Answers
The specific gravity of the other fluid in the bottle with a mass of 53.22 g is determined to be 0.8879.
The ratio of a material's density to a predetermined reference substance is the substance's specific gravity. If anything has a specific gravity, it will either float or sink. When tested against water, the specific gravity of a solid or liquid is compared; if it is less than one, it will float, and if it is greater than one, it will sink. Then, the specific gravity of a material is given by, \(RD = \frac{\rho_{\text{substance}}}{\rho_{\text{reference}}}\).
The mass of water in the bottle is 95.94 g - 36.00 g = 59.94 g. And the mass of another fluid in the bottle is 89.22 g - 36.00 g = 53.22 g. Then,
\(\begin{aligned}\text{specific gravity of other fluid}&=\frac{\rho_{\text{fluid}}}{\rho_{\text{water}}}\\&=\frac{\frac{m_f}{V}}{\frac{m_w}{V}}\\&=\frac{m_f}{m_w}\\&=\frac{53.22}{59.94}\\&=0.8879\end{aligned}\)
The answer is 0.8879.
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Related Questions
How does a wind turbine transform mechanical energy into electrical energy?
Answers
Answer:
"A turbine takes the kinetic energy of a moving fluid, air in this case, and converts it to a rotary motion. As wind moves past the blades of a wind turbine, it moves or rotates the blades. These blades turn a generator."
What type of tv uses a VfL for backlighting
Answers
A VfL (Vertical Field LED) backlighting system is commonly used in LCD (Liquid Crystal Display) televisions.
LCD TVs rely on a backlight to illuminate the liquid crystal layer, which controls the passage of light to create the visual image. The VfL technology is a specific type of LED backlighting arrangement used in certain LCD TV models. In a VfL backlighting system, the LEDs (Light-Emitting Diodes) are positioned vertically along the edges of the LCD panel.
The light emitted by these LEDs is directed across the panel using light guides or optical films, illuminating the liquid crystal layer uniformly. One advantage of VfL backlighting is its ability to provide consistent illumination across the LCD panel, reducing any potential inconsistencies in brightness or color uniformity. The vertical orientation of the LEDs allows for more precise control over light distribution, improving overall image quality.
Additionally, VfL backlighting offers potential advantages in terms of power efficiency. By selectively dimming or turning off specific zones of LEDs, local dimming techniques can be employed to enhance contrast and black levels, resulting in improved picture quality while conserving energy. It's important to note that VfL backlighting is just one of several backlighting technologies available for LCD TVs.
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Which of the following solutions contains the smallest total concentration of ions, assuming complete dissociation?
a) 2 M AI2(SO4)3
b) 2 M AICl3
c) 2 M NaCl
d) 2 M CaCl2
Answers
The solution with the lowest total ion concentration, assuming full dissociation, is 2 M aluminum sulphate.
What is concentration?Concentration in chemistry is defined as the abundance of an ingredient divided by the total volume of a combination. There are four sorts of mathematical descriptions: mass concentration, molar concentration, number concentration, and volume concentration. The amount of a material, such as salt, that is present in a certain amount of tissue or liquid, such as blood. When there is less water present, a material becomes more concentrated. When a person does not drink enough water, the salt in his or her urine may become more concentrated. A substance's concentration is the amount of solute contained in a given amount of solution. Molarity is the number of moles of solute in one liter of solution and is used to express concentrations.
Here,
The solution with the lowest total ion concentration, assuming full dissociation, is 2 M aluminum sulfate.
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Which of the following scenarios will generate electricity using electromagnetic induction?
A. a highly conductive meatal moving within magnetic field
B. a changing magnetic field surrounded by plastic wires
C. electricity Being applied to a magnet
Answers
Answer:
A generates electricity, the others do not
Explanation:
Predict what will happen to the disk of an uncharged electroscope when a positively charged obsject is brought near the disk.
I said: All of the positive charges in the disk will move towards the vanes in the electroscope, being repelled by the similarly charged obsject. When a positively charged object is brought near the uncharged disk of an electroscope then the positive charges attract the negative charges from the disk and repel positive charges from the disk. So, the unchaged disk will become positively charged.
QUESTION: Continue your previous answer so that you describe what happens to the charge in the other parts of the electroscope. Use this to infer what happens to the vanes.
Answers
When a positively charged object is brought near an uncharged electroscope, the vanes will move apart due to the separation of charge within the electroscope.
As the positive charges in the disk are repelled by the positively charged object and move towards the vanes, the negative charges in the disk are attracted to the positively charged object and move towards it. This creates a separation of charge within the electroscope, with the disk becoming positively charged and the vanes becoming negatively charged. As a result, the vanes will repel each other and move apart. This movement of the vanes is an indication of the presence of charge in the electroscope.
