A bottle rocket is fired off and has an acceleration of 14.5 m/s2 for the 2.25s until it burns out. If it starts at rest, what distance does it cover?

Answer:

The dot product of two vectors A and B is given by the formula A.B = Ax * Bx + Ay * By + Az * Bz. So, if A = 10i + 12j - 8k and B = 8i - 10j - 12k, then A.B = (10)(8) + (12)(-10) + (-8)(-12) = 80 - 120 + 96 = 56.

Answer:

-952

Explanation:

because when doting different letter's results into scalar quantity or in short it's one

a) To determine if the car will hit the object before coming to a stop, we need to calculate the distance required to stop the car, assuming maximum braking deceleration. We can use the following formula:

d = (v^2) / (2a)

where:

d = distance required to stop

v = initial velocity

a = acceleration/deceleration

In this case, v = 100 km/h = 27.78 m/s (converted from km/h to m/s)

a = -7 m/s^2 (negative sign indicates deceleration)

We know that the car's headlights extend out to a range of 30 m, so if the distance required to stop the car is greater than 30 m, the car will hit the object before coming to a stop.

Plugging in the values to the formula, we get:

d = (27.78^2) / (2 x -7) = 108.61 m

Since 108.61 m is greater than 30 m, the car will hit the object before coming to a stop.

b) To calculate the time required to stop, we can use the following formula:

t = v / a

where:

t = time required to stop

v = initial velocity

a = acceleration/deceleration

Plugging in the values, we get:

t = 27.78 / 7 = 3.97 s

Therefore, it will take 3.97 seconds to stop the car.

Explanation:

the object with the higher temperature has greater thermal energy

So the answer is

the stick of butter with less thermal energy.

Hope it will help :)

Answer:

The stick of butter with less thermal energy

Explanation:

I am pretty sure

The object of interest for this situation is the piano. The forces acting on the piano are: (1) gravitational force acting on the piano (piano's weight). (2) force of the floor on the piano (normal force). (3) force of Chadwick on the piano

In this situation, the object of interest is the piano. The forces acting on the piano are the gravitational force (weight) pulling the piano down, the normal force of the floor pushing up on the piano, and the force of Chadwick pushing on the piano to move it up the ramp. Since the ramp is frictionless, the only force acting to stop the piano from sliding back down the ramp is the normal force of the floor, which is perpendicular to the ramp surface. Therefore, Chadwick must push the piano with a force greater than its weight to overcome gravity and move it up the ramp.

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Complete question:

Chadwick now needs to push the piano up a ramp and into a moving van. The ramp is frictionless. Is Chadwick strong enough to push the piano up the ramp alone or must he get help? To solve this problem you should start by drawing a free-body diagram.

Determine the object of interest for this situation.

Identify the forces acting on the object of interest. From the list below, select the forces that act on the piano.

(1) gravitational force acting on the piano (piano's weight)

(2) force of the floor on the piano (normal force)

(3) force of Chadwick on the piano

Traits are the expression of alleles combination in a genotype, and depend on the inherited alleles and the inheritance pattern. Option D. Jane can say that she and Matt inherited eye color from their mother.  

Traits are the expression of the allelic combination in a genotype. The expressed phenotype will depend on the alleles inherited from each parent and the inheritance pattern.

According to the segregation principle, alleles separate during gamete formation. And during fertilization, two gametes from different parents merge to produce a zygote.

Each gamete carries one of the parental alleles. During fertilization occurs a combination of alleles that will express a phenotype.

Traits inheritance do not depend on each other, they are inherited by separate.

In the exposed example, eye color and hair type expression depend on the combination of the alleles in each genotype. And each trait is independently inherited from the other one.

Available data:

Mother

Father

Jane

Matt

A. Jane and Matt look like their mother ⇒ Only Matt looks like the mother because both of them have brown eyes and curly hair. Jane has brown eyes but straight hair.

