a building is considered green from an environmental standpoint for all the following reasons except: A. IT WAS PAINTED USING A VOLATILE ORGANIC COMPOUNDS (VOC) -BASED GREEN PAINT. B. IT IS MORE ENERGY EFFICIENT THAN CONVENTIONAL HOMES. C. IT MINIMIZES THE RELEASE OF TOXIC SUBSTANCES D. IT IS CONSTRUCTED WITH MOSTLY RECYCLABLE MATERIALS

Answer:

Non functional

Explanation:

Answer:

The digitization of performance management not only provides more precise data but also positively influences management processes and strategic development. Technology-enabled performance management tools simplify the manager's evaluation process and turn employees into active participants in their review sessions

True. Security-in-depth is a concept that calls for the systematic use of physical security measures in levels or steps to create different layers of protection. This approach ensures a more comprehensive and effective security system.

True. Security-in-depth is a systematic approach that involves implementing physical security measures in multiple layers or steps to provide comprehensive protection against various types of threats. Each layer of security measures provides additional protection, making it more difficult for attackers to penetrate the system.
SIDs can be used by any organization that wishes to protect its equipment, materials, data, information or personnel from damage or theft and to control its movement on the spot. The practice of SID has existed for centuries. Ditches, suspension bridges, outer walls, inner walls, watchtowers, etc. Imagine a fort that has - all this provides multi-layered security against infiltration and escaping with valuables.

Today, the use of physical barriers along with electronic systems, and electronic and security processes is a requirement to complete the SID. These integrated strategies will help prevent or stop and eliminate threats to and from assets. Multiple layers in an effective SID plan will also enable proactive and rapid response to threats.

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In the above case with Technician A and B, non of them are correct in what they have said.

This is known to be a sharp bend that is known to have a little radius over a short distance.

A Bend is said to be the slow alteration or change in shape that exist between the damaged and undamaged area.

Therefore, looking at the definition, you can see that In the above case with Technician A and B, non of them are correct in what they have said.

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Answer:

SECTION LEARNING OBJECTIVES

By the end of this section, you will be able to do the following:

Distinguish between static friction and kinetic friction

Solve problems involving inclined planes

Section Key Terms

kinetic friction static friction

Static Friction and Kinetic Friction

Recall from the previous chapter that friction is a force that opposes motion, and is around us all the time. Friction allows us to move, which you have discovered if you have ever tried to walk on ice.

There are different types of friction—kinetic and static. Kinetic friction acts on an object in motion, while static friction acts on an object or system at rest. The maximum static friction is usually greater than the kinetic friction between the objects.

Imagine, for example, trying to slide a heavy crate across a concrete floor. You may push harder and harder on the crate and not move it at all. This means that the static friction responds to what you do—it increases to be equal to and in the opposite direction of your push. But if you finally push hard enough, the crate seems to slip suddenly and starts to move. Once in motion, it is easier to keep it in motion than it was to get it started because the kinetic friction force is less than the static friction force. If you were to add mass to the crate, (for example, by placing a box on top of it) you would need to push even harder to get it started and also to keep it moving. If, on the other hand, you oiled the concrete you would find it easier to get the crate started and keep it going.

Figure 5.33 shows how friction occurs at the interface between two objects. Magnifying these surfaces shows that they are rough on the microscopic level. So when you push to get an object moving (in this case, a crate), you must raise the object until it can skip along with just the tips of the surface hitting, break off the points, or do both. The harder the surfaces are pushed together (such as if another box is placed on the crate), the more force is needed to move them.

The Bidirectional Shift Register is the shift register that allows one to write a 5bit register if the series is shifted from left to right.

A 5-bit register is valuable because it can represent up to 32 items. It is to be noted that a bit is a digit that is binary that is indicative of two states.

While a 5-bit register can have a possible number of 32 values,

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Like guess guess or actually solve ?

cause I think its 121

Answer:

CMRR(Common Mode Rejection Ratio) is the ratio of differential gain and the common mode gain.

Explanation:

The word problem for y = 2x is as follows.

"If y is the number of cakes produced by using 2 amounts of backing ingredients (x), find the number of cakes produced if x is 25."