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QUESTION 10
An archer fires an arrow towards a tree with initial speed 65 m/s and angle 25 degrees above the horizontal. If the arrow takes 0.85
seconds to hit the tree, calculate the horizontal distance between the archer and the tree.
QUESTION 11
A monkey throws a banana from a tree into a nearby river. The banana has initial speed 7.6 m/s, is angled 40 degrees below the
horizontal, and takes 0.75 seconds to land in the river. Calculate the speed of the banana when it hits the water.
Answers
Answer:
10) The distance between the archer and the tree is 50.074 meters.
11) The speed of the banana when it hits the water is approximately 13.554 meters per second.
Explanation:
10) The arrow experiments a parabolic motion, which is the combination of horizontal motion at constant velocity and vertical uniform accelerated motion. In this case we need to find the horizontal distance between the archer and the tree, calculated by the following kinematic equation:
\(x = x_{o} +v_{o}\cdot t \cdot \cos \theta\) (Eq. 1)
Where:
\(x_{o}\) - Initial position of the arrow, measured in meters.
\(x\) - Final position of the arrow, measured in meters.
\(v_{o}\) - Initial speed of the arrow, measured in meters per second.
\(t\) - Time, measured in seconds.
\(\theta\) - Launch angle, measured in sexagesimal degrees.
If we know that \(x_{o} = 0\,m\), \(v_{o} = 65\,\frac{m}{s}\), \(t = 0.85\,s\) and \(\theta = 25^{\circ}\), the horizontal distance between the archer and the tree is:
\(x = 0\,m + \left(65\,\frac{m}{s}\right)\cdot (0.85\,s)\cdot \cos 25^{\circ}\)
\(x = 50.074\,m\)
The distance between the archer and the tree is 50.074 meters.
11) The final speed of the banana (\(v\)), measured in meters per second, just before hitting the water is determined by the Pythagorean Theorem:
\(v = \sqrt{v_{x}^{2}+v_{y}^{2}}\) (Eq. 2)
Where:
\(v_{x}\) - Horizontal speed of the banana, measured in meters per second.
\(v_{y}\) - Vertical speed of the banana, measured in meters per second.
Each component of the speed are obtained by using these kinematic equations:
\(v_{x} = v_{o}\cdot \cos \theta\) (Eq. 3)
\(v_{y} = v_{o}\cdot \sin \theta +g\cdot t\) (Eq. 4)
Where \(g\) is the gravitational acceleration, measured in meters per square second.
If we know that \(v_{o} = 7.6\,\frac{m}{s}\), \(\theta = -40^{\circ}\), \(g = -9.807\,\frac{m}{s^{2}}\) and \(t = 0.75\,s\), the components of final speed are, respectively:
\(v_{x} = \left(7.6\,\frac{m}{s} \right)\cdot \cos (-40^{\circ})\)
\(v_{x} = 5.822\,\frac{m}{s}\)
\(v_{y} = \left(7.6\,\frac{m}{s}\right)\cdot \sin (-40^{\circ})+\left(-9.807\,\frac{m}{s^{2}} \right) \cdot (0.75\,s)\)
\(v_{y} = -12.240\,\frac{m}{s}\)
And the speed of the banana right before hitting the water is:
\(v = \sqrt{\left(5.822\,\frac{m}{s} \right)^{2}+\left(-12.240\,\frac{m}{s} \right)^{2}}\)
\(v \approx 13.554\,\frac{m}{s}\)
The speed of the banana when it hits the water is approximately 13.554 meters per second.
A 9,900 kg object feels a gravitational force of 12 N due to a 52,000 kg object. What is the distance between the
two objects?
Answers
Answer:
0.05 m
Explanation:
From the question given above, the following data were obtained:
Mass of first object (M1) = 9900 kg
Gravitational force (F) = 12 N
Mass of second object (M2) = 52000 kg
Distance apart (r) =?
Gravitational constant (G) = 6.67×10¯¹¹ Nm²/Kg²
Thus, we can obtain the distance between the two objects as shown below:
F = GM1M2/r²
12 = 6.67×10¯¹¹ × 9900 × 52000 /r²
Cross multiply
12 × r² = 6.67×10¯¹¹ × 9900 × 52000
Divide both side by 12
r² = (6.67×10¯¹¹ × 9900 × 52000)/12
Take the square root of both side
r = √[(6.67×10¯¹¹ × 9900 × 52000)/12]
r = 0.05 m
Therefore, the distance between the two objects is 0.05 m
34. [8 Marks] A spring is compressed with a 5.0 kg mass by 20.0 cm from its equilibrium position. When the spring is released, the 5.0 kg mass travels along a smooth horizontal surface and then up a frictionless plane at 30° to the horizontal. Calculate the distance it would travel up the inclined plane before coming back down again.
