A bowling ball has a mass of 6 kilograms. A person lifts the bowling ball 2 meters above the ground, using a force of about 60
newtons. How much work did the person do?
360 joules
720 joules
120 joules
180 joules

Answer: Inertia

Explanation: If it is multiple choice chose acceleration and inertia

Answer:

as the mass of an object is increased, the acceleration of the object is decreased & vice-versa.

Explanation:

hope this helps!

The layer that the hot-air balloon can travel to, in the layer of the atmosphere is troposphere. its can't a go to higher layers because it would be  affected by density.

The troposphere servesv as the lowest layer of Earth's atmosphere however it has the mass (about 75-80%) of the atmosphere  and most of  tthe types of clouds  can be seen in the troposphere, then the weather occurs within this layer.

It should be noted that the troposphere has the highest density, as well as the greatest air pressure,  however the water vapor, and a temperature range from 62,  layer that the hot-air balloon can travel to, in the layer of the atmosphere is troposphere.

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If both masses double in size and their separation between them triples. 13..33 N will be the force between the masses.

Newton's law of gravity states that each particle having mass in the universe attracts each other particle with a force known as the gravitational force.

Gravitational force is proportional to the product of the masses of the two bodies and inversely proportional to the square of their distance.

Given data:

The gravitational force = 30 N

Mass 1 =m₁

Mass 2=m₂

Distance between charges = R

Condition given:

Mass 1 = 2m₁

Mass 2= 2m₂

Distance  between charges = 3R

\(\rm F = \frac{Gm_1m_2}{R^2}\)

Case 2;

\(\rm F'=\frac{G(2m_1)(2m_2)}{(3R)^2} \\\\ F'=\frac{4}{9} \frac{Gm_1m_2}{R^2} \\\\ F'=\frac{4}{9} F \\\\ F'=\frac{4}{9} \times 30 \\\\ F'=13.33 \ N\)

Hence, the forces between the masses will be 13..33 N.

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Explanation:

the lengths of the x and y components of the vector :

the x- Component:

Vx = 12×cos72° = 12× 0.3090 = 3.708

the y-component:

Vy = 12×sin72° = 12× 0.9510 = 11.412

-

x-component

= 12 . cos 72

= 12 . 0,3090

= 3,708

y component

= 12 . sin 75

= 12 . 0,9510

= 11,412

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Answer: 7/2, 3.5 and   1

                                   3-----

                                        2

based on the condition given condition, formulate;

30-23/2

Calculate: 30-23/2

Answer:

Tieflings are classed as humanoids, not fiends (and technically it appears to be a bloodline curse, not even having any fiendish blood). Note that being classed as a fiend would also mean the character would be immune to spells that target humanoids, such as Hold Person.

Explanation:

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Photons with a frequency of 1.0 × 1020 hertz strike a metal surface. If electrons with a maximum kinetic energy of 3.0 x \(10^-^1^4^\) joule are emitted, the work function of the metal is . 3.6 x\(10^-^1^4^\) J.

The correct answer is option 3.

To determine the work function of the metal, we can use the equation:

E = hf - ϕ

where:

E is the energy of the emitted electron,

h is Planck's constant (6.626 × \(10^-^3^4\) J·s),

f is the frequency of the photons,

ϕ is the work function of the metal.

Given:

Frequency of photons (f) = 1.0 × \(10^2^0\)Hz

Maximum kinetic energy of emitted electron (E) = 3.0 × \(10^-^1^4^\) J

We can rearrange the equation to solve for the work function:

ϕ = hf - E

Substituting the given values, we have:

ϕ = (6.626 × \(10^-^3^4\) J·s)(1.0 ×\(10^2^0\) Hz) - (3.0 × \(10^-^1^4^\) J)

Simplifying the equation, we get:

ϕ = 6.626 × \(10^-^1^4^\) J - 3.0 ×\(10^-^1^4^\)J = 3.626 × \(10^-^1^4^\) J

Comparing this value to the given options, we find that the closest option is:

3. 3.6 x \(10^-^1^4^\) J

Therefore, the correct option is option 3: 3.6 x \(10^-^1^4^\)J.

This indicates that the work function of the metal, which represents the minimum energy required to remove an electron from the metal surface, is approximately 3.6 x\(10^-^1^4^\) J.