B. Only a father can pass on the color of eyes ⇒ Both parents can pass the color of eyes, no only the father.

C. Hair type is not passed down from parent to child ⇒ Hair type is inherited from parents.

D. Jane and Matt inherited eye color from their mother ⇒ Yes, both of them inherited eye color from their mother. The three of them have brown eyes.

Based on her table, Jane can say that she and Matt inherited eye color from their mother. Option D.

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Answer:

88.14 m/s

Explanation:

From the question given above, the following data were obtained:

Radius (r) = length of blade = 80 m

Revolution (rev) = 1

Time (t) = 5.7 s

Velocity (v) =?

The velocity of the blade can be obtained by using the following formula:

v = (rev × 2πr) / t

NOTE: Pi (π) = 3.14

v = (1 × 2 × 3.14 × 80) / 5.7

v = 502.4 / 5.7

v = 88.14 m/s

Therefore, the velocity of the blade is 88.14 m/s

Answer:

m²=m¹

Explanation:

m¹v¹ + m²v² = m¹ v¹+m¹v²

m²v²= m¹v²

m²v²/v² = m¹

m² = m¹

Answer:

opaque = 4

malleable = 3

ductile = 2

lustrous (or whatever the bottom word is) = 1

Explanation:

Answer:

i hope it will be useful for you

Explanation:

F=5.6×10^-10N

R=93cm=0.93m

let take m1 and m2 =m²

according to newton's law of universal gravitation

F=m1m2/r²

F=m²/r²

now we have to find masses

F×r²=m²

5.6×10^10N×0.93m=m²

5.208×10^-9=m²

taking square root on b.s

√5.208×10^-9=√m²

so the two masses are m1=7.2×10^-5

and m2=7.2×10^-5

Explanation:

step 1. a diverging lens is "concave" on both side and always has a negative focal length

step 2. so 1/f = 1/s + 1/s' where f is the focal length, s is the object location, and s' is the image location (f, s, s' are all on the left side of the lens)

step 3. 1/-15 = 1/s + 1/-9 (image is virtual (negative))

step 4. 3/-45 = 1/s + 5/-45

step 5. s = 22.5cm (object is 22.5cm from lens)

step 6. s'/s = 9/22.5 ÷ 0.4 (magnification)

step 7. if the object is 4.5cm then the image is 4.5(0.4) = 1.8cm tall.

Answer:

- They need oxygen to burn fuel

- Aerodynamics

- Extreme temperatures

- Radiation

- Pressure issues

Explanation:

A airplane is a heavier-than-air aircraft kept aloft by the upward thrust exerted by the passing air on its fixed wings and driven by propellers, jet propulsion, etc.

Aeroplanes cannot travel in space for several reasons:

They need oxygen to burn fuel - Aeroplane engines rely on the oxygen in the atmosphere to burn fuel and generate thrust. In space, there is no atmosphere so there is no oxygen for the engines to work.

Aerodynamics - Aeroplane wings generate lift by interacting with the air. In space, there is no air so wings would be unable to generate any lift. Aeroplanes rely on aerodynamics to fly which does not work in space.

Extreme temperatures - In space, temperatures can range from -150 degrees Celsius to 150 degrees Celsius. Aeroplanes are designed to operate within a much narrower temperature range. The extreme cold and heat of space could damage aeroplane components.

Radiation - In space, there are high levels of radiation from the Sun and cosmic rays. Aeroplane bodies are not designed to shield against this type of radiation and it could damage electronics and affect aeroplane systems.

Pressure issues - Aeroplanes are designed to withstand air pressures at altitudes up to around 12 kilometers. In low-Earth orbit and beyond, the air pressure is essentially zero. This extreme change in pressure could cause structural damage to the aeroplane.

In summary, while aeroplanes are designed to fly through the Earth's atmosphere, they lack the key features needed to operate in the extreme environment of outer space like spaceships. Aeroplanes require things like oxygen, aerodynamics and being able to withstand changes in pressure - all of which do not exist or work the same way in space.

Explanation:

The wing is pushed up by the air under it. Large planes can only fly as high as about 7.5 miles. The air is too thin above that height. It would not hold the plane up.

The value of the rate constant at 457 K is 0.478 M/s.