Answers
Answer and Explaination:
To solve this problem, we can analyze the forces acting on the mass as it travels up the inclined plane. We'll consider the gravitational force and the force exerted by the spring.
1. Gravitational force:
The force due to gravity can be broken down into two components: one perpendicular to the inclined plane (mg * cosθ) and one parallel to the inclined plane (mg * sinθ), where m is the mass and θ is the angle of the inclined plane.
2. Force exerted by the spring:
The force exerted by the spring can be calculated using Hooke's Law, which states that the force exerted by a spring is directly proportional to the displacement from its equilibrium position. The force can be written as F = -kx, where F is the force exerted by the spring, k is the spring constant, and x is the displacement from the equilibrium position.
Given:
Mass (m) = 5.0 kg
Compression of the spring (x) = 20.0 cm = 0.20 m
Angle of the inclined plane (θ) = 30°
First, let's find the force exerted by the spring (F_spring):
F_spring = -kx
To find k, we need the spring constant. Let's assume that the spring is ideal and obeys Hooke's Law linearly.
Next, let's calculate the gravitational force components:
Gravitational force parallel to the inclined plane (F_parallel) = mg * sinθ
Gravitational force perpendicular to the inclined plane (F_perpendicular) = mg * cosθ
Since the inclined plane is frictionless, the force parallel to the inclined plane (F_parallel) will be canceled out by the force exerted by the spring (F_spring) when the mass reaches its highest point.
At the highest point, the gravitational force perpendicular to the inclined plane (F_perpendicular) will be equal to the force exerted by the spring (F_spring).
Therefore, we have:
F_perpendicular = F_spring
mg * cosθ = -kx
Now, let's substitute the known values and solve for k:
(5.0 kg * 9.8 m/s^2) * cos(30°) = -k * 0.20 m
49.0 N * 0.866 = -k * 0.20 m
42.426 N = -0.20 k
k = -42.426 N / (-0.20 m)
k = 212.13 N/m
Now that we know the spring constant, we can calculate the maximum potential energy stored in the spring (PE_spring) when the mass reaches its highest point:
PE_spring = (1/2) * k * x^2
PE_spring = (1/2) * 212.13 N/m * (0.20 m)^2
PE_spring = 4.243 J
The maximum potential energy (PE_spring) is equal to the maximum kinetic energy (KE_max) at the highest point, which is also the energy the mass has gained from the spring.
KE_max = PE_spring = 4.243 J
Next, we can calculate the height (h) the mass reaches on the inclined plane:
KE_max = m * g * h
4.243 J = 5.0 kg * 9.8 m/s^2 * h
h = 4.243 J / (5.0 kg * 9.8 m/s^2)
h = 0.086 m
The height the mass reaches on the inclined plane is 0.086 m.
Now, we can calculate the distance traveled.
A 5.0 kg object compresses a spring by 0.20 m with a spring constant of 25 N/m. It climbs an incline, reaching a maximum height of 0.0102 m before coming back down, traveling a total distance of 0.0428 m.
Given data: Mass of the object, m = 5.0 kg, Displacement of the spring, x = 20.0 cm = 0.20 mAngle of the inclined plane, θ = 30°Calculating the spring constant, k. Using Hooke’s Law; F = -kx Where F is the restoring force required to bring the spring back to its equilibrium position.From the equation, F = ma For the object attached to the spring,m * a = -kx. On integrating,∫ma dt = -∫kx dt .On integrating the left side with limits from 0 to t and right side with limits from 0 to x, where the limits on the left are for acceleration and the right are for the displacement of the spring; mv - mu = -½ kx²At maximum compression, the velocity of the mass is zero, i.e., v = 0 and the initial velocity is also zero. Therefore, mv - mu = -½ kx²0 - 0 = -½ k (0.20)²∴ k = 25 N/mWork done on the spring in compressing it, W = ½ kx² = 0.5 * 25 * (0.20)² = 0.5 JSince the inclined plane is frictionless, the only force acting on the object will be the component of its weight acting along the plane. Hence, it will move up the incline with an acceleration of, a = g sin θ = 9.8 * sin 30° = 4.9 m/s²When the object has reached its maximum height, its velocity will be zero. Using the equation of motion; v² - u² = 2as0 - u² = 2as∴ s = u² / 2a. Now, the initial velocity of the object up the incline is,u = √(2gH)Where H is the height to which it climbs, and is given by, H = W / m g Where W is the work done on the object in lifting it to height H, and m is the mass of the object. W = 0.5 J, m = 5 kg. So, H = 0.5 / (5 * 9.8) = 0.0102 m∴ u = √(2gH) = √(2 * 9.8 * 0.0102) = 0.4525 m/sNow, the distance traveled by the object up the incline is,s = u² / 2a = (0.4525)² / (2 * 4.9) = 0.0214 m. When the object comes back down, it will travel the same distance down the incline, before coming to rest. Therefore, the total distance travelled up and down the incline is,2s = 2 * 0.0214 = 0.0428 m.For more questions on the spring constant
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One elevator arrangement includes the passenger car, a counterweight, and two large pulleys, as shown in Figure 11-50. Each pulley has a radius of 1.2 m and a moment of inertia of 380 kg•m². The top pulley is driven by a motor. The elevator car plus passengers has a mass of 3100 kg, and the counterweight has a mass of 2700 kg. If the motor is to accelerate the elevator car upward at 1.8 m/s², how much torque must it generate? Hint: The two pulleys move together, so you can model them as a single pulley with the sum of the moments of inertia.
