A bowling ball has a surface area of about 232 square inches. Find the radius of the bowling ball.

The man exerts a force of approximately 31.875 Newtons on the box. To find the force exerted by the man on the box, we can use Newton's second law of motion.

To find the force exerted by the man on the box, we can use Newton's second law of motion, which states that the net force (F) acting on an object is equal to its mass (m) multiplied by its acceleration (a).

Given:

Mass of the box (m) = 51.0 kg

Displacement (d) = 2.50 m

Time (t) = 2.00 s

We can first calculate the acceleration of the box using the formula:

a = (2 * d) / (t^2)

a = (2 * 2.50 m) / (2.00 s)^2

a = 2.50 m / 4.00 s^2

a = 0.625 m/s^2

Now we can calculate the force exerted by the man using Newton's second law:

F = m * a

F = 51.0 kg * 0.625 m/s^2

F = 31.875 N

Therefore, the man exerts a force of approximately 31.875 Newtons on the box.

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Answer:

A. Her funding was from a source that could profit from the results.

Explanation:

GOT IT RIGHT

The moment of inertia of the wheel is gotten to be I = 41.2 kg.m²

Angular displacement = 5.55 revolutions × 2π radians/revolution

Angular displacement = 34.9 radians

Angular acceleration:

Angular acceleration = (final angular velocity - initial angular velocity) / time

Angular acceleration = (88.8 rad/sec - 0 rad/sec) / 0 s

Angular acceleration = 88.8 rad/sec²

Moment of inertia.

Moment of inertia = (torque × angular displacement) / angular acceleration

Moment of inertia = (77.7 Nm × 34.9 radians) / 88.8 rad/sec²

Moment of inertia = 41.2 kg.m²

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According to the given statement A higher true airspeed for any given angle of attack.

The angle between both the wing and the direction of flight is known as the angle of attack. The angles of attack is also the angle between both the wing and the relative wind since the direction of flight is the opposite of the airflow.

The ideal launch angle is dependent on ball speed, according to physics. The ideal launch angle is around 15 degrees at ball velocities typical of most amateur players. The average launch angle of PGA Tour golfers is just over 11 degrees because to their faster ball speed.

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A platinum coil turns becomes a superconductor when immersed in liquid helium at a temperature of 4 kelvin.

Energy from the outside is captured by the circulating fluid running through the coils, which then releases it through the interior coils into the building's interior. Superconductors have no electrical resistance as well as perfect diamagnetism. Cooper pairs of electrons are what cause superconductivity. The BCS theory, so named in honour of its three discoverers, describes how materials transform into "superb conductors" when their internal electrons cooperate to form Cooper pairs (or BCS pairs). When cooled to extremely low temperatures (near absolute zero, or roughly -273° Celsius), conductors completely lose all of their electrical resistance.

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Answer:

Kinetic and potential energy.

Explanation:

An object possessing mechanical energy has both kinetic and potential energy, although the energy of one of the forms may be equal to zero. A moving car has kinetic energy. If you move the car up a mountain, it has kinetic and potential energy. A book sitting on a table has potential energy.

Answer:

The pressure value changes 400 % relative to the initial value.

Explanation:

Let suppose that the gas behaves ideally and represents a closed system, that is, a system with no mass interactions so that number of moles is conserved (\(n\)). Since the variables involved in the isothermal process are pressure (\(P\)) and volume (\(V\)). Finally, the process is represented by the following relationship:

\(P_{1}\cdot V_{1} = P_{2}\cdot V_{2}\) (1)

Where:

\(P_{1}, P_{2}\) - Initial and final pressures.

\(V_{1}, V_{2}\) - Initial and final volumes.

If we know that \(P_{1} = P_{o}\), \(V_{1} = V_{o}\) and \(V_{2} = 0.2\cdot V_{o}\), then the final pressure of the closed system is:

\(P_{2} = P_{1}\cdot \left(\frac{V_{1}}{V_{2}} \right)\)

\(P_{2} = 5\cdot P_{o}\)

The pressure value changes 400 % relative to the initial value.

The answer for (iv) is;

E.M.F of the battery refers to the chemical energy in the battery that is being converted into electrical energy for the flow of electrons to carry current in a circuit.

The pressure transmitted in the hydraulic fluid is 4000 Pa and the mass of the load is 40.82 kg.

To determine the pressure transmitted in the hydraulic fluid, we can use the formula:

Pressure = Force / Area

Given that a force of 20 N is applied to the small piston and the cross-sectional area of the small piston is 0.005 m², we can calculate the pressure as follows:

Pressure = 20 N / 0.005 m²

Pressure = 4000 Pa

Therefore, the pressure transmitted in the hydraulic fluid is 4000 Pa.

