A body of weight 200N is dropped from a certain height and it attains a maximum velocity before it hit the ground with this velocity it moves at a constant of proportionality 5kg/s .find
A, the terminal velocity
B.the height it moved ​

Answers

Answer 1
We can use the equations of motion and the concept of terminal velocity to solve this problem.

Let's start by finding the terminal velocity:

A. Terminal Velocity:

The terminal velocity is the maximum velocity that a falling object can reach when the resistance of the medium through which it is falling (such as air) is equal to the force of gravity acting on the object. At terminal velocity, the net force on the object is zero, so the object moves at a constant velocity.

We can find the terminal velocity using the equation:

vT = mg/k

where vT is the terminal velocity, m is the mass of the object, g is the acceleration due to gravity, and k is the constant of proportionality.

Given that the body has a weight of 200 N, its mass is:

m = F/g = 200 N/9.81 m/s^2 ≈ 20.38 kg

We are also given that the constant of proportionality is k = 5 kg/s.

Therefore, the terminal velocity is:

vT = mg/k = (20.38 kg)(9.81 m/s^2)/5 kg/s ≈ 39.77 m/s

B. Height Traveled:

Next, we can use the equations of motion to find the height that the body traveled before reaching terminal velocity. At the maximum velocity, the net force on the body is zero, so the body moves at a constant velocity. We can use the equation:

v^2 = u^2 + 2as

where v is the final velocity (terminal velocity), u is the initial velocity (which is zero), a is the acceleration, and s is the distance traveled.

We can rearrange this equation to solve for s:

s = (v^2 - u^2)/2a = v^2/2a

At terminal velocity, the acceleration is zero, so we can use the terminal velocity we found in part (A) to find the height traveled:

s = vT^2/2a = (39.77 m/s)^2/(2 × 0) = 794.60 m

Therefore, the height that the body traveled before reaching terminal velocity is approximately 794.60 meters.

Related Questions

A driver needs to make a delivery to an office that is 30 KM away. The driver has traveled for 45 minutes W. down the straight Road at 50 KM/H. Has the driver traveled far enough to reach the office? Support your response. 

Answers

Answer:

Yes, the driver traveled far enough to reach the office.

Explanation:

We can use the formula

\(v=\frac{x}{t}\)

We are given

\(x=30\) KM

\(t=45\) min

\(v=50\) KM/H

Lets convert minutes to hours.

To convert minutes to hours divide the speed by 60.

\(\frac{45}{60} =\frac{3}{4} =0.75\)

Now we have

\(x=30\) KM

\(t=0.75\) H

\(v=50\) KM/H

\(v=\frac{x}{t}\)

Solve for x.

\(x=vt\)

Lets substitute our values into the equation.

\(x=50*0.75\)

\(x=37.5\)

\(37.5 > 30\) So the answer is yes;  the driver traveled far enough to reach the office.

The driver has to travel 35 km to reach the office. The distance he covered with a speed of 50 km/h within 45 minutes or 0.75 hour is 37.5 km. Hence, he travelled enough to reach the office.

What is velocity?

Velocity of a moving body is the measure of distance it covered within unit time. The velocity is a vector quantity and have a magnitude and direction. The units of velocity are km/h, m/s etc.

Velocity is the ratio of change in distance to the change in time. Hence, distance can be calculated by multiplying the velocity with time.

Given that, velocity of the driver = 50 Km/h

time taken = 45 minutes = 45/60 =0.75 hr

Therefore, the distance = 0.75 hr × 50 km/h = 37.5 km

The distance to the office is 30 km. Therefore, the driver traveled far enough to reach the office.

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A 9,900 kg object feels a gravitational force of 12 N due to a 52,000 kg object. What is the distance between the
two objects?

Answers

Answer:

0.05 m

Explanation:

From the question given above, the following data were obtained:

Mass of first object (M1) = 9900 kg

Gravitational force (F) = 12 N

Mass of second object (M2) = 52000 kg

Distance apart (r) =?