Answers
The torque generated by the motor, accelerating with 1.8 m / \(s^{2}\) Of the elevator is, 18372 Nm.
What is torque?The force which causes the object to rotate about any axis is called torque. In math form, it is equivalent to the product of force and perpendicular distance.
Given: Radius of pulley (r) = 1.2 meters;
Moment of inertia of pulley (I) = 380 kg\(m^{2}\)
Mass of elevator plus passenger (M) = 3100 kg;
Mass of counterweight (W) = 2700 kg;
Now if the rope tension is \(T_{2}\) then
\(T_{2}\) = 3100 × (9.8 + 1.8)
\(T_{2}\) = 35960 N
If \(T_{1\) is the counterweight tension then
\(T_{1\) = 2700 × (9.8 - 1.8) N
\(T_{1\) = 21600 N
Now Angular acceleration (α) = a / r
α = 1.8 / 1.2
α = 1.5 rad / sec
If T is the total torque then
\(T = 2*I*\alpha +(T_{2} -T_{1} )*r\)
T = 2 × 380 × 1.5 + (35960 - 21600) ×1.2
T = 18372 Nm
Therefore, the total torque generated is 18372 Nm.
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The half-life of a radioactive isotope is 210 d. How many days would it take for the decay rate of a sample of this isotope to fall to 0.58 of its initial rate?
Answers
It would take approximately 546 days for the decay rate of the sample of this radioactive isotope to fall to 0.58 of its initial rate.
1. The decay rate of a radioactive isotope is proportional to the number of radioactive atoms present in the sample at any given time.
2. The decay rate can be expressed as a function of time using the formula: R(t) = R₀ * \(e^{(-\lambda t\)), where R(t) is the decay rate at time t, R₀ is the initial decay rate, λ is the decay constant, and e is the base of the natural logarithm.
3. The half-life of a radioactive isotope is the time it takes for half of the radioactive atoms in a sample to decay. In this case, the half-life is given as 210 days.
4. Using the half-life, we can find the decay constant (λ) using the formula: λ = ln(2) / T₁/₂, where ln(2) is the natural logarithm of 2 and T₁/₂ is the half-life.
5. Substituting the given half-life into the formula, we have: λ = ln(2) / 210.
6. Now, we need to find the time it takes for the decay rate to fall to 0.58 of its initial rate. Let's call this time "t".
7. Using the formula for the decay rate, we can write: 0.58 * R₀ = R₀ * e^(-λt).
8. Simplifying the equation, we get: 0.58 = \(e^{(-\lambda t\)).
9. Taking the natural logarithm of both sides, we have: ln(0.58) = -λt.
10. Substituting the value of λ from step 5, we get: ln(0.58) = -(ln(2) / 210) * t.
11. Solving for t, we have: t = (ln(0.58) * 210) / ln(2).
12. Evaluating the expression, we find: t ≈ 546.
13. Therefore, it would take approximately 546 days for the decay rate of the sample of this radioactive isotope to fall to 0.58 of its initial rate.
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Your marble has a mass of 5.0g. What is its mass in kilograms? Remember to include your units.
1kg=1000g
Answers
❖ Your marble has a mass of 5.0g. What is its mass in kilograms? (Remember to include your units. Given: 1kg=1000g)
Answer:\( \color{hotpink} \bold{0.005 \: kg} \\ \)— — — — — — — — — —
Formula:\( \underline{ \boxed{ \sf mass = \frac{mass \: in \: g}{1000 } }}\)— To calculate the mass in grams into kilograms, we just need to divide the given mass in grams by 1000 (since 1kg is equivalent to 1000 g).
Solution:\(\sf mass = \frac{mass \: in \: grams}{1000 } \\ \)\( \sf mass = \frac{5.0 \: g}{1000 } \\ \)\( \sf mass = \underline{ \boxed{ \blue{ \tt 0.005 \: kg}}}\\\)_______________∞_______________
Microwave ovens rotate at a rate of about 5 revolutions per minute (rpm). This is equal to 0.08 revolutions per second (rps). What is the angular velocity in radians per second? 2π rad = 1 revolution.