The rate constant, k, at a given temperature can be related to the activation energy, Ea, and the gas constant, R, through the Arrhenius equation:

\(k = Ae^{(-Ea/RT)}\)

where A is the pre-exponential factor and T is the temperature in Kelvin.

Given k1 = 0.178 M/s at T1 = 280 K, and Ea = 37.8 kJ/mol, we can calculate the rate constant, k2, at T2 = 457 K as:

k2 = A * \(e^{(-Ea/R * T2)}\) = 0.178 * \(e^{(-37.8 kJ/mol / (8.314 J/mol K) * 457 K)}\) = 0.478 M/s.

This means that the reaction will proceed faster at 457 K than it does at 280 K, due to the increase in temperature leading to an increase in the rate constant, k.

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Answer:Magnetic fields from two sources add up as vectors at each point, so the strength of the field is not necessarily the sum of the strengths1. Magnetic fields are vectors, which means they have direction as well as size. Therefore, the sum of two magnetic fields is not simply the sum of their magnitudes2.

Explanation:

Answer:

i think it should be 18

Explanation:

Answer:

The below diagram shows pure spectrum with white light

Explanation:

Answer:

b is correct answer

Explanation:

The scientific explanations are obtained after the observation of the some phenomenon. If the phenomenon is unexplained with all the previous explanations, then new explanation is assigned to that phenomenon.

After the new explanation, some experiments are carried out based upon the theoretical explanation provided. If the experiments proved the result of the theoretical explanation then that explanation become scientific explanation of the new phenomenon.

Thus, the scientific explanations are based on objective and systematic observations carried out under carefully controlled conditio

Answer:

0.10 N

Explanation:

The drag force can be expressed using the following formula:

F = 1/2 * rho * A * Cd * v^2

Let's calculate the cross-sectional area of the sphere:

A1 = pi * r1^2

A1 = pi * (0.02 m)^2

A1 = 0.00126 m^2

Converting the speed to meters per second:

v1 = 0.1 m/s

Now we can use the formula to solve for the density times the drag coefficient:

rho * Cd = 2 * F / (A1 * v1^2)

rho * Cd = 2 * 8 N / (0.00126 m^2 * (0.1 m/s)^2)

rho * Cd ≈ 1.592 kg/m

For the second sphere with a radius of 4 cm and a speed of 5 cm/s, we can calculate the cross-sectional area and the speed in the same way:

A2 = pi * r2^2

A2 = pi * (0.04 m)^2

A2 = 0.00502 m^2

v2 = 0.05 m/s

Using the same value of the density times the drag coefficient:

F2 = 1/2 * rho * Cd * A2 * v2^2

F2 = 1/2 * (1.592 kg/m) * 0.00502 m^2 * (0.05 m/s)^2

F2 ≈ 0.10 N

Answer:

D gravity

Explanation:

please mark me brainliest

Answer:

D. The force that the branch applies to the kitten

Explanation:

I just took the quiz and got it correct!

a) Velocity of basketball player when he leaves the floor is 6.64 m/s ;  b) Acceleration while basketball player is straightening his legs is 73.8 m/s² ; c) Basketball player exerts a force of 8118 N on the floor to jump up for the ball.

Acceleration is the rate of change of velocity, while velocity is the rate of change of displacement.

(a) m g h = (1/2)mv²

m is player's mass, g is acceleration due to gravity, h is initial height, v is velocity when the player leaves the floor.

(110 kg)(9.81 m/s²)(0.300 m) = (1/2)(110 kg)(v²) + (110 kg)(9.81 m/s²)(0.900 m)

v = 6.64 m/s

So, velocity of basketball player when he leaves the floor is 6.64 m/s.

(b) v² = u² + 2as

u is initial velocity (zero in this case), a is acceleration, s is distance traveled, and v is the final velocity (6.64 m/s in this case).

(6.64 m/s)² = 2a(0.300 m)

a = 73.8 m/s²

Therefore,  acceleration while the basketball player is straightening his legs is 73.8 m/s²

(c) F = ma

F : force, m is the player's mass, and a is the acceleration.