Gravitational constant (G) = 6.67×10¯¹¹ Nm²/Kg²

Thus, we can obtain the distance between the two objects as shown below:

F = GM1M2/r²

12 = 6.67×10¯¹¹ × 9900 × 52000 /r²

Cross multiply

12 × r² = 6.67×10¯¹¹ × 9900 × 52000

Divide both side by 12

r² = (6.67×10¯¹¹ × 9900 × 52000)/12

Take the square root of both side

r = √[(6.67×10¯¹¹ × 9900 × 52000)/12]

r = 0.05 m

Therefore, the distance between the two objects is 0.05 m

3. A cylindrical steel drum is tipped over and rolled along the floor of a ware house. If the drum has radius of 0.40m and makes on complete turns in every 8.0 s, how long does it take to roll the drum 36m?​

Answers

It takes approximately 9.05 seconds to roll the drum a distance of 36 meters.

What is circumference of a circle?

We can use the formula for the circumference of a circle:

Circumference = 2 * π * radius

Given:

Radius (r) = 0.40 m

Circumference (C) = 2 * π * 0.40 m

We must figure out how many full rotations the drum makes to go 36 meters in order to calculate how long it takes to roll the drum. Since we are aware of the circumference, we can determine the number of full turns as follows:

Number of turns = Distance / Circumference

Given:

Distance = 36 m

Number of turns = 36 m / (2 * π * 0.40 m)

Now that we know how many turns there are, we can calculate the time by multiplying that number by the length of a turn, which is given as 8.0 seconds:

Time = Number of turns * Time per turn

Time = (36 m / (2 * π * 0.40 m)) * 8.0 s

By substituting the values into the equation, we can calculate the time:

Time = (36 / (2 * 3.14159 * 0.40)) * 8.0 s

Time ≈ 9.05 s

So, it takes approximately 9.05 seconds to roll the drum a distance of 36 meters.

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the object that emit light when they are hot called.......​

Answers

The object that emits light when it is hot is called luminescent.

A lever with an effort arm of 10 meters and a load arm of 2 meters is used to lift an object weighing 220 Newtons to a height of 4 meters. If 400 joules of work is done, how much force must have been applied?


100 N


4000 N


1600 N


800 N




600 Joules of work is used to lift a box from the ground to a height of six meters. How much work would have been done if a lever would have been used with an effort arm of 12 meters and a load arm of 6 meters?

600 J

100 J

72 J

50 J

Answers

The work done by using a lever with an effort arm of 12 meters and a load arm of 6 meters is 72 Joules. The force must have applied is 1600 N.

what is the calculation of work done ?The work done (in Joules) = force x distance.In this case, the force is the weight of the box (F = m * g, where m is the mass of the box and g is the acceleration due to gravity) and the distance is the height of 6 meters.Since work done is 600 J,600 J = m * g * 6When a lever is used, the work done is given by the formula:work done = effort distance x effort force = load distance x load forceEffort arm = 12 m, load arm = 6 m, and effort force = load forceSo, effort distance = load distance / (effort arm/load arm) = 6/2 = 3mTherefore, the work done by using lever = 3m x effort force = 3m x load force = 3m x mg = 3mg3 = 72 JAnd now The work done (in Joules) = force x distance.In this case, the force is the weight of the object (F = m * g, where m is the mass of the object) and the distance is the height of 4 meters.Since work done is 400 J,400 J = force * 4And by using the lever, the work done is given by the formula:work done = effort distance x effort force = load distance x load forceEffort arm = 10 m, load arm = 2 m, and effort force = load forceSo, effort distance = load distance / (effort arm/load arm) = 4/5 = 0.8mTherefore, the effort force = work done / effort distance = 400J / 0.8m = 1600 N

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If you know the answer tell me ASAP

If you know the answer tell me ASAP

Answers

In order to measure the potential difference across one of the bulbs in the circuit, the voltmeter must be connected in parallel with it. So, option D.