Answers
The angular velocity in radians per second, given that Microwave ovens rotate at a rate of about 5 revolutions per minute (rpm) is 0.50 radians per second
How do I determine the angular velocity in radians per second?The angular velocity (in radians per second) can be obtained by simply converting 0.08 revolution per second to radians per second. This is obtained as illustrated below:
Angular velocity (in revolution per second) = 0.08 revolution per secondAngular velocity (in radians per second) =?1 revolution per second = 2π radians per second
Therefore,
0.08 revolution per second = 0.08 × 2π
Recall
Pi (π) = 3.14
Thus,
0.08 revolution per second = 0.08 × 2 × 3.14
0.08 revolution per second = 0.50 radians per second
Thus, we can conclude that the angular velocity (in radians per second) is 0.50 radians per second
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Explain the light detection technique of photovoltaic detection
Answers
Answer:
Photovoltaic detection is a technique that converts light into electrical energy. It is a process that involves the use of a photovoltaic cell, which is made up of semiconductor materials, to generate an electric current when exposed to light.
The photovoltaic cell absorbs the photons of light, which then knock electrons out of their orbits, creating a flow of electricity. The amount of electricity produced is proportional to the intensity of the light. The photovoltaic cell is commonly used in solar panels to generate electricity from sunlight. The efficiency of the photovoltaic cell is dependent on several factors, including the type of semiconductor material used, the purity of the material, and the thickness of the cell.
The photovoltaic cell has many applications, including in solar power generation, telecommunications, and remote sensing. The technique of photovoltaic detection is an important area of research, as it has the potential to provide a clean and renewable source of energy that can help mitigate climate change.
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a bar of gold measures .113m *.0254m*.0106m. how many gallons of water have the same mass as this bar?
Answers
The volume (in gallon) of water that have the same mass as the bar of gold is 0.153 gallon
How do I determine the volume (in gallon) of water?We'll begin by obtaining the mass of the gold bar. This is given below:
Volume of gold bar = 0.113 m × 0.0254 m × 0.0106 m = 0.00003 m³Density of gold = 19300 kg/m³Mass of gold bar =?Density = mass / volume
Cross multiply
Mass = Density × Volume
Mass of gold bar = 19300 × 0.00003
Mass of gold bar = 0.579 Kg
Finally, we shall determine the volume of water having the same mass as 0.579 Kg of the gold bar. Details below:
Mass of gold bar = 0.579 KgMass of water = Mass of gold bar = 0.579 KgDensity of water = 1000 Kg/m³ Volume of water = ?Volume = mass / density
Volume of water = 0.579 / 1000
Volume of water = 0.000579 m³
Multiply by 264.172 to express in gallon
Volume of water = 0.000579 × 264.172
Volume of water = 0.153 gallon
Thus, we can conclude that the volume of the water is 0.153 gallon
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Question: Self-test 3.12 Calculate the change in G for ice at -10°C, with density 917 kg mº, when the pressure is increased from 1.0 bar to 2.0 bar.
Answers
The change in the Gibb's free energy per mole (G) is 1.96 J.
The given parameters:
Density of the ice, ρ = 917 kg/m³Initial pressure, P₁ = 1.0 barFinal pressure, P₂ = 2.0 barTemperature, T = - 10 CMass of water = 18 gThe change in the Gibb's free energy per mole (G) is calculated as follows;
\(\Delta G = V(P_2-P_1) \\\\\)
where;
V is the volume of the ice
\(Density = \frac{Mass}{Volume} \\\\Volume = \frac{Mass}{Density} \\\\Volume = \frac{18 \times 10^{-3} \ kg}{917 \ m^3} \\\\Volume = 1.96 \times 10^{-5} \ m^3\\\\Volume = 1.96 \times 10^{-5} \ m^3 \times \frac{1000 \ L}{m^3} \\\\Volume = 0.0196 \ L\)
Change in pressure;
\(P_2 - P_1 = 2.0 \ bar \ - \ 1.0 \ bar = 1.0 \ bar = 0.987 \ atm\)
The change in the Gibb's free energy per mole (G);
\(\Delta G= V(P_2-P_1)\\\\\Delta G = 0.0196\ L \times 0.987\ atm \\\\\Delta G = 0.0193 \ L.atm\\\\1 \ L.atm = 101.325 \ J\\\\\Delta G = 0.0193 \ L.atm \times \frac{101.325 \ J}{1 \ L.atm} \\\\\Delta G = 1.96 \ J\)
Thus, the change in the Gibb's free energy per mole (G) is 1.96 J.
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Why do people do drugs?