F = (110 kg)(73.8 m/s²)

F = 8118 N

Therefore, basketball player exerts a force of 8118 N on the floor to jump up for the ball.

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Note: The question given on the portal is incomplete. Here is the complete question.

Question: A basketball player jumps straight up for a ball. To do this, he lowers his body 0.300 m and then accelerates through this distance by forcefully straightening his legs. This player leaves the floor with a vertical velocity sufficient to carry him 0.900 m above the floor. (a) Calculate his velocity when he leaves the floor. (b) Calculate his acceleration while he is straightening his legs. He goes from zero to the velocity found in part (a) in a distance of 0.300 m. (c) Calculate the force he exerts on the floor to do this, given that his mass is 110 kg.

The mathematical relationship between variables is suggested by a graph showing an L-shaped hyperbola that drops and flattens quickly is option A:  Inverse (simple).

When two variables change in an inverse relationship, they do so in the opposite directions: one increases while the other drops, and vice versa. Y declines as X rises in an inverse relationship. An inverse relationship always has a negative slope on a graph.

A function that can be altered into another function is said to be one that  can be seen as an inverse function or what we call the anti-function.

Therefore, Inverse operations are a class of mathematical operations where one operation cancels out the effects of another and it best shows  L-shaped hyperbola.

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Answer:

B. Inverse-squared

Explanation:

I took the physics exam

According to the statement, on latitude (l) and mean temperatures in February, the least squares linear regression model calculated for these data was:

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a}The work is done by the piston in the process is 199 cal.

b) The increase in internal energy of the gas is  703 cal

c) The heat was supplied to the gas is  3771 J

(a) To calculate the work done by the piston, we can use the formula:

Work = P * ΔV

Where P is the constant pressure and ΔV is the change in volume. Since the pressure is constant, the work done is given by:

Work = P * (\(V_2 - V_1\))

Since the amount of gas is constant (1 mole), we can use the ideal gas law to calculate the initial and final volumes:

PV = nRT

\(V_1 = (nRT_1) / P_1\)

\(V_2 = (nRT_2) / P_2\)

Here, n is the number of moles (1 mole), R is the gas constant (1.99 cal/mol·°C), T1 is the initial temperature (27 °C + 273 = 300 K), T2 is the final temperature (127 °C + 273 = 400 K), and P1 and P2 are the initial and final pressures, respectively (both 1 atm).

Substituting the values into the equation, we have:

V1 = (1 mol * 1.99 cal/mol·°C * 300 K) / (1 atm) ≈ 597 cal

V2 = (1 mol * 1.99 cal/mol·°C * 400 K) / (1 atm) ≈ 796 cal

Therefore, the work done by the piston is:

Work = 1 atm * (796 cal - 597 cal) = 199 cal

(b) The increase in internal energy of the gas can be calculated using the equation:

ΔU = n * C * ΔT

Where ΔU is the change in internal energy, n is the number of moles (1 mole), C is the molar heat capacity (7.03 cal/mol·°C), and ΔT is the change in temperature (127 °C - 27 °C = 100 °C).

Substituting the values into the equation, we have:

ΔU = 1 mol * 7.03 cal/mol·°C * 100 °C = 703 cal

(c) The heat supplied to the gas can be calculated using the equation:

Q = ΔU + Work

Substituting the values calculated in parts (a) and (b), we have:

Q = 703 cal + 199 cal = 902 cal

Since 1 cal = 4.184 J, the heat supplied to the gas is:

Q = 902 cal * 4.184 J/cal ≈ 3771 J

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Answer:

9 times more kinetic energy

Explanation:

KE₀ = ½mv²

KE₁ = ½m(3v)² = 9(½mv²) = 9KE₀

Answer:

180 LUV:)

Explanation:

The magnetic field in the loop l is equal to the magnetic field outside the loop, which is assumed to be purely azimuthal.

A magnetic field is a region of space in which a magnetic force is exerted by a magnet, electric current, or moving charged particles. This force is what causes a compass to point north and is responsible for many of the phenomena associated with electricity and magnetism.