When two points in a circuit have different electric potentials, a voltmeter is a tool or instrument that measures their potential difference.

We are aware that a voltmeter is a tool that measures the same potential drop in all configurations that are in parallel.

The potential difference between two points in a circuit is thus always measured by connecting a voltmeter in parallel across the conductor's ends.

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6. When can you say that an object is accelerating?
A. when the speed remains the same
B. When the speed is changing
C. when the instantaneous velocity is the same
D. When there is a uniform motion

give explanation ​

Answers

Answer:

When the speed is changing is the correct answer

Explanation:

Because acceleration is rate of change of velocity

PLEASE MARK ME BRAINLIEST IF MY ANSWER IS CORRECT PLEASE

You need to load a crate of mass m onto the bed of a truckon earth. One possibility is just to lift the crate straight up over a height h, equal to height of the truck's bed. Theforce exert in this case is F1 and the work done in this case is W1. The other possibility is to slide the crate up the frictionless ramp of length L.. In this case you exert force F2 and perform work W2. Which statement is true?

a. F1 > F2 and W1 > W2
b. F1 = F2 and W1 > W2
c. F1 = F2 and W1 = W2
d. F1 > F2 and W1< W2
e. F1 > F2 and W1 = W2

Answers

Answer:

The correct answer is - option E. e. F1 > F2 and W1 = W2

Explanation:

Case 1 - F1 = mg, m= mass and g = gravitational force

Work done W1 = F1h= mgh (h - height of bed of truck)

Case 2 - F2 = mgsinθ

work done W2 = mgsinθ×L (L=length of ramp ans sin θ angle of ramp)

sinθ = h/l, then W2 = mg(h/L)L

W2 = mgh

By comparing both,

F2 = mgsinθ and F1 = mg therefore,

F2>F1

now, W2 = mgh, and W1 = mgh

therefore, W2 = W1.

If you borrow $12250 and pay $147 in annual interest, the APR on your loan is 1.2% 14.7% 1.23% 7.35%

Answers

Answer: 1.2%

Explanation:

Given

If one borrows $12,250

and give $147 interest on it

Then the interest is given from the formula

\(\Rightarrow S.I=\dfrac{P\times R\times T}{100}\\\\\Rightarrow 147=\dfrac{12,250\times R\times 1}{100}\\\\\Rightarrow R=\dfrac{147}{122.50}\\\\\Rightarrow R=1.2\%\)

Thus, the annual rate of interest  is 1.2%

If the boat in the preceding example travels with the same speed of 20 km h¹¹ relative to the water and is to travel due north, in what direction should it travel?​

Answers

In the preceding example, we found that the boat needs to travel in a direction of 11.3 degrees west of north relative to the Earth to move directly across the river.

If the boat is now to travel due north relative to the Earth, we need to find the direction it should travel relative to the water, taking into account the effect of the river's velocity.

Since the boat is traveling with a speed of 20 km/h relative to the water, and the water is flowing with a velocity of 8 km/h in a direction of 60 degrees south of east, we can use vector addition to find the boat's resultant velocity relative to the Earth.

Let's define the x-axis as east and the y-axis as north. The velocity of the water is then:

Vw = 8 km/h at an angle of 240 degrees (60 degrees south of east)

We can convert this to vector form:

Vw = (-4 km/h, -6.93 km/h)

The velocity of the boat relative to the water is:

Vb = 20 km/h at an angle of 0 degrees (due north)

We can convert this to vector form:

Vb = (0 km/h, 20 km/h)

To find the resultant velocity, we can add these two vectors:

Vr = Vb + Vw

Vr = (0 km/h - 4 km/h, 20 km/h - 6.93 km/h)

Vr = (-4 km/h, 13.07 km/h)

The direction of this vector is given by:

tan θ = (13.07 km/h) / (-4 km/h)

θ = -73.74 degrees

Since we defined the x-axis as east, the direction of the boat's velocity relative to the water is 73.74 degrees east of north.