Answers
People use drugs for many reasons: they want to feel good, stop feeling bad, or perform better in school or at work, or they are curious because others are doing it and they want to fit in. The last reason is very common among teens.Drugs excite the parts of the brain that make you feel good. But after you take a drug for a while, the feel-good parts of your brain get used to it. Then you need to take more of the drug to get the same good feeling. Soon, your brain and body must have the drug just to feel normal. You feel sick, awful, anxious, and irritable without the drug. You no longer have the good feelings that you had when you first used the drug. This is true if you use illegal drugs or if you misuse prescription drugs. Misuse includes taking a drug differently than how your doctor tells you to (taking more or crushing pills to "shoot up" or snort), taking someone else’s prescription, or taking it just to get “high.”
Question 11
5 pts
Gas Laws: A balloon is carefully filled with one breath of air (about 500ml) underwater at
a depth of 100ft, then tied shut. At this depth, the balloon is under 4 atmospheres of
pressure. Assuming negligible compression by the rubber of the balloon, what is the
volume of the air (in m³) once the balloon rises to the surface of the water and
experiences 1 atm of pressure? Modify the Ideal Gas Law to solve this conservation
problem.
1 Liter 0.001 Cubic Meter
1 atm = 1.01x 105 Pascals
Answers
The volume of the gas once it reaches the surface of water is 2 liters.
The volume of the air in balloon at depth of 100ft (30m) is 500ml.
The pressure at this point is 4 atm.
Assuming that the balloon have no compression by rubber of balloon the volume of air at the water surface is V.
The pressure at the surface of water is 1 atms.
As we know, from the ideal gas equation,
PV = nRT
Where,
P is the Pressure of gas,
V is the volume of the gas,
n is the number of moles,
R is the gas constant whose value is 0.082057 L atm mol-1 K-1,
T is the temperature.
Assuming that the temperature is constant,
We know,
PV = nRT
All quantities on the right side are constants,
So, we can write,
P₁V₁ = P₂V₂
Putting all the the values,
4(0.5) = 1V₂
V₂ = 2 Liters.
The volume of the air at the surface is 2 liters.
1 liter = 0.001 m
Hence,
2 liters = 0.002 m³
So the volume of air at the surface is 0.002m³.
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A lightbulb has a resistance of 3.2 ohms with a current of 1.3 A. What is
the voltage?
4.16 V
O2.46 v
O 0.41 v
O 4.5 v
Answers
The voltage of this lightbulb is 4.16V. So, the correct option is A.
What is Voltage?Voltage is also called electric pressure, electric tension or potential difference which is defined as the difference in electric potential between two points. This corresponds to the work required per unit charge to move a test charge between two points in a constant electric field.
The volt (symbol: V) is described as the derived unit for electric potential, voltage, and electromotive force. This is represented as:
V = IR
Where, V= voltage
I = current
R = resistance
For above given example,
I= 1.3 A
R= 3.2 ohms
V= 1.3* 3.2= 4.16V
Thus, the voltage of this lightbulb is 4.16V. So, the correct option is A.
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Scott travels north 3 Km and then goes west 3 Km before coming straight
back south 3 Km. What is his distance? *
9 Km
3 km, W
3 Km, E
9 km, S
Answers
Answer:
3km,W This is because from the diagram.
moving to the North to the west and to the south with the same distance
Will be same as
3km,W
Sir Dudley the Dextrous is loading cannons on top of the castle's tallest towers in preparation for an expected attack. He slips, and a cannonball of mass 18.0 kg rolls to the edge of the tower, which has a perfectly horizontal surface, and falls to the ground below. It takes the cannonball 1.15 s to fall to the ground, and air resistance is negligible. How much work is done by gravity on the falling cannonball? During the fall, what is the average power transfer to the cannonball due to the force of gravity?
Answers
The cannonball experiences a 997.4 W average power transfer from the force of gravity.
How does gravity impact the cannonball's trajectory?The cannonball drops from rest the same distance that it did when it was simply dropped (refer to diagram below). Yet, the projectile's horizontal motion is unaffected by the gravity present.
The cannonball's gravitational potential energy, which is determined by the following formula, is equal to its potential energy when it is at rest on the tower.
PE = mgh
PE = (18.0 kg)(9.81 m/s²)(height of tower)
When the cannonball strikes the ground, it has the following kinetic energy:
KE = (1/2)mv²
The following factors determine the cannonball's kinetic energy at impact:
v = gt
v = (9.81 m/s²)(1.15 s) = 11.27 m/s
Substituting m = 18.0 kg and v = 11.27 m/s, we get:
KE = (1/2)(18.0 kg)(11.27 m/s)² = 1146.56 J
As a result, the typical power transmission is:
P = W/t = 1146.56 J / 1.15 s = 997.4 W
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A car starts from rest and accelerates at a constant rate in a straight line. In the first second the car moves a distance of 2.0 meters. How much additional distance will the car move during the second second of its motion?