A word problem is a mathematical exercise in scientific education in which substantial background information about the subject is conveyed in regular English rather than mathematical notation.

A word problem in mathematics is a math question expressed as one or more sentences that demand students to apply their arithmetic skills to a real-life setting.

This implies that in order to understand the word problem, students must be conversant with the terminology linked with the mathematical symbols to which they are used.

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The program is an illustration of conditional statements.

The program in Python where comments are used to explain each line is as follows:

highwayNumber = int(input("Highway number: "))

#This checks if the highwayNumber is not between 1 and 999 (inclusive)

if (highwayNumber <1 or highwayNumber > 999):

   #If yes, the highwayNumber is invalid

   print(str(highwayNumber)+" is not a valid interstate highwayNumber number.")

#If otherwise

else:

   #This checks if highwayNumber is less than 100

   if (highwayNumber< 100):

       if (highwayNumber%2 == 0):

           #Even highwayNumber are primary going east/west

           print("I-"+str(highwayNumber)+" is primary, going east/west.")

       else:

           #Odd highwayNumber are primary going north/south

           print("I-"+str(highwayNumber)+" is primary, going north/south.")

   #Otherwise

   else:

       if ((highwayNumber%100) % 2 == 0):

           #Even highwayNumber are auxiliary going east/west

           print("I-"+str(highwayNumber)+" is auxiliary, going east/west.");

       else:

           #Even highwayNumber are auxiliary going north/south

           print("I-"+str(highwayNumber)+" is auxiliary, going north/south.");

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Answer:

Explanation:

In the development of a torsion formula for a circular shaft, the following assumptions are made: Material of the shaft is homogeneous throughout the length of the shaft. Shaft is straight and of uniform circular cross section over its length. Torsion is constant along the length of the shaft.

A bonded resistance strain gauge needs to be connected to an electrical circuit that can detect the minute changes in resistance caused by strain in order to measure strain. Typically, strain gauge transducers use a Wheatstone bridge circuit made up of four strain gauge elements.

A Wheatstone bridge is a specific form of divided bridge circuit used to measure static or dynamic electrical resistance. The output voltage of a Wheatstone bridge circuit is expressed in millivolts for every volt of input. The Wheatstone circuit also functions well with temperature compensation. The Wheatstone bridge equation states that if R1, R2, R3, and R4 are all equal and a voltage, VIN, is applied between points A and C, there will be no potential difference between points B and D.  if R4 is changed to a value that is not equal to R1, R2, and R3, the bridge will become unbalanced and a voltage will exist at the output terminals. Resistance Rg is included in the variable strain sensor in the form of  a "G-bridge," 

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Answer:

The correct option is D

D) At minimum 10-20 minutes

Explanation:

After the car is jump started, the car should be allowed to run atleast for 10-20 minutes, this will help charge the battery of the car. If you don't do it and shut down the car immediately, the battery won't get charged and you will need another jump start. Apart from, parts of the car which are running from the battery e.g headlights, music player etc, should be turned off so it doesn't drain away the battery which is being charged.

Answer:

D. at minimum 10-20 minutes

Explanation: I got it right on FLVS

The five terminals of a real operational amplifier (op amp) include the ground terminal, two power-supply terminals, the inverting input, and the noninverting input. It is not common for an op amp to have two ground terminals; therefore, it is unlikely that it will be a part of the terminals of a real op amp.

The ground terminal, as the name suggests, is connected to the ground or reference point of the circuit, which provides a zero potential voltage level. This terminal serves as the reference point for the other terminals of the op amp.

The two power-supply terminals are usually labeled as VCC and VEE. VCC represents the positive supply voltage, while VEE represents the negative supply voltage. These two terminals provide the necessary power supply for the op amp to function correctly.

The inverting input is where the input signal is applied in an inverting configuration. The signal at this terminal is inverted by the op amp and then amplified. The noninverting input, on the other hand, is where the input signal is applied in a noninverting configuration. The signal at this terminal is not inverted by the op amp.

The output terminal is where the amplified signal is outputted. It is usually connected to a load resistor, which serves as a load to the op amp.

