A basketball is picked up off the ground and carried to the top of a platform that is 160 feet up. It is then dropped to the ground. The ball rebounds one-half the height each time it hits the ground. What is the total vertical distance the ball will travel from the moment it is picked up to the moment it reaches its maximum height after the fourth bounce

Heat will flow from the metal to the water until both are at a temperature somewhere between 20°C and 300°C because of thermal equilibrium.

When there is no temperature differential between the system and its surroundings, a system is said to be in thermal equilibrium.

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\( \Large \text {Answer:} \)

\( \boxed {\text{Heads toward}\: 320.45\degree\: \text {at 157.70 km/h}} \)

\( \Large \text {Solution:} \)

\( V_x = 42\cos(215\degree) + 152\cos(125\degree) \\ V_x \approx -121.588 \: \text{km/h}\)

\( V_y = 42\sin(215\degree) + 152\sin(125\degree) \\ V_y \approx 100.421\: \text{km/h} \)

\( V = \sqrt{{V_x}^2 + {V_y}^2} \\ V = \sqrt{(-121.588)^2 + (100.421)^2} \\ V \approx 157.70\: \text {km/h} \\ \\ \theta = \tan^{-1}\left (\dfrac{V_y}{V_x}\right ) = \tan^{-1}\left (\dfrac{100.421}{-121.588}\right ) \\ \theta \approx -39.55\degree\: \text{or}\: 320.45\degree \)

Answer:

its 10

Explanation:

if you search it up you will see

Answer:

Explanation:

Newton's first law states that an object will not change its motion unless acted on by an unbalanced force.

If an object was acted on by a balanced force, these forces cancel out resulting in a net force of 0 newtons, which doesn't change anything for the object.

For example: A balanced force acts on a box. One man pushes the box with a force of 5 N to the right. Another man is on the other side pushing with 5 N to the left. Calculating the net force, (5-5=0) you get that the net force is 0 N. Because the net force is 0, this situation is a balanced force. Basically, the force cancels out leaving no force to act on the object, so the motion is not changed.

However, an unbalanced force results in a change to an object's motion. For example, if there was only one man pushing the box 5N to the right, the total net force would be 5 N to the right (5-0=5). Which mean the man pushing does not get cancelled out and actually affects the box by pushing it to the right by 5N.

Hope that clarifies things a little.

Newton's first law states that an object will not change its motion unless acted on by an unbalanced force.

If an object was acted on by a balanced force, these forces cancel out resulting in a net force of 0 newtons, which doesn't change anything for the object. According to Newton's first law, an item won't alter its motion unless an unbalanced force acts upon it.

When a balanced force acts on an object, these opposing forces cancel each other out, creating a net force of zero newtons, which has no effect on the object.

For instance, a box is affected by a balanced force. With a force of 5 N, one guy moves the box to the right. On the opposite side, a different man is pushing to the left with 5 N. When you calculate the net force (5-5=0), you discover that it is 0 N.

Therefore, Newton's first law states that an object will not change its motion unless acted on by an unbalanced force.

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For a rectangular storage tank filled with paraffin to a depth of 2 m, the volume, weight, mass of paraffin, and pressure at the bottom of the tank are:

a. The volume is 24 m³.

b. weight is 240,000 N,

c. mass is 24,490 kg, and

d. pressure is 23,530 Pa.

a) The volume of paraffin in the rectangular storage tank can be calculated using the formula:

Volume = Length x Width x Depth

Given:

Length = 4 m

Width = 3 m

Depth = 2 m

Substituting the values into the formula, we have:

Volume = 4 m x 3 m x 2 m

Volume = 24 m³

Therefore, the volume of paraffin in the tank is 24 cubic meters.

b) The weight of the paraffin can be calculated using the formula:

Weight = Volume x Density x Acceleration due to gravity

The density of paraffin varies, but we can assume a typical value of 10,000 kg/m³. The acceleration due to gravity is approximately 9.8 m/s². Substituting these values into the formula:

Weight = 24 m³ x 10,000 kg/m³ x 9.8 m/s²

Weight = 240,000 N

Therefore, the weight of the paraffin in the tank is 240,000 Newtons.

c) The mass of the paraffin can be calculated using the formula:

Mass = Density x Volume

Substituting the given values:

Mass = 10,000 kg/m³ x 24 m³

Mass = 24,490 kg

Therefore, the mass of the paraffin in the tank is 24,490 kilograms.

d) The pressure at the bottom of the tank due to the paraffin can be calculated using the formula:

Pressure = Weight / Area

The area of the bottom of the tank is equal to the length multiplied by the width. Substituting the values:

Area = 4 m x 3 m

Area = 12 m²

Pressure = 240,000 N / 12 m²

Pressure = 20,000 Pa

Therefore, the pressure at the bottom of the tank due to the paraffin is 20,000 Pascals (Pa).