Answers
Since the car is accelerating at a constant rate, the distance it travels during each second of its motion will be directly proportional to the time it has been accelerating.
In the first second, the car moved a distance of 2 meters, and in the second second, it will move twice the distance of the first second, so the car will move additional distance of 2*2 = 4 meters during the second second of its motion.
The distance traveled during the second second of its motion is 1/2 * 2 = 1 meters.
A car that accelerates at a constant rate will move a distance equal to the initial velocity multiplied by time plus 1/2 the acceleration multiplied by the square of time. Since the car starts from rest, the initial velocity is zero.
Therefore, the distance traveled during the second second is 1/2 * acceleration \(* (time)^2 = 1/2 * a * t^2 = 1/2 * a * 1^2 = 1/2 * a\) Since the car moved 2.0 meters in the first second, it means the acceleration is\(2m/s^2\), and the distance traveled during the second second is 1/2 * 2 = 1 meters.
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The height of a helicopter above the ground is given by h = 2.80t3, where h is in meters and t is in seconds. At t = 2.45 s, the helicopter releases a small mailbag. How long after its release does the mailbag reach the ground?
Answers
Answer:
1.45
Explanation:
When the early universe cooled enough for atoms to form, _____ began.
A. dark energy
B. the Big Bang
C. nucleosynthesis
D. the cosmic microwave background radiation
Answers
Answer:
B. the Big Bang
Explanation:
Answer:
When the early universe cooled enough for atoms to form, Nucleosynthesis began.
hope it helps!
Pot holder should have high insulation and low _____.
Answers
Potholder should have high insulation and low conductivity, therefore the correct answer is the option B
What is insulation?Insulation is a type of material used to create barriers to the transmission of the form of energy which either is in form of heat or electricity.
For outdoor trips in cold weather, several thin layers act as better insulating barriers for heat transfer.
The ability of an electric charge or heat to pass through a material is measured by its conductivity. A material is considered a conductor if it offers very little resistance to the flow of thermal or electric energy.
Thus, Potholders should be highly insulated and have low conductivity, therefore the correct answer is the option B
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your question seems incomplete, the complete question is
To be effective, a pot holder should have low _____. viscosity conductivity malleability density
I’ve been stuck please help !!
Answers
Answer:
The slope of the position time graph gives the velocity.
Explanation:
The slope of the position time graph gives the value of velocity.
In first graph,
The slope is constant in both the parts but positive . So the velocity is also constant and positive for both the parts. and more than the second part, so the initial velocity is more than the final velocity.
In the second graph,
The slope is constant in both the parts but negative. So, the velocity is constant but negative for both the parts. Initial velocity is more negative than the final velocity.
The efficiency of a machine can be increased by
Answers
Explanation:
the efficiency of a machine can be increased by reducing the friction
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A woman lives on the eighth floor of an apartment building. She works in a high-rise office building 6.5 blocks away from her apartment on the same street. Her office is on the 14th floor. Assume each story of her apartment building is 4.0 m, each story of her office building is 5.5 m, and a block is 146.6 m long.
Required:
a. Sketch her path.
b. Estimate the distance she travels to work.
c. Find the magnitude of her displacement.
Answers
Answer:
b) d = 997.9 m , c) D = (952.9 i ^ +45 k ^) m , D = 953.6 m and θ = 2.7º
Explanation:
In this exercise we must add the distance traveled, remembering that the displacement is a vector and the distance a scalar.
a) The displacement scheme is the woman walks in her building A to descend to the lower floor 4.0 m, we assume that this includes the vertical displacement, until reaching the street level, the displacement is vertical in this part.
Being on the street, she travels the 6.5 blocks to reach the building where she works, they indicate that each block is 146.6 m, this movement is horizontal.
Upon reaching building B, she goes up to his office on the 14th floor where she travels 5.5m on each floor, it is assumed that the distance to go up to the upper floor is included, this displacement is vertical
b and c) Let's find the distance traveled and the displacement
in building A
Zₐ = 8 * 4.0
Zₐ = -32.0 m k ^
the vector k ^ indicates that the displacement is vertical and the negative sign that it is descending
on the street
\(X_{ab}\) = 6.5 146.6
X_{ab} = 952.9 m i ^
the vector i ^ indicates that the displacement is the x-axis, we assume that the axis is in the direction of the displacement
in building B
\(Z_{b}\) = 14 * 5.5
Z_{b} = 77 m k ^
displacement in the vertical axis and in the positive direction
now we calculate the distance traveled,
d = Zₐ + X_{ab} + Z_{b}
d = -32 + 952.9 + 77
d = 997.9 m
note that this value is a scalar
Let's calculate the displacement,
Z axis
\(Z_{total}\) = Zₐ + Z_{b}
Z_{total} = -32 + 77
Z_{total} = 45 m k ^
X axis
X_{total} = X_{ab}
X_{total} = 952.9 m i ^
we can give the result in two ways
a) D = X_total i ^ + Z_total k ^
D = (952.9 i ^ +45 k ^) m
b) in module form and angles
Let's use the Pythagorean theorem
D² = \(X_{total}^2\) + \(Z_{total}^2\)
D = √(952.9² + 45²)
D = 953.6 m
We use trigonometry
tan θ = Z / X
θ = tan⁻¹ (Z / X)
θ = tan⁻¹ (45 / 952.9)
θ = 2.7º
this angle is measured from the positive side of the x axis towards the z axis
You see a boat sitting at the end of a dock. Ten minutes later you see the same boat in a cove to the right of the dock. You did not see the boat move.