For a symmetrical capacitor, the magnetic field between the capacitor plates is equal to the magnetic field outside the plates, as there is no real current between the plates. Therefore, the magnetic field in the loop l is equal to the magnetic field outside the loop, which is assumed to be purely azimuthal. Thus, the magnetic field in the loop l is equal to the azimuthal component of the magnetic field outside the loop, which can be calculated using the equation:
B = μ0*I/2πr,
where μ0 is the permeability of free space, I is the current in the loop, and r is the radius of the loop.

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According to the diagram the equivalent resistance of the group is

40.05 ohms

The equivalent resistance is calculated by investigating the diagram to note that R2 and R3 are in parallel and both are in series to R1

Resistors in parallel is solved by

Resistors in parallel = 1/25.4 + 1/70.8

Resistors in parallel = 0.0535 ohms

Equivalent resistance

Equivalent resistance = Resistors in parallel + Resistor in series

Equivalent resistance = 0.0535 + 40

Equivalent resistance = 40.0535

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The Milky Way Galaxy's disc and halo contain a number of stars. The order of the stars should be Oldest: Red Giant in globular cluster M13 AND red main-sequence star in globular cluster M13. Sun in the middle. Youngest: The disk's hot, blue main-sequence star.

Our solar system's home galaxy, known as the Milky Way, got its name from how it appears in the night sky from Earth: a hazy band of light made up of stars that are too close together to be seen individually. The Milky Way got its name from a Greek myth about the goddess Hera, who sprinkled milk on her subjects. In China, it is referred to as the "Silver River," while in the Kalahari Desert of southern Africa, it is called the "Backbone of Night."

The Milky Way contains about fifty galaxies, the largest of which is the Large Magellanic Cloud. Only 14,000 light-years are in the diameter of this satellite galaxy. There could be as many as 10 billion stars in the Large Magellanic Cloud.

Sagittarius A*, a supermassive black hole, is located at the Milky Way's centre. The black hole, discovered in 1974, can be seen in the sky using radio telescopes near the constellation Sagittarius.

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The mass of the object is approximately 0.457 kg.

The mass of the object attached to the trolley can be calculated using the principle of conservation of momentum. Since the two trolleys couple together and move as a single system after the collision, the total momentum before and after the collision should be the same. Given the mass of one trolley is 0.80 kg and the initial speed is 1.1 m/s, the momentum before the collision is 0.80 kg * 1.1 m/s = 0.88 kg·m/s. After the collision, the total mass is the sum of the two trolleys, and the final speed is 0.70 m/s.

Using the momentum equation, the mass of the object can be calculated as follows:

Total momentum before collision = Total momentum after collision

0.88 kg·m/s = (0.80 kg + mass of the object) * 0.70 m/s

Solving for the mass of the object, we get:

0.88 kg·m/s = (0.80 kg + mass of the object) * 0.70 m/s

0.88 kg·m/s = 0.56 kg + 0.70 kg * mass of the object

0.88 kg·m/s - 0.56 kg = 0.70 kg * mass of the object

0.32 kg = 0.70 kg * mass of the object

Dividing both sides by 0.70 kg, we find:

mass of the object = 0.32 kg / 0.70 kg = 0.457 kg

The two trolleys collide and couple together, the total momentum before the collision is equal to the total momentum after the collision according to the principle of conservation of momentum.

The momentum of an object is defined as the product of its mass and velocity. In this case, the mass of one trolley is known (0.80 kg) and the initial speed is given (1.1 m/s), allowing us to calculate the momentum before the collision.

After the collision, the two trolleys move together at a new speed (0.70 m/s). By setting the initial momentum equal to the final momentum and solving for the unknown mass of the object, we can find its value.

In the calculation, we subtract the masses of the two trolleys from the total mass in order to isolate the mass of the object.

Dividing the difference in momentum by the product of the known mass and the new speed, we obtain the mass of the object. In this case, the mass of the object is approximately 0.457 kg.

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