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Answer:

129.3 mL

Explanation:

1 cubic cm= 1 millimeter

Microscope

Microscopes are known for magnifying tiny objects

The images produced by a microscope are:

virtual (formed behind the screen)

Inverted

Magnified or enlarged

Therefore, the optical instrument which produces a magnified, virtual, and inverted image is the microscope

Answer:

22 s

Explanation:

time = distance / velocity

We know that distance = 770 m and velocity = 35 m/s.

t = d / v

t = 770 m / 35 m/s

t = 22 s

It takes 22 seconds to cover 770 m. Hope this helps, thank you !!

The value added by the baker is $3. The bread's contribution to GDP is the final sale price of the bread, which is $6

In this scenario, each person involved in the production and sale of the bread adds value to the final product. The concept of value added refers to the increase in the market value of a product at each stage of production.

The farmer grows the wheat and sells it for $1. The value added by the farmer is $1.

The miller processes the wheat into flour, increasing its value. The miller sells the flour to the baker for $3, so the value added by the miller is $3 - $1 = $2.

The baker uses the flour to make bread, further adding value to the product. The baker sells the bread to the engineer for $6, so the value added by the baker is $6 - $3 = $3.

The engineer consumes the bread, but since no further economic value is added, there is no additional value added by the engineer.

The bread's contribution to GDP (Gross Domestic Product) is the final sale price of the bread, which is $6. GDP measures the total value of all goods and services produced within a country's borders, and the sale of the bread represents the final output of the production chain.

Overall, the value added at each stage contributes to the final price of the bread, and the final sale price of the bread represents its contribution to GDP.

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False.  However, a diet high in carbohydrates should also contain fat to increase endurance.

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(a) The induced current in the circuit is clockwise.

b. To find the power (P) using P = Fd/t or P = Fv (since d/t = v). Here, F = ILB (from the Lorentz force), so P = (ILB)v.

(a) The induced current in the circuit is clockwise.

This can be determined using the right-hand rule.

As the metal bar moves to the left through the magnetic field directed out of the plane, the generated force on the electrons (Lorentz force) will push them toward the top rail, creating a clockwise current.

(b) To find the rate at which the applied force is doing work on the bar, first calculate the induced EMF (ε) using Faraday's law:

induced EMF (ε) using Faraday's law:

ε = BLv

= (0.65 T) * (0.36 m) * (5.9 m/s)

= 1.389 Tm²/s

= 1.389 V (since 1 Tm²/s = 1 V)

induced current (I) using Ohm's law:

I = ε/R

= 1.389 V / 45 Ω

= 0.03086 A

force (F) from the Lorentz force law, where F = ILB:

F = ILB

= (0.03086 A) * (0.36 m) * (0.65 T)

= 0.00723 N

Finally, we find the power (P) using P = Fv:

P = Fv

= (0.00723 N) * (5.9 m/s)

= 0.04266 W

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The speed of the object for 1 second is 3 m/s.

The speed of the object for 2 seconds is 1.5 m/s.

The speed of the object for 3 seconds is 1.0 m/s.

The speed of the object for 4 seconds is 0.75 m/s.

The speed of the object for 5 seconds is 0.6 m/s.

The speed of an object is the distance travelled by the object divided by the total time taken for the motion.

The speed of the object for each of the time of motion and total distance traveled is calculated as follows;

v (1 ) = ( 3 m ) / ( 1 s ) = 3 m/s

v ( 2 ) = ( 3 m ) / ( 2 s ) = 1.5 m/s

v ( 3 ) = ( 3 m ) / ( 3 s ) = 1 m/s

v ( 4 ) = ( 3 m ) / ( 4 s ) = 0.75 m/s

v ( 5 ) = ( 3 m ) / ( 5 s ) = 0.6 m/s

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Answer:

Static friction is greater than kinetic friction, but they both act opposite the applied force.

Explanation:

Newton's 3rd law states that every action has and equal but opposite reaction.

If an object has static friction, that means it stays in one spot, and it takes a great amount of force to get it moving.

Once the object is moving it has kinetic friction, but it's easier to keep it moving unless you are trying to stop it.

The equal but opposite reaction to something moving it is stopping it, and the equal but opposite reaction to stopping something is moving it.

The same amount of force used to move/stop something is used to stop/move it.

Static friction is greater than kinetic friction, but they both act opposite the applied force.

Friction is the force that opposes motion. Frictional force always acts in opposition to the direction of motion.

There are two kinds of friction;

Since more forces tend to act on a body at rest and prevent it from getting into motion than the forces that tend to stop an already moving body, it follows that static friction is greater than kinetic friction. Both act in opposite direction to the applied force.