However, you know that the boat moved because its
relative to the dock changed.
Answers
The boat must have moved, despite not being seen to move, because its relative position to the dock has changed. This phenomenon is known as relative motion .
Everything is always in motion, but the way we perceive it depends on our frame of reference.
In this scenario, the dock was the frame of reference for the initial position of the boat. When the boat moved to the cove, its position relative to the dock changed, and the dock was no longer an appropriate frame of reference. The boat's motion is now relative to the cove instead.
It is important to note that relative motion depends on the chosen frame of reference. If we were to choose the boat as the frame of reference, then it would be the dock that appears to move, not the boat. This is because motion is always relative to a chosen frame of reference.
In conclusion, the boat must have moved because its position relative to the dock changed. The concept of relative motion reminds us that motion is always relative to a chosen frame of reference, and that the way we perceive motion depends on our chosen frame of reference.
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2(a)Find the density of air filled in polythene container with mass of 0.419kg when it is empty. When filled with extra air its mass increased to 0.428kg also the top of polythene container mass connected to the perplex box of volume 1000cm³ and the number of times of air inside was 7.2 times
Answers
When filled with extra air its mass increased to 0.428kg also the top of polythene container mass connected to the perplex box of volume 1000cm³ and the number of times of air inside was 7.2 times. The density of the air filled in the polythene container is approximately 1.25 kg/m³.
The density of air filled in the polythene container can be determined by considering the change in mass and volume of the container before and after filling it with air. Given that the mass of the empty container is 0.419 kg and the mass of the container when filled with extra air is 0.428 kg, and the volume of the perplex box is 1000 cm³.
Calculate the mass of the air inside the container by subtracting the mass of the empty container from the mass of the container when filled with air:
Mass of air = Mass of filled container - Mass of empty container
= 0.428 kg - 0.419 kg
= 0.009 kg
Calculate the volume of the air inside the container using the given number of times the air inside is 7.2:
Volume of air = Volume of perplex box * Number of times air inside
= 1000 cm³ * 7.2
= 7200 cm³
Convert the volume of air to cubic meters (m³) by dividing by 1000000:
Volume of air = 7200 cm³ / 1000000
= 0.0072 m³
Calculate the density of air using the formula:
Density = Mass / Volume
Density = 0.009 kg / 0.0072 m³
≈ 1.25 kg/m³
Therefore, the density of the air filled in the polythene container is approximately 1.25 kg/m³.
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A bus in traffic increases its speed from 10km/hr to 23km/hr in 2 minutes. What is the average acceleration of the bus?
Answers
The average acceleration of the bus is −6.00 m/s².
What is average acceleration?The definition of average acceleration is the change in velocity per unit of time. Acceleration is measured in squared time-distance units. The word "average" is interpreted as a symbol with a bar over it, therefore "a-bar" stands for average acceleration. Calculating Average Acceleration: The change in velocity is calculated by dividing the end velocity by the initial velocity, then multiplying the result by the change in time. This result is known as the average acceleration (a). a = v t = v f v I t. How quickly an object is travelling in a specific direction is determined by its velocity. In the formula -a=vt=vfv0tft0, where an is average acceleration, v is velocity, and t is time, the average acceleration is the rate at which velocity changes.a = ? ; Δt = 1.50 s ; v1 = 9.00 m/s ; v2 = 0.00m/s
The formula to use in this case is the definition of acceleration stating that the acceleration a = Δv / Δt or a = (v2- v1) / Δt where v2 is the final velocity and v1 is the initial velocity.
Solving for the acceleration a
a = (v2- v1) / Δt
a = (0 - 9.00 m/s) / 1.50 s
a = - 9.00 m/s / 1.50 s
a = −6.00 m/s^2
The average acceleration of the bus is −6.00 m/s^2.
The complete question is,
When a bus comes to a sudden stop to avoid hitting a dog, it slows from 9.00 m/s to 0.00m/s in 1.50 seconds. What is the average acceleration of the bus?
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