In conclusion, the probable functions of the terminals of a real op amp include a ground terminal, two power-supply terminals, an inverting input, a noninverting input, and an output terminal.

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6.8÷1.5 = 4.53...

So, it's 4 pipe with some left over.

Hope this helps!

In order to prevent mechanical damage to fire hose, several measures can be taken. Below are some of the ways through which mechanical damage to fire hoses can be avoided;

1. Using Protective EquipmentOne of the best ways to prevent mechanical damage to a fire hose is by using protective equipment. Protective equipment such as hose ramps and covers are specially designed to protect hoses from damage due to abrasion and external impact. Hose ramps are often used when hoses need to pass over a curb or other uneven surfaces to prevent any damage to the hose from the sharp edges. Covers, on the other hand, are used to protect hoses from heat, sunlight, and other external elements that can cause damage.

2. Proper StorageFire hoses must be stored correctly to prevent mechanical damage. Fire hoses should be coiled correctly without kinking, as kinks in the hose can weaken it and make it more susceptible to mechanical damage. Hoses should also be hung correctly on brackets, so they do not come into contact with any sharp edges or corners.

3. Regular InspectionRegular inspection of fire hoses is vital in ensuring they are in good condition. Inspections should be done frequently, and any damage should be repaired as soon as possible. Hoses that show signs of wear and tear, such as cracks, fraying, and cuts, should be replaced immediately to prevent any potential mechanical damage.

4. Proper UseFire hoses should be used correctly to prevent mechanical damage. The proper method for dragging, carrying, and rolling hoses should be followed. Hoses should not be dragged or pulled across rough or sharp surfaces, and they should not be used to break windows or other objects that may cause damage. Proper care and handling of hoses will ensure that they last longer and remain in good condition, and this, in turn, will prevent any potential mechanical damage.

In conclusion, mechanical damage to fire hoses can be avoided through the use of protective equipment, proper storage, regular inspection, and proper use.

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Answer:A

Explanation:

Those who want to save money and will use the product for only a few years

Answer:

THE ANSWER is A - those who want to save money and will use the product for only a few years

Explanation: Got it right on edg 2021

Matter can be defined as anything (physical object or body) that has mass and takes up space. Thus, the mass of a physical object measures the amount of matter the object contains.

In Science, water is an example of matter and it exists in three (3) main states or phases such as the following:

Based on scientific records and information, we know that all particles have various degrees of attraction to one another and this can be described as follows:

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Complete Question:

A student is investigating the particles in a glass window, raindrops on the window, and the air around the window. Assume the window, raindrops, and the air are all at 25 degrees Celsius. Identify the particle structure in each sample of matter.

Explanation:

whats

the question choices

In GMAW and FCAW, a welder controls the arc distance by controlling the nozzle-to-work distance. This distance refers to the distance between the welding gun and the workpiece being welded.

By controlling this distance, the welder can ensure that the arc is the appropriate length for the particular welding process being used. GMAW, also known as gas metal arc welding, is a welding process that uses a wire electrode that is fed through a welding gun. This wire is then melted and fused together with the workpiece to create a strong and durable bond. FCAW, or flux-cored arc welding, is similar to GMAW, but it uses a flux-filled wire electrode that creates its own shielding gas as it melts. This makes FCAW more suitable for outdoor welding applications or in windy conditions.In both of these welding processes, it is important to maintain the correct arc distance to ensure proper weld quality. If the arc distance is too short, the weld may be too small or uneven.

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The vectors are magnitude of vector v is 5. The sum of vectors v1 and v2 is (+) = (2, 1, 8).  The difference between vectors v1 and v2 is (-) = (6, -1, -2). The scalar multiple of vector v1 by 3 is 3(2, 0, 3) = (12, 0, 9).

To find the magnitude (||) of a vector, we can use the formula:

||v|| = sqrt(v1^2 + v2^2 + v3^2)

Given vector v = (4, 0, 3), we can calculate its magnitude as follows:

||v|| = sqrt(4^2 + 0^2 + 3^2)

     = sqrt(16 + 0 + 9)

     = sqrt(25)

     = 5

Therefore, the magnitude of vector v is 5.