To find the direction the boat should travel relative to the water to move due north, we need to subtract this angle from 90 degrees:

90 degrees - 73.74 degrees = 16.26 degrees

Therefore, the boat should travel in a direction of 16.26 degrees west of north relative to the water to move due north relative to the Earth.

Calculate the speed of sound in a string that has a tension of 100 N and a linear mass density of 0.0001 kg/m

Answers

You will need to divide it.

what conditions made it possible for earth's interior to separate into layer?

Answers

Answer:

Separation of the Earth into layers (crust, mantle, inner core, and outer core) was largely caused by gravitational differentiation (separating different constituents at temperature where materials are liquid or plastic, owing to differences in density) early in Earth's history.

Explanation:

hoped it helped!!

2. A car of mass 1000kg is being tied along the horizontal road by a rope making an angle of 30° with the horizontal. If the tension in the north rope is 200N and what is the acceleration ​

Answers

The acceleration of the car is determined as 0.35 m/s².

What is the acceleration of the car?

The acceleration of the car is calculated by applying the formula for Newton's second law of motion as follows;

F(net) = ma

where;

F(net) is the net forcem is the mass of the cara is the acceleration of the car

Fy = F sinθ

200 = F x sin(30)

F = 200 / sin(30)

F = 400 N

The tension in horizontal direction;

Fₓ = 400 N x cos(30)

Fₓ = 346.4 N

The acceleration of the car is calculated as;

a = Fₓ / m

a = 346.4 / 1000

a = 0.35 m/s²

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Impulse is equal to ... (pick TWO answers)

A. the change in momentum of an object.
B. the change in mass of an object.
C.the change in volume of an object.
D. a force applied to an object for a period of time.
E. the original momentum of the object.​

Answers

Answer:

A

Explanation:

Momentum change is basically impulse

Object possessing more velocity after bouncing OR the object which bounces more have more impulse

One of the fastest roller coasters (2000 kg) in the world is the Magnum XL - 200 at
Cedar Point Park in Sandusky, Ohio. This ride includes an initial vertical drop of 59.3 m.
Assume that the roller coaster has a speed of nearly zero as it crests the top of the hill.
a. If the track was frictionless, find the speed of the roller coaster at the bottom of
the hill.

Answers

The speed of the roller coaster at the bottom of the hill is 33.9 m/s.

The conservation of mechanical energy is used to determine the speed of the roller coaster at the bottom of the hill, as there is no friction. According to the law of conservation of energy, mechanical energy is constant at all points in a frictionless environment.Let's look at the equation below:PEg + KE = PEg + KEwhere PEg is gravitational potential energy and KE is kinetic energyThe kinetic energy is maximum and the gravitational potential energy is zero when the roller coaster is at the bottom of the hill. The gravitational potential energy is highest when the roller coaster is at the top of the hill, with its potential energy equal to its kinetic energy when it reaches the bottom of the hill.Initially, the roller coaster is at rest at the top of the hill. The gravitational potential energy of the roller coaster is transformed into kinetic energy as it descends the hill. We can calculate the speed of the roller coaster using the law of conservation of energy.Solution:Given,Height of the hill, h = 59.3 mGravitational acceleration, g = 9.8 m/s²Mass of roller coaster, m = 2000 kgWe need to find the speed of the roller coaster at the bottom of the hill, v.To begin, calculate the potential energy at the top of the hill.Potential energy at the top of the hill = mgh Where m is the mass of the roller coaster, g is the acceleration due to gravity, and h is the height of the hill.

