume 12 kilowatt-hours (kWh) of electricity when used continuously for 24 hours.

To calculate the units consumed, we need to consider the power rating and the duration of usage. The power rating of the electric iron is given as 500 watts, which is equivalent to 0.5 kilowatts (kW). By multiplying the power rating by the time used (24 hours), we obtain the total energy consumed, which is 12 kilowatt-hours (kWh). This value represents the units of electricity consumed by the electric iron during the 24-hour period.

Therefore, the electric iron will consume 12 kilowatt-hours (kWh) of electricity when used for 24 hours continuously with a power rating of 500 watts.

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The measurement of 13.2 ounces is 0.375 kg in SI units.

To convert 13.2 ounces to SI units, we need to convert it to kilograms since the SI unit for mass is kilograms (kg).

Given:

1 lb = 16 oz

1 kg = 2.2 lbs

First, let's convert 13.2 ounces to pounds:

13.2 oz * (1 lb / 16 oz) = 0.825 lbs

Now, let's convert pounds to kilograms:

0.825 lbs * (1 kg / 2.2 lbs) ≈ 0.375 kg

Therefore, the measurement of 13.2 ounces is approximately 0.375 kg in SI units.

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