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The height of the cannon where the objects are launched from is 18 feet.

The canons of page construction are historical reconstructions, based on careful measurement of extant books and what is known of the mathematics and engineering methods of the time, of manuscript-framework methods that may have been used in Medieval- or Renaissance-era book design to divide a page into pleasing proportions. Since their popularization in the 20th century, these canons have influenced modern-day book design in the ways that page proportions, margins and type areas (print spaces) of books are constructed.

To determine the height of the cannon where the objects are launched from, we need to find the value of "h" when "t" is equal to zero.

Given the equation: h = (-1/5)×t^2 + 5×(t) + 18

Substituting t = 0 into the equation, we have:

h = (-1/5)×(0)^2 + 5(0) + 18

= 0 + 0 + 18

= 18

Therefore, the height of the cannon where the objects are launched from is 18 feet.

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Answer:

R = 0.2 Ω

Explanation:

Para aplicar el concepto de resistencia de un conductor electrico, consideramos la siguiente formula:

R = ρ . l / S

Donde l es la longitud del conductor

S la superficie

y ρ el coeficiente de resistividad

Primero necestiamos hacer ciertas conversiones:

ρ = 0.10 ×10⁻⁶ (Ω . m²/m)

S = 2 mm² → 2 ×10⁻⁶ m²

R = 0.10 ×10⁻⁶ (Ω . m²/m) . 4m / 2 ×10⁻⁶ m²

Dentro de la formula simplificamos las unidades, los metros de ρ con la longitud y ambos m². De esa forma la unidad de R queda en Ω (ohmios).

Resolvemos:

R = 0.10 ×10⁻⁶ Ω . 4 / 2 ×10⁻⁶

R = 0.2 Ω

Answer:

150 N= 15 or 150 N= 1.1

Explanation:

What I did was subtract 165kg and 150 N and I divided it too but I got 1.1 so yuhh

The correct answer is A) We do not yet have a theory that links quantum mechanics and general relativity.

The Planck era refers to the first fraction of a second after the Big Bang when the universe was extremely hot and dense, and the energy density was so high that the laws of physics as we know them break down.

Therefore, to understand the behavior of the universe during this era, we need a theory that can unify quantum mechanics, which describes the behavior of particles at the atomic and subatomic scale, and general relativity, which describes the behavior of gravity at the cosmological scale.

Currently, there is no such theory, and this is why we cannot describe what happened during the Planck era.

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Answer:fda

afsd

ffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffff

The free body diagram of the elevator can be shown as,

According to free body diagram, the net force acting on the elevator is,

According to Newton's law,

Plug in the known expression,

Substitute the known values,

Thus, the maximum force exerted on the cable is 48925 N.

For minimum, tension the net force can be expressed as,

Plug in the known expression,

Substitute the known values,

Thus, the minimum force exerted on the cable is 44175 N.

Answer:

1.7 g/cm³

Explanation:

Given that:

Density of substance = 3.4 g/cm³

Relative density to another substance = 2

Density of second substance=?

Let density of second substance = x

Relative density = density of substance / density of second substance

Relative density = density of substance / x

2.0 = 3.4g/cm³ / x

2 * x = 3.4 g /cm³

x = 3.4 g/cm³ ÷ 2

x = 1.7 g/cm³

The name and chemical symbol of the elements are

Carbon = C

Lead = Pb

Antimony = Sb

Sodium = Na

Aluminum = Al

Chemical symbols are which are used to represent the elements in the periodic table.

The chemical symbol assigned to elements are usually an abbreviation of the name of the element or the Latin form of the name.

The name and symbol of the given elements are as follows:

Carbon = C

Lead = Pb

Antimony = Sb

Sodium = Na

Aluminum = Al

The chemical symbols are used frequently in writing the formula of compound formed from the elements. For example, the compound sodium aluminate which contains sodium, aluminum and oxygen is written in a simplified form as: \(NaAlO₂.\)

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Note that the complete question is given below:

Part A

Identify the chemical symbols corresponding to each element Drag the appropriate labels to their respective targets.

View Available Hint(s)

Element

Carbon

Lead

Antimony

Sodium

Aluminum

The resistance of a 1.00 m long copper wire that is 0.300 mm in diameter is approximately 2.37 ohms.