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The car is moving at approximately 12.5 meters per second.

The kinetic energy (KE) of an object can be calculated using the formula:

KE = 1/2 * m * \(v^2\)

where

KE = kinetic energy,

m =Mass of the object, and

v = velocity.

In this case, we are given the mass (m) of the car as 1600 kg and the kinetic energy (KE) as 125,000 J. To find the velocity .

Substituting the  values , we have:

125,000 J = 1/2 * 1600 kg *\(v^2\)

Now, we can solve for v by rearranging the equation:

\(v^2\) = (2 * 125,000 J) / 1600 kg

\(v^2\) = 156.25 \(m^2/s^2\)

Taking the square root, we find:

v = √156.25\(m^2/s^2\)

v ≈ 12.5 m/s

Therefore, the car is moving at approximately 12.5 meters per second.

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The smallest angle at which the rope can bend up from the horizontal on either side of the tightrope walker to avoid breaking is approximately 82.8 degrees.

A tightrope walker is a skilled performer who walks or performs acrobatics on a thin, flexible rope, typically suspended at a considerable height.

Let's start by calculating the weight of the walker:

weight = mass x acceleration due to gravity = 60 kg x 9.8 m/s^2 = 588 N

To avoid breaking the rope, the tension in the rope cannot exceed 5200 N. Let's assume that the angle of the rope with respect to the horizontal is θ.

The tension in the rope can be calculated using the following formula:

tension = weight / (2 x cosθ)

Where

We can rearrange this formula to solve for the angle θ:

cosθ = weight / (2 x tension)

θ = arccos(weight / (2 x tension))

Plugging in the values for weight and tension gives:

θ = arccos(588 N / (2 x 5200 N)) = 82.8 degrees

Therefore, the smallest angle at which the rope can bend up from the horizontal on either side of the tightrope walker to avoid breaking is approximately 82.8 degrees.

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Answer:

Explanation:

Let the separation required be d .

Force between rod = 10⁻⁷ x  2 I₁ I₂ L / d

where I₁ and I₂ are current in them , d is distance of separation and L is length of wire .

Force between rod = 10⁻⁷ x  2 x 1200 x  1200 x .69  / d

= .1987 /d

Restoring Force by spring = k x where k is force constant and x is compression .

= 130 x .03

= 3.9 N

For balancing

Restoring Force by spring = Force between rod

.1987 /d = 3.9

d = .1987 /3.9

= .0509 m

= 5.09 cm .

Answer:

I do apologize but I can't figure out Q 2 , 3 but

Q 1 is 1

Q4 is 0.0125%

so sorry

#1

3zeros hence significant figures will be 4

#2

\(\\ \sf\longmapsto 31.2+38.02+45\)

\(\\ \sf\longmapsto 114.22lbs\)

#3

\(\\ \sf\longmapsto 11.5s\pm 0.19s\)

\(\\ \sf\longmapsto 11.5s\pm 0.20s\)

#4

0.0125%

Answer:

If two bumper cars collide with a certain force, then they will move away from each other in opposite directions with the same force. This demonstrates Newton's third law, which states that for every action, there is an equal and opposite reaction.

Explanation:

The magnitude of the acceleration  of the engine that must be produced is 0.068 m/s².

The magnitude of the acceleration of the engine is calculated by applying the following kinematic equation.

s = vt + ¹/₂at²

where;

The acceleration of the engine in x direction is calculated as follows;

( 3.71 x 10⁸ x cos 46 ) = ( 1670 x cos73 )(8.64 x 10⁴) + ¹/₂ (ax)(8.64 x 10⁴)²

2.58 x 10⁸ = 4.22 x 10⁷ + 3.73 x 10⁹ax

3.73 x 10⁹ax = 2.16 x 10⁸

ax = ( 2.16 x 10⁸ ) / ( 3.73 x 10⁹ )

ax = 0.058 m/s²

The acceleration of the engine in y direction is calculated as follows;

( 3.71 x 10⁸ x sin 46 ) = ( 1670 x sin73 )(8.64 x 10⁴) + ¹/₂ (ay)(8.64 x 10⁴)²

2.67 x 10⁸ = 1.38 x 10⁸ + 3.73 x 10⁹ay

3.73 x 10⁹ay = 1.29 x 10⁸

ay = ( 1.29 x 10⁸ ) / ( 3.73 x 10⁹ )

ay = 0.035 m/s²

The magnitude of the acceleration  of the engine that must be produced is calculated as;

a = √ ( ax² + ay² )

a = √ ( 0.035² + 0.058² )

a = 0.068 m/s²

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Answer: An jack makes changing a tire easier because it lifts up the car to get the tire off of the ground.