To determine the mass of the load, we need to consider the equilibrium of forces in the hydraulic system. The force applied to the small piston is transmitted to the larger piston. Since the system is in equilibrium, the force exerted by the larger piston must balance the force applied to the small piston.

Using the formula:

Force = Pressure × Area

The force exerted by the larger piston can be calculated as follows:

Force = Pressure × Area (large piston)

Force = 4000 Pa × 0.1 m²

Force = 400 N

Therefore, the force exerted by the larger piston is 400 N.

Since force is equal to mass multiplied by acceleration (F = m × a), and the acceleration due to gravity is approximately 9.8 m/s², we can calculate the mass of the load:

400 N = mass × 9.8 m/s²

Solving for the mass:

mass = 400 N / 9.8 m/s²

mass ≈ 40.82 kg

Therefore, the mass of the load is approximately 40.82 kg.

The question was incomplete. find the full content below:

The diagram shows a basic hydraulic system which has a small piston and a large piston with cross-sectional areas of 0.005m² and 0.1m² respectively. A force of 20 N is applied to the small piston. Determine (a) the pressure transmitted in the hydraulic fluid (b) the mass of the load​

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Answer:

If you haven’t read about the shark found swimming in and out of a segment of an undersea volcano, then you really need to get up to date.

Explanation:

Answer:

The catapult works when the potential energy stored in a stretched rubber band is converted to kinetic energy when it snaps back to its loose shape, moving the catapult arm—and the projectile! ... The kinetic energy of the catapult will give the projectile a force moving up and away from the catapult.

Explanation:

Answer:

The answer is D.

Explanation:

They both orbit around the sun so they are similar in that way.

Answer:

Yes D. Both orbit the sun

Explanation:

Based on the data, we can infer that Rachel is moving faster because the slope of her line is steeper (option B).

To identify the runner who was going faster we must take into account the information in the graph. In this case, Rachel's line shows that she has covered more distance in less time than Kathy.

Therefore, Rachel's line is steeper than Kathy's. In this case, Kathy has taken about 70 minutes to cover 7 kilometers. While Rachel has taken 50 minutes to travel about 90 km.

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To determine the direction of the induced currents, you can use Lenz's Law, which states that the direction of the induced current will always be such that it opposes the change in magnetic field that produced it.

For the oval metal frame: If the frame is moving into the magnetic field, the induced current will flow in a direction that creates a magnetic field opposing the increase in magnetic field inside the frame. Conversely, if the frame is moving out of the magnetic field, the induced current will flow in a direction that creates a magnetic field opposing the decrease in magnetic field inside the frame.

For the two conducting sheets: Similar to the oval frame, when a conducting sheet is moved into the magnetic field, the induced current will flow in a direction that creates a magnetic field opposing the increase in magnetic field inside the sheet. When a conducting sheet is moved out of the magnetic field, the induced current will flow in a direction that creates a magnetic field opposing the decrease in magnetic field inside the sheet.

In each case, the direction of the induced currents will be determined by the direction of movement and the application of Lenz's Law to oppose the change in magnetic field.

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Tendon Sheath - is a specialized bursa that wraps around a tendon to reduce friction.

Tendon Sheath is a thin layer of tissue, surrounds each tendon in our body. The tendon sheath can also be called synovial lining or fibrous sheath. Tendon sheaths help to protect tendons from abrasive damage as they move.

Connection between Bursa and Tendon Sheath : Bursae are small fluid-filled sacs that can lie under a tendon, cushioning the tendon and protecting it from the injury. Bursae also provides an extra cushioning to adjacent structures that otherwise might rub against each other, which will cause wear and tear ( example, between a bone and a ligament ) .

So, lastly we can say that Tendon Sheath is the specialized bursa that wraps around a tendon to reduce friction.

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Answer:

hola

Explanation:

jffkbjkcvncncjcncjcjchchchcjcjcjcjcjckgmndjekbm hdfstfm mvndbfncn bdhwhgmvmch

Answer:

meat

Explanation:

ewwww

Answer:

5 Kg force I think try

Explanation:

the force is equal to the weight divided by two. It will require a 5 Kg force to lift a 10Kg weight.

Answer:

4.0 m/s ^2

Explanation:

The acceleration of the block weighing 80 n attached to a spring scale, and both are pulled to the right on a horizontal surface with negligible friction between the block and the surface will be 4 m/s² when it reads 32 n.

Acceleration is physical quantity used to express the rate of change in velocity of a moving massive body. Acceleration of an object is directly proportional to the force acting and inversely proportional to the mass.