The potential energy at the top of the hill is given by:PEg = mgh= 2000 kg × 9.8 m/s² × 59.3 m= 1.15 × 10⁶ JNow, let's figure out the velocity at the bottom of the hill.Using the conservation of energy, we can write,PEg = KE + KEwhere PEg is gravitational potential energy and KE is kinetic energyThe gravitational potential energy is equal to the kinetic energy.KE = PEg= 1.15 × 10⁶ JKE = 1/2 × mv²Where m is the mass of the roller coaster and v is the velocity of the roller coaster.Substituting the given values in the above equation, we get;1.15 × 10⁶ = 1/2 × 2000 × v²v² = (2 × 1.15 × 10⁶) / 2000v² = 1150v = √1150v = 33.9 m/s.

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What is the momentum in kg m/s of a 42.9 g golf ball traveling at 78.2 m/s? If the impact of the golf club on the ball occurs over a time of 2 x 10^-3 seconds, b). what force does the ball experience to accelerate from rest to 78.2 m/s?

Answers

Explanation:

force=(42.9/1000) × (78.2-0/(2 × 10^-3))

=1528.81N

How did earth change about 2.5 billion years ago when many organisms began using photosynthesis to make food

A. The amount of oxygen in the atmosphere increased

B. Mass extinctions occurred

C. The oceans became larger

D. Rainfall increased

Answers

The amount of oxygen in the air was increased

You and your friends are at the lake on a particularly sunny day. Use specific heat capacity to explain why the sand on the shores of the lake feels so much hotter than the water in the lake even though the same solar energy is being absorbed by both materials.

Answers

Answer:

well the water is way bigger and cant hold much heat while the sand

is smaller than the ocean and is able to hold heat

Explanation:

i dont have one ;-;

Answer:

hi

Explanation:

1. The kinetic energy of a car is 8  106 J as it travels along a horizontal road. How much work is required to stop the car in 10 s? (A) zero joules (B) 8  105 J (C) 8  107 J (D)8  104 J (E) 8  106 J​

Answers

The power to stop the car with kinetic energy of a car is  \(8*10^{6} J\) as it travels along a horizontal road is  \(8*10^{5} watt\), option B

What is Kinetic energy ?

Kinetic energy can be seen as one that is been recorded when an object is able to move from a place , in a broad term we can say this is the energy that can be attributed to that of someone leaving a place and go to another place hence we can see it as the one in the motion.

The definition of energy as the "power to accomplish work" refers to the capacity to apply a force that moves an object. Even if the word is vague, it is clear what energy actually means: it is the force that causes objects to move. The two types  can be attributed to the one we know which are kinetic and potential energy.

\(Power \frac{Energy}{time}\)

\(Energy = 8*10^{6} J\)

\(time = 10 s\)

\(Power = \frac{8*10^{6} J}{10}\)

\(power = 8*10^{5} watt\)

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proper question;

The kinetic energy of a car is 8 × 106 J as it travels along a horizontal road. How much power is required to stop the car in 10 s? (A) zero joules (B) 8  105 J (C) 8  107 J (D)8  104 J (E) 8  106 J​

A box weighs 300N. A force of 20N slide it across a floor at a constant speed. What is the mass of the box? What is the acceleration of the box?

Answers

Answer:

Mass = 30kg

Acceleration = 0m/s/s

Explanation:

The weight of an object is its mass multiplied by the gravitational field strength. On Earth the value often used for gravity is 10N/kg. This means there is 10N of force per kg of mass, so the weight of an object will be 10x its mass. Here we are given a weight of 300N, so to find its mass we simply need to divide it by 10. 300/10 = 30kg. The mass of the box is 30kg.

Because the box is being slid across the floor at a constant speed, the velocity is not changing, therefore the acceleration is 0.

Hope this helped!

Answer:

Mass = 30 kg

Acceleration = 0 m / s²

Explanation:

Gravity = 10 N / kg

Thus the mass = 30 kg

We know that the box slide in a constant speed

Thus it doesn't have any acceleration.