Now, let's find the sum (+) and difference (-) of the given vectors.

Given vectors v1 = (4, 0, 3) and v2 = (-2, 1, 5), the sum of these vectors is calculated by adding the corresponding components:

v1 + v2 = (4 + (-2), 0 + 1, 3 + 5)

       = (2, 1, 8)

The difference between the vectors is found by subtracting the corresponding components:

v1 - v2 = (4 - (-2), 0 - 1, 3 - 5)

       = (6, -1, -2)

Lastly, let's calculate the scalar multiple of vector v1:

3v1 = 3(4, 0, 3)

   = (12, 0, 9)

Therefore, the vectors are as follows:

- The magnitude of vector v is 5.

- The sum of vectors v1 and v2 is (+) = (2, 1, 8).

- The difference between vectors v1 and v2 is (-) = (6, -1, -2).

- The scalar multiple of vector v1 by 3 is 3(2, 0, 3) = (12, 0, 9).

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There are a lot of ways employees uses in controlling exposure routes.  But when risk assessment is not be performed is not a part of the control methods.

The ways to control workplace hazards are known to be means taken to ensure safety in the workplace.

The examples are:

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A flexible budget prepared (before) the period begins allows management to make adjustments to increase profits or decrease losses.

A budget can be defined as a financial plan that is typically used for the estimation of revenue and expenditures of an individual, business organization or government for a specified period of time, often one (1) year.

In Economics, there are different types of budget and this include the following:

In conclusion, management can make several adjustments to increase profits or decrease losses when a flexible budget is prepared before the period begins.

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Answer:

Weight Percentage of Ash = 3.4

Explanation:

Given - Coal containing 21% ash is completely combusted, and the ash is 100% removed in a water contact scrubber. If 10,000 kg of coal is burned per hour with a scrubber flow rate of 1.0 m3/min.

To find - the weight percentage of the ash in the water/ash stream leaving the scrubber is most nearly ?

Solution -

Given that,

Coal Burned Rate = 10,000 kg/hr

                              = \(\frac{10,000}{60 min} * 1 hr *\frac{kg}{hr}\)

                              = 166.6666 kg/min

⇒Coal Burned Rate = 166.6666 kg/min

Now,

Given that,

Ash content in coal = 21 %

⇒Ash in (coal that burned) = 166.6666 × \(\frac{21}{100}\) kg/min

                                             = 34.9999 ≈ 35 kg/min

⇒Ash in (coal that burned) = 35 kg/min

Now,

We know,

Density of water = 1000 kg/m³

Now,

Water flow Rate = \(1\frac{m^{3} }{min} * density\)

                           = 1000 kg/min

⇒Water flow Rate = 1000 kg/min

Now,

Total Mass flow Rate of (Water + Ash stream) = ( 1000 + 35) kg/min

                                                                           = 1035 kg/min

⇒Total Mass flow Rate of (Water + Ash stream) = 1035 kg/min

So,

Weight Percentage of Ash = (Weight of Ash ÷ Total weight of Stream) × 100

                                            = (35 ÷ 1035) × 100

                                            = 3.38 ≈ 3.4

∴ we get

Weight Percentage of Ash = 3.4

The molar volume of acetylene vapor at 247.1 K and 13.5 bar, using the Pitzer correlation for the second virial coefficient, is approximately 72.5 cm3/mol.

Explanation:

The Pitzer correlation can be used to estimate the second virial coefficient of a gas. The equation is given by B = (RTc)/(Pc) * (1 + m(1 - (T/Tc)^(0.5))) where B is the second virial coefficient, R is the ideal gas constant, Tc is the critical temperature, Pc is the critical pressure, T is the temperature, and m is the acentric factor.

Plugging in the given values and solving for B, we get B = -0.009413 m3/mol. Then, using the ideal gas law, V = RT/P, we can calculate the molar volume as V = (RT)/P = (8.314 J/mol-K * 247.1 K) / (13.5 bar * 10^5 Pa/bar) ≈ 0.0725 m3/mol ≈ 72.5 cm3/mol.

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