Explanation:

Convert to m/s

\(\\ \sf\longmapsto v=20\times 5/18=5.5m/s\)

We know

\(\boxed{\sf \omega=\dfrac{rv}{|r|^2}}\)

\(\\ \sf\longmapsto \omega=\dfrac{0.5(5.5)}{|0.5|^2}\)

\(\\ \sf\longmapsto \omega=\dfrac{2.75}{0.25}\)

\(\\ \sf\longmapsto \omega=11rad/s\)

Dimensions are measured using a Vernier Caliper  (option A)

A device renowned for its accuracy in measuring the size of objects, the Vernier caliper functions with two jaws to hold an object steady as its scale offers readings. It can assess both external and internal measurements as well as depth with precision.

The Vernier caliper is made up of two main parts: the main scale and the vernier scale. The main scale is a graduated scale that is used to read the measurement in millimeters. The vernier scale is a smaller scale that is used to read the measurement in fractions of a millimeter.

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The magnitude and direction of the resultant force (F=10N+5N+4N+6N) when four forces of magnitude 10N, 5N, 4N, and 6N operate on an object in the directions of north, west, east, and south, respectively, is 25N.

In terms of physics, magnitude is just "distance or quantity." It displays an object's size, direction, or motion in absolute or relative terms. It is employed to indicate the size or scope of something. The word "magnitude" in physics frequently denotes a size or quantity.. Something's magnitude is determined by its size. For example, a car moves faster than a bike with terms of speed. The speed difference between the car and the bike in this case is greater. It reveals the absolute or relative size or direction that an object moves when in motion.

Speed is defined as the magnitude of velocity, and the magnitude of the slope of the displacement-time graph provides the speed. Since the slope gets steeper as we move from A to B, Speed is increased as a result between points A and B.

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Answer:

 ΔV = -2.1 L

Explanation:

To solve this exercise we can use the ideal gas equation for two points

         PV = nRT

          P₁V₁ = P₂ V₂

where point 1 is on the surface and point 2 is at the desired depth,

          V₂ = \(\frac{P_1}{P_2} \ V_1\)

let's calculate

           V₂ = ( \(\frac{1 atm}{2.5 atm}\) ) 3.5 L

            V₂ = 1.4 L

this is the new volume, the change in volume is

          ΔV = V₂ -V₁

          ΔV = 1.4-3.5

          ΔV = -2.1 L

The final temperature of the water and copper pellets is 43.8°C.

We can use the equation:

\(mc\Delta T = mwCw\Delta T\)

Substituting the values given in the problem:

m c = 28 g

m w = 90 mL = 90 g

c = 0.385 J/g°C

Cw = 4.18 J/g°C

ΔT = T f - 25°C

where T f is the final temperature of the water and copper pellets.

Simplifying the equation:

28 g x 0.385 J/g°C x (T f - 300°C) = 90 g x 4.18 J/g°C x (T f - 25°C)

Solving for T f:

T f = (90 g x 4.18 J/g°C x 25°C + 28 g x 0.385 J/g°C x 300°C) / (90 g x 4.18 J/g°C + 28 g x 0.385 J/g°C)

T f = 43.8°C

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--The complete Question is, What are the final temperature of the water and the copper pellets after thermal equilibrium is reached, assuming no heat is lost to the surroundings?  --

The falcon take 14 seconds to reach the pigeon.

A mathematical expression that expresses the location, speed, or acceleration of a body in relation to a specified frame of reference is called as Equation of motion,

By using equation of motion

s = \(\frac{1}{2}\)g\(t^{2}\)

where, s = total distance travelled by an object = 68.6 m

g = acceleration of gravity = 9.8m/\(s^{2}\)

t = time taken to travel the distance = ?

Therefore, t = \(\sqrt{2s/g}\)

t = \(\sqrt{2*68.6/9.8}\)

t = 14 seconds

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Answer:

Given:

W=104J

t=8sec

Solve:

P=?

Equation:

P=W/t or Fd/t

P= 104J'8sec

P=13W

The component that pushes right or left is referred to as the x-component, while the component that pushes up or down is referred to as the y-component.

Depending on the angle, the x-component of a vector can be either sin or cos. Cos is always associated with the right triangle side that is next to (touches) the specified angle. Shadows and force components. The components behave mathematically as shadows of the force vector on the coordinate axes.

All two-dimensional vectors have x and y components. The x-component of a vector indicates how far the vector extends horizontally. The y-component indicates how far the vector travels vertically. They are referred to as x and y components.

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The combined impact (the sum) of all pushing and pulling forces that are actually acting on an object is known as the net force. An item will accelerate in the direction of the net force if the forces pressing and pulling on it are not balanced.

The net force is the vector total of all forces acting on a particle or object. The net force, which is a single force, replaces the original forces' influence on the particle's motion.

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