To find the resistance of a 1.00 m long copper wire that is 0.300 mm in diameter, we can use the formula for resistance:

Resistance (R) = (Resistivity (ρ) × Length (L)) / Cross-sectional Area (A)

1. First, we need to find the cross-sectional area (A) of the wire. Since it's a cylindrical wire, we can use the formula for the area of a circle: A = π × (radius)².

The diameter of the wire is 0.300 mm, so its radius is half of that, which is 0.150 mm. To convert this to meters, we need to divide by 1,000:

Radius = 0.150 mm / 1000 = 0.00015 m

Now, we can find the cross-sectional area:

A = π × (0.00015)^2 = 7.07 × 10^(-8) m²

2. Next, we need the resistivity (ρ) of copper. The resistivity of copper is approximately 1.68 × 10^(-8) ohm meters (Ωm).

3. Now, we can use the formula for resistance:

Resistance (R) = (Resistivity (ρ) × Length (L)) / Cross-sectional Area (A)

R = (1.68 × 10^(-8) Ωm × 1.00 m) / 7.07 × 10^(-8) m²

R ≈ 2.37 Ω

So, the resistance of a 1.00 m long copper wire that is 0.300 mm in diameter is approximately 2.37 ohms.

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The sound waves produced by the engine have a frequency of 120 Hz.

To calculate the frequency of the sound waves produced by the engine, we can use the following formula:

f = 1/T

where f is the frequency and T is the period of the sound wave.

Sound waves have a period of 8.3 milliseconds, so we can plug this value into the equation to find the frequency.

f = 1 / (8.3 x 10^-3s)

f = 120 hertz

Therefore, the sound waves produced by the engine have a frequency of 120 Hz.

It is important to note that frequency is the number of wave oscillations or cycles that occur in a unit of time and is measured in hertz (Hz). The period is the time of one oscillation and is the reciprocal of the frequency. The lower the frequency, the longer the period and vice versa.

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True. When a star begins to fuse iron in its core, it is a sign that the star is nearing the end of its life cycle. Iron fusion is the heaviest element that can be produced through nuclear fusion in a star, and it requires more energy than it releases.

During this process, the core of the star sucks up energy, which leads to a runaway reaction that causes the star to collapse into a small, dense object such as a neutron star or a black hole. The energy released during the supernova explosion is what creates the heavy elements, such as gold and silver, that are found in the universe.

In summary, when a star begins to fuse iron in its core, it is a sign that the star is approaching the end of its life cycle, and the core sucks up energy, leading to a supernova explosion and the creation of heavy elements.

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The length of the pendulum is 0.44338 m.

Acceleration due to gravity, g = 9.80 m/s2, Number of oscillations, n = 16, Time taken, t = 7.05 s.

Let l be the length of the pendulum. Now, one complete oscillation means when the pendulum starts from its extreme position (i.e., extreme position A), moves to the other extreme position (i.e., extreme position B), and returns back to position A.

Let’s calculate the time taken by the pendulum to complete one oscillation, i.e., the time period of the pendulum.t1 = time taken for 1 oscillation.

t1 = t/n = 7.05/16.0=0.44125 s

Now, the time period is given by, T=2π √(l/g) Where T is the time period of the pendulum. π = 3.1415 (approx)

Putting the given values of g and T in the above equation,

T = 2π √(l/g) = 2 x 3.1415 √(l/9.80)

Now, substituting T1 in the above equation, we get:

0.44125 = 2 x 3.1415 √(l/9.80)√(l/9.80)

= 0.44125/(2π)

= 0.07010049l

= (√(0.07010049 × 9.80))2l = 0.44338 m

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Therefore, based on the estimated duration of a galactic year, Earth has been around for approximately 18.4 to 20.4 galactic ye

A "galactic year" refers to the time it takes for our solar system to complete one orbit around the Milky Way galaxy. The exact duration of a galactic year is not precisely determined due to various factors, such as the varying speeds of stars within the galaxy. However, it is estimated to be roughly 225-250 million years.