The equation relating force and acceleration is F = ma. Thus as the mass of the body increases, acceleration decreases and this is called deceleration.

Given that the weight of the body is 80 n. It is the product of mass and gravity of 10 m/s². Thus mass m = 80/10 = 8 kg.

The scale reads a force of 32 Newton for the body weighing 8 Kg. Hence the acceleration can be calculated as follows:

a = F/m

   = 32 N/ 8 Kg

   = 4 m/s².

Therefore, when the acceleration of the body of 8 kg when the scale reading is 32 N is 4 m/s².

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Answer:

C

Explanation:

By Using Euler's method with two steps, we can find the approximate value of Y(2) is 2.125. , where Y is the solution of the initial value problem dy/dx = x - y, and Y(1) = 3.

Euler's method is defined as a numerical technique which is  used to approximate solutions into ordinary differential equations. The method includes dividing the interval of interest into smaller steps and thereafter approximating the solution at each step by using the derivative of the function.

In this case, we are given the initial value problem dy/dx = x - y, with the initial condition Y(1) = 3. To approximate Y(2) using Euler's method with two steps, we will divide the interval [1, 2] into two equal steps.

Step 1:

We start with the initial condition Y(1) = 3. Using the differential equation dy/dx = x - y, we can approximate the value of Y at the midpoint of the interval [1, 2].

Using the step size h = (2 - 1) / 2 = 0.5, we can calculate Y(1.5) as follows:

Y(1.5) ≈ Y(1) + h × (x - y) = 3 + 0.5 × (1.5 - 3) = 3 + 0.5 × (-1.5) = 2.25

Step 2:

Now, using the value of Y(1.5) as the new approximation, we calculate Y(2) using the same process:

Y(2) ≈ Y(1.5) + h × (x - y) = 2.25 + 0.5 × (2 - 2.25) = 2.25 + 0.5 × (-0.25) = 2.125

Thus,  by using Euler's method with two steps, the approximate value of Y(2) is 2.125.

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The complete question is

Use Euler's Method With Two Steps To Approximate Y(2), Where Y Is The Solution Of The Initial Value Problem: Dy : X − Y, Y(1) = 3

The correct statement regarding minimum allowable bend radii for 1.5 inches OD or less aluminum alloy and steel tubing of the same size is:

The minimum radius for steel is greater than for aluminum.

This means that steel tubing requires a larger bend radius compared to aluminum tubing of the same size. It is important to follow the specified minimum bend radii to prevent excessive stress on the tubing. Using a smaller radius than recommended can result in deformation, cracking, or failure of the tubing. Therefore, it is necessary to adhere to the guidelines to ensure the structural integrity and longevity of the tubing.

When it comes to minimum allowable bend radii for 1.5 inches OD or less aluminum alloy and steel tubing of the same size, the true statement is that the minimum radius for steel is greater than for aluminum. This means that steel tubing requires a larger bend radius to avoid excessive stress on the material during bending.

Bend radii are important considerations in tubing applications as they directly impact the structural integrity and performance of the tubing. If the bend radius is too small, it can lead to deformation, cracking, or failure of the tubing, compromising its functionality and potentially causing safety concerns.

Steel tubing typically has a higher yield strength and greater stiffness compared to aluminum, which is why it requires a larger bend radius. Aluminum alloys, on the other hand, are more ductile and can withstand smaller bend radii without compromising their structural integrity.

Adhering to the specified minimum bend radii ensures that the tubing is bent within safe limits, preventing excessive stress concentrations and maintaining the desired mechanical properties. It is essential to follow these guidelines to ensure the longevity and reliability of the tubing in various applications, including automotive, aerospace, construction, and industrial sectors.

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The altitude h is around 344 kilometers.

We'll start by utilizing the condition for the expanding speed of a dissent moving in a circular way:

a = v²/r

where a is the speeding up,

v is the speed,

r is the span of the circular way.

Since the attendant is moving in a circular way around the Soil, we'll anticipate that the speeding up is due to the gravitational imperative between the fanatic and the Soil. The speeding up due to gravity at a height of h over the Earth's surface is given by:

a = GM/r²

where G is the gravitational relentless,

M is the mass of the Soil,

r is the division between the center of the Soil and the attendant (which is rise to the aggregate of the span of the Soil

the stature h of the disciple).