Hopefully this answer helps you :)

A gust of wind blows an apple from a tree. As the apple falls, the force of gravity on the apple is 9.13 N downward, and the force of the wind on the apple is 1.31 N to the right. What is the magnitude of the net external force on the apple? Answer in units of N.​

Answers

Answer: See the diagram,from the vevtor addition we can say,net force acting on the apple is =

2.25

2

+

1.05

2

+

2

2.25

1.05

cos

90

=

2.48

N

And,this resultant force makes an angle of

tan

1

(

1.05

2.25

)

or,

25

degrees w.r.t vertical

find the magnitude of the vecter c that satisfies the equation 2A-6B+3C=2j

Answers

Answer:

We can solve for the magnitude of vector C by first isolating it on one side of the equation:

2A - 6B + 3C = 2j

3C = 2j - 2A + 6B

C = (2/3)j - (2/3)A + 2B

Now that we have an expression for vector C, we can find its magnitude using the formula:

|C| = sqrt(Cx^2 + Cy^2 + Cz^2)

where Cx, Cy, and Cz are the x, y, and z components of vector C, respectively.

Since the equation only gives us information about the y-component of vector C, we can assume that the x and z components are zero. Therefore,

Cx = 0

Cy = 2/3

Cz = 0

|C| = sqrt((0)^2 + (2/3)^2 + (0)^2)

|C| = sqrt(4/9)

|C| = 2/3

Therefore, the magnitude of vector C is 2/3.

describe the relationship of the atoms shown above
choices:

describe the relationship of the atoms shown abovechoices:

Answers

Answer:

I don't know.

the mass of a density bottle is 18.00g when empty 44.00g when full of water, and 39.84g when full up of a second liquid. calculate the density of the liquid where density of water =1000kgm³​

Answers

The density of the second liquid is 0.812 g/cm³

To calculate the density of the second liquid, we need to use the principle of displacement. The mass of the liquid can be found by subtracting the mass of the empty density bottle from the mass of the bottle filled with the liquid. Therefore, the mass of the liquid is:

mass of liquid = mass of bottle + liquid - mass of empty bottle

mass of liquid = 39.84g + x - 18.00g

where x is the mass of the liquid.

We can now use the density formula, which is:

density = mass/volume

The volume of the liquid is equal to the volume of the density bottle that is filled with the liquid, which can be calculated by subtracting the volume of the empty bottle from the volume of the bottle filled with the liquid. Therefore, the volume of the liquid is:

volume of liquid = volume of bottle filled with liquid - volume of empty bottle

We can now substitute this expression into the density formula to get:

density of liquid = mass of liquid / (volume of bottle filled with liquid - volume of empty bottle)

We know that the density of water is 1000 kg/m³, which is equal to 1 g/cm³. We can use this to find the volume of the liquid by dividing the mass of water by its density:

volume of water = mass of water / density of water

volume of water = 44.00g / 1 g/cm³

volume of water = 44.00 cm³

Now, we can calculate the volume of the density bottle filled with the second liquid by using the principle of displacement:

volume of bottle filled with liquid = volume of water - volume of liquid

volume of bottle filled with liquid = 44.00 cm³ - (39.84g - 18.00g) / 1 g/cm³

volume of bottle filled with liquid = 44.00 cm³ - 21.84 cm³

volume of bottle filled with liquid = 22.16 cm³

Finally, we can substitute these values into the density formula to get:

density of liquid = x / 22.16 cm³

Solving for x, we get:

x = density of liquid x 22.16 cm³

Substituting x back into the mass equation, we get:

mass of liquid = 39.84g + (density of liquid x 22.16 cm³) - 18.00g

Solving for the density of the liquid, we get:

density of liquid = (mass of liquid - 21.84g) / 22.16 cm³

Substituting the given values, we get:

density of liquid = (39.84g - 21.84g) / 22.16 cm³ = 0.812 g/cm³

In conclusion, the density of the second liquid is 0.812 g/cm³. This value is less than the density of water, which means that the second liquid is less dense than water and will float on top of water.