To calculate the number of galactic years Earth has been around based on the age of the solar system (4.6 billion years), we can divide the age of the solar system by the estimated duration of a galactic year:

Number of Galactic Years = Age of the Solar System ÷ Duration of a Galactic Year

Number of Galactic Years = 4.6 billion years ÷ 225-250 million years

Number of Galactic Years ≈ 18.4 to 20.4 galactic years

Therefore, based on the estimated duration of a galactic year, Earth has been around for approximately 18.4 to 20.4 galactic years.

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Answer:37

Explanation:

Answer:

Newton

Explanation:

Hope this helps. Please give brainliest.

Answer:

we can incinerate waste materials and use the product as fuel rather than dumping them. It may produce carbon dioxide but we can create a machine that can convert carbon into energy.

The value was determined to be 0.122 m/s. The velocity of a body or object determines its direction of motion. Speed is a scalar quantity in its most fundamental form.

Velocity is essentially a vector quantity. It is the rate of change in distance. The initial speed of the first train, which has a mass of 150,000 kg, is 0.3 m/s. The second train has an initial speed of -0.120 m/s and a mass of 110,000 kg.

Let v represent the post-collision speed of the connected mass.

Utilize the idea of momentum.

The speed of the trains is constant both before and after a collision.

150.000 + 110.000v 45.000 - 13200 = 260.000 v 31800 = 260.000 v v = 0.122 m/s 150000 x 0.3 - 110000 x 0.120

After colliding, they move at a speed of 0.122 m/s towards the direction of the right.

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Answer:

displacement means moving something or the occupation by a submerged body part or part of the body

A automobile stopped after driving 50 meters at the a pace of 20 m / sec. Count on the rate of slowing being constant. Us = 0.5 and Uk = 0.03 are indeed the coefficient of friction between the seat and the user.

A force known as friction works between two systems to stop any motion including attempted motion. Its normal force N that has been bringing the systems together has an inverse connection with the simple friction.

Here following is an overview of friction's detrimental effects: Friction among various mechanical parts causes a substantial quantity of heat to be wasted as heat. Since movement is constrained, it takes more energy to go around it. Using a machine when it is making noise is useless and irritating.

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Total, 110 ohms resistance you would need to the circuit in order to limit the current to 2 amperes.

To limit the current in the circuit to 2 amperes, we can use Ohm's Law, which states that the current (I) in a circuit is equal to the voltage (V) divided by the resistance (R);

I = V / R

Given;

Operating voltage (V) = 220 volts

Circuit resistance (R) = 55 ohms

Desired current (I_desired) = 2 amperes

We wil rearrange Ohm's Law to solve for the resistance required to achieve the desired current;

R_required = V / I_desired

Substituting the given values, we have;

R_required = 220 V / 2 A

Calculating the division, we find;

R_required = 110 ohms

Therefore, you would need to add an additional resistance of 110 ohms to the circuit in order to limit the current to 2 amperes.

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In Part A, the angular momentum of the system about the origin can be calculated using the formula:

L = r × p, where r is the position vector from the origin to the center of mass of the system, and p is the linear momentum of the system. In this case, since the system is rotating in the xy-plane about the origin, the angular momentum is in the +z direction. The position vector r is perpendicular to the plane of rotation and has a magnitude of ℓ/2. The linear momentum of each particle is mvi, where vi is the speed of the particle. Using this information, we can calculate the angular momentum of the system as: L = (ℓ/2) × (m1v1 - m2v2). Substituting the given values, we get: L = (1/2) × (4.00 kg × 6.40 m/s - 3.00 kg × 6.40 m/s) = 22.4 kg·m^2/s. In Part B, we need to find the new angular momentum of the system if each of the masses were instead a solid sphere 10.5 cm in diameter. In this case, we can assume that the spheres rotate about their own center of mass. The moment of inertia of each sphere can be calculated using the formula for the moment of inertia of a solid sphere: I = (2/5) × mr^2, where m is the mass of the sphere and r is the radius of the sphere. Substituting the given values, we get: I = (2/5) × (m/4π) × (10.5/200)^2, where m = 4.00 kg for one sphere and m = 3.00 kg for the other sphere. The total moment of inertia of the system can be found by adding the moments of inertia of the two spheres. We can then use the formula for the angular momentum of a rotating object: L = Iω, where ω is the angular velocity of the system. However, we do not have enough information to find the angular velocity ω. Therefore, we cannot find the new angular momentum of the system with the given information.

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