Comparing the two expressions for expanding speed and understanding for h, we get:

GM/r² = v²/r + a

GM = r(v²/r + a)

GM = v² + ar

r = (GM/a) / (v²/a + 1)

Substituting the given values, we get:

r = ((\(6.67 x 10^-11\) Nm²/kg²) x (\(5.97 x 10^24\)\(5.97 x 10^24\) kg) / (2.5 m/s²)) / ((20 x 10^6 m/h)^² / (3600 s/h)² + 1)

r =\(6.7 x 10^6\) m

The stature h of the stooping is at that point:

h = r - (Earth's sweep)

h = \(6.7 x 10^6\) m - \(6.356 x 10^6\) m

h = 344,000 meters or 344 kilometers

In this way, the altitude h (stature) is around 344 kilometers. 

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Answer:

proton and neutron respectively.

Explanation:

Atoms of the same element will always have the same number of proton but will have different numbers of neutron if their mass numbers are different.

If you doble the width of a single slit the intensity of the light passing through the slit is doubled. This statement is  true.

The intensity of the light passing through a single slit is not directly proportional to the width of the slit. When you double the width of the slit, it will cause a change in the diffraction pattern, but it will not simply double the intensity of the light.

he intensity of the light passing through a single slit is not directly proportional to the width of the slit.

When the width of the slit is doubled, it will not simply double the intensity of the light passing through the slit. In fact, as the width of the slit increases, the central maximum of the diffraction pattern becomes wider, while the intensity of the light decreases.

This is because the increased width allows more light to diffract, leading to interference patterns and a reduced intensity in the central maximum.

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The cocountable topology is coarser than the usual topology and is not Hausdorff.

Let X be an infinite set and P (X) the power set of X. We define three topologies on X: the cofinite topology, the left ray topology, and the cocountable topology. We will compare each topology to the usual topology on X. We denote the usual topology by u.  

The Cofinite Topology Let F be the family of subsets of X such that F is either finite or X. That is, F = {A ⊆ X : A is finite or A = X}. The cofinite topology on X is defined by Tcf = {U ⊆ X : X \ U ∈ F} ∪ {Ø}. The open sets in the cofinite topology are the complements of finite sets plus the empty set.

A subset A of X is closed if and only if A is either X or finite. Thus, in the cofinite topology, every infinite subset of X is dense in X. Compared to the usual topology, the cofinite topology has fewer open sets and is coarser. In other words, the cofinite topology is a weaker topology than the usual topology.

The cofinite topology is also Hausdorff since given any two distinct points x, y ∈ X, the complements of the cofinite sets containing x and y are disjoint

. The Left Ray Topology Let F be the family of subsets of X such that F contains the empty set and all sets of the form L(a) = {x ∈ X : x < a}, where a is any element of X. The left ray topology on X is defined by TL = {U ⊆ X : U = ∅ or U contains some set L(a) from F}.

The open sets in the left ray topology are the empty set, all left rays L(a), and all sets that contain a left ray L(a). A subset A of X is closed if and only if A is the empty set, X, or contains the right endpoint of every left ray it meets. The left ray topology is finer than the cofinite topology but coarser than the usual topology.

Thus, the left ray topology is a weaker topology than the usual topology but stronger than the cofinite topology.

The left ray topology is also Hausdorff. The Cocountable Topology Let F be the family of subsets of X such that F is countable or all of X. The cocountable topology on X is defined by Tcc = {U ⊆ X : X \ U ∈ F} ∪ {Ø}. The open sets in the cocountable topology are the complements of countable sets plus the empty set.

A subset A of X is closed if and only if A is either countable or all of X. Thus, in the cocountable topology, every countable subset of X is nowhere dense.

Compared to the usual topology, the cocountable topology is coarser. The cocountable topology is also not Hausdorff since any two nonempty open sets have nonempty intersection. Hence, in the cocountable topology, the closure of a singleton set is the whole space X.

Among the three topologies, the cofinite topology is the weakest topology, and it is also a Hausdorff space. The left ray topology is a topology that is weaker than the usual topology but stronger than the cofinite topology, and it is also a Hausdorff space. Finally, the cocountable topology is coarser than the usual topology and is not Hausdorff.

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The beat frequency is 16 Hz and the average frequency is 562 Hz.

When two sound waves of slightly different frequencies are played simultaneously, the resulting sound wave will have a fluctuation in amplitude known as beats. The beat frequency is the difference between the two frequencies.

The beat frequency is the absolute difference between the frequencies of the two speakers.

Beat frequency = |570 Hz - 554 Hz| = 16 Hz

The average frequency is the arithmetic mean of the two frequencies.

Average frequency = (570 Hz + 554 Hz) / 2 = 562 Hz

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Answer:

im going to guess the 3rd one

Explanation:

Answer:

Voltage will be 1/2 original

Explanation:

V = I R        if  I  is constant

V = k R       now multiply both sides by  1/2

1/2 V  = k 1/2 R     <===== you can see the voltage is halved too