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Mention 2 everyday applications each of conduction, convection and radiation​

Answers

Answer:

Conduction: Touching a stove and being burned. Ice cooling down your hand. .

Explanation:

a car is moving 5.82 m/s when it accelerates at 2.35 m/s2 for 3.25, what is its final velocity

Answers

The final velocity of the car can be calculated using the formula: final velocity = initial velocity + acceleration * time. Plugging in the values you provided, we get: final velocity = 5.82 m/s + 2.35 m/s² * 3.25 s = 13.44 m/s.

What is an example illustrating gravitational potential energy transforming into kinetic energy?

What is an example illustrating gravitational potential energy transforming into kinetic energy?

Answers

Answer:

A. a hammer dropped off a roof accelerates as it falls.

Explanation:

The example that illustrates gravitational potential energy transforming into kinetic energy is a hammer dropped off a roof accelerating as it falls.

 Gravitational potential energy is the energy due to the position of a body.

A hammer held up at roof level has a measure of gravitational potential energy.

As it drops and begins to accelerate, the energy is converted to kinetic energy. Kinetic energy is the energy due to the motion of a body.

The acceleration due to gravity causes the body to move.

So, the gravitational potential energy is converted to kinetic energy.

A researcher would like to perform an experiment in a zero magnetic field, which means that the field of the earth must be canceled. Suppose the experiment is done inside a solenoid of diameter 1.0 m, length 4.6 m , with a total of 5000 turns of wire. The solenoid is oriented to produce a field that opposes and exactly cancels the 52 μT local value of the earth's field.
What current is needed in the solenoid's wires?
Express your answer to two significant figures and include the appropriate units.

Answers

Answer:

I = 3.81 x 10⁴ A

Explanation:

The magnetic field of a solenoid must be equal to the field of earth:

\(Field\ of\ Earth = Field\ of\ Solenoid\\52\ T = \mu n I\\I = \frac{52}{\mu n}\)

where,

I = current passing through solenoid = ?

μ = permeability of free space = 4π x 10⁻⁷ N/A²

n = no. of turns per unit length = \(\frac{5000\ turns}{4.6\ m}\) = 1086.96 /m

Therefore,

\(I = \frac{52\ T}{(4\pi\ x\ 10^{-7}\ N/A^2)(1086.96\ /m)}\)

I = 3.81 x 10⁴ A

w
х
2. Identify the correct statement about the diagrams above.
O Y represents a mixture and Z represents an element.
O Y represents an compund and X represents a pure substance.
O X represents a mixture and W represents a pure substance
O W represents an element and Y represents a mixture.

w2. Identify the correct statement about the diagrams above.O Y represents a mixture and Z represents

Answers

Answer: W represents an element Y represents a mixture

Explanation: I just took a quiz on this and got it right. Good Luck

A student drops a pen from a classroom window on the third floor of the mathematics building. If the pen is dropped from33 ft above ground level, at what velocity does the pen hit the ground? Use - 32 ft/s2 for the acceleration caused by gravity.Ignore air resistance. Round any intermediate calculations to no less than six decimal places, and round your final answer totwo decimal places.

A student drops a pen from a classroom window on the third floor of the mathematics building. If the

Answers

Answer:

45.96 m/s

Explanation:

To find the velocity when the pen hits the ground, we will use the following equation

\(v^2_f=v^2_i+2ay\)

Where vf is the velocity when the pen hits the ground, vi is the initial velocity, a is the acceleration and y is the height of the building.

So, replacing vi = 0 m/s, a = -32 ft/s², and y = -33 ft, we get

\(\begin{gathered} v^2_f=0^2+2(-32)(-33) \\ v^2_f=2112 \\ vf=\sqrt[]{2112} \\ v_f=45.96\text{ m/s} \end{gathered}\)

Then, the pen hit the ground at 45.96 m/s

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